

InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
251. |
Name the physical quantity obtained by diving ‘distance travelled’ by ‘time taken’ to travel that distance. |
Answer» Speed is the physical quantity that is obtained from distance travelled and time taken. Speed is defined as the distance travelled per unit time. |
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252. |
The speed of a moving object is determined to be 0.06 m/s. This speed is equal to :A. 2.16 km/hB. 1.08 km/hC. 0.216 km/hD. 0.0216 km/h |
Answer» Correct Answer - C | |
253. |
The speed of a moving object is determined to be 0.06 m/s. This speed is equal to: a) 2.16 km/h b) 1.08 km/h c) 0.216 km/h d) 0.0216 km/h |
Answer» The correct answer c) 0.216 km/h |
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254. |
A freely falling object travels 4.9m in 1st second, 14.7m in 2nd second, 24.5m in 3 rd second, and so on. This data shows that the motion of a freely falling object is a case of: a) uniform motion b) uniform acceleration c) no acceleration d) uniform velocity |
Answer» The correct answer b) uniform acceleration |
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255. |
When a car runs on a circular track with a uniform speed, its velocity is said to be changing. This is because: a) the car has a uniform acceleration b) the direction of car varies continuously c) the car travels unequal distances in equal time intervals d) the car travels equal distances in unequal time intervals |
Answer» The correct answer b) the direction of car varies continuously |
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256. |
Name the physical quantity which gives us an idea of how slow or fast a body is movin |
Answer» Speed gives an idea of how slow or fast a body is moving |
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257. |
What is acceleration ? |
Answer» Acceleration is the rate of change of velocity a = \(\frac{Δv}{Δt}\) The SI unit of acceleration is m/sec2 |
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258. |
What is deceleration? |
Answer» If the rate of change of velocity is negative, then it is called deceleration (Retardation) denoted by ‘-a’. |
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259. |
Fill in the blanks. (i) ………..is the term used for negative acceleration. (ii) A bus starting from rest attains a velocity of 54 km/h in 60 s, its acceleration is …………….. . |
Answer» (i) Retardation is the term used for negative acceleration. Explanation: If the velocity of an object is decreasing, it is said to have negative acceleration. (ii) A bus starting from rest attains a velocity of 54 km/h in 60 s, its acceleration is 0.25 m/s2 . Explanation: initial velocity = 0 time = 60 secs final velocity = 54 km/hr =\(\frac{54\,\times\,1000}{60\,\times\,60}\) m/s = 15 m/s Acceleration = \(\frac{change\,in\,velocity}{time\,taken}\) = \(\frac{final\,velocity\,(v)\,-intial\,velocity(u)}{time\,taken(t)}\) = \(\frac{15\frac{m}{s}-0}{60 sec}\)= = 0.25 m/s2 |
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260. |
(i) Give two factors on which acceleration depends. (ii)Mention the formula and SI unit of acceleration. |
Answer» (i) Acceleration depends on the change in the velocity and the time taken by the object to travel. (ii) Acceleration = \(\frac{change\,in\,velocity}{time\,taken}\) = \(\frac{final\,velocity\,(v)-\,initial\,velocity(u)}{time\,taken(t)}\) SI unit of acceleration is meter per second square (m/s2). |
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261. |
What are the Graphical representation of motion? |
Answer» A graph represents the relation between two variable quantities in pictorial form. It is plotted between two variable quantities. The quantity that is varied our choice is called independent variable. The other quantity, which varies as a result of this change, is called dependent variable. For example, in distance-time graph, time is independent variable and distance is dependent variable. Similarly, in velocity-time graph, time is independent variable and velocity is dependent variable. |
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262. |
(a) What remains constant in uniform circular motion ? (b) What changes continuously in uniform circular motion ? ‘ |
Answer» (a)Speed (b)Direction of motion |
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263. |
a) Define velocity. What is the SI unit of velocity? b) What is the difference between speed and velocity? c) Convert a speed of 54 km/h into m/s. |
