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11001.

12 different toys are to be distributed to three children equally. In how many ways this can be done?

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ANSWER :34650
11002.

Check whether the relation R in R defined by R = {(a,b): a le b ^(3)} is reflexive, symmetric or transitive.

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ANSWER :NEITHER REFLEXIVE nor symmetyric nor TRANSITIVE.
11003.

If int(dx)/(sin2x-2xsinx)=C-(1)/(4)log|f(x)|+(1)/(8sin^(2)(x)/(2)) then f(x) is equal to

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`TAN^(2)X`
`2 tan (x)/(2)`
`tan (x)/(2)`
`SIN (x)/(2)`

ANSWER :C
11004.

Simplify (i) (1 + i)^(18) "" (ii) (-sqrt(3) + 3i)^(31)

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Answer :`(2sqrt(3))^(31)(-(1)/(2)+i(sqrt(3))/(2))`
11005.

Fill int the blanks choosing correct answer from the bracket. In triangle ABC if cosA/a = cosB/b = cosC/c then the triangle is _____.

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equilateral
isosceles
scalene

Answer :A
11006.

Which of the following species exist as liquid at room temperature ?

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`I_2`
`AU`
`AG`
`Br_2`

11007.

If theta is the angle between the curves xy = 2 and x^2 + 4y = 0 then tantheta is equal to

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1
`-1`
2
3

Answer :D
11008.

Prove that .^(n)C_(1)- (1+1/2) .^(n)C_(2) + (1+1/2+1/3) .^(n)C_(3) + "…"+ (-1)^(n-1) (1+1/2+1/3 + "…." + 1/n) .^(n)C_(n) = 1/n

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SOLUTION :LET `S = .^(n)C_(1) - (1+1/2) .^(n)C_(2) + (1+1/2 + 1/3) .^(n)C_(3) + "….."`
`+(-1)^(n-1)(1+1/2+1/3+"…."+1/n) .^(n)C_(n)`.
rth term ofthe series is
`T(r ) = (-1)^(r-1) . C_(r ) (1+1/2+1/3+"……"+1/r)`, where `C_(r) = .^(n)C_(r)`
Let us consider a series whose general term is
`T_(1)(r ) = (-1)^(r-1). C_(r)(1+X+x^(2)+"...."+x^(r-1))`
`= (-1)^(r-1). C_(r) ((1-x^(r))/(1-x))`
` = ((-1)^(r-1)C_(r))/(1-x) +((-1)^(r)x^(r)C_(r))/(1-x)`
`rArr underset(r=1)overset(n)sum T_(1)(r ) = (1)/((x-1))underset(r=1)overset(n)sum (-1)^(r) C_(r ) + (1)/((1+x))underset(r=1)overset(n)sum(-1)^(r). C_(r).x^(r )`
`rArrunderset(r=1)overset(n)sumT_(1)(r ) = (1)/((x-1)) (0-x) + (1)/((1-x)) ((1-x)^(n) - 1) = (1-x)^(n-1)`
`= L` (say)
Clearly `S= underset(0 )overset(1)intLdx = underset(0)overset(1)INT(1-x)^(n-1) dx = 1/n`
11009.

A set A has 3 elements anda set B has 4 elements . The number of one one function defined from set A to B is .........

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144
12
24
64

Solution :N/A
11010.

LetP(n ) =n ( n +1)isaneven number, thenwhichofthefollowingis true ?

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<P>`p(3)`
`p(100)`
`p(50)`
ALLOF these

Answer :D
11011.

Find the value of x,y and z. [{:(x+y+z),(x+y),(y+z):}]=[{:(7),(5),(3):}]

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ANSWER :`x=4,y=1,z=2`
11012.

Let (x, y) be any point on the parabola y^2=4x. Let P be the point that divides the line segment from (0, 0) to (x, y) in the ratio 1 : 3. Then, the locus of P is :

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`x^2=y`
`y^2=2x`
`y^2=x`
`x^2=2y`

ANSWER :C
11013.

