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10101.

Let a=2hat(i)-hat(j)+hat(k), b=hat(i)+2hat(j)-hat(k) and c=hat(i)+hat(j)-2hat(k) be three vectors, A vector in the plane of b and c whose projection on a is of magnitude sqrt(2/3), is

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`2hat(i)+3hat(j)-3hat(k)`
`2hat(i)+3hat(j)+3hat(k)`
`2hat(i)-5hat(j)+5hat(k)`
`2hat(i)+hat(j)+5hat(k)`

Solution :Any vector I the PLACE of b and C is
`r=mb+c(m+1)HATI+(2m+1)hati+(-m-2)hatk`
PROJECTION of r on a `=(r*a)/(|a|)=|sqrt(2/3)|`
`:.""(2(m+1)-(2m+1)+(-m-2))/(sqrt6)=+-sqrt(2/3)`
`rArr""-m-2+-2rArrm=-3"and"1`
Hence, `r=-2hati-5hatj+hatk" and "r=2hati+3hatj-3hatk`
10102.

in the given figure y=x^(2)+bx+c is a quadratic polynomial which meets x-axis at A and B and y-axis at C Q is vertex of quadratic polynomial and foot of perpendicular from Q to x-axis and y-axis are P and R respectively. Then answer the following questions. Q. If ("area of" DeltaABC)/("Area of rectangle" OPQR)=(8)/(3) satisfies the relation b^(2)=kc then k will be

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`9`
`(2)/(9)`
`(9)/(2)`
`2`

Solution :`((1)/(2)(beta-alpha)C)/(((b^(2)-4c)/(4))(-(b)/(2)))=(8)/(3)` squaring and using
`(beta-alpha)^(2)=b^(2)-4c`
`9C^(2)=4b^(4)-16b^(2)c`
`4b^(4)-16b^(2)c-9c^(2)=0`
`4b^(4)-18B^(2)c+2b^(2)c-9c^(2)=0`
`(2b^(2)+c)(2b^(2)-9c)=0impliescgt0because2b^(2)+cne0`
`(b^(2))/(c)=(9)/(2)implies(b^(2))/(c)=4.5`
10103.

in the given figure y=x^(2)+bx+c is a quadratic polynomial which meets x-axis at A and B and y-axis at C Q is vertex of quadratic polynomial and foot of perpendicular from Q to x-axis and y-axis are P and R respectively. Then answer the following questions. Q. if two circles passing through A and B touches y-axis at C and R respectively then

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`b^(2)=2C`
`b^(2)=3C`
`b^(2)=4c`
`b^(2)=8C`

Solution :`OA.OB=OC^(2)`
`alpha.beta=c^(2)` & `((b^(2)-4c)/(4))^(2)=alphabeta`
`(b^(2)-4)^(2)=16`
`c=c^(2)` `b^(2)-4=4`
`c=1` `b^(2)=8`
10104.

sum _(r = 2) ^(oo) (1)/(r ^(2) - 1) is equal to :

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ANSWER :`3//4`
10105.

Find the equation of the circum circle of the triangle formed by the lines5x -3y + 4=0, 2x + 3y -5 =0 , x + y =0

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ANSWER :` 49 (x^(2) +y^(2)) +280x - 259y + 245 =0 `
10106.

Examine the following functions for continuity : f(x)=x^(3)+x^(2)-1

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ANSWER :CONTINUOUS
10107.

Evaluate the deternminant Delta=|{:(1,2,4),(-1,3,0),(4,1,0):}|

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ANSWER :-52
10108.

Let f(x) is of the form alpha z _beta , where alpha, beta are constants and alpha, beta,z are complex numbers such that |alpha| ne |beta|.f(x) satisfies followingproperties : (i)If imaginary part of z is non zero, then f(x)+bar(f(z)) = f(barz)+bar(f(z)) (ii)If real part of of z is zero , then f(z)+bar(f(x)) =0 (iii)If z is real , then bar(f(x)) f(x) > (x+1)^2 AA z in R (4x^2)/((f(1)-f(-1))^2)+y^2/((f(0))^2)=1 , x , y in R, in (x,y) plane will represent :

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HYPERBOLA
circle
ELLIPSE
PAIR of LINE

ANSWER :A
10109.