Answer» a) Velocity is defined as the distance travelled by the body in unit time in a given direction. The SI unit of velocity is m/s. b) The difference between speed and velocity is: i) Speed is a scalar quantity while velocity is a vector quantity. ii) Speed is always positive while velocity can be either positive or negative. iii) Speed is defined as the distance travelled in unit time while velocity is the distance travelled in unit time in a particular direction. c) Speed = 54 km/h = (54)(1000/3600) = 15 m/s |
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264. |
The distance between Delhi and Agra is 200km. A train travels the first 100 km at a speed of 50 km/h. How fast must the train travel the next 100 km so as to average 70 km/h for the whole journey? |
Answer» Total distance = 200 km Average speed = 70 km/h Total time taken = total distance/average speed = 200/70 = 20/7 h First part of the journey, Distance = 100 km Speed = 50 km/h Time taken, t1 = 100/50 = 2h Second part of the journey, Distance = 100 km Speed = x km/h Time taken, t2 = 100/x h t1 + t2 = 20/7 x = 116.6 km/h |
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265. |
Give two uses of graphical representation of motion. |
Answer» Two uses of Graphical representation of motion are:
For Example,
For example,
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266. |
Define average speed. |
Answer» Average speed of a body is defined as the total distance travelled divided by the total time taken to cover the distance. Average speed = \(\frac{total\,distance\,travelled}{total\,time\,taken}\) Let us consider a car is travelling 2 Km in 30 minutes and then next 3 Km at 20 minutes. Then the average speed of the car is Average speed =\(\frac{5}{30+20}\) = 0.1 Km/min |
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267. |
State whether the following statement is true or false : Earth moves round the sun with uniform velocity. |
Answer» No, earth moves round the sun with uniform speed, but its velocity changes continuously |
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268. |
In a two dimensional motion,instantaneous speed `v_(0)` is a positive constant.Then which of the following are necessarily true?A. The average velocity is not zero at any timeB. Average acceleration must always vanishC. Displacements in equal time intervals are equalD. Equal path lengths are traversed in equal intervals |
Answer» Correct Answer - D We know that speed `v_(0) = ("total distance travelled")/("time taken")` Hence, total distance travelled = Path length =(speed) `xx` time taken |
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269. |
A motorcycle moving with a speed of 5 m/s is subjected to an acceleration of 0.2 m/s2 . Calculate the speed of the motorcycle after 10 seconds and the distance travelled in this time. |
Answer» Initial velocity, u = 5 m/s Final velocity, v = ? Acceleration, a = 0.2 m/s2 Time, t = 10 s v = u + at = 7 m/s |
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270. |
How are we different?Random motion and Oscillatory motion. |
Answer» Random motion : The motion that changes its direction and speed continuously is called random motion, e.g. Motion of a butterfly Oscillatory motion : The motion of a body that is swinging back and forth is called oscillatory motion, e.g. Pendulum of a clock, the wing of a bird. Rondom motion is a motion where body changes direction and speed continouslyOscollatory motion is a motion of body which is swinging side by side |
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271. |
How are we different?Linear motion and Random motion. |
Answer» Linear motion : Motion in a straight line is called linear motion. e.g. Motion of a train. Random motion : The motion that changes its direction and speed continuously is called random motion, e.g. Motion of a bird. Linear motion is the movement of a body in linear lineRondom motion is when the body changes direction and velocity instantly |
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272. |
Give two example for each of the following.1. Linear motion 2. Spinning motion 3. Oscillatory motion 4. Periodic motion 5. VibrationaI motion 6. Circular motion 7. Random motion. |
Answer» 1. Linear motion:
2. Spinning motion :
3. Oscillatory motion:
4. Periodic motion:
5. Vibrational motion:
6. Circular motion:
7. Random motion:
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273. |
A ball is projected horizontal from the top of a tower with a velocity `v_(0)`. It will be moving at an angle of `60^(@)` with the horizontal after time.A. `(v_(0))/(sqrt(3)g)`B. `(sqrt(3)v_(0))/(g)`C. `(v_(0))/(g)`D. `(v_(0))/(g)` |
