InterviewSolution
Saved Bookmarks
InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 12 knowledge and support exam preparation. Choose a topic below to get started.
| 151. |
At the first minimum adjacent to the central maximum of a single slit diffraction pattern, the phase difference between the Huygen's theh wavelet from the edge of the slit and the wavelet from the edge of the slit and the wavelet from the edge of the slit and the wavelet from the midpoint of the slit is |
| Answer» <html><body><p>`(pi)/<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>` <a href="https://interviewquestions.tuteehub.com/tag/radian-1175760" style="font-weight:bold;" target="_blank" title="Click to know more about RADIAN">RADIAN</a><br/>`(pi)/<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>` radian<br/>`pi` radian <br/>`(pi)/8` radian </p>Answer :C</body></html> | |
| 152. |
How does refractive index (mu) of a material vary with respect to wavelenght (lambda). (A and B are constants). |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/mu-566056" style="font-weight:bold;" target="_blank" title="Click to know more about MU">MU</a> = A + (<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>)/(lambda^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))`<br/>`mu = A + Blambda^(2))`<br/>`mu = A + (B)/(lambda)`<br/>`mu = A = B lambda` </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/according-366619" style="font-weight:bold;" target="_blank" title="Click to know more about ACCORDING">ACCORDING</a> to cauchy.s relation, `mu = A + (B)/(lambda^(2))`</body></html> | |
| 153. |
In a chamber, a uniform magnetic field of 6.5G ( 1G = 10^(-4) T) is . Maintained . An electron is shot into field witha speed of 4.8 xx 10^(6) ms^(-1) normal to the field . Explain why the path of the electron is a circle. Determine the radius of the circular orbit. (e = 1.6 xx 10^(-19) C, m = 9.1 xx 10^(-31) kg) |
| Answer» <html><body><p></p>Solution :`B=6.5 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 10^(-4) T,v= 4.8 xx 10^(6) ms ^(-1)` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/bqv-3563546" style="font-weight:bold;" target="_blank" title="Click to know more about BQV">BQV</a> = (<a href="https://interviewquestions.tuteehub.com/tag/mv-1082193" style="font-weight:bold;" target="_blank" title="Click to know more about MV">MV</a>^<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)/(r) , r = (mV)/(<a href="https://interviewquestions.tuteehub.com/tag/qb-610265" style="font-weight:bold;" target="_blank" title="Click to know more about QB">QB</a>)= (9.1 xx 10^(-31) xx 4.8 xx 10^6)/(1.6 xx 10^(-19) xx 6.5 xx 10^(-4)) = 4.2 xx 10^(-2) m = 4.2 cm `</body></html> | |
| 154. |
Draw a graph of number of undecayed nuclei to the time, for a radioactive nuclei. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/DBT_SM_PHY_XII_U_VII_VIII_E01_052_S01.png" width="80%"/></body></html> | |
| 155. |
Choose the correct statement for an isolated system. |
| Answer» <html><body><p>`DeltaU(<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> to D)` = <a href="https://interviewquestions.tuteehub.com/tag/negative-570381" style="font-weight:bold;" target="_blank" title="Click to know more about NEGATIVE">NEGATIVE</a> <br/>`DeltaQ(A to B)` = <a href="https://interviewquestions.tuteehub.com/tag/positive-1159908" style="font-weight:bold;" target="_blank" title="Click to know more about POSITIVE">POSITIVE</a> <br/>`DeltaU(A - B - C - D- A) != <a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>`<br/>`DeltaQ(D to A) = 0`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 156. |
Give an example for isobars. |
| Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/example-978283" style="font-weight:bold;" target="_blank" title="Click to know more about EXAMPLE">EXAMPLE</a> : 1) ` ""_(1)H^3 and ""_(2)He^3` <br/> 2) `""_(13)<a href="https://interviewquestions.tuteehub.com/tag/ar-380980" style="font-weight:bold;" target="_blank" title="Click to know more about AR">AR</a>^(40)and ""_(<a href="https://interviewquestions.tuteehub.com/tag/20-287209" style="font-weight:bold;" target="_blank" title="Click to know more about 20">20</a>)Ca^(40)`</body></html> | |
| 157. |
Draw a circuit diagram to show biasing of a solar cell. Draw its characteristic curve and explain it |
| Answer» <html><body><p></p>Solution :A circuit diagram showing biasing of a <a href="https://interviewquestions.tuteehub.com/tag/typical-1434778" style="font-weight:bold;" target="_blank" title="Click to know more about TYPICAL">TYPICAL</a> p-n junction solar cell has been <a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a> in<br/> When light (with photon <a href="https://interviewquestions.tuteehub.com/tag/energy-15288" style="font-weight:bold;" target="_blank" title="Click to know more about ENERGY">ENERGY</a> hv ` gt E_(g)`) falls at the junction, electron-hole pairs are generated which <a href="https://interviewquestions.tuteehub.com/tag/move-548879" style="font-weight:bold;" target="_blank" title="Click to know more about MOVE">MOVE</a> in mutually opposite directions due to the junction field. Ifno external load is connected or if the circuit of solar cell is open, electrons and holes are collected at the two sides of the junction giving a photo-voltage `V_(oc)` . When external load R is connected, a photo-current `I_(L)`flows. For R = 0, the current has a maximum value `I_(sc)` which is known as short circuit current. <a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>- I characteristics is shown in . The graph is in the fourth quadrant because a solar cell does not draw current but supplies current to the load.<br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/U_LIK_SP_PHY_XII_C14_E09_027_S01.png" width="80%"/></body></html> | |