Integrate the following functions: (sin^3x + cos^3x)/(sin^2x cos^2x)

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SOLUTION :`(sin^3 x+cos^3 x)/(sin^2 xcos^2x) = sinx/cos^2x + cosx/sin^2x`
= SECX tanx+cosecx COTX
THEREFORE` int (sin^3x+cos^3x)/(sin^2x cos^2x) dx`
=secx-cosecx+c
11014.

If a and b are two non-zero, non-collinear vectors, then 2[abhati]hati+2[abhatj]hatj+2[abhatk]hatk+[abc] is equal to

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`2(axxb)`
`axxb`
`a+b`
None of these

Solution :Let `a=a_(1)hat(i)+a_(2)hat(j)+a_(3)hat(K) and b=b_(1)hat(i)+b_(2)hat(j)+b_(3)hat(k)`
Now , `[abhat(i)]=|{:(a_1,a_2,a_3),(b_1,b_2,b_3),(1,0,0):}|`
`=a_(1)(0-0)-a_2(0-b_3)+a_(3)(0-b_2)=a_2b_3-a_3b_2`
`therefore 2[ab hat(i)]hat(i)=2(a_2b_3-a_3b_2)hat(i)`
Similarly, `2[a b hat(j)]hat(j)=2(a_1b_2-a_1b_3)hat(j)`
and `2[a BHAT(k)]hat(k)=2(a_2b_2-a_2b_1)hat(k)`
`therefore 2[ab hat(i)]hat(i)+2[abhat(j)]hat(j)+2[abhat(k)]hat(k)+[aba]`
`=2[(a_2b_3-a_(3)b_2)hat(i)+(a_3b_1-a_1b_3)hat(j)+0+(a_1b_2-a_2b_1)hat(k)]`
`=2(axxb)` .
11015.

A company has three plants at which it produces a certain item. 30% are produced at plant A, 50% at plant B and 20% at plant C. Suppose that 1%, 4% and 3% of the items produced at plants A, B and C respectively are defective. If an item is selected at random from all those produced, what is the probability that the item is defective ?

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ANSWER :0.029
11016.

For the differential equations, find a particular solution satisfying given condition;(x^(3) + x^(2) + x+ 1)(dy)/(dx) = 2x^(2) + x, y = 1 when x = 0.

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ANSWER :`y = (1)/(4) log [ (x + 1)^(2)(x^(2) + 1)^(3)]- (1)/(2) TAN^(-1) x+ 1`
11017.

If for a continuous function f(x), int_(-pi)^(t) (f(x)+ x) dx= pi^(2) -t^(2), for all t ge - pi, then f(-(pi)/( 3) ) is equal to:

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`PI`
`(pi)/(2)`
`pi/3`
`pi/6`

ANSWER :A
11018.

""^10C_1 . ""^9C_5 + ""^10C_2. ""^9C_4 + ""^10C_3. ""^9C_3 + ""^10C_4. ""^9C_2 + ""^10C_5. ""^9C_1 + ""^10C_6 = ""^19C_6 + xthen x =

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`-84`
84
81
`-81`

ANSWER :A
11019.

Differentiate the functions with respect to x in sin(ax+b)

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ANSWER :`a.cos (AX + B)`
11020.

Find the value of y if the following equations has at least one solution. (i) 5sinx + 12cosx = y^(2)-4y+17 (ii) 4"cosec "^(2)pi(y+x)+y^(2)-4y=0

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Solution :(i) `-13 le 5sinx + 12 cosx le 13`…………(i)
Also, `y^(2)-4y+17=(y-2)^(2)+13 ge 13`……….(ii)
By (i) and (ii) we observe that SOLUTIONS is obtained at `5 sinx + 12 cosx = (y-2)^(2) + 13=13`
`RARR y=2`.
(ii) `4 " cosec "pi(y+x)=-y^(2)+4y-4+4=4-(y-2)^(2)`
As we KNOW that `4" cosec "^(2)pi(y+x) ge 4` and `4-(y-2)^(2) le 4`
Hence, solution is obtained at `4" cosec " ^(2)pi(y+x)=4-(y-2)^(2)=4 rArr y=2`
11021.

i. Show that the lines joining the vertices of a tetrahedron to the centroids of opposite faces are concurrent. ii.Show that the joins of the midpoints of the opposite edges of a tetrahedron intersect and bisect each other.

