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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 12 knowledge and support exam preparation. Choose a topic below to get started.
| 45201. |
A nucleus containing Z protons and N neutrons has a mass M . If the mass of a proton is m_p and that of a neutron is m_n , then the mass defect of the nucleus is |
| Answer» <html><body><p>`M-Zm_p-Nm_n`<br/>`Zm_p+Nm_n-M`<br/>`(M-Zm_p-Nm_n)/(Z+N)`<br/>`(Zm_p+Nm_n-M)/(Z+N)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 45202. |
A force vector applied on a mass is represented as vec(F)=6 hat(i) - 8hat(j) + 10hat(k) N and accelerates the mass at 5 ms^(-2) . The mass of the body is : |
| Answer» <html><body><p>`2sqrt(2)`kg<br/>40 kg<br/>1.6 kg<br/>`2sqrt(10)` kg</p>Solution :`m=(|<a href="https://interviewquestions.tuteehub.com/tag/vec-723433" style="font-weight:bold;" target="_blank" title="Click to know more about VEC">VEC</a>(F)|)/(|vec(A)|)=<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(36 + 64+100)/5=sqrt(2)/5`<br/>`2sqrt(2)` kg</body></html> | |
| 45203. |
Two beams of light having intensities I and 4I interfere to produce a fringe pattern on the screen.Phase differenced between the beamsis (pi)/(2) atpoint A and pi at point B.Then difference between the resultant intensities at A and B is : |
| Answer» <html><body><p>3I<br/>4I<br/>5I<br/>6I</p>Solution :`I_(1) = I , I_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) = 4I` <br/> `theta_(1) = (<a href="https://interviewquestions.tuteehub.com/tag/pi-600185" style="font-weight:bold;" target="_blank" title="Click to know more about PI">PI</a>)/(2), theta_(2) = pi` <br/> Now, `I_(A) = I_(1) + I_(2) +2sqrt(I_(1)I_(2)) <a href="https://interviewquestions.tuteehub.com/tag/cos-935872" style="font-weight:bold;" target="_blank" title="Click to know more about COS">COS</a> (pi)/(2)` <br/> ` = I + 4I + 0 = 5I` <br/> `I_(<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>) = I_(1) + I_(2) +2sqrt(I_(1)I_(2)) cos pi = 1` <br/> `therefore I_(A) - I_(B) = 5I - I = 4I`</body></html> | |
| 45204. |
The focal length of a thin biconvex lens is 20cm. When an object is moved from a distance 25cm in front of it 50cm, the magnitude of magnification of its image changes from m_25to m_50 . The ratio (m_25)/(m_50) is |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a></body></html> | |
| 45205. |
What is an electrostatic shielding? Mention its one application. |
| Answer» <html><body><p></p>Solution :The field inside the cavity of conductor is alaways zero and it remain shielded from outside electric influence . This is known as <a href="https://interviewquestions.tuteehub.com/tag/electrostatic-2069468" style="font-weight:bold;" target="_blank" title="Click to know more about ELECTROSTATIC">ELECTROSTATIC</a> shielding . <a href="https://interviewquestions.tuteehub.com/tag/sensitive-3019148" style="font-weight:bold;" target="_blank" title="Click to know more about SENSITIVE">SENSITIVE</a> <a href="https://interviewquestions.tuteehub.com/tag/components-926700" style="font-weight:bold;" target="_blank" title="Click to know more about COMPONENTS">COMPONENTS</a> of <a href="https://interviewquestions.tuteehub.com/tag/electronic-968847" style="font-weight:bold;" target="_blank" title="Click to know more about ELECTRONIC">ELECTRONIC</a> <a href="https://interviewquestions.tuteehub.com/tag/devices-25633" style="font-weight:bold;" target="_blank" title="Click to know more about DEVICES">DEVICES</a> are protected.</body></html> | |
| 45206. |
Which of the following is not due to total internal reflection ? |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/optical-583872" style="font-weight:bold;" target="_blank" title="Click to know more about OPTICAL">OPTICAL</a> fibre<br/>mirage<br/>reddish <a href="https://interviewquestions.tuteehub.com/tag/appearance-881925" style="font-weight:bold;" target="_blank" title="Click to know more about APPEARANCE">APPEARANCE</a> of <a href="https://interviewquestions.tuteehub.com/tag/sun-1234558" style="font-weight:bold;" target="_blank" title="Click to know more about SUN">SUN</a> at sunset<br/>brillance of diamond</p>Answer :D</body></html> | |
| 45207. |
Velocity of a particle moving in a straight line is v=sqrt(9+4s). Here v is in m/s and 's' displacement in meter.Mass of the particle is 2kg. The time in seconds at which average power is ((3)/(4))^(th) of the instantaneous power is : |
| Answer» <html><body><p>0.92<br/>0.67<br/><a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>.5<br/>`3.0`</p>Solution :Maximum energy stored in spring `=(1)/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)<a href="https://interviewquestions.tuteehub.com/tag/mu-566056" style="font-weight:bold;" target="_blank" title="Click to know more about MU">MU</a> V_("ret")^(2)=(1)/(2)((mm)/(m+m))(V_(0)^(2))=(1)/(4)mV_(0)^(2)`</body></html> | |
| 45208. |
What are anastigmatic lenses ? |
| Answer» <html><body><p></p>Solution :The lenses which have been duly corrected for most of the optical defects of images <a href="https://interviewquestions.tuteehub.com/tag/formed-464209" style="font-weight:bold;" target="_blank" title="Click to know more about FORMED">FORMED</a> by them are called anastigmatic lenses. <br/> These lenses are used in good <a href="https://interviewquestions.tuteehub.com/tag/quality-17732" style="font-weight:bold;" target="_blank" title="Click to know more about QUALITY">QUALITY</a> optical instruments <a href="https://interviewquestions.tuteehub.com/tag/like-1073845" style="font-weight:bold;" target="_blank" title="Click to know more about LIKE">LIKE</a> camera, <a href="https://interviewquestions.tuteehub.com/tag/microscope-1095829" style="font-weight:bold;" target="_blank" title="Click to know more about MICROSCOPE">MICROSCOPE</a>, <a href="https://interviewquestions.tuteehub.com/tag/telescope-1240831" style="font-weight:bold;" target="_blank" title="Click to know more about TELESCOPE">TELESCOPE</a>, binoculars, etc.</body></html> | |
| 45209. |
(a) In a typical nuclear reaction, e.g., " "_(1)^(2)H + " "_(1)^(2)H to " "_(2)^(3)He +n +3.27 MeV, although number of nucleons is conserved, yet energy is released. How ? Explain. (b) Show that nuclear density in a given nucleus is independent of mass number A. |
