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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 4551. |
section contains multiple choice questions. Each question has * choices (A), (B), (C), (D), outONLY ONE is correct: Choose the correct option.If B lies between A and C, AC = 15 cm and BC = 9 cm. Then the value of ABP is(A) 30 cm(B) 36 cm? (C) 20 cm(D) 26 cm |
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Answer» the value of AB² is 36cm² AB=15-9=6AB^2=36. ans. |
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| 4552. |
If AD/DB = 3/4 and AC = 15 cm, find AE. |
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Answer» basic proportionality theorem. If AD/DB = AE/EC 3/4 = AE/EC EC/AE = 4/3 (EC/AE)+1 = (4/3)+1 (EC +AE)/AE = 7/3 AC/AE = 7/3 15/AE = 7/3 AE = 15×3/7 AE = 45/7 thanks |
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| 4553. |
DandE are the points on sides AB and AC such that AB 7.5 em, AD 15 cm, AC-6 em andAE 1.2 cm. show that DE BC. |
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| 4554. |
Angle BAC of triangle ABC is obtuse andAB AC. P is a point in BC such thatPC 12 cm. PQ and PR are perpendicularsto sides AB and AC respectively. IfPQ 15 cm and PR 9 cm; find the lengthof PB. |
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| 4555. |
In the adjacent figure, ABCD is a rectangle. If BM and DN areperpendiculars from B and D on AC, prove that Δ BMC :l DNA. Is ittrue that BM DN?Hint. In triangles BMC and DNA, we have |
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| 4556. |
7.) In the given figure ZAPQLC If AQ9 cm, BP315 cm, find AC.cm and AP(A) 30 cm(B) 100 cm(C) 50 cm(D) 80 cm |
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| 4557. |
9. A contractor employed 210 men to build a house in 60 days. After 12 days, he was joined by70 more men. In how many days will the remaining work be finished?Hint. 210 men can complete the remaining work in 48 days. Find in how many days 280 men can do it. |
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| 4558. |
8. A and B can do a piece of work in 6 days, B and C do it in 10 days and Cand A do it in 15 days.(a) In how many days will A, B and C finish it working together?(b) In how many days will A and B finish their working alone?оде |
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| 4559. |
how manydayswas theworkcompletea?2A can do of a certain work in 16 days and B can do 4many days can both finish the work, working together?of the same work in 3 days. In how10. |
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| 4560. |
16 men can reap a field in 30 days. In how many days will 20 men reap thefield ?(a) 25 days(b) 24 days(c) 10 days d) 37 days |
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| 4561. |
v N ———— B R |A motorbike travels 330 km in 5 litres of petrol. How much(i) one litre of petrol ? (i) 2:5 litres of petrol ? |
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Answer» A motor bike travel in petrole 1 litre=330/5=66Then travel in 2.5 = 66×2.5= 165km |
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| 4562. |
If 20 men take 15 days to complete a job, in howmany days 25 men can complete the job?(a) 18.75 days(c) 12 days(b) 18.25 days(d) 10 days |
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| 4563. |
51. 12 men or 15 women can finish a work in 24 days.In how many days the same work can be finished by8 men and 8 women ?(A) 16 days (B) 20 days(C) 24 days(D) 28 days- days |
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Answer» b) 20 days you need 16 days |
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| 4564. |
(l) 13 articles2. A motorbike travels 330 km in 5 litres of petrol. How much distance will it cover in(0) one litre of petrol(ii) 2.5 litres of petrol? |
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Answer» A motor bike travel in petrole 1 litre=330/5=66then travel in 2.5 = 66×2.5= 165km |
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| 4565. |
A man on a tour travels the first 120 km at60 km/h and the next 120 km at 80 km/hWhat is the average speed of the journey? |
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| 4566. |
UL VICT5. Usha ran thrice around a rectangular park of length 275 m and breadth 180 m. Poonamaround a square park of side 95 m five times. What distance was covered by both of themcovered more distance and by how much? |
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| 4567. |
wide. Find the total length of carpel fequineu.11. A person walks at the rate of 4 km/hr. How long will he take to go round a square park 5 timesarea is 2500 m2? |
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Answer» Given area of square Park = 2500 = a² => side = √a = √2500 = 50mso, distance to be covered in 5 rounds of sqaure is = 5*(perimeter) = 5*(4a) = 5*(4*50) = 20*50 = 1000m = 1km now time taken = distance/speed = 1km/(4km/h) = 1/4 hr so, time taken is = 1/4hr or 60/4 = 15mins |
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| 4568. |
10. A room 7 m long and 6.5 m wide is to have the floor covered with carpet which is sold ina roll 50Gwide. Find the total length of carpet required.ill ho take to an round a square park 5 times, who |
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Answer» Total area of roll required is the area of the room i.e 7 m × 6.5 m = 45.5 m2 hence total number of rolls required is 45.5/0.5 = 91 carpets but how it come 0.5 wide is 50 cm |
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| 4569. |
Rohan watched a drama show that lasted 2 hours 10 minutes. If the show ended at5:50 p.m., at what time did it start? |
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| 4570. |
\begin{array} { l } { \text { If in } \Delta A B C \text { the ratio of the angles is } 1 : 2 : 3 , \text { then } } \\ { \text { prove that } a : c = 1 : \sqrt { 3 } : 2 } \end{array} |
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Answer» Let the angles be k, 2k and 3k. Then, k + 2k + 3k = 180° ⇒ 6k = 180° ⇒ k = 30° So, the angles are 30°, 60° and 90° Let x, y, and z denote the sides opposite to these angles. Then, x/sin 30° = y/sin 60° = c/sin 90° ⇒ x : y : z = sin 30° : sin 60° : sin 90° ⇒ x : y : z = ½ : √3/2 : 1 ⇒ x : y : z = 1 : √3 : 2. |
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| 4571. |
In the adjoining figure, BM丄AC andDN丄AC. If BM=DN, prove that ACbisects BD |
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| 4572. |
न —— >> । — 3का ang ५. #-९िशा: 5. हिल पी o sB bl e |
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Answer» Let x-1, x-4, x-7 are in ap. So find the value of x. To check whether these terms are in AP (x-4) - (x-1) = (x-7) - (x-4) = d = common difference => x - 4 -x + 1 = x - 7 -x + 4 => -3 = -3 So these terms are in AP for any given value of x with common difference = -3 If these terms are in GP then (x-4)/(x-1) = (x-7)/(x-4) = r = common Ratio => (x-4)² = (x-7)(x-1) => x² + 16 - 8x = x² -8x + 7 => 16 = 7 which is not possible hence these terms can not be in GP for any value of x Like my answer if you find it useful! |
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| 4573. |
Rohan watched a drama show5:50 p.m., at what time did it start?that lasted 2 hours 10 minutes. If the show ended at |
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| 4574. |
In the adjoining figure, BM and DN are perpendiculars tosegment AC. If BM DN, prove that AC bisectsBD.Hint: ΔΒΕΜΔDEN by AAS.TRIANGLES |
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Answer» DE=EBProof In tri EMB AND tri ENDangle EMB=END (each 90)"""""" MEB=NED (VOA)side BM=DN(given)BY A AS Congruencey:;triEMB congruent tri ENDso BE=DE (cpct)proved |
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| 4575. |
5. In the adjoining figure, BM L AC andDN IAC. If BM = DN, prove that AC /bisects BD. |
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| 4576. |
35) 3240 Seconds minutes |
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Answer» 60 seconds=1 minute1 second=1/60 minute3240 seconds=(1/60)×3240 minutes 3240 seconds=54 minutes |
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| 4577. |
5. Draw a line segment AB of length 6.5 cm. Ateach end of the line segment AB, draw a lineperpendicular to the line AB. Are these two linesparallel ? |
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Answer» no, 2 opp perpendicular lines can't be parallel or a square would be called a parallelogram. |
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| 4578. |
Example 3. The projections of a line segmenton the axes are 3, 4, 12 respectively. Find thelength & direction cosines of the line segment. |
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| 4579. |
Draw3AB. Write steps of construction.15a line segment AB-12 cm and by ruler and compasses, obtain a line segment of length |
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Answer» drow the line segment a,b= cm |
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| 4580. |
Construct a line segment of length 10 cm. From this, cut a segment AC of length 4.9 cm. Measurethe remaining segment.4. |
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Answer» Point C would be 4.9 cm away from A, between points A and B on the line AB, so the answer is BC would be the rest of the 10 cm segment (10 cm - 4.9 cm = 5.10 cm). |
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| 4581. |
11. In Δ ABC and Δ DEF. AB-DE-ABI DE, BC-EFand BC I EF. Vertices A. B and C are joined tovertices D. E and F respectively (see Fig. 8.22).Show thatthe angó) quadrilateral ABED is a parallelogramfn) quadrilateral BEFC is a parallelogram(m) AD ICF andAD-CE(iv) quadrilateral ACFD is a parallelogram(v) AC#DF(v) Δ ABC Δ DEFecrighl angFig. 8.22other12, ARC |
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| 4582. |
he figure 10.13, ZA -75° and CE II AB. If ECD -40°, find the other two anghe triangle ABC.75°40°Fig. 10.13 |
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| 4583. |
2.50of 0.142. it son of Eureka wirein diameter as resistence of 314Findnate siadspecific resistence ofAngllom10 x 100 cma- 90s?0Veby?-XR. 2.SR |
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Answer» this question was very easy in class 7 the question was if I O N of a wire of 0.14 in diameter is 10.5 |
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| 4584. |
ind 4D andIn Fig. 10.43, ABCD is a trapezium such that Averify that sum of the four angles is 36070°40°Fig. 10.43Provethen it is a right triangle.that if one angle of a triangle is equal to the sum of the other twis triangle such that ZABC- LACB. Find the angtriangle135°CDFig. 10.444 LOCUSng the game of cricket, when a player hits the ball, it describes a path, bht or touching the ground. |
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Answer» If ABCD is isosceles trapezium such that m\CDA=3x , m/BAD=2x ,Find all angle |
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| 4585. |
3. The angles of a triangle are in the ratio l': 3:5. Find the measure of each of the ang |
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| 4586. |
p(x) = 5x2 +3x + 1,ang(x) = 2x\begin{array}{l}{\frac{5}{3} x-\frac{3}{2}, 1} \\ {\frac{5}{2} x-\frac{3}{2}, 2} \\ {3}\end{array}s.(B)x |
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Answer» Option (B) is correct. |
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| 4587. |
Fig. 10.13In Fig. 10.14, AB-8 cm, BC = 6 cm, AC-3 cm andthe angle ADC= 90°. Calculate CD18.SeconGivenTo prConstof8 cm为ˇ3 cmCMN | AProofB 6 cm C |
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| 4588. |
13. Find all the ange anglerl of i narallelogram are equal, then show that it is a rectanglo1. The angles of quadrilateral are in the ratio 3:5:9:andvertices D, E aShow thatquadrilateral.is a rectangle.0) quadrilateundrilat |
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| 4589. |
18. In Fig. 10.14, AB 8 cm, BC 6 cm, AC 3 cm andthe angle ADC 90. Calculate CD8 cm3 cmB 6 cm CFig. 10.14 |
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| 4590. |
18. In Fig. 10.14, AB 8 cm, BC-6 cm, AC 3 cm andthe angle ADC 90. Calculate CD8 cm3 cmB 6 cm CFig. 10.14 |
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| 4591. |
3. In AABC, ZB = 909,BC = 6 cm andAB = 8 cm, thenfind the radius ofthe circle.8 cm-_-6cm |
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| 4592. |
A game requires its players to runaround a square playground. Eachside of the playground is 20 m long.One player took 5 rounds around theplayground. How many metres did herun altogether? |
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Answer» Givenside=20mPerimeter of square = 4 x side= 4 x 20 = 80mIf he took 5 rounds if the playground he will run5 x 80m = 400m.Like if you find it useful |
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| 4593. |
wire needed tor iO7. A game requires its players to runaround a square playground. Eachside of the playground is 20 m long.One player took 5 rounds around theplayground. How many metres did herun altogether ? |
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Answer» Perimeter of square ground=4×side=4×20 m=80 m Metres covered in 5 rounds=5×80=400 m |
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| 4594. |
) 30.A manruns around a circle of diameter 100 mS at a speed of 12 km/h. then the time required totake 10 rounds of the circle will bepproximately):6 minutes35 minutesb) 25 minutesd) 46 minutes |
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Answer» Diameter =100mRadius=D/2=100/2=50mCircumference=2πr=2*22/7*50=314.28mHence in 10 rounds =10*314.28=3142.8m=3.1428kmSpeed=distance/timehence time=speed*distance=3.1428*12=3.77hrIn Minutes=3.77*60=25minutesoption b |
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| 4595. |
A man runs around a circle of diameter 100 mat a speed of 12 km/h. then the time required totake 10 rounds. of the circle will be(approximately)a) 16 minutesc) 35 minutesb) 25 minutesd) 46 minutes |
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Answer» If you find this solution helpful, Please like it. |
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| 4596. |
If we take 4 rounds around a field thatis 160 m long and 90 m wide, what isthe distance we walk in kilometres?4. |
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Answer» Perimeter=2(160+90)=2*250m=500m4rounds =500*4=2000mTotal distance(in kilometers)=2km As we know peri. 2(l+b)l=160m b=90mhence, 2(160+90) =500magain , given 4 rounds of feildtherefore, total distance = 500×4=2000 mand in 1000m=1kmtherefore 2000m= 2km |
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| 4597. |
. If we take 4 rounds around a field thatis 160 m long and 90 m wide, what isthe distance we walk in kilometres? |
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Answer» In one roundperimeter= 2(160+90)= 500 min 4 rounds= 2000mand 2 km |
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| 4598. |
d of the walking track in the park is 250 metres long. Ajit'sthe) One roundOwalks that path 4 times every morning. How many kilometres doeshe walk every day? |
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| 4599. |
Solve the Tonowing problems(1) One round of the walking track in the park is 250 metres long. Ajit'slometres doesgrandfather walks that path 4 times every morning. How many kihe walk every day? |
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| 4600. |
1hours every day. Find the ratio of the time she is awake to the timeA baby girl sleeps 12she is asleep. |
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Answer» total hours in a day =24so girl sleep =12 1/2so ratio is 1/1 total hours in a day=24she sleeps=12 1/2=25/2hencetime she doesn't sleep 24-25/2=48-25/2=23/2hence ratio will be23/2/25/2=23/25 |
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