InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 9302. |
The two successive terms in the expansion (1+x)^24 whose coeff's are in the ratio 4:1 are |
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Answer» 18TH , 19th |
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| 9303. |
Let M be a 2xx2 symmetric matrix with integer entries. Then , M is invertible, if |
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Answer» the FIRST column of M is the transpose of the second row of M is invertible if`abs((a,b),(b,c)) ne 0 rArr AC- b^(2) ne 0 ` (a) `[[a],[b]]=[[b],[c]]rArr a = b =c rArr ac-b^(2)=0` `therefore` Option (a) is incorrect (b) `[(b,c)]= [(a,b)] rArr a = b = c rArr ac - b^(2) = 0` `therefore` Option (b) is incorrect (c) `M= [[a,0],[0,c]], ` then` abs(M) = ac ne 0` `therefore` M is invertible `therefore` Potion ( c) is correct. (d) As `acne"Integre """^(2)rArrac ne b^(2)` `therefore ` Option (d)is correct. |
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| 9304. |
10 g of hydrogen and 64 g of oxygen were filled in a steed vessel and exploded. Amount of water produced in this reaction will be :- |
| Answer» Answer :A | |
| 9305. |
A conic has latus rectum length 1, focus at (2,3)and the corresponding directrix is x+y -3=0 . Then the conic is |
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Answer» a parabola |
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| 9306. |
If A = {1,2,3,4} , define relations on A which have properties of being : Reflexive , symmetric and transitive . |
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| 9307. |
Using the proprties of determinants in Exercise 7 to 9, prove that |{:(y+z,z+y),(z,z+x,x),(y,x,x+y):}|=4xyz |
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| 9308. |
If A=[[1,2],[-2,3]]B=[[3,2],[1,4]],C=[[2,2],[1,3]]Calculate CA. |
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Answer» SOLUTION :`CA=[[2,2],[1,3]][[1,2],[3,4]]` `=[[2.1+2.3""2.2+2.4],[1.1+3.3" "1.2+3.4]]=[[8,12],[10,14]]` |
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| 9309. |
Coefficient of x^(m) in the expansion of S = (1 + x)^(2m) + x(1 +·x)^(2m-1) + x^(2)(1 + x)^(2m- 2) + .... +x^(2m) is |
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Answer» `""^(2M)C_(m)+""^(2m+1)C_(m-1)` |
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| 9310. |
For non-negative integers n, let int(n)=(sum_(k=0)^(n)((k+1)/(n+2)pi)sin((k+2)/(n+2)pi))/(sum_(k=0)^(n)sin^2((k+1)/(n+2)pi)) Assuming cos^(-1)x takes values in [0.pi], which of the following options is/are correct? |
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Answer» If `mu=tan (cos^(-1)//(6),then" "ALPHA^2+2alpha-1=0` `int (n)=(sum _(k=0)^(n)sin((k+1)/(n+2))sin((k+2)/(n+2)pi))/(sum_(k=0)^(n)sin^2((k+1)/(n+2)pi))` `int (n)=(sum _(k=0)^(n)(cos.(pi)/(n+2)-cos((2k+3)/(n+2)pi)))/(sum_(k=0)^(n)(1-cos((2k+2)/(n+2)pi)))` `[because 2 sin B=cos(A-B)-cos (A+B)and 2sin^2A=1-cos 2A]` = ((cos(pi/(n+2)))sum_(k=0)^(n)1-{{:(cos'(3pi)/(n+2)+,cos'(5pi)/(n+2)+cos'(7pi)/(n+2)),(,+"........"+cos'((2n+3)/(n+2)pi)):}})/(sum_(k=0)^(n)1-{{:(cos'(2pi)/(n+2)+,cos'(4pi)/(n+2)+cos'(6pi)/(n+2)),(,+"........"+cos'((2n+2)/(n+2)pi)):}})` `[because cos (alpha)+cos(alpha+beta)+ cos (alpha+2beta)+.......` `+cos (alpha)+cos (alpha+beta)+cos(alpha+beta)+...` `+cosalpha+(n-1)(beta)=(sin((nbeta)/2))/(sin((beta)/2))cos((2alpha+(n-1)beta)/(2))]` `=((n+1)cos((pi)/(n+2))-(sin(pi-(pi)/(n+2)))/(sin((pi)/(n+2)))cos(pi+(pi)/(n+2)))/((n+1)-(sin((pi)/(n+2)))/(sin((pi)/(n+2)))cos(pi))` `=((n+1)cos((pi)/(n+2))+(sin((pi)/(n+2)))/(sin((pi)/(n+2)))cos((pi)/(n+2)))/((n+1)+(sin((pi)/(n+2)))/(sin((pi)/(n+2))))` `=((n+2)cos((pi)/(n+2)))/((n+2))=cos ((pi)/(n+2))` `rArr f(n)=cos ((pi)/(n+2))` Now, `f(6)=cos(pi)/(8)` `because alpha =tan cos^-1f(((6))=tan(pi)/(8)""{{:(because cos^-1cosx =X),(if x in (0,(pi)/(2))):}}` `=sqrt(2)-1` `rArr (alpha+1)=sqrt(2)rArr(alpha+1)^2=2rArr alpha^2+2alpha+1=2` `rArr alpha^2+2alpha-1=0` Now, `f(4)=cos ((pi)/(4+2))=cos (pi)/(6)=(sqrt(3))/(2)`, Now, `sin (7cos ^-1f(5))=sin(7cos^-1((pi)/(5+2)))` `sin(7(pi)/(7))=sinpi=0` and Now, `LIM(NTO oo)f(x)=lim(n to oo) cos (pi)/(n+2)=cos=1` Hence, options (a),(b) and (c) are correct. |
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| 9311. |
If z is a complex number such that (z-1)/(z+1) is purely imaginary then |z|= |
| Answer» ANSWER :A | |
| 9312. |
Decrypt the received encoded message [2,-3][20,4] with the encryption matrix [{:(-1,-1),(2,1):}] and the decryption matrix as its inverse, where the system of codes are described by the numbers 1-26 to the letters A-Z respectively, and the number 0 to a blank space. |
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| 9313. |
