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sinθ= 5/13 [Given]

∴cosecθ= 1/sinθ= 1÷ (5/13)

∴cosecθ= 13/5

We know that,

sin2θ+ cos2θ= 1

∴(5/13)2+ cos2θ= 1

∴25/169 + cos2θ= 1

∴cos2θ= 1 – 25/169

∴cos2θ= (169 – 25 )/169

∴cos2θ= 144/169

∴cosθ= ±√ (144/169)

∴cosθ= ±12/13

But,θis an acute angle [Given]

∴All trigonometric ratios must be positive,

∴cosθ= 12/13

secθ= 1/cosθ

∴secθ= 1÷ (12/13)

∴secθ= 13/12

tanθ= sinθ÷ cosθ

∴tanθ= 5/13 ÷ 12/13

∴tanθ= 5/13 × 13/12.

∴tanθ= 5/12

cotθ= 1/tanθ

∴cotθ= 1÷ (5/12)

∴cotθ= 12/5

1/18 + 1/18

1+1/18

2/18

1/9

Sol. 1/18+1/18=. 1/9

36*15*55/5*13*18

= 2*3*55/13

= 330/13

= 25.384615385

10

10

10

follow VBODMAS

Right answer

X=a.sec theta+b.tan theta ----------(1)y=a.tan theta +bsec theta-----------(2)

equation (1) and (2) squaring and then subtracting from (1) to (2)

x^2-y^2=a(sec^2theta-tan^2theta) -b (sec^2theta-tan^2theta)

we know sec^2x-tan^2x=1

nowx^2-y^2=a^2-b^2

a.

-2/3 x 6/7-12/21-4/7

e.

13/(-14) x -4/2652/36413/911/7

- 4 upon 7 answer first

thank u

tan^-1A+tan^-1B=tan^-1(A+B/1-AB)hencetan^-1(4x+6x/1-24x^2)=tan^-1(1) as tanπ/4=1hence10x/1-24x^2=110x=1-24x^224x^2+10x-1=0hencex=-10+-√100+96/48x=-10+-√196/48x=-10+-14/48hencex=-10+14/48=4/48=1/12andx=-10-14/48=-24/48=-1/2

tan^-1a-tan^-1b=tan^-1(a-b/1+ab)hencetan^-1(a/b-(a-b/a+b)/1+a/b(a-b/a+b)=tan^-1(a^2+ab-ab+b^2/a+b)/1+a^2-ab/ab+b^2)=tan^-1(a^2+b^2/a+b)/(a^2+b^2)/b(a+b))=tan^-1(1)=π/4

it is the answer above in the picture

yes

but how this step occurs

(-13)×23+(-13)×(-3)=-13{23+(-3)}=-13×20=-260 (Ans)

-13×23+(-13)×(-3)= -299+39= -260

A). +7/13B). 8/36it is the answer for this sum's

A composite number has more than 2 factors .Only composite numbers can be expressed in the form of product of two numbers other than 1 and itself .

= 7×11×13+13

= 13 ×( 7 × 11 + 1 )

= 1 × 13 × ( 7×11 + 1 )

7×11×13+13 can be expressed as product of other numbers

Therefore , 7×11×13+13 is a composite number

7× 6 × 5 × 4 × 3 × 2 × 1+ 5

= 5 ( 7× 6 × 4 × 3 × 2 × 1 + 1 )

= 1 × 5 × ( 7 × 6 × 4 × 3 × 2 × 1 + 1 )

As the expansion 7× 6 × 5 × 4 × 3 × 2 × 1+ 5 has more than two factors .Its a composite number. A prime numbers has only two factors, one and itself .A composite number has more than two factors

The answer of the question is 774

15√5-5√5+2√13-3√13=10√5-√13

A composite number has more than 2 factors .Only composite numbers can be expressed in the form of product of two numbers other than 1 and itself .

= 7*11*13+13

= 13 * ( 7 * 11 + 1 )

= 1 * 13 * ( 7*11 + 1 )

7*11*13+13can be expressed as product of other numbers

Therefore , 7*11*13+13 is a composite number

13 - (12- 6 ÷3)= 13 - (12- 2)=13- 10 = 3

13-(12-6÷3) =13-(12-2) =13-10=3

3 is the correct answer of the given question .

