InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 6151. |
State whether the following is a probability distribution of a random variable. Give reason for your answer. |
| Answer» Solution :Since P(3) lt 0, the GIVEN table can't be the PROBABILITY distribution of a RANDOM variable. | |
| 6152. |
State whether the following is a probability distribution of a random variable. Give reason for your answer. |
| Answer» Solution :Since `0 LT P(x) lt1` for all VALUE of x and `sumP(x)=0.4+0.4+0.2=1`, the given table is the PROBABILITY DISTRIBUTION of a random variable. | |
| 6153. |
State whether the following is a probability distribution of a random variable or not. Give reason for your answer. |
| Answer» Solution :Since `sumP(Z) ne 1`, the given table is not the probability DISTRIBUTION of a RANDOM VARIABLE. | |
| 6154. |
State whether the following is aprobability distribution of a random variable. Give reason for your answer. |
| Answer» SOLUTION :Since `sumP(Z)=0.6+0.1+0.2 ne1`, the given table is not the probability distribution of a random variable. | |
| 6156. |
int (x)/((1 - x)^(n))dx = |
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Answer» `((1 - X)^(2- n))/(2 - n) + ((1 - x)^(1 -n))/(1 - n)` + C |
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| 6157. |
If bar(x)xx(bar(y)xx bar(z))=(bar(x)xx bar(y))xx bar(z) then bar(y)xx(bar(z)xx bar(x)) = ………… . |
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Answer» `bar(Z)xx (bar(X)xx bar(y))` |
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| 6158. |
Let alpha, betabe the roots ofax^(2)+bx+c=0 and gamma, delta be the roots ofpx^(2)+qx+r =0and D_(1), D_(2)be the discriminants respectively. Ifalpha, beta, gamma, deltaare in A.P., thenD_(1):D_(2)is |
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Answer» `(a^(2))/(B^(2))` |
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| 6159. |
Resolve (x^(4)+13x^(2)+15)/((2x^(2)+3)(x^(2)+3)^(2)) into partial fractions |
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| 6160. |
If alphabe the set of integral values of c for which the equations cos 2xx + c sin x =2c - 7 has solutions then find the number of distinct symmetricmatrix of order3xx3 whose treace is 18 and entries are from the set alpha |
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Answer» 100 |
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| 6161. |
If (x_(1),y_(1)),(x_(2),y_(2)) and (x_(3),y_(3)) are the vertices of a triangle whose area is 'k' square units, then |(x_(1),y_(1),4),(x_(2),y_(2),4),(x_(3),y_(3),4)|^(2) is |
| Answer» Answer :C | |
| 6162. |
Let PSP ^(1)is a focal chord of the ellipse 4x^(2) +9y^(2) =36and SP =4, then S^(1) P^(1)= |
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Answer» `( 26) /(5) ` |
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| 6163. |
A box contains 4 red and 7 blue balls. Two balls are drawn at randon with replacement. Find the probability of getting (i) 2 red balls (ii) 2 balls are of blue colour (iii) one red and one blue ball is selected. |
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| 6164. |
int_(0)^(a)(a^(2)-x^(2))^(5//2)dx= |
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Answer» `(PI a^(2))/(2)` |
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| 6165. |
If alpha and beta are the eccentric angles of the ends of a focal chord of the ellipse then cos^(2)((alpha+beta)/(2))sec^(2)((alpha-beta)/(2))= |
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Answer» `(a^(2)+B^(2))/(a^(2))` |
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| 6166. |
Integrate the following function : int(dx)/(sqrt(x^(2)-6x+10)) |
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| 6167. |
Assertion: The polynomial 5x^9+3x^5-x^4-2x^2+5 has atleast six imaginary roots. Reason: Descretes rule of sign. |
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Answer» (R) is ONE of the reason of prove (A) |
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| 6168. |
Find the probability distribution of i. number of head in two tosses of a coin. ii. number of tails in the simultaneous tosses of three coins. iii.number of heads in four tosses of a coin. |
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Answer» `(##NCERT_TAM_MAT_XII_P2_C13_E04_004_A02##)` |
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| 6169. |
If 2^(f(x)) = (2+x)/(2-x), x in (-2, 2) and f(x) = lambda f((8x)/(4+ x^(2))) then value 'lambda' will be |