If A, B and C are three independent events such that P(A) = P(B) = P(C )= p,then P ( Atleasttwo of A, B, C occur) = 3p^(2) - 2p^(3). |
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| 9314. |
If a circle passes through the point (a,b) and cuts the circle x^2+y^2=k^2 orthogonally then the locus of its centre is |
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Answer» `2ax+2by=a^2+b^2+k^2` |
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| 9316. |
Write the distance of the point (2,3,6) from zx-plane. |
| Answer» Solution :The DISTANCE of p (x,y,Z) from orgin = 4 `rArrsqrt(x^2+y^2+z^2)=4rArrx^2+y^2+z^2=4` is the REQUIRED locus. | |
| 9317. |
If two tangents drawn from a point P to the parabola y^(2)=4x are at right angles then the locus of P is |
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Answer» ` 2X+ 1=0` |
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| 9318. |
Let f:RtoR be a differentiable function such that f(x)=x^(2)+int_(0)^(x)e^(-t)f(x-t)dt. y=f(x) is |
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Answer» injective but not surjective `x^(2)+int_(0)^(x)e^(-x-t)f(x-(x-t))dt` [Using `int_(a)^(b)f(x)DX=int_(a)^(b)f(a+b-x)dx`] `=x^(2)+e^(-x)int_(0)^(x)e^(t)f(t)dt`……………..2 Differentiating w.R.t.`x` we get `f'(x)=2x-e^(-x)int_(0)^(x)e^(t)f(t)dt+e^(-x)e^(x)f(x)` `=2x-e^(-x)int_(0)^(x)e^(t)f(t)dt+f(x)` `=2x+x^(2)` [using equation 2] `:. f(x)=(x^(3))/3+x^(2)+c` Also `f(0)=0` [from equation 1] or `f(x)=(x^(3))/3+x^(2)` or `f'(x)=x^(2)+2x` Thus `f'(x)=` has real roots. Hence `f(x)` is non monotonic. Hence `f(x)` is many one but range is `R` and hence, is surjective `int_(0)^(1)f(x)dx=int_(0)^(1)((x^(3))/3+x^(2))dx` `=[(x^(4))/12+(x^(3))/3]_(0)^(1)` `=1/12+1/3` `=5/12` |
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| 9319. |
The solution of (dy)/(dx) = 2xy - 3y + 2x - 3 is |
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Answer» `E^(x^(2)) + 3X = C(y+1)` |
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| 9320. |
A coin tossed twice. Find the probability of getting at most one head |
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Answer» `THEREFORE S={HH,HT,TH,T T}, |S|=4` Let A be the event of GETTING exactly one HEAD. `thereforeA={HT,TH,T T}implies|A|=3` `P(A)=|A|/|S|=3/4` |
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| 9321. |
Two numbers are selected from the numbers 1 to 11. If there sum is even find the probability of an event that both numbers are odd. |
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| 9322. |
Coefficient of x^n in e^(e^x)is 1/(n!) k then k = |
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Answer» `1+1/(1!) +1/(2!) +.......OO` |
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| 9323. |
Themaximum or minimum of the objective funtion occurs only at the corner points of the feasible region. This theorem is known as fundamental theorem of |
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Answer» Algebra |
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| 9324. |
The image of the point (4, -13) with respect to the line 5x+y+6=0 is : |
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Answer» (-1, -14) |
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| 9325. |
If the chords of contacts of the tangents from the points (x y,) and (x_(2), y_(2)) to the hyperbola 2x^(2) - 3y^(2) = 6 are at right angle, then 4x_(1)x_(2) + 9y_(1)y_(2) is equal to |
| Answer» ANSWER :B | |
| 9326. |
Sketch theregion{(x,0) //y= sqrt( 4-x^2)} andX- axis. Findthe areaof theregionusingintegration. |
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| 9328. |
Ratio of seventh term from beginning and seventh term from end in the expansion of (root(3)(2)+(1)/3_sqrt(3))^(n)"is"1 : 6 .Find value of n . |
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| 9329. |
Complementary events of E and Fare E' and F' respectively if 0 lt P(F) lt 1 then ………… |
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Answer» <P>`P(E//F) + P(E'//F) = 1` |
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| 9330. |
Special fluid helps in transportation of substances in complex animals is/are :- |
| Answer» Answer :A | |
| 9331. |
(i) y=e^(x)sin^(3)xcos^(4)x (ii) y=x*e^(xsinx) |
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| 9333. |
Use induction to prove that, int _(0) ^(pi//2) cos ^(n-1) x sin nx dx = AA n ge 2, n in N |
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| 9334. |
Let f :R to R is not identically zero, differentiable function and satisfy the equals d (xy)= f(x) f(y) and f (x+z) + f(x) + f (a), then f (5)= |
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Answer» 3 |
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| 9336. |
