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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1251. |
Newton's III law is applicable_________. |
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Answer» for a BODY is at rest |
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| 1252. |
Answer question numbers (a) - (d) on the basis of your understanding of the following paragraph and the related studied concepts : India today is facing the problem of overuse of resources, contamination of water and soil and lack of methods of processing the waste. The time has come for the world to say goodbye to "single-use plastics". Steps must be undertaken to develope environment-friendly substitutes, effective plastic waste collection and methods of its disposal. Indore treated 15 lakh metric tonnes of waste in just 3 years, through biomining and bioremediation, techniques. Bioremediation involves introducing microbes into a landfill to naturally 'break' it down and biomining involves using trommel machines to sift through the waste to separate the soil and the waste component. The city managed to chip away 15 lakh metric tonnes of waste at a cost of around Rs. 10 crore. A similar experiment was successfully carries out in Ahmedabad also. Do you think microbes will work similarly in landfill sites as they work in the laboratory ? Justify your answer. |
| Answer» Solution :As is the case in Indore CITY, the MICROBES can WORK in landfill SITES just as WELL as in laboratory conditions by substantiating it with biomining. | |
| 1253. |
............. in the Chairman of the State disaster management authority |
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Answer» |
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| 1254. |
The valueof universal gravitational constituent is _____________ |
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Answer» `6.743 xx 10^(-11) Nm^(2) KG^(-1)` |
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| 1255. |
Which of the following quantity remains constant in a uniform circular motion: (a) velocity (b) speed (c) acceleration (d) both velocity and speed |
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Answer» VELOCITY |
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| 1256. |
Social health is the ability of a person to establish ……….with other persons. |
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Answer» |
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| 1258. |
The human eye forms the image of an object at its………. . |
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Answer» cornea |
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| 1259. |
Shilpa is using spectacles. Is she eligible to pledge to donate her eyes ? Why ? |
| Answer» Solution :YES. Allthough SHILPA is using spectacles, the cornes of her eye is WORKING properly and hence she can donate her eye cornes. | |
| 1260. |
How do you demonstrate the formation of compression and rarefactions in a slinky? |
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Answer» Solution :1) Take a slinky. 2) It is a spring SHAPED toy which can be extrnded or compressed very easily. 3) Lay it down on a table or the floor as shown in figure. 4) Ask a FRIEND to hold one end. 5) Pull the other end to stretch the slinky and then move it to and fro along its LENGTH. 6) We will see alternate compressions and rarefactions of the coil. 7) This is SIMILAR to the pattern of varying density produced in a medium when sound passes through it.  .
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| 1261. |
How is the vision of a person having cataract restored ? |
| Answer» SOLUTION :By CATARACT SURGERY. | |
| 1262. |
Explain why a tank filled with water or swimming pool looks shallower. Explain with the help of a ray diagram. |
Answer» Solution :To an observer, a swimming pool or a tank filled with water APPEARS shallower due to the phenomenon of refraction of light. The bottom of the pool or the tank appears to be raised. TWO light rays starting from the edge of the object (O) kept at the bottom of the pool gets refracted at the water - air interface. The light rays move from a denser (water) to a rarer medium (air), hence they bend AWAY from the normal. On externding the diverging rays, they APPEAR to meet at point 1 to form the IMAGE which is virtual and appear to be raised. The distance of the object from the surface of water is called the Real depth and the distance of the image from the water surface is called Apparent depth. Apparent depth is less than the real depth. Therefore the bottom floor of the pool or an object at the floor of the pool appears to be raised.
