InterviewSolution
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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 751. |
For a vibration magnetometer, the time period of suspended bar magnet can be reduced by -A. Moving it towards south poleB. Moving it towards north poleC. Moving it towards equatorD. Anyone of them |
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Answer» Correct Answer - C `T=2pi sqrt(1//MB_H)` `B_H=0` at poles `B_H` = max at equator `B_H uparrow implies Tdownarrow` |
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| 752. |
For a inductor coil L = 0.04 H, then workdone by source to establish a current of 5A in it is -A. 0.5 JB. 1.00 JC. 100 JD. 20 J |
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Answer» Correct Answer - B Work done by source `Exxq=E((Deltaphi)/(R))=E(LI_0)/(R)` `(E/R)LI_0=(I_0)LI_0=LI_0^2` `0.04xx(5)^2=1.0J` |
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| 753. |
Eight equals charged tiny drops are combined to form a big drop. If the potential on each drop is 10V then potential of big drop will be -A. 40VB. 10VC. 30VD. 20V |
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Answer» Correct Answer - A Given : `8V_("tiny")=V_(big)` `8(4)/(3)pir^3=4/3piR^3` 2r =R `V_("tiny")=(Kq)/(r)` `V_(big)=(Kxx8q)/(R)` `V_(big)=(8Kq)/(2r)` `V_(big)=4V_("tiny")` `V_(big)=4xx10 implies 40V` |
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| 754. |
Initially plane of coil is parallel to the uniform magnetic field B. In time `Deltat` it makes to perpendicular to the magnetic field, then charge flows in `Deltat` depends on this time as -A. `propDeltat`B. `prop(1)/(Deltat)`C. `prop(Deltat)^0`D. `prop(Deltat)^2` |
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Answer» Correct Answer - C `therefore " " q=(Deltaphi)/R " " therefore q prop (Deltat)^@` |
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| 755. |
A current carrying coil (I = 5A, R = 10 cm.) having 50 number of turns find field at its centre-A. 1.57 mTB. 3.14 mTC. 1 mTD. 2 mT |
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Answer» Correct Answer - A Magnetic field at the centre of coil `B = (mu_(0)iN)/(2a)` `(4pixx10^(-7)xx5xx50)/(2xx10//100)=1.57xx10^(-3)T` =1.57mT. |
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| 756. |
The floral formula is that ofA. TobaccoB. TulipC. SoybeanD. Sunnhemp |
| Answer» Correct Answer - 1 | |
| 757. |
In barley stem vascular bundles areA. Closed and radialB. Open and scatteredC. Closed and scatteredD. Open and in a ring |
| Answer» Correct Answer - 3 | |
| 758. |
Lichens can be used as:-A. Bio-indicator for water and air pollutionB. Initial vegetation for waste landsC. Source of woodD. To check the air pollution |
| Answer» Correct Answer - A | |
| 759. |
Biotic and abiotic components form:-A. CommunityB. SocietyC. PopulationD. Species |
| Answer» Correct Answer - A | |
| 760. |
The endosperm of gymnosperm isA. PolyploidB. DiploidC. TriploidD. Haploid |
| Answer» Correct Answer - D | |
| 761. |
The plant having the largest flower is:-A. Total stem parasiteB. EpiphyteC. Total root parasiteD. Partial stem parasite |
| Answer» Correct Answer - C | |
| 762. |
The allele for tallness is dominant over that of dwarfness. This is calledA. Law of independent assortmentB. Law of segregationC. Law of unit characterD. Law of dominance |
| Answer» Correct Answer - D | |
| 763. |
Oxytocin is mainly help in:-A. Milk productionB. Child birthC. DiuresisD. Gametogenesis |
| Answer» Correct Answer - B | |
| 764. |
When AABBcc is crossed with AaBbCc then the ratio of hybrid for all the three genes isA. `1/8`B. `1/4`C. `1/16`D. `1/32` |
| Answer» Correct Answer - A | |
| 765. |
Point mutation is induced by :-A. AdenineB. GuanineC. 3-cytosineD. Bromouracil |
| Answer» Correct Answer - D | |
| 766. |
