Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Ifalpha , beta, gammaare therootsof x^3 +qx +r=0 thensum( beta + gamma )^(-1)=

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`(Q)/(R )`
`(r )/(q)`
`-(q)/( r)`
`-r/q`

ANSWER :A
2.

If A.M and G.M of the roots of a quadratic equation in x are p and q repectively then its equation is

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`X^(2) - 2PX + Q^(2) = 0`
`x^(2) + 2px + q^(2) = 0`
`x^(2) - PX + q = 0`
`x^(2) - 2px + q = 0`

Answer :A
3.

Let a_n(10^n)/(n!) for0 len le 1then theminimumvalueofn !(1-n)!is attainedwhena valueofn=

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11
20
10
8

Answer :C
4.

If alpha+beta, gamma epsilon R^(+) such that alpha gamma =1/(beta) then maximum value of alpha^(beta+gamma), .beta^(beta+gamma).gamma^(alpha+beta) is_____

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SOLUTION :`beta=1/(alpha GAMMA)`
Assume `alpha GE beta ge gamma` (SAY)
`impliesalpha ge 1` and `gamma LE1`
`:.(alpha^(beta+gamma).gamma^(alpha+beta))/((alpha gamma)^(alpha+gamma))=(gamma^(beta-gamma))/(alpha^(alpha-beta)) le 1`
5.

Find the area of region : {(x,y) : 0 le y le x^(2) + 1, 0 le y le x + 1,0 le x le 2}.

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ANSWER :`(23)/(6)` SQ. UNIT `~~` 3.83 sq. unit
6.

A die is thrown. If E is the event the number appearing is a multiple of 3 and F be the event the number appearing is even'. Then find wheather E and F are independent ?

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ANSWER :E and F are INDEPENDENT EVENTS.
7.

Let n be a fixed positive integer and X take values 1,2,3,………..n. If P(X=k)=(1)/(n) for

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`sqrt(N^(2)-1)/(2SQRT3)`
`(n^(2)+1)/(2sqrt3)`
`(sqrt(n^(2)-1))/(12)`
`(n^(2)+1)/(12)`

ANSWER :A
8.

Find the middle term inn (i) ((2y^(2))/(3)+(3)/(2y^(2)))^(9),y ne0 (ii) (4x^(2)+9y^(2)+12xy)^(n)

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Solution :(i) Number of terms in the expansion is (9+1)=10 (EVEN)
`therefore` There are two middle terms given by `T_((9+1)/(2)) annd T_((9+3)/(2))` i.e., `T_(5) and T_(6)`
We know that `T_(r+1)=.^(n)C_(r)x^(n-r)a^(r)`
`thereforeT_(5)=T_(4+1)=.^(9)C_(4)((2y^(2))/(3))^(5)((3)/(2y^(2)))^(4)`
`=(9xx8xx7xx6)/(4xx3xx2xx1)xx(2^(5))/(3^(5))y^(10).(3^(4))/(2^(4)y^(8))`
`=(9xx8xx7xx6)/(4xx3xx2xx1)xx(2)/(3)xxy^(2)`
`=84y^(2)`.
and `T_(6)=T_(5+1)=.^(9)C_(5)((2y^(2))/(3))^(4)((3)/(2y^(2)))^(5)`
`=(9xx8xx7xx6)/(4xx3xx2xx1)xx(2^(4))/(3^(4))xx(3^(5))/(2^(5))xx(1)/(y^(2))`
`=(9xx8xx7xx6)/(4xx3xx2xx1)xx(3)/(2)xx(1)/(y^(2))`
`=(189)/(y^(2))`
(ii) `(4x^(2)+9y^(2)+12xy)^(n)`
Since `4x^(2)+9y^(2)+12xy=(2x+3y)^(2)`, therefore `(4x^(2)+9y^(2)+12xy)^(n)=(2x+3y)^(2n)`
Hence, there is only one middle TER namely `((2n)/(2)+1)^(th)` term i.e., `(n+1)^(th)` term.
`therefore` The required middle term `=T_(n+1)=.^(2n)C_(n)(2x)^(2n-n)(3y)^(n)` . . .
`=.^(2n)C_(n)(2x)^(n)(3y)^(n)`
`=(lfloor(2n))/(lfloor(n)lfloor(n)).2^(n).3^(n)x^(n).y^(n)`
hence, the middle term int he expansion of `(4x^(2)+9^(y)+12xy)^(n)` is `(lfloor(2n))/(floor(n)floor(n)).2^(n).3^(n)x^(n).y^(n)`
9.

