InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 9151. |
If x = 2 + 5i then value of the expression x^(3)-5x^(2)+33x-49 equals |
| Answer» ANSWER :A | |
| 9152. |
A kite is flying at a height 151.5 m from horiozontal. The speed of the kite is 10 m/s. The distance of the kite from a boy who flies the kite is 250 m. Find the rate of change of thread of the kite. |
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| 9153. |
int "In" ( x + sqrt( 1+x^(4) )) dx. |
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| 9155. |
Statement I : Sum of the series 1^(3) - 2^(3) + 3^(3) - 4^(3) +…+ 11^(3) = 378 Statement II : For any off integer n ge 1, n^(3) - (n-1)^(3) +…+(-1)^(n-1) 1^(3) = (1)/(4)(2n-1) (n+1)^(2) |
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| 9156. |
A chord of length 8 units is at a distance of 4 uits from the centre of a circle then its radius is |
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Answer» `4sqrt(2)` |
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| 9157. |
Evaluation of definite integrals by subsitiution and properties of its : int_(-e)^(e)log((e^(5)-x^(5))/(e^(5)+x^(5)))dx=............. |
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Answer» E |
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| 9158. |
Find the values of the following integrals int(secx+tanx+(3)/(x)-4)dx |
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| 9159. |
Let (1+ x + x^2)^n = a_0 + a_1x + a_2x^2 + …….+a_(2n)x^(2n) Then match the items of List - I with those of List-II The correct match is |
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Answer» `A to (IV) , B to (I), C to (III)` |
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| 9160. |
Prove that three lines drawn from origin with direction cosines proportional to (1,-1,1),(2,-3,0),(1,0,3) lie on one plane . |
| Answer» SOLUTION :Let `OVERSETTOA=i+j+koversettob=2i-3joversettoci+3k` The lines are co-planar if `oversettoa.(oversettobxxoversettoc)=0` Now `oversettoa.(oversettobxxoversettoc)=|(1,-1,1),(2,-3,0),(1,0,3):|=1(-9)+1(6)+1(3)=0` | |
| 9161. |
If f(x)=3x^(2)+4x+5, what must the value of k equal so that the graph of f(x-k) will be symmetric to the y-axis? |
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Answer» `-4` x-coordinate is -0.66666. . ..if the function entered into `Y_(1)`, set `Y_(2)=Y_(1)(x-(2)/(3))` and graph `Y_(2)` to verify this answer. |
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| 9162. |
y=-x^(2)+120x-2,000 the equation above gives the profit in dollars, y, a coat manufacturer earns day where x is the number of coats sold. What is the maximum profit he earns in dollars? |
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| 9163. |
What is the perimeter of quadrilateral STUR if it has vertices with (x,y) coordinates S(0,0), T(2,-4),U(6,-6) , R(4,-2) ? |
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Answer» `2sqrt20` |
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| 9164. |
If A, B, C are any three events in an experiment then show that (i) P(A//B^(C)) = (P(A) - P(A nn B))/(1-P(B)) "if P"(B^(C)) gt 0 (ii) A sube B rArr P(A//C) le P(B//C) "if P(C)" gt 0 (iii) If A, B are mutually exclusive, then P(A//B^(C)) = (P(A))/(1-P(B)) "if P(B)" ne 1 (iv) If A, B are mutually exclusive and P(A uu B) ne 0 "then" P(A//A uu B) = (P(A))/(P(A) + P(B)) |
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Answer» <P> (ii) `RARR P(A//C) le P(B//C)` (iii) `P(A//B^(C)) = (P(A nn B^(C)))/(P(B^(C)))=(P(A))/(1-P(B))` (IV) `P(A nn B) = 0` |
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| 9165. |
The value of definite integral int_(-pi)^(pi) (cos 2x. cos2^(2)x.cos2^(3)x.cos 2^(4)x.cos2^(5)x)dx is |
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Answer» 1 |
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| 9166. |
If a and b are unit vectors, then the greatest value of |a+b|+|a-b| is |
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Answer» 2 Now, `|a+b|^(2)=|a|^(2)+|b|^(2)+2a.b` `=1+1+2xx1xx1xxcos theta` `=2+2 cos theta=4 "cos"^(2) theta/2` `implies |a+b|=2 "cos" theta/2` and `|a-b|^(2)=|a|^(2)+|b|^(2)-2a.b` `=2-2 cos theta=2 (2 "SIN"^(2) theta/2)` `|a-b|=2"sin" theta/2` `:. |a+b|+|a-b|=2 ("cos" theta/2 +"sin"theta/2) le 2 sqrt(2)` |
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| 9167. |
There are 5 letters and 5 addressed envelopes. If the letters are placed at random in the envelopes. Find the chance that exactly 3 letters go into correct envelopes. |
