InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 4551. |
A and B are two tanks, such that capacity of A is 3 times that of B. Both tanks are completely filled and their inlets are closed. Now water is released from the tanks. The rate of flow of water from each tank is proportional to the water in the tank at that instant. If after 1 hours, the water in time A is 2 times the water in tank B. Of both tanks have same quantity of water after time(log_(2m)(m)). then find(1/m). |
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| 4552. |
A card is drawn at random from a pack, the probability that it may be either king or queen is |
| Answer» Answer :D | |
| 4553. |
Integrate the following intcosec7xdx |
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Answer» Solution :`intcosec7xdx` [PUT 7x=t then DX=(1/7)DT] `intcosectcdot(1/7)dt` `(1/7)IOG abs(cosec7x-cot7x)+C` |
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| 4554. |
Equation of normal to y^(2) = 4x at the point whose ordinate is 4 is |
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Answer» X +2y-12 = 0 |
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| 4555. |
A :cos 20^(@) + cos 100^(@) + cos 140^(@) =0 . R :cos theta + cos (120^(@) - theta ) + cos (120^(@) + theta ) =0 |
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Answer» A is true , R is true and R is CORRECT EXPLANATION of A |
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| 4556. |
int 2^(x) .sin3x dx = |
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Answer» `(2^(X))/((log 2)^(2) + 9)` [ (log 2 ).sin3 x - 3 cos 3x ] + c |
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| 4557. |
Find the coordinates of the vertex and focus and the equations of the directrix and axis of the parabolas (i) y^(2) = 16 x |
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| 4558. |
Find the coordinates of the vertex and focus and the equations of the directrix and axis of the parabolas (iii) 3x^(2) -9x+ 5y - 2=0 |
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| 4559. |
Find the coordinates of the vertex and focus and the equations of the directrix and axis of the parabolas (ii) x^(2) = -4y |
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| 4560. |
int_(0)^(x)(2^(t))/(2^([t]))dt, where [.] denotes the greatest integer function, and x epsilonR^(+) is equal to |
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Answer» `1/(1n2)([x]+2^({x})-1)` `I=int_(0)^(x)(2^(t))/(2^([t]))DT=int_(0)^(n)2^({t})dt+int_(n)^(x)2^({t})dt` `=n int_(0)^(1)2^({t})dt+int_(n)^(x)2^({t})dt` `=n int_(0)^(1)2^(t)dt+int_(n)^(x)2^(t-n)dt` `=n(2^(t))/(In2)|_(0)^(1)+1/(2^(n)) (2^(t))/(In2)|_(n)^(x)` `=n/(In2)(2-1)+1/(2^(n)In2)(2^(x)-2^(n))` `=n/(In2)+1/(In2)(2^(x-n)-1)` `=([x]+2^({x})-1)/(In2)` |
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| 4561. |
Find the vertex, focus, equation of directrix and axis, of parabolas y^(2) - x + 4y + 5 = 0 |
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| 4562. |
A cyclist moves uniformaly on a horizontal circular track of radius 100 m . If the cofficient of friction is 0.1. At which of the following speed (s) can he travel without slipping |
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Answer» 5 m/s |
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| 4563. |
The solution of (dy)/(dx) + (y^(2) + y +1)/(x^(2) + x + 1) = 0is |
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Answer» `TAN^(-1) (2X + 1) + Tan^(-1) (2y + 1) = c` |
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| 4564. |
Statement-I: The number of integral values of K for which the equation (x^(2))/(3K-2) +(y^(2))/(K-10)=1 represents a hyperbola is 10. Statement-II : The above equation represents a rectangular hyperbola for K =3. Which of above statements is true |
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Answer» only I |
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| 4565. |