Minimise and maximise Z=3x+9y subject to the constraints. x+3y le 60 x+y ge 10 x le y x ge 0, y ge 0

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ANSWER :180
10.

Let baru and barv be two non-collinear vectors. If the lengths a, b, c of the sides of DeltaABC are such that (a-b)baru+(b-c)barv+(c-a)(baruxxbarv)=bar0 then DeltaABC is

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RIGHT angled
equilateral
isosceles
obtuse angled

Answer :B
11.

If A, B, C, in (-(pi)/(2), (pi)/(2)). Then prove that cos A+ cos B + cos C le 3/2 .

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ANSWER :
12.

If f(x)=8x^2 +x-3, then find f(-1)

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13.

The p.m.f.ofa random variable X is (# TRG_MAT_MCQ_XII_P2_C08_E02_009_Q 01.png" width="80%"> If b= 2a, then

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`a =1/2, b=1/3`
`a =1/3, b=1/2`
`a =1/4, b=1/2`
`a =1/2, b=1/4`

ANSWER :C
14.

Solve the differential equation ydx = (x + y^(2))dy ( y ne 0).

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15.

int_(0)^((pi)/(2))(cosxdx)/(sqrt(1+cosxsinx))=

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`sqrt(2)COS^(-1)((1)/(sqrt(3)))`
`(1)/(sqrt(2))SIN^(-1) ((1)/(sqrt(3)))`
`sqrt(2)sin^(-1)((1)/(sqrt(3))`
`sqrt(2) sin^(-1) (sqrt(3))`

ANSWER :C
16.

A company manufactures two types of novelty souvenirs made of plywood. Souvenirs of type A require 5 minutes each for cutting and 10 minutes each for assembling. Souvenirs of type B require 8 minutes each for cutting and 8 minutes each for assembling. There are 3 hours 20 minutes available for cutting and 4 hours for assembling. The profit is Rs. 5 each for type A and Rs. 6 each for type B souvenirs. How many souvenirs of each type should the company manufacture in order to maximise the profit ?

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Answer :The maximum profit is Rs. 160 when MANUFACTURED 8 souvenirs of type A and 20 souvenirs of type B
17.

Find the area of the region bounded by y= ln x,y= 0, x= 1 and x= e

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ANSWER :1
18.

Sketch the graph of y = |3| and evaluate int_(-6)^(0)|x+3|dx .

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ANSWER :9
19.

If theanglesof a trianglesare inthe ratio3 : 4: 5then the ratioof thelargestsidetothesmallestsideof thetriangleis

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A. `(sqrt(3))/(2)`
B. `(sqrt(3 )+1)/(2sqrt(2))`
C. `(sqrt(3)+1)/(2)`
D. `(sqrt(3) )/(2sqrt(2))`

ANSWER :D
20.

(vec(a).(vec(b)xxvec(c)))/(vec(b).(vec(c)xxvec(a)))+(vec(b).(vec(a)xxvec(b)))/(vec(a).(vec(b)xxvec(c))) is equal to

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1
2
0
`OO`

ANSWER :A
21.

Equatinof linepassingthroughthe point(2,3,1)and parallelto the line ofintersection of the planes x−2y−z+6=0 and x+y+3z=5 is

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`(x-2)/(4)=(y-3)/(3)=(z-1)/(2)`
`(x-2)/(5)= (y-3)/(4)=(z-1)/(3)`
`(x-2)/(-5)=(y-3)/(-4)=(z-1)/(3)`
`(x-2)/(5)=(y-3)/(-4)=(z-1)/(3)`

ANSWER :C
22.