| 158. |
A mixture of two gases is contained in a vessel. The Gas 1 is monoatomic and gas 2 is diatomic and the ratio of root mean square speeds of the molecules of two gases is |
| Answer» <html><body><p>2<br/>4<br/>8<br/>16</p>Answer :A</body></html> | |
| 159. |
In a p-n junction the width of depletion region on either side of junction is ______ or even less. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(-<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>)` m</body></html> | |
| 160. |
Development goals of different sections of our society can be achieved by: |
| Answer» <html><body><p>Force<br/>Democratic <a href="https://interviewquestions.tuteehub.com/tag/political-592237" style="font-weight:bold;" target="_blank" title="Click to know more about POLITICAL">POLITICAL</a> process<br/>Violent agitation<br/>Terrorism</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 161. |
If "^imu_g represent the refractive index when a light ray goes from medium 'I' to medium 'g' then the product 2mu_1xx^3mu_^4mu_3 is equal to: |
| Answer» <html><body><p>`"^3mu_2`<br/>`"^2mu_4`<br/>`"^3mu_1`<br/>`(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)/("^1mu_4)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 162. |
Two point charges +q and -2qare placed at the vertices B and C of an equilateral triangle ABC of side 'a' as shown Obtain the expession for (i) the magnitude ,and (ii) the direction of the resultant electric field at the vertex A due to these two charges . |
| Answer» <html><body><p><br/></p>Answer :(i) ` (<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>) /( <a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a> pi in _0)(sqrt3q)/( a^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))(<a href="https://interviewquestions.tuteehub.com/tag/ii-1036832" style="font-weight:bold;" target="_blank" title="Click to know more about II">II</a>)<a href="https://interviewquestions.tuteehub.com/tag/30-304807" style="font-weight:bold;" target="_blank" title="Click to know more about 30">30</a>^(@) ` from Ac</body></html> | |
| 163. |
What is the unit of magnetic permeability? |
| Answer» <html><body><p>`wb^-1Am^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)`<br/>`wb^-1Am`<br/>`wbA^-1`<br/>`wbA^-1m`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 164. |
Answer the following questions : (a) You have learnt that plane and convex mirrors produce virtual images of objects. Can they produce real images under some circumstances ? Explain. (b) A virtual image, we always say, cannot be caught on a screen. Yet when we 'see' a virtual image, we are obviously bringing it on to the 'screen' (i.e., the retina) of our eye. Is there a contradiction ? (c) A diver under water, looks obliquely at a fisherman standing on the bank of a lake. Would the fisherman look taller or shorter to the diver than what he actually is ? (d) Does the apparent depth of a tank of water change if viewed obliquely ? If so, does the apparent depth increase or decrease ? (e) The refractive index of diamond is much greater than that of ordinary glass. Is this fact of some use to a diamond cutter ? |
| Answer» <html><body><p></p>Solution :(a) We know that both plane and convex mirrors produce virtual images of real objects. They may produce real image of virtual objects i.e., when the incident light beam is highly convergent, converging towards a point O behind the mirror as shown in Fig. 9.05(a) for a plane mirror and Fig. 9.05(b) for a convex mirror respectively.<br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/U_LIK_SP_PHY_XII_C09_E01_018_S01.png" width="80%"/> <br/> (b) A virtual image <a href="https://interviewquestions.tuteehub.com/tag/means-1091780" style="font-weight:bold;" target="_blank" title="Click to know more about MEANS">MEANS</a> that the reflected/ refracted light rays form a divergent beam and <a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a> it cannot be converged on a screen. However, when we .see. a virtual image, this virtual image acts as an object and the convex lens of eye converges it on the screen (the retina) of our eye. Therefore, there is no <a href="https://interviewquestions.tuteehub.com/tag/contradiction-425534" style="font-weight:bold;" target="_blank" title="Click to know more about CONTRADICTION">CONTRADICTION</a> of any sort. <br/> (c) As shown in Fig. 9.06, when an object OO. situated in air is viewed from inside water its virtual, erect and magnified image II. is formed. It is on this account that to a diver under water a fisherman standing on the bank of lake appears to be taller than what he actually is.<br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/U_LIK_SP_PHY_XII_C09_E01_018_S02.png" width="80%"/> <br/> (d) The apparent depth decreases when a tank filled with water is viewed obliquely compared to the depth when <a href="https://interviewquestions.tuteehub.com/tag/seen-3017120" style="font-weight:bold;" target="_blank" title="Click to know more about SEEN">SEEN</a> near normally. <br/> (e) Refractive index of diamond is much greater than that of glass. In fact, it is 2.42 as compared to 1.5 of glass. Consequently, <a href="https://interviewquestions.tuteehub.com/tag/critical-427694" style="font-weight:bold;" target="_blank" title="Click to know more about CRITICAL">CRITICAL</a> angle for diamond air interface is quite small (about 24°). Thus, a skilled diamond cutter has a large option to cut the diamond faces for any value of angle of incidence varying from 24° to 90°. It makes his work easy.</body></html> | |
| 165. |