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| 9168. |
There are 5 letters and 5 addressed envelopes. If the letters are placed at random in the envelopes. Find the chance that all letters go into correct envelopes. |
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| 9169. |
A bag contains six balls. Two balls are drawn and found them to be red. The probability that 5 balls in the bag are red is |
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Answer» `5//6` |
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| 9170. |
Find the value of cos 1^@, cos 2^@ ….. Cos 100^@ |
| Answer» SOLUTION :`cos 1^@ cos 2^@ …… cos 100^@ = 0` as `cos 90^@` is there which is ZERO. | |
| 9171. |
Find the shortest distacne between the lines vecr=hati+2hatj+3hatk+mu(2hati+3hatj+4hatk) and vecr=(2hati+4hatj+5hatk)+lambda(3hati+4hatj+5hatk) |
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| 9172. |
Statement-1 f(x) = |{:((1+x)^(11),(1+x)^(12),(1+x)^(13)),((1+x)^(21),(1+x)^(22),(1+x)^(23)),((1+x)^(31),(1+x)^(32),(1+x)^(33)):}| the cofferent of x in f(x)=0 Statement -2 If P(x)=a_(0)+a_(1)x+a_(2)x^(2)+a_(2)x_(3) +cdots+a_(n)s^(n) then a_(1)=P'(0), where dash denotes the differential coefficient. |
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| 9173. |
If the area of the triangle on the complex plane formed the points z , iz and z + iz is 50 square units, then |z| is |
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Answer» 5 |
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| 9174. |
A particle moves along the curve y=x^((3)/(2)) in the first quadrant in such a way that its distance from the origin increases at the rate of 11 units/sec. The value of (dx)/(dt) when x = 3 is ………… |
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Answer» 4 |
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| 9175. |
Let f be a function defined on [-pi/2, pi/2] by f(x) = 3cos^(4)x - 6 cos^(3)x -3 Then the range of f(x) is |
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Answer» `[-12,-3]` |
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| 9177. |
Ifa ray of light incident along the line 3x+ (5-4 sqrt2 ) y= 15gets reflected from the hyperbola (x^(2))/( 16)-(y^(2))/( 9)=1 then reflected ray goes along the line |
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Answer» `xsqrt 2- y +5=0 ` |
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| 9178. |
The solution of the differential equation (dy)/(dx) = sin (x +y) tan (x + y) -1 is |
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Answer» `COSEC (x + y) + tan (x + y) = x +C` |
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| 9179. |
Form a quadratic equation with rational coefficients if one of its root is cot^(2)18^(@). |
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| 9180. |
A noraml to the parabola at a point A on the parabola whose equation is y^(2)=2013x cuts the axis of x at N. AN is produced to the point B such that NB=1/2AN. If the normals through any point of the parabola y^(2)=2013x, cut the line 2x - 2013 = 0, in points whose ordinates are in AP, then the slopes of these normals are in |
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Answer» AP |
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| 9181. |
A normal to the parabola at a point A on the parabola whose equation is y^(2)=2013x cuts the axis of x at N. AN is produced to the point B such that NB=1/2AN. If C is a point on the parabola y^(2)=2013x such that OCN=pi/2 (O being origin), then projection of CN on x-axis is equal to |
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Answer» 2013 |
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| 9182. |
A noraml to the parabola at a point A on the parabola whose equation is y^(2)=2013x cuts the axis of x at N. AN is produced to the point B such that NB=1/2AN. If two more normals to the parabola y^(2)=2013x pass through B, then they are |
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Answer» coincident |
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| 9183. |
Prove that the function f given by f(x) = log | cos x|" is decreasing on "(0,pi/2)" and increasing on "((3pi)/2,2pi). |
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Answer» Solution :f(x) = log cos x ` rArrf'(x) = (-SIN x)/(cos x) =- tan x` (a) For STRICTLY decreasing FUNCTION `f'(x) LT 0` ` rArr-tan x lt 0` ` rArrtan xgt 0` ` rArr x in ]0,PI/2[` (b) Forstrictly decreasing function ` f'(x) gt 0` ` rArr- tan x gt 0` ` rArrtan x lt 0` ` rArrx in ]pi/2, pi [` |