| Answer» ANSWER :B | |
| 6170. |
0.2 + 0.22 + 0.222 + …….. to n terms = |
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Answer» `(2/9) - (2/81)(1 - 10^(-N))` |
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| 6171. |
IFalpha, betaare therootsofax ^2+ bx+ c=0, alpha_1 , - betathe rootsofa_1 x^2+ b _1 x + c_(1) =0thenalpha, alphaaretherootsof theequation |
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Answer» `(b/a+b_1/a_1)^-1x^2+x(b_1/c_1+b/c)^-1=0` |
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| 6172. |
If the value of prod_(k=1)^(50)[{:(1,2k-1),(0,1):}] is equal to [{:(1,r),(0,1):}] then r is equal to |
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Answer» Solution :`(B)` `[{:(1,1),(0,1):}][{:(1,3),(0,1):}]=[{:(1,4),(0,1):}]` `[{:(1,4),(0,1):}][{:(1,5),(0,1):}]=[{:(1,9),(0,1):}]` `[{:(1,9),(0,1):}][{:(1,7),(0,1):}]=[{:(1,16),(0,1):}]` If `n` is no. of matrices that are MULTIPLIED, then PRODUCT is `[{:(1,n^(2)),(0,1):}]` `:.r=2500` |
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| 6173. |
Find the value of k so that the function f(x) = {((2^(x+2) - 16)/(4^(x) - 16),"if",x ne 2),("k","if",x = 2):} is continuous at x = 2. |
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| 6174. |
The value of int_0^100 [ tan^(-1) x] dx is ([.] G.I. F.) |
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Answer» 100 `int_0^100[tan^(-1)X]DX =int_(0)^(tan1)[tan^(-1)x]dx + int_(tan1)^100 [tan^(-1)x]dx` `RARR int_0^100[tan^(-1)x]dx=int_0^(tan1)0 dx + int_(tan1)^(100)1.dx=100-tan1` |
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| 6175. |
Find the approximate change in the volume V of a cube of side x meters caused by increasing the side by 2%. |
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| 6176. |
Find points at which the tangent to the curve y=x^(3)-3x^(2)-9x+7 is parallel to the x-axis. |
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| 6177. |
Evaluate the following integrals intxsin^(-1)dx |
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| 6178. |
Equation of circle touching the lines.| x- 2 | + | y-3| =4is |
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Answer» ` (x-2 ) ^(2) + (y-3) ^(2) =1 2` |
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| 6179. |
Let f(x)={(2x+a",",x ge -1),(bx^(2)+3",",x lt -1):} and g(x)={(x+4",",0 le x le 4),(-3x-2",",-2 lt x lt 0):} If the domain of g(f(x))" is " [-1, 4],then |
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Answer» `a=1, b GT 5` `or-1 le x le 2` `or -2 le 2x le 4` `or -2+a le 2x+a le 4+a` `or -2+a le -2 and 4+a le 4, i.e., a=0` b can TAKE any VALUE. |
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| 6180. |
The sum of an infinity decreasing G.P is equal to 4 and the sum of the cubes of its terms is equal to 64/. Then 5^(th) term of the progression is : |
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Answer» `1/4` `implies(a)/(1-r) =4 ""….(1)` ALSO, `a^3 + (ar)^3 + ………. = (a^3)/(1-r^3) implies(a^3)/(1-r^3)=(64)/(7)` `implies7a^3 = 64 (1-r^3) ""….(2)` USING (1) and (2) , we have `7 xx 64 (1-r)^3 = 64(1-r^3) implies2r^2 - 5R + 2 = 0impliesr=1//2,2` `therefore ` G.P. is decreasing `impliesr=1//2 ` and a=2 |
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| 6181. |
Find the approximate value of root(4)(17) |
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| 6182. |
squareABCDEF is a regular hexagone with each side a. bar(AB).bar(AF)+(1)/(2)bar(BC)^(2)= ………… |
| Answer» Answer :D | |
| 6183. |
If the angle alpha between two forces of equal magnitude is reduced to (alpha-pi//3), then the magnitude of their resultant becomes (alpha-pi//3),times of the earlier one. The angle alpha is |
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Answer» `pi//2` on solving `,alpha=(2pi)/(3)"""]"` |
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| 6184. |
A circle S having centre (alpha, beta) intersect at three points A, B and C such that normals at A,B and C are concurrent at (9,6) for parabola y^(2)=4x and O origin. Then, |
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Answer» Sum of modulus of SLOPES of normals at points `A, B` and `C` is 6 `implies6=9m-2m-m^(3)` `impliesm^(3)-7m+6=0impliesm=1, +2, -3` `:.` Centre is `(11/2, 3/2)` |
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| 6186. |
Minimize and Maximize Z = 3x + 9y subject to the constraints x+3ylt=60 x+ygt=10 xlt=y x gt= 0, y gt= 0 by the graphical method . |