| Answer» <html><body><p></p>Solution :(a) Ina typical nuclear reaction, e.g., <br/>`" "_(1)^(2)H + " "_(1)^(2)H to " "_(2)^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)He +n +3.27 MeV`,<br/> although number of nucleons is conserved, yet <a href="https://interviewquestions.tuteehub.com/tag/energy-15288" style="font-weight:bold;" target="_blank" title="Click to know more about ENERGY">ENERGY</a> is released. It is on account of fact that in a nuclear reaction there is <a href="https://interviewquestions.tuteehub.com/tag/tinkering-7717118" style="font-weight:bold;" target="_blank" title="Click to know more about TINKERING">TINKERING</a> with the <a href="https://interviewquestions.tuteehub.com/tag/nucleus-18220" style="font-weight:bold;" target="_blank" title="Click to know more about NUCLEUS">NUCLEUS</a> so as to rearrange its nucleons into more stable configurations. In other words the binding energy per <a href="https://interviewquestions.tuteehub.com/tag/nucleon-1126010" style="font-weight:bold;" target="_blank" title="Click to know more about NUCLEON">NUCLEON</a> is more in a nucleus with stable configuration. As a result energy is released in a nuclear reaction. In fact, the energy released in a nuclear reaction is the difference between the total binding energy of products and total binding energy of reactants.</body></html> | |
| 45210. |
A charge particle q is projected in an electric field produced by a fixed point charge Q as shown in figure. Mark the correct statements. |
| Answer» <html><body><p>The path taken by q is a straight line. <br/>Thepath taken by q is not a straight line. <br/>The <a href="https://interviewquestions.tuteehub.com/tag/minimum-561095" style="font-weight:bold;" target="_blank" title="Click to know more about MINIMUM">MINIMUM</a> distance between the <a href="https://interviewquestions.tuteehub.com/tag/two-714195" style="font-weight:bold;" target="_blank" title="Click to know more about TWO">TWO</a> particles is `((<a href="https://interviewquestions.tuteehub.com/tag/qq-610902" style="font-weight:bold;" target="_blank" title="Click to know more about QQ">QQ</a>)/(2piepsilon_0) + sqrt((qQ)/(2piepsilon_0) + 4m^2u^2a^2))/(2m u^2)`<br/>Velocity of the particle q is changing in both magnitude and direction. </p>Solution :b.,c.,d. <br/> The path traced by `q` is <a href="https://interviewquestions.tuteehub.com/tag/shown-1206565" style="font-weight:bold;" target="_blank" title="Click to know more about SHOWN">SHOWN</a> in Fig. `SAI.58`, The path is curvilinear and acceleration is due to the force exerted by `Q` on `q`. The separation between them is minimum if relative velocity of the particle along the line joining them is zero. Let `d` be the minimum separation between them. As torque about `Q` is zero, angular momentum remains conserved. <br/> `mua=mvd` or `<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>=(ua)/(d)` <br/> From energy conservation law, `(mu^(2))/(2)=(mv^(2))/(2)+(1)/(4piepsilon_(0))(qQ)/(d)` <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/BMS_V03_CA1_E01_116_S01.png" width="80%"/></body></html> | |
| 45211. |
A compound microscope uses an objective lens of focal length 4 cm and eyepiece lens of focal length 10 cm. An object is placed at 6 cm from the objective lens. Calculate the magnifying power of the compound microscope. Also calculate the length of the microscope |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> : It is given that focal length of objective lens `f_(0)= + 4 cm`focal length of eyepiece lens `f_e = +10 cm` and `u_(0) = - 6 cm` <br/> Let the final image is formed at the least distance of distinct vision (D = 25 cm). <br/> For object lens `1/v_(0) -1/u_(0) =1/f_(0) rArr 1/v_(0) + 1/f_(0) = -1/6 + 1/4 =(-2+3)/12 = 1/12` <br/> `therefore v_(0) = + 12 cm` <br/> Again for eyepiece lens `v_e = - D = - 25 cm`, <a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a> <br/> `1/v_(<a href="https://interviewquestions.tuteehub.com/tag/e-444102" style="font-weight:bold;" target="_blank" title="Click to know more about E">E</a>) -1/u_(e) =1/f_(e) rArr 1/u_(e) -1/_(f_(e)) =1/(-25) -1/(10) = (-2-5)/50 = -7/50` <br/> or `u_(e) = -50/7 =-7.4 cm` <br/> Length of the microscope tube `L = |v_(0)| + |u_(e)| = 12 + 7.4 = 19.4 cm` <br/> and magnifying the power `m=m_(0) xx m_(e) =(v_(0)/u_(0)) xx(v_(e)/v_(f)) =12/(-6) xx (-25)/(-7.4) = -7`</body></html> | |
| 45212. |
Torque is experienced by a current carrying rectangular coil placed in a magnetic field.” Can this principle be used to detect feeble current? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Yes. Even if the <a href="https://interviewquestions.tuteehub.com/tag/current-940804" style="font-weight:bold;" target="_blank" title="Click to know more about CURRENT">CURRENT</a> is <a href="https://interviewquestions.tuteehub.com/tag/feeble-456884" style="font-weight:bold;" target="_blank" title="Click to know more about FEEBLE">FEEBLE</a>, torque is <a href="https://interviewquestions.tuteehub.com/tag/produced-592947" style="font-weight:bold;" target="_blank" title="Click to know more about PRODUCED">PRODUCED</a> and deflection of the coil can be <a href="https://interviewquestions.tuteehub.com/tag/made-3718337" style="font-weight:bold;" target="_blank" title="Click to know more about MADE">MADE</a> notable</body></html> | |
| 45213. |
A graph of thermoelectric power against temperature of hot junction of the thermocouple when the cold junction is at 0^(@)C is |
| Answer» <html><body><p>Parabola<br/>Circle<br/>Expotential<br/>Straight line</p>Answer :D</body></html> | |
| 45214. |
