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951.

Find the distance of the point (-1, -5, -10) from the pointof intersection of the line 7 = (2-ſ+2) + 2(3î +4j+2)and the plane F. (î-f+h)=5.INCERT)

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952.

Find the distance of the point (-1, -5,-10) from thepoint of intersection of the line 2i-+2k+2(31 +4+2k) and the plane F (-j+K) 5.

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953.

Find the distance of the point (-1, -5, -10) from the point of intersectionof the liner-(2i-j+2k)+4 3i+4j+ 2k)and the plane r(i-j-k)5

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954.

28. Find the distance of the point (-1, -5,-10) from the point of interseetion of the tine2i-+2+A(3i+4j + 2k) and the plane T. (-3+k)-.

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955.

The length of the diameter of the circle which touches the x-axis at the point (1, 0) and passes throughthe point (2, 3) is:\begin{array}{llll}{(1) \frac{10}{3}} & {(2) \frac{3}{5}} & {(3) \frac{6}{5}} & {\text { (4) } \frac{5}{3}}\end{array}

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956.

10. Find equation of the plane passing through the line of intersection of the planes x + y + zand 2x + 3y + 4z-5 = 0 and the point, (1, 1, 1).

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957.

Multiple Choice QuestionsChoose the right answer from the options given after every questionThe three angle bisectors of a triangle are concurrent. Their point of concurrencecalled the ....(1) circumcentre (ii) apex (11i) incentre (iv) point of intersection.E' m (?)" () ()" (1v()The simplest form of 5+03 (1) 5(i)(iv)+YISThe solution of the equation 3x0()(i) 4(iv)Which of the following expressions has the value 37?(1) 10 * 3+(5+2) (ii) 10 x 4+ (5 - 3)iii) 8 x 4+3(iv) (9 3) +2

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958.

(c) 60 = 6(d) 24 = 4(g) 18 = 2 (h) 48 = 6(k) 81 - 9(1) 56 = 8and check your answer.(C) 92 = 4 (d) 66 = 2(g) 96 = 8 (h) 84 = 6(k) 99 = 5(1) 78 = 7it Number

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(1 1 + 10 square of 1 + cot square bracket equal to 1 by sin square A minus sin by 4

959.

\frac{30}{4 \sqrt{3}+3 \sqrt{2}}=4 \sqrt{3}-a \sqrt{2}value e a

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960.

5. A cuboid is 50 cm x 20 cm x 27 cm. Will its volume be thesame as that of a cube of side 30 cm?cm

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yas

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50×27×20 = 2700030×30×30 = 27000

volume of cuboid=50x20x27=20000cm³volume of cube=30³=27000no the volume is not the same

volume of cuboid=50x20x27=27000cm³volume of cube=30³=27000cm³yes they have same volume

961.

If the median of the distribution given below is 28.5, find the values of x and y.Class intervalFrequency0-1010- 2020 3030- 4040-5050 60Total201560

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962.

ABCD is a trapezium in which AB llDC, DC = 30 cm and AB-50 cm. If X and Y arerespectively the mid-points of AD and BC, prove that:ar(quad. DCYX) =ar(quad. XYBA)

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963.

दी गई आकृति का क्षेत्रफल ज्ञात कीजिए।50 cm60 cm40 cmA30 cm B

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area of this figure = length×breadth

180 cm is the answer

964.

243Mensurationa quadrilateral ABCD, AB 28 cm, BC 26 cm, CDAC-30 cm. Find the area of the quadrilateral.cm, CD 50 cm, DA 40 cm and diagonal50 cm,0.50 cmA 28 cm BAACD)Area of quad. ABCD (area of AABC)+ (area ofHint.

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thank you

965.

—6.16 में, यदि ४ +.2 1 + 2 है, तो सिद्ध कीजिए,. कि 08 एक रेखा है।

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thanks

966.

4A school auditorium is 50 m long and 30 m wide. This auditorium is surroundedbyaverandah5mwide on the outside of it. Find the area of the verandah. If tiles of 50 cm x 50 cm are fixed on theverandah, how many tiles will be required?