Find the velocity of the excited hydrogen atoms if the first line of the Lyman series is displaced by Delta lambda= 0.20 nm when their radiation is observed at an angle theta=45^(@) to their motion direction. |
| Answer» <html><body><p></p>Solution :Since `<a href="https://interviewquestions.tuteehub.com/tag/delta-947703" style="font-weight:bold;" target="_blank" title="Click to know more about DELTA">DELTA</a> lambda(= 0.20nm)lt lt lambda(= 121nm)` of the first <a href="https://interviewquestions.tuteehub.com/tag/lyman-545655" style="font-weight:bold;" target="_blank" title="Click to know more about LYMAN">LYMAN</a> line of `H` atom, we need not worry about `V^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)//c^(2)` effects. Then <br/> `omega'=(omega)/(1-betacos theta),beta=(v)/(c )` <br/> Hence `1- beta <a href="https://interviewquestions.tuteehub.com/tag/cos-935872" style="font-weight:bold;" target="_blank" title="Click to know more about COS">COS</a> theta=(omega)/(omega')=(lambda')/(lambda)` <br/> or `beta cos theta=1-(lambda')/(lambda)=(Delta lambda)/(lambda)` <br/> But `omega=(3)/(4)R so lambda=(2pic)/(omega)=(8pic)/(<a href="https://interviewquestions.tuteehub.com/tag/3r-311113" style="font-weight:bold;" target="_blank" title="Click to know more about 3R">3R</a>)` <br/> Hence `v=cbeta=(3RDeltalambda)/(8pi cos theta)` <br/> Substitution gives `( cos theta=(1)/(sqrt(2)))` <br/> `v= 7.0xx10^(5)m//s`</body></html> | |
| 166. |
What is the magnetic induction due to a magnet of pole strength 20A-m and length 20 cm at a distance of 0.5m from its centre on the axial line? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`69.44 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(-<a href="https://interviewquestions.tuteehub.com/tag/7-332378" style="font-weight:bold;" target="_blank" title="Click to know more about 7">7</a>)T `</body></html> | |
| 167. |
A uniform magnetic field vecB is set up along the positive x-axis. A particle of charge q and mass m moving with a velocity vecv enters the field at the origin in X - Y plane such that it has velocity components both along and perpendicular to the magnetic field vecB. Trace, giving reasons, the trajectory followed by the particle. Find out the expression for the distance moved by the particle along the magnetic field in one rotation. |
| Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/consider-2017521" style="font-weight:bold;" target="_blank" title="Click to know more about CONSIDER">CONSIDER</a> a charged particle of mass m and charge q entering a uniform magnetic field `vecB` with a <a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a> `vecv` along an angle `theta` with the direction of magnetic field in the plane of peper . <br/> Velocity `vecv` may be resolved into two components(i) `v cos theta` along the magnetic field, and (ii) `v sin theta` perpendicular to the magnetic field as shown in fig. Obviously due to normal <a href="https://interviewquestions.tuteehub.com/tag/component-926634" style="font-weight:bold;" target="_blank" title="Click to know more about COMPONENT">COMPONENT</a> `v sin theta` the charged particle will ecperience a force `F = q(v sin theta) B` along a direction perpendicular to `vecB` as well as `(v sin theta)` i.e, force F is along the z-axis. Under its effect, the charged particle describe a <a href="https://interviewquestions.tuteehub.com/tag/circular-916697" style="font-weight:bold;" target="_blank" title="Click to know more about CIRCULAR">CIRCULAR</a> path of radius r, such that <br/> `B q v sin theta = (m (v sin theta)^2)/(r)` <br/> `implies r = (m v sin theta)/(B q) "" ......(i)` <br/> The time period of revolution will be given by <br/> `T = (2 pi r)/((v sin theta)) = (2 pi m)/(B q) "" .......(ii)` <br/> or Frequency of revolution `v = 1/T = (Bq)/(2 pi m) ""........(iii)` <br/> Due to component `v cos theta` the charged particle does not experience force due to magnetic field and tends to move linearly with a constant speed. Thus, under the combined effect of both the velocity componetns we can say that the charged particlewill describe a helical path having its axis parallel to magnetic field. <br/> In one <a href="https://interviewquestions.tuteehub.com/tag/complete-423576" style="font-weight:bold;" target="_blank" title="Click to know more about COMPLETE">COMPLETE</a> revolution of its circular path the charged particle covers a linear distance along `vecB`, which is called as "pitch" of helix and is denoted by p. Obviously <br/> `p = (v cos theta) T = (2 pi m v cos theta)/(Bq)`<br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/U_LIK_SP_PHY_XII_C04_E10_010_S01.png" width="80%"/></body></html> | |
| 168. |
What ideas led Maxwell to think about e.m. wave? |
| Answer» <html><body><p></p>Solution :Faraday from his exprimental study on electromagnetic induction, conclude that a magnetic field changing <br/> with time in a region produces an electric field there. Maxwell thought that there is a <a href="https://interviewquestions.tuteehub.com/tag/great-2556" style="font-weight:bold;" target="_blank" title="Click to know more about GREAT">GREAT</a> <a href="https://interviewquestions.tuteehub.com/tag/symmetry-657996" style="font-weight:bold;" target="_blank" title="Click to know more about SYMMETRY">SYMMETRY</a> in <br/> nature. He from his theortical study concluded that an electric field changing with time in a region produces <br/> a magnetic field there. It means a change in either field (electric or magnetic) with time produces the other <br/> field. This <a href="https://interviewquestions.tuteehub.com/tag/ideal-1035490" style="font-weight:bold;" target="_blank" title="Click to know more about IDEAL">IDEAL</a> led Maxwell to conclude that thevariation in electric and magnetic field <a href="https://interviewquestions.tuteehub.com/tag/vectors-14090" style="font-weight:bold;" target="_blank" title="Click to know more about VECTORS">VECTORS</a> perpendicular <br/> to each other leads to the production of e.m. wave, which can travel in <a href="https://interviewquestions.tuteehub.com/tag/space-649515" style="font-weight:bold;" target="_blank" title="Click to know more about SPACE">SPACE</a>.</body></html> | |