The maximum number of points of intersection of 4 circles and 4 straight lines is |
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Answer» 25 |
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| 4566. |
The system of homogenous equations (a-1)x+(a+2)y+az=0 (a+1)x+ay+(a+2)z=0 ax+(a+1)y+(a-1)z=0 has a non trivial solution if a equals |
| Answer» ANSWER :B | |
| 4567. |
If a relation R .............. |
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Answer» Let `x in N, x^(2)-4.x.x+3x^(2)=0` `:. (x, x) in R :. R` is reflexive we have `(3)^(2)-4(3)(1)+3(1)^(2)=9-12+3=0` or `(3, 1) in R` Also `1^(2)-4(1)(3)+3(3)^(2)=1-12+27 NE 0` `:. (1, 3) in R, :. R` is not symmetric again `(9, 3) in R` because `9^(2)-4(9)(3)+3(3)^(2)=108-108=0` and `(3, 1) in R` because `(3)^(2)-4(3)(1)+3(1)^(2)=12-12=0` and `(9, 1) in R` if `9^(2)-4(9)(1)+3(1)^(2)=0` if `84-36=0` which is not possible `:. (9, 3), (3, 1) in R` and `(9, 1) in R :. R` is not transitive `:.` Relation R is reflexive but NEITHER symmetric nor transitive. |
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| 4568. |
evaluate| [1,x,y],[1,x+y,y],[1,x,x+y] | |
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Answer» SOLUTION :GIVEN DETERMINANT `|[1,X,y,],[0,y,0],[0,0,x]|` (by `R_2 rarr R_2-R_1` and `R_3rarrR_3-R_1`) `=1xxyxx x=xy` |
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| 4569. |
A variable plane passes through a fixed point (1,-2,3) and meets the coordinate axes at point A, B, C then the point of intersection of the planes through A, B, C parallel to the coordinate planes lies on |
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Answer» `XY-(1)/(2)yz+(1)/(3)zx=6` |
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| 4570. |
If z_(1), z_(2) and z_(3) are the vertices of a triangle in the argand plane such that |z_(1)-z_(2)|=|z_(1)-z_(3)|, then |arg((2z_(1)-z_(2)-z_(3))/(z_(3)-z_(2)))| is |
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Answer» `(PI)/(3)` |
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| 4571. |
IfP_(r) is the coefficient ofx^® in the expansion of (1 + x)^(2) (1 + (x)/(2))^(2) (1 + (x)/(2^(2)))^(2) (1 + (x)/(2^(3)))^(2)...prove thatP_(r) = (2^(2))/((2^(r) -1))(P_(r-1) + P_(r-2) )and P_(4) = (1072)/(315) . |
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Answer» Solution :LET `(1 + x)^(2) (1 + (x)/(2))^(2) (1 + (x)/(2^(2)))^(2) (1 + (x)/(2^(3)))^(2)...` ` = 1 + P_(1)x + P_(2)x^(2) + P_(3) x^(3) + P_(4) x^(4) + ...+ P_(r-1) x^(r-1) + P_(r) x^(r) +....`...(i) Replacing x by `(x)/(2)` , we get ` (1 + (x)/(2))^(2) (1 + (x)/(2^(2)))^(2) (1 + (x)/(2^(3)))^(2)(1 + (x)/(2^(4)))^(2)...` `=[1 + P_(1) ((x)/(2)) + P_(2) ((x)/(2))^(2) + P_(3) ((x)/(2))^(3)+ ...]` On MULTIPLYING both sides by ` (1 + x)^(2)` , we get `(1+x)^(2)(1 + (x)/(2))^(2) (1 + (x)/(2^(2)))^(2) (1 + (x)/(2^(3)))^(2)...` `= (1 + x)^(2) [1 + P_(1) ((x)/(2)) + P_(2) ((x)/(2))^(2) + P_(3) ((x)/(2))^(3)+ ...]`...(ii) From Eqs .(i) and (ii) , we get ` 1 + P_(1) x+ P_(2) x^(2) + P_(3) x^(3) + P_(4)x^(4) + ...+ P_(r-1) x^(r-1) + P_(r) x^(r) + ...` `= (1 + x)^(2) [1 + P_(1) ((x)/(2)) + P_(2) ((x)/(2))^(2) + P_(3) ((x)/(2))^(3)+ ...]` On equating coefficient of ` x^(r)` , we get `P_(r) = P_(r)((1)/(2^(r))) + 2P_(r-1) ((1)/(2^(r-1))) + P_(r-2) ((1)/(2^(r-2)))` ` rArr P_(r) (1-(1)/(2^(r))) = (1)/(2^(r-2)) (P_(r-1) + P_(r-2))` ` rArr P_(r) (2^(2))/((2^(r-1))) = (P_(r-1) + P_(r-2))` Now , ` P_(0) = 1 ,P_(1)= 2 + 1 + (1)/(2) + (1)/(2^(2)) + ...= 4` `P_(2) = (2^(2) (P_(1) + P_(0)))/(2^(2)-1)=(20)/(3)` ` P_(3)=(2^(2) (P_(2) + P_(1)))/(2^(3)-1)=(128)/(21)` `P_(4) = (2^(2) (P_(3) + P_(2)))/(2^(4) -1) = (4((128)/(21)+ (20)/(3)))/(15) = (1072)/(315)` . |
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| 4572. |
Compute the ^15C_12 |
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Answer» Solution :`""^15C_12 =((15)!)/((12)!3!)=(15*14*13)/(3*2)` `5*7*13=455` |
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| 4573. |
