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9651.

Let ABC be triangle whose equation of sides are AB=x+2y=3, AC=2x+y=3 and BC=x+y=4 . S_1,S_2,S_3 are three circles drawn considering AB,AC and BC as diameter respectively. The radical axis of S_1 of S_2,S_1 and S_3 and S_2and S_3 are L_12 =0 , L_13 =0 ,L_23=0 .These radical axes meet sides BC,AC and AB at D,E,Frespectively and triangle DEF is formed. Equation of L_12=0 is

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x-y=2
2x+3y=5
x-y=0
none of these

ANSWER :C
9652.

Let ABC be triangle whose equation of sides are AB=x+2y=3, AC=2x+y=3 and BC=x+y=4 . S_1,S_2,S_3 are three circles drawn considering AB,AC and BC as diameter respectively. The radical axis of S_1 of S_2,S_1 and S_3 and S_2and S_3 are L_12 =0 , L_13 =0 ,L_23=0 .These radical axes meet sides BC,AC and AB at D,E,Frespectively and triangle DEF is formed. Radical centre of circles S_1,S_2,S_3 is

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(3,-3)
(-3,-3)
(-7,-7)
NONE of these

ANSWER :C
9653.

Let ABC be triangle whose equation of sides are AB=x+2y=3, AC=2x+y=3 and BC=x+y=4 . S_1,S_2,S_3 are three circles drawn considering AB,AC and BC as diameter respectively. The radical axis of S_1 of S_2,S_1 and S_3 and S_2and S_3 are L_12 =0 , L_13 =0 ,L_23=0 .These radical axes meet sides BC,AC and AB at D,E,Frespectively and triangle DEF is formed. Equation of circumcircleof triangle ADC is a

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`x^2+y^2-6x+4=0`
`x^2+y^2-6y+4=0`
`x^2+y^2+6x+4=0`
NONE of these

ANSWER :B
9654.

Evaluate int(1)/((x-1)sqrt(x+2))dx

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ANSWER :`1/(SQRT(3))log|(sqrt(x+2)-sqrt(3))/(sqrt(x+2)+sqrt(3))|+C`
9655.

f and g are real valued function f(x) =x^(2) + x + 7 , x in R and g(x) = 5x -3 , x in R. Find fog and gof. Also find (fog) (2) and (gof) (1).

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SOLUTION :N/A
9656.

For|x|lt(1)/(5)thecoefficientofx ^ 3intheexpansion of(1)/((1 - 5x ) ( 1 - 4 x))is

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369
370
371
372

Solution : ` (1)/(( 1 - 5 x)( 1 - 4x )) = (1 - 5x ) ^(-1) (1 - 4x ) ^( -1 ) `
`= [ 1 + 5x+(5x ) ^ 2+ (5x ) ^3 + …. ][ 1+ 4x+ (4x) ^ 2+(4x ) ^3 + … ]`
`therefore`Co- efficientof` x ^ 3` intheaboveexpansion
`= (1)(4) ^3+ 5 (4)^2 + (5 ^ 2 ) (4)+1 (5) ^ 3 `
`= 64+80+ 100 +125 `
` = 369 `
9657.

Find the approximate value of each of the following :cos 29^(@)

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ANSWER :`(SQRT(3))/(2)+(PI)/(360)`
9658.

Evaluate the definite integrals int_(0)^(pi/2)cosxdx

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9659.

If the distance between two points A and B is d, and the lengths of the projections of AB on the coordinate planes are d_(1), d_(2), d_(3), then

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`2d^(2) = d_(1)^(2) + d_(2)^(2) + d_(3)^(2)`
`d_(1) + d_(2) + d_(3) = 0`
`d_(1)^(2) + d_(2)^(2) + d_(3)^(2) = d^(2)`
`d_(1) + d_(2) + d_(3) = d`

ANSWER :A
9660.

Statement I : The points 4i + 5j + k, -j -k, 3i + 9j + 4k and -4i + 4j + 4k are coplanar. Statement II : The given points from the vertices of a parallelogram. Which of the following is true ?