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Length of the veranda = 50m = 5000cmBreadth of the veranda = 30m = 3000cmArea of the veranda = l*b = 5000cm*3000cm = 15000000cm.sq

Area of tiles = 50cm*50cm = 2500cm.sq

Total no of tiles required = 1500000/2500 = 6000

967.

2 tan 30°| + tan” 30° «6०० जि करA) sin60° * (08 e

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[2(1/√3)]/[1+1/3]=[2(1/√3)]/[4/3]=√3/2It is equal to sin60°So, option A is correct

968.

&£o e ९ जगाT ks T o

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4 3/8 = 35/8 2 1/2 = 5/2 6 1/4 = 25/4 म.स. = (5×5×7)/2 = 175/2

969.

Rt R T T ie e ks s s Smz-. {an Ao यु दम न कला (डर ;e

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numerator=L(denominator)+m(derivative of denominator)

ie.

sinx=L(sinx+cosx)+m(cosx-sinx).................. eq 1

sinx=Lsinx+Lcosx+mcosx-msinx.

sinx=(L-m)sinx+(L+m)cosx.

comparing coeffecients of sinx and cosx on LHS AND RHS.

l-m=1 and m+m=0.

solving we get L=1/2,m=-1/2.

put sinx if form of eq 1

question is:

∫(L(sinx+cosx)+m(cosx-sinx))/(cosx+sinx)

=∫Ldx+∫m(cosx-sinx)/(sinx+cosx)dx

=(1/2)x-(1/2)log(sinx+cosx)

Putting limits

ans is:pi/4 -(1/2)*0=pi/4 (take sinx+cosx as t so (cosx-sinx)=dtso∫1/tdt=logt=log(sinx+cosx)

970.

.4.Find the area of the following polygon, ifAL-10 cm, AM-20 cm, AN-50 cm,A0%-60 cm and AD = 90 cm20 cm60 cm30 cm40 cm

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971.

three tankers contains 103 l & 43 l and 465 l petrol respectively. find maximum capacity of the container then measure them exact no. of times.

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972.

- % ks lsin F — sin~! (- अ3 2N%W eकि हू हिलo1

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sin(π/3 - sin⁻¹(1/2) )

We know that sin30 =sinπ/6 = 1/2

π/6= sin⁻¹(1/2)

So,

=sin(π/3 - sin⁻¹(1/2) )

=sin(π/3 - π/6 ) = sin(π/6)= 1/2

973.

\begin{array} { l } { 31 x + 43 y = 117 } \\ { 43 x + 31 y = 105 } \end{array}

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974.

1.The expression-cos(x-2) tan-simplifies to3R(D) cos x(C) -(1 cos x)--,72-car 47-sin, 43·sin2 107 is equal to-(B) sinx

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{tan(x-π/2).cos(3π/2+x)-sin³(7π/2-x)}/{cos(x-π/2)tan(3π/2+x)}=[tan{-(π/2-x)}.cos{(π/2×3)+x}-sin³{(π/2×7)-x}]/[cos{-(π/2-x)}.tan{(π/2×3)+x}=[-tan(π/2-x).sinx-(-cosx)³]/[cos(π/2-x).(-cotx)]=(-cotx.sinx+cos³x)/[sinx.(-cotx)]=[-(cosx/sinx).sinx+cos³x]/[sinx.(-cosx/sinx)]={-cosx(1-cos²x)}/(-cosx)=1-cos²x=sin²x

975.

Find the values of a and b for which the following holds:\left[ \begin{array}{rr}{4} & {2} \\ {3} & {-1}\end{array}\right] \left[ \begin{array}{l}{a} \\ {b}\end{array}\right]=\left[ \begin{array}{c}{-4} \\ {2}\end{array}\right]

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976.

08%2 x0.3403°x0.32+0.35 3

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977.

\begin{array}{l}{2^{x}=3^{y}=6} \\ {08 \frac{1}{x}+\frac{1}{4}+\frac{1}{2}}\end{array}

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978.

2 6, 18794 2 08

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2*3=6

6*3=18

18*3=54

Thus we can conclude that the ratio of any term with the previous term is 3.