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| 1263. |
Two plane mirrors subtend an angle theta . Light incident on one mirror after reflection from the other mirror returns parallel to the original direction. The angle thetamust be |
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Answer» `30^@ ` |
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| 1265. |
Twinkling of stars happens because of which of these? |
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Answer» Refraction |
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| 1266. |
What does an electric circuit mean? |
| Answer» Solution :An electric circuit is a continuous and closed path for flow of an electric CURRENT. If the electric current is complete, electric current can flow through the circuit. IF the circuit is broken anywhere or SWITCH of the circuit is TURNED off, the current STOPS FLOWING. | |
| 1267. |
In a house, if three bulbs of lOOW, 60W and 40W respectively are used 2 hours per day, how many units of electrical energy will be consumed in 30 days? |
| Answer» SOLUTION :12 UNITS | |
| 1268. |
(i)A solution is prepared by dissolving 15g of NaCl in 85 g of water. Calculate the mass percentage of solute. (ii) Calculate the p_(H) of 0.001 M NaOH. |
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Answer» Solution :(i) MASS of solute=15g Mass of solvent=85g Mass percentage`=("Mass of the solute")/("Mass of the solution")xx100` `=(15)/(15+85)xx100=(15)/(100)xx100=15%` (II) `[OH^(-)]=`Normality=Molarity`xx`ACIDITY `=0.001xx1=1xx10^(-3)` `pOH=-log_(10)[OH^(-)]` `=-log_(10)^(1)xx[10^(-3)]` `=-log_(10)^(1)xxlog_(10)10^(-3)` `=0-(-3log_(10)^(10))` `pOH=3` `pH=pOH=14` `pH=14-pOH=14-3` `pH=11` (iii) `n=0.01` mole, `mu=18g" "mol^(-1),W=?` `W=nxxM` `=0.01xx18=0.18g` |
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| 1269. |
(i) Explain the sign conventions of lenses. (ii) Define dispersion of light. |
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Answer» SOLUTION :(i) (a) The object is always placed on the left side of the lens. (b) All the distances are measured from the OPTICAL centre of the lens. (c) The distances measured in the same direction as that of incident light are taken as POSITIVE. (d) The distances measured against the direction of incident light are taken as negative. (e) The distances measured upward and perpendicular to the principal axis is taken as positive. (f). The distances measured downward and perpendicular to the principal axis is taken as negative. (ii) When a beam of white light or composite light is refracted through any transparent media such as glass or water, it is split into its component COLOURS. This phenomenon is called as DISPERSION of light. |
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| 1270. |
Light enters from air to glass having refractive index 1.50. What is the speed of light in the glass? The speed of the light in vacuum is 3xx10^(8)ms^(-1). |
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Answer» Solution :`n_(g)=1.5` `C=3XX10^(8)m//s` `n_(g)=v/(v_(g))` `v_(v)=c/(n_(g))=(3xx10^(8))/1.5=2xx10^(8)`m/s Speed of LIGHT m glass in `2xx10^(8)` m/s |
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| 1271. |
A microscopic gap between a pair of adjacent neurons over which the nerve impulses pass is called : |
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Answer» Neutrotransmitter |
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| 1272. |
If mass of a planet is eight times the mass of the earth and its radius is twice the radius of the earth, what will be the escape velocity for that planet? |
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Answer» Solution :Given : Mass of the PLANET `(M_1)` = 8 x Mass of the earth `(M_2)` Radius of the planet `(R_1)` = 2 x Radius of the earth `(R_2)` To find : Escape VELOCITY`(v_"esc")` of the planet Formula : `v_"esc"=SQRT((2GM)/R)` Solution: Mass of earth = `6xx10^24` KG and Radius of the earth `=6.4xx10^6` m , G=Gravitational constant = `6.67xx10^(-11) Nm^2//kg^2` `therefore` Mass of the planet = `8xx6xx10^24` kg `therefore` Radius of the planet = `2xx6.4xx10^6` m `v_"esc"=sqrt((2GM_1)/R_1)=sqrt((2xx6.67xx10^(-11)xx8xx6xx10^24)/(2xx6.4xx10^6))` `=2xx11.18xx10^3` `=22.4xx10^3` =22.4 km/s `(because sqrt((2xx6.67xx10^(-11)xx8xx6xx10^24)/(2xx6.4xx10^6))=11.18xx10^3)` The escape velocity of the planet is 22.4 km/s |
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| 1273. |
Deduce an expression to measure electrc power. |
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Answer» Solution :1. Consider that a charge (Q) COULOMB passes through a POINT A. moves to point B in time interval 't' seconds. 2. Let V be the potential DIFFERENCE between the points A and B. 3. The work done by electric field in time 't' is given by W = QV-(1) 4. The work is equal to the energy lost by the charge while passing through the conductor for time 't'. 5. Energy lost by the conductor in `sec = (W)/(t).` From (1), `(W)/(t)=(QV)/(t)-(2)` We know, `(Q)/(t)=Iand(W)/(t)=P("Power")` Then `(2)rArrP=VI-(3)` This equation can be used to calculate power consumption by any electric devie that is connected in a CIRCUIT. From Ohm's law V = I R `therefore(3)rArrPI^(2)R. (or)(V^(2))/(R)-(4)` 6. To know the power that can be extracted from BATTERY or any source can be calculated by `P=epsilonI.` Whose `epsilon` is the emf of the battery or source. 
