InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1101. |
(e) of these(d) Can't be determined[Panjab & Sindh Bank PO 2A water tank has three taps A. B, C Tap A, when opened, can fill thewater tank alone in 4 hours. Tap B, when opened, can filled the watertank alome in 6 hours and tap C when opened, can empty the watertank alone in 3 hours. If taps A B and C are opened simultaneouslyhow ong will it take to fill the tank completely ?(a) 10 hours(b) 8 hours(c) 18 hourspo11 |
|
Answer» 1 hr capacity by A,B,C=1/4 +1/6 -1/3=1/12So tank will be filled completely in 12 hours |
|
| 1102. |
8. Five bells ring after time interval of 6 secs, 8 secs, 12 secs, 45 secs respectively, if they stetringing together at 7am, then they will ring again together after:b) 6 minc) 7 min2d) 1 min 19 sec.a)3 min |
| Answer» | |
| 1103. |
\sqrt 18 %2B \sqrt 55 - \sqrt 32 %2B \sqrt 16 - 9 ! |
|
Answer» √18+√55-√32+√16as √16=4√18+√55-√32+4√18+√55-√36√36=6√18+√55-6√18+√49√49=7√18+7√25=5 |
|
| 1104. |
2. Find the ratio of 2 min 6 sec to 3 min 54 sec in thesimplest form.Ans |
| Answer» | |
| 1105. |
if the roots of the equation 2x^2 + 7x + 4 = 0 are in the ratio p : q, then find the value o\sqrt{\frac{p}{4}}+\sqrt{\frac{9}{t}}+-7/root2+-r root2+-7root2/16+=7root2/4 |
| Answer» | |
| 1106. |
q ( y ) = 3 y ^ { 3 } - 4 y + \sqrt { 11 } \text { at } y = 2 |
|
Answer» q(2)=3(2)^3-4(2)+root(11)=24-8+root(11)=16+root(11) |
|
| 1107. |
-3/4 %2B 3/8 %2B 4/7 |
|
Answer» 3/8 -6/8 +4/7=(3-6)/8 +4/7=(-3)/8 +4/7=(-21+32)/56=11/56 11/56 is correct answer 11/56 is the correct answer of the given question 11/56 is the answer for the question. correct answer is 11/56 The answer of this question is 11/56 |
|
| 1108. |
4 %2B 3*8 %2B 4*16 |
|
Answer» √2⁴+3√64+4√2^8=√16+3√64+4√256=4+3(8)+4(16)=4+24+64=92 92 is the right answer |
|
| 1109. |
(p %2B 1/p)^2=m^2 %2B 4 |
|
Answer» p^²+1/p^²= m^²+2 is the correct answer of the given question |
|
| 1110. |
-3 - 1 - 2 %2B 4*8 %2B 55 |
|
Answer» first add negative and positive numbers then subtract lesser from greater then you answer you get is 81 the correct answer is 18 4×8-2-1+55-332-2-1+55-387-2-1-387-2-487-681 clrrect answer |
|
| 1111. |
\frac{p}{q}=\left(\frac{2}{5}\right)^{4} \div\left(\frac{2}{5}\right)^{2} \text { find the value of }\left(\frac{p}{q}\right)^{-3} |
| Answer» | |
| 1112. |
(2*p %2B q %2B 5)^2 |
|
Answer» We know, (a + b + c)^2 = a^2 + b^2 + c^2 + 2ab + 2bc + 2ca Hence, (2p + q + 5)^2 = (2p)^2 + q^2 + 25 + 2*2p*q + 2*q*5 + 2*5*2p = 4p^2 + q^2 + 25 + 4pq + 10q+ 20p = (2p + q)^2 + 5(4p + 2q + 5) |
|
| 1113. |
\frac{2}{3}(p+1)-\frac{3}{5}(p-2)=3 |
| Answer» | |
| 1114. |
(sqrt(p - 2) - sqrt(p %2B 2*q))/(sqrt(p - 2*q) - sqrt(p %2B 2*q)) |
| Answer» | |
| 1115. |
\frac { 3 p - 2 } { 5 } - \frac { p } { 3 } = 8 |
| Answer» | |
| 1116. |
36I tall U,1) 4acIfx2-3x+2 is a factor of f(x) = x4-pr+ q, then (p, q) =2) a23) 2b37.4) (5, 4)2) (4, 5)d eauations:h and c is |
| Answer» | |
| 1117. |