Why does a galvanometer show a momentary deflection at the time of charging or discharging a capacitor? Write the necessary a expression to explain this obervation. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Yes, the ammeter <a href="https://interviewquestions.tuteehub.com/tag/show-642916" style="font-weight:bold;" target="_blank" title="Click to know more about SHOW">SHOW</a> a momentary deflection during the process of charging of capacitor by <a href="https://interviewquestions.tuteehub.com/tag/connecting-929445" style="font-weight:bold;" target="_blank" title="Click to know more about CONNECTING">CONNECTING</a> it across a d.c. source along with an ammeter. This deflection is due to a conduction current `I=(dq)/(dt)` is flowing through the connecting <a href="https://interviewquestions.tuteehub.com/tag/wries-3286145" style="font-weight:bold;" target="_blank" title="Click to know more about WRIES">WRIES</a>. Between the plates a capacitor a displacement current `I_(D)=in_(0)(dphi_(E))/(dt)`, where `(dphi_(E))/(dt)` is the rate of change of electric <a href="https://interviewquestions.tuteehub.com/tag/flux-993757" style="font-weight:bold;" target="_blank" title="Click to know more about FLUX">FLUX</a> inside the capacitor.</body></html> | |
| 45215. |
q_(1), q_(2), q_(3) and q_(4) are point charges located at points as shown in thte figure and S is a spherical Gaussian surface of radius R. Which of the following is true according to the Gauss.s law |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/oint-7840256" style="font-weight:bold;" target="_blank" title="Click to know more about OINT">OINT</a>(vec(E_(1))+vec(E_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))+vec(E_(3))).<a href="https://interviewquestions.tuteehub.com/tag/dvec-3608317" style="font-weight:bold;" target="_blank" title="Click to know more about DVEC">DVEC</a>(A)=(q_(1)+q_(2)+q_(3))/(epsilon_(0))`<br/>`oint(vec(E_(1))+vec(E_(2))+vec(E_(3))+vec(E_(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)))dvec(A)=(q_(1)+q_(2)+q_(3))/(epsilon_(0))`<br/>`oint(vec(E_(1))+vec(E_(2))+vec(E_(3))).dvec(A)=((q_(1)+q_(2)+q_(3)+q_(4)))/(epsilon_(0))`<br/>`oint(vec(E_(1))+vec(E_(2))+vec(E_(3))+vec(E_(4))).dvecA=((q_(1)+q_(2)+q_(3)+q_(4)))/(epsilon_(0))`</p>Answer :B</body></html> | |
| 45216. |
Four charges are arranged at the corners of a square ABCD of side d, as shown in Fig. 2.15.(a) Find the work required to put together this arrangement. (b) A charge q_(0) is brought to the centre E of the square, the four charges being held fixed at its corners. How much extra work is needed to do this? |
| Answer» <html><body><p></p>Solution :(a) Since the work done depends on the final <a href="https://interviewquestions.tuteehub.com/tag/arrangement-884592" style="font-weight:bold;" target="_blank" title="Click to know more about ARRANGEMENT">ARRANGEMENT</a> of the charges, and not on how they are put together, we calculate work needed for <a href="https://interviewquestions.tuteehub.com/tag/one-585732" style="font-weight:bold;" target="_blank" title="Click to know more about ONE">ONE</a> way of putting the charges at A, B, C and D. Suppose, first the charge +q is brought to A, and then the charges –q, +q, and –q are brought to B, C and D, respectively. The total work needed can be calculated in steps: <br/> (i) Work needed to bring charge +q to A when no charge is present elsewhere: this is zero. <br/> (ii) Work needed to bring –q to B when +q is at A. This is given by (charge at B) × (electrostatic potential at B due to charge +q at A) <br/> `-q xx (q/(4piepsilon_(0)d)) = -q^(2)/(4pi epsilon_(0)d)` <br/> (iii)Work needed to bring charge +q to C when +q is at A and –q is at B. This is given by (charge at C) × (potential at C due to charges at A and B) <br/> `=+q (+q/4pi epsilon_(0)dsqrt(2)) + -q/(4pi epsilon_(0)d)` <br/> `-q^(2)/(4pi epsilon_(0)d) (1- 1/sqrt(2))` <br/> (iv)Work needed to bring –q to D when +q at A,–q at B, and +q at C. <br/> This is given by (charge at D) × (potential at D due to charges at A, B and C) <br/> `=-q (+q/((4pi epsilon_(0)d)) + (-q)/(4pi epsilon_(0)dsqrt(2)) + q/(4pi epsilon_(0)d))` <br/> `=-q^(2)/(4pi epsilon_(0)d) (2-1/sqrt(2))` <br/> Add the work done in steps (i), (ii), (iii) and (iv). The total work <a href="https://interviewquestions.tuteehub.com/tag/required-1185621" style="font-weight:bold;" target="_blank" title="Click to know more about REQUIRED">REQUIRED</a> is <br/> `=-q^(2)/(4pi epsilon_(0)d) {(0+1 + (1-1/sqrt(2)) + (2-1/sqrt(2))}` <br/> `=-q^(2)/(4pi epsilon_(0)d) (4- sqrt(2))` <br/> The work done depends only on the arrangement of the charges, and not how they are assembled. By definition, this is the total electrostatic energy of the charges. (Students may try calculating same work/energy by taking charges in any other <a href="https://interviewquestions.tuteehub.com/tag/order-1138220" style="font-weight:bold;" target="_blank" title="Click to know more about ORDER">ORDER</a> they desire and convince themselves that the energy will remain the same.) <br/> (b) The extra work necessary to bring a charge `q_0`to the point E when the four charges are at A, B, C and D is `q_0`× (electrostatic potential at E due to the charges at A, B, C and D). The electrostatic potential at E is clearly zero since potential due to A and C is cancelled by that due to B and D. <a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a>, no work is required to bring any charge to point E.</body></html> | |
| 45217. |
A sample of {:(131),( 53):} I, as iodine ion, was administered to a patient in a carrier consisting of 0.10 mg of stable iodide ion. After 4.00 days, 67.7% of the initial radioactivity was detected in the thyroid gland of the patient. What mass of the stable iodide ion had migrated to the thyroid gland ? (t_(1 //2= 8 days.) |
| Answer» <html><body><p>`65.8%`<br/>`95.7%`<br/>`85.8%`<br/>`75.8%`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 45218. |
The half life of radium is 1620 years and its atomic weight is 226 kg per kilomol. The number of atoms that will decay from its 1 g sample per second will be : |
| Answer» <html><body><p>`3.61 xx 10^(10)`<br/>`3.61 xx 10^(12)`<br/>`3.11 xx 10^(15)`<br/>`3.11 xx 10^(16)`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Number of atoms that will decay per second <br/> `=lambdaN=(0.693)/(T_(1//2))N` <br/> `=(0.693)/(<a href="https://interviewquestions.tuteehub.com/tag/1620-1794901" style="font-weight:bold;" target="_blank" title="Click to know more about 1620">1620</a> xx <a href="https://interviewquestions.tuteehub.com/tag/365-1859550" style="font-weight:bold;" target="_blank" title="Click to know more about 365">365</a> xx 86400) xx (6.02 xx 10^(<a href="https://interviewquestions.tuteehub.com/tag/23-294845" style="font-weight:bold;" target="_blank" title="Click to know more about 23">23</a>))/(<a href="https://interviewquestions.tuteehub.com/tag/226-1825001" style="font-weight:bold;" target="_blank" title="Click to know more about 226">226</a>)` <br/> `=3.61 xx 10^(10)`</body></html> | |
