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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1151. |
Select the correct statement from the following regarding cell membrane.A. Lipids are arranged in bilayer with polar heads towards the inner partB. Fluid mosaic model of cell membrane was proposed by singer and NicolsonC. `Na^(+) and K^(+)` ions move across cell membrane by passive transportD. Proteins make up 60 to 70% of the cell membrane |
| Answer» Correct Answer - B | |
| 1152. |
Which one of the following is not a correct statement?A. Herbarium houses dried, pressed and preserved plant specimensB. Botanical gardens have collection of living plants for referenceC. A museum has collection of photographs of plants and animalsD. Key is a taxonomic aid for identification of specimens |
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Answer» Correct Answer - C Museum is the collection of dead and preserved specimen of animals generally. |
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| 1153. |
Isogamous condition whit non-flagellated gametes is found in :A. ChlamydomonasB. SpirogyraC. VolvoxD. Fucus |
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Answer» Correct Answer - B In spirogyra isogamy occur by nonomotile gametes. |
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| 1154. |
You are required to draw blood from a patient and to keep in it a test tube for analysis of blood cropuscles and plasma. You are also provided with the following four types of test tuebes. Which of them will you not use for the purpose.A. Chilled test tubeB. Test tube containing heparinC. Test tube containing sodium oxalateD. Test tube containing calcium bicarbonate |
| Answer» Correct Answer - D | |
| 1155. |
In inducible operon, regulatory gene synthesize:A. PromoterB. OperatorC. RepressorD. Aporepressor |
| Answer» Correct Answer - C | |
| 1156. |
Shell of egg in bird becomes thin (not properly formed) due to the pollution of pesticides. This is due to interference in the activity ofA. Ca ATPaseB. Mg ATPaseC. CalmodulinD. None |
| Answer» Correct Answer - C | |
| 1157. |
Secondary structure of protein, which is attached to lipid layer and lining the pores of cell membrane will beA. `alpha` - HelixB. `beta` - StrandC. `beta` - chainD. Random |
| Answer» Correct Answer - A | |
| 1158. |
Agglutination occurs in blood present in a test tube. This indicateA. Antibodies are present in plasmaB. Antigens are present on R.B.C.C. Antigens are present in plasmaD. Antibodies are present on R.B.C. |
| Answer» Correct Answer - B | |
| 1159. |
Simplest reflex action in human isA. Mono synapticB. Bi synapticC. Tri synapticD. Poly synaptic |
| Answer» Correct Answer - A | |
| 1160. |
Functional megaspore in an angiosperm develops intoA. OvuleB. EndospermC. Embryo sacD. Embryo |
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Answer» Correct Answer - C Megaspore is the first cell of female gametophytic generation in angiosperm. It undergoes three successive generations of free nuclear mitosis to form 8-nucleated and 7-celled embryo sac. |
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| 1161. |
Among the following characters, which one was not considered by Mendel in his experiment on peaA. Stem – Tall or DwarfB. Trichomes – Glandular or non-glandularC. Seed – Green or YellowD. Pod – Inflated or Constricted |
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Answer» Correct Answer - B During his experiments Mendel studied seven characters. Nature of trichomes i.e., glandular or non-glandular was not considered by Mendel. |
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| 1162. |
GnRH, a hypothalamic hormone, needed in reproduction acts onA. Anterior pituitary gland and stimulates secretion of LH and oxytocinB. Anterior pituitary gland and stimulates secretion of LH and FSHC. Posterior pituitary gland and stimulates secretion of oxytocin and FSHD. Posterior pituitary gland and stimulates secretion of LH and relaxin |
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Answer» Correct Answer - B Hypothalamus secretes GnRH which stimulates anterior pituitary gland for the secretion of gonadotropins (FSH and LH). |
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| 1163. |
Select the mismatchA. Pinus – DioeciousB. Cycas – DioeciousC. Salvinia – HeterosporousD. Equisetum – Homosporous |
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Answer» Correct Answer - A Pinus is monoecious plant having both male and female cones on same plant. |
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| 1164. |
The correct order of steps in Polymerase Chain Reaction (PCR) isA. Denaturation, Extension, AnnealingB. Annealing, Extension, DenaturationC. Extension, Denaturation, AnnealingD. Denaturation, Annealing, Extension |