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Both statements are true and statement II is CORRECT EXPLANATION of staement I
Both statements are true and statement II is not a correct explanation of statement I
Statement I is true and Statement II is false
Statement I is false and STATEMETN II is true

Answer :C
9661.

Solve : x " sin"(y)/(x).(dy)/(dx)=y " sin"(y)/(x)-x

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`E^((y)/(x)) = CY`
`e^(cosy//x) = cx`
`e^((x)/(y)) = cx`
`e^((2Y)/(x)) = cx`

Answer :B
9662.

If the projection of the line x/2=(y-1)/2=(z-1)/1 on a plane P is x/1=(y-1)/1=(z-1)/-1. Then the distance of plane P from origin is

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`SQRT(3)`
`sqrt(3/2)`
`sqrt(6)`
`2/sqrt(3)`

SOLUTION :Projection of line `x/2=(y-1)/2=(z-1)/1` on a plane P is `x/1=(y-1)/1=(z-1)/-1`.
`therefore` Plane through these lines is PERPENDICULAR to the plane P.
Normal to the plane determined by the given lines is.
`|{:(hati,HATJ,hatk),(2,2,1),(1,1,-1):}|=-3hati+3hatj`
9663.

int _(0) ^(1//2)[sin 4 pix] dx=

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`pi-1`
`2/pi`
`1/pi`
`0`

ANSWER :C
9664.

Method of integration by parts : int e^(x)((x^(2)+1))/((x+1)^(2))dx=....

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`((X-1)/(x+1))E^(x)+C`
`e^(x)((x+1)/(x-1))+c`
`e^(x)(x+1)(x-1)+c`
NONE of these

Answer :A
9665.

Consider aDelta ABC and let a, b and c denote the lengths of the sides opposite to vertices A, B and C, respectively. Suppose a=2, b = 3, c = 4and H be the orthocenter. Find 15(HA)^(2).

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ANSWER :11
9666.

Multiply(x-(1+sqrt(-3))/2)(x-(1-sqrt(-3))/2)

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SOLUTION :`(X-(1+sqrt(-3)/2)(x-(1-sqrt3)/2)`
`=(X+(-1-isqrt3)/2)(X+(-1+isqrt3)/2)`
`=(X+omega)(X+omegea^2)=X^2+omega^2X+omegaX +omega^3`
`=X^2+X (omega^2+omega) +1=X^2-X+1`
9667.

Fill in the gaps with correct answer .sin^2(24)^@-sin^2(6)^@ = _____.

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SOLUTION :`(sqrt5-1)/8`
9668.

Let a,lambda,mu in R, Consider the system of linear equations ax+2y=lambda 3x-2y=mu Which of the flollowing statement (s) is (are) correct?

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If `a=-3`, then the SYSTEM has infinitely MANY solutions for all values of `lambda and mu`
If `a ne-3`, then the system has a UNIQUE solution for all values of `lambda and mu`
If `lambda+mu=0`, then the system has infinitely many solution for `a=-3`
IF `lambda+mune0`, then the system has no solution for `a=-3`

9669.

Evaluate (sqrt(3) + sqrt(2))^(6) - (sqrt(3) - sqrt(2))^(6)

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ANSWER :`396sqrt(6)`
9670.

Find the equation of the circle which touches X-axis at a distance of 3 units from the origin and making an intercept of length 6 on Y- axis.

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Answer :` X ^(2) + y ^(2)- 6x + 6 SQRT2 y + 9=0 and x^(2) + y ^(2)- 6x -6 sqrt2 y + 9 =0`
9671.

In the three element group {e,a,b} where e is the identity ,a^(5)b^(4) is equal to

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a
e
ab
b

Answer :A
9672.

Find the sum of all 4 digit numbers formed with the digits 1, 2, 4 and 6.

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36664
26664
24
46632

Answer :B
9673.

Evaluate the following integrals (iii) int_(0)^(pi) x sin^(7) x cos^(6) x dx

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ANSWER :`(16pi)/(3003)`
9674.

The product of (32)(32)^(1//6)(32)^(1//36) …….. To infty is

Answer»

16
32
64
0

Answer :C
9675.

Which of the following when simplified, reduces to unity?

