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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
36201. |
A freely falling body travels _ _ of total distance in 5^(th) second |
Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a>%`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/12-269062" style="font-weight:bold;" target="_blank" title="Click to know more about 12">12</a>%`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/25-296426" style="font-weight:bold;" target="_blank" title="Click to know more about 25">25</a>%`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/36-309156" style="font-weight:bold;" target="_blank" title="Click to know more about 36">36</a>%`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
36202. |
An extensible string is wound over a rough pulley of mass M_(1) and radius R and a cylinder of mass M_(2) and radius R such that as the cylinder rolls down. The string unwounds over the pulley as well the cylinder. Findthe acceleration of cylinder M_(2). |
Answer» <html><body><p></p>Solution :Through this illustration we will learn the application of torque equation and <a href="https://interviewquestions.tuteehub.com/tag/constraint-930945" style="font-weight:bold;" target="_blank" title="Click to know more about CONSTRAINT">CONSTRAINT</a> relation in more complex case here. We have change the block with cylinder `M_(2)` Pulley `M_(1)` will have oly pure rotation while cylinder `M_(2)` will have rotatioin and translation combined. Let us analyse step by step in the same way as the previous illustration. <br/> Step I: Analyse the motion of the pulley and the cyinder. Pulley: One <a href="https://interviewquestions.tuteehub.com/tag/rotational-625601" style="font-weight:bold;" target="_blank" title="Click to know more about ROTATIONAL">ROTATIONAL</a> acceleration `alpha_(1)` (clockwise) <br/> Cylinder: One rotational acceleration `alpha_(2)` (clockwise) andn a linear acceleration `a_(2)` (downward) <br/> Step II: Equation of motion for `M_(2)` <br/> `M_(2)g-T=M_(2)a_(2)` ..........i <br/> Step III: Torque equation for pulley `tau_(c)=I_(c)alpha` <br/> `TR=((M_(1)R^(2))/2)alpha_(1)implies(2T)/(M_(1)R)`.......ii <br/> Torquue equation for the cylinder (about centre of mass of cylinder `tau_(c)=I_(c)alpha` <br/> `implies TR=((M_(2)R^(2))/2)alpha_(2)` <br/> `alpha_(2)=(2T)/(M_(2)R)`.........iii <br/> Step IV: The acceleration of `P` and `Q` should be equal as both are connected with the same <a href="https://interviewquestions.tuteehub.com/tag/inextensible-2736845" style="font-weight:bold;" target="_blank" title="Click to know more about INEXTENSIBLE">INEXTENSIBLE</a> string ltbr. Accceleration of `P, a_(M)=alpha_(1)R` (downward) .........iv <br/> Acceleration of `Q, a_(N)=a_(2)-alpha_(2)R` (downwards) .............. v <br/> Hence, constraint relation `alpha_(1)R=a_(2)-alpha_(2)R` .............vi<br/> Step V: Solving equations <br/> After solving eqn i, ii, iii and iv, we <a href="https://interviewquestions.tuteehub.com/tag/get-11812" style="font-weight:bold;" target="_blank" title="Click to know more about GET">GET</a><br/> ` a_(2)=[((2M_(1)+M_(2)))/(3M_(1)+2M_(2))]g`</body></html> | |
36203. |
The time period of polalr satellite is almost [April - 2015) |
Answer» <html><body><p>100 <a href="https://interviewquestions.tuteehub.com/tag/days-944904" style="font-weight:bold;" target="_blank" title="Click to know more about DAYS">DAYS</a> <br/>100 <a href="https://interviewquestions.tuteehub.com/tag/minutes-1098164" style="font-weight:bold;" target="_blank" title="Click to know more about MINUTES">MINUTES</a> <br/>100 <a href="https://interviewquestions.tuteehub.com/tag/hours-1030090" style="font-weight:bold;" target="_blank" title="Click to know more about HOURS">HOURS</a> <br/>100 <a href="https://interviewquestions.tuteehub.com/tag/seconds-1198593" style="font-weight:bold;" target="_blank" title="Click to know more about SECONDS">SECONDS</a> </p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
36204. |
A body of mass 0.5 kg travels in a straight line with velocity v = ax^(3/2) "where " a=5m^(-1/2)s^(-1) . What is the work done by the net force during its displacement from x = 0 to x = 2 m ? |