| 169. |
A short-circuited coil is placed in a time varying magnetic field. Electrical power is dissipated due to the current induced in the coil. If the number of turns were to be quadrupled and the radius of the wire is to be halved, then find the electrical power dissipated |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> : Current is induced in the short-circuited coil due to the imposed time - varying magnetic field. <br/>Power P = `(e^2)/(R )` <br/>Here e ` = - (dphi)/(dt)` where `<a href="https://interviewquestions.tuteehub.com/tag/phi-599602" style="font-weight:bold;" target="_blank" title="Click to know more about PHI">PHI</a> = NBA` <br/>and `R = (<a href="https://interviewquestions.tuteehub.com/tag/rho-623364" style="font-weight:bold;" target="_blank" title="Click to know more about RHO">RHO</a> l)/(pi r^2) ` where l and r are <a href="https://interviewquestions.tuteehub.com/tag/length-1071524" style="font-weight:bold;" target="_blank" title="Click to know more about LENGTH">LENGTH</a> and radius of the wire<br/>` therefore P = (pi r^2)/(rho l) [ (d)/(dl) (NBA) ]^2 " or " P = (pi r^2)/(rho l) N^2 A^2 ((dB)/(dt))^2`<br/>or P = (constant) `(N^2r^2)/(l)` <br/>When `r_2= (r_1)/(2)` then `l_2 = 4l_1` <br/>` P_2/P_1 = ((4N)^2)/(N^2) xx ((r)/(2r))^2 xx ((l)/(4l))`<br/>` therefore P_2/P_1 = (16N^2 xx r^2 xx l)/(N^2 xx 4r^2 xx 4l) " or " P_2/P_1 = 1/1 `<br/>`therefore ` Power dissipated is the same</body></html> | |
| 170. |
A paricle starts from the origin at t = 0s with a velocity of 10.0hatjm//s and moves in the xyplane with a constant acceleration of (8.0hati+2.0hatj)ms^(-2). What time is the xcoordinate of the particle 16m? |
| Answer» <html><body><p>t = 2s<br/>t=4s<br/>t=3s<br/>t=1s</p>Answer :A</body></html> | |
| 171. |
A ball is thrown upwards from the ground . It is at a height of 100m in upwards and downward journeys at times t_1 and t_2 respectively , If g = 10m/s^2 , then t_1t_2 is equal to |
| Answer» <html><body><p>10<br/>20<br/>40<br/>50</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 172. |
A radioactive sample decays with a mean life of 20ms. A capacitor of capacitance 100muF is charged to some potential and then the plates are connected to a resistance .R.. If the ratio of the charge on the capacitance to the activity of radioactive sample remains constant in time is R=100(x)Omega, then x= |
| Answer» <html><body><p>2<br/>3<br/>4<br/>5</p>Answer :A</body></html> | |
| 173. |
Unit of molality is |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/mol-1100196" style="font-weight:bold;" target="_blank" title="Click to know more about MOL">MOL</a>/kg<br/>Mol/L<br/>`Mol L^2`<br/>It is <a href="https://interviewquestions.tuteehub.com/tag/unitless-3246853" style="font-weight:bold;" target="_blank" title="Click to know more about UNITLESS">UNITLESS</a> quantity</p>Answer :A</body></html> | |
| 174. |
Is photoelectric emission possible at all frequencies ? Give reason for your answer . |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Kinetic energy of photoelectrons is <a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a> by Einstein.s <a href="https://interviewquestions.tuteehub.com/tag/photoelectric-599886" style="font-weight:bold;" target="_blank" title="Click to know more about PHOTOELECTRIC">PHOTOELECTRIC</a> equation `K_max = 1/2 mv_max^2 = hv - omega_0` = `(hv)/lembda - omega_0` <br/> `therefore v_max^2 prop 1/lambda` <br/> `v_max prop 1/sqrtlembda`. As the wavelength of incident <a href="https://interviewquestions.tuteehub.com/tag/light-1073401" style="font-weight:bold;" target="_blank" title="Click to know more about LIGHT">LIGHT</a> decreases, the velocity of photoelectrons increases.</body></html> | |
| 175. |
From the two e.m.f. equations e_1 = E_0 sin (100 pit) and e_2 = E_0 sin (100 pit + pi/3), we find that |
| Answer» <html><body><p>`e_1` leads `e_2` by `60^@` <br/>`e_2` lags behind `e_1` by `60^@`<br/>`e_2` <a href="https://interviewquestions.tuteehub.com/tag/achieves-2396761" style="font-weight:bold;" target="_blank" title="Click to know more about ACHIEVES">ACHIEVES</a> its maximum <a href="https://interviewquestions.tuteehub.com/tag/value-1442530" style="font-weight:bold;" target="_blank" title="Click to know more about VALUE">VALUE</a> `1/300` <a href="https://interviewquestions.tuteehub.com/tag/second-1197322" style="font-weight:bold;" target="_blank" title="Click to know more about SECOND">SECOND</a> before `e_1`<br/>`e_1` achieves its maximum value `1/300` second before `e_2`</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 176. |
A 900 pF capacitor is charged by 50 V battery. Find the electrostatic potential energy of this capacitor. (2) Now this capacitor is disconnected from the battery and connect to another equivalent capacitor, then what is the total electrostatic energy stored by the system respectively ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`1.125 xx10^(-<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>) <a href="https://interviewquestions.tuteehub.com/tag/j-520843" style="font-weight:bold;" target="_blank" title="Click to know more about J">J</a>, 0.5625 xx10^(-6)`J</body></html> | |
| 177. |
The mutual inductance of a pair of coils if a current of 3 ampere in one coil causes the flux in the second coil of 2000 turns to change by 6xx10^(-4) weber per turn of the secondary coil is |
