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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1401. |
iv) Rational numbers cannot be compared.c |
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Answer» Rational numbers can be compared. The term ratio is derived from the word ratio, which means the comparison of two quantities and expressed in simple fraction. A number is said to be rational if it can be written in the form of a fraction such as p/q where both p (numerator) and q (denominator) are integers and denominator is a natural number (a non-zero number). Integers, fractions including mixed fraction, recurring decimals, finite decimals, etc., are all rational numbers. |
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| 1402. |
\tau %2B x \varepsilon = ( z %2B x g ) x \cdot z |
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Answer» x(3x + 2) = 3x^2 + 23x^2 + 2x = 3x^2 + 22x = 2x=1 |
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| 1403. |
L I = S %2B x g ( ! ) |
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Answer» Like if you find it useful thanks |
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| 1404. |
( i ) p ( x ) = 2 x ^ 3 %2B x ^ 2 - 2 x - 1 , g ( x ) = x %2B 1 |
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Answer» 0 is correct answer g(x)=0x+1=0x=-1 now, p(-1)=2*(-1)³+(-1)²-2*(-1)-1= -2+1+2-1= 0 |
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| 1405. |
\left. \begin array l \text nust be added to f ( x ) = 4 x ^ 4 %2B 2 x ^ 3 - 2 x ^ 2 %2B x - 1 \text so that the \\ \text e by g ( x ) = x ^ 2 %2B 2 x - 3 ? \end array \right. |
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Answer» p( x )= 4x⁴+ 2x³- 2x²+x -1 g(x )= x²+2x-3 x²+2x-3)4x⁴+2x³-2x²+x-1(4x²-6x+22 4x⁴+8x³-12x²______________________-6x³+10x²+x -6x³-12x²+18x___________________ 22x²-17x-1 ____________________-61x+65 The remainder = -61x +65 Now we have to add 61x -65 to p(x) So that the resulting polynomial is divisible by g( x ) Like my answer if you find it useful! |
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| 1406. |
\left. \begin array c 0 = L - k L - x g \\ I I %2B C g = x L \end array \right. |
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Answer» 7x - 8y = 11x = 11 + 8y/7...........(1)8x - 7y = 7................(2) Put value of x from eq(1) in eq(2) 8*(11 + 8y)/7 - 7y = 788 + 64y - 49y = 4915y = -39y = - 39/15 = - 13/5 Put value of y in eq(1)x = (11 + 8*(-13/5))/7x = (55 - 104)/35 = - 49/35x = - 7/5 |
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| 1407. |
f ( x ) = x ^ 4 - x ^ 2 - 12 cis ^ \circ g ( x ) = x %2B 2 |
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Answer» 16-4-12=> 12+1224. |
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| 1408. |
tual division, determine which of the following rational numbers have aa decimal representation and which have a non-terminating decimal2 Without actual divisterminating decimarepresentation.126(vii)(V)45 |
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Answer» denominator which have 2^m 5^n are terminating decimals is the correct answer of the given question |
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| 1409. |
(g*l)*Integral(dx/((x^2*(x^4 %2B 1)^(3/4))), x) |
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| 1410. |
12. Without doing any actual division, find whichof the following rational numbers haveterminating decimal representation16 |
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Answer» l choose option (I) 7/16 The answer of this question is 2,5,6,7,8 the easy method to solve is that denoninator is divisible by 2 and 5 |
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| 1411. |
[HOTS)5. Without dividing the numerator bydenominator, find which of the followingrational numbers have the terminatingdecimal representation : |
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Answer» option (iii) 17/45 is the rational number have the terminating decimal representation decimal represention of (3)= 17/45 (iii) 17/45 . . 17/45 is the correct answer of the given question option (3) is the rational number have terminating decimal representation |
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| 1412. |
511500Has the rational numbernating or a non-terminating decimalrepresentation?, a termi[CBSE Foreign 2009] |
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Answer» 51/1500 51/ (15 × 100) 17/( 5 × 100) 0.034 Terminating Decimal representation |
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| 1413. |
2The digit at the tens place of a two-digit number is 3 times the digit at the units place. If the digitsare reversed, the new number will be 36 less than the original number. Find the number |
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| 1414. |
10*2/5+23*11/20+13*7/10=? |
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Answer» 10*2/5+23*11/20+13*7/10=4+253/20+91/10=515/20=103/4=25.75Ans |
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| 1415. |
hucr.Check your12. The digit in the tens place of a two-digit number is three times that in the units place. If thedigits are reversed, the new number will be 36 less than the origtnal number. Find theoriginal number. Check your solution. |
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| 1416. |
1.Decimal representation of a rational number cannot be-a). Terminating2 b) Non-terminating c)Non-terminating Repeatingd) Non-terminating Non-Repeating |
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Answer» option D is the answer |
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| 1417. |
