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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 12 knowledge and support exam preparation. Choose a topic below to get started.
| 45101. |
When a compact disc is illuminated by a source of white light, coloured lines are observed. This is due to: |
| Answer» <html><body><p>dispersion<br/>diffraction<br/>interference<br/>refraction</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 45102. |
An LCR circuit consists of L = 230 mH, C = 70 mu F and R = 200 Omega. The frequency of AC main is 60Hz and E = 36V . Calculate impedance Z, current I and angle phi . |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/JYT_AJP_AIO_PHY_XII_C07_SLV_018_S01.png" width="80%"/> <br/> `X_C= (<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)/(2pi v C) = (1)/(2 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 3.14 xx 60 xx 70 xx 10^(-<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>) ) = 38 Omega` <br/> ` X_L = 2pi v L = 2 xx 3.14 xx 60xx <a href="https://interviewquestions.tuteehub.com/tag/230-295101" style="font-weight:bold;" target="_blank" title="Click to know more about 230">230</a> xx 10^(-3) = 87 Omega` <br/> `R = 200 Omega`<br/> ` Z = sqrt(R^2 + (X_L - X_C)^2) = sqrt(200^2+ (87 -38)^2)` <br/> ` = sqrt(200^2 + 49^2) = 206 Omega `<br/> Current `I = E/Z = 36/206 = 0.174 A` <br/> Phase `phi = tan^(-1)( (X_L - X_C)/(R ) ) = tan^(-1) [ (87-38)/(200) ]` <br/> `phi = tan^(-1) (0.245) = 13.8^@ = 13^@46.` <br/> ` V_R = IR= 0.174 xx 200 = 34.8 V` <br/> ` V_L = IX_L = 0.174 xx 87 = 15.1 V` <br/> ` V_C = IX_C = 0.174 xx 38 = 6.6 V `<br/>`X_L gt X_C` so emf lead the current I.</body></html> | |
| 45103. |
An induced emf of 10 mV is set up in a coil when current flowing through a neighbouring coil is 2As^(-1) The mutual inductance for the pair of coils is ____. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a> <a href="https://interviewquestions.tuteehub.com/tag/mh-1082136" style="font-weight:bold;" target="_blank" title="Click to know more about MH">MH</a></body></html> | |
| 45104. |
Critical angle of light passing from glass to air is minimum for |
| Answer» <html><body><p>red<br/>yellow<br/>green<br/>violet</p>Answer :A</body></html> | |
| 45105. |
Same quantity of ice is filled in each of the two metal containers P and having the same size, shape and wall thickness but made of different materials. The containers are kept in identical surroundings. The ice in P melts completely in time t_1, whereas that in Q takes a time t_2. The ratio of thermal conductivities of the materials of P and Q is |
| Answer» <html><body><p>`t_2 : t_1`<br/>`t_1:t_2`<br/>`t_1 :t_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)^(2)`<br/>`t_(2)^(2) :t_(1)^(2)`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Let`K_1and K_2 `be thethermalcondictivitiesofcontainersP and <a href="https://interviewquestions.tuteehub.com/tag/qrespectively-2236428" style="font-weight:bold;" target="_blank" title="Click to know more about QRESPECTIVELY">QRESPECTIVELY</a><br/> Asthe samequanitityof icemelts in Pand Qthequanitityof heatflowsinP andQ <a href="https://interviewquestions.tuteehub.com/tag/mustbe-2850066" style="font-weight:bold;" target="_blank" title="Click to know more about MUSTBE">MUSTBE</a> same<br/> ` thereforeQ = (K_1A(T_1 -T_2)t_1)/(<a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a>) = (K_2 A(T_1 -T_2)t_2)/(x)` <br/> ` orK_1 T_1 = k_2t_2or(k_1)/(k_2) = (t_2)/(t_1)`</body></html> | |
| 45106. |
A capacitor in an LC oscillator has a maximum potential difference of 17 V and a maximum energy of 160 muJ. When the capacitor has a potential difference of 5 V and an energy of 10 muJ, what are (a) the emf across the inductor and (b) the energy stored in the magnetic field? |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :(a)<a href="https://interviewquestions.tuteehub.com/tag/5v-326363" style="font-weight:bold;" target="_blank" title="Click to know more about 5V">5V</a> ; (<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>) `<a href="https://interviewquestions.tuteehub.com/tag/150-275254" style="font-weight:bold;" target="_blank" title="Click to know more about 150">150</a> <a href="https://interviewquestions.tuteehub.com/tag/muj-2847157" style="font-weight:bold;" target="_blank" title="Click to know more about MUJ">MUJ</a>`</body></html> | |
| 45107. |
When an object is placed in front of a concave mirror of focal length f, a virtual image is produced with a magnification of 2. To obtain a real image with a magnification of 2, the object has to be moved by a distance equal to |
| Answer» <html><body><p>`(f)/(2)`<br/>`(2f)/(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)`<br/>f<br/>`(<a href="https://interviewquestions.tuteehub.com/tag/3f-310706" style="font-weight:bold;" target="_blank" title="Click to know more about 3F">3F</a>)/(2)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :C</body></html> | |