| Answer» <html><body><p>`6xx10^(-4)` henry <br/>`<a href="https://interviewquestions.tuteehub.com/tag/2xx10-1840192" style="font-weight:bold;" target="_blank" title="Click to know more about 2XX10">2XX10</a>^(-4)` henry <br/>0.4 henry <br/>4 henry </p>Solution :`<a href="https://interviewquestions.tuteehub.com/tag/phi-599602" style="font-weight:bold;" target="_blank" title="Click to know more about PHI">PHI</a> N =<a href="https://interviewquestions.tuteehub.com/tag/mi-1095461" style="font-weight:bold;" target="_blank" title="Click to know more about MI">MI</a>, M = (2000xx6xx10^(-4))/(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)=0.4` henry.</body></html> | |
| 178. |
The north pole of a magnet is brought from a coil, then the direction of induced current will be __ |
| Answer» <html><body><p>in the <a href="https://interviewquestions.tuteehub.com/tag/clockwise-919294" style="font-weight:bold;" target="_blank" title="Click to know more about CLOCKWISE">CLOCKWISE</a> <a href="https://interviewquestions.tuteehub.com/tag/direction-1696" style="font-weight:bold;" target="_blank" title="Click to know more about DIRECTION">DIRECTION</a> <br/>in the <a href="https://interviewquestions.tuteehub.com/tag/anticlockwise-2431777" style="font-weight:bold;" target="_blank" title="Click to know more about ANTICLOCKWISE">ANTICLOCKWISE</a> direction <br/><a href="https://interviewquestions.tuteehub.com/tag/initially-516121" style="font-weight:bold;" target="_blank" title="Click to know more about INITIALLY">INITIALLY</a> in the clockwise and then anticlockwise direction <br/>initially in the anticlockwise and then clockwise direction.</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 179. |
The value of horizontal component of the earth's field, at a place where the dip is 45^(@) and total field 3.4 xx 10^(-5) tesla is |
| Answer» <html><body><p>`2.404 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(-<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>) T`<br/>`0.2404 xx 10^(-5)T`<br/>`24.04 xx 10^(-5) T`<br/>`0.02404 xx 10^(-5) T`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 180. |
A pellet with charge +Q is centered inside a spherical cavity in a conducting ball. The conducting ball has a charge -2q on it. The cavity in the ball is off-center, as shown in Fig. (a) How much charge resides on the inner surface of the cavity ? (b) Is the charge on the cavity surface distributed uniformly or nonuniformly ? Why ? (c ) How much charge resides on the outer surface of the conducting ball ? (d) Is the charge on the ball's outer surface distribution uniformly or nonuniformly ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :(a) -<a href="https://interviewquestions.tuteehub.com/tag/q-609558" style="font-weight:bold;" target="_blank" title="Click to know more about Q">Q</a>, (<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>) <a href="https://interviewquestions.tuteehub.com/tag/uniformaly-3245823" style="font-weight:bold;" target="_blank" title="Click to know more about UNIFORMALY">UNIFORMALY</a>, (<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> ) -q, (d) uniformaly</body></html> | |
| 181. |
How does a lubricant help in decreasing friction ? |
| Answer» <html><body><p></p>Solution :Lubricant gets <a href="https://interviewquestions.tuteehub.com/tag/filled-2641169" style="font-weight:bold;" target="_blank" title="Click to know more about FILLED">FILLED</a> in the irregularities and <a href="https://interviewquestions.tuteehub.com/tag/thus-2307358" style="font-weight:bold;" target="_blank" title="Click to know more about THUS">THUS</a> <a href="https://interviewquestions.tuteehub.com/tag/forms-11384" style="font-weight:bold;" target="_blank" title="Click to know more about FORMS">FORMS</a> a layer in between the two surfaces. Under such circumstances firm interlocking is not <a href="https://interviewquestions.tuteehub.com/tag/possible-592355" style="font-weight:bold;" target="_blank" title="Click to know more about POSSIBLE">POSSIBLE</a>. <a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a>, there is a decrease in force of faction.</body></html> | |
| 182. |
unit of mole fraction is - |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/mol-1100196" style="font-weight:bold;" target="_blank" title="Click to know more about MOL">MOL</a> L<br/>Mol/L<br/>`Mol L^2`<br/>it is <a href="https://interviewquestions.tuteehub.com/tag/unitless-3246853" style="font-weight:bold;" target="_blank" title="Click to know more about UNITLESS">UNITLESS</a> quantity</p>Answer :D</body></html> | |
| 183. |
The earth (mass=6xx10^24 kg), revolves around the sun with angular velocity of 2xx10^(-7) rad/s in a circular orbit of radius 1.5xx10^8 km. What is the force exerted by the sun on the earth ? |
| Answer» <html><body><p></p>Solution :The <a href="https://interviewquestions.tuteehub.com/tag/gravitational-476409" style="font-weight:bold;" target="_blank" title="Click to know more about GRAVITATIONAL">GRAVITATIONAL</a> force exerted by the sun of the earth is <a href="https://interviewquestions.tuteehub.com/tag/equal-446400" style="font-weight:bold;" target="_blank" title="Click to know more about EQUAL">EQUAL</a> to the <a href="https://interviewquestions.tuteehub.com/tag/cp-427206" style="font-weight:bold;" target="_blank" title="Click to know more about CP">CP</a> force `(mv^2)/r =mrw^2` <br/> `therefore F=mrw^2` <br/> `6xx10^24xx1.5xx10^8xx10^3xx(2xx10^(-7))^2` <br/> `3.6xx10^32` N.</body></html> | |
| 184. |