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| 1274. |
The velocity time graph for a particle is shown in figure. Draw acceleration time graph from it. |
Answer» SOLUTION :
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| 1275. |
The magnetic effect of electric current was discovered by________ . |
| Answer» SOLUTION :H.C. OERSTED | |
| 1276. |
Two wires X and Y are of equal length and have equal resistances. If the resistivity of X is more than that of Y which wire is thicker and why ? For the electric circuit given below calculate : (i) Current in each resistor (ii) Total current drawn from the battery and (iii) Equivalent resistance of circuit |
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Answer» Solution :V= IR wire A is thicker (i) for `30 Omega I = (6)/(30)= (1)/(5) ` AMPERE or 0.2 Afor `10 OMEGA1 = (6)/(10) = 0.6 ` Ampere for `5 Omega I = (6)/(5) = 1.2 ` Ampere (ii) `(1)/(R) = (1)/(30) +(1)/(10)+(1)/(5) =(1)/(3) implies R = 3 Omega` `V= IR implies I =(V)/(R) = (6)/(3) = 2 ` Ampere (III) Equivalent Resistance = `3 Omega` |
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| 1277. |
If a sillicon solar cell of dimension 1 cm^(2) generates current of about 30 mA and potential difference of about 0.5 V. Find the current and potential difference generated bya sillicon solar cell of dimension 1000 cm^(2). |
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Answer» Solution :For a SILICON solar cell of dimension 1000 `CM^(2)` Current generated `=30mA//c^(2)x1000cm^(2)` =30000 mA=30 A Since POTENTIAL difference available from a solar cell is independent of its area, Potential difference generated =0.5 V. |
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| 1278. |
What is meant by power of a lens ? Write its Sl unit. A student uses a lens of focal length 40 cm and another of - 20 cm. Write the nature and power of each lens. |
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Answer» Solution :The degree of convergence or DIVERGENCE of a lens is called the power of a lens (P). OR Power of a lens is DEFINED as the reciprocal of focal LENGTH of a lens. Power of lens (P) `=(l)/("Focal length of the lens in metre (f)")` `P=(l)/(f)` The SI unit of power of lens is expressed in dioptre (D). `{:("Lens 1","Lens 2"),(f=+40 cm=+0.40 m,f=-20cm=-0.2m),(P=(l)/(f)=(1)/(0.4)=+2.5 D,P=(l)/(f)=(1)/(0.2)=+5D),("It is a CONVEX lens, converges incident light.","It is a concave lens, diverges incident light."):}` |
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| 1279. |
5cm high object is placed at a distance of 25 cm from a converging lens of focal length of 10 cm. Determine the position, size and type of the image. |
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Answer» Solution :Given: `h_(1) = 5 CM` U = 25 cm f = 10 cm (Converging LENS) To find: Position, size and type of image Solution :`1/V - 1/u = 1/f ` `1/v - 1/-25 =1/10` `1/v + 1/25 = 1/10` = `1/10 - 1/25` `(1/Y)/V = (5-2)/(50)` `1/v = 3/50` v = `50/3 ` `therefore`V = 16.7 cm `v/u = (h_(2))/(h_(1))` `(50/3)/25= (h_(2))/5` `50/3 xx 5/25 = h_2` |
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| 1280. |
In the circuits A, B, C and D, with switch S open, the lamps Q and R would light up but not lamp P in : |
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Answer» CIRCUIT A |
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| 1281. |
The saturatedhydrocarbon fromthefollowingcarboncompounds is ______. |
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Answer» Ethene |
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| 1282. |
(a) What is the source of energy of this sun and other stars ? (b) Describe the working of a hydrogen bomb.(c ) What is common between the sun and a hydrogen bomb ? |
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Answer» |
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| 1283. |
A given ray of light suffers minimum deviation in an equilateral prism P. Additional prisms Q and R of identical shape and of same material as P are now added as shown in figure. The ray will now suffer |
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Answer» no DEVIATION |
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| 1284. |
Who discoveredelectromagneticinduction ? |
| Answer» SOLUTION :Faraday | |
| 1285. |
Observer the garbage vans of grampanchayat and municipality . Nowadays , there is facility of decreasing the volume of garbage by compaction in those vans . Explain the advantages of this activity . |
| Answer» SOLUTION :When the garbage is COMPRESSED , its volume is reduced . The trips of the vans that pick-up the garbage can be reduced due to such measures . The land filling SITES can ALSO accommodate more garbage if it is compacted . | |
| 1286. |
Themagneticfieldproduced by a straight conducting wireon passingthe currentthrough it is …… |
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Answer» in THEDIRECTION of the CURRENT |
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| 1287. |
Two resistances of 100 Ωand zero ohm are connected in parallel. The overall resistance will be |
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Answer» 100 Ω |
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| 1288. |
If a pendulum is allowed to oscillate in vacuum, its time period will |
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Answer» decrease |