Answer» <html><body><p></p>Solution :If a body <a href="https://interviewquestions.tuteehub.com/tag/undergoes-1436539" style="font-weight:bold;" target="_blank" title="Click to know more about UNDERGOES">UNDERGOES</a> displacement dx, then work done by the <a href="https://interviewquestions.tuteehub.com/tag/force-22342" style="font-weight:bold;" target="_blank" title="Click to know more about FORCE">FORCE</a> W = ma dx . <br/> ` :. W = m (dv)/(dt) .dx `<br/> `= m (dx)/(dt) .dv ` <br/> = mv dv<br/> ` :. W = int dW = m int_(<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>)^(2) " v dv" =1/2 mv^(2)`<br/> ` = 1/2 m (ax^(3/2))_(0)^(2)` <br/> ` = 1/2 "ma"^(2)<a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a>^(3)` <br/> ` = 1/2 xx 1/2 xx(5)^(2) xx(2)^(3)` <br/> = 50 <a href="https://interviewquestions.tuteehub.com/tag/j-520843" style="font-weight:bold;" target="_blank" title="Click to know more about J">J</a></body></html> | |
36205. |
A great physicist of this century (P.A.M. Dirac) loved playing with numerical values of Fundamental constants of nature. This led him to an interesting observation. Dirac found that from the basic constants of atomic physics(c,e, mass of electron, mass of proton) and the gravitational constant G, he could arrive at a number with the dimension of time. Further, it was a very large number, its magnitude being close to the present estimate on the age of the universe (~15 billion years). From the table of fundamental constants in this book, try to see if you too can construct this number (or any other interesting number you can think of ). If its coincidence with the age of the universe were significant , what would this imply for the constancy of fundamental constants ? |
Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>></p>Solution :Some <a href="https://interviewquestions.tuteehub.com/tag/constants-20556" style="font-weight:bold;" target="_blank" title="Click to know more about CONSTANTS">CONSTANTS</a> of nuclear physics, <br/> charge of electron `e=1.6xx10^(-19)C` <br/> Light of speed in free <a href="https://interviewquestions.tuteehub.com/tag/space-649515" style="font-weight:bold;" target="_blank" title="Click to know more about SPACE">SPACE</a> `c=3xx10^(8)ms^(-1)` <br/>Universal Gravitation constant <br/> `G=6.67xx10^(11)Nm^(2)kg^(-2)` <br/> Mass of electron `m_(e)=9.1xx10^(-31)kg` <br/> Mass of <a href="https://interviewquestions.tuteehub.com/tag/proton-1170983" style="font-weight:bold;" target="_blank" title="Click to know more about PROTON">PROTON</a> `m_(p)=1.67xx10^(-27)kg` <br/> Permitivity in free space <br/> `in_(0)=8.85xx10^(-12)Nm^(2)C^(-2)` <br/> A physical quantity x is obtained of dimension of time by using these constants. <br/> where `x=(e^(4))/(16pi^(2)in_(0)^(2)m_(p)m_(e)^(2)c^(3)G)` <br/> By writing <a href="https://interviewquestions.tuteehub.com/tag/dimensions-439808" style="font-weight:bold;" target="_blank" title="Click to know more about DIMENSIONS">DIMENSIONS</a> on both sides, <br/> `[x]=([AT]^(4))/([M^(-1)L^(-3)T^(4)A^(2)][M.]^(2)xx[L^(1)T^(-1)]^(3)xx[M^(-1)L^(3)T^(-2)])` <br/> `=M^(2-1-2+1)L^(6-3-3)T^(4-8+2+3)A^(4-4)` <br/> `=M^(3-3)L^(6-6)T^(9-8)A^(0)` <br/> `=M^(0)L^(0)T^(1)A^(0)` <br/> `[x]=[T]` <br/> Now, substituting values of constants in given equation, <br/> `x=((1.6xx10^(-19))^(4))/(16xx(3.14)^(2)xx(8.854xx10^(-12))^(2)xx(1.67xx10^(-27))xx(9.1xx10^(-31))^(2)xx(3xx10^(8))^(3)xx(6.67xx10^(-11))` <br/> `:.x=(6.5536xx10^(-76))/(34221942xx10^(-10))` <br/> `=281xx10^(16)s` <br/> `=6.9xx10^(8)` years <br/> `=10^(9)`years <br/> =1 Billion years <br/> This calculation shows that value of constant is approximately equal to age of world.</body></html> | |
36206. |
If an object executes a to and fro motion about a fixed point, is an example for |
Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/rotational-625601" style="font-weight:bold;" target="_blank" title="Click to know more about ROTATIONAL">ROTATIONAL</a> motion<br/>vibratory motion<br/>circular motion<br/>curvilinear motion</p>Answer :A::<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
36207. |
A stone is dropped freely, while another thrown vertically downward with an initial velocity of 2ms^(-1) from the same point, simultaneously, The time required by them to have a distance of separation 22 m between them is |
Answer» <html><body><p>11s<br/>5.5s<br/>44s<br/>22s</p>Answer :A</body></html> | |