| 45219. |
In Young's experiment, two coherent sources are placed 0.9 mm apart and fringe are observed one meter away. If it produces second dark fringe at a distance of 1 mm from central fringe, the wavelength of monochromatic light used would ...... |
| Answer» <html><body><p>`60xx10^(-<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>) cm`<br/>`10xx10^(-4) cm`<br/>`10xx10^(-<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>) cm`<br/>`6xx10^(-5) cm`</p>Solution :For dark fringe, <br/> `x=(2n-1)(lambdaD)/(2d)` <br/> `:. lambda=(2xd)/((2n-1)D)=(2xx10^(-<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)xx0.9xx10^(-3))` <br/> `(2xx2-1)<a href="https://interviewquestions.tuteehub.com/tag/xx1-1463705" style="font-weight:bold;" target="_blank" title="Click to know more about XX1">XX1</a>)` <br/> `lambda=0.6xx10^(-6) m` <br/> `:. =6xx10^(-5) cm`</body></html> | |
| 45220. |
A proton initially has vec v = 4.0 hati- 2.0 hatj + 3.0 hatk and then 4.0 slater has vec v = -2.0 hati - 2.0 hatj + 5.0hatk(in meter per second) for that 4.0s what are (a) the proton's average acceleration vec a_(avg)in unit vector notation (b) the magnitude of vec a_(avg) and (c ) the angle between veca_(avg) and the positive direction of the x axis ? |
| Answer» <html><body><p></p>Solution :We use <a href="https://interviewquestions.tuteehub.com/tag/eq-446394" style="font-weight:bold;" target="_blank" title="Click to know more about EQ">EQ</a>. with <a href="https://interviewquestions.tuteehub.com/tag/vec-723433" style="font-weight:bold;" target="_blank" title="Click to know more about VEC">VEC</a> v_1` designating the initial <a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a> and `vec v_2` designating the later one.<br/>(a) The <a href="https://interviewquestions.tuteehub.com/tag/average-13416" style="font-weight:bold;" target="_blank" title="Click to know more about AVERAGE">AVERAGE</a> acceleration during the `Delta t = 4s` interval is<br/>`vec a_(avg) = ((-2.0 hati - 2.0 hatj + 5.0 hatk) m//s - (4.0hati - 22hatj + 3.0 hatk)m//s)/(4s)` <br/>` = (-1.5 m//s^2) hati + (0.5 m//s^2) hatk`<br/>(b) The magnitude of `vec a_(avg) ` is<br/>` sqrt( (-1.5 m//s^2)^2 + (0.5m//s^2)^2) = 1.6 m//s^2`<br/>( c) Its angle in the xz plane (measured from the +x axis is one of these <a href="https://interviewquestions.tuteehub.com/tag/possibilities-1160393" style="font-weight:bold;" target="_blank" title="Click to know more about POSSIBILITIES">POSSIBILITIES</a> :<br/>` tan^(-1) ( (0.5m//s^2)/(-1.5 m//s^2)) = - 18^@ or162^@`</body></html> | |
| 45221. |
A wooden toroidal core with a square cross section has an inner radius of 10 cm and an outer radius of 12 cm. It is wound with one layer of wire (of diameter 1.0 mm and resistance per meter 0.020 Omega /m). What are (a) the inductance and (b) the inductive time constant of the resulting toroid? Ignore the thickness of the insulation on the wire. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :(a) `2.9 xx 10^(-<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>) <a href="https://interviewquestions.tuteehub.com/tag/h-1014193" style="font-weight:bold;" target="_blank" title="Click to know more about H">H</a>, (<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>) 2.9 xx 10^(-4)`</body></html> | |
| 45222. |
Two long wires AB and CD carrly currents i_(1) and i_(2) in the directions shown |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/force-22342" style="font-weight:bold;" target="_blank" title="Click to know more about FORCE">FORCE</a> on <a href="https://interviewquestions.tuteehub.com/tag/wire-1457703" style="font-weight:bold;" target="_blank" title="Click to know more about WIRE">WIRE</a> <a href="https://interviewquestions.tuteehub.com/tag/ab-360636" style="font-weight:bold;" target="_blank" title="Click to know more about AB">AB</a> is <a href="https://interviewquestions.tuteehub.com/tag/towards-7269729" style="font-weight:bold;" target="_blank" title="Click to know more about TOWARDS">TOWARDS</a> left<br/>Force on wire AB is towards right<br/>Torque on wire AB is clockwise<br/>Torque on wire AB is anticlockwise</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a></body></html> | |
| 45223. |
Two solid sphere of copper have radii 10 cm and 8 cm respectively. Their temperature are 227^(@)C and 127^(@)C respectively they are allowed to cool by radiation in a room of temperature 27^(@)C then the initial rates of heat los are in the ratio |
| Answer» <html><body><p>`(85)/(14)`<br/>`(34)/(7)`<br/>`(7)/(34)`<br/>`(14)/(85)`</p>Solution :`(((<a href="https://interviewquestions.tuteehub.com/tag/dq-959213" style="font-weight:bold;" target="_blank" title="Click to know more about DQ">DQ</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/dt-960413" style="font-weight:bold;" target="_blank" title="Click to know more about DT">DT</a>))_(1))/(((dQ)/(dt))_(2))=(T_(1)^(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>))/(T_(2)^(4))=(<a href="https://interviewquestions.tuteehub.com/tag/625-330389" style="font-weight:bold;" target="_blank" title="Click to know more about 625">625</a>)/(256)=2.44`.</body></html> | |
| 45224. |
What do you mean by resonant frequency ? |
| Answer» <html><body><p></p>Solution :When the <a href="https://interviewquestions.tuteehub.com/tag/frequency-465761" style="font-weight:bold;" target="_blank" title="Click to know more about FREQUENCY">FREQUENCY</a> of the applied alternating source `(omega_(r))` id equal to the natural frequency `[(1)/(sqrt(<a href="https://interviewquestions.tuteehub.com/tag/lc-536651" style="font-weight:bold;" target="_blank" title="Click to know more about LC">LC</a>))]` of the RLC circuit, the <a href="https://interviewquestions.tuteehub.com/tag/current-940804" style="font-weight:bold;" target="_blank" title="Click to know more about CURRENT">CURRENT</a> in the circuit reaches its <a href="https://interviewquestions.tuteehub.com/tag/maximum-556915" style="font-weight:bold;" target="_blank" title="Click to know more about MAXIMUM">MAXIMUM</a> <a href="https://interviewquestions.tuteehub.com/tag/value-1442530" style="font-weight:bold;" target="_blank" title="Click to know more about VALUE">VALUE</a>. Then th4e circuit is said to be in electrical resonance. The frequency at which resonance takes place is called resonant frequency.</body></html> | |
