InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 5351. |
Integrate the rational functions in exercise. (1)/(x^(4)-1) |
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| 5352. |
Express the matrix A=[{:(2,3,4),(5,6,-2),(1,4,5):}]as the sum of a symmetric and a skew symmetric matrix . |
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| 5353. |
Integrate the function is Exercise. (x^(2)+x+1)/((x+1)^(2)+(x+2)) |
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| 5354. |
Evalute the following integrals int (1)/(2 + 3" sin x")dx |
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| 5355. |
A random variable X has its range {0,1,2,3,……..}. If P(X=r)=(c(r+1))/(3^(r)) for r=0,1,2,………. Then c = |
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Answer» 2 |
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| 5356. |
Let Delta(x)=|{:(cos^(2)x,cosxsinx,-sinx,),(cosx sinx,sin^(2)x,cosx,),(sinx,-cosx,0,):}|"then" int_(0)^(pi//2)[Delta(x)+Delta'(x)]dx equals |
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Answer» `(pi)/(3)` Let `f(n)=K,""kinN` `implies k-(1)/(2)ltsqrt(n)LTK+(1)/(2)impliesk^(2)-k+(1)/(4)ltnltk^(2)+k+(1)/(4)impliesk^(2)-k+1lenlek^(2)+k""(therefore nin N)` `therefore` Number of integers for which `f(n)=k" is "(k^(2)+k)-(k^(2)-k)=2k` `{:(therefore,,f(n)=1" for",,n=1.2),(,,f(n)=2" for",,n=3.4.5.6),(,,f(n)=3" for",,n=7.8.9.10.11.12):}` `therefore underset(2)ubrace((1)/(f(1))+(1)/(f(2)))+underset(2)ubrace((1)/(f(3))+(1)/(f(4))+(1)/(f(5))+(1)/(f(6)))+.......+(1)/(f(2015))+(1)/(f(2016))` Sum of first 2 terms = 2 Sum of next 4 terms =2 Sum of next 6 terms = 2 |
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| 5357. |
If n is a multiple of 3, then coefficient of x^(n) in log(1+x+x^(2)) is |
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Answer» `-(2)/(N)` |
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| 5358. |
Writethe set builder form A= {-1,1} |
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Answer» A= {X: x is a root of the EQUATION `x^(2) + 1=0`} |
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| 5359. |
If lim_(xrarroo) xlog_(e)(|(alpha//x,1,gamma),(0,1//x,beta),(1,0,1//x)|)=-5. where alpha, beta, gamma are finite real numbers, then |
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Answer» `alpha=2, BETA=1, gamma in R` `=underset(xrarroo)(lim)x.log_(e)((alpha)/(x^(3))+beta-(gamma)/(x))` For LIMIT to EXIST, `beta=1` `therefore""L=underset(xrarroo)(lim)x.log_(e)(2+(alpha)/(x^(3))-(gamma)/(x))` `=underset(xrarroo)(lim)x((alpha)/(x^(3))-(gamma)/(x))` `=underset(xrarroo)(lim)((alpha)/(x^(2))-gamma)=-gamma=-5 and alpha in R` |
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| 5360. |
By approximatly what percent did the number of questions decrease in CET 1994 over the previous year? |
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Answer» 0.16 |
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| 5361. |
The locus of the point z=x+iy satisfying |(z-2i)/(z+2i)|=1 is |
| Answer» ANSWER :A | |
| 5362. |
Two unbiased dice are thrown. The probability that the sum of the numbers appearing on the top face of two dice is greater than 7, if 4 appear on the top face of first dice is ……….. |
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Answer» `(1)/(3)` |
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| 5363. |
int_(0)^(1) ((tan^(-1)x)^(3))/(1+x^(2))dx= |
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Answer» `1/4 (pi/12)^(6)` |
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| 5364. |
{:(,"Hyperbola point ",,"Tangent"),(I,3x^(2) -4y ^(2) =12","3x+2y +6=0, ,(a) ("2,-3")),(II,x^(2) -3y^(2) =3","2x+ y-1 =0,,(b) ("-1,-3")),(III,3x^(2) -4y^(2) =8","(2","-1) ,,(c) x+2y-4=0),(IV,9x^(2) -16y^(2) =144","3x-16y + 48 =0,,(d) ("6,-1")):} |
| Answer» Answer :B | |
| 5365. |