True statement for Ulothrix :A. Filamentous thallus and flagellated reproductive structuresB. Branched thallusC. Flagellated cells absentD. None of the above |
| Answer» Correct Answer - A | |
| 767. |
true statement for cellulose molecule isA. `beta-1-4` linkage, unbranchedB. `beta-1-4` linkage, branchedC. `alpha-1-4` linkage, branchedD. `beta-1-6` linkage, unbranched |
| Answer» Correct Answer - A | |
| 768. |
lactose is composed ofA. Glucose + galactoseB. Glucose + fructoseC. Glucose + glucoseD. Glucose + mannose |
| Answer» Correct Answer - A | |
| 769. |
Deficiency of protein leads toA. RicketsB. ScurvyC. KwashiorkerD. Carotenemia |
| Answer» Correct Answer - C | |
| 770. |
Multivalent chromosome form by :A. InversionB. DeletionC. Reciprocal translocationD. Point mutation |
| Answer» Correct Answer - C | |
| 771. |
A bacterium divides every `35` minutes. If a culture containing `10^(5)` cells/ml is grown for `175` minutes. What will be the cell concentration / ml after `175` minutesA. `2xx10^(5)`B. `5xx10^(5)`C. `32xx10^(5)`D. `16xx10^(5)` |
| Answer» Correct Answer - C | |
| 772. |
Ligament consist ofA. Yellow fibres + Elastic fibresB. Yellow fibres + Collagen (white) fibresC. Yellow fibres + Muscle fibresD. White fibres + Muscle fibres |
| Answer» Correct Answer - B | |
| 773. |
Which of the following statements is correct ?A. Horsetails are gymnospermsB. Selaginella is heterosporous, while Salvinia is homosporousC. Ovules are not enclosed by ovary wall in gymnospermsD. Stems are usually unbranched in both Cycas and Cedrus |
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Answer» Correct Answer - C `*` Gymnosperms have naked ovule. `*` Called phanerogams without womb/ovary |
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| 774. |
Sweet potato is a modifiedA. Tap rootB. Adventitious rootC. StemD. Rhizome |
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Answer» Correct Answer - B Sweet potato is a modified adventitious root for storage of food `*` Rhizomes are underground modified stem `*` Tap root is primary root directly elongated from the redicle |
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| 775. |
Plants having little or no secondary growth areA. ConifersB. Deciduous angiospermsC. GrassesD. Cycads |
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Answer» Correct Answer - C Grasses are monocots and monocots usually do not have secondary growth. Palm like monocots have anomalous secondary growth. |
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| 776. |
Casparian strips are present in the ______ of the rootA. CortexB. PericycleC. EpidermisD. Endodermis |
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Answer» Correct Answer - D `*`Endodermis have casparian strip on radial and inner tangential wall. `*` It is suberin rich. |
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| 777. |
Pneumatophores occur inA. Carnivorous plantsB. Free-floating hydrophytesC. HalophytesD. Submerged hydrophytes |
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Answer» Correct Answer - C `*`Halophytes like mangrooves have pneumatophores. `*` Apogeotropic (–vely geotropic) roots having lenticels called pneumathodes to uptake `O_(2)`. |
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| 778. |
The general molecular formula, which represents the homologous series of alkanols isA. ` C_(n)H_(2n)O_(2) `B. ` C_(n)H_(2n)O `C. ` C_(n)H_(2n+1)O`D. `C_(n)H_(2n+2)O` |
| Answer» Correct Answer - D | |
| 779. |
The name of complex ion, `[Fe(CN_(6))]^(3-)` isA. Tricyanoferrate (III) ionB. hexacyanidoferrate (III) ionC. Hexacyanoiron (III) ionD. Hexacyanitoferrate (III) ion |
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Answer» Correct Answer - B `[Fe(CN)_(6)]^(3-)` `x-6=-3` `x=+6-3` `x=+3` hexa cyanide ferrate (III) ion. |
