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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 951. |
How can you prove that `AlOH_(3)` is amphoteric in nature ? |
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Answer» Correct Answer - `Al(OH)_(3)+underset("acid")(3H^(+))rar rAl^(+3)+3H_(2)` `Al(OH)_(3)+underset("base")(NaOH)rar runderset("sodium meta aluminate")(Na[Al(OH)_(4)] "or" NaAlO_2).2H_(2)O` |
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| 952. |
Which one of the following is an amphoteric oxide?A. `Na_2O`B. `SO_2`C. `B_2O_3`D. ZnO |
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Answer» Correct Answer - D ZnO -amphoteric , `Na_2O`-basic , `SO_2`-acidic , `B_2O_3`-acidic |
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| 953. |
Mark the oxide which is amphoteric in character.A. `CO_(2)`B. `SiO_(2)`C. `SnO_(2)`D. CaO |
| Answer» (c ) `SnO_(2)` is amhoteric. It dissolves in acids as well as in alkalies | |
| 954. |
Which of the following are amphoteric oxides ?A. `SnO_(2)`B. `Al_(2)O_(3)`C. `Ga_(2)O_(3)`D. `SiO_(2)` |
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Answer» Correct Answer - A::B::C Only `SiO_(2)` is acidic while all other are amphoteric. |
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| 955. |
The basic structural unit of silicates isA. `SiO_(3)^(2-)`B. `SiO_(4)^(2-)`C. `SiO^(-)`D. `SiO_(4)^(4-)` |
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Answer» Correct Answer - D Basic structural unit of silicates is `SiO_(4)^(4-)`. |
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| 956. |
Oxidation states of `P` in `H_(4)P_(2)O_(5), H_(4)P_(2)O_(6)` and `H_(4)P_(2_)O_(7)`, respectively areA. `+3,+5` and +4B. `+5,+3` and +4C. `+5,+4` and +3D. `+3,+4` and `+5` |
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Answer» Correct Answer - D Oxidation state of H is `+1` and that of O is `-2`. Let the oxidation state of P in the given compounds is x. In `H_(4)P_(2)O_(5)` `(+1)xx4+2xx x+(-2)xx5=0` `4+2x - 10 = 0` `2x = 6` `:. x = +3` In `H_(4)P_(2)O_(6)` `(+1) xx4+2xx x + (-2)xx6=0` `4+2x-12=0` `2x=8` `:. x = +4` In `H_(4)P_(2)O_(7)` `(+1)xx4+2xx x + (-2)xx7=0` `4+2x-14=0` `2x=10` `:. x = +5` Thus the oxidation states of `P` in `H_(4)P_(2)O_(5)`. `H_(4)P_(2)O_(6)` and `H_(4)P_(2)O_(7)` are `+3,+4` and `+5` respectively. |
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| 957. |
The term noble gases is referred to which groups of element?A. 13 groupB. 14 groupC. 18 groupD. 12 group |
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Answer» Correct Answer - C Group 18 elements (zero group) are inert or noble gases. |
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| 958. |
Which electronic configuration corresponds to minimum energy and maximum stability?A. `(n-1) d^10 ns^1`B. `(n-1) d^5 ns^1`C. `ns^2 np^6`D. `ns^2 np^3` |
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Answer» Correct Answer - C `ns^2 np^6` (configuration of octet) has maximum stability and minimum energy |
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| 959. |
Which of the following noble gases has the lowest atomic number?A. HeB. NeC. KrD. Xe |
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Answer» Correct Answer - A He (At. No. 2) has lowest at. No. among noble gases |
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| 960. |
Which of the following outer electronic configuration represents argon ?A. `ns^2`B. `ns^2 np^6`C. `ns^2 np^5`D. `ns^2 np^4` |
| Answer» Correct Answer - B | |
| 961. |
The correct decreasing order for the acidic strength of oxides of nitrogen isA. `N_(2)O_(5)gtN_(2)O_(3)gtN_(2)O_(4)gtNOgtN_(2)O`B. `NOgtN_(2)OgtN_(2)O_(3)gtN_(2)O_(4)gtN_(2)O_(5)`C. `N_(2)OgtNOgtN_(2)O_(3)gtN_(2)O_(4)gtN_(2)O_(5)`D. `N_(2)O_(5)gtN_(2)O_(4)gtN_(2)O_(3)gtNOgtN_(2)O` |
