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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 2201. |
Write the next term of the A P3, v12, v27, 48, . |
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| 2202. |
1. If nth term of a sequence is 4n2 +1, find the sequence Is this sequence an AP. ? |
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Answer» Given Tn=4n²+1 T1=4(1)²+1=5 T2=4(2)²+1=17 T3=4(3)²+1=37 So the terms 5,17,37,…….. with no common difference So it is not an AP |
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| 2203. |
2If nih term of a sequence is 4n2 + 1, find the sequence. Is this sequencean A.P. |
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Answer» n=1,a1=5n=2,a2=17n=3,a3=37d=a2-a1=17-5=12d=a3-a2=37-17=20This is not in A. P, because common diffrence is not same. Put n=1then a1=4(1)^2+1=5n=2then a2=4(2)^2+1=4*4+1=17a3=4(3)^2+1=36not an ap as the common difference is not equal. sequence and series lesson 1, -1, -1, 1, - 1 the sequence 1 statement for this sequence my 1,-1,1,-1 these qns series |
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| 2204. |
uTheAihmacci sequence is difinedmaeo sequence is Cuttimedim |
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| 2205. |
1) Write an arithmetic sequence with common difference 7• Write it's algebraic formCan 150 is a term of this sequence• Can the difference between any two terms of this sequence be 75 ? Why |
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Answer» 7,14,21,28,35....... i. a,a+d,a+2d,a+3d.....ii. no 150 will not be the term of this ap because it not divided by 7iii no there difference cannot be75 |
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| 2206. |
Example 17: Solve2 4 3 2 |
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| 2207. |
17 < 2 \frac { 1 } { 4 } \times 1 \frac { 3 } { 5 } + 2 \frac { 3 } { 4 } \div \frac { 1 } { 4 } - 1 \frac { 3 } { 4 } |
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| 2208. |
2 ^ { - 1 } [ ( \frac { 5 } { 3 } ) ^ { 4 } + ( \frac { 3 } { 5 } ) ^ { - 2 } ] \div \frac { 17 } { 9 } |
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| 2209. |
1. In each example below. find the ratio of the first number to the second(1) 24,56 (2) 63.49 (3) 52.65 (4) 84, 60 (5) 35, 65 (6) 121, 99. |
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Answer» ) 3/7b) 9/7c) 4/5d) 7/5e)7/13f) 11/9 1)3/72)9/73)4/54)7/55)7/136)11/9 1 is the ratio of the first number to the second (1) 24/56 = 3/7 = 3:7(2) 63/49 = 9/7 = 9:7(3) 52/65 = 4/5 = 4:5(4) 84/60 = 7/5 = 7:5(5) 35/65 = 7/13 = 7:13(6) 121/99 = 11/9 = 11:9 1. 3/7/2 . 9/73. 4/54. 7/55. 7/1311/9 is the correct answer me a. 3/7b. 9/7C. 4/5d. 7/5e. 7/13f. 11/9 (1) 24/56=3/7=3:7(2)63/49=9/7=9:7(3)52/65=4/5=4:5(4) 84 /60=7/5=7:5(5)35/65=7/13=7:13(6)121/99=11/9=11:9 (1)24/56=3/7=3:7(2)63/49=9/7=9:7(3)52/65=4/5=4:5(4)84/60=7/5=7:5(5)35/65=7/13=7:13(6)121/99=11/9=11:9 |
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| 2210. |
1. In each example below, find the ratio of the first number to the second(1) 24, 56 (2) 63, 49 (3) 52, 65 (4) 84, 60 (5) 35, 65 (6) 121, 99 |
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Answer» (1) 24:56=3:7 (2) 63:49=9:7(3) 52:65=4:5(4) 84:60=7:5(5) 35:65=7:13(6) 121:99=11:9 ans. a) 3:7b) 9:7c) 4;5d)7:5e) 7:13f) 11:9 Neha is the best answer neha Gupta is right plz like |
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| 2211. |
2. Subtract the following:Guv) 13 - 133. Find the sum :(1}}+20+34. Find the difference(1) 4 - 2 2 - 2 3 3fiv) 16 - 175. Simplify the following: |
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Answer» (i) 1/11(iv) 3/13(i)15/2(i)13/6(iv)7/10 2 a = 1/112 b = 3/133 a = 15/24 a = 13/64 b = 7/10 (2). 6/11 - 5/11 =1/11iv) 7/13 - 4/13 = 3/13 3) (I)11/5+23/10+3 22+23+30/10 75/10 =7.5 (4) (I)5/2. -7/3 =15/6. -14/6 =1/6 iv)9/5. -. 11/10 =18/10. - 11/10 =8/10 = 0.8is the best answer |
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| 2212. |
2, 5, 11, 17, 23,(1)29 (2)3141.(3)37(4)39 |
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| 2213. |
38. In an examination, Ramesh scored 15 marks morethan Gurdas, whereas Leela scored 7 marks lessthan Gurdas in the same examination. If their totalscore is 83, find the marks scored by Gurdas- |
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Answer» 15 marks sry i was just checking the software whether the answer is posting or not Let marks scored by gurudas be xThen ramesh scored=x+15Leela scored=x-7Total score=83x+15+x+x-7=833x+8=833x=83-83x=75x=75/3x=25Therefore marks scored by gurudas is 25___________________________Hope this helps you Gurdas scored 61 15+7=2283-22=61 let marks of gurdas=xmarks of ramesh=x+15marks of leela=x-7now, x+x+15+x-7=833x+8=833x=83-8=75x=75/3=25marks scored by gurdas is 25 x+x+x+15-7=833x+8=83 3x=83-83x=75x=75/3x=25 The marks scored by gurudas- 25 |
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| 2214. |