MCQ1. The decimal representation of 150 is(a) a terminating decimal(b) a nonterminating, repeating decimal(c) a nonterminating and nonrepeating decimal(d) none of these2. Which of the following has a terminating decimal expansion?!q and r satisfyingtheCE of two3. On dividing a positive integer by 9, we get 7 as remainder. What will |
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Answer» THE ANSWER OF 1st QUESTION IS OPTION (c). THE ANSWER OF wst QUESTION IS OPTION (b). 1.c2.d are the right answers |
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| 1418. |
A storekeeper sells a book at 15% gain. Had he sold it for 18 more,he would have gained 18%. Find the cost price of the book.5, |
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| 1419. |
1500+ 4500 - 2500-A500 +1 |
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Answer» 4500+4500-4500-4500+1=1 1 is the best answer 1 is the correct answer. the answer to the question is 1 4500+4500-4500-4500+1=1 1 is the right answer 1 is the correct answer questions right answer 1 1 is the correct answer 1 is the correct answer both + 4500 and - 4500 cancelled each other and answer is 1 1 is the best answer 1 will be the answer the best answer is 1 1 is the best answer 1 is the correct answer hey .mate he is your answer your answer is 1 1 is the correct answer 4500 + 4500 - 4500 - 4500 + 1= 9001 - 9000 = 1 answer is onehow simple |
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| 1420. |
115. A shopkeeper sells an article at15% gain. Had he sold it for : 18more, he would have gained 18%.The cost price (in ?) of the article is(A) 540(C) 600(B) 318(D) 350 |
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Answer» Let Cost price of article be CP Then selling price of articleSP = CP(1 + 15/100) As per given conditionCP(1 + 15/100) + 18= CP(1 + 18/100) CP(18/100 - 15/100) = 18CP(3/100) = 18CP = 1800/3CP = 600 Therefore cost price of article is Rs 600 (C) is correct option |
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| 1421. |
18. I bought a certain number of apples at three for 5 paise, andfive-sixths of that number at four for 5 paise;, by selling them ateleven for 20 paise, I gained 15 paaise: how many apples did I buy? |
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Answer» Let number of apples bought = x Then,Cost price of apples = (x)*5/3 + (5x/6)*5/4 Selling price of apples= x*20/11 As per given condition20x/11 - 5x/3 - 25x/24 = 15(480x - 40x - 275x) = 15*264165x = 15*264x = 15*264/165x = 264/11x = 24 Therefore, total number of apples bought = 24 |
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| 1422. |
7. Manish gained 15% by selling a old taxi foră43470, Find the cost price of the car. |
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| 1423. |
8. Using the rearrangement property find the sum:84 3 2113 5 3 513 11 -5 7-ㄧㄧ-+20 14 7 1067(iii)(iv)+--+ |
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Answer» thanks |
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| 1424. |
18. A merchant bought two cows for Rs 500. Hesold one cow at 12% loss and the other at 8%gain. In this transaction he neither lost norgained. What was the cost price of each cow?A. Rs. 300 and Rs. 200B. Rs. 200 and Rs. 300C. Rs. 175 and Rs. 325D. Rs. 240 and Rs. 260 |
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Answer» B is the answer for the question hope you like this bye |
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| 1425. |
Ll edil - 20 quiresby selling goods for 3432. 10% of their cost is gained, at what price should they have% of their cost is gained at what price should they have been sold soto gain 20%? |
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Answer» I couldn't understand the question 6864 as the double of 3432 |
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| 1426. |
3. Mr. Jones sold two pipes at $1.20 each. Basedon the cost, his profit one was 20% and his loss onthe other was 20%, on the sale of the pipes, he:(a) broke even, (b) lost 4 cents, (c) gained 4 cents,(d) lost 10 cents, (e) gained 10 cents |
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Answer» 20 % profit on $ 1.20 = $ 20/100 × 1.20 = $ 0.20 × 1.20 = $ 0.24 Similarly, 20 % loss on $ 1.20 = $ 20/100 × 1.20 = $ 0.20 × 1.20 = $ 0.24 Therefore, in one pipe his profit is $ 0.24 and in the other pipe his loss is $ 0.24. Since both profit and loss amount is same so, it’s broke even. |
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| 1427. |
9761 -3 5Arrange the following rational numbers in ascending order!4 5 7 -2-912–18' 34 -12' 16'-24-4 -9 13 -233 -7 -11 -13(iv) 7 14' -28' 425 to 15 20 |
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Answer» the answer is 4: -5, and the option is 1) |
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| 1428. |
5 \frac { 3 } { 5 } + \frac { 8 } { 15 } - \frac { 7 } { 20 } + \frac { 1 } { 12 } |
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| 1429. |
s Using thee rearrangement property find the sum:3 4 6 83 5 3-13 11 5 720 14 7 105-6 -5 4 1576 97-14isfind the othesof the numbers is |
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| 1430. |
The denominator of a rational number is leanumerator than S. If 5 is added to the mumeratorthe new number becomes. Find the original rational 1 |
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Answer» 6/1is the original rational number |
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| 1431. |