36208. |
At a certain height a shell at rest explodes into two equal fragments. One of the fragments receives a horizontal velocity u. The time interval after which, the velocity vectors will be inclined at 120^@to each other is |
Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/u-1435036" style="font-weight:bold;" target="_blank" title="Click to know more about U">U</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/sqrt3-3056952" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT3">SQRT3</a> <a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a>)` <br/>`(sqrt3u)/(g)` <br/>`(<a href="https://interviewquestions.tuteehub.com/tag/2u-301178" style="font-weight:bold;" target="_blank" title="Click to know more about 2U">2U</a>)/(sqrt3g)` <br/>`(u)/(2sqrt3g)` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
36209. |
It is easier to rollbarrel than to pull it alongthe road why |
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/bacause-2456908" style="font-weight:bold;" target="_blank" title="Click to know more about BACAUSE">BACAUSE</a> rollingfrictionis lessthanslidingfriction</body></html> | |
36210. |
The mass of a box measured by a grocer's balance is 2.30 kg. Two gold pieces of masses 20.15 g and 20.17 g are added to the box. What is (a) the total mass of the box, (b) the difference in the masses of the pieces to correct significant figures ? |
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :(a) 2.3 <a href="https://interviewquestions.tuteehub.com/tag/kg-1063886" style="font-weight:bold;" target="_blank" title="Click to know more about KG">KG</a> (<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>) 0.02 <a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a></body></html> | |
36211. |
The dimensional formula of energy propagated per unit area at a given point in unit time is..... |
Answer» <html><body><p>`M^(1)L^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)T^(-2)`<br/>`M^(1)L^(<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>)T^(-3)`<br/>`M^(1)L^(2)T^(-3)`<br/>`M^(1)L^(0)T^(-1)`<br/></p>Solution :`[("<a href="https://interviewquestions.tuteehub.com/tag/energy-15288" style="font-weight:bold;" target="_blank" title="Click to know more about ENERGY">ENERGY</a>")/("area" xx"time")]=(M^(1)L^(2)T^(-2))/(L^(2)<a href="https://interviewquestions.tuteehub.com/tag/xxt-3292708" style="font-weight:bold;" target="_blank" title="Click to know more about XXT">XXT</a>^(1))=M^(1)L^(0)T^(-3)`</body></html> | |
36212. |
A metallic strip has thickness 3 mm and breadth 4 cm. The strip is kept horizontal on two wedges kept 80 cm apart and a mass of 50 g is placed at its middle. Calculate the depression of themid-point of the strip, Given Y=2 times 10^12 dyn.cm^-2 and g=980 cm.s^-2. |
Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :0.029 <a href="https://interviewquestions.tuteehub.com/tag/cm-919986" style="font-weight:bold;" target="_blank" title="Click to know more about CM">CM</a></body></html> | |
36213. |
A child running a temperature of 101 ^(@) F is given an antipyrin (1.e. a medicine that lowers fever) which causes an increase in the rate of evaporation of sweat from his body. If the fever is brought down to 98^(@) F in 20 minutes, what is the average rate of extra evaporation caused by the drug. Assume the evaporation mechanism to be the only way by which heat is lost. The mass of the child is 30 kg The specific heat of human body is approximately the same as that of water, and latent heat of evaporation of water at that temperature is about580 " calg"^(-1). |
Answer» <html><body><p>4.31 g/min <br/>43.1 g/min <br/>4.31 g/sec <br/>43.1 g/sec </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
36214. |
The ratio between kinetic and potential energies of a body executing simple harmonic motion, when it is at a distance of 1/N of its amplitude from the mean position is |
Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a>^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) +<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>`<br/>`1/N^(2)`<br/>`N^(2)`<br/>`N^(2)-1` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
36215. |
Explain in detail the Eratosthenes method of finding the radius of Earth. |