| 45108. |
When .^(30)Si bombarded with a deutron. .^(31)Si is formed in its ground state with the emission of a proton. The energy released in this reaction from the following is E then find [E]:- |
| Answer» <html><body><p><br/></p>Solution :`d+^(30)Sirarr^(31)Si+p`.......(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>) <br/> `Q=M_(d)+M_(Si^(30))-M_(si^(31))-M_(p)` .....(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) <br/> Given <br/> `M_(si^(30)+M_(d)=M_(p)^(31))+M_(<a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a>)+5.1` .....(3) <br/> `M_(Si)^(31)=M_(p^(31))+M_(e )+1.51` ......(4) <br/> Subtract (4) from (3) <br/> `M_(si^(30))+M_(d)-M_(si^(31))=M_(n)-M_(e )+3.59` .......(5) <br/> Further <br/> `M_(n)=M_(p)+M_(e )+<a href="https://interviewquestions.tuteehub.com/tag/overset-2905731" style="font-weight:bold;" target="_blank" title="Click to know more about OVERSET">OVERSET</a>(-)v+0.78` .......(6) <br/> <a href="https://interviewquestions.tuteehub.com/tag/add-361838" style="font-weight:bold;" target="_blank" title="Click to know more about ADD">ADD</a> (5) and (6) <br/> `M_(si^(30))+M_(d)-M_(si^(31))-M_(p)=Q=3.59+0.78=4.37MeV`</body></html> | |
| 45109. |
A 0.030 m container is initially evacuated. Then, 4.0 g of water is placed in the container and, after some time, all the water evaporates. If the temperature of the water vapor is 388 K, what is its pressure? |
| Answer» <html><body><p>`1. 5xx 10^5Pa`<br/>`2.4 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 10^4 <a href="https://interviewquestions.tuteehub.com/tag/pa-1145246" style="font-weight:bold;" target="_blank" title="Click to know more about PA">PA</a>`<br/>`6.9 xx 10^4 `Pa<br/>`8.2 xx 10^4 Pa`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 45110. |
Out of the two coils placed near each other, when a current of 2 amp is passes through the other .If the number of turns in the secondary coils is 20, the value of coefficient of mutual induction in the coils will be __ |
| Answer» <html><body><p>6H<br/>6 mH<br/>0.6H<br/>0.mH</p>Answer :d</body></html> | |
| 45111. |
Which one of the following line integrals is correct ? Note : The direction of the loops orientation is shown in the following figure. |
| Answer» <html><body><p>`oint_(c_(1))vecB.vecdl=mu_(0)i_(1)`<br/>`oint_(c_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))vecB.vecdl=mu_(0)i_(2)`<br/>`oint_(c_(1))vecB.vecdl=-mu_(0)i_(2)`<br/>`oint_(c_(1))vecB.vecdl=-mu(i_(1)-1_(2))`</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>::D</body></html> | |
| 45112. |
Light of intensity 10^(-5) W m^(-2) falls on a sodium photo-cell of surface area 2 cm^(2) . Assuming that the top 5 layers of sodium absorb the incident energy, estimate time required for photoelectric emission in the wave-picture of radiation. The work function for the metal is given to be about 2 eV. What is the implication of your answer? |
| Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/assume-384429" style="font-weight:bold;" target="_blank" title="Click to know more about ASSUME">ASSUME</a> one conduction electron per atom. Effective atomic area `~10^(-<a href="https://interviewquestions.tuteehub.com/tag/20-287209" style="font-weight:bold;" target="_blank" title="Click to know more about 20">20</a>)m^(2)` <br/> Number of electrons in 5 layers <br/> `=(5xx2xx10^(-4)m^(2))/(10^(-20)m^(2))=10^(17)` <br/> Incident power <br/> `=10^(-5)Wm^(-2)xx2xx10^(-4)m^(2)=2xx10^(-9)<a href="https://interviewquestions.tuteehub.com/tag/w-729065" style="font-weight:bold;" target="_blank" title="Click to know more about W">W</a>` <br/> In the wave picture, incident power is uniformly absorbed by all the electrons continuously. Consequently, energy absorbed per second per electron <br/> `=2xx10^(-9)//10^(17)=2xx10^(-26)W` <br/> Time required for photoelectric emission <br/> `=2xx1.6xx10^(-19)J//2xx10^(-26)W=1.6xx10^(7)s` <br/> Which is about 0.5 year <br/> Implication: Experimentally, photoelectric emission is observed nearly instantaneously `(~10^(-9) s)`: Thus, the wave picture is in gross disagreement with experiment. In the photon-picture, energy of the radiation is not continuously shared by all the electrons in the top layers. <a href="https://interviewquestions.tuteehub.com/tag/rather-2973755" style="font-weight:bold;" target="_blank" title="Click to know more about RATHER">RATHER</a>, energy comes in discontinuous ‘quanta’. and <a href="https://interviewquestions.tuteehub.com/tag/absorption-15370" style="font-weight:bold;" target="_blank" title="Click to know more about ABSORPTION">ABSORPTION</a> of energy does not take place gradually. A photon is either not absorbed, or absorbed by an electron nearly instantly.</body></html> | |
| 45113. |
In deriving Newton's formula for velocity of sound, the changes in volume of air are assumed to be |