Prove that : (vecaxxvecb)^2=|\veca|^2.|\vecb|^2-(veca.vecb)^2. |
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| 4574. |
If A is in the third quadrant and tan A = (sqrt(7))/(3) then 18 - 16 sin^(2)^(A)/(2)-32 sin""(A)/(2)sin""(5A)/(2) = |
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Answer» -6 |
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| 4575. |
Evalute the following integrals int (3x + 1)/((x + 2)^(2))dx |
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| 4576. |
If the transformed equation of 6x^(2) + 5xy - 6y^(2)=0 when the axes are translated to the pont (-1,-1) is 6X^(2) + 5XY - 6Y^(2)+aX + bY+c=0 then the descending order of a,b,c is |
| Answer» Answer :A | |
| 4577. |
Evaluate lim_(nrarroo)[((n^(2)+1)(n^(2)+1+3)(n^(2)+1+3+5).......2n" terms")/(n^(4n))]^(1l n) |
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| 4578. |
I: The solution of (dy)/(dx) = (y^(2) - 2xy)/(x^(2) - 2xy) " is " xy (y -x) = c II: The solution ofxdy = [y + x cos^(2) ((y)/(x))] dx " is " tan. (y)/(x) = log (cx) |
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Answer» only I is TRUE |
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| 4579. |
Write a rational function g with vertical asymptotes at x = 3 and x = -3, a horizontal asymptote at y = -4 and with no x-intercept. |
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Answer» Solution :`*` Since g has vertical is asymptotes x = 3 and x = -3, then the denominatorof the rational function contains theproduct of (x-3) and (x+3) . Function g has the form `g(x)=(H(x))/((x-3)(x+3)` `*` For the horizontal asymptote to EXIST, the numerator h(x) of g(x) has same DEGREE as that of the denominator with a leading COEFFICIENT equal to -4. At the same time, h(x) has no REAL zeros. Hence `f(x)=(-4x^(2)-6)/((x-3)(x+3))` `*` Check the characteristics in the graph of g shown below.
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| 4580. |
Integration of some particular functions : int(1)/(3t^(2)+4)dt=A tan^(-1)(Bt)+c then AB=.... |
| Answer» Answer :B | |
| 4581. |
int sin (tan^(-1) x) dx = |
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Answer» `(1)/(sqrt(x +x^(3))) +C ` |
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| 4582. |
To each element of the set S= {1,2,…, 1000} a colour is assigned. Suppose that for any two elements a,b of S, if15 divides a+b then they are both assigned the same colour. What is the maximum possible number of distinct colours used? |
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| 4583. |
Write antiderivative of tan^2x |
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Answer» SOLUTION :`(x-1)/(xsqrt(x^2-1))dx=int(1/sqrt(x^2-1)-1/(xsqrt(x^2-1)))dx =In(x+(sqrt(x^2-1))-sec^(-1)x+c` `THEREFORE` The PRIMITIVE =`In(x+sqrt(x^2-1)-sec^(-1)x` |
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| 4584. |
A: In a Delta ABC, r_1 r_2 r_3 =s^2 R: In an equilateral triangle , r:R:r_1=1:4:5 |
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Answer» A is TRUE, R is true and R is CORRECT explanation of A |
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| 4585. |
Find the number of ways to arrange 5 boys and 5 girl in a row such that no two of the same sex sit together |
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| 4586. |
Compute the integrals :int _(0) ^(pi//2) " sinIn 2 x arc tan " (sin x dx ) |
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| 4587. |
Method of integration by parts : int x sin x sec^(3)xdx=.... |
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Answer» `(1)/(2)[SEC^(2)x-tanx]+c` |
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| 4588. |
An inverted frustum (truncated cone) is mounted on a hemisphere of radius R. Height of the frustum is h with an opening of radius r. The vessel is filled with water. If the rate of evaportion of the liquid is proportional (constant of proportionality k gt 0) to the surface area of water in contact with air, find the time is which the vessel will be amptied. |