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| 780. |
Function of Nucleases :A. Break the polynucleotide chain by breaking the each terminal nucleotideB. Breaks phosphodiester bondC. Breaks peptide bondsD. Breaks ester bonds |
| Answer» Correct Answer - B | |
| 781. |
Double unit membrane is absent inA. RibosomesB. NucleusC. PlastidsD. E.R. |
| Answer» Correct Answer - A | |
| 782. |
Which hormone is concerned with the concentration of urine :A. OxytocinB. VassopressinC. ProlactinD. Cortisol |
| Answer» Correct Answer - B | |
| 783. |
Which of the following does not contain metA. GlycoproteinsB. FerritinC. CytochromesD. Chromoproteins |
| Answer» Correct Answer - A | |
| 784. |
Ventricular contraction in command of `:-`A. S.A. NodeB. A.V. NodeC. Purkinje fibersD. Papillary muscles |
| Answer» Correct Answer - A | |
| 785. |
Minute quantity of hormones & steroid are detected by :A. ElectrophoresisB. Radio immunoassayC. Electro encephalogramD. Fractional analysis |
| Answer» Correct Answer - B | |
| 786. |
Which one is obtained by S. Miller in his experiments on origin of life before 1953A. Simple sugarsB. Amino acidsC. NucleotideD. Peptides |
| Answer» Correct Answer - B | |
| 787. |
E. coli are used in production of:A. RifampicinB. LHC. EcdysonD. Interferon |
| Answer» Correct Answer - D | |
| 788. |
Hybridoma isA. Collection of DNA from DNAB. Collection of RNA from DNAC. A fusion of tumour sex cell with non tumour sex cellD. A fusion of tumour somatic cell with non tumour somatic cell |
| Answer» Correct Answer - D | |
| 789. |
Which substance can be used as male contraceptive in future :-A. FSHB. LHC. TestosteroneD. Progesterone |
| Answer» Correct Answer - D | |
| 790. |
Genetic material of prokaryotic cellA. Non histonic double stranded DNAB. Histonic double stranded DNAC. Histone & DNA both are absentD. Histone without DNA |
| Answer» Correct Answer - A | |
| 791. |
Growth of leaf primordia :A. First apical then marginalB. Only apicalC. Only marginalD. Lateral |
| Answer» Correct Answer - A | |
| 792. |
Initiation codon in eukaryotesA. UGAB. CCAC. AGAD. AUG |
| Answer» Correct Answer - D | |
| 793. |
Practical purpose of taxonomy or classification:-A. Facilitate the identification of unknown speciesB. Explain the origin of organismsC. To know the evolutionary historyD. Identification of medicinal plants |
| Answer» Correct Answer - A | |
| 794. |
Anticodon occur in :A. t-RNAB. m-RNAC. r-RNAD. DNA |
| Answer» Correct Answer - A | |
| 795. |
A foreign DNA and plasmid cut by the same restriction endonuclease can be joined to form a recombinant plasmid usingA. Eco RIB. Taq polymeraseC. Polymerase IIID. Ligase |
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Answer» Correct Answer - D The answer is Ligase. |
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| 796. |
2-Bromo pentane reacts with ethanolic KOH gives main product :A. Trans-2-penteneB. Cis-2-penteneC. 1-penteneD. None of the above |
| Answer» Correct Answer - A | |
| 797. |
What is true for cyano bacteria : -A. Oxygenic with nitrogenaseB. Oxygenic without nitrogenaseC. Non oxygenic with nitrogenaseD. Non oxygenic without nitrogenase |
| Answer» Correct Answer - A | |
| 798. |
Plant Decomposers belongs to:-A. Monera and fungiB. Fungi and plantsC. Protista and AnimaliaD. Anibalia and Mogna |
| Answer» Correct Answer - A | |
| 799. |
Which of the following pairs has the same size ?A. `Fe^(2+),Ni^(2+)`B. `Zr^(4+),Ti^(4+)`C. `Zr^(4+),H^(4+)`D. `Zn^(2+),Hf^(4+)` |
| Answer» Correct Answer - C | |
| 800. |
The correct order of decreasing ionic radii among the following isoelectronic species isA. ` Ca^(2+) gt K^(+) gt S2^(–) gt Cl^(– )`B. `Cl^(–) gt S^(2–) gt Ca^(2+) gt K^(+ )`C. ` S^(2–) gt Cl^(–) gt K^(+) gt Ca^(2+ )`D. `S^(2–) gt Cl^(–) gt K^(+) gt Ca^(2+ )` |
| Answer» Correct Answer - C | |