| Answer» <html><body><p>Isobaric<br/>Adiabatic<br/><a href="https://interviewquestions.tuteehub.com/tag/isothermal-520014" style="font-weight:bold;" target="_blank" title="Click to know more about ISOTHERMAL">ISOTHERMAL</a><br/>Isochoric</p>Solution :In deriving Newton's <a href="https://interviewquestions.tuteehub.com/tag/formula-464310" style="font-weight:bold;" target="_blank" title="Click to know more about FORMULA">FORMULA</a> for velocity of sound, the <a href="https://interviewquestions.tuteehub.com/tag/changes-913881" style="font-weight:bold;" target="_blank" title="Click to know more about CHANGES">CHANGES</a> in volume of <a href="https://interviewquestions.tuteehub.com/tag/air-852233" style="font-weight:bold;" target="_blank" title="Click to know more about AIR">AIR</a> are assumed to be isothermal.</body></html> | |
| 45114. |
A man is using concave mirror for shavinghis face the mirror having magnification 2 what will be the radius of curvature of the mirror? |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/60-328817" style="font-weight:bold;" target="_blank" title="Click to know more about 60">60</a> cm <br/>80 cm <br/><a href="https://interviewquestions.tuteehub.com/tag/50-322056" style="font-weight:bold;" target="_blank" title="Click to know more about 50">50</a> cm<br/>40 cm </p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 45115. |
Who propounded that the radiation from a source is emitted not continuously but intermittently in integral multiples of atom of energy called quantum ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/max-546895" style="font-weight:bold;" target="_blank" title="Click to know more about MAX">MAX</a> <a href="https://interviewquestions.tuteehub.com/tag/plank-1155681" style="font-weight:bold;" target="_blank" title="Click to know more about PLANK">PLANK</a></body></html> | |
| 45116. |
If f(x)max{x^2,(1-x)^2,3/4}, x in [0,1] , then the value of underset0overset1int f(x) dx is |
| Answer» <html><body><p>`(6sqrt3-1)/12`<br/>`3/4(sqrt3-1)`<br/>`(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>-sqrt3)/2`<br/>`(8-3sqrt3)/<a href="https://interviewquestions.tuteehub.com/tag/24-295400" style="font-weight:bold;" target="_blank" title="Click to know more about 24">24</a>`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/ALN_JEE_SCR_TST_01_E01_067_S01.png" width="80%"/> <br/> `underset0overset1f(x)=underset0overset((2-sqrt3)/2)<a href="https://interviewquestions.tuteehub.com/tag/int-11513" style="font-weight:bold;" target="_blank" title="Click to know more about INT">INT</a>(1-x)^2dx+underset((2-sqrt3)/2)<a href="https://interviewquestions.tuteehub.com/tag/overset-2905731" style="font-weight:bold;" target="_blank" title="Click to know more about OVERSET">OVERSET</a>(sqrt3/2)int3/4dx+underset(sqrt3/2)overset1intx^2dx` <br/> `=(6sqrt3-1)/12`</body></html> | |
| 45117. |
How many resonating structures of are possible (including given structure) : |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/RES_P20_17_APCT_P5_XI_E01_067_S01.png" width="80%"/></body></html> | |
| 45118. |
The force acting per unit length on one conductor due to the other for two long parallel current - carrying wires is |
| Answer» <html><body><p>`(mu_(0))/(<a href="https://interviewquestions.tuteehub.com/tag/4pi-1882352" style="font-weight:bold;" target="_blank" title="Click to know more about 4PI">4PI</a>)(I_(1)I_(2))/(<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>)`<br/>`(mu_(0))/(4pi)(I_(1)I_(2))/(r)`<br/>`(mu_(0))/(4pi)(2I_(1)I_(2))/(r)`<br/>`(mu_(0))/(4pi)(I_(1)I_(2))/(<a href="https://interviewquestions.tuteehub.com/tag/4r-319038" style="font-weight:bold;" target="_blank" title="Click to know more about 4R">4R</a>)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 45119. |
Two progressive transverse waves given by y_1 = 0.07 sin pi ( 12x - 500 t) and y_2 = 0.07 sin pi (12 x 500t)travelling along a stretched string form nodes and antinodes. What is the displacement at the What is the wavelength ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`1//6 m`</body></html> | |
| 45120. |
Power dissipated in an L-C-R series circuit connected to an AC source of emf epsilon is |
| Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/epsilon-973455" style="font-weight:bold;" target="_blank" title="Click to know more about EPSILON">EPSILON</a>^(2)R)/([R^(2)+(Lomega-(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)/(Comega))^(2)])`<br/>`(epsilon^(2)[R^(2)+(Lomega-(1)/(Comega))^(2)])/(R)`<br/>`(epsilon^(2)[R^(2)+(Lomega+(1)/(Comega))^(2)])/(R)`<br/>`(epsilon^(2)R)/(<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(R^(2)+(Lomega-(1)/(Comega))^(2)))`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 45121. |
Why did the author and grandmother go to school together? |