While doing an experiment with potentiometer (see figure) it was found that the deflection is one sided and (i) the deflection decreased while moving from one and A of the wire, to the end R, (ii) the deflection increased, while the jockey was moved towards the end D. (a)Which terminal positive and negative of the cell E_1 is connected at X in case (i) and how is E_1 related to E ? (b)Which terminal of the cell E_1 is connected at X in case (i in a) ? |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/na-572417" style="font-weight:bold;" target="_blank" title="Click to know more about NA">NA</a></body></html> | |
| 185. |
A ball is suspended a cord from the ceiling of a motor car. What will be the effect on the position of the ball if the car is moving with constant velocity |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :The <a href="https://interviewquestions.tuteehub.com/tag/ball-891849" style="font-weight:bold;" target="_blank" title="Click to know more about BALL">BALL</a> will <a href="https://interviewquestions.tuteehub.com/tag/remains-621920" style="font-weight:bold;" target="_blank" title="Click to know more about REMAINS">REMAINS</a> <a href="https://interviewquestions.tuteehub.com/tag/suspended-656920" style="font-weight:bold;" target="_blank" title="Click to know more about SUSPENDED">SUSPENDED</a> <a href="https://interviewquestions.tuteehub.com/tag/vertically-3260386" style="font-weight:bold;" target="_blank" title="Click to know more about VERTICALLY">VERTICALLY</a></body></html> | |
| 186. |
A ball is suspended by a cord from the ceiling of a motor car. What will be the effect on the position of the ball if the car is moving with accelerated motion |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :The <a href="https://interviewquestions.tuteehub.com/tag/ball-891849" style="font-weight:bold;" target="_blank" title="Click to know more about BALL">BALL</a> will <a href="https://interviewquestions.tuteehub.com/tag/move-548879" style="font-weight:bold;" target="_blank" title="Click to know more about MOVE">MOVE</a> <a href="https://interviewquestions.tuteehub.com/tag/backward-391901" style="font-weight:bold;" target="_blank" title="Click to know more about BACKWARD">BACKWARD</a></body></html> | |
| 187. |
A ball is suspended by a cord from the ceiling of a motor car. What will be the effect on the position of the ball if the car is turning towards right. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :The <a href="https://interviewquestions.tuteehub.com/tag/ball-891849" style="font-weight:bold;" target="_blank" title="Click to know more about BALL">BALL</a> will <a href="https://interviewquestions.tuteehub.com/tag/move-548879" style="font-weight:bold;" target="_blank" title="Click to know more about MOVE">MOVE</a> <a href="https://interviewquestions.tuteehub.com/tag/towards-7269729" style="font-weight:bold;" target="_blank" title="Click to know more about TOWARDS">TOWARDS</a> the <a href="https://interviewquestions.tuteehub.com/tag/left-1070879" style="font-weight:bold;" target="_blank" title="Click to know more about LEFT">LEFT</a>.</body></html> | |
| 188. |
In Question 3 and 4, what is the net power absorbed by each circuit over a complete cycle ? Explain your answer. |
| Answer» <html><body><p></p>Solution :`P = E_(<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>) I_(v) cos phi` <br/> In a pure inductor, phase difference between alternating <a href="https://interviewquestions.tuteehub.com/tag/voltage-1447811" style="font-weight:bold;" target="_blank" title="Click to know more about VOLTAGE">VOLTAGE</a> and current is `phi = 90^(@)` <br/> `:. P = E_(v) I_(v) cos 90^(@) =` Zero. <br/> In Q.4 `P = E_(v) I_(v) cos phi` <br/> In a pure capacitor, phase difference between alternating voltage and current is `phi = 90^(@)` <br/> `:. P = E_(v) I_(v) cos 90^(@) =` Zero <br/> Infact, in both the cases, power spent in one <a href="https://interviewquestions.tuteehub.com/tag/half-1014510" style="font-weight:bold;" target="_blank" title="Click to know more about HALF">HALF</a> <a href="https://interviewquestions.tuteehub.com/tag/cycle-942437" style="font-weight:bold;" target="_blank" title="Click to know more about CYCLE">CYCLE</a> is retrieved in <a href="https://interviewquestions.tuteehub.com/tag/hte-2718409" style="font-weight:bold;" target="_blank" title="Click to know more about HTE">HTE</a> other half cycle.</body></html> | |
| 189. |
In a full wave rectifier circuit operating from50 Hz mains frequency, the fundamental frequency in the ripple would be ……… |
| Answer» <html><body><p> <a href="https://interviewquestions.tuteehub.com/tag/25-296426" style="font-weight:bold;" target="_blank" title="Click to know more about 25">25</a> <a href="https://interviewquestions.tuteehub.com/tag/hz-493442" style="font-weight:bold;" target="_blank" title="Click to know more about HZ">HZ</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/50-322056" style="font-weight:bold;" target="_blank" title="Click to know more about 50">50</a> Hz <br/>70.7 Hz <br/><a href="https://interviewquestions.tuteehub.com/tag/100-263808" style="font-weight:bold;" target="_blank" title="Click to know more about 100">100</a> Hz </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :100 Hz <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/KPK_AIO_PHY_XII_P2_C14_E04_127_S01.png" width="80%"/></body></html> | |
| 190. |
Two block-spring mass system are moving on smooth horizontal surface as shown in the figure as t=0. find out the minimum time t when the spring is maximum elongated l_(0) is the natural length of spring. |
| Answer» <html><body><p></p>Solution :`T=2pisqrt((<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)/(9pi^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)))=(2xx2)/(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)=(4)/(3)` <br/> `t=(3T)/(4)=(3)/(4)xx((4)/(3))=1`</body></html> | |