(i) A manufacturer produces nuts and bolts for industrial machinery.It takes 1 hour of work on machine A and 3 hours on machine B to produce a package of nuts while it takes 3 hours on machine A and 1 hour on machine B to produce a package of bolts.He earns a profit og ₹ 17.50 per package of nuts and ₹ 7.00 per package of bolts.How many packages of each should be produced each day so as to maiximise his profit, if he operate his machine for at the most 12 hous a day?Form an LPP for the problem and solve it graphically. (ii) A manufacturer produces nuts and bolts.It takes 1 hour of work on machine A and 3 hours on machine B to produce a package of nuts. It takes 3 hours on amchine A and 1 hour on machine B to produce a package of bolts.He earns a profit ₹35 per package of nuts and ₹14 per package of bolts.How many packages of each should be produced each day so as to maximise his profit, if he operates each machine for atmost 12 hours a day? Convert it into an LPP and solve graphically. |
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| 5366. |
ABCD is a square of side 'a'. If AB and AD are taken as co-ordinate axes, prove that the equation of the circle circumscribing the square is x^2+y^2=a(x+y). |
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Answer» SOLUTION :`THEREFORE` CENTRE of the circle is at (a/2, a/2) and radius is `(asqrt2)/2=a/sqrt2` `therefore` Equation of the circle is `(x-a/2)^2+(y-a/2)^2=a^2/2` or, `x^2+a^2/4-ax+y^2+a^2/4-ay=a^2/2` or, `x^2+y^2-ax-ay=0` or, `x^2+y^2=a(x+y)` |
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| 5367. |
After beating Donkey Kong, Mario was informed by his friend Toad the Mushroom Guy that Bowser, the evil dragon who has kidnapped Princess Peach, uses a different lan- guage to communicate which is based on the English alphabets in matrices, and that the princess was not in the castle he was in! So, he decided to use the warp tunnel and left for the same. On reaching the warp zone, he saw the below pattern on the tunnel and real- ized that Bowser had put it there to prevent him from entering the warp zone. Figure the one important word which the sentence implied by this pattern on the Warp tunnel says to help Mario get out of the castle through the warp.Noticing his dilemma, Toad hinted that it is very well versed with the word.eodC dorW +*-!Write down the 2nd letter of the word. |
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Answer» S eodC dorW `+*!` , when descrambled gives us, Code Word `!*+`So, when one follows the pattern of !*+ in each row, it literally translates to:Wise is the code word. HENCE, the Answer is option: C)I |
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| 5368. |
Matrix A=[(a,-b,0),(c,0,b),(0,-c,-a)] then : |
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Answer» `A^9=(a^2-2bc)^3A` |
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| 5369. |
If 24 cos^(2)x+8sin 2x cos x +18 cos x+6 sin 2x=15 +10 sin x then general solutionof x is |
| Answer» Answer :b | |
| 5370. |
Three vertices of a convex n sided polygon are selected. If the number of triangles that can be constructed such that none of the sides of the triangles is also the side of the polygon is 30, then the polygon is a |
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Answer» Heptagon |
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| 5371. |
If w(ne 1) is a cube root of unity and (1+w^2)^n = (1+w^4)^n then find the least positive integral value of n |
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Answer» LEAST POSITIVE integral value of n is 3 |
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| 5374. |
if f(x)=(x^(3)-3x^(2)+3x-x^(2)l n(e^((1)/(x^(2)))(x^(2)-x+2)))/(l n(x^(2)-x+2)) then f^('')(1) is equal to |
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Answer» `(2)/((l N2)^(2))` `=((x-1)^(3))/(ln(x^92)-x+2)` `thereforef^('')(1)=-2` |
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| 5375. |
Find the angle between the lines vecr = (hati+hatj)+lambda(3hati+2hatj+6hatk) and vecr = (hati-hatk) +mu(hati+2hatj+2hatk) |
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Answer» Solution :Here `VECM = 3hati+2hatj+6hatk` and `vecn=hati+2hatj+2hatk` Let ` theta` be the ANGLE between TWOLINES . `:. cos theta = (vecm.vecn)/(|vecm||vecn|) = ((3hati+2hatj+6hatk).(hati+2hatj+2hatk))/(|3hati+2hatj+6hatk|| hati+2hatj+2hatk|)` `= (3+4+12)/(sqrt(9+4+36)sqrt(1+4+4)) = (19)/(7xx3) = (19)/(21)` `theta = cos^(-1) (19/21)` |