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Answer» Correct Answer - D This technique is used for making multiple copies of gene (or DNA) of interest in vitro. Each cycle has three steps (i) Denaturation (ii) Primer annealing (iii) Extension of primer |
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| 1165. |
Select the correct matchA. T.H. Morgan -TransductionB. `F_(2) xx` Recessive parent -Dihybrid crossC. Ribozyme -Nucleic acidD. G.Mendel -Transformation |
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Answer» Correct Answer - C Ribozyme is a catalytic RNA, which is nucleic acid. |
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| 1166. |
Which of the following facilitates opening of stomatal aperture ?A. Contraction of outer wall of guard cellsB. Decrease in turgidity of guard cellsC. Radial orientation of cellulose microfibrils in the cell wall of guard cellsD. Longitudinal orientation of cellulose microfibrils in the cell wall of guard cells |
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Answer» Correct Answer - C Cellulose microfibrils are oriented radially rather than longitudinally which makes easy for the stoma to open. |
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| 1167. |
Which of the following paris is wrongly matched ?A. XO type sex determination-GrasshopperB. ABO blood grouping :Co-dominanceC. Starch synthesis in pea-Multiple allelesD. T.H. Morgan -Linkage |
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Answer» Correct Answer - C Starch synthesis in pea is controlled by pleiotropic gene Other options (1,2,3 & 4) are correctly matched. |
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| 1168. |
The association of histone `H_(1)` with a nucleosome indicatesA. Transcription is occurringB. DNA replication is occurringC. The DNA is condensed into a Chromatin FibreD. The DNA double helix is exposed |
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Answer» Correct Answer - C The association of H1 protein indicates the complete formation of nucleosome. Therefore the DNA is in condensed form. |
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| 1169. |
Select the correct statementA. Spliceosomes takes part in translationB. Punnett square was developed by a British scientistC. Franklin Stahl coined the term "linkage".D. Transduction was discovered by S. Altman |
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Answer» Correct Answer - B Punnett square was developed by a British geneticist, Reginald C. Punnett. -Franklin Stahl proved semi-conservative mode of replications . -Transduction was discovered by Zinder and Laderberg. - Spliceosome formation is part of post-transcriptional change in Eukaryotes. |
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| 1170. |
Which of the following flowers only once in its life-timeA. MangoB. JackfruitC. Bamboo speciesD. Papaya |
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Answer» Correct Answer - C Bamboo species are monocarpic i.e., flower generally only once ini its life-time after 50-100 years. Jackfruit,papaya and mango are polycarpic i.e., produce flowers and fruits many times in their life-time. |
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| 1171. |
The experimental proof for semiconservative replication of DNA was first shown in aA. PlantB. BacteriumC. FungusD. Virus |
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Answer» Correct Answer - B Semi-conservation DNA replication was first shown in Bacterium Escherichia coli by Mattew Meselson and Franklin Stahl. |
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| 1172. |
Which of the following is a correct pair?A. Cuscuta – parasiteB. Dischidia – insectivorousC. Opuntia – predatorD. Capsella – hydrophyte |
| Answer» Correct Answer - A | |
| 1173. |
Bond order of 1.5 is shown by:A. `O_(2)^(2-)`B. `O_(2)`C. `O_(2)^(+)`D. `O_(2)^(-)` |
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Answer» Correct Answer - D `O_(2)^(-)` Bond order =1.5 |
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| 1174. |
Edible part of banana isA. EpicarpB. Mesocarp and less developed endocarpC. Endocarp and less developed mesocarpD. Epicarp & mesocarp |
| Answer» Correct Answer - C | |
| 1175. |
Which of the following ion is the largest in size?(a) K+ (b) Ca2+ (c) Cl- (d) S2- |
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Answer» The correct option is : (d) S2- Explanation: Since all of these ions contain 18 electrons each, so these are isoelectronic. For isoelectronic ions, smaller the positive nuclear charge, greater is the size of the ion. |
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| 1176. |
Which of the following electronic configuration will have maximum I.P. difference between II and III I.P. :A. `1s^2 2s^2 2p^6 3s^1`B. `1s^2 2s^2 2p^6 3s^2`C. `1s^2 2s^2 2p^6`D. `1s^2 2s^2 2p^5` |
| Answer» Correct Answer - B | |
| 1177. |
The concentration of a solution is changed from 0.2 to 0.4, then what will be rate and rate constant. The reaction is of first order and rate constant is `K = 1xx10^(–6)` :A. `2xx10^-7,1xx10^-6`B. `1xx10^-7,1xx10^6`C. `4xx10^-7,1xx10^-6`D. `2xx10^-3,1xx10^-3` |
| Answer» Correct Answer - C | |
| 1178. |
Half life of a radioactive sample is 4 days. After 16 days how much quantity of matter remain undecayed :A. `1/4`B. `1/8`C. `1/16`D. `1/32` |
| Answer» Correct Answer - C | |
| 1179. |
For protecting a sensitive equipment from the external magnetic field, it should beA. In iron boxB. In wooden boxC. In metallic boxD. None of these |
| Answer» Correct Answer - A | |
| 1180. |
If `C_(p) and C_(v)` denote the specific heats (per unit mass of an ideal gas of molecular weight `M`), then where `R` is the molar gas constant.A. `C_(p)-C_(v)=R`B. `C_(p)-C_(v)=R//M`C. `C_(p)-Cv=MR`D. `C_(p)-C_(v)=R//M^(2)` |
| Answer» Correct Answer - B | |
| 1181. |
What is the net magnetic moment of an atom of a diamagnetic material?A. 1B. between zero and oneC. equal to zeroD. much greater than one |
| Answer» Correct Answer - C | |
| 1182. |
A current loop consists of two identical semicircular parts each of radius R, one lying in the x-y plane and the other in x-y plane. If the current in the loop is i, the resultant magnetic field due to two semicircular parts at their common centre isA. `(mu_(0)i)/(2R)`B. `(mu_(0)i)/(4R)`C. `(mu_(0)i)/(sqrt(2)R)`D. `(mu_(0)i)/(2sqrt(2)R)` |
| Answer» Correct Answer - D | |
| 1183. |
Two particles A and B are moving in uniform circular motion in concentric circles of radii `r_(A)` and `r_(B)` with speed `u_(A)` and `u_(B)` respectively. Their time period of rotation is the same. The ratio of angular speed of a to that of B will be:A. `1:1`B. `r_(A):r_(B)`C. `upsilon_(A):upsilon_(B)`D. `r_(B):r_(A)` |
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Answer» Correct Answer - A Time period (T) `=(2pi)/(omega)` `omega=` angular speed `T_(1)=T_(2)` (given) `(2pi)/(omega_(1))=(2pi)/(omega_(2))` `omega_(1)=omega_(2)` `omega_(1):omega_(2)=1:1` |
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| 1184. |
A soap bubble, having radius of 1 mm, is blown from a detergent solution having radius of 1 mm is blown from a detergent solution having a surface tension of `2.5xx10^(-2)N//m`. The pressure inside the bubble equals at a point `Z_(0)` below the free surface of water in a container. Taking `g=10 m//s^(2)`, density of water `=10^(3) kg//m^(3)`, the value of `Z_(0)` is :A. 0.5cmB. 100 cmC. 10 cmD. 1 cm |
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Answer» Correct Answer - D Pressure inside soap bubble `=P_(0)+(4T)/(R)` Pressure at a point `Z_(0)` below surface of water `=P_(0)+rhogZ_(0)` `P_(0)`= atomospheric pressure `(4T)/(R)=rhogZ_(0)` `Z_(0)=(4T)/(rhogR)` `Z_(0)=(4xx2.5xx10^(-2))/(10^(3)xx10xx1xx10^(-3))` `Z_(0)=1cm` |
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| 1185. |
Select the hormone-releasing Intra-Uterine Devices.A. Lippes Loop, Multiload 375B. Vaults, LNG-20C. Multiload 375, ProgestasertD. Progestasert, LNG-20 |
| Answer» Correct Answer - D | |
| 1186. |
The internal resistance of a `2.1 V` cell which gives a current `0.2 A` through a resistance of `10 Omega`A. `0.2 Omega`B. `0.5 Omega`C. `0.8Omega`D. `1.0Omega` |
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Answer» Correct Answer - B `I=(E)/(R+r)` `0.2=(2.1)/(10+r)` `2+0.2r=2.1` `0.2r=2.1` `r=0.5Omega` |
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| 1187. |
When a proton is released from rest in a room, it starts with an initial acceleration `a_(0)` towards west. When it is projected towards north with a speed `v_(0)` it moves with an initial accelaration `3a_(0)` towards west. The electric and the maximum possible magnetic field in the room (i) `(ma_(0))/(e)`, towards west (ii) `(2 ma_(0))/(ev_(0))`, downward (iii) `(ma_(0))/(e)`, towards east (iv) `(2ma_(0))/(ev_(0))`, upwardA. `(ma_(0))/(e)"west", (2ma_(0))/(ev_(0))"up" `B. `(ma_(0))/(e)"west", (2ma_(0))/(ev_(0))"down" `C. `(ma_(0))/(e)"east", (3ma_(0))/(ev_(0))"up" `D. `(ma_(0))/(e)"east", (3ma_(0))/(ev_(0))"down" ` |
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Answer» Correct Answer - B `vecF_(L)=vecF_(e)+vecF_(m)=qvecE+q(vecvxxvecB)` `ma_(0)=qE+0 " " ` ...(1) `E=(ma_(0))/(q) " so "vecE=(ma_(0))/(e)` in west `vecF_(L)=vecF_(e)+vecF_(m)` `3ma_(0)=qE+q(vecvxxvecB)rArr q(vecvxxvecB)=2ma_(0)`(west) `vecF_(m)=qvecvxxvecB` `-hati=(+hatj)xx.......` `B=(2ma_(0))/(qv)` in vertically downward |
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| 1188. |
A convex lens is dipped in a liquid whose refractive index is equal to the refractive of the lens. Then its focal length willA. Become zeroB. Become infiniteC. Become small, but non-zeroD. Remain unchanged |