4. In a two digit number, the ten's place digit is three times the digit in unitsplace. If the digits are reversed, the new number becomes 36 less than theoriginal number. Find the number. |
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| 1432. |
\log _{e} x+\log _{e}(1+x)=0 |
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| 1433. |
\left[ \begin{array} { c c c } { 1 } & { 3 } & { 1 } \\ { 3 } & { k } & { 6 } \\ { - 1 } & { 5 } & { 1 } \end{array} \right] |
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Answer» for A matrix to be non- invertible , The determinant should be zero . => 1(k-5*6) -3(3*1+6*1) +4(5*3+k) = 0=>. k-30 -27 +60+4k = 0=> 5k + 3 = 0=> k = -3/5. |
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| 1434. |
(v) S.P. =1600 and Loss = 400 |
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| 1435. |
(x-y)^{3}+(y-z)^{3}+(z-x)^{3}=k(x-y)(y-z)(z-x) \text { then }\left(\frac{k-1}{2}\right)^{2018} |
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| 1436. |
1600 +1500=? |
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Answer» 1600 + 1500 = 3100. this is the Wright answer 3100 is the answer hope it helps you 3100 is the answer hope it helps you 3100 is the answer of this equation 3100 is the correct answer for above ques 3100 is the right answer. 3100 answer very easy question 3100 is the correct answer 3100 is the correct answer |
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| 1437. |
š.The denominator of a rational number is greater than its numerator by 7. If the numeratoris increased by 17 and the denominator decreased by 6, the new number becomes 2. Findthe original number |
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| 1438. |
35) The sum of a two-digit number and the number formed by interchanging the digits is 132. If 12 is addedto the number, the new number becomes 5 times the sum of the digits. Find the number. |
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| 1439. |
1764 = 1600 ( 1 + \frac { 5 } { 100 } ) ^ { T } |
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| 1440. |
13. The denominator of a rational number is greater than its numerator by 7. If the numeratois increased by 17 and the denominator decreased by 6, the new number becomes 2. Findthe original number. |
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| 1441. |
The ten's digit of a two digit number exceeds its unit's digit by 5. When digits arereversed, the new number added to the original number becomes 99. Find the originalnumber |
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| 1442. |
re of third child = 8 of 581-䞣:581) =147mple 13 Divide 1870 into three parts in such a way that half ofird of the second part and one-sixth of the third part are all e |
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Answer» Let parts be x,y,zx+y+z=1870x/2=y/3=z/6x:y=2:3y:z=1:2x:y:z=2:3:6x=2×1870/11=340y=510z=1020 |
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| 1443. |
What is that least number which is wheradded to 52,792, the new number becomesperfectly divisible by 15? |
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Answer» After dividing 52792 by 15 , We get the remainder = 7 The quotient = 3519 . Then multiply 15 by 3520 . The product we get = 52,800 Subtracting 52792 from 52800 , We get the difference = 8 So if we add 8 to 52792 it will exactly divide by 15 . The required Answer is 8 . 8 must be added to 52792 for making it a multiple of 15. Like my answer if you find it useful! |
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| 1444. |
15. DivideR 1870 into three parts so that half of the first part, one-third of second part and one-sixthof the third part are equal. |
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| 1445. |
\left[ \begin{array} { c c } { x + y } & { 2 } \\ { 5 + z } & { x y } \end{array} \right] = \left[ \begin{array} { c c } { 6 } & { 2 } \\ { 5 } & { 8 } \end{array} \right] |
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| 1446. |
\left[ \begin{array} { l } { 2 } \\ { 5 } \\ { 6 } \end{array} \right] = \left[ \begin{array} { c } { z + x } \\ { z + x } \\ { z + x + k } \end{array} \right] |
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Answer» comparing the termsX+y+z=9---1X+z=5------2y+z=7------3adding 2 and 3X+y+2z=12hence X+y=12-2zput this value in eq 112-2z+z=912-z=9z=3hence X+z=5X=5-3=2and y+z=7y=4 |
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| 1447. |
\left. \begin array c z %2B K = \varepsilon %2B K z \\ z = L - x \varepsilon \end array \right. |
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Answer» 3x - 7 = 23x = 9x = 9/3 = 3 2y + 3 = y + 22y - y = 2 - 3y = - 1 |
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| 1448. |
\left[ \begin{array} { c c c } { x } & { y z } \\ { y } & { y ^ { 2 } } & { z x } \\ { z } & { z ^ { 2 } } & { x y } \end{array} \right] = ( x - 4 ) ( y - 2 ) ( 2 - x ) |
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| 1449. |
\left[ \begin{array} { c c } { x + y } & { 2 } \\ { 5 + z } & { x y } \end{array} \right] = \left[ \begin{array} { l l } { 6 } & { 2 } \\ { 5 } & { 8 } \end{array} \right] |
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Answer» by comparing both the matrixx+y=6 and xy=8 so y=8/xx+8/x=6x*x-6x+8=0(x-2)(x-4)so if x=2 then y=4if x=4 then y=25+z=5 so z=0 thanx |
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| 1450. |
\begin{array}{c}{\text { Prove that: }} \\ {x^{\text { log } y-\log z} \cdot y^{\log z-\log x} \cdot z^{\log x-\log y}=1}\end{array} |
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Answer» It is wrong answer |
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