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Solution :i. `G_(1)`, the centroid of `DeltaBCD`, is `(vecb+vecc+vecd)/(3) and A` is `VECA`.
The position vector of point G which divides `AG_(1)` in the ratio 3 : 1 is
`""(3*(vecb+vecc+vecd)/(3)+1*veca)/(3+1)=(veca+vecb+vecc+vecd)/(4)`
The symmetry of the result shows that this point will also lie on `BG_(2)`, `CG_(3) and DG_(4)` (where `G_(2), G_(3), G_(4)` are centroids of faces ACD, ABD and ABC, respectively). Hence, these FOUR lines are concurrent at point `(veca+vecb+vecc+vecd)/(4)` , which is called the centroid of the tetrahedron.
ii. The midpoint of `DA` is `(veca+vecd)/(2)`and the of `BC` is `(vecb+vecc)/(2)` and the midpoint of these midpoint is `(veca+vecb+vecc+vecd)/(4)` and symmetry of the result proves the fact.
11022.

If Ram secure 100 marks in Maths, then he will get a mobile. The converse is

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If RAM gets a MOBILE, then he will not SECURE 100 marks in Maths.
If Ram does not GET a mobile, then he will secure 100 marks in Maths.
If Ram will get a mobile, then he secure 100 marks in maths.
none of these

Answer :C
11023.

Select the Correct Optiond/dx {log(logx)}=

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1/logx
1/(XLOGX)
1/x
xlogx

Answer :D
11024.

Prove the A uu B = A for all A implies B =phi

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Solution :As `A UU B` = A for all A we have `B sub A` for all A
`:. B sub A` EVEN for `A =phi` Thus `B =phi`
11025.

Some standard forms of integration : intsqrt(3-x^(2))dx=...............+c (where |x|ltsqrt3 )

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`(X)/(2)sqrt(3-x^(2))+(3)/(2)SIN^(-1)((x)/(SQRT3))`
`(x)/(2)sqrt(3-x^(2))+(3)/(2)log(x+sqrt(3-x^(2)))`
`(x)/(2)sqrt(3-x^(2))-(3)/(2)log(sqrt((3)/(x)))`
`(x)/(2)sqrt(3-x^(2))+(3)/(2)log(sqrt(x)/(3))`

ANSWER :A
11026.

If y = lamda x -3, y = mu x + , y = x +4 are three nomals drawn from a fixed point P to the parabola whose axis is along x-axis then 2 lamda - 3mu is equal to

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5
`5/2`
`-5/2`
NONE of these

ANSWER :C
11027.

underset(theta to pi//2)lim ([1-tan(x//2)][1-sin x])/([1+tan(x//2)][pi-2x]^(3))=

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`1//8`
0
`1//32`
`OO`

ANSWER :C
11028.

The value of ((100),(0))((200),(150))+((100),(1))((200),(151))+......+((100),(50))((200),(200)) equals (where ((n),(r ))="^(n)C_(r))

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`((300),(50))`
`((100),(50))((200),(150))`
`((100),(50))^(2)`
`((300),(50))^(2)`

Solution :`(a)` Writing `((200),(r ))=((200),(200-r))`, we have
`((100),(0))((200),(50))+((100),(1))((200),(49))+((100),(2))((200),(48))+......+((100),(50))((200),(0))`
`=` Coefficient of `X^(50)` in the expansion of `(1+x)^(100)(x+1)^(200)`
`=` Coefficient of `x^(50)` in the binomial expansion of `(1+x)^(300)`
`=((300),(50))`
11029.