\left. \begin array l p ( y ) = y ^ 2 - y %2B 1 \\ p ( x ) = x ^ 3 \end array \right. |
|
Answer» i)p(y) = y² - y + 1 p(0) = 0 - 0 + 1 = 1 p(1) = 1² - 1 + 1 = 0 p(2) = 2² - 2 + 1 = 3 iii)p(x) = x³ p(0) = 0 p(1) = 1³ = 1 p(2) = 2³ = 8 |
|
| 1118. |
gamma %2B p %2B q=0 |
|
Answer» p=10 q=20 r=-30 p+q+r=0 p= 10 q = 10 r= - 20 is the correct answer p=10 q=20 r=-30p+q+r=0 right answer. p=10,q=20, r=-30 is right answer 30 is the correct answer |
|
| 1119. |
(f*y)/((5*sqrt(2))) %2B 2*(2*sqrt(2)) - 12*sqrt(2) %2B 4*(8*sqrt(2)) |
|
Answer» 5root(2) + 2root(8) - 3root(32) + 4root(128) = 5root(2) + 4root(2) - 12root(2) + 32root(2) = 41 root(2) - 12 root(2) = 29 root(2) |
|
| 1120. |
-(-3*sqrt(5) %2B 7)/(-sqrt(5) %2B 3) %2B (3*sqrt(5) %2B 7)/(sqrt(5) %2B 3) |
| Answer» | |
| 1121. |
(3*p)*(4*p^2 %2B 5*p %2B 7) |
|
Answer» (4p² + 5p + 7) × 3p = 12p³ + 15p² + 21p |
|
| 1122. |
EU AUTUVUSICCOLIAccording to a survey of 50,000 students under mid day meal in fivedistricts of Rajasthan, 60% students like Pulses- Chapati, 25% likevegetable and chapatti and rest like khichdi. Determine percentage ofstudents who like khichdi? |
|
Answer» Answer: 15% Step-by-step explanation: 60% of students like pulses-chapati and 25% of students like vegetable and chapati Total number of student is 50000=100% %of students who like khichdi=100%-(%of students who like pulses and chapati +%of students who like vegetable and chapati). % of students like khichdi=100%-(60+25) =100%-85% =15% 15% is the right answer My friend answer is = 15% The percentage of students who like pulses - chapati is, 60 And The percentage of students who like vegetable and chapati is, 25 so, 60% + 25% = 85% total percentage of students, obviously 100 so, 100% - 85% = 15% 15% students like khichdi total students=50000total percentage=100%student who like pulses-chapati=60%student who like vegetable and chapati=25%percentage of student who like khichdi=(100-60-25)% =15% =(15/100)x50000 =7500 15% is correct answer. |
|
| 1123. |
(2*p %2B 5*p - 7)/(9*p - 4*p - 3)=7/6 |
| Answer» | |
| 1124. |
17*((2*p %2B 5*p - 7)/(9*p - 4*p - 3))=7/6 |
| Answer» | |
| 1125. |
9 x ^ 2 - 9 ( p %2B q ) x %2B ( 2 p ^ 2 %2B 5 p q %2B 2 q ^ 2 ) = 0 |
|
Answer» Like my answer if you find it useful! |
|
| 1126. |
2*q^2 %2B 2*p^2 %2B 5*(p*q) %2B 9*x^2 - 9*x*(p %2B q)=0 |
| Answer» | |
| 1127. |
x^p/(x^p %2B x^q) %2B 1/(x^(p - q) %2B 1) |
|
Answer» slots pic SC SC ice ab ice WC in WC in TV Web WC October WC on SC to 1 is the correct answer of the given question is |
|
| 1128. |
-4*a*q %2B 3*(a*p) %2B 16*q^2 %2B 9*p^2 - 24*p*q |
| Answer» | |
| 1129. |
(sqrt(-12*i %2B 5) %2B sqrt(12*i %2B 5))/(-sqrt(-12*i %2B 5) %2B sqrt(12*i %2B 5)) |
| Answer» | |
| 1130. |
((-(-2 %2B 3 %2B 5))/2)/(-Abs(-8 %2B 5)/3 %2B Abs(-3 %2B 5)) |
| Answer» | |
| 1131. |
(-6*5^(n %2B 2) %2B 5^(n %2B 4))/(-4*5^(n %2B 1) %2B 9*5^(n %2B 1)) |
| Answer» | |
| 1132. |
10)What is the probability of occuring four Wednesdays in 23 consecutive days in amonth? |
|