15 less than the marks scored by Sunil is 55. How many marks did Sunil score? |
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Answer» marks scored by Sunil = 55+15=70 |
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| 2215. |
15 less than the marks scored by Sunil is 55many marks did Sunil score ? |
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Answer» Let the marks scored by Sunil be x. According to the question, x-15 =55 =>x =15+55 =>x=70 Hence, Sunil scored 70 marks. incomplete question |
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| 2216. |
9. Marks of 12 students in a unit test are given as 4, 21, 13, 17, 5, 9, 10, 20, 19,1214. Assume a mean and calculate the arithmetic mean of the data. Assume annumber as mean and calculate the arithmetic mean again. Do you getthe šame resComment |
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Answer» Assumed mean = 13a.mean = (4+21+13+17+5+9+10+20+19+12+20+14)/12(154)/1212.8assumed mean = 12.8a.mean = 154/12a.mean = 12.8 Yes i got the same result assumed mean is 12 |
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| 2217. |
0. 15 less than the marks scored by Sunil is 55. How many marks did Sunil score? |
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Answer» Let sunil score xaccording to the questionx -15 = 55x = 15+55 = 70Now,Marks scored by sunil is 70 |
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| 2218. |
8 (C)15 less than the marks scored by Sunil is 55. Howmany marks did Sunil score ? |
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| 2219. |
Marks2UKavitaSunilJasmine Murugan Amit AryanStudentsNow look at the bar graph and answer the following questions:a. Who scored the least marks?b. Who scored the highest marks?c. How many more marks did Murugan score than Jasmine?d. How many students scored more than sixteen marks?e. How many marks less did Amit score than Aryan? |
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Answer» hii a. Sutuil scored the least marks b. Kavita scored the highest marks. |
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| 2220. |
E 8 (C)10. 15 less than the marks scored by Sunil is 55. Homany marks did Sunil score? |
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| 2221. |
he following table gives the marks scored by 50 students in a class test0-50 50-100 100-150 150-200 200-250Marksumber of students2d the arithmetic mean marks scored by a student in a class test.81220SARASWATIMATHEMATICS-X |
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| 2222. |
r the maximum marks of 20, 50% of the students scored more than 15 marks and7. In a test, fothe rest 50% scored less than 15. Then the score 15, isa) Medianc) frequencyb) Meand) mode |
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| 2223. |
L ‘€ ) (T ‘o)l vl—R B RIy 2 I pcniery 1 lofeld T |
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| 2224. |
रस 2 SIS => MAB_- - NS D 26 LNSQ > S S Sa vl T + |
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Answer» a)64.32×100=6432b)2.068<2.680c)62/1000=0.062 hit like if you find it useful |
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| 2225. |
oEfl\& vl 9{ < QDH 1 1 > <fi’°3 q’g ‘ o ¢ ८) (व 21८ ) C’Q"éz %) 43 |
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Answer» Answer is 2Use property of logLog a b (log b base a)= logb/log a All terms will get cancel only log9/log 3 remainsIf u bring back to format and solve u will get answer. |
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| 2226. |
(vl)Show, that |
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Answer» (3x+7)^2-84x=9x^2+49+42x-84x=9x^2+49-42x....LHSnow RHS will be(3x-7)^2=9x^2+49-42xhence LHS=RHS |
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| 2227. |
e mean of marks scored by 100 students was ucovered that a score of 53 was misread as83. Find the correct mearir exgluded. the mean |
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Answer» thank u |
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| 2228. |
The mean of 20 observations Is 4. If one oservatt8. The mean marks secured by a student in five subjects is 75, If one more subject in which he securedt mrls otained hy 15 students is 63. If marks of two students were read wrongly 7372 marks is included, calculate the new mean |
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| 2229. |
I 2 8 vl 10 o टद कुछ हि 'डू ०५ 912 ही 14% (कवि हा T |
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Answer» Cost of 18 books = 216Cost of 1 book = 216/18 = 12 Therefore,Cost of 32 books = 12*36= Rs 432 |
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| 2230. |
uestions(FTATQ)Find the equations of the bisectors of the angles betweenthe co-ordinate axes |
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| 2231. |
2. Write the numbers in figures :(a) Twenty three thousand one hundred ten |