Let f(x) is of the form alpha z _beta , where alpha, beta are constants and alpha, beta,z are complex numbers such that |alpha| ne |beta|.f(x) satisfies followingproperties : (i)If imaginary part of z is non zero, then f(x)+bar(f(z)) = f(barz)+bar(f(z)) (ii)If real part of of z is zero , then f(z)+bar(f(x)) =0 (iii)If z is real , then bar(f(x)) f(x) > (x+1)^2 AA z in R Consider ellipse S:x^2/((Re(alpha))^2) + y^2/(Im(beta))^2) =1 , x, y in R in (x,y) plane , then point (1,1) will lie :

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OUTSIDE the ELLIPSE S
INSIDE the ellipse S
on the ellipse S
none of these

Answer :B
10110.

sin^(2) (3^(@))+sin^(2) (6^(@))+sin^(2) (9^(@))+...+sin^(2) (84^(@))+sin^(2) (87^(@))+sin^(2) (90^(@))=

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`31/2`
`39/2`
`59/2`
36

Answer :A
10111.

Choose the correct answer. The degree of the differential equation 2x^2(d^2y)/(dx^2) - 3((dy)/(dx)) + y = 0 is

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2
1
0
not DEFINED

ANSWER :A
10112.

f(x) is a polynomial of degree 3 passing through the origin having local extrema atx=+- 2 Statement-I: Ratio of theareas in which f(x) cuts the circle x^(2) +y^(2) =36is 1: 1 Statement-II Both y= f(x) and the circle are symmetric about the origin

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STATEMENT -I is TRUE statement -II is a CORRECT explanation for statement-I
Statement -I is true ,Statement-II is not Trueexplanation for Statement-I
Statement -I is True Statement-II is FALSE
Statement -I is False,Statement -II is True

ANSWER :A
10113.

Figure shows three events A,B and C. Probabilities of differents events are shown in the figure. For instance,P(AnnB'nnC')=0.18, P(A'nnBnnC')=0.06 " etc". Which of the following is false?

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A and B are INDEPENDENT
B and C areindependent
A and C are independent
A and `B NN C`are independent

Solution :
10114.

If((x + 1 ))/((2x - 1 ) (3x + 1 ))= (A)/((2x - 1 ))+ (B)/((3x+ 1)) , then16 A +9 Bisequalto

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4
5
6
8

Solution : ` ((X + 1 ))/((2x - 1 )(3x+ 1 )) = (A)/((2x - 1)) + (B)/((3x+ 1 )) `
` rArrx + 1= A (3x + 1 ) + B(2x - 1) `
` rArrx + 1=x (3A + 2B)+(A -B) `
`3A +2B = 1`
` A -B = 1`
` rArrA =1 + B `
` 3( 1 + B)+2B =1`
`rArr3+5B = 1`
` B = (-2)/(5) `
` A =1+B =1-( 2 ) /(5) `
` A =(3)/(5) `
`therefore16 A +9B =16 ((3)/(5)) +9 ((-2)/(5)) =(30)/(5)= 6 `
10115.

Find the value of sum_(1 le I,)sum_(j le n)(1).

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SOLUTION :N/A
10116.

Calculate the area enclosed in the region (i) {(x,y):x ^(2) + y ^(2) le 1 le x + y} (ii) {(x,y):x ^(2) + y ^(2) le 4x, 4x^(2) + 4y ^(2) le 9} (iii) {(x,y) : x ^(2) + y ^(2) le 16, x ^(2) le 6y} (iv){(x,y) :y ^(2) le 6 ax, x ^(2) +y ^(2) le 16a^(2)} (v) {(x,y) :x ^(2) +y ^(2) le 8, x ^(2) le 2y}.