A chemist wishes to provide his consumers, at least cost, the minimum daily requirements of two vitamins A, B by using a mixture of two products M and N. The amount of each vitamin in one gram of each product, cost per gram of each product and the minimum daily requirement are given below: Find the least expensive combination which provides the minimum requirement of the two vitamins. |
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| 9337. |
A car moving with a speed of 40 km/hr can be stopped by applying brakes after at least 2 m. If the same car is moving with a speed of 80 km/hr. What is the stopping distance ? |
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Answer» 2 m |
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| 9339. |
The value of int_(0)^(a)(sqrt(a^(2)-x^(2)))^(3) dx is……. . |
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Answer» `(pia^(3))/(16)` |
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| 9340. |
If f(x) = sin^(-1) x. cos^(-1) x. tan^(-1) x . cot^(-1) x. sec^(-1) x. cosec^(-1) x, then which of the following statement (s) hold(s) good? |
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Answer» The graph of y = F (x) does not lie above x axis |
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| 9341. |
Find the number of ways of arranging the letters of the word SINGING so that the two G's come together |
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| 9342. |
If I= int_(0)^(pi//4) ( sqrt(sin x) + sqrt(cos x) )^(-4) dx then I equals |
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| 9343. |
Let Z be the set of integers and o be a bonary operation of z defined as aob = a + b - ab for all a, b in Z. The inverse of an element a (ne 1 ) in Z is |
| Answer» Answer :A | |
| 9344. |
If alpha, beta , gamma are the roots of x^(3) + 3px + q = 0then the equation whose roots are(alpha + 1)/( beta + gamma - alpha), (beta + 1)/(gamma + alpha - beta) and (gamma + 1)/(alpha + beta - gamma) is |
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Answer» `8Y^(3) + 12y^(2) + (6 + 6P) y + 1 + 3p - q = 0 ` |
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| 9345. |
Let f(x) = [{:((g(x) - g(a))/(x-a),x ne 0),(g'(a),x = a):}, where g is a function derivable at x = a, then at x = a : |
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Answer» F is continuous only if G'(a) = 0 |
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| 9346. |
If the orthocentre of the triangle formedby the lines 2x+3y-1=0, x+2y-1=0, ax+by-1=0 is at the origin, then (a, b) is given by |
| Answer» ANSWER :C | |
| 9347. |
Equation of a line passing through (-1, 2, -3) and perpendicular to the plane 2x + 3y + z + 5=0 is |
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Answer» `(x-1)/(-1)=(y+2)/(1)=(z-3)/(-1)` |
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| 9348. |
Evaluate the following integrals int (x^3-x^2 +x -1)/(x-1) dx |
| Answer» SOLUTION :`INT (x^3-x^2+x-1)/(x-1) DX = int(x^2(x-1)+x-1)/(x-1) dx = int (x^2+1)dx = x^3/3 +x+c` | |
| 9349. |
Consider the parabola x ^(2) + 4x - 2y + 6 = 0. If its chord AB 2mx - 2y + (4m + 3) =0 intersect its axis at K and directrix at M, then AM, KM and BM are in |
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Answer» A.P |
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| 9350. |
You are running out of time but have no idea about the route from Nepal to IIT Guwahati. The various cut-out parts of the map that can help you reach IIT Guwahati are hidden in the houses shown in the figure below. You will get the parts of the map only on delivering the right article(one per house) to all the houses. (i)An ‘X’ coloured ARTICLE should be delivered to an ‘X’ coloured HOUSE only by using an ‘X’ colouredTRUCK. (ii)A truck can also carry other coloured articles so that it can place them at any of the CHECKPOINTS from where other truck can later carry it to the destination. (iii) Trucks can carry any number of articles at a time. (iv) The main objective is to start all the trucks at the same time, with same speed and deliver the articles without collision of trucks. Also, a truck picks up every article that comes on its way. (v)Last and the most importantly, the PATHS of the trucks should not overlap at any point other thanjunctions.At junctions, the paths can though cross each other (but both trucks should not reach that junction at same time which leads to collision). The trucks can move only forward. Give the total number of articles carried by the red truck on it’s way. |
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Answer» 1 From the above FIGURE, No. of turns taken by BLUE truck = 6. No. of articles CARRIED by RED truck = 2 ( 1red + 1blue ). |
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