If a,b,c are all different and |(a,a^(3),a^(4)-1),(b,b^(3),b^(4)-1),(c,c^(3),c^(4)-1)|=0 then abc (ab+bc+ca)=

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0
1
-1
`a+b+c`

ANSWER :D
11030.

If p,q are two statements, then

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`not(p^^q)=notp^^notq`
`not(PVVQ)=notpvvnotq`
`not(PTOQ)=p^^q`
`not(ptoq)=p^^notq`

ANSWER :D
11031.

ABCD is a square, vertices being taken in the anticlockwise sense. If A represents the complex number z and the intersection of the diagonals is the origin then

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B REPRESENTS the COMPLEX number IZ
D represents the complex number `ibar(z)`
B represents the complex number `i_bar(z )`
D represents the complex number – iz

Answer :A,D
11032.

If f'(x)=sqrt(2x^2-1) and y=f(x^2) then what is dy/dx at x = 1 ?

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SOLUTION :`y=f(X^2)rArrdy/dx=f(x^2)2x=2xsqrt(2x^4-1)(thereforef(x)=SQRT(2x^2-1))thereforedy/dx]_(x=1)=2sqrt(2-1)=2
11033.

If matrix A_lambda=[{:(lambda+1,lambda-2),(lambda-1,lambda):}], lambda in N then the value of |A_1|+|A_2|+|A_3|+..... + |A_300| is :-

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`(299)^2`
`(300)^2`
`2(300)^2`
`(301)^2`

Solution :`|A_lambda|=lambda(lambda+1)-(lambda-1)(lambda-2)=4lambda-2`
`|A_1|+|A_2|+|A_3|` + …. + `|A_300|`
`RARR` 4{1+2+3+….+300} -600
`rArr 4.(300.301)/2 -600=2(300)^2`
11034.

If two events A and B are such that P(barA)=0.3, P(B)=0.4and P(AnnbarB)=0.5 then P((B)/(AuubarB))=

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`1//3`
`1//4`
`1//2`
`1//5`

ANSWER :B
11035.

If each of the three matrices of the same order are symmetric , then their sum is a symmetric matrix.

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ANSWER :TRUE
11036.

If (bar(a)xx bar(b))xx(bar(b)xx bar( c ))=bar(b), where bar(a),bar(b),bar( c ) are non zero vectors, then …………..

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`BAR(a),bar(b),bar( C )` are COPLANAR VECTORS.
`bar(a),bar(b),bar( c )` may be coplanar vectors.
`bar(a),bar(b),bar( c )` are not coplanar vectors.
can not say ANYTHING.

Answer :C
11037.

In the parallelogram ABCD, overline(AD)^(2) - overline(AB)^(2) =

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`4 overline(AB)`. (orthogonal PROJECTION of `overline(AD)` on `overline(AB)`)
`2 overline(AB)`. (orthogonal projection of `overline(AD)` on `overline(AB)`)
` overline(AC)`. (orthogonal projection of `overline(BD)` on `overline(AC)`)
`2 overline(AC)`. (orthogonal projection of `overline(BD)` on `overline(AC)`)

Answer :C
11038.

If y= x^(x^(x)) then find (dy)/(dx)

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ANSWER :`X^(x^(x)).LOG x^((x^(x))) [1 + log x + (1)/(x log x)]`
11039.

Evalute the following integrals int (1)/((x+ 1)^(2)(x^(2) + 1)) dx

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ANSWER :`(1)/(2) LOG | X+1|-(1)/(4) log (x^(2) + 1) - (1)/(2(x + 1)) + c `
11040.

For the same laon, what is the loan balance after 3 years assuming no payments on the loan, and ul("annual") compounding?

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ANSWER :`$17,778.53`
11041.

Coefficient of a^8b^6c^4 in (a+b+c)^18 is

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`(18!)/(4!10!5!)`
`(18!)/(3!8!8!)`
`(18!)/(2!7!9!)`
`(18!)/(8!6!4!)`

Answer :D
11042.