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| 5376. |
Fill in the blank choosing correct answer from the brackets cot^(-1)[(sqrt(1-sin x ) +sqrt(1+sinx))/(sqrt(1-sin x)- (sqrt 1+ sin x))]=_______(2pi -x/2,x/2,pi- x/2) |
| Answer» SOLUTION :`pi-x/2` | |
| 5377. |
If the lines of regreasion of y on x and x on y makes angle 30 ^(@) and 60^(@)respectively with positive direction of x - axis the correlationcoefficient between x on y is |
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Answer» ` +-(1)/(3)` |
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| 5378. |
Given sum of first n terms of an A.P. is 2n + 3n^(2). rel then Another A.P. is formed with the same first term and double the common difference. Let Sn) denote the 98. sum to n terms of new A.P., then S(10)= |
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| 5379. |
Let A_(n) = a_(1) + a_(2) + "……" + a_(n), B_(n) = b_(1) + b_(2) + b_(3) + "…." + b_(n), D_(n) = c_(1) + c_(2) + "….." + c_(n) and c_(n) = a_(1)b_(n) + a_(2)b_(n-1) + "……." + a_(n)b_(1)Aan in N. Using mathematical induction , prove that (a) D_(n) = a_(1)B_(n) + a_(2)B_(n-1) + "....."+a_(n)B_(1) = b_(1)A_(n) + b_(2)A_(n-1) + "......"+b_(n)A_(1) AA n in N (b) D_(1) + D_(2) + "......"+ D_(n) = A_(1)B_(n) + A_(2)B_(n-1) + "....." + A_(n)B_(1) AA n in N |
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Answer» Solution :Let ` P(n) : D_(n) a_(n)B_(n) + a_(n)B_(n-1)+"……."+a_(n)B_(1)` For `n = 1,P(1) = D_(1) = a_(1)B_(1) = a_(2)b_(1) = c_(1)` Thus, ` P(1)` is true. Let`P(n)`be true for `n = K` i.e., `P(k) = D_(k) = a_(1)B_(k)= a_(1)B_(k) + a_(2)B_(k-1) + "....."+ a_(k)B_(1)` Now, `D_(k+1) = D_(k) + c_(k+1)` `= a_(1)B_(k) + a_(2)B_(k-1) + "......"+a_(k)B_(1) +a_(1)b_(k+1) + a_(2)b_(k) + "....."+a_(k+1)b_(1)` `=a_(1)(B_(k)+b_(k+1))+ a_(2)(B_(k-1)+b_(k)) + "......" + a_(k)(B_(1) + b_(2)) + a_(k+1)b_(1)` ltbrlt `= a_(1)B_(k+1)+a_(2)B_(2)+"......."+a_(k)B_(2) +a_(k+1)B_(1)`. Thus, `P(k+1)` is ALSO truewhenever`P(k)` is true. So, by the principle of mathematical induction `P(n)` is true for any NATURAL number n. Let `P_(1)(n) : D_(n)= b_(1)A_(n) + b_(2)A_(n-1)+"......."+b_(n)A_(1)` For `n = 1,P_(1)(1) = D_(1) = b_(1)A_(1) = b_(1)a_(1) = c_(1)` Thus, `P_(1)(1)` is true. Let, `P_(1)(n)` be true for `n= k`. i.e, `P_(1)(k) = b_(1)A_(k) + b_(2)A_(k-1) + "....." + b_(k)A_(1)` Now, `D_(k+1) = D_(k) +c_(k+1)` `= b_(1)A_(k) + b_(2)a_(k-1) + "......." + b_(k)A_(1) + a_(1)b_(k+1) + a_(2)b_(k) + "....." + a_(k+1)b_(1)` `= b_(1)(A_(k) + a_(k+1))b_(2)(A_(k-1)+a_(k))+"......"+b_(k)(A_(1) + a_(2)) + b_(k+1)a_(1)` `= b_(1)A_(k+1) + b_(2)A_(k) + "......"+b_(k)A_(2) + b_(k+1)A_(1)` Thus, `P_(1)(k+1)` is alsotrue. So, by the principle of mathematical induction `P_(1)(n)` is TRUEFOR any natural number n. (b) Say,`P_(2)(n) = D_(1) + D_(2) + "......"+D_(n) = A_(1)B_(n) + A_(2)B_(n-1) + "......" + A_(n)B_(2)` For `n = 1, P_(2)(1) = D_(1) = A_(1)B_(1) = a_(1)b_(1) = c_(1)` Thus, `P_(2)(1)` is true . Let `P_(2)(n)` be true for `n = k` i.e, ` P_(2)(k) = A_(1)B_(k) + A_(2)B_(k+1) + "......" + A_(k)B_(1)` Now, `P_(2)(k+1)` `= P_(2)(k) + D_(k+1)` `= A_(1)B_(k) + A_(2)B_(k-1) +"........"+)A_(k)B_(1) +b_(1)A_(k+1) + b_(2)A_(k) + "......" + b_(k)A_(2) + b_(k+1)A_(1)` `= A_(1)(B_(k) + b_(k+1)) + A_(2)(B_(k-1)+b_(k)) +"....." + A_(k)(B_(1) + b_(2)) + A_(k+1)b_(1)` ` = A_(1)B_(k+1) + A_(2)B_(k) + "....." + A_(k)B_(2) + A_(k+1)B_(1)` Thus, `P_(2)(k+1)` is also true. So, by the principle of MATHEMATICALINDUCTION, `P_(2)(n)` is true for any natural number n. |
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| 5380. |
If the roots of the equation x^(2)+x+a=0 exceed a,then |
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Answer» Option1`a GT 2` |
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| 5381. |
If P_(1), P_(2), P_(3) are the perimeters of the three circles x^(2) + y^(2) + 8x - 6y = 0, 4x^(2) + 4y^(2) - 4x - 12y - 186 =0 and x^(2) + y^(2) - 6x + 6y - 9 = 0 respectively, then |