Answer» Correct Answer - B `tan 60^(@) = (v_(V))/(v_(H)) = (g t)/(v_(0))` `:. T = (sqrt(3)v_(0))/(g)` |
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274. |
An aeroplane is flying in a horizontal direction with a velocity `600 km//h` at a height of 1960 m. When it is vertically above the point A on the ground, a body is dropped from it. The body strikes the ground at point B. Calculate the distance AB.A. `3.33 km`B. `4.33km`C. `5.33km`D. `6.33km` |
Answer» Correct Answer - A `t = sqrt((2h)/(g)) = sqrt((2 xx 1960)/(9.8)) = 20s` `:.` Horizontal distance `= 600 xx (20)/(60 xx 60) km = 3.33 km` |
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275. |
A water fountain on the ground sprinkles water all around it. If the speed of water coming out of the fountains is v, the total area around the fountain that gets wet is:A. ` pi(v^(4))/(g^(2))`B. `(pi)/(2) (v^(4))/(g^(2))`C. ` pi (v^(2))/(g^(2))`D. ` pi (v^(2))/(g)` |
Answer» Correct Answer - A Total area around fountain ` A = pi R_(max)^(2) = pi (v^(4))/(g^(2)) ` ` [ because R_(max) = (v^(2) sin 2theta )/(g) = (v^(2) sin 2 theta)/ (g) = (v^(2) sin 90(@))/ (g) = (v^(2))/(g) ]` |
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276. |
Which of the following figures represents uniform motion of a moving object correctly ?A. B. C. D. |
Answer» Correct Answer - (a) When motion is uniform, the distance time graph is a straight line inclined to time axis. Choice (a) is correct. |
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277. |
Four cars `A, B` and `C` are moving on a levelled road. Their distance versus time graphs are shown in Fig. Choose the correct statement A. Car `A` is fatser than Car `D`.B. Car `B` is the slowest.C. Car `D` is faster than Car `C`.D. Car `C` is the slowest. |
Answer» Correct Answer - (b) The slope of distance time graph represents velocity. As slope of graph `B` is minimum, therefore, car `B` is the slowest. |
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278. |
Which of the following graphs represent abody at rest ?A. B. C. D. |
Answer» Correct Answer - ( c) When body is at rest, its velocity `= 0`. The vel-time graph is straight line coinciding with time axis. |
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279. |
Write the Uses of Velocity-time Graphs. |
Answer» The following results can be deduced from velocity-time graph. • The acceleration produced in a body • The distance covered by a moving object • We can derive the equations of motion |
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280. |
Write the Expression for Linear Velocity |
Answer» Suppose an athlete takes t seconds to go once around the circular path of radius r, then the velocity v is given by the relation v = distance travelled / time Distance travelled = circumference of the circle = 2r Linear velocity = 2πr/t |
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281. |
Write the Equations of Motion. |
Answer» The variable quantities in a uniformly accelerated rectilinear motion are time, speed, distance covered and acceleration. Simple relations exist between these quantities. These relations are expressed in terms of equations called equations of motion The equations of motion are: (1) v = u + at (2) S = ut + ½ at2 (3) v2 - u2 = 2aS |
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282. |
Distinguish between speed and velocity. |
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Answer»
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283. |
In the above graph speed is high at A) A B) B C) C D) speed is equal |
Answer» Correct option is B) B |
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284. |
The unit of speed is A) m B) m/s C) m/s2D) m2/s |
Answer» Correct option is B) m/s |
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285. |
The unit of force is …………… A) kg B) Newton C) Kelvin D) kg m/s |
Answer» Correct option is B) Newton |
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286. |
First law of motion isA) v = u + at B) s = ut + 1/2 at2C) v2– u2 = 2asD) Snth = u + 1/2 a(n – A) |
Answer» Correct option is A) v = u + at |
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287. |
Third law of motion is A) v = u + at B) s = ut + 1/2 at2C) v2 – u2 = 2as D) None of these |
Answer» C) v2 – u2 = 2as |
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288. |
Acceleration = ………………… A) a = \(\cfrac{v-u}t\)B) a = \(\cfrac{d}t\)C) a = \(\cfrac{s}t\)D) a = v × t |
Answer» A) a = \(\cfrac{v-u}t\) |
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289. |