Answer» <html><body><p></p>Solution :During noon time of summer solstice the Suns rays cast no shadow in the city Syne which was located 500 miles away from Alexandria. At the same day and same time in Alexandria the Suns rays <a href="https://interviewquestions.tuteehub.com/tag/made-3718337" style="font-weight:bold;" target="_blank" title="Click to know more about MADE">MADE</a> 7.2 <a href="https://interviewquestions.tuteehub.com/tag/degree-47" style="font-weight:bold;" target="_blank" title="Click to know more about DEGREE">DEGREE</a> with local vertical as shown in the figure. This difference of 7.2 degree was due to the curvature ofthe <a href="https://interviewquestions.tuteehub.com/tag/earth-13129" style="font-weight:bold;" target="_blank" title="Click to know more about EARTH">EARTH</a>. <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/SUR_PHY_XI_V02_C06_E03_015_S01.png" width="80%"/> <br/> The angle 7.2 degree is <a href="https://interviewquestions.tuteehub.com/tag/equivalent-446407" style="font-weight:bold;" target="_blank" title="Click to know more about EQUIVALENT">EQUIVALENT</a> to `1/8` radian. So, `theta = 1/8 rad. <br/> If S is the length of the arc between the cities of Syne and Alexandria, and if R is radius of Earth, then <br/> `S = R theta= 500` miles <br/> So radius of the Earth <br/> `R = 500/(theta) miles, R = 500 ("miles")/(1/8)` <br/> `R = 4000` miles <br/> 1 <a href="https://interviewquestions.tuteehub.com/tag/mile-560607" style="font-weight:bold;" target="_blank" title="Click to know more about MILE">MILE</a> is equal to 1.609 km. So, he measured the radius of the Earth to be equal to R = 6436 km, which is amazingly close to the correct value of 6378 km.</body></html> | |
36216. |
The distance of Neptune and Saturn from the sun are respectively 10^(13) and 10^(12)metres and their periodic times are respectively T_N and T_SIf their orbits are assumed to be circular, then the value of T_(N)//T_S. |
Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/100-263808" style="font-weight:bold;" target="_blank" title="Click to know more about 100">100</a><br/>`<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a> <a href="https://interviewquestions.tuteehub.com/tag/sqrt10-3056923" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT10">SQRT10</a>`<br/>`1/(10sqrt10)` <br/>10</p>Answer :B</body></html> | |
36217. |
A wire of length 1 m fixed at one end has a sphere attached to it at the other end. The sphere is projected horizontally with a velocity of sqrt( 9g). When it describes a vertical circle, the ratio of elongations of the wire when the sphere is at the top and bottom of the circle is |
Answer» <html><body><p>`2:5`<br/>`5:2`<br/>`3:5`<br/>`5:3`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
36218. |
A block of mass 10kg is dragged across a horizontal surface by pulling the blockwith force of 100N. The force is applied by attaching a chord to the block. The chord is inclined at an angle of 60^(@) with the horizontal. If the coefficient of kinetic friction is 0.2 what is theacceleration of the block ? |
Answer» <html><body><p></p>Solution :`m=10kg`, `F=100N` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/theta-1412757" style="font-weight:bold;" target="_blank" title="Click to know more about THETA">THETA</a>=60^(@)`, `mu_(<a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>)=0.2`, `a=?` <br/> Horizontal component of the applied force <br/> `=F cos theta` <br/> `=100xxcos60=50N` <br/> <a href="https://interviewquestions.tuteehub.com/tag/frictional-465947" style="font-weight:bold;" target="_blank" title="Click to know more about FRICTIONAL">FRICTIONAL</a> force opposing the motion of the block <br/> `=mu_(k)mg` <br/> `=0.2xx10xx9.8=19.6N` <br/> <a href="https://interviewquestions.tuteehub.com/tag/net-5194" style="font-weight:bold;" target="_blank" title="Click to know more about NET">NET</a> force acting on the block `=Fcostheta-mu_(k)mg` <br/> `=50-19.6=30.4N` <br/> <a href="https://interviewquestions.tuteehub.com/tag/acceleration-13745" style="font-weight:bold;" target="_blank" title="Click to know more about ACCELERATION">ACCELERATION</a> of the block `=("Net force")/("Mass")=(30.4)/(10)=3.04m//s^(2)` <br/> `=3.04m//s^(2)` <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/SCH_DKB_ISC_PHY_XI_C05_SLV_003_S01.png" width="80%"/></body></html> | |
36219. |
