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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 4601. |
The area of a square park is the same as of a rectangular park. If the side of the square park is 60 m and the rectangular park is 90 m, find the breadth of the rectangular park. |
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| 4602. |
The area of a square park is equal to that of arectangular park. If the side of the square park is70 m and the width of the rectangular park is 49m, find the perimeter of the rectangular park. |
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Answer» Like if you find it useful |
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| 4603. |
4-There is a square park of dimension 35 m. There are 2 semi circularcemented flower beds on two opposite sides of the park as shown in thefigure. Find the area and perimeter of the square park including the flowerbeds. |
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Answer» Area of the park including the flower beds=2*22/7*35/2*35/2*1/2+35*35=962.5+1225=2187.5cm^2...now..perimeter of the figure=35+35+2*22/7*35/2=180cm |
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| 4604. |
2. The area of a square park is the same as of a rectangular park. If the side of the square parkis 60 m and the length of the rectangular park is 90 m, find the breadth of the rectangularpark. |
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| 4605. |
One meter wide path is built inside a square park of side 30 m along its sides. The remaining part ofthe park is coverod by grass. If the total cost of covering by grass is ? 1176. Find the rate per squaremeter at which the park is covered by the grass. |
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| 4606. |
One meter wide path is built insido a square park of side 30 m along its sides. The remaining part ofthe park is covered by grass. If the total cost of covering by grass is1176. Find the rate per squaremeter at which the park is covered by the grass |
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| 4607. |
) ABCD is a rhombus.is a rhombus. Show that diagonal AC bisects. A as well s Cand dingnalBD bisects B as well as D.which diagonal AC |
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| 4608. |
aas well16. In a rhombus ABCD show that diagonal AC bisects ZAand diagonal BD bisects 4B as well as D. |
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| 4609. |
ABCD is a rhombus. Show that diagonal ACbisects < A as well as < C and diagonal BDbisects < B as well as < D. |
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| 4610. |
5.) In Fig 7.51, PR > PQ and PS bisects 4QPR. Provethat Z PSR> ZPSQ.Fig. 7.51 |
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| 4611. |
7. ABCD is a rhombus. Show that diagonal ACbisects Z A as well as Z C and diagonal BDbisects ZB as well as D. |
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| 4612. |
16. In a rhombus ABCD show that diagonal AC bisects ZA as well as4and diagonal BD bisects ZB as well as D |
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| 4613. |
7. ABCD is a rhombus. Show that diagonal ACbisects Z A as well as C and diagonal BDbisects Z B as well as D. |
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| 4614. |
7. ABCD is a rhombus. Show that diagonal ACbisects A as well as Z C and diagonal BDbisects Z B as well as D |
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| 4615. |
ABCD is rhombus. Show that diagonal AC bisects angle A as well as angle C and diagonal BD bisects angle B as well as angle D. |
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Answer» ABCD is a rhombus so, it's all side are equal.Take a triangle ABCin which AB=ACAngleACB=AngleBAC. Equation 1In triangle ADCAD=CDso, angle DCA=Angle DAC. Equation2from 1 and 2we get, AC bisect angle A and angle Bsimilarly,BD bisect angle C and angle D please like the solution 👍 ✔️ |
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| 4616. |
7.To locate a point Q on line segment ABsuch that BQ = -x AB Line Segment ABshould be divided in the ratio.a) 5:7b) 7:55:2d) 2:5 |
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Answer» Line segment AB is divided by point P in ratio such that BQ = 5/7 * AB Then,AQ = AB - 5/7*ABAQ = 2/7*AB Therefore,AQ:BQ = 2/7:5/7 = 2:5 (d) is correct option |