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Answer :`(i) ((pi)/(4) - (1)/(2)) (II) (( 2sqrt2)/(3) - (1)/(sqrt2) + (9pi)/(8) - (9)/(4) sin ^(-1) "" (1)/(3)) (iii) (4)/(3) (4PI + SQRT3) (iv) (4a ^(2))/(3) (4 pi + sqrt3) (v) (2pi + (4)/(3))` (sq. units).
10117.

vec(r )=(hat(i) +2hat(j) +hat(k)) + lambda(hat(i)-hat(j) + hat(k)) vec(r )=(2hat(i) -hat(j) -hat(k)) + lambda(2hat(i) + hat(j) +2hat(k))

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ANSWER :`(3sqrt(2))/(2)` UNITS
10118.

sqrt3 cosec 20^(@) -sec 20^(@) is equal to

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2
`2 SIN 20^(@) cosec 40^(@)`
4
`4 sin 20^(@) cosec 40^(@)`

ANSWER :C
10119.

Prove the following int_-1^1 x^(17) cos^4x dx = 0

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Solution :`(-X)^(17) cos^4(-x) = -x^(17)cos^4x`
`GT x^(17) cos^4x` is an ODD function.
THEREFORE `int_-1^1 x^(17) cos^4x dx = 0`
If F(x) is an odd function, then `int_-a^a f(x) dx = 0`
10120.

Let bar(x) and M.D be the mean and the mean deviation about bar(x)of n observations x_(p) , i=1, 2 . . . . .n . If each of the observation is increased by 5, then the new meandeviation aboutthe new mean, respectively are .

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`BAR(x) , M.D`
`bar(x) + 5, M.D`
`bar(x), M.D. + 5`
`bar(x) - 15 , m M. D. + 5`

ANSWER :B
10121.

Consider hyperbola xy = 16 to find the following: (i) Coordinates of vertices (ii) Length of transverse axis (iii) Coordinates of foci (iv) Length of latus rectum (v) Equations of two directrices (vi) Equation of tangent at point (2, 8) (vii) Equation of normal at point (2, 8) (viii) Equation of chord of contact w.r.t. point (2, 3) (ix) Equation of chord which gets bisected at point (5, 6) (x) Equation of tangent having slope - 2 (xi) Equation of noraml having slope 2

Answer»

Solution :We havehyperbola xy = 16.
(i) Clearly, transverse axis is `x-y=0` and conjugate axis is `x+y=0.`
Vertices are points of intersection of transverse axis `x-y=0` and hyperbola.
So, vertices are `A (4,4) and A'(-4,-4).`
(ii) Length of transverse axis is `"AA'"=8sqrt2=(=2a).`
(iii) Foci lie at distance 'ae' from centre on line `x-y=0.`
Now, `ae=4sqrt2sqrt2=8`
Therefore, foci are `F_(1)(4sqrt2, 4sqrt2) and F_(2)(-4sqrt2, -4sqrt2)`.
(iv) Length of latus rectum `=(2b^(2))/(a)=2a=8sqrt2`
(as a = b for rectangular hyperbola)
(v) Each of the directrices lies at distance `(a)/(e)(=4)` from centre and is parallel to the conjugate axis `x+y=0`.
So, equation of two directrices are `x+y=pm4sqrt2`.
(VI) Equation of tangent at point (2, 8) is
T = 0
`rArr""(2y+8x)/(2)-16=0`
`rArr""4x+y-16=0`
Alternatively, we can differentiate the equation of curve to get the slope of tangent.
Then, we get
`y+x(dy)/(dx)=0`
`therefore""(dy)/(dx)=-(y)/(x)`
`therefore""((dy)/(dx))_(("2,8"))=-(8)/(2)=-4`
So, equation of tangent at (2, 8) is
`y-8=-4(x-2)`
`rArr""4x+y-16=0`
(vii) Equation of normal at (2,8) is `x-4y+30=0`.
(VIII) Equation of chord of contact w.r.t. point (2, 3) is
T = 0
`rArr""(2y+3x)/(2)-16=0`
`rArr""3x+2y-32=0`
Equation of chord which GETS bisected at point (5,6) is
T = `S_(1)`
`rArr""(5y+6x)/(2)-16=(5)(6)-16`
`rArr""6x+5y=60`
(x) To find the equation of tangent having slope `-2`, we differetiate the curve and compare derivative to `-2`.
`therefore""(dy)/(dx)=-(y)/(x)=-2`
`therefore""y=2x`
Solving this with hyperbola, we get points `P(sqrt8, 2sqrt8)`and `Q(-sqrt8,-2sqrt8)` on the hyperbola where slope of tangent is `-2.`
Equation of tangent at point P is
`y-2sqrt8=-2(x-sqrt8)`
`rArr""2x+y=4sqrt8`
Equation of tangent at point Q is
`y+2sqrt8=-2(x+sqrt8)`
`rArr""2x+y=-4sqrt8.`
(xi) We have `(dy)/(dx)=-(y)/(x)`
THUS, slope of normal at any point on the curve is `-(dx)/(dy)=(x)/(y)=2` (given)
`therefore""x=2y`
Solving this with hyperbola, we get points `A(2sqrt8, sqrt8)` and `B(-2sqrt8-sqrt8)` on the hyperbola where slope of normal is 2.
Equation of normal at point A is
`y-sqrt8=2(x-2sqrt8)`
`rArr""2x-y=3sqrt8`
Equation of normal at point B is
`y+sqrt8=2(x+2sqrt8)`
`rArr""2x-y=-3sqrt8`
10122.