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Answer» Correct Answer - D `N_(2)O_(5)gt N_(2)O_(4)gtN_(2)O_(3)gtNOgtN_(2)O` |
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| 962. |
If phospheric acid is allowed to react with sufficient quantity of `NaOH`, the product obtained isA. `NaHPO_(3)`B. `Na_(2)HPO_(4)`C. `NaH_(2)PO_(4)`D. `Na_(3)PO_(4)` |
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Answer» Correct Answer - D `3NaOH+H_(3)POrarrNa_(3)PO_(4)+3H_(2)O` |
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| 963. |
Which of the following oxides will be the least acidic?A. `As_(4)O_(6)`B. `As_(4)O_(10)`C. `P_(4)O_(10)`D. `P_(4)O_(6)` |
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Answer» Correct Answer - A As the oxidation state of central atom increases the acidic character character increases, so the correct order of acidic character is `overset(+5)P_(4)O_(10) gt overset(+3)P_(4)O_(6) gt overset(+5)(A)s_(4)O_(10) gt overset(+3)(A)s_(4)O_(6)` and hence, `As_(4)O_(6)` in least acidic. |
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| 964. |
Which of the following halogen exists in the solid state?A. `F_2`B. `Cl_2`C. `Br_2`D. `I_2` |
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Answer» Correct Answer - D `I_2` exist in solid state (stronger vander waal forces of attraction) |
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| 965. |
One of the acid listed below is formed `P_(2)O-(3)` and the rest are formed from `P_(2)O_(5)`. The acid formed from phosphorus `(III)` pxide isA. `HPO_(3)`B. `H_(4)P_(2)O_(7)`C. `H_(3)PO_(4)`D. `H_(3)PO_(2)` |
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Answer» Correct Answer - D `P_(2)O_(3)+3H_(2)Orarr2H_(3)PO_(3)` |
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| 966. |
The elements which exists in the liquid state is/ areA. `Br_2`B. HgC. GaD. All |
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Answer» Correct Answer - D `Br_2` , Hg, Ga all are in liquid state at room temperature |
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| 967. |
Oxidation of thiosulphate by iodine givesA. tetrathionate ionB. sulphide ionC. sulphate ionD. sulphate ion |
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Answer» Correct Answer - A `underset("ion")underset("Thiosulphate")(2S_(2)O_(3)^(2-))+I_(2) rarr underset("ion")underset("Tetrathionate")(S_(4)O_(6)^(2-))+2I^(-)` |
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| 968. |
The oxidation state of iodine in NaOI isA. `+1`B. `+2`C. `-1`D. 0 |
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Answer» Correct Answer - A NaOI- The oxidation no. of I is +1 |
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| 969. |
`P_(2)O_(5)` is heated with water to giveA. Hypophosphorus acidB. Orthophosphorus acidC. Hypophosphoric acidD. Orthophosphorus acid |
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Answer» Correct Answer - D `P_(2)O_(5)+3H_(2)Orarr2H_(3)PO_(4)` orthophosphoric acid. |
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| 970. |
`PH_(4)I+NaOH rarr`? The product isA. `PH_(3)`B. `NH_(3)`C. `P_(4)O_(6)`D. `P_(4)O_(10)` |
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Answer» Correct Answer - A When `PH_(4)I` and `NaOH` react, phosphorus gas is obtained. `PH_(4)I + NaOH rarr PH_(3) + NaI + H_(2)O` |
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| 971. |
In the following reaction `PCl_5 overset(H_2 O) to HCl + A`A. `H_2P_2O_4`B. `H_2P_2O_7`C. `H_2PO_4`D. `H_3PO_3` |
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Answer» Correct Answer - C `PCl_5 + 4H_2O to H_3PO_4 + 5HCl` |
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| 972. |
Which oxidation state is not shown by iodine ?A. `-1`B. `+1`C. `+4`D. `+5` |
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Answer» Correct Answer - C I does not exhibit oxidation state of +4 |
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| 973. |