The first term of this series is 2

The second term of this series is 2*3

The third term of this series is 2*3*3

Thus we can write the general term of this series nth term=2*(3^(n-1))

so putting 8 in place of n we get

2*(3^7)=4374

P.S. this type of series is called ageometric progression.

979.

Find value de Pゐach that (m)Poafaste, de the

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980.

3In the given figure, DEBC, DE | | BC and the distance between DE and BC is 3 units.If BC = 6 units, what is the area of ΔBCE?

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981.

KS toTe cost him ? 10 less. How many books did he buy. If he had bought 4 more books for the sameProve that if a line is drawn parallel to one side of a trthe other two sides in distinct points, then the other two sides are dividedin the same ratio.iangle to intersectIn Fig. 2, DE 11AC and DFIIAE.Prove that:The mean of the following fremmBF BEFE EC25.

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BASIC PROPORTIONALITY THEOREM (BPT) : If a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points then the other two sides are divided in the same ratio. That is also known as Thales theorem.SOLUTION:

GIVEN:In ∆BAC, DE || ACBE/EC = BD/DA………..(1)

[ By Thales theorem(BPT)]

In ∆BAE, DF || AE (GIVEN)BF/FE = BD/DA………..(2)

[ By Thales theorem(BPT)]

(From eq 1 and 2)BF/FE = BE/ECFE/BF = EC/BE [reciprocal the terms]

Hence proved.

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982.

2.A:force of 200 N acts on a body for 10 s andgives it a velocity of 40 ms Find the mass ofthe body

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F=mdv/dtm=200*10/40m=50kg

983.

गा R e ली e e A लिन नि_3 3 ऊाएव 8 ७ ७-७ शोन e s 6x+47 पाए 1) (x-T) (x-9)=195(vi) 10x—- है =3,x#0e l 4 X # ——2 9 6

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please like my answer if you find it useful

Thanks

984.

77 8475>-0=10/sNow, arrange the given numbers in ascending order.34 5 2q 8 7 6/ 10574/"(5 1028// 5 6 2 39 71 4 10

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1,2,3,4,56,7,8,9,102,3,4,5,61,4,7,9,10

The ascending order is in order of thier occurence1,2,3,4,56,7,8,9,102,3,4,5,61,4,7,9,10

985.

१० है, तो दूसरी छ।4.टो संज्ञाओं का योग 11009 है। यदि एक संख्या 9999 है(2) 1010(3) 21008(?) 2110

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1010 is the correct answer of the given question

option (2) is the right answer

986.

the temperature at 12 noon was 17 degree Celsius above 0. if It decreases at the rate of 2 degree Celsius per hour until midnight, would the temperature be 3 degree Celsius below 0.

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987.

24. Without stoppages, a train travels certain distancewith an average speed of 80 km/h, and withstoppages, it covers the same distance with anaverage speed of 60 km/h. How many minutes perhour the train stops ?(a) 15 min/h(b) 20 min/h(c) 25 min/h(d) 30 min/h

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988.

. Without stoppage, a train travels a certain distancewith an average speed of 50 km/h, and with stoppage,it covers the same distance with an average speed of40 km/h. On an average, how many minutes per hourdoes the train stop during the journey ?(a) 20 min/h (b) 15 min/h (c) 10 min/h (d) 12 min/h

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Since, the train travels at 60 km/h, it's speed per minute is 1 km per minute. Hence, if it's speed with stoppage is 40 km/h, it will travel 40 minutes per hour i.e. train stops 20 min per hour.

989.

Q4 if the co-ordinates of the point of intersection of less than ogive and more than ogive is (14.5,20),then findthe value of median.

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The median for the coordinates of intersection point of less than ogive and more than ogive will be-The median of grouped data is the x-coordinate of the point of intersection of the two ogives. Here, the ‘less than ogive’ and ‘more than ogive’ intersect at (14.5, 20).so, median = 14.5

990.