If y= sqrt(sin x + y), then (dy)/(dx) is equal to

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`(COS X)/(2y-1)`
`(cos x)/(1-2y)`
`(SIN x)/(1-2y)`
`(sin x)/(2y-1)`

ANSWER :A
10123.

If X represents difference between the number of heads and number of tails obtained when a fair coin is tossed 3 times. Then find mean and variance of X.

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ANSWER :MEAN = 0, VARIANCE =3
10124.

f(x)= |(sin x,cos x),(tan x,cot x)| then f'((pi)/(4))= …….

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0
`-SQRT2`
`-2 sqrt2`
`sqrt2`

ANSWER :D
10125.

If f(x) is a polynomial such that (alpha+1)f(alpha)-alpha=0AA alpha epsilon Nuu{0}, alpha le n, then

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`f(76)` is 1
`f(21)` is `10/11`
`f(37)` is `1/7`
`f(148)` is `9/13`

Solution :`G(X)=(x+1)f(x)-xs`
`g(x)=0` for `x=0,1,2,……..n`
`g(x)=ax(x-1)…….(x-n)`
`:. (f(x)=((-1)^(n+1)x.(x-1)…..(x-n))/(|___(n+1))+x)/(x+1`
10126.

Find (dy)/( dx), if x=a [ cos t + log ( tan ""t//2)]& y= a sin t

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ANSWER :`(DY)/( dx) = (dy//dt)/( dx//dt) = ( a COS t)/( ( a cos^(2) t)/( sin t) )= ( SINT )/( cos t) = TAN t`
10127.

underset(r=0)overset(10)sum (40-r)C_(5)=

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`""^(41)C_(5)-""^(30)C_(5)`
`""^(41)C_(6)-""^(30)C_(6)`
`""^(41)C_(5)+""^(30)C_(5)`
`""^(41)C_(6)`

Answer :B
10128.

a is perpendicular to both b and c . The angle between b and c is (2 pi)/(3). If |a| = 2, |b| = 3, |c| = 4, then c. (a xx b) is equal to

Answer»

`18 sqrt(3)`
`12 sqrt(3)`
`8 sqrt(3)`
`6 sqrt(3)`

ANSWER :B
10129.

If the normal at P ony^(2)= 4ax cuts the axis of the parabola in G and S is the focus then SG=

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<P>SP
2 SP
`(1)/(2)` SP
`sqrt(P)`

Answer :A
10130.

Evaluate the following integrals (v) int_(0)^(1)x tan^(-1) x dx

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ANSWER :`(pi-2)/(4)`
10131.

b=2.35+0.25x c=1.75+0.40x In the equations above, b and c represent the price per pound, in dollars, of beef and chicken, respectively, x weeks after July 1 during last summer. What was the price per pound of beef when it was equal to the price per pound of chicken?

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`$2.60`
`$2.85`
`$2.95`
`$3.35`

ANSWER :D
10132.

You are given that A and B are two events such that P(B)= (3)/(5), P(A//B)= (1)/(2)and P(A cup B)= (4)/(5)then P(A) equal …….