Satellites are object which revolve around the earth. The direction of revolution of geosynchronous satellite is ..... |
Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/east-447972" style="font-weight:bold;" target="_blank" title="Click to know more about EAST">EAST</a> to West<br/>West to East<br/>North to South<br/>South to North</p>Answer :A</body></html> | |
36220. |
A boy throws a ball with initila velocity u at an angle of porjection theta from a tower of height H. Neglecting air resistance, find (a) how high above the building the ball rise, and (b) its speed just before it hits the ground. |
Answer» <html><body><p></p>Solution :(a) Only gravitational force acts on the ball, which is conservative, therefore we can apply <a href="https://interviewquestions.tuteehub.com/tag/conservation-929810" style="font-weight:bold;" target="_blank" title="Click to know more about CONSERVATION">CONSERVATION</a> of energy i.e., U = 0. At the topmost point in the path, the ball is moiving horizonrally with <a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a> `ucos theta`. <br/> Initial total mechanical energy, <br/> `E_(i) = 0 + (1)/(2) m u^(2)` <br/> Total mechanical energy at thetopmost point : <br/> `E_(r) = (1)/(2) m u^(2) cos^(2)theta + mgh` <br/> From conservation of energy, we have `E_(i) = E_(r)` <br/> (a) `(1)/(2) m u^(2) = (1)/(2) <a href="https://interviewquestions.tuteehub.com/tag/mu-566056" style="font-weight:bold;" target="_blank" title="Click to know more about MU">MU</a>^(2) cos^(2) theta + mgh` <br/> or `h = (u^(2) - u^(2) cos^(2) thea)/(2g)` <br/> (b) If v is the <a href="https://interviewquestions.tuteehub.com/tag/speed-1221896" style="font-weight:bold;" target="_blank" title="Click to know more about SPEED">SPEED</a> of the ball at the ground, <br/> `E_(f) = (1)/(2) mv^(2) - mgh` <br/> From conservation of energy, wehave <br/> `E_(i) = E_(f) <a href="https://interviewquestions.tuteehub.com/tag/rarr-1175461" style="font-weight:bold;" target="_blank" title="Click to know more about RARR">RARR</a>(1)/(2)m u^(2) = (1)/(2)mv^(2)-mgH.v=sqrt(u^(2)2gH)`</body></html> | |
36221. |
Two pendulums of different lengths are in phase at the mean position at a certain instant. The minimum time after which they will be again in phase is 5T/4, where T is the time period of shorter pendulum. Find the ratio of lengths of the two pendulums: |
Answer» <html><body><p>`1:16`<br/>`1:4`<br/>`1:2`<br/>`1:25`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
36222. |
A man of 50kg is standing at one end on a boat of length 25m and mass 200kg. If he starts running and when he reaches the other end, h has a velocity 2ms^(-1) with respect to the boat. The final velocity of the boat is (in ms^(-1)) |
Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>)`<br/>`(2)/(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)`<br/>`(<a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a>)/(5)`<br/>`(8)/(3)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
36223. |
A sphere can roll on a surface inclined at an angle theta if the friction coefficient is more than (1)/(7)g tan theta. If a sphere is released from rest on the incline. |
Answer» <html><body><p>it will stay at <a href="https://interviewquestions.tuteehub.com/tag/rest-11386" style="font-weight:bold;" target="_blank" title="Click to know more about REST">REST</a> <br/>it will make <a href="https://interviewquestions.tuteehub.com/tag/pure-1172806" style="font-weight:bold;" target="_blank" title="Click to know more about PURE">PURE</a> translational motion <br/>it will translate and rotate about the <a href="https://interviewquestions.tuteehub.com/tag/centre-912170" style="font-weight:bold;" target="_blank" title="Click to know more about CENTRE">CENTRE</a> <br/>the angular momentum of the sphere about its centre will remain constant </p>Answer :C</body></html> | |
36224. |
A particle is at x=+5m at t=0, x=-7m at t=6s and x=+2m at t=10s. Find the average velocity of the particle during the intervals (a) t=0 to t=6s (b) t=6s to t=10s (c ) t=0 to t=10s. |