Showthat|{:(a-x,,c,,b),(c ,,b-x,,a),( b,, a,,c-x):}|=0 where a+b+c ne0

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Solution : Applying `C_(1) to C_(1) +C_(2)+C_(3)` we get
`Delta=|{:(a+B+c-X,,c,,b),(a+b+c-x,,b-x,,a),(a+b+c-x,,a,,c-x):}|`
`=(a+b+c-x) |{:(1,,c,,b),(1,,b-x,,a),(1,,a,,c-x):}|`
Applying `R_(1) to R_(1)-R_(2),R_(2)toR_(2)-R_(3),` we get
`Delta =(a+b+c-x) |{:(0,,c-b+x,,b-a),(0,,b-a-x,,a-c+x),(1,,a,,c-x):}|`
`=(a+b+c -x){(x^(2)+x(a-b)+c-b)(a-c)`
`+(x+a-b)(b-a)`
`=(a+b+c-x){(x^(2)+x(a-b)+(c-b)(a-c)`
`+x(b-a)-(a-b)^(2)}`
`=(a+b+c-x)(x^(2)+ac-c^(2)-ab+bc-a^(2)-b^(2)+2ab)`
`=(a+b+c-x)(x^(2)-a^(2)-b^(2)-c^(2)+ab+bc+ca)`
`=(a+b+c-x)(x^(2)-(1)/(2){(a-b)^(2)+(b-c)^(2)+(c-a)^(2))})`
SINCE `Delta =0` we have
`x=a +b +c, +- sqrt((1)/(2)((a-b)^(2)+(b-c)^(2)+(c-a)^(2)))`
23.

The solution of the differential equaiton

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`(dy)/(dx)+y TAN X =sec x,` is
`y sec x=tan x+C`
`y tan x=sec x+C`
`tan x=y tan x +C`

ANSWER :A
24.

One morning, each member of manjul's family drank an 8-ounce mixture of coffee and milk. The amount of coffee and milk varied from cup to cup but never zero. Manjul drank (1/7)^(th) of the total amount of milk and (2/7)^(th)of the total amount of coffee. How many people are there in manjul's family?

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ANSWER :8
25.

If two tangents to the parabola y^(2)=8x meet the tangent at its vertex in M and N such that MN = 4, then the locus of the point of intersection of those two tangents is

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`y^(2)=8(x+3)`
`y^(2)=8(x-2)`
`y^(2)=8(x+2)`
`y^(2)=4(x+2)`

ANSWER :C
26.

If the first degree terms of x^(2) + 4xy+y^2 - 2x + 2y-6=0 are eliminated by translation of axes then the transformed equation is

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`X^(2) + 4xy + y^(2)=8`
`x^(2) + 4xy + y^(2)=6`
`x^(2) + 4xy + y^(2)=4`
`5x^(2) + 4xy + 8Y^(2)=9`

Answer :C
27.

A: underset(x to pi//2)"Lt" ((cot x)/(pi//2-x))=1 R: If underset(x to a)"Lt" "f(x) exists, then " underset(x to a)"Lt" f(x)=underset(x to 0)"Lt" f(a+x)=underset(x to a)"Lt" f(a-x)

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Both A and R are true and R is the correct EXPLANATION of A
Both A and R are true and R ISNOT the correct explanation of A
A is true but R is false
A is false but R is true

Answer :A
28.

Differentiate the following functions with respect to x: sqrtx + sqrty = sqrta

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ANSWER :`-SQRT((y)/(X))`
29.

The plane 3x+4y+6z+7=0 is rotated about the line r=(i+2j-3k)+t(2i-3j+k) (1) until the plane passes through the origin. If the equation of this plane is x+y+lambdaz=0, then lambda=_______

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ANSWER :`1.00`
30.

int_(0)^(pi)e^(x)cos2xdx=.............

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`(1)/(5)(e^(PI/2)-1)`
`(1)/(5)(e-1)`
`(1)/(5)(e^(pi)-1)`
`(1)/(5)(e^(pi)-e)`

Answer :C
31.

lim_(x to pi/6) { (3 sin x - sqrt3 cos x)/( 6x - pi) }is equal to

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` SQRT3`
`1/sqrt3`
`- 1/sqrt3`
`-1/3 `

ANSWER :B
32.