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| 4617. |
ABCD is a rhombus. Show that diagonal ACbisects Z A as well as C and diagonal BDbisects Z B as well as Z D. |
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| 4618. |
UNIT 113. In figure, AP and BQ areperpendiculars to the line segmentAB and AP BQ. Prove that O is themidpoint of line segment AB as wellAas PQ4. Suppose ABC is an isoscelestrianple with AB AC; BD and CE |
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Answer» in ∆ AOP and ∆ BOQ angle AOP = angle BOQAP = BQangle OAP = angle OBQ (90°)by AAS ∆ AOP and ∆ BOQ are congurent,therefore by CPCT AO = OBPO = OQthat means O is midpoint of AB and PQ thanks a lot for helping |
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| 4619. |
x+1)6x4+6x+7( |
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| 4620. |
3Given a triangle with side AB 8cm. To get a line segment ABof AB, it isrequired to divide the line segment AB in the ratio:(A) 3:44(B) 4: 3 |
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| 4621. |
x+2)6x4+5x+7( |
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| 4622. |
(d)(6x4 + 9x - 12x) + 3x? |
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Answer» 2x2 + 3x - 4 is the correct answer 2x2 +3x-4 you s the Correct answer 😭😭 2×2 +3×_4 Is the correct answer as best please like my answer 😍😍😍 |
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| 4623. |
9.indt8cm. To get a line ssegment AB 4 of AB, it is13)310. Given a triangle with side ABrequired to divide the line segment AB in the ratio;(A) 3:4(B) 4: 3a aland pinre equidistant fro |
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Answer» AB=8cmAB'=(3/4)*AB=(3/4)*8=6AB-AB'=8-6=2cmDo ratio is 6:2=3:1 option D is correct |
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| 4624. |
ABCD is a parallelogram. AC and BD are the diagonalsintersect at O. Pand Q are the points of tri section ofthe diagonal BD. Prove that CQ |l AP and also ACbisects PQ (see figure).A" |
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| 4625. |
5.The co-ordinates of the points A and B are (3,-5) and (1, -2) respectively. Then the ordinate of thepoint'C" on the line segment AB such that A4point 'C'on the line segment AB such that |
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| 4626. |
In Fig 7.51, PR> PQ and PS bisects 4 QPR. Provethat Z PSR> Z PSQ.5. |
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| 4627. |
QPR. ProveIn Fig 7.51, PR > PQ and PS bisectsthat Z PSR> Z PSQ.Fig. 7.51 |
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| 4628. |
QPR. ProveIn Fig. 7.51, PR > PQ and PS bisectsthat Z PSR PSQFig. 7.51 |
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| 4629. |
Fig. 7.505. In Fig 7.51, PR> PQ and PS bisects QPR. Provethat Z PSR>PSQ.Fig. 7.51 |
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Answer» hi tq sister |
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| 4630. |
C+D C DSin C + Sin D= 2 sÄąn _____ cos22 |
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| 4631. |
s InFig 751, PR PO and PS bisects 2 QPR PFig. 7.31 |
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| 4632. |
5. ABCD is a quadrilateral in which AB = AD. The bisector of ZBAC and CAD intersectthe sides BC and CD at the points E and F respectively. Prove that EF || BD. |
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| 4633. |
4. In the given figure, ABCD is a square & EF IBD then prove that BEDFC. |
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Answer» thanks .wring Means wrong |
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| 4634. |
QPR. Prove5InFig 7.51, PR>PQ and PS bisectshat 2PSR>LPSQFig. 7.51 |
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| 4635. |
3. In Figure 3, AB | CD.EF intersects them at P and Q, respectivelyIf 21 130°, find all the other angles.3 B57Fig. 3 |
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| 4636. |
(9) (6x®- 4x4 + 8x + 2x) = 2x |
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Answer» abjshsnsnsnsndushsis answer is attached____(: |
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| 4637. |
3.4. In Fig. PR > PQ and PS bisects <QPR. Prove thatPSR >PSQ. |