| Answer» <html><body><p>Because temple was <a href="https://interviewquestions.tuteehub.com/tag/attached-1964039" style="font-weight:bold;" target="_blank" title="Click to know more about ATTACHED">ATTACHED</a> to the school<br/>Because the author <a href="https://interviewquestions.tuteehub.com/tag/wanted-3266983" style="font-weight:bold;" target="_blank" title="Click to know more about WANTED">WANTED</a> to <a href="https://interviewquestions.tuteehub.com/tag/take-662846" style="font-weight:bold;" target="_blank" title="Click to know more about TAKE">TAKE</a> care of his grandmother<br/>Both a and b<br/>None of the above</p>Answer :A</body></html> | |
| 45122. |
In charging a capacitor of capacitance C by a source of emf V, energy supplied by the sources QV and the energy stored in the capacitor is1//2 QV. Justify the difference. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :In the capacitor the voltage increases from O to V, hence energy <a href="https://interviewquestions.tuteehub.com/tag/stored-7260220" style="font-weight:bold;" target="_blank" title="Click to know more about STORED">STORED</a> will correspond to average which will be ` 1//2 <a href="https://interviewquestions.tuteehub.com/tag/qv-611767" style="font-weight:bold;" target="_blank" title="Click to know more about QV">QV</a>`.Whilethe sourceisatconstantemf V. Soenergysuppliedwill be QV. Thedifferencebetweenthe twogoesas heatandemf <a href="https://interviewquestions.tuteehub.com/tag/radiations-1175877" style="font-weight:bold;" target="_blank" title="Click to know more about RADIATIONS">RADIATIONS</a>.</body></html> | |
| 45123. |
The load current in the transmitting antenna of an unmodulated AM transmitter is 6 Amp. What will be the antenna current when modulation is 60%. |
| Answer» <html><body><p></p>Solution :Total power carried by AM wave <br/> `P_(T)=P_(<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>)(1+(m^(2))/(2))`…..(1) <br/>Where `P_(C)` is the power of carrier componenet and m is the modulation factor.If R is the resistance ,`I_(m)` the antenna <a href="https://interviewquestions.tuteehub.com/tag/load-11593" style="font-weight:bold;" target="_blank" title="Click to know more about LOAD">LOAD</a> current when modulation is <a href="https://interviewquestions.tuteehub.com/tag/60-328817" style="font-weight:bold;" target="_blank" title="Click to know more about 60">60</a>% and `I_(C)` Is the antenna load current when unmodulated ,then <br/>`(P_(T))/(P_(C))=(I_(m)^(2)R)/(I_(C)^(2)R)""therefore 1+(m^(2))/(2)=(I_(m)^(2))/(I_(C)^(2))` <a href="https://interviewquestions.tuteehub.com/tag/using-7379753" style="font-weight:bold;" target="_blank" title="Click to know more about USING">USING</a> (1) <br/>or `I_(m)=I_(C)<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>({(1+(m^(2))/(2))})` <br/>Given `I_(C)`=6Amp,m=0.6 <br/>6[1.086]=6.52 Amp.</body></html> | |
| 45124. |
(a) Name three elements required to specify the earth's magnetic field at a given place. Draw a labelled diagram to define these elements . Explain briefly how these elements are determined to find out the magnetic field at a given place on the surface of earth. (b) A short bar magnet of magnetic moment m = 0.32 J T^(-1) is placed in a uniform magnetic field of 0.15 T. If the bar is free to rotate in the plane of the field , which orientation would correspond to its (a) stable and (b) unstable equilibrium ? What is the potential energy of the magnet in each case ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :(<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>) (i) parallel , `-4.8xx10^(-<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) J, `(ii) <a href="https://interviewquestions.tuteehub.com/tag/antiparallel-878790" style="font-weight:bold;" target="_blank" title="Click to know more about ANTIPARALLEL">ANTIPARALLEL</a>, + 4.8 `xx 10^(-2) J`</body></html> | |
| 45125. |
In any Bohr orbit of the hydrogen atom, the ratio of kinetic energy to potential energy of the electron is ...... |
| Answer» <html><body><p>`(1)/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>2<br/>`(-1)/(2)`<br/>`-2`</p>Solution :Kinetic energy for H atom `K=(e^(2))/(<a href="https://interviewquestions.tuteehub.com/tag/2r-300472" style="font-weight:bold;" target="_blank" title="Click to know more about 2R">2R</a>)` <br/> Potential energy `U=(-e^(2))/(r )` <br/> `:.(K)/(U)=(e^(2)//2r)/(-e^(2)//r)=(-1)/(2)`</body></html> | |
| 45126. |
In an experiment a convex lens of focal length 15 cm is placed coaxially on an optical bench in front of a convex mirror at a distance of 5 cm from it. It is found that an object and its image coincide, if the object is placed at a distance of 20 cm from the lens. The focal length of the convex mirror is : |