If ((2n+1),(0))+ ((2n+1),(3)) +((2n+1),(6))+ ...= 170,then n equals

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2
4
6
8

Solution :`because (1+x)^(2n+1)=""^(2n+1)C_(0) + ""^(2n+1)C_(1)x +""^(2n+1)C_(2)x^(2)+""^(2n+1)C_(3)x^(3)`
` + ""^(2n+1)C_(4)x^(4)+""^(2n+1)C_(5)x^(5)+""^(2n+1)C_(6)x^(6)+...`
Putting `x=1, omega, omega^(2)` (where `omega` is cube root of unity and
adding, we GET
`2^(2n+1)+(1+omega) ""^(2n+1)+(1+omega^(2))^(2n+1)=3(""^(2n+1)C_(0) +""^(2n+1)C_(3)+""^(2n+1)C_(6)+...)`
`rArr 2""^(2n+1)-omega ^(2) " "^(2n+1)- omega^(2n+1)=3(""^(2n+1)C_(0) +""^(2n+1)C_(3)+""^(2n+1)C_(6)+...)[because 1 + omega + omega^(2) = 0]`
`rArr ""^(2n+1)C_(0) +^(2n+1)C_(3)+^(2n+1)C_(6)+...=1/3 `
`(2^(2n+1) -omega^(2) " "^(2n+1) -omega^(2n+1))`
`((2n+1),(0))+ ((2n+1),(3)) +((2n+1),(6))+...=1/3(2^(2n+1) -omega^(2) " "^(2n+1) -omega^(2n+1))`
For N `= 4,170 = 1/3 (512-1-1)=170 [because omega^(2)=1]`
Hence,`n=4`
33.

Let P(alpha,beta) and Q(gamma,delta) be two points that lie on the curve tan^(2)(x+y)+cos^(2)(x+y)+y^(2)+2y=0in the XY - plane . If the distance between P and Q is d then cos d=

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0
`(-1)^(n), n in N`
`+- pi`
`+-2NPI , n in N`

ANSWER :B
34.

If veca=hati+hatj+hatk, overset(-)(b)=veci+vecj, vecc=veci and (veca xx vecb) xx vecc=lambda veca+mu vecb," then "lambda +mu is equal to

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0
1
2

ANSWER :A
35.

From the set {1,2,3,4,5} two numbers a and b (a != b) are chosen at random . The probability that a/b is an integar is

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`1/3`
`1/4`
`1/2`
`3/5`

ANSWER :B
36.

A moving body is opposed by a force per unit mass of value cx and resistance per unit mass of value bv^(2) where x and v are displacement and velocity of the particle at that instant. Find the velocity of the particle in terms of x, if its initial velocity is v_(0).

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Answer :`(c )/(2B^(2))(1-e^(-2BX))-(cx)/(B)+v_(0)e^(-2bx)`
37.

IFsqrt( x^2 + 4a +5 )+ sqrt( x^2 + 4b+ 5 )=2 (a-b)thenx=

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`((a-b)^2 -5)/(2(a+b))`
`(a^2-b^2)/(2(a+b))`
` ((a+b)^2)/((a+b)-5)`
none

Answer :A
38.

If A and B are square matrices of the same order , then (i) (AB) = ……… (ii)(kA) ' = …….. (iii)[k(A-B)]' =…… k is any scalar)

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ANSWER :(i)(AB)'=B'*A
(II)`(kA)'=K*A`'
(III)`[k(A-B)]=k(A'-B)`
39.

Let ABCD be a square such that the side AB is on the line 2x-y=17 and two vertices C and D are on the parabola y=x^(2). If lengthof side of ABCD is less than 10 and its area is A, then A is equal to

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ANSWER :A::B
40.

Find the radius of the circle passing through the foci of an ellipse 9x^2+16y^2=144 and having least radius.

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ANSWER :`X^(2)+y^(2)=7`
41.

If f:RrarrR is defined by f(x) = x^2-3x+2, find f(f(x))

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SOLUTION :F(f(X)) = `f(x^2-3x+2)`
`= (x^2-3x+2)^2-3(x^2-3x+2)+2`
`= x^4+9x^2+4-6x^3+4x^2-12x-3x^2+9x-6+2`
`= x^4-6x^3+10x^2-3x`
42.