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| 1289. |
What are resolution and resolving power? |
| Answer» SOLUTION :In brain, the cortex is extremely FOLDED forming elevation called GYRI with DEPRESSION between them termed as sulci that increase its SURFACE area. | |
| 1290. |
Which of the following will produce more energy in a short time? |
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Answer» NUCLEAR fission |
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| 1292. |
Frequency is the most fundamental . Why is heavy water used as amoderator ? |
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Answer» Solution :(i) Heavy water is water highly enriched in the HYDROGEN isotope deuterium. (ii) We can compare the neutron interactions with billiard ball collision. Where neutron collides with nucleus of other atoms & LOSE energy. If the colliding nucleus size is small like hydrogen nucleus it will lose MAXIMUM energy. If nucleus is heavy the neutron hits the nucleus just changes is direction but not that much change in the energy of neutron. (ii) So we USE heavy water as MODERATOR to slow down neutrons. |
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| 1293. |
A wire of given length is doubled on itself and this process is repeated once again. By what factor does the resistance of the wire change? |
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Answer» Solution :As the length of the wire become `1/4`of the ORIGINAL length its area of cross-section become 4 times. So, NEW resistance `R.RHO (l.)/(A.) = rho ((1 //4))/(4A) = 1/(4 xx4) (rho 1/A) = R/16 ( :. R = rho l/A)` Thus, the new resistance is `1/16` of the original resistance. |
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| 1294. |
You are given kerosene. turpentine water in which of these does the light |
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Answer» SOLUTION :Use the information given In water light travels faster as compared to KEROSENE and TURPENTINE because the refractive INDEX of water is lower than that of kerosene and turpentine. The SPEED of light is inversely proportional to the refractive index. |
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| 1295. |
An object is placed at distance of 25cm from a spherical mirros & its image is formed behind the mirror at distance of 5cm. Find focal length ? Is it concave or convex mirror? |
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Answer» SOLUTION :Here u=-25cm , v=5cm from the MIRROR formula 1/f=1/u +1/v Then 1/f=-1/25+1/5=4/25 F=6.25cm as the FOCAL length is positive the mirror is CONVEX in nature. |
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| 1296. |
Name the instrument used for measuring : (i) Potential difference (ii) Current |
| Answer» SOLUTION :(i) VOLTMETER(II) AMMETER . | |
| 1297. |
____________ of a lens is a point situated on its principal axis, a ray of light passing through which goes straight without any deviation. |
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Answer» |
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| 1298. |
Get information. Mkeet the medical officer/ doctor from your village and collect information about providin the first aid. |
| Answer» SOLUTION :Students are EXPECTED to COLLECT more INFORMATION from MEDICAL officers or doctors. | |
| 1299. |
How does a solenoid behave like a magnet ? Can you determine the north and south poles of a current carrying solenoid with the help of a bar magnet ? Explain. |
Answer» Solution :A solenoid is a long coil of CIRCULAR loops of insulated COPPER wire, magnetic field lines are produced around the solenoid when a current is allowed to flow through it. The field lines produced in a current carrying solenoid is shown in the following figure.  In the above figure, when the north pole of a bar magnet is brought NEAR the end connected to the negative terminal of the battery, the solenoid repels the bar magnet, since like POLES repel each other, the end connected to the nagative terminal of the battery behaves as the north pole of the solenoid and other end behaves as a south pole. Hence, ONE end of the solenoid behaves as a north pole and the other end behaves as a south pole. |
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| 1300. |
What does an electric circuit mean ? Name a device that helps to maintain a potential difference acrou a conductor in a clrcuit. When do we say that the potential difference across a conductor is 1 volt ? Calcu1tte the amount of work done in shifting a charge of 2 coulombs from a point A to B having potentials 110 V and 25 V respectively. |
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Answer» SOLUTION :Electric circuit : The closed path ALONG which an electric current flows is called an .electric circuit.. The device that help& to maintain a POTENTIAL difference across a conductor in a circuit are- Electric cell, e.lecbic battery, electric generator 1 Volt: The potential difference between two points in an electric field is said to be ONE volt if one joule of work has to be done in bringing a positive charge of one coulomb from one POINT to another. `1 volt = (1 "joule")/(1 "Coulomb") or 1 V = (1 J)/(1 C)` Work done = V ( Potential difference ) `xx` Q (Coulombs) `W = VxxQ ` `= 85 xx2` =170 Joule . |
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