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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 79551. |
125. The taxi fare in a city is as follows: For the first kilometre, the fare is Rs.8 and for thesubsequent distance it is Rs.5 per km. Taking the distance covered as x km and totalfare as Rs. y, write a linear equation for this information, and draw its graph. |
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Answer» Given,Total distance covered= xkm=1+(x-1)km Fare For first kilometre= ₹8 Fare for subsequent distance= ₹5 per km Fare for next(x-1)km= 5(x-1) A.T.Q Total fare= y 8+5(x-1)=y 8+5x-5=y 5x-y+3=0 Which is the required linear equation. It can also be written as y= 5x+3 When X = 0 ,then Y = 3,When x=1, then y=5+3=8 When x= 2, then y= 10+3=13 |
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| 79552. |
\operatorname { log } _ { 2018 } ( \frac { a + 2018 b + 2018 ^ { 2 } c } { 2018 ^ { - 4 } a + 2018 ^ { - 3 } b + 2018 ^ { - 2 } c } ) = |
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| 79553. |
5. The average age of three brothers is 15 years. If the age of two brothers is15 years and 12 years, find the age of the third brother. |
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Answer» let the age of 3rd brother be x now , avg is (x+15+12)/3 = 15=> x+27 = 45=> x = 45-27 = 18 years Let the ages of 3 brothers be x; y ; z respectively. Then A.T.Q, we have (x+y+z) /3=15(x+y+z)=45 --------1)Also we have ages of two brothers as 15 and 12 yrs so by putting x=15 and y =12 in EQ. 1) we get 15+12 + z= 45z= 45-27= 18 |
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| 79554. |
Radhika bought 2 m 5 cm cloth for her salwar and 3 m 35 cm cloth for her shirt. Find thetotal length of cloth bought by her. |
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| 79555. |
9. Solve the quadratic equation -x+3 1-X 17by factorisation method.1-2 x 410. Solve the quadratic equation 3x2 + 11x + 10 = 0 by method of completing the square.11. Using quadratic formula, solve the following equation for x :abx2 + (b2 - uc)r -- bc = 012. Find the values ofk for which the equation x2 - k (4x + k-1) + 2 = 0 has real and equal roots. |
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| 79556. |
Solve the following quadratic equation for x:4x2-4a2x + (a4-b4-0. |
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Answer» what is this ?????????????????? please like |
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| 79557. |
. Solve the following quadratic equation forx 4 x^{2}+4 b x-\left(3-b^{2}\right)=0 |
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| 79558. |
(Converse of corresponding angles axixample 6 In Fige values of x, y and z.. 6.27. AB II CD and CDI EF. Also EALAB. If Z BEF55° |
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| 79559. |
p q x ^ { 2 } - ( p ^ { 2 } + q ^ { 2 } ) x + p q = 0 |
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| 79560. |
Hint: Study we remaillues wTulugu3. Express the following in the form where p and q are integers and q +0.0 0.6(ii) 0.47(ii) 0.001 |
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Answer» (1) Let us assume that x=0.6 bar= 0.6666............------> (1) Now, we need to Multiply (1) with 10 10x = 10×( 0.666...) 10x=6.666... Subtracting (2) from (1)10x-x=6.6666.... - 0.6666...9x = 6 x= 9/6 = 2/3 (2). 0.47 bar = 0.4777777----> (1) Now we need to multiply with (1) with 10 10x = 10× (0.47777)... 10x= 4.7777.... Now we need to subtract (2) from (1) 10x-x = 4.7777...- 0.47777..... 9x = 4.3000 x= 4.3 /9 Therefore x = 43/90 3) 0.001 bar Let us assume that x= 0.001 = 0.001001...... Now let us multiply equation with 1000 1000 x = 1000× ( 0.001001...) Now we need to subtract (2) (1) 1000x - x = 1.001001...- 0.001001... 999x = 1 x = 1/999 ok thanks but explain thank u |
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| 79561. |
the first kilometre, the fare isi(1)3. If the point (3, 4) lies on theThe taxi fare in a city is as follows: For the first kilometre, the faresubsequent distance it is 5 per km. Taking the distance covered afare as y, write a linear equation for this information, and draw its.ore the equation whose graphs are give |