3 is the right answer

13-(12-6÷3) =13-(12-2) =13-10=3 ANS

=13(

13 - (12 - 6 ÷ 3)=13 - (12 - 2)=13 - 10=33 is the answer of the following question.

3 is the right one.......

3 is right answer...

3 is the right answrr

3 is the correct answer

A composite number is a positive integer that has a factor other than 1 and itself. Now considering your numbers,

7×11×13+13 may be written as, 13x{(7x11) + 1} i.e. 13x(78). So other than 1 and the number itself, 13 and 78 are also the factors of the number. Further, 78=39x2. So, 39 and 2 are also it's factors. So this number is definitely not prime. Hence its composite number.

Similarly, 7×6×5×4×3×2×1+5 can be written as 5x{(7x6x4x3x2x1)+1}, i.e. 5x(1009). So, other than the number and 1, it have 5 and 1009 as it's factors too. So it is also a composite number.

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tan^-1(X)+tan^-1(y)=tan^-1(X+y/1-xy)hencetan^-1((x-1/x-2)+(X+1)/X+2)/1-(x-1/x-2)*(X+1)/(X+2))=tan^-1(1)cancelling tan^-1 on both sideshencex^2+2x-x-2+x^2-2x+x-2/(x^2-4)-(x^2-1)=1-(2x^2-4/3)=12x^2-4=-32x^2=1x^2=1/2X=+-1/√2value of X is +-1/√2

2/ 1+x^2 is the correct answer of the given question is

ANSWER IS .. OPTION NUMBER IS 3.

let the number be xaccording to questionx+x+1+x+2=1263x+3=1263x=126-33x=123x=123/3x=41

(x+1)=(41+1)=42(x+2)=(41+2)=43

therefore the sum of first two number is= 41+42=83

hence the sum of first two numbers is 83 so option 'd' is correct

Mean = sum of observations /number of observations

250 = sum of observations /50

Sum of observations = 250*50= 12500

As given number 152 wrongly copied as 102 Then, Correct sum of observations = 12500 + 152 - 102= 12500 + 50 = 12550

Therefore, Correct mean= 12550/50= 251

please give me the answer

thanks dude

mean is 80.4 and total 50 so sum is 4020now 69 is wrong and 96 is correct so correct sum is 4020-69+96=4047so new mean=4047/50=80.94

Perimeter of quadrant = length of arc + 2* Radius

= pi r/ 2 + 2r

= 22*3.5/7*2 + 2*3.5

= 11/2 + 7

= 5.5 + 7

= 12.5 cm

Distance travelled = 710 kmTime taken = 10 hrs

We know Distance = speed * time Speed = Distance /time = 710/10 = 71 km/hr

Average speed = 71 km/hr

average speed

Incorrect Mean =X’ = 160

No of observations = 40

Incorrect Sum of observations =sum’= 160 x 40 = 6400

Correct sum of observations = = sum’ – 125 +165

= 6400 +40

= 6440

Correct mean = X = 6440/ 40 = 161

Given: Average height of 30 students = 150 cm

Mean height = (sum of heights of students)/(Number of students)

150 = (sum of heights of students)/(30)

Hence, Sum of heights of students = 4500 cm

Given: One observation is wrongly copied as 135 cm instead of 165 cm

Error in the entering the observation = 165 – 135 = 40 cm

Hence, correct sum of heights of students = 4500 +40 = 4540 cm

Correct mean height = 4540/30 = 151.33 (nearly)

thanks

A duma was a Russian assembly with advisory or legislative functions. The term comes from the Russian verb думать (dumat’) meaning "to think" or "to consider". The first formally constituted duma was the State Duma introduced into the Russian Empire by Tsar Nicholas II in 1905 after the revolt of people against him demanding for the elected assembly. The Tsar dismissed the first duma within 75 days and re-elected second duma within three months. It was dissolved in 1917 during the Russian Revolution. Since 1993, the State Duma is the lower legislative house of the Russian Federation.

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