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Answer» 23110 is right answer 23,110 is right answer 23,110 is the answer 23,110bis the answer 23110 is the right answer 23,110 is right answer hi Anusha you study in Gyandeep Academy in Guwahati |
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| 2232. |
..... एकता९००८-0८: छू eपथ vl _लि -8 0 ७० पथ2. 80. ८.५0. +उर ९ स>६७-फ० Nyt पट ५९९७ <oM,’/ S = DT/’/ |
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Answer» InΔabe and inΔacdab =ac ∠B=∠C BE=CDBY SAS RULEΔABE≡ΔACDBY CPCTAE=AD |
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| 2233. |
(1) XLVI (2) VL (3) VLC (4) XXXV |
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Answer» 40=XL6=VISo,46=XLVI option 1 is correct |
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| 2234. |
5.Is the sequence 13, v6, +9, vl 2,form an Arithmetic Progression ? Give reason. |
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| 2235. |
tA tree is broken15 m from the base of the tree. Find the original height of the tree.ataheightofsmfromthegroundanditstoptouchesthegroundatadis |
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| 2236. |
After 15 years, Hema's age will become four times thatpresent age. |
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Answer» o |
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| 2237. |
) Ifa sum of money doubles itself at compound interest in n years,let us write in how manyyears will it become four times. |
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| 2238. |
Ifa sum of money doubles itself at compound interest in n years, let us write in how manyyears will it become four times. |
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Answer» clear nahin ho raha hai |
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| 2239. |
3 %2B 9 %2B 7 %2B 8 |
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Answer» 27 is the correct answer 27 is the right answer 27 is the right answer of the following 7+8+9+3= 27 right answer 7 + 8 + 9 + 3 = 27So 27 is the right answer. 27 is a correct answer 7 + 8 + 9 + 3 =27 is answer of following question the correct answer is 27 27 is answer if your sum is direct to add. 27 answers **************** , yaar ek dusre ka answer like kar diya karo |
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| 2240. |
3. Rajesh deposits a certain amount in abank which becomes three times of itselfin 16 years. Find the time required by thesame amount to become four times ofitselfat the same rate of interest, if the interest isnot compounded. |
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| 2241. |
-7/12 - 5/8 %2B 8/9 |
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| 2242. |
7/12 - 9/8 %2B 8*(5/6) |
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| 2243. |
6 %2B 2*(4/5) %2B 6*(8/9) |
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Answer» =(14/5)+(62/9)+(6/1)=(126+310+270)/45=706/45. ans. 706/45 is the following question answer 706/45is correct answer 706/45 is the answer 706/45 is the correct answer of the given question |
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| 2244. |
-4 %2B (3*5)/9 %2B 8 |
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| 2245. |
3. Rajesh deposits a certain amount in abank which becomes three times of itselfin 16 years. Find the time required by thesame amount to become four times of itselfat the same rate of interest, if the interest isnot compounded |
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Answer» amount becomes 3 times so I=2Pso 2P=(P×R×16)/100so R=12.5now amount becomes 4 times so I=3P3P=(P×12.5×N)/100 so N=24 years |
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| 2246. |
3/17+4/21 |
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Answer» 0.366946779 is the correct answer me 84.176 is the correct answer for me |
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| 2247. |
3. Rajesh deposits a certain amount in abank which becomes three times of itselfin 16 years. Find the time required by thesame amount to become four times of itselfat the same rate of interest, if the interest isnot compounded. |
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Answer» amount becomes 3 times so I=2Pso 2P=(P×R×16)/100so R=12.5now amount becomes 4 times so I=3P3P=(P×12.5×N)/100 so N=24 years |
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| 2248. |
Age of Ramanjeet's father is 49 years. Ifhis father's ageÄ°s4 years more than three times ofhis age. Findhisage.Hs old am E |
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| 2249. |
JAftab tells his daughter, "Seven years ago, I was seven timesold as you were thewill be." (Isn't thiastimes asAlso, three years from now, I shall be three times as old as youinteresting?) Represent this situation algebraically and graphically |
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| 2250. |
. A die is thrown 5 times. Find the probability that an odd number will come up exactly three times. |
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