| Answer» <html><body><p>27.5 cm<br/>20.0 cm<br/>25.0 cm <br/>30.5 cm</p>Solution :Given that the focal length of the convex lens, `<a href="https://interviewquestions.tuteehub.com/tag/f-455800" style="font-weight:bold;" target="_blank" title="Click to know more about F">F</a>=15cm`<br/> Object distance, `u= -20 cm ` <br/> Let the distance of the <a href="https://interviewquestions.tuteehub.com/tag/image-11684" style="font-weight:bold;" target="_blank" title="Click to know more about IMAGE">IMAGE</a> formed by the lens from its optical centre be `<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>`. <br/> Using lens formula <br/> `1/f= 1/v -1/u` <br/> `1/v = 1/f +1/u= 1/15 - 1/20` <br/> `1/v = (4-3)/(60)` <br/> ` v = 60 cm ` <br/> The convex lens forms an image at a distance 60 cm, rightwards, the image is real and inverted <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/MOD_UNT_PHY_XII_P2_C09_E08_099_S01.png" width="80%"/> <br/>The final image can be formed on the object itself when the rays afterrefraction from the lens retracetheir paths. That is only possible here when the rays fall normally on the convex mirror. <br/> The rays directed <a href="https://interviewquestions.tuteehub.com/tag/towards-7269729" style="font-weight:bold;" target="_blank" title="Click to know more about TOWARDS">TOWARDS</a> the centre of curvature of the convex mirror are actually perpendicular to it and they retrace their paths. <br/> Hence, the image formed by the convex lens should lie at the the centre of curvature of the convex mirror. Image distance for lens = distance between the lens and the mirror `+` radius of curvature <br/> `60 cm = 5 cm + R` <br/> ` R = 55 cm` <br/> We <a href="https://interviewquestions.tuteehub.com/tag/know-534065" style="font-weight:bold;" target="_blank" title="Click to know more about KNOW">KNOW</a> the relation between focal length f and radius of curvature R <br/> `2f= 55 cm` <br/> ` f = 55//2 = 27.5cm`</body></html> | |
| 45127. |
A 1m long wire having tension of 100 N and of linear mass density 0.01 kg/m is fixed and A and free at end B. the point C which is 20cm from end B is constrained to be stationary. To create resonance in the wire, the minimum frequency of the tuning fork will be : |
| Answer» <html><body><p>125 Hz<br/>150 Hz<br/>300 Hz<br/>275 Hz</p>Solution :Length of <a href="https://interviewquestions.tuteehub.com/tag/bc-389540" style="font-weight:bold;" target="_blank" title="Click to know more about BC">BC</a> to AC is `(20)/(<a href="https://interviewquestions.tuteehub.com/tag/80-337972" style="font-weight:bold;" target="_blank" title="Click to know more about 80">80</a>)=(1)/(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)` <br/> So, value of loops in BC to AC will also be `1 : 4` <br/> `f_(1)=(1)/(4(0.2))sqrt((T)/(mu))=125 Hz` <br/> `f_(2) = (3)/(4(0.2))sqrt((T)/(mu))=275 Hz`.</body></html> | |
| 45128. |
In the above question what is the acceleration of the cylinder? |
| Answer» <html><body><p>g<br/>`g//3`<br/>`2g//3`<br/>`(3g)/(4)`</p>Solution :Let the cylinder fall through a height .<a href="https://interviewquestions.tuteehub.com/tag/h-1014193" style="font-weight:bold;" target="_blank" title="Click to know more about H">H</a>. in time t, then the loss in P.E. is equal to gain in K.E. <a href="https://interviewquestions.tuteehub.com/tag/thus-2307358" style="font-weight:bold;" target="_blank" title="Click to know more about THUS">THUS</a> <br/> `Mgh=(1)/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)Mv^(2)+(1)/(2)<a href="https://interviewquestions.tuteehub.com/tag/iomega-2133375" style="font-weight:bold;" target="_blank" title="Click to know more about IOMEGA">IOMEGA</a>^(2)` <br/> or `Mgh=(1)/(2)Mv^(2)+(1)/(2)xx(1)/(2)MR^(2)xx(v^(2))/(R^(2))` <br/> `=(1)/(2)Mv^(2)+(1)/(4)Mv^(2)=(3)/(4)Mv^(2)` <br/> or `gh=3//4v^(2),"But "v^(2)=2ah` <br/> `gh=(3)/(4)xx2ah` <br/> `therefore a=(2g)/(3)`</body></html> | |
| 45129. |
The earth magnetic field at the equator is approximately 04.G. Estimate the earth's dipole moment. |
| Answer» <html><body><p></p>Solution :From Eq (5.7), the equatorial magnetic field is `B_(E)=(mu_(0)m)/(4pi <a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>^(3))` <br/> We are given that `B_(E)-0.4G=4 xx <a href="https://interviewquestions.tuteehub.com/tag/106-266627" style="font-weight:bold;" target="_blank" title="Click to know more about 106">106</a>(-5)T.` For r we take the radius of the earth `6.4 xx 10^(6) m`. Hence `m=(4 xx 10^(-5) xx (6.4 xx 10^(6))^(3))/(mu_(0)//4pi)=4 xx 10^(2) xx (6.4 xx 10^(6))^(3) (mu_(0)//4pi=10^(-7))` <br/> `=1.05 xx 10^(23) Am^(2)` <br/> This is close to the <a href="https://interviewquestions.tuteehub.com/tag/value-1442530" style="font-weight:bold;" target="_blank" title="Click to know more about VALUE">VALUE</a> of `8 xx 10^(22) A m^(2)` quoted in geomegnetic <a href="https://interviewquestions.tuteehub.com/tag/texts-1243373" style="font-weight:bold;" target="_blank" title="Click to know more about TEXTS">TEXTS</a>.</body></html> | |
| 45130. |
A rectangular wire loop of sides 8 cm and 2 cm with a small cut is moving out of a region of uniform magnetic field of magnitude 0.3 T directed normal to the loop. What is the emf developed across the cut if the velocity of the loop is 1 "cm s"^(-1)in a direction normal to the (a) longer side, (b) shorter side of the loop ? For how long does the induced voltage last in each case ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>) 2.4xx10^(-4) V , ` lasting <a href="https://interviewquestions.tuteehub.com/tag/2s-301125" style="font-weight:bold;" target="_blank" title="Click to know more about 2S">2S</a> <br/>(2) `0.6xx10^(-4) V, ` lasting 8s</body></html> | |