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Answer» answer Here is the complete explanation to the mentioned question. Fare for the first km = Rs 8 Total distance covered =xkm After travelling first km, remaining distance = (x– 1) km Rate of fare = Rs 5 per km Fare for (x– 1) km = 5 × (x–1) Total fare = Rsy Fare for the first km + fare for the remaining distance =y 8 + (x– 1) 5 =y 8 + 5x– 5 =y 5x–y+ 3 = 0 |
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| 79562. |
A. Write P- (4, 16, 64, 256) in set builder form.B. Write Q={2.며x=n/2; 0 < n5and n E N)ǐn roster form. |
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| 79563. |
\left. \begin{array} { l } { \frac { n ! } { 3 ! ( n - 3 ) ! } : \frac { n ! } { 5 ! ( n - 5 ) ! } = 5 : 3 } \\ { \frac { n ! } { 3 ! ( n - 5 ) ! } : \frac { n ! } { 5 ! ( n - 7 ) ! } = 1 : 6 } \end{array} \right. |
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| 79564. |
3. If A and B commute, then prove that (AB) A"B n, for all n E N. |
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| 79565. |
1. Find the volume of the cuboid which is 15 cm long, 12 cm wide and 10 cm high. |
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Answer» valume of cuboid=l×b×h=15×12×10=1800 cubic cm volume of cuboid=b*h*l=15*12*10=1800 Volume of cuboid is 1800 cubic cm |
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| 79566. |
8. A rectangular sheet of paper is 15 cm long and 12cm wide. Find its perimeter |
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Answer» show the answer ans Length of paper l = 15 1/3 cmWidth of paper w = 12 1/2 cm Perimeter of paper= 2(length + width)= 2(46/3 + 25/2)= 2(92 + 75)/6= 167/3= 55.6 cm |
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| 79567. |
en 5 km/h moretimes the larger und8. A train travels 360 km at a uniform speed. If the speed had been 5 kmhave taken 1 hour less for the same journey. Find the speed of the train |
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| 79568. |
15.A train travels a distance of 300 km at a uniform speed. If the speed oftrain is increased by 5 km per hour, the journey would have taken two hoursless. Find the original speed of the train.16.Find the roots of the following quadratic equation:(x+3) (x-1 )-3 (x-)the13 |
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| 79569. |
If the sum of p, q and r terms of an A.P. It be a, b and c respectively,\frac{a}{p}(q-r)+\frac{b}{q}(r-p)+\frac{c}{r}(p-q)=0 |
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| 79570. |
Lysosomes are very important cell organellein humans'. Why? |
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Answer» Lysosomes are important cell organelle as: 1. They help in formation of thyroid gland. 2. They eat up harmful substances and act as a defense mechanism. 3. They help in cell protection.4. As they throw or remove harmful substances from a cell they are also known as 'suicidal bags' |
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| 79571. |
A A patient in a hospital is given soup daily in a cylindrical bowl ofdiameter 7 cm. If the bowl is filled with soup to a height of 4 cm, howmuch soup the hospital has to prepare daily to serve 250 patients? |
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Answer» thank u scholr |
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| 79572. |
used as follows:F basic fare as forAcharges and 200 as aI (Unified Cound)Example 1: In this question, the symbols are used asA "B means'Add B to AA'B means'Subtract B from A'A B means 'Divide A by B'A*B means'Multiply A by B'The total airfare is calculated by adding 15% of basicsurcharge, 2% of the basic fare as IATA charges andport tax to the basic fare. If the basic fare of a sector isfollowing represents the total fare?(A) B' (B* 15) 100" (B * 2) 100" 200(B) B" (B* 15) (B* 2) 100' 200(C) B" (B* 15) (B * 2) 100" 200(D) B" (B* 15) 100" (B * 2) 100" 200Answer: (C)sic fare of a sector is B, which of the |
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| 79573. |