Answer» <html><body><p></p>Solution :From the <a href="https://interviewquestions.tuteehub.com/tag/definition-11288" style="font-weight:bold;" target="_blank" title="Click to know more about DEFINITION">DEFINITION</a> of <a href="https://interviewquestions.tuteehub.com/tag/average-13416" style="font-weight:bold;" target="_blank" title="Click to know more about AVERAGE">AVERAGE</a> <a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a> <br/> `<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>=(Deltax)/(Deltat)=(x_(2)-x_(1))/(t_(2)-t_(1))` <br/> (a) The average velocity between the times `t=0` to `t=6s` `x_(1)=+5m,t_(1)=0,x_(2)=-7mt_(2)=6s` <br/> Hence `v_(1)=(x_(2)-x_(1))/(t_(2)-t_(1))=(-7-5)/(6-0)=-2ms^(-1)` <br/> (b) The average velocity between the times `t_(2)=6s` to `t_(3)=<a href="https://interviewquestions.tuteehub.com/tag/10s-267218" style="font-weight:bold;" target="_blank" title="Click to know more about 10S">10S</a>` is <br/> `v_(2)=(x_(3)-x_(2))/(t_(3)-t_(2))=(2-(-7))/(10-6)=(9)/(4)=2.25ms^(-1)` <br/> (c ) The average velocity between times `t_(1)=0` to `t_(3)=10s` is `v_(3)=(x_(3)-x_(1))/(t_(3)-t_(1))=(2-5)/(10-0)=-0.3ms^(-1)`</body></html> | |
36225. |
Obtain in expression for the time period T of a simple pendulun. The time period depend upon (i) mass 'm' of the bob (ii) length 'l' of the pendulum and (iii) acceieration due to gravity g at the place where the pendulum is suspended. (Constant k = 2pi ) i.e. |
Answer» <html><body><p></p>Solution :`Tproptom^(a)l^(<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>)g^(c),""T=<a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>.m^(a)l^(b)g^(c)` <br/> Here k is the dimensionless constant. <br/> Rewriting the above equation with dimensions. <br/> `[T^(1)]=[M^(a)][L^(b)][LT^(-2)]^(c)` <br/> `[M^(0)L^(0)T^(1)]=[M^(a)L^(b+c)T^(-2c)]` <br/> Comparing the <a href="https://interviewquestions.tuteehub.com/tag/powers-1162174" style="font-weight:bold;" target="_blank" title="Click to know more about POWERS">POWERS</a> of M, L and T on both sides, <br/> `a=0, b+c=0, -2c=1` <br/> <a href="https://interviewquestions.tuteehub.com/tag/solving-1217196" style="font-weight:bold;" target="_blank" title="Click to know more about SOLVING">SOLVING</a> for a, b and c, we get `a=0, b=1//2, " and " c=-1//2` <br/> From the above equation `T=k.m^(0)l^(1//2)g^(-1//2)` <br/> `T=k(1/g)^(1//2)=ksqrt(1//g)` <br/> Experimentally `k=2pi`, hence `T=2pisqrt(l//g)`</body></html> | |
36226. |
A 2 kg mass is rotating on a circular path of radius 0.8 m with angular velocity of 44 rad/sec. If radius of the path becomes 1 m, then what will be the value of angular velocity? |
Answer» <html><body><p>28.16 rad/sec <br/>19.28 rad/sec<br/>8.12 rad/sec <br/>35.26 rad/sec </p>Solution :Mass (m) = 2 <a href="https://interviewquestions.tuteehub.com/tag/kg-1063886" style="font-weight:bold;" target="_blank" title="Click to know more about KG">KG</a> , <br/> initial radius of the path `(r_(1)) = 0.8` m , initial angular velocity (`omega_(1))` = 44 rad/sec and <a href="https://interviewquestions.tuteehub.com/tag/final-461168" style="font-weight:bold;" target="_blank" title="Click to know more about FINAL">FINAL</a> radius of the path `(r_(2)) = 1` m <br/> Initial moment of inertia , `I_(1) = m r_(1)^(2) = 2 xx (0.8)^(2) = 1.28 kg m^(2)` <br/> and final moment of inertia , `I_(2) = mr_(2)^(2) = 2 xx (1)^(2) = 2 kg m^(2)` <br/> From the law of conservation of angular <a href="https://interviewquestions.tuteehub.com/tag/momentum-1100588" style="font-weight:bold;" target="_blank" title="Click to know more about MOMENTUM">MOMENTUM</a> <br/> `I_(1) omega_(1) = I_(2) omega_(2) or omega_(2) = (I_(1) omega_(1))/(I_(2)) = (1.28 xx 44)/(2) = 28.16` rad/sec</body></html> | |
36227. |
Water is heated by using an immersion heater, Can the process be reversed ? |
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> : No, it is an irrvrsible <a href="https://interviewquestions.tuteehub.com/tag/process-11618" style="font-weight:bold;" target="_blank" title="Click to know more about PROCESS">PROCESS</a>.</body></html> | |
36228. |
A narrow capillary tube when dipped in a beaker containing water, the rise is 20 cm. If the area of cross section of the bore is reduced to 1/4 th value, water will rise to a height of |
Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a> cm<br/>20 cm<br/>40 cm<br/>80 cm</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
36229. |
At what angle must a railway track with a bend of 250 m radius be banked for safe running of a train at a speed of 72 kmh^(-1). |
