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79851.

nd then an3. Construct a triangle with sides 5 cm, 6 cm and 7 cm asides are of the corresponding sides of the first triangle.4. Construct an isosceles triangle whose base is 8 cm and altitude 4triangle whose sides are 1times the corresponding sides of th5. Draw a triangle ABC with side BC 6cm, AB-5 cm and Z ABC

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79852.

le 5 : The school canteen charges R 20 for lunch and? 4 for milk foday. How much money do you spend in 5 days on these things?each

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79853.

2. 7359105 pencils are packed equally in 845 boxes. How many pencils are packed in one box?

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Given:7359105 pencils are equally packed in 845 boxes

No of pencils in one box=7359105/845=8709 pencils

79854.

triangle whose corresponding altitude is 90 m.8. The base and height of a triangle are in the ratio 3:4 and its area is 96 cm2. Find its base and heightEx. 2.

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Let base=(3x)cm and height =(4x) cm respectively. So its area = 1/2 ×base×height =(1/2 ×3x×4x)cm^2=6x^2 cm^2 .6x^2=96 .or x^2=16 or x=4. So base is 12 cm and height is 16 cm

79855.

2) The perimeter of a triangle is 150m and its sides are in the ratio5:12:13.Find the area of the triangle.(area :750 sq.m)3) A triangular park ABC has sides 120m,80m,50m.A gardener hasto put fence all around it and also plants grass inside.Find thearea of planted grass and also find the cost of fencing it withbarbed wire at the rate of Rs.20 per metre leaving a space of3m wide for a gate on one side.(area-375v15 sq.m,cost-Rs.4940)4) Find the area of equilateral triangle whose perimeter is 150m.(area-625V3 sq.m)5) Find the area of triangle whose sides are 9m,8m,3m.6) Find the area of an isosceles triangle whose equal sides is 40cm7) The sides of a triangle are in the ratio 3:5:7 and its perimeter is8) Find the area of a triangle, two sides of which are 8cm and(area-2v35 sq.m)and unequal side is 18 cm.(area:378v31 sq.cm)300m.Find its area.(area:1500v3 sq.m)11cm and the perimeter is 32cm.(area:8v30 sq.cm)

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plezz type witch question

1st one is question number 1 and 2nd one is question number 3..if you want the solution for other..please specify and post it again one by one

79856.

9. Construct an isosceles triangle whose base is 8 cm and altitude 4 cmand then another triangle whose sides are.1 2 times the correspondingdes are, times the correspondingsides of the isosceles triangle.2.

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79857.

4.Construct an isosceles triangle whose base is 8 cm and altitude 4 cm and then anothertriangle whose sides are 1- times the corresponding sidcs of t1 times the corresponding sides ofthe isosceles triangle.2

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79858.

Find the area of an isosceles triangle whose one side is 10 cm greater than each of its equal sides andperimeter is 100 cm.

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79859.

cuemathmaking kids great at math.A teacher drew a pictaph tokeep a note of the nun er ofstudents eating junk f id and thenumber of times they it in aweek.c000-cocCOC+occera+occo12 3 4 5Number of studentsHow many students ate junk foodexactly twice a week if each smileyrepresents a day in a week?

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answer is day 3 (day 3 me hi exactly twice student hai)

6

79860.

The college canteen sold 136 packed lunches on Monday and 293 packedlunches on Tuesday. How many packed lunches were sold in these two days?Write the number sentence.

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Lunch sold on Monday=136Lunch sold on Tuesday=293Total lunch sold=sum of both days136+293=429In word= Four hundred twenty nine.

Lunch sold on Monday =136Lunch sold on Tuesday=293hence total packets sold is 136+293=429Four hundred and twenty nine

79861.

2. Find the area of a rectangle whose length is 135 cm and breadth 12 m.

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length=135cmbreadth=120cmarea =l×b=135×120=16200 cm2

79862.

A field is in the shape of a trapezium whose-parallel sides are 25 m and 10 m. The non-parallel sides are 13 m and 14 m. Find the area of the field.

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Given: AB || CDAB =25 m CD= 10m BC=14mAD= 13m

From point C draw CE || DA . Hence ADCE is a ||grm having CD || AE & AD||CE

AE= CD= 10mCE= AD= 13mBE= AB- AE =25- 10=15 m BE= 15m

In ∆BCEBC= 14m, CE= 13m, BE= 15m

Semiperimeter (s)= (a+b+c)/2

Semiperimeter(s) =( 14+13+15)/2s= 42/2= 21ms= 21m

Area of ∆BCE= √ s(s-a)(s-b)(s-c)Area of ∆BCE=√ 21(21-14)(21-13)(21-15)

Area of ∆BCE= √ 21×7× 8×6

Area of ∆BCE= √ 7×3× 7× 4×2×2×3Area of ∆BCE=√7×7×3×3×2×2×4Area of ∆BCE= 7×3×2×2= 21× 4= 84m²

Area of ∆BCE= 84m²

Area of ∆BCE= 1/2 × base × altitudeArea of ∆BCE= 1/2 × BE ×CL

84= 1/2×15×CL

84×2= 15CL168= 15CLCL= 168/15CL= 56 /5m

Height of trapezium= 56/ 5m

Area of trapezium= 1/2( sum of || sides)( height)

Area of trapezium=1/2(25+10)(56/5)Area of trapezium= 1/2(35)(56/5)

Area of trapezium= 7×28= 196m²_____________________________Hence the area of field is 196m²

79863.

Find the area of an isosceles triangle whose equal sides measure 5 cm each and heightcorresponding to the third side is 4 cm.

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base of the triangle = 2*(√5²-4²) ...... using Pythagoras theorem

so, base = 2*(3) = 6cm

now area = 1/2*(h*b) = 1/2*(4)*(6) = 12cm²

79864.

The area of a triangle is equal to the area of asquare having side 70 m. Find the side of thetriangle whose corresponding altitude is 98 m.

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thank U for solving this question

79865.

3. Find the area of a right trianglese or a triangle whose area is 0.45 m mof a right triangle whose hypotenuse is 13 cm and one side is sohe area of an isosceles right triangle whose equal sides are 15 cm each

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ans3hyp=13cmone side=5cmother side²=13²-5²=169-25=144other side=√144=12cmtherefore area=1/2xbasexheight=1/2x12x5=6x5=30cm²

ans4area of triangle = 1/2×base×height =1/2×5×5=25/2area =12.5 cm²

79866.

2. Find the perimeter of(a) Rectangle whose length - 30 cm, breadth - 15 cm(b) Square whose each side is 15 cm

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Perimeter1) 2(length+breadth)= 2(45)= 90cm2) 4* side= 4*15= 60cm

79867.

3. Find the aluarea Ullength. Hence, fCalculate the area of the triangle whose sides are 18 cm, 24 cm and30 cm in length. Also, find the length of the altitude corresponding tothe smallest side.nd the height corresponding to he longular field whose sides are 91 m, 98 m and 105 mnost side.

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79868.

find the area of an isosceles triangle ,whose equal side are of length 15cm each and third side is 12 cm

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79869.

d the aea of the tollowing trapezionsParallet sides8 cm and 10 cm2.2 cm and 3.5 em i) 4 mParallel İles10 em and 12 cm15 cm and 78 cmca(n) 15 em

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79870.

&The area of a trapezium is 1,586 cm and sum of parallel sides is 122 cm. Find thedistance between two parallel sides.

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79871.

sThe lengths of a triangle are 6 cm, 8 cm and 10 cm. Then the lerngth otperpendicular from the opposite vertex to the side whose length is Bcm is

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79872.

The lengths of the diagonals of a rhombus are 16 cm and 12 cm Then, the length of the side of the rhombus is(a) 9 cm(b) 10 cm(c) 8 cm(d) 20 cnm

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79873.

A wheel makes 360 revolutions in one minute. Through how many radians doesit turn in one second?3.

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1 minute = 60 seconds. Revolutions in one second = 360/60 = 6. 1 revolution = 2 radians. 6 revolutions = 12 radians.

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thanks 😊..right answer

79874.

:A wheel makes 360 revolutions in 1 minute.Through how many radians does it turn in 1, second?tion:

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79875.

3. A wheel makes 360 revolutions in one minute. Through how many radians doesit turn in one second?nglesutended at the centre of a circle oi

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Number of revolutions made by the wheel in 1 minute = 360∴Number of revolutions made by the wheel in 1 second =360/60 = 6In one complete revolution, the wheel turns an angle of 2π radian.Hence, in 6 complete revolutions, it will turn an angle of 6 × 2π radian, i.e.,12 π radianThus, in one second, the wheel turns an angle of 12π radian.

79876.

physical change is

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Aphysical changeis anychangein matter that involves the substance going from onephysicalstate to another. ... Examples ofPhysical changes: 1. Ice melting involves achangefrom a solid to a liquid and the substances maintain the properties of water because the molecules neverchange. 2.

physical change is a reversible

79877.

In a cricket match, a batswoman hits a boundary 6 times out of 30 balls she plays. Findthe probability that she did not hit a

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79878.

(D) 139. In Pig. the length of PR is:12 cm4 em3 em5 cmFig. 3(B) 26 em(A) 20 em(C) 24 cm

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79879.

2. In a trapezium MUST, TS 11 MU. The perimeter of the trapeziumis48 cm. If one of the parallel sides is twice the other and the sum ofthe two non-parallel sides is 21 cm, find the two parallel sides

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79880.

2. In a trapezium MUST, TS I MU. The perimeter of the trapezium is48 cm. If one of the parallel sides is twice the other and the sum ofthe two non-parallel sides is 21 cm, find the two parallel sides.MZL

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79881.

. I mu ie length ot each of the parallel sides.7. The area of a trapezium is 180 cm2 and its height is 9 cm. If one of the parallel sides islonger than the other by 6 em, find the two parallel sides.

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79882.

areoflengths10cmeach.Find the area of the trapezium.The parallel sides of a trapezium are 30 cm and 23 cm and non-parallel sides are 6.5 cm and 7.5 cm.Find the area of the trapezium18.

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79883.

10. The areas of a rectangle and a square are inthe ratio 3:2. If the length of the rectangle isdoubled and the side of the square is tripled,find the ratio of their new areas. 3

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We know that Area of rectangle = length * breadth

We know that Area of square = a^2.

Now,

Given that ratio of area of rectangle and area of square is 3:2.

= > (lb)/(a^2) = 3/2. ------ (1)

(i)

Given that length of rectangle is doubled = 2l.

Area = (2l)(b) = 2lb.

(ii)

Given that Side of square is tripled = 3a.

Area of square = (3a)^2 = 9a^2.

Now,

Ratio of areas:

= > (2lb)/9a^2

= > (2/9) * (lb/a^2)

= > (2/9) * (3/2) {From (i)}

= > 1/3

= > 1 : 3

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thanks

79884.

. What is the magnitude of the gravitational force between theearth and a 1 kg object on its surface? (Mass of the earth is6 x 104 kg and radius of the earth is 6.4 x 10° m.)

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79885.

A wheel, 14 cm in diameter, makes 3000 revolutions per minute. Find its speed

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79886.

14. Mass of the Earthof the Earth is 5.97 x 1024 kg and mass of the Moon is 7.35 x 104 kg. What is thedifference of their masses?nascost 104 kg and mass of the Moon is 735 * 102 kg what is the

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Mass of the earth =(5.97*10 to the power 24 )kg= (597.00*10 to the power 22)kg.

Mass of the moon=(7.35*10 to the power 22)kg.

Total mass of the two=(597*10 to the power 22) kg+(7.35*10 to the power 22) kg.=(597+7.35)10 to the power.22kg.

=604.35*10 to the power220 kg.

79887.

¡hel(a) IfNeeraj had walked 1 km/hr faster, he wouldhavetaken 10 minutes less to walk 2 km. Find the rateof his walkingor

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79888.

Nandini's house is 1 km from her school. She walked some distance and then10took a bus forkm to reach the school. How far did she walk?

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Total distance from house to school= 9/10 kmLet distance covered by walking= x kmAs per given conditionx + 1/2 = 9/10x = 9/10 - 1/2x = (9-5)/10x = 4/10 = 2/5

She walked 2/5 km

79889.

The area of a rectangle having breadth 20 cm is 1200 cm2. What is thekilo- perimeter of the rectangle?(1) 160 cm(2) 120 cm(3) 100 cm(4) 80 cm

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79890.

In a cricket match, a batswoman hits a boundary 6 times out of 30 balls she plays. Findthe probability that she did not hit a boundary.

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79891.

'The parallel sides of a trapezium are 20 cm and 13 cm. Its non-parallel sides are 10 cm each. Find thearea of trapezium.,

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154.6 h ieas ka ans

79892.

In a cricket match, a batswoman hits a boundary 6 times out of 30 balls she plays. Findthe probability that she did not hit a boundary

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79893.

3.The parallel sides of a trapezium are 20 cm and 13 cm. Its non-parallel sides are 10 cm each. Find thearea of trapezium.

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sorry but this answer is wrondg the right answer is coming154.11

79894.

The line parallel to parallel sides of a trapezium passing through mid points of slant sidesdivides trapezium in the ratio 5:2. Then ratio of parallel sides is(A) 1 1(C) 12:1(B) 13:1(D) can't say

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How can Find The Ratio of their Heights???

79895.

(1) Sum of the squares of two successive positive numbers is 452. Find the numbers.[Ans. Op

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79896.

pobd pur fhour with which the boy is cycling17. The diameter of the driving wheel of a bus is 140 cm. How many revolutions per minute mustthe wheel make in order to keep a speed of 66 km per hour ?

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79897.

Hence, the diameter of the wheel is 70 cm.eel of a bus is 140 cm. How many recolutionseel make in order to move at a speed of oper minute must a wper hour?

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yes it is

79898.

Ange įr divided at DLe.th0壍BD%BC..2.

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GIVEN:BD = 1/2 DCCONST:Draw a line ⊥ BC, AE⊥ BCLet AE = h (Ht. ofΔABC)∵ BD + DC = BCBD + 2BD = BC3BD = BCBD = 1/3 BCAr.ΔABD = 12× BD× AE = 1/2× (1/3 BC)× AE= 13× 12 = BC× AE= 13× Ar. ABC

79899.

Mass of earth is 15.97 x 104 kg and mass of moon is (7.35 x 104kgWhat is the total massof the two?

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79900.

she didn't use.Milton can walk 1 1 km in an hour. Find the distance travelled by him inMilton can walk 1km in an hour. Find the distance travelled by hinhours.tance travelled by him in-hours.

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dist = speed× time = 3/2×3/4 km = 9/8 = = 1.125 km

distance=speed x time = 3/2 × 3/4 = 9/8=1.125