a cylindrical road roller made of iron is 1 metre long. its inner diameter is 54 cm and the thickness of iron sheet rolled into road roller is 9 cm. find the weight of the roller if 1 cm^3 of iron sheet weighs 8 g |
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| 79574. |
\sin \theta=\frac{m^{2}+2 m n}{m^{2}+2 m n+2 n^{2}}\begin{array}{l}{\frac{m(m+2 n)}{2 n(m-n)}} \\ {\frac{m(m+2 n)}{2 n\left(m+n^{2}\right)}}\end{array} \quad(b) \frac{m(m-2 n)}{2 n(m+n)} |
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Answer» hypotaneous=m^2+2mn+n^2remaining one side=m^2+2mnso other side=xx^2=(m^2+2mn+n^2)^2-(m^2+2mn)^2 =m^4+4m^2n^2+n^4+4m^3n+4mn^3+2m^2n^2-m^4-4m^2n^2-4m^3n=n^4+4mn^3+2m^2n^2=n^2(m^2+2mn+n^2)=n^2(m+n)^2so x=n(m+n) so tanx=(m^2+2mn)/(n(m+n)) =(m(m+2n))/(n(m+n)) wro wrong |
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| 79575. |
Find the 13th and 16th terms of the sequence defined by:bn={n^2 ,if n belongs to N and n is even n(n+ 2) ,if n belongs to N and n is odd |
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| 79576. |
Find the 13th and 16th terms of the sequence defined by, if n e N and n is evenInn(n + 2)if n e N and n is odd |
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| 79577. |
)md lle välue of y.Find the mode of the data 40, 35, 41, 43, 37, 35, 37,37,41,37. |
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| 79578. |
If " CC, then correct statement is(b) 2m n(n+ 1)(d) 2n m(m-1)2m = n(n + 1(a)(c)2m =n2m = n(n-1)1 10 |
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Answer» The answer is option 3. Derivation do plz |
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| 79579. |
Dy lle!er A rectangular sheet of paper is 15cm long and 12 cm wide. Find its perimeter. |
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| 79580. |
8. A train travels 360 km at a uniform speed. If the speed had been 5 km/h more, it woulkhave taken 1 hour less for the same journey. Find the speed of the train. |
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| 79581. |
. A train covers a distance of 180 k.m. at a uniform speed. If the speed hadbeen 9 k.m./Hr more, It would have taken 1 hour less for the same journey.Find the speed of the train. |
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Answer» Let speed of train is v1Time taken at v speed is t1 If speed increased by 9v2 = v1 + 9Time taken at increased speedt2 = t1 - 1 As distance remains same v1*t1 = v2*t2v1*t1 = (v1+9)(t1-1)v1*t1 = v1*t1 - v1 + 9t1 - 9v1 = 9(t1 - 1).....(1) Distance = speed*time180 = 9(t1-1)*t1t1^2 - t1 - 20 = 0t1^2 - 5t1 + 4t1 - 20 = 0t1(t1 - 5) +4(t1 - 5) = 0t1 = 5, - 4 Put value of t1 in eq(1)v1 = 9(5-1)v1 = 9*4 = 36 km/hr Speed of train is 36 km/hr |
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| 79582. |
htof the earthsizeonDlaath44Tattaight OA wethe rectangular plot? 5omm.inTo what extent will theheigll of inner diameter 14 m is dug to a depth of 8 m. The earth taken out of it has14nly spread all around it to. a width of 14 m to form an embankment. Find theof the embankment so formed. nencil consists of a cylinder of wood with a solid cylinder of graphite filled inu been evenlybcr. The diameter of the pencil is 7 mm and the diameter of the graphite isgth of the pencil is 14 cm, find the volume of the wood and that of the) A lead1 mm. If the lengraphite.HOTS QUESTIONS |
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Answer» a)GIVEN width of embankment = 14mits inner radius (r) = 7 m and outer radius (R) = 7+14=21m volume of earth dug out = vol of soil in embankmentπr²h = vol of soil in embankment 22/7×7²×8000 = π h ( R²- r² )1232000 = 22/7 × h × ( 21²-7² )1232000 × 7/22 = h x 392h = 1000m answer- 1 m |
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| 79583. |
9. A road roller takes 750 complete revolutions to moveonce over to level a road. Find the area of the road ifthediameter ofa road roller is 84 cm and length is I m. |
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| 79584. |
हल कीजिए : 4[17 + {2 + 54 + 2)}].N e e s I e R TN e e |
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Answer» 4(17+{2+5*6))4(17+(2+30))4(17+32)4(49)196 Good |