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`log_(10)5. log_(10) 20+ log_(10)^(2)2`
`(2 log 2+ log 3)/(log 48 - log4)`
`-log_(5),log_(3) = sqrt(ROOT5(9))`
`(1)/(6) log_((sqrt(3))/(2))((64)/(27))`

ANSWER :A::B::C::D
9676.

Evaluation of definite integrals by substitution and properties of its : If n is an integer int_(0)^(pi)e^(cos^(2)x)cos^(3)(2n+1)xdx=............

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1
`-1`
0
`PI`

ANSWER :C
9677.

If A = [(alpha ,0),(1,1)] and B = [(1,0),(5,1)]whenever A^(2) = Bthen value of alphais :

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5
-1
11
no REAL VALUE of `ALPHA `

ANSWER :D
9678.

{:(" "Lt),(n rarr oo):}{ (1)/(2n+1)+(1)/(2n+2)+......+(1)/(3n)}=

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ANSWER :`LOG((3)/(2))`
9679.

Equation of the tangent to the circle x^(2)+y^(2)-2x+4y-4=0 which is parallel to the line 3x+4y-1=0 is

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`3x+4y=5`
`3x+4y=15`
`3x+4y=10`
`3x-4y=10`

ANSWER :C
9680.

Determine with proof all triples (a, b, c) of positive integers satisfying 1/a+2/b+3/c=1where a is a prime number and a le b lec

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ANSWER :(2,5,30)(2,6,18)(2,7,14)(2,8,12)(2,10,10)(3,4,6)(3,6,9)
9681.

Differentiate the following w.r.t.x e^(mtan^-4x)

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SOLUTION :`d/dx(E^(mtan^-1x))=e^(mtan^-1x)d/dx(mtan^-1x)e^(mtan^-1xm/(1+x^2)=(me^(mtan^-1x))/(1+x^2)`
9682.

A particle is moving along a curve 6y=x^(3)+2. Find the points on the curve at which y-coordinate is changing 8 times as fast as the x-coordinate.

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ANSWER :(4, 11), `(-4, -31/5)`
9683.

Solve the following differential equations.dy/dz=secy

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Solution :`DY/DZ=secyrArr cos y CDOT dy =dz`
`RARR sin y =z+C`
9684.

A: In a Delta ABC (a+b+c) (b+c-a) =Abc if 0 lt lamda lt 4 R: In a Delta ABC,-1 le cos A le 1

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A is TRUE, R is true and R is CORRECT explanation of A
A is true, R is true and R is not correct explanation of A
A is true, R is FALSE
A is false, R is true

Answer :C
9685.

LetD and E be the midpoints of the sides AC and BC of a triangle ABC respectively . If O is an interior point of the triangle ABC such that OA + 2OB+ 3OC= 0, then the area (in sq units) of the triangle ODE is

Answer»

6
5
`(3)/(4)`
0

Answer :D
9686.

Evaluate int(cos4x+cos2x)/(sin4x+sin2x)dx.

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SOLUTION :`INT(cos4x+cos2x)/(sin4x+sin2x)==int("2cos"(6x)/2"cos"(2X)/2)/(2"sin"(6x)/2"cos"(2x)/2)dx =intcot3xdx=1/3In|sin3x|+C`
9687.

If 2[(3,4),(5,x)]+[(1,y),(0,1)]=[(7,0),(10,5)], find (x-y).

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ANSWER :10
9688.

A: In a Delta ABC, if the sides a,b,c are in A.P. then a cos^2""C/2+c cos^2""A/2=3b R: In a Delta ABC, if A,B,C are in A.P. then B=pi//3

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A is true, R is true and R is CORRECT EXPLANATION of A
A is true, R is true and R is not correct explanation of A
A is true, R is false
A is false, R is true

Answer :D
9689.

Number of diagonals in a decagon is

Answer»

45
36
46
35

Answer :D
9690.

Length of the perpendicular form the point (-6,2,3) on the plane 3x-6y+2z+10=0 is

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2
`(13)/(7)`
`(10)/(7)`
`(8)/(7)`

ANSWER :A
9691.

If [(a-b,2a+c),(2a-b,3c+d)]=[(-1,5),(0,13)], then a = __________.

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ANSWER :`a=1`
9692.

If int((sqrt(x))^(5))/((sqrt(x))^(7)+x^(6))dx=lamdaln(1+2cosx)/((2+cosx)^(2))+C, then a+lamda is

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`=2`
`gt2`
`LT2`
`=1`

Answer :B
9693.

Evaluate the following integrals: int_0^(pi/4) tanx dx

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SOLUTION :`int_^(pi/4) tanx dx = [log |SECX|]_0^(pi/4)`
=`log|SEC pi/4 |-log |sec 0`
=`log |sqrt2| -log|1|`
=`log|sqrt2| = log^(1/2) = 1/2 log2`
9694.

If the lines x^(2) + 2xy- 35 y^(2) - 4x +44y - 12 = 0 and 5x + lambda y - 8 = 0 are concurrent , then the value of lambda is ,

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0
1
`-1`
2

Answer :D
9695.

The solution for x of the equation int_(sqrt(2))^(x) (dt)/(|t|sqrt(t^(2)-1))=pi/2 is

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`2sqrt(2)`
2
`PI`
`-SQRT(2)`

ANSWER :D
9696.

What is the value of lambda if the triangle whose vertices are hat(i), hat(j) and hat(i)+hat(j)+lambdahat(k) will be right angled?

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2
0
-1
1

Solution :Let us consider TRIANGLE ABC. Suppose `hat(i), hat(j) and hat(i)+hat(j)+lambda hat(K)` are the position vector of A, B and C.
Then `vec(AB)=hat(j)-hat(i), vec(AC)=hat(j)+lambda hat(k), vec(BC)=hat(i)+lambda hat(k)`
`|vec(AB)|=sqrt((-1)^(2)+(1)^(2))=sqrt(2)`
`|vec(BC)|=sqrt((1)^(2)+(lambda))^(2))=sqrt(1+lambda^(2)`
`|vec(AC)|=sqrt((1)^(2)+(lambda))^(2)=sqrt(1+lambda^(2))`
9697.

Find the equation of the circle passing through the three points (4, 7), (5, 6) and (1, 8). Also find the coordinates of the point of intersection of the tangents to the circle at the points where it is cut by thestraight line 5x + y + 17 = 0.

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ANSWER :`(-4, 2), x^(2) + y^(2) - 2X - 6y - 15 = 0`
9698.

A monopolist's demand function is p= 300 - 5x. At what price is the marginal revenue zero.

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ANSWER :RS 150
9699.

Sum of n terms of the series (1^(4))/(1.3)+(2^(4))/(3.5)+(3^(4))/(5.7)+…. is equal to

Answer»

`(N(n+1)(2N^(2)+n+1))/(6(2n+1))`
`((n+1)(n^(2)+1))/(6(2n+1))`
`((n+1)((2n+1)^(2)+1))/(8(2n+1))`
`(n(n+1)((2n+1)^(2)+1))/(16(2n+1))`

ANSWER :B
9700.

A merchant plans to sell two types of personal computers -a desktop model and a portable model that will cost Rs. 25000 and Rs. 40000 respectively. He estimates that the total monthly demand of computers will not exceed 250 units. Determine the number of units of each type of computers which the merchant should stock to get maximum profit if he does not want to invest more than Rs. 70 lakhs and if his profit on the desktop modelis Rs. 4500 and on portable model is Rs. 5000.

Answer»

Solution :Let `X` and `y` be the number of desktop and protable COMPUTERS respectively.
According to the problem,
MAXIMUM profit `Z=4500x+5000y`
and constraints `xge0, yge0`
`x+yle250`
`25000x+40000yle7000000`
`implies25x+40yle7000`
`implies25x+40y le7000`
First, draw the graph of the lines `x+y=250` and `25x+40y=7000`.
Now, find the feasible region from the constraints`xge0,yge0,x+yle250, 25x+40yle7000` and shade it. The vertices of this shaded region are `A(250,0),B(200,50)` and `C(0,175)`. We find the value of `Z` at these vertices.

For the the maximum profit 200 desktop and 50 portable computers should be produced.