v = u + at …………………. 1 s = ut + 1/2 at2 ……………….. 2 v2 = 2as + u2 …………………. 3 v2 + u2 = 2as …………………. 4Which of the above is not a equation of uniform acceleration ? ( ) A) 1 B) 3 C) 4 D) 1, 2, 3 |
Answer» Correct option is C) 4 |
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290. |
From the given diagram we can say that the object. A) has maximum speed at ‘C’ B) travelled in uniform motion. C) has minimum speed at ‘A’. D) A and C |
Answer» Correct option is D) A and C |
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291. |
Define acceleration. |
Answer» The rate of change of velocity in an object is known as its acceleration. |
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292. |
What is the key difference between distance and displacement? |
Answer» Distance is the length of the path traversed by an object in a given time interval and displacement is the shortest distance covered by the object in a specific direction. |
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293. |
A projectile thrown with a speed v at an angle `theta` has a range R on the surface of earth. For same v and `theta`, its range on the surface of moon will beA. 36RB. `(R)/(36)`C. `(R)/(16)`D. 6R |
Answer» Correct Answer - D `R prop (1)/(g) :. R_("moon") = 6R_("earth")` |
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294. |
A body `P` moves with unifrom velocity and another body `Q` moves with uniform retardation. The correct velocity time graph of the two bodies isA. B. C. D. |
Answer» Correct Answer - (a) Body `P` moves with uniform velocity. Therefore, vel-time graph of `P` is a straight line parallel to time axis. Body `Q` moves with uniform retardation. Therefore, velocity-time graph of `Q` is a straight line with negative slope. Choice (a) is correct. |
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295. |
A body of mass m is thrown upwards at an angle `theta` with the horizontal with velocity v. While rising up the velocity of the mass after t second will beA. `sqrt((v cos theta^(2)) + (v sin theta)^(2))`B. `sqrt((v cos theta - v sin theta)^(2) - g t)`C. `sqrt(v^(2) + g^(2)t^(2) - (2b sin theta) g t)`D. `sqrt(v^(2) + g^(2)t^(2) -(2v cos theta) g t)` |
Answer» Correct Answer - C Instantaneous velocity of rising mass after ts will be `v_(t) = sqrt(v_(x)^(2)+v_(y)^(2))` where, `v_(x) = v cos theta =` Horizontal component of velocity `v_(y) = v sin theta - g t = ` Vertical component of velocity `rArr v_(t) = sqrt((v cos theta)^(2)+(v sin theta - g t)^(2))` `rArr v_(t) = sqrt(v^(2)+g^(2)t^(2)-(2v sin theta)g t)` |
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296. |
Observe the figure and classify the type of motion. |
Answer» 1. Circular motion 2. Linear motion 3. Circular motion 4. Linear motion 5. Oscillatory motion 6. Oscillatory motion 7. Circular motion 8. Circular motion 9. Bird – Random; Wings – Oscillatory motion 10. Circular motion 11. Linear, circular |
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297. |
While chasing a butterfly in a garden, do you run along a definite path or in the same direction all the time? |
Answer» No, we move in random motion. |
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298. |
The motion of a butterfly from one flower to another flower is an example of …………… motion.(a) circular (b) periodic (c) linear (d) random |
Answer» Option : (d) random |
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299. |
The distance traversed by an object in a unit time is called ……….. of that object.(a) length (b) motion (c) speed (d) displacement |
Answer» Option : (c) speed |
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300. |
Explain and giving one example of each.(1) Uniform linear motion(2) Non-uniform linear motion(3) Non-linear motion(4) Speed |
Answer» (1) Uniform linear motion : When the distance traversed by an object along a straight line in unit time is the same, the motion is called as uniform linear motion, e.g. Motion of soldiers on parade. (2) Non-uniform linear motion : When the distance traversed by an object along a straight line in unit time keeps on changing, the motion is called non-uniform linear motion. e.g. A girl coming down a slide. (3) Non-linear motion : The motion of an object that does not move in a straight line is called non-linear motion. e.g. Motion of a swing, (4) Speed : The distance traversed by an object in unit time is called the speed of that object. e.g. A boy riding on a bicycle covers a distance of 15 kilometres in 3 hours. Hence, Speed = \(\frac{15}{3}\) = 5 kilometres/hour |
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