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| 4589. |
Solve the equation 6x^4-35x^3+62x^2-35x+6=0 . |
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| 4590. |
Area (in square units) of the region bounded by [x]^(2)=[y]^(2) for x in [1,5] ,(where [*] denotes the greatest integer function) is |
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Answer» 4 |
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| 4591. |
Let x_(1) , x_(2) , x_(3) be the solution of tan^(-1) ((2x + 1)/(x +1 )) + tan ^(-1) ((2x - 1)/( x -1 )) = 2 tan ^(-1) ( x + 1) " where " x_(1) lt x_(2) lt x_(3) " , then " 2x_(1) + x_(2) + x_(3)^(2)is equal to |
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| 4592. |
If f(x)=sinx+|sinx|andg(x)=f(x-pi)+f(x+2pi), then value of underset(-2pi)overset(5pi)(f)g(x)dx is |
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Answer» 15 `:.""g(x)=F(x-pi)+f(x+2pi)` ![]() `UNDERSET(-2pi)OVERSET(5pi)(f)g(x)dx` `:."required area"=2[2xx7]=28`. ALITER : `g(x)=f(x-pi)+f(x+2pi)=(-sinx+|sinx|)+(sinx|sinx|)rArrg(x)=2|sinx|` `"So,"underset(-2pi)overset(5pi)(f)g(x)dx=28`. |
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| 4593. |
Discuss the continuity of the function f defined byf(x) = 1/(x-1) , x ne 1 |
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Answer» Solution :For any real number c, for `c ne 1` we have ` underset(X to c)LIM f(x) = underset(x to c) lim 1/(x -1) = 1/(c-1) ` ALSO, since for ` c ne 1 f(c)= 1/ (c-1)` we have ` underset(x to c) f(x) = f(c)` and hence f is CONTINUOUS at every point in the domain of f is a continuous function. |
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| 4594. |
The unit vectors vec(a),vec(b) and vec( c ) are not coplanar. If vec(a)xx(vec(b)xx vec( c ))=(1)/(sqrt(2))(b+c) then the angle between vec(a) and vec(b) is ……………… |
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Answer» `(3PI)/(4)` |
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| 4595. |
The position vectors of the vertices of triangle are 3hati+4hatj+5hatk,hati+7hatk and 5hati+5hatj. The distance between ortho centre and circum centre is …………. |
| Answer» Answer :B | |
| 4596. |
If a,b,c,d be four consecutive coefficients in the binomial expansion of (1+x)^(n), then value of the expression (((b)/(b+c))^(2)-(ac)/((a+b)(c+d))) (where x gt 0 and n in N) is |
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Answer» positive `a+b=^(n+1)C_(r )` `b+c=^(n+1)C_(r+1)` `c+d=^(n+1)C_(r+2)` `(a+b)/(a)=(n+1)/(r )` `implies(a)/(a+b)=(r )/(n+1)`, `(b)/(b+c)=(r+1)/(n+1)`, `(c )/(c+d)=(r+2)/(n+1)` `:. (a)/(a+b)`, `(b)/(b+c)`, `(c )/(c+d)` are in `A.P.` `A.M. gt G. M.` `(b)/(b+c) gt SQRT((ac)/((a+b)(c+d)))` `implies((b)/(b+c))^(2)-(ac)/((a+b)(c+d)) gt 0` |
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| 4597. |
Evaluate the following integrals int((3e^(x)-4)e^(x))/(e^(2x)-2e^(x)+10)dx |
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| 4598. |
C : x^2+y^2=9, E:(x^2)/(9)+(y^2)/(4)=1,L, y=2x P is a point on the circle C, the perpendicular PQ to the major axis of the ellipse E meets the ellipse at M, then (MQ)/(PQ) is equal to : |
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Answer» `(1)/(3)` |
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| 4599. |
Let a = p (hati + hatj + hatk ).b = hati + hatj - 2 hatk" and "c= 2 hati - hatj + 2 hatkbe three vecotrs . If the values of [a b c] is not more than15 and not lees than -5, then the p lies in the interval |
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Answer» `( (-5)/(3) , 5/9)` |
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| 4600. |
Let each side of smallest square of chess boards is one unit in length. Find the total number of rectangles (including squares) whose side parallel to side of chess board |
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