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| 4638. |
If the polynomial 6x^4 + 8x^3 -5x^2+ax + b is exactly divisible by the polynomial 2x^2 -5, thenfind the values of a and b. |
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Answer» since the the above polynomial is exactly divisble by 2x^2 -5..it means that the remainder is 0 therefore we can write it as 6x^4 + 8x^3 - 5x^2 + ax + b = (2x^2 - 5)× g(x) where g(x) is a polynomial of 2nd degree simplifying this furthur..we can arrive at 6x^4 + 8x^3 - 5x^2 + ax + b = (√2x -√5)(√2x +√5)× g(x) now r.h.s become 0 when x =√(5/2) and x = -√(5/2) by substituting x =√(5/2) 6(25/4) +8(5√5/2√2) - 5(5/2) + a(√5/√2) +b =0 25 + 20(√5/√2) + a(√5/√2) +b =0 -----(1) by substituting x = -√(5/2) 6(25/4) - 8(5√5/2√2) - 5(5/2) - a(√5/√2) +b =0 25 - 20(√5/√2) - a(√5/√2) +b =0 -----(2) (1) + (2) 50 +2b =0b = - 25 (1) - (2) 40(√5/√2) + 2a(√5/√2) =0a = -20 |
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| 4639. |
3. Divide:(a) 6x x -1 by 2x -1(c) 71x -31x -24x -21 by 3-8x |
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Answer» Solution a) the divisor is not complete in part (c) wrong h |
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| 4640. |
b aiogn alagram. In the giveniven figure, ABDE and ABAC are isosceles triangles and AE DO.What can you say about ZADB and ZCEB?HOTSD E |
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| 4641. |
Find the value of x for which (8x + 4), (6x-2) and (2x +7) are in A.P |
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| 4642. |
PQRS is the rectangle given here. TS is parallelto the diagonal PR and ZSPR 30°. Prove thatASPT and ΔRQP are congruent to each other |
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Answer» please post the figure to the question |
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| 4643. |
Find the value of x for which (8x 4), (6x -2) and (2x7) are in AP. |
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| 4644. |
5x-6x+8x*2x/4x= |
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Answer» using Bodmas rule = 5x-6x+8x* 1/2=5x-6x+4x=3x |
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| 4645. |
364. The angles of a quadrilateral are 100°, 70, 1202, and x.Find the value of x |
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| 4646. |
1661'16667, and so on". Isn't that interesting? Carhelp Atul to find some other examples like6416EXERCISE 14.4Find and correct the errors in the following mathematical statements.1. 4(x - 5) = 4x-5 2. x(3x + 2) = 3x2 +2 3. 2x + 3y = 5xy4. * + 2x + 3x = 5x 5. 5y +2y + y - 7y = 0 6. 3x + 2x = 5x2.7. (2x)2 + 4(2.x) + 7 = 2x² + 8x + 78. (2x)2 + 5x = 4x + 509. (3x + 2)2 = 3x² + 6x + 4 |
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Answer» suno maine 10th grade pe question daala hua hai tm ise best accept kar lo mai tmhare answer ko best accept kar lunga dono ko 100 points milenge |
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| 4647. |
sin A + sin Bua and cos A + cos B =ß, then the value of tan A+B) isef sin A+ Bin B =cos A+cos B =, tan(A+B) |
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| 4648. |
(a) 4xy from 60(0)6. Subtract the sum of (6x? +8x-9) and (3+5x-3x) from 10.213) If one of them is (2x |
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Answer» 6x*x+8x-9-3+5x-3x*x = 3x*x+13x-12 10-(3x*x+13x-12) = -3x*x+13x+22 |
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| 4649. |
cm2. If EFIfA,B, and C are interior angles of a triangle ABC, then show that15.4cm, find BCQ.11B + Csin() cos2ilntion of the top of tower from a point on the ground, |
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Answer» Part 1 Part 2 |
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| 4650. |
ABCD is a square and EF || BD.R is mid point of EF. Prove that BE = DE |
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Answer» Since diagonal of a square bisects the vertex and BD is the diagonal of square ABCD.∴ ∠CBD =∠ CDB = 90/2 = 45°Given :EF || BD⇒∠ CEF =∠ CBD = 45° and∠ CEF =∠ CDB = 45° (Corresponding angles)⇒ CEF = CFE⇒ CE = CF (Sides opposite of equal angles are equal) .....(1)Now, BC = CD (Sides of square) .....(2)Subtracting (1) from(2), we get⇒ BC CE = CD CF⇒ BE = DF or DF = BE Hence, proved. |
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