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Wall;l=16m=1600cmh=3m=300cmb=22.5cmvolume of the wall=lbh =1600*300*22.5 =10800000centi metre cubebrick;l=25cmb=11.25cmh=6cmvolume=lbh =25*11.25*6 =1687.5 centi metre cubetherefore number of bricks=volume of wall/volume of 1 brick = 10800000/1687.5 =6400 brickstherefore number of bricks is 6400 bricks

given the area of rectangular field and Square playground is equal.length of rectangular field, l = 405mbreadth of a rectangular field, b = 80mlet the length of each side of a square playground be "a"

therefore, area of rectangle= area of square=> l*b=a^2=>. 405*80=a^2=>. a=√32400=>. a=180 m. (answer)

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we check at x = 0so LHL is when x tends to 0sin(x²-x)------------ xso when x tends to we have 0/0 so use L'Hopitals rulecos(x²-x) × (2x-1)-------------------------- 1so when x tends to 0 cos(0) × (-1) = -1

so at x= 0, f(x) is not continuous,To remove it redefine f(x) = sin(x²-x) ------------ + 3 when x is not 0 x

corresponding angles are equal=> a = 120°

Let the smaller diameter tap takes x hours to fill the tank

Then, time taken by larger diameter tap to fill the tank=(x-3)

Both taps together can fill the tank in 40/13 hours

portion of tank filled by smaller diameter tap in x hours= 1/x

portion of tank filled by smaller diameter tap in40/13 hours= 40/13x

portion of tank filled bylarger diameter tap in (x-3) hours=1/x-3

portion of tank filled bylarger diameter tap in 40/13 hours= 40/13(x-3)

ATQ,40/13x+40/13(x-3)=1

1/x+1/x-3=13/40

x-3+x/x(x-3)=13/402x-3/x²-3x=13/40

13x-119x+120=0a=13b=119c=120D=b²-4ac =14161-6240 =7921applying quadratic formula we get two roots = -b+√D/2a and -b-√D/2a119+89/26 and 119-89/268 and 15/13x= 15/13 neglected because time taken by smaller tap cannot be less than 3 hours so smaller tap time = 8 hours and larger tap = 5 hours

1) e2) c3) d4) b5) a

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Area = Side*Side=> Side* Side = 225=> Side = 15 m.Perimeter = 4* Side= 4*15= 60 m

Given,Side of square = 50 mReactangular field length = 80 mReactangular field breadth = b

Then,Perimeter of Reactangular field= 2(80 + b)Perimeter of Square field= 4*50 = 200 m

2(80 + b) = 20080 + b = 100b = 100 - 80 = 20

Thus, Area of square field = 50*50= 2500 m^2Area of Reactangular field= l*b = 80*20 = 1600 m^2

Therefore square field has larger area

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area of remaining piece=area of rectangular piece-triangular piece=25*16-1/2*14*10=400-70=330cm^2area of rectangle=length*breadtharea of triangle=1/2*base*height.

BM=1470÷49=30cmDL=1470÷35=42cm

area of parallelogram=h×b DL×AB DL×351470÷35=42cm height so, height is also BMbut we find length of BM area of parallelogram=h×b1470÷49. 49×BM =30cm is length BM

Let Rehana's present age be x.Then Mother's age = (7/2)x = 3.5xAfter 2 years, (x+2) / (3.5x+2) = 1/3=> 3x + 6 = 3.5x + 2=> 4 = 0.5x=> x = 8 years old.

REHANA IS 8 YEARS OLD PRESENTLY.

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Length/Breadth=5/33L=5BL=5B/3Area of 4 walls=Curved surface of cuboid=2(L+B)HNow area=24000/75=320m^2320=2(L+B)H160=(5B/3+B)532=8B/396/8=BB=12mL=5(12)/3=20m

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Area of road parralel to length =80×3=240

Now,Area of road parallel to breadth=60×3=180

Total area will be=240+ 180-3*3( because they are intersecting and 3*3 is coming two times )=240+180-9=411

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s=a+b+c/2.

Area= √s(s−a)(s− b)(s−c)

s = 25+25+14/2 = 64/2 = 32

Area = √{32*(32-25)*(32-25)*(32-14)}

= √(32*7*7*18)

= √28224

= 168

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38892.5442726 is the correct answer

Triangle ABC is a right triangle with its right angle at B. Therefore, AC is the hypotenuse of right triangle ABC, and AB and BC are the legs of right triangle ABC. According to the Pythagorean theorem,

AB=√202−162=√400−256=√144=12

Since triangle DEF is similar to triangle ABC, with vertex F corresponding to vertex C, the measure of angle∠F equals the measure of angle∠C. Therefore, sinF=sinC. From the side lengths of triangle ABC,

sinF=oppositesidehypotenuse=AB/AC=12/20=3/5

Therefore, sinF=3/5.

The final answer is 3/5 or 0.6.

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The basic key to the question is that Earth has two hemispheres which are equal. If we figure out this logic we can easily solve this question. Since the ratio of land to water on earth is 1:2 let us assume the proportion to be 1x and 2x , therefore the total volume would be 3x. Since each of these two hemispheres share these resources equally, the share of northern hemisphere is (3/2)x.

It is also given that the ratio of Land to water in N.H is 2:3, using ratios and proportions we can find the volume of land and Water separately.

Volume of land in N.H = (3/2)x X (2/5) = 3x/5

Volume of water in N.H = (3/2)x X (3/5) = 9x/10

Since we know the total volume of land and water present on earth is 1x and 2x respectively. we can deduce the following.

Volume of land in S.H = 1x-3x/5 = 2x/5

Volume of water in S.H = 2x-9x/10 = 11x/10

Finding the ratio of land to water in S.H : 2x/5 : 11x/10 which is4:11.

4:11 is the ratio in southern hemisphere

4 ratio 1 1 is the correct answer of the given question