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Answer» Correct Answer - B use `1/f=(mu-1)(1//R_1-1//R_2)`, Here `mu-(mu_"convex lens")/(mu_"liquid")=1 therefore f=oo` |
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| 1189. |
A particle of mass m oscillates with simple harmonic motion between points `x_(1)` and `x_(2)`, the equilibrium position being O. Its potential energy is plotted. It will be as given below in the graphA. B. C. D. |
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Answer» Correct Answer - A PE in SHM=`1/2Kx^2` [equation of parabola ] |
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| 1190. |
A car battery of emf 12V and internal resistance `0.05 omega` receives a current of 60 A from an external source, then the terminal potential difference of the battery isA. 12 VB. 9 VC. 15 VD. 20 V |
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Answer» Correct Answer - C `V = E + IR` `= 12 + 60 xx 5 xx 10^(-2)` `= 12 + 3` ` = 15 V` |
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| 1191. |
In human female the blastocyst:A. gets implanted into uterus 3 days after ovulationB. gets nutrition from uterine endometiral secretion only after implanationC. gets implanted in endometrium by the trophoblast cellsD. forms placenta even before implantation |
| Answer» Correct Answer - C | |
| 1192. |
Which one of the following is most appropriately defined?A. Amensalism is a relationship in which one species is benefited where as the other is unaffectedB. Predator is an organism that catches and kills other organism for food.C. Parasite is an organism which always lives inside the body of other organism and may kill it.D. Host is an organism which provides food to another organism. |
| Answer» Correct Answer - B | |
| 1193. |
Secretions from which one of the following are rich in fructode,calcium and some enzymes?A. LiverB. PancreasC. Salivary glandsD. Male accessory glands |
| Answer» Correct Answer - D | |
| 1194. |
When domestic sewage mixes with river waterA. The increased microbial activity releases micro-nutrients such as ironB. The increased microbial activity uses up dissolved oxygenC. The river water is still suitable for drinking as impurities are only about 0.1%D. Small animals like rats will die after drinking river water |
| Answer» Correct Answer - B | |
| 1195. |
A thin circular ring of mass M and radius R is rotating about its axis with constant angular velocity `omega`. The objects each of mass m are attached gently to the ring. The wheel now rotates with an angular velocity.A. `(2M omega)/(M+2m)`B. `((M+2m)omega)/(M)`C. `(M omega)/(M+2m)`D. `((M+2m)omega)/(2m)` |
| Answer» Correct Answer - C | |
| 1196. |
From a circular disc of radius R and mass 9 M , a small disc of radius R/3 is removed from the disc. The moment of inertia of the remaining disc about an axis perpendicular to the plane of the disc and passing through O is A. `MR^(2)`B. `4MR^(2)`C. `(4)/(9)MR^(2)`D. `(40)/(9) MR^(2)` |
| Answer» Correct Answer - D | |
| 1197. |
A particle of mass M starting from rest undergoes uniform acceleration. If the speed acquired in time T is V, the power delivered to the particle is -A. `(1)/(2)(MV^(2))/(T^(2))`B. `(MV^(2))/(T^(2))`C. `(1)/(2)(MV^(2))/(T)`D. `(MV^(2))/(T)` |
| Answer» Correct Answer - C | |
| 1198. |
A solid cylinder and a hollow cylinder, both of the same mass and same external diameter are released from the same height at the same time on an inclined plane. Both roll down without slipping. Which one will reach the bottom first ?A. Both togetherB. Hollow cylinderC. Solid cylinderD. Both together only when angle of inclination of plane is `45^(@)` |
| Answer» Correct Answer - C | |
| 1199. |
Four identical thin rods each of mass `M` and length `l`, from a square frame. Moment of inertia of this frame about an axis through the centre of the square and perpendicular to its plane isA. `(1)/(3)Ml^(2)`B. `(4)/(3)Ml^(2)`C. `(2)/(3)Ml^(2)`D. `(13)/(3)Ml^(2)` |
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Answer» Correct Answer - B `I= 4xx[(ml^(2))/(12)+M((l)/(2))^(2)]` the parallel axis theorem `=(4)/(3) Ml^(2)` |
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| 1200. |
Select the wrong statement :A. Isogametes are similar in structure, function and behaviorB. Anisogametes differ either in structure, function of behaviourC. In Oomycetes female gamete is smaller and motile, while male gamete is larger and non-motileD. Chlamydomonas exhibits both isogamy and anisogamy and Fucus shows oogamy |
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Answer» Correct Answer - C In oomycetes sexual reproduction occur by Isogamy or Oogamy. In isogamy both the fusing gametes are similar in structure, while in oogamy in oomycetes male gamete and female gamete both are nonmotile and female gamete is large while male gamete is small. |
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