Answer» Let’s assume the 1st is a Wednesday. Seven days later, the 8th is also a Wednesday Seven more days, the 15th is also a Wednesday Seven more days, the 22nd is a fourth Wednesday, falling within the same month. The same will occur if the 2nd is a Wednesday, the fourth will fall on the 23rd. Or if the 3rd is a Wednesday, the 24th The 4th? The 25th. The 5th? The 26th The 6th? The 27th The 7th? The fourth Wednesday will fall on the 28th In every case, within your 23 consecutive day period. No month contains fewer than 28 days, so every month will always have a configuration with 4 Wednesdays falling within a 23 day period |
|
| 1133. |
5^(-x %2B 2) %2B 5^(x %2B 1)=1 %2B 5^3 |
| Answer» | |
| 1134. |
Find four consecutive terms in an A.P. whose sum is 12 and sum of 3l anis 14(Assume the four consecutive terms in А.Р. are a-d, a, a + d, a + 2d.)f 3d and 4h term |
|
Answer» thank you so much |
|
| 1135. |
ud four consecutive terms in an A.P. whosemis 12 and the sum of the 3rd and 4th termsis 14.tlan four consecutive terms in an A.P. |
|
Answer» The answer is -3,1,5,9 |
|
| 1136. |
iort10. Following temperature was recorded for three consecutive days:Tuesday 33.5°CWednesday 40.2°CThursday 38.3°C0) Find the difference between temperature on Thursday and Tuesday.(0) Find the sum of temperature for the three days. |
|
Answer» Tuesday temperature = - 33.5 c Wednesday temperature = - 40.2 c Thursday temperature = - 38.5 c 1) Difference between Thursday. and Tuesday temperature = (-38.5) - (-33.5) = - 38.5 + 33.5 = - 5 c 2) Sum of 3 days temperature = (-33.5) + (-40.2) + (-38.5) = - 112.2 c |
|
| 1137. |
Rice consumed in a school under the mid-day meal program for 5consecutive days is 15.750 kg, 14.850 kg, 16.500 kg, 14.700kg, and 17.700 kg. Find the average rice consumption for the 5days. |
| Answer» | |
| 1138. |
Rice consumed in a school under the mid-day meal program for 5consecutive days is 15.750 kg, 14.850 kg, 16.500 kg, 14.700kg, and 17.700 kg. Find the average rice consumption for the 5 days. |
|
Answer» average=total rice/no of days=15.750+14.850+16.500+14.700+17.700/5=79.500/5=15.900 |
|
| 1139. |
. Aboy cycles x km at 8 km/hr and y km at 20 km/hr. His total time is 3.5 hours. Thetotal time taken to cycle (2x + 4) km at 8 km/h andx and V.ăăźkm at 20km/h is 5 hours. Find |
| Answer» | |
| 1140. |
A train leaves Srinagar at 9:20am and reaches Jammu at 7:25pm The total time taken during the journey will be . |
|
Answer» The total time taken is( 2 hr 40 mins+7 hr 25 mins)=10 hr 5 mins |
|
| 1141. |
.Twotaps,runningtogethercafillabathin4minutes,whichisfilledbyonefeaps, running together can fill a bath in 4 minuminutes. How long would it take, if the other pipe is ruming by itsel?lich the floors of a huildino in İ 2 days. A alone can doof this job in 4 days,nodays. n |
|