The median from the following data is{:("Mid-value","Frequency"),(115,6),(125,25),(135,48),(145,72),(155,116),(165,60),(175,38),(185,22),(195,3):}

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`153.79`
`153.91`
`165.18`
`165.93`

ANSWER :A
11043.

Which of the following is NOT equivalent to ~ p wedge q ?

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<P>`~(Q to p)`
`~p WEDGE (~p to q)`
`~ (p VV ~q)`
`~p to ~ q`

ANSWER :D
11044.

Let R be a relation defined on the set of real numbers by aRb iff 1+ab gt 0 then R is

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REFLEXIVE & SYMMETRIC
transitive
anti symmetric
EQUIVALENCE

ANSWER :A
11045.

Solve system of linear equations ,using matrix method2x+ y +z=1 x- 2y -z= (3)/(2)3y-5z =9

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ANSWER :`x=1,y=(1)/(2) ,Z=(-3)/(2) `
11046.

n different things are arrnaged around a circle. In how many ways can 3 objects be selected when no two of the selected objects are consecutive?

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Solution :Let the object be denoted by `a_(1),a_(2),a_(3), . .,a_(n)` arranged in a circle, we have to select 3 objects so that no TWO of them are consecutive. For this, we first find the number of ways in which 2 or 3 objects are consecutive. Now, number of ways in which 2 or 3 objects are consecutive, is obtained as follows with `a_(1)`. the number of such triples is
`a_(1)a_(2)a_(3),a_(1)a_(2)a_(4),a_(1)a_(2)a_(5), . . .,a_(1)a_(2)a_(n-1)`.
[Since, we have excluded `a_(1)a_(2)a_(n),` so it will be repeated again. if we start with `a_(n)`, then we shall GET triples: `a_(n)a_(1)a_(2),a_(n)a_(1)a_(3)`]
so, number of such triples when we start with `a_(1)`, is (n-3). similarly, with `a_(2),a_(3),a_(4), K, . . .,` we shall get the numbers of triples that is (n-3).
but total number of triples is `.^(n)C_(3)`.
Hence, REQUIRED number of ways `=.^(n)C_(3)-n(n-3)`
`=(n(n-1)(n-2))/(1*2*3)-n(n-3)=(n)/(6)[n^(2)-3n+2-6n+18]`
`=(n)/(6)(n^(2)-9n+20)=(n)/(6)(n-4)(n-5)`.
11047.

Let vec(a)=2hat(i)+hat(j)+hat(k),vec(b)=hat(i)+2hat(j)-hat(k) and a unit vector vec(c) be coplanar. If vec(c)" is perpendicular to "vec(a)," then "vec(c)=

Answer»

`(-hat(J)+hat(k))/(SQRT(2))`
`(-hat(i)-hat(j)-hat(k))/(sqrt(3))`
`(hat(i)-2hat(j))/(sqrt(5))`
`(hat(i)-hat(j)-hat(k))/(sqrt(3))`

ANSWER :A
11048.

inttan^-1sqrt((1-cos2x)/(1+cos2x))dx

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SOLUTION :`I=inttan^-1sqrt((1-cos2x)/(1+cos2x))DX`
=`inttan^-1(sinx/cosx)dx`
=`inttan^-1(TANX)dx`
=`intxdx=x^2/2+c`
11049.

If X+Y=[(5,2),(0,9)] and X-Y=[(3, 6), (0,-1)] and X=[(k,k),(0,k)], then k =

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8
2
4
1

Solution :N/A
11050.

A compound (X) on decomposition gives a colourless gas. The residue is dissolved in water to obtain (Y). Excess CO_(2) is bubbled through aqueoussolution of (Y) and (Z) is formed. (Z) are gentle heating gives back (X) . The (X) is

Answer»

`CaCO_(3)`
`Ca(HCO_(3))_(2)`
`NaHCO_(3)`
`Na_(2)CO_(3)`

SOLUTION :