| 45225. |
What is pair production? |
| Answer» <html><body><p></p>Solution :Pair production is the phenomenon of production of a pair of particles (<a href="https://interviewquestions.tuteehub.com/tag/particle-1147478" style="font-weight:bold;" target="_blank" title="Click to know more about PARTICLE">PARTICLE</a> +antiparticle), when a gamma ray passes close to the <a href="https://interviewquestions.tuteehub.com/tag/nucleus-18220" style="font-weight:bold;" target="_blank" title="Click to know more about NUCLEUS">NUCLEUS</a>. Thus energy is <a href="https://interviewquestions.tuteehub.com/tag/converted-2543437" style="font-weight:bold;" target="_blank" title="Click to know more about CONVERTED">CONVERTED</a> into <a href="https://interviewquestions.tuteehub.com/tag/matter-22749" style="font-weight:bold;" target="_blank" title="Click to know more about MATTER">MATTER</a> by this phenomenon.</body></html> | |
| 45226. |
The direction of electromagnetic wave is in the direction of |
| Answer» <html><body><p>(A) `(vec(E ))/(vec(B))`<br/>(B) `vec(E )<a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> vec(B)`<br/>(C) `vec(B)xx vec(E )`<br/>(D) `vec(B)`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/taking-1238585" style="font-weight:bold;" target="_blank" title="Click to know more about TAKING">TAKING</a> the direction in consideration in the phenomenon of <a href="https://interviewquestions.tuteehub.com/tag/propagation-607415" style="font-weight:bold;" target="_blank" title="Click to know more about PROPAGATION">PROPAGATION</a> of electromagnetic waves, `vec(E )_|_ vec(B)_|_ vec(v)` from the right hand screw rule.<br/>`vec(E )xx vec(B)_|_ vec(v)`<br/>`therefore` It becomes `vec(E )xx vec(B)= vec(v)`</body></html> | |
| 45227. |
The threshold wavelength for a metal surface whose photoelectric work function is 3.313 eV is…………………… |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/4125-1875654" style="font-weight:bold;" target="_blank" title="Click to know more about 4125">4125</a> Å<br/>3750 Å<br/>6000 Å<br/>2062.5 Å</p>Solution :`phi = hv_0 <a href="https://interviewquestions.tuteehub.com/tag/rarr-1175461" style="font-weight:bold;" target="_blank" title="Click to know more about RARR">RARR</a> phi = (<a href="https://interviewquestions.tuteehub.com/tag/hc-1016346" style="font-weight:bold;" target="_blank" title="Click to know more about HC">HC</a>)/(lambda_0)` <br/> `:.lambda_0 = (hc)/(phi) = (6.6 xx 10^(-34)xx 3 xx 10^8)/(3.313 xx 1.6 xx 10^(-19))=3.7352 xx 10^(-<a href="https://interviewquestions.tuteehub.com/tag/7-332378" style="font-weight:bold;" target="_blank" title="Click to know more about 7">7</a>)` <br/> `= 3.740 xx 10^(-7) rArr lambda_0 ~~ 3740 Å`</body></html> | |
| 45228. |
Three persons P, Q, R are at the three comers of an equilateral triangle of each side 1. They start moving simultaneously with velocity v such that Pathways moves towards Q Q always moves towards R and R always moves towards P. After what time they would meet each other at O? |
| Answer» <html><body><p>`a/v`<br/>`(2a)/(v)`<br/>`(2a)/(sqrt(3v))`<br/>`(2a)/(3v)`</p>Solution :The <a href="https://interviewquestions.tuteehub.com/tag/three-708969" style="font-weight:bold;" target="_blank" title="Click to know more about THREE">THREE</a> <a href="https://interviewquestions.tuteehub.com/tag/person-25481" style="font-weight:bold;" target="_blank" title="Click to know more about PERSON">PERSON</a> follow curvilinear <a href="https://interviewquestions.tuteehub.com/tag/path-11833" style="font-weight:bold;" target="_blank" title="Click to know more about PATH">PATH</a> to <a href="https://interviewquestions.tuteehub.com/tag/meet-1092928" style="font-weight:bold;" target="_blank" title="Click to know more about MEET">MEET</a> at the centroid `.O.` of the traingle <br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/MOD_RPA_OBJ_PHY_C02_E01_103_S01.png" width="80%"/> <br/> Velocity Component with which each moves =`v cos 30^(@)` <br/> `=(vsqrt(3))/(2)` <br/> =`(2a)/(3v)`</body></html> | |
| 45229. |
Assertion:Naturally , thermonuclear fusion reaction is not possible on earth. Reason : For thermonuclear fusion to take place, extreme condition of temperatureand pressure are required . |
| Answer» <html><body><p>If both assertion and reason are <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a> and reason is the correct <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> of assertion .<br/>If both assertion and reason are true but reason is notthe correct explanation of assertion . <br/>If assertion is true but reason is false . <br/>If both assertion and reason are false </p>Solution :For thermonuclear fusion to take place, <a href="https://interviewquestions.tuteehub.com/tag/extreme-981946" style="font-weight:bold;" target="_blank" title="Click to know more about EXTREME">EXTREME</a> conditions of temperature and pressure are required , which are available only in the <a href="https://interviewquestions.tuteehub.com/tag/interiors-1048316" style="font-weight:bold;" target="_blank" title="Click to know more about INTERIORS">INTERIORS</a> of stars including <a href="https://interviewquestions.tuteehub.com/tag/sun-1234558" style="font-weight:bold;" target="_blank" title="Click to know more about SUN">SUN</a>.</body></html> | |
| 45230. |
What is the total change in energy when a positive charge is taken round a closed loop in an electrical network ? |
| Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/zero-751093" style="font-weight:bold;" target="_blank" title="Click to know more about ZERO">ZERO</a>. This is <a href="https://interviewquestions.tuteehub.com/tag/kirchhoff-2147768" style="font-weight:bold;" target="_blank" title="Click to know more about KIRCHHOFF">KIRCHHOFF</a>'s <a href="https://interviewquestions.tuteehub.com/tag/voltage-1447811" style="font-weight:bold;" target="_blank" title="Click to know more about VOLTAGE">VOLTAGE</a> law or <a href="https://interviewquestions.tuteehub.com/tag/loop-1079198" style="font-weight:bold;" target="_blank" title="Click to know more about LOOP">LOOP</a> law.</body></html> | |