| 191. |
A solid disc is rotating at an angular speed of 20 rad//s. It is decelerated at a constant rate of 2 rad // s^2 . Through what angle disc will turn before coming to rest ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`omega^2-omega_0^2=2 alpha <a href="https://interviewquestions.tuteehub.com/tag/theta-1412757" style="font-weight:bold;" target="_blank" title="Click to know more about THETA">THETA</a>`<br/> `<a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a> 0-400=2xx(-2)xxtheta therefore theta`=<a href="https://interviewquestions.tuteehub.com/tag/100-263808" style="font-weight:bold;" target="_blank" title="Click to know more about 100">100</a> <a href="https://interviewquestions.tuteehub.com/tag/radian-1175760" style="font-weight:bold;" target="_blank" title="Click to know more about RADIAN">RADIAN</a></body></html> | |
| 192. |
(A) : In Ampere Maxwell law, displacement current has same physical effect as conduction current. (R) : The units and dimensions of displacement current and conduction current are same. |
| Answer» <html><body><p>Both 'A' and '<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>' are <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a> and 'R' is the correct <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> of 'A'.<br/>Both 'A' and ’R' are true and 'R' is not the correct explanation of 'A<br/>A' is true and 'R' is <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a><br/>'A' is false and R' is true</p>Answer :B</body></html> | |
| 193. |
The following objects are placed one after each other in given order onto a central axis with a separation of 40 cm each. A point source of light O. a diverging lens of focal length 40 cm. a converging lens of focal length 40 cm and converging mirror of focal length 80 cm. The aperture diameter of lenses and mirror is d=20 cm. If a point source of light is placed at a perpendicular distance of x from central axis then. (You have to consider single optical event at any optical element) Mark the CORRECT statement(s):- |
| Answer» <html><body><p>Final image is formed in the plane of converging lens<br/>If `x gt 1.5d` the rays will not be reflected by converging mirror<br/>For `x gt d` final real images can be <a href="https://interviewquestions.tuteehub.com/tag/captured-7293063" style="font-weight:bold;" target="_blank" title="Click to know more about CAPTURED">CAPTURED</a> on a screen after on optical <a href="https://interviewquestions.tuteehub.com/tag/event-976579" style="font-weight:bold;" target="_blank" title="Click to know more about EVENT">EVENT</a> (i.e refraction or reflection)at every optical system<br/>Final image is real and inverted </p>Solution :Let us follow the way the images are formed by the lenses and the mirror. The virtual image formed by the diverging lens has an image distance of<br/> `i_(1)=(O_(1)f_(1))/(O_(1)-f_(1))=(-4.4)/(4-(-4))dm=-2dm`(dmrarrdecimeter) <br/> Since the linear magnification is <br/> `m_(1)=(H_(i1))/(H_(O1))=(i_(1))/(O_(1))=(1)/(2)`<br/> the height of the first image is <br/> `H_(i1)=(x)/(2)=H_(O2)`. <br/> This virtual image is seen bythe diverging lens as an object with an object distance of `O_(2)=f_(2)+|i_(2)|=6dm`, <a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a> the image formed by second lens has an image distance of<br/> `i_(2)=(O_(2)f_(2))/(O_(2)-f_(2))=(6.4)/(6-4)dm=12dm`<br/> The linear magnification of the second lens is <br/> `m_(2)=(i_(2))/(O_(2))=(12)/(6)=2`<br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/ALN_XII_P4_E01_164_S01.png" width="80%"/> <br/> Hence the height of the second image is `H_(i2)=m_(2)H_(O2)=m_(2)H_(i1)=xc=H_(O3.)`<br/> The second image is seen by the concave mirror as a virtual object bering at a distance of `O_(3)=f_(3)-i_(2)=-8dm`, therefore the image is formed at <br/> `i_(3)=(O_(3)f_(3))/(O_(3)-f_(3))=(-8.8)/(-8-8)=(-64)/(-16)=1dm`<br/> This is a real image and since the linear magnification of the mirror is: <br/> `m_(3)=(i_(3))/(O_(3))=(1)/(2)`<br/> the height of the final image is <br/> `H_(i3)=m_(3)H_(O3)=(x)/(2)` <br/> Note that final image is formed in the plane of the converging lens, therefore the image can only be captured on a screen if its height is greater than the radius of the lens. This happens when x is greater than d, therefore the list condition for perpendicular is d lt x. If x is increased further than`1.5 d`,the rayswillall pass under the concave mirror and there will be no image formation. Therefore the solution of the <a href="https://interviewquestions.tuteehub.com/tag/problem-25530" style="font-weight:bold;" target="_blank" title="Click to know more about PROBLEM">PROBLEM</a> is : <br/> `d lt x lt 1.5 d`.creased further than `1.5 d`, the rays will all pass under the concave mirror and there will be no images formation. Therefore the solution of the problem is: <br/> `d lt x lt 1.5 d`.</body></html> | |
| 194. |
What are drawbacks of the capillary rise method? |
| Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a> It is difficult to measure mean radius .r. over a <a href="https://interviewquestions.tuteehub.com/tag/range-1177030" style="font-weight:bold;" target="_blank" title="Click to know more about RANGE">RANGE</a> of the entire height.<br/>2 The cleaning of such narrow tube is not easy.<br/>3 A correction for the curvature of the surface of liquid in the <a href="https://interviewquestions.tuteehub.com/tag/container-20566" style="font-weight:bold;" target="_blank" title="Click to know more about CONTAINER">CONTAINER</a> is necessary but difficult to <a href="https://interviewquestions.tuteehub.com/tag/determine-437910" style="font-weight:bold;" target="_blank" title="Click to know more about DETERMINE">DETERMINE</a></body></html> | |