`PCl_(3)` reacts with water to form :A. `PH_(3)`B. `H_(3)PO_(3).HCl`C. `POCl_(3)`D. `H_(3)PO_(4)` |
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Answer» Correct Answer - B `PCl_(3)` is easily hydrolysed by water to give `POCl_(3)` and finally it gives `H_(3)PO_(3)` and `HCl`. `PCl_(3) + H_(2)O rarr POCl_(3) + 2HCl` `POCl_(3) + 3H_(2)O rarr H_(3)PO_(3) + 3HCl` |
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| 974. |
`P_(2)O_(5)` is heated with water to giveA. hypophosphours acidB. phosphorous acidC. hypophosphorous acidD. orthophosphoric acid |
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Answer» Correct Answer - D When `P_(2)O_(5)` (or `P_(4)H_(10)`) is heated with water. It form orthophosphoric acid `(H_(2)PO_(4))`. `P_(4)O_(10) + 6H_(2)O rarr 4H_(3)PO_(4)` |
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| 975. |
Bond energy is highest for which of the following?A. `F_2`B. `Cl_2`C. `Br_2`D. `I_2` |
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Answer» Correct Answer - B Cl-Cl bond is strongest and hence `Cl_2` has highest bond energy |
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| 976. |
The order of electron affinity among halogen isA. F gt Cl gt Br gt IB. Cl gt F gt I gt BrC. Cl gt F gt Br gt ID. I gt F gt Cl gt Br |
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Answer» Correct Answer - C Trends of electron affinity is Cl gt F gt Br gt I |
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| 977. |
Atoms in `P_4` molecule of white phosphorus are arranged regularly in the following way :A. at the corners of a cubeB. at the corners of an octahedronC. at the corners of tetrahedronD. at the centre and corners of tetrahedron |
| Answer» Correct Answer - C | |
| 978. |
`PH_3`, the hydride of phosphorus isA. MetallicB. IonicC. Non-metallicD. Covalent |
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Answer» Correct Answer - D `PH_3` is covalent . Electronegativity difference between P and H is small |
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| 979. |
White phosphorus isA. a monoatomic gasB. `P_4` a pyramidal with triangular base solidC. `P_8` , a crownD. a linear diatomic mokcuk |
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Answer» Correct Answer - B `P_4` molecule . P is `sp^3` hybridised. Tetraheral molecule. |
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| 980. |
Which of the following phosphorus is the most reactive?A. Red phosphorusB. White phosphorusC. Scarlet phosphorusD. Violet phosphorus |
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Answer» Correct Answer - B White phosphorous is most reactive |
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| 981. |
Which of the following phosphorus is the most reactive?A. Red phosphorusB. White phosphorusC. Scariet phosphorusD. Violet phosphorus |
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Answer» Correct Answer - B White phosphorus has low ignition temeprature So, it is most reactive. |
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| 982. |
Percentage of lead in lead pencil isA. zeroB. 20C. 80D. 70 |
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Answer» Correct Answer - A In lead pencil graphite and clay is present. So the percentage of lead is zero. |
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| 983. |
Which of the following does not show electrical conductance?A. PotassiumB. GraphiteC. DimondD. Sodium |
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Answer» Correct Answer - C Diamond does not show electrical conductivity due to the absence of free electrons. Sodium and potassium are mtallic conductors while graphite is a non-metallic conductor. |
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| 984. |
Which of the following is most acidic ?A. `N_(2)O_(5)`B. `P_(2)O_(5)`C. `As_(2)O_(5)`D. `Sb_(2)O_(5)` |