| 45231. |
For protecting a sensitive equipment from external magnetic field, it should be |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/placed-591674" style="font-weight:bold;" target="_blank" title="Click to know more about PLACED">PLACED</a> inside an <a href="https://interviewquestions.tuteehub.com/tag/aluminium-858823" style="font-weight:bold;" target="_blank" title="Click to know more about ALUMINIUM">ALUMINIUM</a> can<br/>wrapped with <a href="https://interviewquestions.tuteehub.com/tag/insulated-2741678" style="font-weight:bold;" target="_blank" title="Click to know more about INSULATED">INSULATED</a> <a href="https://interviewquestions.tuteehub.com/tag/wire-1457703" style="font-weight:bold;" target="_blank" title="Click to know more about WIRE">WIRE</a>, through which current is passed<br/>surrounded with fine copper gauge<br/>placed inside an <a href="https://interviewquestions.tuteehub.com/tag/iron-1051344" style="font-weight:bold;" target="_blank" title="Click to know more about IRON">IRON</a> can</p>Answer :D</body></html> | |
| 45232. |
(A): If a current flows through a wire of non uniform cross-section,potential difference per unit length of wire in direction of current is same at different points (R): ohms law V = iR is not valid for a wire of non-uniform cross-section |
| Answer» <html><body><p>Both 'A' and '<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>' are <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a> and 'R' is the correct <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> of 'A'<br/>Both 'A' and 'R' are true and 'R' is not the correct explanation of 'A'<br/>'A' is true and 'R' is <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a> <br/>'A' is false and 'R' is false </p>Answer :D</body></html> | |
| 45233. |
Fig. Shows a concavo-convex lens. What is the condition on the refractive indices so that the lens is diverging ? |
| Answer» <html><body><p>`2mu_3 <a href="https://interviewquestions.tuteehub.com/tag/lt-537906" style="font-weight:bold;" target="_blank" title="Click to know more about LT">LT</a> mu_1+ mu_2`<br/>`2mu_3 gt mu_1 + mu_2` <br/>`mu_3 gt <a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>(mu_1 - mu_2)`<br/><a href="https://interviewquestions.tuteehub.com/tag/none-580659" style="font-weight:bold;" target="_blank" title="Click to know more about NONE">NONE</a> of these</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 45234. |
In a large building, there are 15 bulbs of 40W, 5 bulbs of 100 W, 5 fans of 80 W and 1 heater of 1 kW. The voltage of the electric mains is 220 V. The minimum capacity of the main fuse of the building will be |
| Answer» <html><body><p>`8A`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a> A`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/12-269062" style="font-weight:bold;" target="_blank" title="Click to know more about 12">12</a> A`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/14-272882" style="font-weight:bold;" target="_blank" title="Click to know more about 14">14</a> A`</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 45235. |
Infrared radiations are detected by: |
| Answer» <html><body><p>Spectrometer<br/>Pyrometer<br/>Nanometer<br/>Platometer</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 45236. |
Two particles of masses m and 2m are placed on a smooth horizonttal table. A string, which joins these two masses, hangs over the edge supporting a pulley, which suspends a particle of mass 3m, as shown in Fig. 5-40. The pulley has negligible mass. The two parts of the string on the table are parallel and perpendicular to the edge of the table. The hanging parts of the string are vertical. Find the acceleration of the particle of mass 3m. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`5.<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>" m"//"s"^(2)`</body></html> | |
| 45237. |
A triangular wedge of mass M is moving with uniform velocity v_(0) along a smooth horizontal surface in the leftward direction. A particle of mass m falls from rest from height h onto the inclined face, colliding elastically with it. Find velocity of the ball and wedge after the impact taking M = 2m. |
| Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/line-1074199" style="font-weight:bold;" target="_blank" title="Click to know more about LINE">LINE</a> of impact is a <a href="https://interviewquestions.tuteehub.com/tag/straight-633156" style="font-weight:bold;" target="_blank" title="Click to know more about STRAIGHT">STRAIGHT</a> line perpendicular to the incline. Normal reaction force between the body and the wedge acts along the impact line. This normal force becomes internal force when we consider (wedge + body) as a total system. But normal reaction is considerable in <a href="https://interviewquestions.tuteehub.com/tag/magnitude-1083080" style="font-weight:bold;" target="_blank" title="Click to know more about MAGNITUDE">MAGNITUDE</a> because the impact force during collision has contribution towards making of the normal force. Momentum of the system is conserved along the line perpendicular to this normal force.....(i)<br/>Momentum of the system is conserved along horizontal.....(ii)<br/> Momentum of the particle is conserved along the common tangent at the point of impact......(iii)<br/> As this is an elastic collision, relative velocity of separation along the impact line = Relative velocity of approach......(<a href="https://interviewquestions.tuteehub.com/tag/iv-501699" style="font-weight:bold;" target="_blank" title="Click to know more about IV">IV</a>)<br/>If the wedge were at rest then the particle would deflect along the horizontal after collision because it is an elastic collision.....(v)<br/>As, in this case, wedge is moving, the <a href="https://interviewquestions.tuteehub.com/tag/object-11416" style="font-weight:bold;" target="_blank" title="Click to know more about OBJECT">OBJECT</a> would not be deflected horizontal, but at an angle `.alpha.