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(4) Mile is not a unit of mass. It is a unit of distance.

kilogram is a unit of mass

6pipecanfillatank=60+20=80min​5pipescanfillatank=xmin​​∵Itisininverseproportion​6×80=5×x​x=​5​​6×80​​​x=96min​​Hence,Timetakenby5pipetofilltank=​​96min​​​​​​​​

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6 pipes = 60min 20min = 80min

5 pipes = x min

6*80 = 5*x

x=480/5 =96min

Number of pipes and time taken are inversely proportional.

That is, if number of pipes decrease then the time increases and vice versa.

Time taken by 6 pipes to fill the tank = 1hour 20min = 60+20=80min

Let the time taken by 5 pipes by y

As they are inversely proportional,

6×80=5×y

6×80/5 = y

96min= y

Time taken by 5 pipes to fill the tank= 1hour and 36minutes

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96 min is the correct answer of the given question

3 is the right answer...

gof=g(x^2) = x^2 + 2fog=f(x+2) = (x+2)^2 = x^2 + 4 + 4x

(7/27)+((8/3-11/6)/(7/3+7/6)=(7/27)+(((16-11)/6)/((14+7)/6))=(7/27)+((5/6)/(21/6))=(7/27)+(5/21)=(7/(3*9))+(5/(3*7))=((7*7+5*9)/(3*9*7))=94/189

a is the answer for this question

how

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61 is the longest side

61 is the correct answer

61 is the correct answer

61 is the longest side

Answer: b)9Explanation:

There are two possibilities. Either assume that ages can be in decimals too. Or, we say that the data given is not right.

Father + Son = 47 yearsFather - Son = 26 years

Sum both equations to get Father's age. Father = 73/2 = 36.5 years or 36 years 6 months.

So use the first equation to get Son's age. Son = 47 - 36.5 = 10.5 years or 10 years and 6 months.

the answer is gopal =15yrs,father=41yrs

Ravi has sold with 6% profit and Sudhir sold with 5% lossso x(1.06)(0.95)=2014so CP of Ravi=2000

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Let the CP = Rs.100

Then SP= 100 + 19 = Rs.119

Let the marked price be Rs. x

Then 85% of x = 119

85/100* x = 119

x = 119 * 100/85 =140

Marked price = 40% above CP

Given:-Suresh works at a speed of x kilometres per hour.

∴Distance covered in 3x hours=Speed×time=x km/hr × 3x hr=3x² km

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thanku sir

To cover the distance of 85 kilometers we have to multiply 20 by 8520×85 = 1700 minutesTo convert minutes into hours we have to 1700÷60 = 3 hrs approx

to cover distance of 85 kilometres we have multiply 20 by 85 -_1700 minutes 1700 divid 60 -_ 3hrs

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As D and E are mid-points of sides AB and BC of the triangle ABC, by Theorem 1,

DE || AC

Similarly, DF || BC and EF || AB

Therefore ADEF, BDFE and DFCE are all parallelograms.

Now DE is a diagonal of the parallelogram BDFE,

therefore, ∆ BDE ≅ ∆ FED

Similarly ∆ DAF ≅ ∆ FED

and ∆ EFC ≅ ∆ FED

So, all the four triangles are congruent.

Point A and B cars speed be A km/hr and B km/hr respectivelythey travel in same directionthey meet in 7hrPoint A and B are 70 km apart7A=7B+70A=B+10they travel toward each otherthey meet in 1hrPoint A and B are 70 km apartA+B=70keeping the value for AB+B+10=70A=40km/hrB=30km/hr

thank thank Bhai the intended recipient or the taking of square feet in length of time to get to the future please unsubscribe by clicking here Comcast the intended recipient or an employee the future of square feet of snow on you and your team to help with your company is not the same you are doing great and I have a great weekend too and consideration and I will be in a few days ago you mentioned you would like to see you soon and we will have to go to a new message the other hand the keys to the same you are interested in the morning to see you then if you have any other information you need to be a good day please find the future and I will send the future of our lives and consideration and I am not sure if it is a very good at it again in a while ago you said that he was the first time itrtnhiyyn the future of our clients so you have received your email address is the best way for you and I am not sure if you have any questions or comments about this but I'm still working on the intended

2 - root(5) irrational 3 + root(23) - root(23) = 3 rational 2root(7)/7root(7) = 2/7 irrational

1) 1 ---------- 3 +√2 ans. 1 3 - √2 3 - √2 ---------- = ----------- = ----------- 3 + √2 3 - √2 9 - 2

= 3 - √2 ---------- .....👌 7

7'o cleck is the answerminutes hand at 12 and hour hand at 7

A minute hand moves 6° in a minute and hour hand move 30' in a minute so the gain is 5°30'.

At exactly 7:00 be our reference. Let's start our observation here - Start time and start position.

Minute hand — 0 deg.

Hour hand — 210 deg.

By 7:20, the minute hand is 120 degs ahead from its start position -

Minute hand — 0 + 120 degs

In this duration, hour hand had moved some angle ahead, say x degs.

Hour hand — 210 + x degs

Then the angle between minute and hour hand becomes -

(210 + x) - (0 + 120) = 90 + x

So if we find x, we get the answer. x is the angle moved by hour hand in 20 mins. In 60 mins, hour hand moves by 30 degs, so in 20 mins it must move by 20*(30/60) = 10 degs. So x = 10

Therefore the required angle is 90 + 10 = 100 degs.

This can be solved faster if we consider relative speed of min on the second hand

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Angle between minute and hour hand at 6:50 is 60 degree

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I can't read the full answer so plz send me by doing in your copy and send me pic