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Answer» `P_1 LT P_2 lt P_3` |
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| 5382. |
Let C be the locus of the circumcentre of a variable traingle having sides Y-axis ,y=2 and ax+by=1, where (a,b) lies on the parabola y^2=4lamdax. For lamda=2 , the product of coordinates of the vertex of the curve C is |
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Answer» -8 |
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| 5383. |
If A_(j) = ( x-a_(j))/( | x- a_(j)|) , j = 1,2,"........" nand a_(1) lt a_(2) lt a_(3)lt"....."lt a_(n)underset( x rarr a_(m)) ( "lim") (A_(1).A_(2)."........" A_(n)), 1 le m le n |
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Answer» is EQUAL to `( -1)^(N -m+1)` |
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| 5384. |
Match the following for the system of linear equations lambda x+ y+z= 1x + lambda y+ z=lambdax+y +lambda z=lambda ^(2) (##FIITJEE_MAT_MB_07_C02_E04_001_Q01.png" width="80%"> |
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| 5385. |
If n= 10, sum_(i=1)^(10) x_(i) = 60 and sum_(i=1)^(10) x_(i)^(2) = 1000 then find s.d. |
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| 5387. |
Find the equation of a circle which passes through (4,1) (6,5) and having the centre on 4x + 3y - 24 = 0 |
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| 5388. |
Using elementry transformation, find the inverse of the matrices. A = [(4,5),(3,4)] |
| Answer» SOLUTION :`A^(-1) = [(4,-5),(-3,4)]` | |
| 5389. |
Find the Cartesian equation of the line parallel to y - axis and passing through the point (1,1,1). |
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| 5390. |
Protective components of food are :- |
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Answer» MINERALS, VITAMINS, and WATER |
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| 5391. |
The point on the curve y^(2)=x, where the tangent makes an angle of (pi)/(4) with x-axis is : |
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Answer» `((1)/(2),(1)/(4))` |
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| 5392. |
y=x is tangent to the ellipse whose foci are (1, 0) and (3, 0) then: |
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Answer» MAJOR axis of ellipse is `sqrt(6)` |
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| 5393. |
(.^(n)C_(0))^(2)+(.^(n)C_(1))^(2)+(.^(n)C_(2))^(2)+ . . .+(.^(n)C_(n))^(2) equals |
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Answer» `.^(2n)C_(N)` |
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| 5394. |
Resolve into Partial Fractions (v) (2x^(3)+3)/(x^(2)-5x+6) |
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| 5395. |
If sinx+siny=a and cosx+cosy=b then find the values of "tan"(x+y)/2,cot (x+y) and "sin"(x-y)/2 interms of a and b (given a!=0 !=b) |
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| 5396. |
Larger of 99^50+100^50 and 101^50 |
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Answer» `101^50` |
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| 5397. |
AD is a median of the Delta ABC.If AE are medians of the Delta ABD and DeltaADC respectively, and AD=m_(1), AE =m_(2),AF =m_(3), then find the value of (a^(2))/(8). |
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| 5398. |
The value of sum_(k=0)^(7)[(((7),(k)))/(((14),(k)))sum_(r=k)^(14)((r ),(k))((14),(r ))], where ((n),(r )) denotes "^(n)C_(r ) is |
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Answer» `6^(7)` `=sum_(k=0)^(7)(('^(7)C_(k))/(14!)xxk!(14-k)!sum_(r=k)^(14)(r !)/(k!(r-k)!)*(14!)/(r!(14-r)!))` `=sum_(k=0)^(7)('^(7)C_(k)sum_(r=k)^(14)'^(14-k)C_(r-k))` `=sum_(k=0)^(7)'^(7)C_(k)*2^(14-k)=2^(14)sum_(k=0)^(7)'^(7)C_(k)((1)/(2))^(k)` `=2^(14)*(1+(1)/(2))^(7)=6^(7) gt 7^(6)` |
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| 5399. |
Let f(x) bea polynomialfor whichthe remainderswhendividedbyx-1, x-2 , x-3respectivelyare 3,7,13thenthe remainderof f(x)whendividedby(x-1) (x-2)(x-3)is |
| Answer» Answer :B | |