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`(3)/(10)`
`(1)/(5)`
`(1)/(2)`
`(3)/(5)`

ANSWER :C
10133.

If the point P(4, –2) is the one end of the focal chord PQ of the parabola y^(2) = x, then the slope of the tangent at Q is

Answer»

`-1//4`
`1/4`
`4`
`-4`

Solution :The equation of the tangent at (4, -2) to `y^(2) = X` is `-2y = 1/2(x+4) or x + 4y + 4 = 0`
Its slope is `-1/4`
Therefore the slope of the perpendicular line is 4. Since the tangents at the end of FOCAL chord of a PARABOLA are at RIGHT angle, the slope of the tangent at Q is 4.
Hence, (C) is the correct answer.
10134.

P is a point satisfying arfz = pi//4 ,such that sum of its distance form two given point (0,1) and (0,2) is minimum, then P must bek/2 (1+i) then numerical value of k should be ________.

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ANSWER :3
10135.

D=|{:(a^2+2a,2a+1,1),(2a+1,a+2,1),(3,3,1):}| then,

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`DGT0 if AGT1`
`Dlt0if alt1`
`D=0 if a=1`
All the GIVEN ALTERNATES

ANSWER :D
10136.

Expressisqrt3 =rcos theta +ir sin theta complex numbers in the polar form.

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SOLUTION :where`r=sqrt(a^2+b^2)=SQRT3`
`"and theta=TAN^(-1)(sqrt3/0)=tan^(-1)prop=pi/2`
`:.isqrt3=sqrt3(COS pi/2+isin pi/2)
10137.

thevalue cos 480^@ . Sin150^@ + sin600^@ . Cos390^@ =

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0
1
`1/2`
`-1`

ANSWER :D
10138.

The value of {x in R[log(1.6)^(1-x^(2))-(0.625)^(6(1+8))]in R}

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`(-OO,-1)UU (7,oo)`
`(-1,5)`
`(1,7)`
`(-1,7)`

ANSWER :D
10139.

For positive real numbers x and y, define their special mean to be average of their arithmetic and geometric means. Find the total numbe of pairs of integers (x,y) with x le y, from the set of numbers (1,2,……,2016), such that the special mean of x and y is a perfect square.

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ANSWER :506
10140.

Find the approximate value of each of the following :(65)^((1)/(3))

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ANSWER :`4.021`
10141.

Forany twovectors overset(to)(u) " and" overset(to)(v) prove that (i) |overset(to)(u).overset(to)(v)|^(2) +|overset(to)(u) xx overset(to)(v)|^(2) =|overset(to)(u)|^(2)| overset(to)(v)|^(2) (ii) (1+|overset(to)(u)|^(2))(1+|overset(to)(v)|^(2))=|1-overset(to)(u).overset(to)(v)|^(2)+|overset(to)(u)+overset(to)(v)+(overset(to)(u)xxoverset(to)(v))|^(2)

Answer»


SOLUTION :(i) Since`vec(u) ". " vec(v) = |vec(u) ||vec(v)| COS0`
and `vec(u) xx vec(v) = |vec(u)||vec(v)|` sin 0 `HAT(n)`
where0 is theanglebetween`vec(u)" and" vec(v)" and" vec(n)` isunitvector perpendicular to theplaneof `vec(u) " and" vec(v)`
Again `|ve(u) ". " vec(v)|^(2) =|vec(u)|^(2) |vec(v)|^(2) | cos^(2) 0` and
` |vec(u) xx vec(v)|^(2)= |vec(u)|^(2)|vec(v)|^(2) sin^(2) 0= |vec(u)|^(2) |vec(v)|^(2) sin^(2) 0`
`:. |vec(u)"." vec(v)|^(2) +|vec(u)xx vec(v)|^(2)=|vec(u)|^(2) |vec(v)|^(2) (cos^(2) 0+sin^(2)0)`
`=|vec(u)|^(2) |vec(v)|^(2)`
(ii) `|vec(u)+vec(v)+(vec(u)xxvec(v)|^(2)`
`|vec(u)+vec(v)|^(2) +|vec(u)xxvec(v)|^(2)+2(vec(u)+vec(v)).(vec(u)xxvec(v))`
`=|vec(u)|^(2)+|vec(v)|^(2)+2vec(u)"."vec(v)+|vec(u)xx vec(v)|^(2) +0`
[`:' vec(u) xx vec(v)` isperpendicularto theplaneof `vec(u)" and " vec(v)`]
`:. |vec(u) |^(2) +|vec(v)|^(2)+2vec(u)". " vec(v) +|vec(u)xx vec(v)|^(2) +1 -2 vec(u)". " vec(v) + |vec(u) ". " vec(v)|^(2)`
`=|vec(u)|^(2) + |vec(v)|^(2) +1+ |vec(u)|^(2) |vec(v)|^(2)`
` =|vec(u)|^(2) (1+|vec(v)|^(2)) +(1+|vec(v)|^(2)) =(1+|vec(v)|^(2)) (1+|vec(u)|^(2))`
10142.