` to the line of impact....(vi)<br/> Velocity of particle before impact `u=sqrt(2gh)` along `vec(PO)`<br/> Velocity of particle after collision `= v_(1)` along `vec(OQ)`<br/>Velocity of wedge before collision `= v_(0)` along `vec(RO)`<br/>Velocity of wedge after collision `= v_(2)` along `vec(RO)` <br/>Velocity of approach = velocity of separation<br/>`v_(0)cos 45^(@)-ucos 45^(@)=-v_(1)cos alpha - v_(2)cos 45^(@)`<br/>`rArr v_(1)cos alpha + (v_(2))/(sqrt(2))=(u)/(sqrt(2))-(v_(0))/(sqrt(2))`<br/>`sqrt(2)v_(1)cos alpha + v_(2)=u-v_(0) "" ....(A)`<br/> Conserving momentum along the horizontal<br/>`Mv_(0)=Mv_(2)-mv_(1)cos (45^(@)-alpha)`<br/>`rArr 2v_(0)=2v_(2)-v_(1)cos (45^(@)-alpha)`<br/>`rArr 2v_(2)-v_(1)cos(45^(@)-alpha)=2v_(0) ""`....(B) <br/>Conserving momentum along the common tangent<br/>`mu sin 45^(@)=mv_(1)sin alpha`<br/>`rArr v_(1)sin alpha = u ""`....(C )<br/> On solving (A), (B) and (C )<br/>`v_(1)=sqrt(u^(2)[(u(4-sqrt(2))-6v_(0))/(20)]^(2))` and `v_(2)=(v_(0)+(sqrt(2)+1)u)/(5)`<br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/FIITJEE_PHY_MB_01_C01_E01_018_S01.png" width="80%"/></body></html> | |
| 45238. |
A galvanometer having a coil of resistance 12 Ωgives full scale deflection for a current of 4 mA. How can it be converted into a voltmeter of range 0 to 24V. |
| Answer» <html><body><p></p>Solution :`G= <a href="https://interviewquestions.tuteehub.com/tag/12-269062" style="font-weight:bold;" target="_blank" title="Click to know more about 12">12</a> <a href="https://interviewquestions.tuteehub.com/tag/omega-585625" style="font-weight:bold;" target="_blank" title="Click to know more about OMEGA">OMEGA</a> I_(g) =4A ,V =24 V` <br/> `R=(I)/(I_(g))-G` <br/> =6000-12 <br/> =5988 <br/> R=5988 `omega`By <a href="https://interviewquestions.tuteehub.com/tag/connecting-929445" style="font-weight:bold;" target="_blank" title="Click to know more about CONNECTING">CONNECTING</a> this high resistance in <a href="https://interviewquestions.tuteehub.com/tag/series-1201802" style="font-weight:bold;" target="_blank" title="Click to know more about SERIES">SERIES</a> with the <a href="https://interviewquestions.tuteehub.com/tag/galvanometer-1003291" style="font-weight:bold;" target="_blank" title="Click to know more about GALVANOMETER">GALVANOMETER</a> we can convert galvanometer into a voltmeter.</body></html> | |
| 45239. |
A stretched string has a mass per unit length of 5.00 g/cm and a tension of 10.0 N A sinusoidal wave on this string has an amplitude of 0.16 mm and a frequency of 100 Hz and is traveling in the negative direction of an x axis. If the wave equation is of the form y(x,t)= y_m sin(kx pm omegat), what are (a) y_m (b) k. (c) omega, and (d) the correct choice of sign in front of omega? |
| Answer» <html><body><p><br/></p>Answer :(a) 1mm; (b) `<a href="https://interviewquestions.tuteehub.com/tag/141-273556" style="font-weight:bold;" target="_blank" title="Click to know more about 141">141</a> m^(-1)`; (c) 628 rad/s; (d) <a href="https://interviewquestions.tuteehub.com/tag/plus-591752" style="font-weight:bold;" target="_blank" title="Click to know more about PLUS">PLUS</a> sign in used <a href="https://interviewquestions.tuteehub.com/tag/since-644476" style="font-weight:bold;" target="_blank" title="Click to know more about SINCE">SINCE</a> the wave is <a href="https://interviewquestions.tuteehub.com/tag/traveling-3230325" style="font-weight:bold;" target="_blank" title="Click to know more about TRAVELING">TRAVELING</a> in the negative x direction</body></html> | |
| 45240. |
Which of the following is regarding mutual inductance? |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/unit-1438166" style="font-weight:bold;" target="_blank" title="Click to know more about UNIT">UNIT</a> of M is henry<br/>unit of M is `Wb//ampere^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>`[M]=[<a href="https://interviewquestions.tuteehub.com/tag/ml-548251" style="font-weight:bold;" target="_blank" title="Click to know more about ML">ML</a>^(2)T^(-2)A^(-2)]`<br/>both (A) and (<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>)</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 45241. |
A heat conducting piston can move freely inside a closed, thermally insulated cylinder with an ideal gas (gamma= 5/3). At equilibrium, the piston divides the cylinder into two equal parts, the gas temperature being equal to 300 K. The piston is slowly displaced by an external agent. Find the gas temperature when the volume of the greater section is seven times the volume of the smaller section. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/395-310437" style="font-weight:bold;" target="_blank" title="Click to know more about 395">395</a> <a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a></body></html> | |
| 45242. |
Two gases O_2 and H_2 are at the same temperature . If E_o is the average kinetic energy of a molecule of oxygen sample , and E_H is the average kinetic energy of a molecule of hydrogen sample , then |
| Answer» <html><body><p>`E_o=1/16E_H`<br/>`E_o=16E_H`<br/>`E_o <a href="https://interviewquestions.tuteehub.com/tag/gt-1013864" style="font-weight:bold;" target="_blank" title="Click to know more about GT">GT</a> E_H`<br/>`E_o=E_H`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 45243. |
An electron and a photon each have a wavelength of 1.00 nm. Find (a) their momenta, (b) the energy of the photon, and (c) the kinetic energy of electron. |
| Answer» <html><body><p></p>Solution :Here `lamda=1.00nm=1.00xx10^(-9)m` <br/> (a) Momentum of electron momentum of photon `p=(h)/(lamda)=(6.63xx10^(-34))/(1.00xx10^(-9))=6.63xx10^(-25)<a href="https://interviewquestions.tuteehub.com/tag/kg-1063886" style="font-weight:bold;" target="_blank" title="Click to know more about KG">KG</a>" "<a href="https://interviewquestions.tuteehub.com/tag/ms-549331" style="font-weight:bold;" target="_blank" title="Click to know more about MS">MS</a>^(-1)`. <br/> (<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>) Energy of photon `E=(<a href="https://interviewquestions.tuteehub.com/tag/hc-1016346" style="font-weight:bold;" target="_blank" title="Click to know more about HC">HC</a>)/(lamda)p*c=6.63xx10^(-25)xx3xx10^(<a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a>)=1.989xx10^(-16)J` <br/> `=(1.989xx10^(-16))/(1.6xx10^(-19))eV=1.24xx10^(3)eV or 1.24keV`. <br/> (c) Kinetic energy of electron `K=(p^(2))/(2m)=((6.63xx10^(-25))^(2))/(2xx9.11xx10^(-31))=2.413xx10^(-19)J` <br/> `=(2.413xx10^(-19))/(1.6xx10^(-19))eV=1.51eV`.</body></html> | |