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| 9184. |
Find all possible values of (i) sqrt(|x|-2) (ii) sqrt(3-|x-1|) (iii) Sqrt(4-sqrt^2)) |
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Answer» Solution :`sqrt(|x|-2)` we know that SQUARE roots are defined for non- negative values only . It implies that we must have `|x|-2 LE 0` Thus `sqrt(|x|-2) ge 0 ` (ii) `sqrt(3-|x-1|)` is defined when `3-|x-1| le 0 ` But the maximum value of 3-|x-1| is 3 , when |x-1| is 0 HENCE for `sqrt(3-|x-1|)` to get defined , `0 le 3- |x-1| le 3 ` Thus , `sqrt(3-|x-1|)in [0,sqrt(3)]` Alternatively , `|x-1| ge 0` `rArr-|x-1| le 0 ` `rArr3-|x-1|le3` But for `sqrt(3-|x-1|)` to get defined ,we must have `0 le 3 -|x-1| le 3 ` `rArr0 le sqrt(3-|x-1| le sqrt(3)` (iii) `sqrt(4-sqrt(x^2))=sqrt(4-|x|)` `|x| ge 0 ` `rArr- |x| le 0 ` `rArr4-|x| le 4 ` But for `sqrt(4-|x| )` to get defined `0 le 4 - |x| le 4 ` `therefore0 le sqrt(4-|x|) le 2 ` |
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| 9185. |
Using the proprties of determinants in Exercise 7 to 9, prove that |{:(a^2+2a,2a+1,1),(2a+1,a+2,1),(3,3,1):}|=(a-1)^3 |
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| 9187. |
Find the area (in sq. unit) bounded by the curves : y = e^(x), y = e^(-x) and the straight line x =1. |
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| 9188. |
S=sum_(r=1)^(4)tan^(2)(2r-1)(pi)/(16) is an integer divisible by |
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Answer» 2 |
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| 9189. |
Find the quadrants of the coordinate planes such that for each point (x,y) on these quadrants ( wherex ne 0 , y ne 0) , the equation,(sin^(4) theta )/x + ( cos^4 theta)/( y)=(1)/(x+y)is soluble fortheta. |
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| 9190. |
Statement-1 : if P and D be the ends of conjugate diameters then the locus of mid-point of PD is a circle. and STATEMENT-2 : if P and D be the ends of conjugate diameter, then the locus of intersection of tangents at P and D is an ellipse. |
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Answer» Statement-1 is TRUE, statement-2 is true, Statement -2 is a CORRECT explanation for Statement -1 |
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| 9191. |
Which of the following numbers is NOT prime? (Hind : avoid actually computing these numbers.) |
| Answer» ANSWER :B | |
| 9192. |
Write tan^(-1)(sqrt((1-cosx)/(1+cosx))), 0 lt x lt pi in the simplest form. |
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| 9193. |
Express the following differential equations in the form (dy)/(dx) = F((y)/(x)). (i) xdy - ydx = sqrt(x^(2) + y^(2))dx (ii) [x - y Tan^(-1)((y)/(x))] dx + x Tan^(-1)((y)/(x)) dy = 0 (iii) xdy = y(log y - log x+1)dx |
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Answer» `(dy)/(dx) = ((y)/(x) Tan^(-1)((y)/(x))-1)/(Tan^(-1)((y)/(x)))` (III) `(dy)/(dx) = (y)/(x)[log((y)/(x))+1]` |
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| 9194. |
Each of five questions on a multiple choice examination has four choices, only one of which is correct. A student is attempting to guess the answer. If the random variable X is the number of questions answered correctly, the probability that the student will get at most three answers correct is |
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Answer» `45/512` |
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| 9196. |
Let f(x)=x^(2)+3x-3, x ge0 if in points x_(1),x_(2),x_(3),...x_(n) are so chosed on the x-axis such that (i) (1)/(n) underset(i=1) overset(n)sumf^(-1)(x_(i))=f((1)/(n)underset(i=1) overset(n)sumx_(i)) (ii) underset(i=1) overset(n)sumf^(-1)(x_(i))=underset(i=1) overset(n)sumx_(i) wehre f^(-1) denots the inverser of f. then mean of x_(1),x_(2),x_(3),....x_(n) is : |
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Answer» 1 |
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| 9197. |
Differentiate the functions sqrt(((x-1)(x-2))/((x-3)(x-4)(x-5))) |
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| 9199. |
If a function f:CtoC is defined by f(x)=3x^(2)-1, where C is theset of complex numbers, then the pre-images of -28 are |
| Answer» Answer :B | |
| 9200. |
Let veca = hati + hatj + hatk, vecb = hati - ahtj + hatk and hati - hatj - hatkbe three vectors. A vector vecv in the plane of veca and vecb, whose projection on vecc is (1)/(sqrt3), is given by : |
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Answer» `4i-j+4k` |
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