| 45131. |
The resistivity of indium arsenide is 2.5xx10^(-3) ohm m, its Hall constant is 10^(-2)m^(3)//C. Assuming the conductivity to be due to carriers of one sign only, find the concentration and the mobility of the charge carriers. . |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`6.2xx10^(<a href="https://interviewquestions.tuteehub.com/tag/20-287209" style="font-weight:bold;" target="_blank" title="Click to know more about 20">20</a>)m^(-<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>);4.0m^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)//(V.s)`</body></html> | |
| 45132. |
Show graphically, the variation of the de-Broglie wavelength (lambda) with the potential (V) through which an electron is accelerated from rest. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/OSW_SP_PHY_XII_C11_E02_007_S01.png" width="80%"/></body></html> | |
| 45133. |
A projectile of mass m is thrown with a velocity v making an angle 60° with the horizontal. Neglecting air resistance, the change in momentum from the departure A to its arrival at B, along the vertical directions : |
| Answer» <html><body><p>2mv<br/>`sqrt(3)`mv<br/>`mv`<br/>`(mv)/sqrt(3)`</p>Solution :The vertical component of velocity v at the <a href="https://interviewquestions.tuteehub.com/tag/points-1157347" style="font-weight:bold;" target="_blank" title="Click to know more about POINTS">POINTS</a> A and B in the fig. will be equal but opposite i.e. v <a href="https://interviewquestions.tuteehub.com/tag/sin-1208945" style="font-weight:bold;" target="_blank" title="Click to know more about SIN">SIN</a>`<a href="https://interviewquestions.tuteehub.com/tag/theta-1412757" style="font-weight:bold;" target="_blank" title="Click to know more about THETA">THETA</a>` and (- v sin`theta`). <br/><a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a> `Deltap = mv sin 60° - (- mv sin 60°)`<br/>`2mv=sqrt(3)/2=sqrt(3)mv`</body></html> | |
| 45134. |
If the number of turns of a solenoid is doubled, keeping the other factors constant, how does the self-inductance of the solenoid change? |
| Answer» <html><body><p><br/></p>Answer :As `Lpropot <a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a>^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`, hence self-inductance becomes 4 <a href="https://interviewquestions.tuteehub.com/tag/times-1420471" style="font-weight:bold;" target="_blank" title="Click to know more about TIMES">TIMES</a> of its original <a href="https://interviewquestions.tuteehub.com/tag/value-1442530" style="font-weight:bold;" target="_blank" title="Click to know more about VALUE">VALUE</a>.</body></html> | |
| 45135. |
Ratio of number density of holes is (7)/(5) and ratio of their current is (7)/(4) in a semiconductor. The ratio of their drift velocity is ……. |
| Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)/(7)` <br/>`(<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>)/(8)` <br/>`(4)/(5)` <br/>`(5)/(4)` </p>Solution :`(5)/(4)` <br/><a href="https://interviewquestions.tuteehub.com/tag/current-940804" style="font-weight:bold;" target="_blank" title="Click to know more about CURRENT">CURRENT</a> in semiconductor `I=nAv_(d)e` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a> v_(d)=(I)/(nAe)` <br/> `therefore v_(d ) prop (I)/(n) [because "A, e constant"]` <br/> `therefore ((v_(d))_(e))/((v_(d))_(h))=(I_(e ))/(I_(h))xx(n_(h))/(n_(e ))`<br/> `=(7)/(4) xx (5)/(7)=(5)/(4)`</body></html> | |
| 45136. |
Deuteron and a-particle are put 1A apart in air. Magnitude of intensity of electric field due to deuteron at a particle is : |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/zero-751093" style="font-weight:bold;" target="_blank" title="Click to know more about ZERO">ZERO</a><br/>`2.88xx10^11"<a href="https://interviewquestions.tuteehub.com/tag/newton-11212" style="font-weight:bold;" target="_blank" title="Click to know more about NEWTON">NEWTON</a>"//"<a href="https://interviewquestions.tuteehub.com/tag/coul-2551043" style="font-weight:bold;" target="_blank" title="Click to know more about COUL">COUL</a>"`<br/>`1.44xx10^11"Newton"//"coul"`<br/>`5.76xx10^11N//<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :C</body></html> | |
| 45137. |
An inductor of 5H inductance carries a steady current of 2A. How can a 50V self-induced emf to made to appear in the inductor? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :L= 5H, |e| = 50V <br/> Let <a href="https://interviewquestions.tuteehub.com/tag/us-718298" style="font-weight:bold;" target="_blank" title="Click to know more about US">US</a> produce the required emf by reducing current to zero. Now `|e|= L (dI)/(dt) or dt= (LdI)/(|e|)= (<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a> xx 2)/(50)s` <br/>`=(10)/(50)s= (1)/(5)s= 0.2s` <br/> So, the desired emf can be produced by reducing the given current to zero in 0.2 second.</body></html> | |
| 45138. |
The S.I. unit of inductive reactance is |
| Answer» <html><body><p>Henry<br/>Ohms<br/>Volt<br/>No unit</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 45139. |
The strong neutron excess (defined as N - Z) of high- mass nuclei is illustrated by noting that most high-mass nuclides could never fission into two stable nuclei without neutrons being left over. For example, consider the spontaneous fission of a ""^(235)U nucleus into two stable daughter nuclei with atomic numbers 39 and 53. From Appendix F, determine the name of the (a) first and (b) second daughter nucleus. From Fig. 40-6, approximately how many neutrons are in the (c) first and (d) second? (e) Approximately how many neutrons are left over? |
| Answer» <html><body><p><br/></p>Answer :a.yttrium,<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>. iodine; <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>. 50 <a href="https://interviewquestions.tuteehub.com/tag/neutrons-1114464" style="font-weight:bold;" target="_blank" title="Click to know more about NEUTRONS">NEUTRONS</a> d. 74 neurtons e. <a href="https://interviewquestions.tuteehub.com/tag/19-280618" style="font-weight:bold;" target="_blank" title="Click to know more about 19">19</a></body></html> | |
| 45140. |
Select the correct answer out of the options given against each question and write in the box provided on rigth hand side bottom: The process in which the amplitude of the carrier wave is made proportional to the instantnaeous amplitude of the signal wave is called |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/amplitude-859568" style="font-weight:bold;" target="_blank" title="Click to know more about AMPLITUDE">AMPLITUDE</a> modulation <br/>demodulation<br/>rectification <br/>amplification<br/></p>Solution :In the process of amplitude modulation, the amplitude of the <a href="https://interviewquestions.tuteehub.com/tag/carrier-413704" style="font-weight:bold;" target="_blank" title="Click to know more about CARRIER">CARRIER</a> wave is <a href="https://interviewquestions.tuteehub.com/tag/made-3718337" style="font-weight:bold;" target="_blank" title="Click to know more about MADE">MADE</a> <a href="https://interviewquestions.tuteehub.com/tag/proportional-1170279" style="font-weight:bold;" target="_blank" title="Click to know more about PROPORTIONAL">PROPORTIONAL</a> to the instantaneous amplitude of the <a href="https://interviewquestions.tuteehub.com/tag/signal-1207167" style="font-weight:bold;" target="_blank" title="Click to know more about SIGNAL">SIGNAL</a> wave.</body></html> | |
| 45141. |
In a noiseless transformer, an alternating current of 2A is flowing in primary coil. The number of turns in primary and secondary coil are 100 and 20 respectively the secondary current is ......... |
| Answer» <html><body><p>0.4 A<br/>`<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a> A`<br/>0.08 A<br/>`<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a> A`</p>Solution :`I_1`=<a href="https://interviewquestions.tuteehub.com/tag/2a-300249" style="font-weight:bold;" target="_blank" title="Click to know more about 2A">2A</a> , `N_1` = 100, `N_2`= <a href="https://interviewquestions.tuteehub.com/tag/20-287209" style="font-weight:bold;" target="_blank" title="Click to know more about 20">20</a> , `I_2`= ? <br/>`I_2/I_1=N_1/N_2` <br/> `therefore I_2=I_1 N_1/N_2 = (2xx100)/20`= 10 A</body></html> | |
| 45142. |
In CGS system whats the unit of coefficient of self induction. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/ab-360636" style="font-weight:bold;" target="_blank" title="Click to know more about AB">AB</a> <a href="https://interviewquestions.tuteehub.com/tag/henry-484399" style="font-weight:bold;" target="_blank" title="Click to know more about HENRY">HENRY</a>.</body></html> | |
| 45143. |
L is a long conducting thread and there is a small plate p which is earthed through C. Some amount of electricity will flow through C |
| Answer» <html><body><p> if a <a href="https://interviewquestions.tuteehub.com/tag/current-940804" style="font-weight:bold;" target="_blank" title="Click to know more about CURRENT">CURRENT</a> fluctuates in the L<br/> if a current through L is reversed<br/> if L is <a href="https://interviewquestions.tuteehub.com/tag/replaced-613867" style="font-weight:bold;" target="_blank" title="Click to know more about REPLACED">REPLACED</a> by a <a href="https://interviewquestions.tuteehub.com/tag/fine-989069" style="font-weight:bold;" target="_blank" title="Click to know more about FINE">FINE</a> beam of a particles<br/>if <a href="https://interviewquestions.tuteehub.com/tag/lis-542554" style="font-weight:bold;" target="_blank" title="Click to know more about LIS">LIS</a> replaced by a narrow beam of electrons.</p>Answer :C::D</body></html> | |