If the tangents to the ellipse at M and N meet at R and the normal to the parabola at M meets the x-axis at Q, then the ratio of area of the triangle MQR to area of the quadrilateral MF_1NF_2 is

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3:4
4:5
5:8
0.085416666666667

Answer :C
10143.

[PtCl(NH_(3))_(3)][Cu(NH_(3))Cl_(3)] correct name of complex.

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Triammine CHLORIDE platinum (II) ammine trichlorido cuprate (II)
Triammine chloride platinate (+2) ammine trichlorido copper (-2)
Triammine chloride platinate (II) ammine trichlorido copper (II)
Triammine chloride platinum (+1) ammine trichlorido cuprate (-1)

Solution :`{:(+2,,+2),([PTCL(NH_(3))_(3)],,[CU(NH_(3)Cl_(3))]):}`
Triammine chlorido platinum (II) ammine trichloride cuprate (II)
or
`[PtCl(NH_(3))_(3)]^(+)[Cu(NH_(3)Cl_(3))]^(-)`
Triammine chlorido platinum (+1) ammine trichloride cuprate (-1)
10144.

(dy)/(dx) +2x tan(x-y) = 1 rArr sin(x-y) =

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`A E^(-X^(2))`
`A e^(2x)`
`Ae^(x^(2))`
`Ae^(-2x)`

ANSWER :C
10145.

If (x^(2)+13x+15)/((x-1)(x^(2)+2))=(A)/(x-1)+(Bx+C)/(x^(2)+2), then the descending order of A, B, C is

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A, B, C
B, C, A
C, A, B
A, C, B

Answer :D
10146.

Evaluate the following definite integrals : int_(0)^(pi/2)sqrt(1-cos2x)dx

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ANSWER :`SQRT2`
10147.

Evaluate the following : [[sin^2theta,cos^2theta,1],[cos^2theta,sin^2theta,1],[-10,12,2]]

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SOLUTION :`[[sin^2theta,cos^2theta,1],[cos^2theta,sin^2theta,1],[-10,12,2]]`
=`[[0,cos^2theta,1],[0,sin^2theta,1],[0,12,2]]`
`(C_1=C_1+C_2-C_3)`
=0`(THEREFORE C_1=0)`
10148.

Select the CORRECT order according to given property ?

Answer»

Li lt Na : Reducing NATURE in water
`Na^+` lt `Li^+` : Ionic MOBILITY in water
`Na_((g)) lt Li_((g))` : Size
`Na_((AQ))^+ lt Li_((aq))^+` : RADIUS

10149.

int sin^(2)8xdx =

Answer»

`(1)/(2)(x + (SIN 16x)/(16)) +C `
`(1)/(2)(x - (sin 16x)/(16)) +C `
`(1)/(8)(x + (sin 16x)/(2)) +C `
`(1)/(16)(x - (sin 16x)/(16)) +C `

Answer :B
10150.

Which of the following statement(s) is / are correct

Answer»

The internal energy of an ideal gas may be increased by adding more molecules to it, at constant temperature.
The molar enthalpy of any substance decrease on COOLING , at constant pressure.
A diabatic FREE EXPANSION & isothermal free expansion are similar PROCESSS for an ideal gas .
It is possible to have a process in which the entropy of an isolated system is DECREASED. .

Solution :(A),(B),(C ),(D)