| 45244. |
The penetrating powers of alpha and betaand radiations, in decreasing order, are |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/gamma-470142" style="font-weight:bold;" target="_blank" title="Click to know more about GAMMA">GAMMA</a>, <a href="https://interviewquestions.tuteehub.com/tag/alpha-858274" style="font-weight:bold;" target="_blank" title="Click to know more about ALPHA">ALPHA</a> , <a href="https://interviewquestions.tuteehub.com/tag/beta-2557" style="font-weight:bold;" target="_blank" title="Click to know more about BETA">BETA</a>` <br/>`gamma , beta , alpha` <br/>`alpha, beta , gamma` <br/>`beta , gamma, alpha` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 45245. |
In a two dimensional x – y plane, the magnetic field lines are circular, centred at the origin. The magnitude of the field is inversely proportional to distance from the origin and field at any point P has magnitude given by B = k /r, where k is a positive constant. A wire carrying current I is laid in xy plane with its ends at point A (x_(1), y_(1) and point B (x_(2)), y_(2)). Find force on the wire. |
| Answer» <html><body><p><br/></p>Answer :`<a href="https://interviewquestions.tuteehub.com/tag/vec-723433" style="font-weight:bold;" target="_blank" title="Click to know more about VEC">VEC</a>(<a href="https://interviewquestions.tuteehub.com/tag/f-455800" style="font-weight:bold;" target="_blank" title="Click to know more about F">F</a>)=(kl)/<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> l n(x_(2)^(2)+y_(2)^(2)/x_(1)^(2)+y_(1)^(2)) <a href="https://interviewquestions.tuteehub.com/tag/hat-1016178" style="font-weight:bold;" target="_blank" title="Click to know more about HAT">HAT</a>(k)`</body></html> | |
| 45246. |
Resistivity of material does not depend on ...... of conductor |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/temperature-11887" style="font-weight:bold;" target="_blank" title="Click to know more about TEMPERATURE">TEMPERATURE</a> <br/>pressure<br/>dimensions<br/>type of <a href="https://interviewquestions.tuteehub.com/tag/material-1089170" style="font-weight:bold;" target="_blank" title="Click to know more about MATERIAL">MATERIAL</a> </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 45247. |
Two bulbs are rated (P_1, V)"and"(P_2, V) . If they are connected (i) in series and (ii) in parallel across a supply V, find the power dissipated in the two combinations in terms of P_1 and P_2. |
| Answer» <html><body><p></p>Solution :Resistance of given bulbs are `R_1 = (V^2)/(P_1) " and " R_2 = (V^2)/(P_2)` <br/> (i) In series grouping net resistance `R_s = R_1 + R_2`. If `P_s` be the power dissipated in series arrangement then `R_s = (V^2)/(P_s)` <br/>`rArr (V^2)/(P_s) = (V^2)/(P_1) + (V^2)/(P_2) rArr (1)/(P_s) = (1)/(P_1) + (1)/(P_2) rArr P_s = (P_1 P_2)/(P_1 + P_2)`<br/>(<a href="https://interviewquestions.tuteehub.com/tag/ii-1036832" style="font-weight:bold;" target="_blank" title="Click to know more about II">II</a>) In <a href="https://interviewquestions.tuteehub.com/tag/parallel-1146369" style="font-weight:bold;" target="_blank" title="Click to know more about PARALLEL">PARALLEL</a> grouping <a href="https://interviewquestions.tuteehub.com/tag/equivalent-446407" style="font-weight:bold;" target="_blank" title="Click to know more about EQUIVALENT">EQUIVALENT</a> resistance `R_P = (V^2)/(P_P)` is given as <a href="https://interviewquestions.tuteehub.com/tag/per-590802" style="font-weight:bold;" target="_blank" title="Click to know more about PER">PER</a> relation :<br/>`(1)/(R_P) = (1)/(R_1) + (1)/(R_2) rArr (P_P)/(V^2) = (P_1)/(V^2) + (P_2)/(V^2) rArr P_P = P_1 + P_2`</body></html> | |
| 45248. |
Complete the following statement about photo electric effect. The radiations having minimum frequency called............... falls on a metallic surcace, electrons are emitted from it. The metal which emits photoelec trons are called........... The kinetic energy of pho toelectrons emitted by a metal depends on of.......... the radiations. |
| Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/threshold-1419373" style="font-weight:bold;" target="_blank" title="Click to know more about THRESHOLD">THRESHOLD</a> <a href="https://interviewquestions.tuteehub.com/tag/frequency-465761" style="font-weight:bold;" target="_blank" title="Click to know more about FREQUENCY">FREQUENCY</a>, <a href="https://interviewquestions.tuteehub.com/tag/photosensitive-2221004" style="font-weight:bold;" target="_blank" title="Click to know more about PHOTOSENSITIVE">PHOTOSENSITIVE</a> frequency <a href="https://interviewquestions.tuteehub.com/tag/number-582134" style="font-weight:bold;" target="_blank" title="Click to know more about NUMBER">NUMBER</a> of photons</body></html> | |
| 45249. |
Moving particles of matter should display wavelike properties under suitable conditions. A photon and electron have got the same wavelength. Explain which has got greater energy? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Energy of <a href="https://interviewquestions.tuteehub.com/tag/photon-599910" style="font-weight:bold;" target="_blank" title="Click to know more about PHOTON">PHOTON</a> `E_1=<a href="https://interviewquestions.tuteehub.com/tag/hv-1033771" style="font-weight:bold;" target="_blank" title="Click to know more about HV">HV</a>=(hv)/lambda` Energy of electron `E_2=mc^2=(hc^2)/(lambdav^2 ` i.e`E_2>E_1` or electron has greater energy</body></html> | |
| 45250. |
The length of the antenna (a) limits the frequency of EM waves to be radiated (b) makes the users to opt for Higher frequency transmission © is insignificant during transmission. |
| Answer» <html><body><p>a & b are true<br/>b & <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> are true<br/>c & a are true<br/>a, b & c are true</p>Answer :A</body></html> | |