| 195. |
Calculate the relation between the angle of incidence and angle of deviation of a prism? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :M = 1+D/f.</body></html> | |
| 196. |
In an L-C-R A.C. series circuit L = 5H, omega = "100 rads"^(-1), R= 100 Omega and power factor is 0.5. Calculate the value of capacitance of the capacitor. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/first-461760" style="font-weight:bold;" target="_blank" title="Click to know more about FIRST">FIRST</a> Method : <br/>Power factor `cosdelta=R/sqrt(R^2+(omegaL-1/(omegaC))^2)` <br/>Square on both <a href="https://interviewquestions.tuteehub.com/tag/sides-1207029" style="font-weight:bold;" target="_blank" title="Click to know more about SIDES">SIDES</a> `cos^2delta=R^2/(R^2+(omegaL-1/(omegaC))^2)` <br/> but , cos`delta=0.5=1/2` <br/> `therefore 1/4=R^2/(R^2+(omegaL-1/(omegaC))^2)` <br/>`therefore R^2+(omegaL-1/(omegaC))^2` <br/> `therefore (omegaL-1/(omegaC))^2=3R^2` <br/> `therefore omegaL-1/(omegaC)=sqrt3R` <br/> `therefore omegaL-sqrt3R=1/(omegaC)` <br/> `therefore C=1/omega(1/(omegaL-sqrt3R))` <br/>`=1/100(1/(100xx5-sqrt3xx100))` <br/> `=<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(-2)/(500-173.2)=10^(-2)/326.8=306xx10^(-7)` <br/> `=30.6xx10^(-6)` F <br/>=30.6 `muF` <br/>Second Method: <br/>Power factor `cosdelta=0.5` <br/>`therefore delta=pi/3` rad <br/> Now tan`delta=(omegaL-1/(omegaC))/R` <br/> `therefore "tan"pi/3 xx R=omegaL-1/(omegaC)` <br/> `therefore sqrt3xx100=100xx5-1/(100xxC)` <br/> `therefore 1.732xx100=500-1/(100C)` <br/>`therefore 1/(100C) =500-173.2` <br/> `therefore 1/(100C) =326.8` <br/>`therefore C=1/(326.8xx100)`=0.00003059 <br/> `approx 30.6xx10^(-6)F=30.6 muF`</body></html> | |
| 197. |
The capacitance of a conductor ____________ when an earthed conductor is brought near it. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Increases. On <a href="https://interviewquestions.tuteehub.com/tag/bringing-402272" style="font-weight:bold;" target="_blank" title="Click to know more about BRINGING">BRINGING</a> an <a href="https://interviewquestions.tuteehub.com/tag/earthed-7680948" style="font-weight:bold;" target="_blank" title="Click to know more about EARTHED">EARTHED</a> conductor <a href="https://interviewquestions.tuteehub.com/tag/close-408965" style="font-weight:bold;" target="_blank" title="Click to know more about CLOSE">CLOSE</a> by, the potential decreases and <a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a> capacitance increases.</body></html> | |
| 198. |
While doing an experiment with potcntiometc as shown in figure in was found that th deflection is one sided and(i) the detlectio, decreased while moving from one end A of the wire to the end B,(ii) the deflection increase while the jockey was moved towards the end (i) Which terminal + or - ve Of the cell E_(1)connected at X in case (i) and how is related to E ? (ii) Which terminal of the cellE_(1) is connected at X in case (ii) ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :(i) Deflection of galvanometer is on one <a href="https://interviewquestions.tuteehub.com/tag/side-1206832" style="font-weight:bold;" target="_blank" title="Click to know more about SIDE">SIDE</a> when jokey key is moved from A to B if deflection decreases, then it can be <a href="https://interviewquestions.tuteehub.com/tag/said-629244" style="font-weight:bold;" target="_blank" title="Click to know more about SAID">SAID</a> that current through primary cell (<a href="https://interviewquestions.tuteehub.com/tag/lower-1080637" style="font-weight:bold;" target="_blank" title="Click to know more about LOWER">LOWER</a> circuit) decrease. and p.d. between point A and jokey key increase. This is possible only if positive of `E_(1) ` cell is connected with terminal X, thus `E_(1) gt ` <a href="https://interviewquestions.tuteehub.com/tag/e-444102" style="font-weight:bold;" target="_blank" title="Click to know more about E">E</a> <b> (ii) When jokey key is moved from A to B if deflection increases then it can be said that current through primary cell (lower circuit) increases and p.d. between jokey key and A decreases.<br/> This is possible only if positive of `E_(1) ` cell is connected with X.</b></body></html> | |
| 199. |
As shown in the figure, the planes of two concentric coils are mutually perpendicular. The mutual inductance of this system is ……. |
| Answer» <html><body><p>`mu_0N^2A`<br/>`(mu_0NA)/L`<br/>zero<br/>none of zero </p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/passing-1148520" style="font-weight:bold;" target="_blank" title="Click to know more about PASSING">PASSING</a> current `I_1`, through <a href="https://interviewquestions.tuteehub.com/tag/coil-921250" style="font-weight:bold;" target="_blank" title="Click to know more about COIL">COIL</a>-1 produced (induced) magnetic field lines (magnetic flux) is perpendicular to plane of coil -1 and coil-2 is <a href="https://interviewquestions.tuteehub.com/tag/also-373387" style="font-weight:bold;" target="_blank" title="Click to know more about ALSO">ALSO</a> <a href="https://interviewquestions.tuteehub.com/tag/kept-2146214" style="font-weight:bold;" target="_blank" title="Click to know more about KEPT">KEPT</a> perpendicular to coil-1. So magnetic flux passing through it `phi_2=0`. <br/> Now, `phi_2=M_21 I_1` in `phi_2=0` so `M_21=0`. <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/KPK_AIO_PHY_XII_P1_C06_E04_090_S01.png" width="80%"/></body></html> | |
| 200. |
The following truth table corresponds to the logical gate |
| Answer» <html><body><p>NAND<br/>OR<br/>AND<br/>XOR</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |