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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 4451. |
A, B and C completed a work costing Rs. 1800. A worksheet for 6 days ,B worked for 4 days and C worked for 9 days .If their daily wages are in the ratio of 5:6:4 ,how much amount will be received by A? |
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| 4452. |
2. Cost price1900.2000,selling pricepotsel |
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Answer» Loss = Cost price (C.P.) – Selling Price (S.P.)=2000-1900=100 the answer is100 as 2000-1900 = 100 |
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| 4453. |
A and B can finish a piece of work in 16 days and 12 days respectively. A started theand worked at it for 2 days. He was then jotned by B. Find the total time taken to finiworkA can do a piece of work in 14 days while B can do it in 21 days. They began togetheworked at it for 6 days. Then. A fell ill and B had to complete the remaining work alohow many days was the work completed? |
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Answer» X could complete a piece of work in 16 hours and Y could complete the same work in 20 hours. they worked together for 8 hours and then Y left . Find the time required by X to complete the remaining work alone. |
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| 4454. |
轲37 AB, BC, CD 37R DAず啊ー储言(ii) PQ-SREI |
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| 4455. |
13. Two workers A and B workingtogether completed a job in 5days. If A worked twice as effi-ciently as he actually did andB worked as efficiently ashe actually did, the work wouldhave been completed in 3 days.To complete the job alone, Awould require |
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Answer» please like my answer then I like your answer to all of you please like my answer then I solve this question I know very well |
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| 4456. |
2200 to paint the inner curved surface of a cylindrical vessel 10 m deep.2312200 tIt costs0 imer curved surface area of the vessel,ii)capacity of the vessel.n cost of painting is at the rate of 20 per m', findhe coSel)(i) radius of the base, |
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| 4457. |
sel? |
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Answer» 1 km=1000mso total distance=9.180km+21.290km+2.230km=32.7 km=32 km 700 m |
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| 4458. |
137+5 conurst inh deui mols and sel/O o |
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Answer» 137+5/100=137+0.05=137.05 |
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| 4459. |
7. In the given figure, AB| CD | EF. Find the value of x.70°130° |
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| 4460. |
23) Simplify and find the value of the expression when x-y z-1:ai) (x ty+z)(x+y-z): i |
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Answer» x= y= z= 1 then(1+1+1)(1+1-1)= 3*2= 6 thanks |
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| 4461. |
If x. : y = 3 : 8 and y : z = 4 : 9 then find x : z. |
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Answer» Thanks dudes |
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| 4462. |
20. In the given igure, AB/CD/EF Find the value of x and y130 |
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| 4463. |
A polyhedron has 8 faces and 18 edges, find the number of vertices. |
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Answer» Euler's Theorem for polyhedra: F + V - 2 = E where F = # of facesV = # of verticesE = # of edges ==> V = E + 2 - F = 18 + 2 - 8 = 12 vertices |
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| 4464. |
\left. \begin{array} { l l } { \text { (A) } 10 } \\ { \text { (A) } 10 } \\ { \text { (C) } 14 } \end{array} \right. |
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| 4465. |
Ans. Sel. Prove by geometrical method 1+ tan2 A seA |
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Answer» Form a right triangle with angleθ. Letybe the side oppositeθ,xbe the side adjacentθ, and label the hypotenuser, wherer²=x²+y²(by theorem of Pythagoras |
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| 4466. |
NGRon no. 9-12: If a car can go 20 km using 1 liter of petrol and 50 km using theThen calculate the cost for both fuels for a distance of 10,000 km and compare the differencebetween their cost. To be done on A3 sheet).distancean place valueUPERVAVEESETANCELIER |
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Answer» Your correct answer is 200kg 200 kg is the right answer to your question I hope that my answer helped u in doing ur work If it helped then like the answer and accept as best |
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| 4467. |
104MATHEMATLINES AND ANIn Fig. 6.29, if AB II CD, CD Il EF and y: z 3:7,find x.6.7 AngleSIn the earlieof a trianglrelated to pTheoremProof : Iabove, thB prove. WA xi signs3. In Fig. 6.30, if AB II CD, EF L CD andFig. 6.294 GED-126°, find 2 AGE, 4 GEF and ZFGE.A G |
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Answer» answer of this question is 126° |
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| 4468. |
5 hours 10 minutes from 10 hours |
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Answer» 10 hr - (5 hr 10 min)=(9 hr 60 min) - (5 hr 10 min)= 4 hr 50 min |
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| 4469. |
In figure, AB II PQ II CD,AB x units, CD -y units andPQ z units. Prove that +3 |
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Answer» See the diagram. ΔABD andΔPQD are similar, as the corresponding sides are parallel. x/z = BD / QD => 1/x = QD /(z * BD) ΔCDB andΔPQB are similar, as corresponding sides are parallel. y/z = BD/ BQ => 1/y = BQ / (z * BD) Add the two equations: 1/x + 1/y = (BQ + QD) / (z * BD) = 1 /zPlease like the solution 👍 ✔️👍 |
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| 4470. |
if AB II CD, EF L CD and1. In Fig 6.30,GED 126 |
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| 4471. |
in Fig. 3.29, ifAB II CD, CD || EF andy : z-3 : 7,find x |
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| 4472. |
Find the area of the triangle, the lengths of vohosides are 18 cm, 24 cm and 30 cm. |
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Answer» s= 18+24+30/272/236then area will be√s(s-a)(s-b)(s-c)√36(36-18)(36-24)(36-30)√36*18*12*67776cm ^2 |
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| 4473. |
5. In a quadrilateral ABCD, AC and BD are diagonals. Prove thatAB+ BC+ CD> AD(ii) AB+BC+ CD+ DA 2BD(ii) AB-BC + CD + DA > 2AC(iv) AB + BC+ CD+ DA> AC+BD0ICSE Mathematics- IX |
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| 4474. |
6. In the adjoining figure, AB II CD and CD | EF.Answer the following questions:(i) Is L 1=22?Why ?(ii) is < 2 = < 3 ? Why ?(ii) Is AB || EF? Why?PA 70 |
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| 4475. |
3 : 7,An Fig. 6.29, ifAB II CD, CD || EFand y: z=3:7,find x.A. |
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| 4476. |
MATHEMATICS104In Fig. 6.29, if AB II CD, CD I EF and y:zfind x.3:7,2. |
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Answer» part 2 part 3 |
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| 4477. |
1. Find the area of a triangle whose sides are 18cm, 24 cm and 30 cm |
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Answer» Let a=18cm,b=24cm,c=30cm.Then, l=18cmb=24cmh=30cm s=√a+b+c/2 18+24+30/2 36cm using Heron's Formula √s(s-a) (s-b) (s-c) √36(36-18)(36-24)(36-30)√36.18.8.6√2.2.3.3.2.3.3.2.2.2.2.32.3.3.2.2√672√6cm2 area=72√6cm2 |
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| 4478. |
13. Three cubes having edges 18 cm, 24 cm and 30 cm respectively are melted and made into a newcube. Find the edge of the new cube so formed. |
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Answer» Ok |
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| 4479. |
\left. \begin array l l 10 cm & \text (B) 15 cm \\ 18 cm & \text (D) & 20 cm \end array \right. |
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| 4480. |
The hypotenuse of a right triangle is 10 cm and radius of the inscribed circle is 1 cmtriangle isa) 15 cmQ2.22 cmc) 24 cmd) 18 cm |
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| 4481. |
is b.(c) 182cme the diagonals of a rhombus are 18 cm and 15 cm. The area of the(d) 190 cm(a) 45.5 cmThe lengths of therhombus is(a) 270 cm(b) 135 cm?(c) 90 cm(a) 180 cm |
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| 4482. |
8.Amina buys a book for7275 and sells it at a loss of 15%. How much does she sellit for? |
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| 4483. |
MATHEMATICS8.Amina buys a book forit for?275 and sells it at a loss of 15%. How much does she |
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| 4484. |
Amina buysabokfore275 and sells it at a loss of 15%. How much does she sell |
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| 4485. |
DateCest their Votsthe(it |
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Answer» tqqq |
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| 4486. |
Today, 2:23 PMDIRECT AND INVERSE PROPORTIONQ1a varies directly as . Given that for y- 3, x-2. Find the value ofx when y-5Ir 5 persons can do a piece of work in 28 days, then find the number ofpersons to do the same work in 7 daysQ2.Ir 5 persons can do a piece of work in 28 days, then find the number of persons to dothe same work in 7 days.Q3.Convert the speed 63km/hr into m/secQ4.Convert the speed 48m/secinto km/hrQ5.Arun drives his car at 60km/hr. Find the distance he will cover in 2 hours 15seconds.Q6.68 boxes of certain cominodity require a shelf-length of і3.61n. How many boxesof the same commodity would occupy a shelf- length of 20.4 m?employed for digging 27m long trench of the same type in one day?epidemic. How long will the remaining food last?Q7. 11 men can dig 6 and 3/4 m long trench in one day. How many men should beQ8. 120 men had food provisions for 200 days. After 5 days, 30 men die due to an |
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Answer» Please crop a question you want to ask. plz give me all ans |
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| 4487. |
Juma's stride when running is 1 m 5 cm long. On school days he runs roundthe school field twice daily. The field is 450 m all the way round.(a) How many strides does he require to cover one complete round?(Give your answer to the nearest whole number.)How many km does he run in a week?(b) |
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Answer» a) Number of stride to cover one round = 450m/1m5cm =45000cm/105cm =428.57=429b) he run 900 m in a day so, he runs in a week = 7×900m = 6300m=6.3km |
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| 4488. |
how many years will ₹1800 require to eran ₹378 at 6% per annum? |
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Answer» principal(P)=RS 1800time (t)=?rate(r)=6%Simple Interest=378rssi=(P*R*T)/100378=1800*6*t/100t=3.5years. |
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| 4489. |
heJuma's stride when running is I m 5 cm long. On school daysthe school field twice daily. The field is 450 m all the way round.(a) How many strides does he require to cover one complete round?14.runs roundGive your answer to the nearest whole number.)How many km does he run in a week?(b) |
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Answer» a) Number of stride to cover one round = 450m/1m5cm =45000cm/105cm =428.57=429b) he run 900 m in a day so, he runs in a week = 7×900m = 6300m=6.3km |
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| 4490. |
Prove that : In a right angled triangle, thehypotenuse is the longest side. |
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| 4491. |
After running 4 rounds of a square field, a distance covered 16km. Find the length and area of the ground. |
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Answer» perimeter = 16/4 = 4 km length = perimeter/4 = 4/4 = 1 km Area = 1² = 1 km² |
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| 4492. |
z=e^{i \theta}, \text { show that } \frac{z^{2}-1}{z^{2}+1}=i \tan \theta |
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| 4493. |
A, B and C can separately do a work in 2, 6 and 3 days respectively. Working together,how much time would they require to do it? If the work earns them 960, how shouldthey divide the money? |
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| 4494. |
MUCH the pairs :Fraction on the number lineAns(3) TTTTTATI(4) TTDTTTTTTMATHEMATICS : SEMESTER II (BOOK 1) |
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Answer» (1)=5/10(2)=9/20(3)=7/10(4)=3/10 hope this will help you like my answer and Mark it as best answer (1)=5/10(2)=9/20(3)=7/10(4)=3/10 (1)=5/10(2)=9/10(3)=7/10(4)=3/10 1=5/102=9/203=7/104=3/10 |
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| 4495. |
b âZ e (X) 3 - |
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| 4496. |
MATHEMATICSAmina buys a book for?275 and sells it at a loss of 15%. How much does sheit for?8. |
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| 4497. |
) 15 hours into minutes. |
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Answer» 1 hour = 60 minutes15 hours=15*60=900 minutes |
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| 4498. |
-z_ E+xp |
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| 4499. |
Thelengthofthe perpendicular drawn from the point(3.-1,11)to the line x/2=(y-2)/3= (z-3)/4(a) √29 (b) √33 (c) √53 (d) √66 |
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| 4500. |
Find complete integral of the followingz=e^{a} |
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