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| 6187. |
Let S be the set of all real number and let R be relation on S , defined by a R b hArr (1+ab)gt0 then, R is |
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Answer» REFLEXIVE and SYMMETRIC but TRANSITIVE |
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| 6188. |
Show that the family of curves for which the slope of the tangent at any point (x,y) on it is (x^(2)+y^(2))/(2xy), is given by x^(2)-y^(2)=Cx |
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| 6189. |
If the equation x ^(2) +ax+12 =9, x ^(2) +bx +15 =0 and x^(2) + (a+b) x +36=0 have a common positive root, then b+2a equal to. |
| Answer» ANSWER :B | |
| 6190. |
Which of the following options is the only CORRECT combination |
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Answer» `(I) (II)(R) ` |
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| 6191. |
Findthepolynomialwithrationalcoefficientsand whoserootsare a+b,a-b,-a+b,-a-b |
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| 6192. |
Using {1,2,3,4,5} foure digited numbers are formed without repetation at random. The probability that the number so formed is not divisible by 5 is |
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Answer» `(1)/(5)` |
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| 6193. |
vec(a),vec(b) and vec( c ) are three vector vec(a)ne0 and |vec(a)|=|vec( c )|=1,|vec(b)|=4,|vec(b)xx vec( c )|=sqrt(15). If vec(b)-2vec( c )=lambda vec(a) then the value of lambda is …………. |
| Answer» Answer :A | |
| 6194. |
For a complex number Z = a ib, let hat(Z) = b + ia. If Z_(1), Z_(2) are such complex numbers, then hat(Z_(1)Z_(2)) = |
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Answer» `hat(Z)_(1) hat(Z)_(2)` |
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| 6195. |
A variable straight line passes through the intersection of x+2y=1,2x-y=1 and meets co-ordinate axes in A and B. The locus of mid-point of AB is : |
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Answer» `2x-3y=4` ![]() Let `A(3lambda+7,2lambda+7,lambda+3)` `B(2k+1,4k-1,3k-1)` `because` DIRECTION ratios of L are 2,2,1. `implies(3lambda-2k+6)/(2)=(2lambda-4k+8)/(2)=(lambda-3k+4)/(1)` `implieslambda=2" and "k=0` `thereforeA(13,11,5),B(1,-1,-1)` `implies AB = 18` |
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| 6196. |
Let a(n) =1-(1)/(2)+(1)/(3)+…+(-1)^(n-1)(1)/(n)," then "(1)/(n+1)+(1)/(n+2)+…+(1)/(2n) is equal to |
| Answer» Answer :A | |
| 6197. |
if A=[{:(-1,2,,3),(5,7,9),(-2,1,1):}]and B=[{:(-4,1,-5),(1,2,0),(1,3,1):}],thenverifythat(I) (A+B)'=A'+B',(ii) (A-b)'=A'=B' |
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Answer» `B=[{:(-4,1,-5),(1,2,0),(1,3,1):}]=[{:(-4,1,1),(1,2,3),(-5,0,1):}]` `(i) A+B=[{:(-1,2,3),(5,7,9),(-2,1,1):}]+[{:(-4,1,-5),(1,2,0),(1,3,1):}]` `=[{:(-5,3,-2),(6,9,9),(-1,4,2):}]` `=[{:(-5 implies (A+B)'=[{:(-5,3,-2),(6,9,9),(-1,4,2):}]=[{:(-5,6,-1),(3,9,4),(-2,9,2):}]` `and A'+B'=[{:(-1,5,-2),(2,7,1),(3,9,1):}]+[{:(-4,1,1),(1,2,3),(-5,0,1):}]` `=[{:(-5,6,-1),(3,9,4),(-2,9,2):}]` `therefore(A+B)'=A'+B'` hence proved `(ii) A-B=[{:(-1,2,3),(5,7,9),(-2,1,1):}]-[{:(-4,1,-5),(1,2,0),(1,3,1):}]` `=[{:(3,1,8),(4,5,9),(-3,-2,0):}]` `implies (A-B)'=[{:(3,1,8),(4,5,9),(-3,-2,0):}]=[{:(3,4,-3),(1,5,-2),(8,9,0):}]` ` and A'-B' =[{:(-1,5,-2),(2,7,1),(3,9,1):}]-[{:(-4,1,1),(1,2,3),(-5,0,1):}]` `=[{:(3,4,-3),(1,5,-2),(8,9,0):}]` `therefore (A-B)'=A'B'` hence proved . |
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| 6198. |
A ball moving around the circle x^(2)+y^(2)-2x-4y-20=0 in anti-clockwise direction leaves it tangentially at the point P(-2,-2). After getting reflected from a straingt line, it passes through the centre of the circle. Find the equation of the straight line if its perpendicular distance from P is 5/2. You can assume that the angle of incidence is equal to the angle of reflection. |
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| 6199. |
Find graphically the minimum value of Z=5x+7y, subject to the constraints given below: 2x+y ge 8, x +2y ge 0 and x, y ge 0 |
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| 6200. |
Let f_(1) (x)= int_(0)^(x) f(t) dt, f_(2) (x) = int_(0)^(x) f_(1) (t) dt and f_(3) (x) = int_(0)^(x) f_(2) (t) dt if f_(3) (x) =A int_(0)^(x) f(t) (x-t)^(2) dt then the value of A is |
| Answer» Answer :B | |