| 45144. |
The dimensional formula of pressure is (1990) |
| Answer» <html><body><p>`[MLT^(-2) ]`<br/>`[<a href="https://interviewquestions.tuteehub.com/tag/ml-548251" style="font-weight:bold;" target="_blank" title="Click to know more about ML">ML</a>^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)T^(2)]` <br/>`[ML^(-1) T^(-2)]`<br/>`[MLT^(2) ] `</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 45145. |
What are the dimensions of R/L ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`M^(<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>)<a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a>^(0)T^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)`</body></html> | |
| 45146. |
A beam of monochromatic light entering a glass window pane from the air will experience a change in |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/frequency-465761" style="font-weight:bold;" target="_blank" title="Click to know more about FREQUENCY">FREQUENCY</a> nad wavelength<br/>frequency and speed<br/>speed and wavelength<br/>speed only</p>Solution :When a wave <a href="https://interviewquestions.tuteehub.com/tag/enters-972302" style="font-weight:bold;" target="_blank" title="Click to know more about ENTERS">ENTERS</a> a new medium, its frequency does not <a href="https://interviewquestions.tuteehub.com/tag/change-913808" style="font-weight:bold;" target="_blank" title="Click to know more about CHANGE">CHANGE</a>, but its wave speed does. Since `lamdaf=v`, the change in wave speed <a href="https://interviewquestions.tuteehub.com/tag/implies-1037962" style="font-weight:bold;" target="_blank" title="Click to know more about IMPLIES">IMPLIES</a> a change in wavelength also.</body></html> | |
| 45147. |
In a plane electromagnetic ware the electric field oscillates sinusoidally at frequency of 2.0xx10^10 Hz and amplitude 48Vm^(-1).What is the amplitude of the oscillating magnetic field? |
| Answer» <html><body><p></p>Solution :Amplitude of <a href="https://interviewquestions.tuteehub.com/tag/magnetic-551115" style="font-weight:bold;" target="_blank" title="Click to know more about MAGNETIC">MAGNETIC</a> <a href="https://interviewquestions.tuteehub.com/tag/field-987291" style="font-weight:bold;" target="_blank" title="Click to know more about FIELD">FIELD</a> `B_0=(E_0)/<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>=(48)/(3xx10^8)=1.6xx10^(-<a href="https://interviewquestions.tuteehub.com/tag/7-332378" style="font-weight:bold;" target="_blank" title="Click to know more about 7">7</a>).`</body></html> | |
| 45148. |
In a plane electromagnetic ware the electric field oscillates sinusoidally at frequency of 2.0xx10^10 Hz and amplitude 48Vm^(-1).What is wagelength of the wave ? |
| Answer» <html><body><p></p>Solution :Here `epsilon=48 Vm^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>), f=<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>.0xx10^10 Hz C=3xx10^8 <a href="https://interviewquestions.tuteehub.com/tag/ms-549331" style="font-weight:bold;" target="_blank" title="Click to know more about MS">MS</a>^(-1)` (i) Wavelength of the <a href="https://interviewquestions.tuteehub.com/tag/wave-22399" style="font-weight:bold;" target="_blank" title="Click to know more about WAVE">WAVE</a> `lambda=C/f=(3xx10^8)/(2.0xx10^10) = 1.5xx10^(-2) m.`</body></html> | |
| 45149. |
A particle executes S.H.M. with an amplitude of 2 cm. When the particle is at 1 cm from the mean position the magnitude of tis velocity is equalto that of its acceleration. Then its time periodin second is : |
| Answer» <html><body><p>`(1)/(2pi sqrt(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>))`<br/>`2pi sqrt(3)`<br/>`(2pi)/(sqrt(3))`<br/>`(sqrt(3))/(2pi)`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`omega sqrt(r^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)-y^(2))=omega^(2)y` <br/> `sqrt(r^(2)-y^(2))=omega y=(2pi)/(T)y` <br/> `T=(2pi y)/(sqrt(r^(2)-y^(2)))=(2pi <a href="https://interviewquestions.tuteehub.com/tag/xx1-1463705" style="font-weight:bold;" target="_blank" title="Click to know more about XX1">XX1</a>)/(sqrt(2^(2)-1^(2)))=(2pi)/(sqrt(3))`second. <br/> Correct choice is ( c ).</body></html> | |
| 45150. |
Match the following |
| Answer» <html><body><p></p>Solution :a. is directlyproportional to <a href="https://interviewquestions.tuteehub.com/tag/current-940804" style="font-weight:bold;" target="_blank" title="Click to know more about CURRENT">CURRENT</a> <br/> <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>. no battery is required <br/> <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>. shorter the de-Broglie <a href="https://interviewquestions.tuteehub.com/tag/wavelength-1450414" style="font-weight:bold;" target="_blank" title="Click to know more about WAVELENGTH">WAVELENGTH</a> <br/> d. electron volt</body></html> | |