NameMultiplesIn 1 through 8, write five multiples of each number1.52. 33.7445.96. 27.6in 9 through 16, tell whether the first number is a multiple of thesecond number.9. 21.710. 28.311. 17.313. 54.914. 15,515. 26,417. Circle the number in the box that is a multiple of 8.10182024313618. Number Sense List five multiplesfor 3 and five multiples for 4. Thencircle the common multiples.19. Reasoning What numberfactors of 2 and and12 and 18720. What are five multiples of 9?A 9, 19, 29, 39, 49 B 9, 18, 27, 36, 45 C 1,3,9,18,27 D 1,9,18,213821. Carmen listed the multiples of 6 as 1,2,3, and 6.Is she correct? Explain why or why not.P113

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17)24,3618)3,6,9,12,15 multiples of 3 4,8,12,16,20 multiples of 4Common multiples=1220)B21)yes,1,2,3,6 are multiples of 6 because they divide 6

1- 5,10,15,20,252- 3,6,9,12,153- 7,14,21,28,354- 4,8,12,16,205- 9,18,27,36,456- 2,4,6,8,107- 6,12,18,24,308- 8,16,24,32,409- yes10- no11- no12- yes13- yes14- yes15- no16- yes17- 2418- Multiples of 3= 3,6,9,12,15 Multiples of 4= 4,8,12,16,20 Common multiple = 12

20- B21- It ' s wrong because these are factor of 6 not multiples of sixmultiples of 6= 6,12,18,24,30......

991.

Write first five multiples of 200.

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200,400,600,800 and 1000

0, 500, 1000, 1500, 2000, 2500, 3000, 3500, 4000, 4500, 5000, 5500, 6000, 6500, 7000, 7500, 8000, 8500, 9000, 9500, 10000, 10500, 11000, 11500, 12000, 12500, 13000, 13500, 14000, 14500, 15000, 15500, 16000, 16500, 17000, 17500, 18000, 18500, 19000, 19500, 20000, 20500, 21000, 21500, 22000, 22500, 23000, 23500, 24000, 24500, 25000, 25500, 26000, 26500, 27000, 27500, 28000, 28500, 29000, 29500, 30000, 30500, 31000, 31500, 32000, 32500, 33000, 33500, 34000, 34500, 35000, 35500, 36000, 36500, 37000, 37500, 38000, 38500, 39000, 39500, 40000, 40500, 41000, 41500, 42000, 42500, 43000, 43500, 44000, 44500, 45000, 45500, 46000, 46500, 47000, 47500, 48000, 48500, 49000, 49500, 50000.

992.

Write the first five multiples of 5.

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First 5 multiples of 5 are: 5, 10, 15, 20, 25.

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993.

1010: 10 :105. 5 विन:10.5 - 7.5

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Please like the solution 👍 ✔️

3. plz like my answer

994.

Find the mean of first five multiples of 3.

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995.

Q1. Write the first five multiples of 12

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just do 12 times 1 then 2 then 3 all the way to 5

996.

.............. is the mean of first five multiples of 3.

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997.

1010+1010

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1010+ 1010= 2020

998.

1. Find the mean of first five multiples of 3.

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999.

2 cos*(45°+0)+ cos®(45° - 9I 60. Evaluate: “tan (60°7 6 tan (30°=8) +cosec (75° + 8) - sec (15° - 0). [CBSE 2011] |

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LHS = cos ²(45°+ϴ) + cos²(45° - ϴ) / tan(60° +ϴ) tan(30 - ϴ) = 1= sin²[90° - (45°+ϴ)]+ cos²(45° - ϴ) / cot [90° - (60° +ϴ)] tan(30 - ϴ) [ Cosϴ= sin(90°-ϴ) & cot ϴ= tan (90°-ϴ)]= sin²(45°-ϴ)+ cos²(45° - ϴ) / cot 30° - ϴ)] tan(30° - ϴ) = 1/1 = RHS[ sin²ϴ + cos²ϴ= 1 and tanϴcotϴ=1]

1000.

“पथ otEvaluate : cos” (45°+0) + cos” (45°—8)tan (60% i 9) tan (30% 9 ग+ cosec (75° + 0) — sec (15° — 6)

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