Answer» Two taps running together can fill a bath in 4 minutes. Two taps running together can fill 1/4th of the bath in 1 minute. One tap alone can fill the bath in 7 minutes. Therefore it can fill 1/7th of the tap in 1 minute. The second tap alone can fill 1/4 - 1/7 of the tap in 1 minute. i.e., 3/28th of the tap in 1 minute. That is second tap alone can fill the tap in 28/3 minutes = 91/3 minute how did 7 cane |
|
| 1142. |
173Time and Workcan finish a piece of work in 16 days and 12 days respectiveand worked at it for 2work.ays. He was then joined by B. Pind the total time taken to finish thew |
|
Answer» thanks |
|
| 1143. |
of distance x km with a speed of 4 kmph and the remaining distancewith a speed of 5 kmph. If the total time taken for the journey is 56 minutes, then x= |
|
Answer» let the distance be xin first case, distance =2x/3speed =4time =distance /speed =2x/3/4 =x/6now in second case ,distance =x - 2x/3 =x/3speed =5time =distance /time = x/3/5 = x/15and, given total time =56 x/6 +x/15=565x+2x/30=567x/30=56x=240 sorry, it mistake from total Time =56/607x/30=56/60x=8/2x=4 |
|
| 1144. |
Q3. A kite is flying at a height of 60 m above the ground. The stringattached to the kite ts temporarily tiel to a point on the ground.The inclination of the string with the ground is 60°. Find the lengof the string, assuming that there is no slack in the string. |
| Answer» | |
| 1145. |
17. A(1, 2, (3, 4) (5), which of the following is true ?(A) (3, 4)CA (B) 3 A(C) n(A) 5 (D) (5) E A |
|
Answer» As set {5} belongs to A option (D) is correct |
|
| 1146. |
How many different words can be formed with the letters of the word HARYANA? Howmany of these:(i) have H and N together(i) begin with H and end with N?(i) have three vowels together? |
| Answer» | |
| 1147. |
व तात कीनिट] हित Catb)n+ Ca-b)y = 2 |
|
Answer» Here,(a + b)x + (2a - b)y = 21 2x + 3y = 7 A/c to question , infinity many solutions possible , so, (a + b)/2 = (2a - b)/3 = 21/7 (a + b)/2 = 21/7 = 3 (a + b) = 6 ------(1) again,(2a - b)/3 = 21/7 = 3 (2a - b) = 9 --------(2) solve equations (1) and (2) 3a = 15 a = 5 and b = 1 hence, if a = 5 and b = 1 then , infinitely many solutions possible of given equations. |
|
| 1148. |
a = b b-c c-a16-c ca a-b=0ca amb bec |
|
Answer» c1 is fillup by c1+c2+3 |
|
| 1149. |
A, B and C together earn 300 per day, while Aand C together earn R 188 and B and C togetherearm ? 152. The daily earning of C is:1S . |
|
Answer» Daily earning of A + B+ C = 300.....(1)A + C = 188......(2)B + C = 152......(3) Add eq(2) and eq(3) A + B + 2C = 188 + 152 = 340 Subtract eq(1) C = 340 - 300 Daily earning of C = Rs 40 |
|
| 1150. |
A class starts at 10: 00 am lasts till 1 : 27 pm. Fourperiods are held during this interval. After everyperiod, 5 min rest are given to the students. The exactduration of each period is(a) 40 min(c) 51 min[RPSC 2013](b) 48 min(d) 53 min |
|
Answer» Total time between 10:00 am to 1:27 pm = 3 hrs 27 min= 3*60 + 27= 180 + 27= 207 minutes Now let duration of each period be x Then,4x + 15 = 2074x = 207 - 15 = 192x = 192/4 = 48 Therefore duration of each period is 48 minutes (b) is correct option |
|