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| 79585. |
\int \frac { e ^ { 2 x } - 1 } { e ^ { 2 x } + 1 } |
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| 79586. |
9. Find the value of variables in the following(ii) | 클(iii) |(iv)(a) Ifx = (4-1-5 !)(3) find the value of x-210.(b) Ifx-G)1,findthe value ofnd the value of--b.6. |
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Answer» question 9 ka ii and iii |
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| 79587. |
\int \frac { e ^ { 2 x } - 1 } { e ^ { 2 x } + 1 } d x |
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| 79588. |
simplify the following expression (l-m) (m-n)+(m-n)(n-l)-(n-l)(l-m) |
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| 79589. |
If a cyclist had gone 3km/hr faster, he would have taken 1 hour 20 minutes less to ride80km. What time did he take? |
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Answer» thanks sit |
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| 79590. |
1. Can a pencil of 15 cm fit into a pencil box of length 160 mm? |
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Answer» 1 cm = 10mm15 cm = 150mmso yes it can fitas its 160mm 1 cm=10mm15 cm=150mmso yes it can fitas it's 160mm 1cm=10mm15cm=150 mmso that yesit can fit as it's 160 mmis the best answer Answer is 1cm=10m15CM =150mmit's fit =160mm Correct Answer given,pencil =15cmpencil box = 160mmso let's convert cm to mmif,1 cm = 10mmso,15cm = 150 mm.'. pencil can fit in pencil box given,pencil =15cmpencil box = 160mmso let's convert cm to mmif,1 cm = 10mmso,15cm = 150 mm.'. pencil can fit in pencil box yes it can fit as its 1600 Yes the pencil will fit in 160mm box as 1cm =10 mm 15 cm =150 cmso the 15 cm long pencil will fits in 160mm length box 15 cm=150 mm150 mm is less than 160 mmso pencil fit into pencil box yes 1 mm = 10 cm160mm=16cmbecause 16 is smaller than 15 . therefore it can fit into a pencil box |
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| 79591. |
18. A lead pencil consists of a cylinder of wood with a solid cylinder ofgraphite fitted into it. The diameter of the pencil is 7 mm, the diameterof the graphite is 1 mm and the length of the pencil is 10 cm. Calculatethe weight of the whole pencil, if the specific gravity of the wood is0.7g/cm2 and that of the graphite is 2.1 g/em2 |
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| 79592. |
How many words with or with are meaninger be formed by wing all the letters ofthe word, & BELHI asisg each letterexactly once ? |
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| 79593. |
10)0) 00How many words with or without meaning, can be formed by using all thethe word, 'DELHI', using each letter exactly once?(d) 120c) 60 |
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| 79594. |
9.)A road rollertakes 750 complete revolutions to moveonce over to level a road. Find the area of the road if thediameter of a road roller is 84 cm and length is 1 m. |
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| 79595. |
3. Combine terms: 12a 26b -4b 16a. |
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Answer» 12a + 26b - 4b - 16a= (12 - 16)a + (26 - 4)b= - 4a + 22b |
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| 79596. |
(i) 64a%+ 16a+1 TIH a=1 |
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| 79597. |
Factorise the following expressions:(a) 16a 64a b2 |
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Answer» 16a^5 - 64a^3b^2Take 16a^3 as common16a^3(a^2 - 4b^2)16a^3(a-2b)(a+2b) |
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| 79598. |
9. Factor compietely: () 16a()8+5(e)+2() -1 |
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| 79599. |
\left. \begin{array} { l l l l } { 3 } & { 9 } & { 4 } & { 6 } \\ { 6 } & { 5 } & { 7 } & { 9 } \\ { 2 } & { 0 } & { 5 } & { 0 } \end{array} \right. |
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Answer» The answer is 12,575 thank Just like it please on adding, the answer is 12575 |
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| 79600. |
If a 3-5, find the value ofa4-a3-20a2-16a+24 |
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