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Answer» Correct Answer - A Acidic nature of oxides decreases down a group. So, `N_(2)O_(5)` is most acidic. Another reason of acidic strength of `N_(2)O_(5)` is that the electronegativity of `N` is maximum in the given Vth group elements. As we know that on increasing the electronegativity character, acidic nature increases. |
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| 985. |
The correct order of electron affinity of B , C , N and O isA. O gt B gt C gt NB. O gt C gt B gt NC. B gt Ngt C gt OD. OgtCgtNgtB |
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Answer» Correct Answer - D Electron affinity increases from left to right in a period |
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| 986. |
Which one of the elements has the maximum electron affinity?A. ClB. BrC. ID. F |
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Answer» Correct Answer - A The electron affinity decreases from `Cl rarr Br rarr I`, i.e., on moving down the group. However, electron affinity of florine is unexpected low. It cannot be explained by any simple mechanism. It is probably due to small size of the atom. The addition of an extra electron produces high electron charge density in a relatively compect 2p subshell resulting in strong electron-electron repulsion. The repulsive forces between electrons imply low electron affinity So, the correct order of electron affinity for halogens is `I lt Br lt F lt Cl. |
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| 987. |
Which show maximum catenation property ?A. TeB. SC. SeD. O |
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Answer» Correct Answer - B Sulphur : `H_2S_3 (H-S-S-S-H), H_2S_4 (H-S-S-S-S-H)` |
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| 988. |
Electron affinity of sulphur isA. more than O and SeB. more than O but less than SeC. less than O but more than SeD. equal to O and Se |
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Answer» Correct Answer - C Electron affinity decreases from O to Se down the group. |
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| 989. |
The correct increasing order of acidic strength of oxyacids of group 15 elements isA. `H_(3)SbO_(4)ltH_(3)PO_(4)ltH_(3)AsO_(4)ltHNO_(3)`B. `H_(3)SbO_(4)ltH_(3)AsO_(4)ltH_(3)PO_(4)ltHNO_(3)`C. `HNO_(3)ltH_(3)SbO_(4)ltH_(3)AsO_(4)ltH_(3)PO_(4)`D. `H_(3)PO_(4)ltH_(3)AsO_(4)ltH_(3)SbO_(4)ltHNO_(3)` |
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Answer» Correct Answer - B `H_(3)SbO_(4) lt H_(3)AsO_(4)lt H_(3)PO_(4)ltHNO_(3)` |
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| 990. |
Bleaching powder reacts with a few drops of conc.`HCl` to yieldA. chlorineB. hypochlorous acidC. calcium oxideD. oxygen |
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Answer» Correct Answer - A When bleaching powder reacts with `HCl`, it form chlorine gas. `CaOCl_(2) + 2HCl rarr CaCl_(2) + H_(2)O + Cl_(2)` |
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| 991. |
Among the following compounds, the most acidic isA. `As_(2)O_(3)`B. `P_(2)O_(5)`C. `Sb_(2)O_(3)`D. `Bi_(2)O_(3)` |
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Answer» Correct Answer - B Pentoxides are more acidic than trioxide and their acidic character decreases down the group from N to Bi. |
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| 992. |
Boron, the first member of group 13 (p-block) is a typical non-metal. H exists in two allotropic forms. The compounds of boron are mainly electron deficient as well as Lewis acids. For example, all the trihalides of boron `(BX_(3))` are Lewis acids. The expected order of acidic strength based on the electro negativity of halogen atoms is : `BF_(3)gtBC l_(3)gtBBr_(3)gtBl_(3)`. But the actual order is the reverse. This is explained with the help of the concept of back bonding `(p pi- p pi)` . Among the hydrides of boron. diborane has a bridged structure. In the reaction: `BF_(3)+3LiBH_(4)rarr3liF+X` isA. `B_(4)H_(10)`B. `AlCl_(3)`C. `B_(2)H_(6)`D. `B_(3)H_(8)` |