If z = x + iy and if the point P in the argand plane represents z , then the locus of P satisfying the equation |z-2-3i|=5

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43.

underset(x to 0)"Lt" {1-x+[x-1}+[1-x]}" is "

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0
1
2
3

Answer :D
44.

a={1,2,3,4,5}, Relation R on A is defined by R={(x,y)//x lt y" and "|x^(2)-y^(2)|lt 9} then R =

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`{(1,1),(2,2),(3,3),(4,4),(5,5)}`
`{(2,1),(3,2),(3,2),(4,3),(5,4)}`
`{(1,2),(1,3),(2,3),(3,4),(4,5)}`
`{(1,2),(1,3),(2,3),(3,4)}`

ANSWER :D
45.

Match the following lists:

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SOLUTION :a. `f(x)=cot^(-1)(2x-x^(2)-2)`
`=cot^(-1)(-1-(x-1)^(2))`
Now` -OO lt -1 -(x-1)^(2) lt -1`
` :. Cot^(-1) (-1-(x-1)^(2)) in [(3pi)/(4),pi)`
Also, `f(0)=f(2)`
So, `f(x)` is onto and many-one.
B.

Clearly, from the graph, `f(x)` is many-one and onto.
c.

d. Clearly, `f(x)` is INVERSE to itself.
So, `f(x)` is BIJECTIVE.
46.

Match the following lists:

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Solution :a. `tan^(-1)((2x)/(1-X^(2))) in (-(pi)/(2),(pi)/(2))`
`or 2 tan^(-1)x in (-(pi)/(2),(pi)/(2))`
`or tan^(-1)x in (-(pi)/(4),(pi)/(4))`
`ortan^(-1)x in (-1,1)`
b. `f(x)=sin^(-1)(sinx) and g(x)=sin(sin^(-1)x)`
`f(x)` is DEFINED if `sin x in [-1,1]` which is true for all `x in R`.
But g(x) is defined for only `x in [-1,1]`.
Hence, `f(x)` and g(x) are identical if `x in [-1,1]`.
C.`f(x)=log_(x^(2))25 and g(x)=log_(x)5`
`f(x)` is defined ` AA x in R - {0,1} and g(x) ` is defined for `(0, oo) -{1}.`
Hence, `f(x)`and g(x) are identical if `x in (0,1) cup (1,oo).`
d.`f(x)=sec^(-1)x+"cosec"^(-1)x,g(x)=sin^(-1)x+cos^(-1)x`
`f(x)` has domain `R -(-1,1) and g(x)` has domain [-1, 1]
Hence, both the functions are identical only if `x=-1,1.`
47.

Find maximum and minimum value of the following functions in the given interval.f(x)=2x^(3)-3x^(2)-12x+1, x in [-2, (5)/(2)]

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ANSWER :MAXIMUM VALUE 8,
MINIMUM value `-19`
48.

Match the following lists:

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Solution :a.`f(x) ={(sgn x)^(sgn x)}^(n)`
`={([(1)^(1)]^(n)",",x gt 0),([(-1)^(-1)]^(n) ",",x lt 0):}={(1",",x gt 0),(-1",",x lt 0):}.`
Hence, `f(x)` is an ODD function.
b. `f(x)=(x)/(e^(x)-1)+(x)/(2)+1`
`or f(-x)=(-x)/(e^(-x)-1)-(x)/(2)+1`
`=(xe^(x))/(e^(x)-1)-(x)/(2)+1`
`=(xe^(x)-x+x)/(e^(x)-1)-(x)/(2)+1`
`=x+(x)/(e^(x)-1)-(x)/(2)+1`
`=(x)/(e^(x)-1)+(x)/(2)+1`
`=f(x)`
C.`f(x)={(0",","if x is rational"),(1",","if x is irrational"):}`
`f(-x)={(0",","if -x is rational"),(1",","if -x is irrational"):}`
`={(0",","if x is rational"),(1",","if x is irrational"):}`
`=f(x)`
d. `f(x)=max [tanx, cotx}`
From the graph of function, it can be verified that `f(x)` is neither odd nor even.
ALSO, `f(x+pi)=max {TAN(x+pi),cot(x+pi)`
`=max {tanx, cot x}`
Hence, `f(x)` is periodic with period `pi`.
49.

If z = x + iy and if the point P in the argand plane represents z , then the locus of P satisfying the equation |z - 3 + i| = 4

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ANSWER :A::B::C
50.

Find the area of the region bounded by the ellipse x^(2)/16+y^(2)/9=1.

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ANSWER :`12pi`