| Answer» X is `B _(2 )H_(6)` (diborane). | |
| 993. |
Action of caustc soda on aluminium hydrox ide giv es a compound with formula.A. `Al_(2)(OH)_(4)`B. `Na_(2)Al(OH)_(4)`C. `NaAIO_(2)`D. `Na_(3)AIO_(3)` |
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Answer» Correct Answer - C `NaAiO_(2)` is formed in the reaction. |
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| 994. |
Which of the following options are not accordance with the property mentioned against them? (a) `F_(2)gtCl_(2)gtBr_(2)gtI_(2)` Oxodising power (b) `MIgtMBrgtMClgtMF` Ionic character of metal halide (c ) `F_(2)gtCl_(2)gtBr_(2)gtI_(2)` Bond dissociation enthalphy (d) `HIltHBrltHClltHF` Hydrogen - halogen bond strength |
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Answer» Correct Answer - B::C `F_(2)gtCl_(2)gtBr_(2)gtI_(2)` As ability to gain electron increases oxidising property increases. Here, F is the most electronegative element having highest value of SRP hence it has highest oxidising power. `MIgtMBrgtMClgtMF` This is the incorrect order of ionic character of metal halide. Correct order can be written as `MIltMBrltMClltMF` As electronegativity difference between metal and halogen increases ionic character increases. `F_(2)gtCl_(2)gtBr_(2)gtI_(2)` This is incorrect order of bond dissociation energy . Correct order is `Cl_(2)gtBr_(2)gtI_(2)` due to electronic repulsion among lone pairs in `F_(2)` molecule. |
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| 995. |
White phosphorus `(P_(4))` hasA. six `P-P` single bondsB. four `P-P` single bondsC. four lone pairs of electronsD. `P-P-P` angle of `60^(@)` |
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Answer» Correct Answer - A::C::D |
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| 996. |
When cold `NaOH` reacts with `Cl_(2)` which of the following is formedA. `NaClO`B. `NaClO_(2)`C. `NaClO_(3)`D. None of these |
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Answer» Correct Answer - A `NaOH+Cl_(2)rarrNaClO+NaCl+H_(2)O` |
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| 997. |
Write two uses of hydrogen chloride. |
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Answer» Uses of hydrogen chloride : `to` It is ysed in medicines and as a laboratory reagent. `to` It is used in the manufacturing of `Cl_(2),NH_(4)Cl` and glucose (from corn starch). `to` It is used in extracting glue from bones and purifying bone black. |
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| 998. |
Explain the reactions of `Cl_(2)` with NaOH. |
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Answer» i) Reaction with cold dilute NaOH : Chlorine reacts with cold dilute NaOH to give sodium hypochlorite and sodium chloride. `underset(("cold, dil."))(2" NaOH"+Cl_(2))toNaCl+NaOCl+H_(2)O` ii) Reaction with hot concentrated NaOH : Chlorine reacts with hot concentrated NaOH to give sodium chlorate and sodium chloride. `3" Cl"_(2)+underset(("hot, Conc."))(6" NaOH") to"NaCl"+"NaOCl"+H_(2)O` |
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| 999. |
What happens when `Cl_(2)` reacts with dry slaked lime ? |
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Answer» Chlorine reacts with dry slaked lime and forms bleaching powder. `Ca(OH)_(2)+Cl_(2)to"CaOCl"_(2)+H_(2)O` |
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| 1000. |
Which of the following is/are properties of helium ?A. It is chemically inert.B. It has very high thermal conductivityC. It has extremely low boiling pointD. It has very low viscosity |
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Answer» Correct Answer - ABCD |
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