Answer» <html><body><p><br/></p>Solution :`<a href="https://interviewquestions.tuteehub.com/tag/tan-1238781" style="font-weight:bold;" target="_blank" title="Click to know more about TAN">TAN</a> theta = v^(2)//<a href="https://interviewquestions.tuteehub.com/tag/rg-1188560" style="font-weight:bold;" target="_blank" title="Click to know more about RG">RG</a> = 20^(2)//<a href="https://interviewquestions.tuteehub.com/tag/250-297421" style="font-weight:bold;" target="_blank" title="Click to know more about 250">250</a> <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 9.8 = 0.1632, theta = 9.27^(@)`</body></html> | |
36230. |
When a horse suddenly starts moving,the rider falls backward. Name and state the law use to explain the above situation. |
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Newton.s <a href="https://interviewquestions.tuteehub.com/tag/first-461760" style="font-weight:bold;" target="_blank" title="Click to know more about FIRST">FIRST</a> <a href="https://interviewquestions.tuteehub.com/tag/law-184" style="font-weight:bold;" target="_blank" title="Click to know more about LAW">LAW</a> of motion.Statement</body></html> | |
36231. |
Derive the expression pressure exerted by the gas on the walls of the container. |
Answer» <html><body><p></p>Solution :Expression for pressure exerted by a gas : <br/> (i) Consider a monoatomic gas of N molecules each having a mass m inside a cubical inside a cubical <a href="https://interviewquestions.tuteehub.com/tag/container-20566" style="font-weight:bold;" target="_blank" title="Click to know more about CONTAINER">CONTAINER</a> of side l as shown in the figure (a). <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/SUR_PHY_XI_V02_C09_E03_002_S01.png" width="80%"/> <br/> (ii) The molecules of the gas are in random motion. They collide with each other and also with the walls of the container. As the collisions are elastic in naturem there is no loss of energy, but a change in momentum occurs. <br/> (iii) The molecules of the gas exert pressure on the walls of the container due to collision on it. During each collision, the molecules impart <a href="https://interviewquestions.tuteehub.com/tag/certain-407894" style="font-weight:bold;" target="_blank" title="Click to know more about CERTAIN">CERTAIN</a> momentum to the wall. Due to transfer of momentum to the wall. Due to transfer of momentum, the walls experience a continuous force. The force experience a continuous force. The force experienced per unit area of the walls of the container determines the pressure exerted by the gas. It is essential to determine the <a href="https://interviewquestions.tuteehub.com/tag/total-711110" style="font-weight:bold;" target="_blank" title="Click to know more about TOTAL">TOTAL</a> momentum transferred by the molecules in a short interval of time. <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/SUR_PHY_XI_V02_C09_E03_002_S02.png" width="80%"/> <br/> (iv) A molecule of mass m moving with a velocity v having components `(v_(x),v_(y),v_(z))` hits the right side wall. Since we have assumed that the collision is elastic, the particle rebounds with same speed and its x-component is reversed. This is shown in the. The components of velocity of the molecule after collision are `(-v_(x),v_(y),v_(z))`. <br/> (v) The x-component of momentum of the molecule before collision = `mv_(x)` <br/> The x-component of momentum of the molecule after collision = `-mv^(x)` <br/> The change in momentum of the molecule in x direction = Final momentum - initial momentum = `-mv_(x)-mv_(x)=-2mv_(x)` <br/> (vi) According to law of conservation of linear momentum, the change in momentum of the wall = `2mv_(x)` <br/> (vii) The number of molecules hitting the right side wall in a small interval of time `Deltat`is calculated as follows. <br/> (viii) The molecules within the distance of `vDeltat` from the right side wall and moving <a href="https://interviewquestions.tuteehub.com/tag/towards-7269729" style="font-weight:bold;" target="_blank" title="Click to know more about TOWARDS">TOWARDS</a> the right will hit the wall in the time interval `Deltat`. This is shown in the Figure. The number of molecules that will hit the right side wall in a time interval `Deltat` is equal to the product of volume `(Av_(x)Deltat)` and number density of the molecules (n). Here A is area of the wall and n is number of molecules per unit volume `((N)/(V))`. We have assumed that the number density is the same throughout the cube. <br/> (ix) Not all the n molecules, will move to the right, therefore on an average only half of the n molecules move to the right and the other half <a href="https://interviewquestions.tuteehub.com/tag/moves-1104598" style="font-weight:bold;" target="_blank" title="Click to know more about MOVES">MOVES</a> towards left side. <br/> (x) The number of molecules that hit the right side wall in a time interval `Deltat` <br/> `=(n)/(2)Av_(x)Deltat""...(1)` <br/> (xi) In the same interval of time `Deltat`, the total momentum transferred by the molecules <br/> `DeltaP=(n)/(2)Av_(x)Deltatxx2mv_(x)=Av_(x)^(2)mnDeltat""...(2)` <br/> (xii) From Newton's second law, the change in momentum in a small interval of time gives rise to force. <br/> (xiii) The force exerted by the molecules on the wall (in magnitude) <br/> `F=(Deltap)/(Deltat)=nmAv_(x)^(2)""...(3)` <br/> (xiv) Pressure, P = force divided by the area of the wall <br/> `P=(F)/(A)=nmv_(x)^(2)""...(4)` <br/> (xv) Since all the molecules are moving completely in random manner, they do not have same speed. So we can replace the term `v_(x)^(2)` by the average `bar(v_(x)^(2))` in equation. <br/> `P=nmbar(v_(x)^(2))""...(5)` <br/> (xvi) Since the gas is assumed to move in random direction, it has no preferred direction of motion (the effect of gravity on the molecules is neglected). It implies that the molecule has same average speed in all the three direction. <br/> So, `bar(v_(x)^(2))=bar(v_(y)^(2))=bar(v_(z)^(2))`. The mean square speed is written as <br/> `bar(v^(2))=bar(v_(x)^(2))+bar(v_(y)^(2))+bar(v_(z)^(2))=bar(3v_(x)^(2))` <br/> `bar(v_(x)^(2))=(1)/(3)bar(v^(2))` <br/> Using this is equation (5), we get <br/> `P=(1)/(3)nmbar(v^(2))orP=(1)/(3)(N)/(V)mbar(v^(2))` <br/> as `[n=(N)/(V)]`</body></html> | |
36232. |
Whether the potential energy increases or decreases in the case of rising bubbles in water ? |
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Decreases .Because work done on the <a href="https://interviewquestions.tuteehub.com/tag/bubble-904920" style="font-weight:bold;" target="_blank" title="Click to know more about BUBBLE">BUBBLE</a> by buoyant <a href="https://interviewquestions.tuteehub.com/tag/force-22342" style="font-weight:bold;" target="_blank" title="Click to know more about FORCE">FORCE</a> . This work done is negative and <a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a> potential energy decreases.</body></html> | |
36233. |
Standardisation of thermometers is obtained with |
Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/jolly-521899" style="font-weight:bold;" target="_blank" title="Click to know more about JOLLY">JOLLY</a>'s <a href="https://interviewquestions.tuteehub.com/tag/thermometer-1410877" style="font-weight:bold;" target="_blank" title="Click to know more about THERMOMETER">THERMOMETER</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/platinum-601402" style="font-weight:bold;" target="_blank" title="Click to know more about PLATINUM">PLATINUM</a> <a href="https://interviewquestions.tuteehub.com/tag/resistance-1186351" style="font-weight:bold;" target="_blank" title="Click to know more about RESISTANCE">RESISTANCE</a> thermometer<br/>thermocouple thermometer<br/>gas thermometer</p>Answer :D</body></html> | |
36234. |
Which of the following represent simple harmonic motion? (i) x=A sin omegat+Bcos omegat (ii) x=Asin omegat+Bcos2omegat (iii) x=Ae^(iomegat) (iv) x=Alnomegat |
Answer» <html><body><p>(i) <a href="https://interviewquestions.tuteehub.com/tag/alone-2412120" style="font-weight:bold;" target="_blank" title="Click to know more about ALONE">ALONE</a><br/>(i) and (<a href="https://interviewquestions.tuteehub.com/tag/ii-1036832" style="font-weight:bold;" target="_blank" title="Click to know more about II">II</a>)<br/>(ii) and (<a href="https://interviewquestions.tuteehub.com/tag/iv-501699" style="font-weight:bold;" target="_blank" title="Click to know more about IV">IV</a>)<br/>all</p>Solution :(i) and (<a href="https://interviewquestions.tuteehub.com/tag/iii-497983" style="font-weight:bold;" target="_blank" title="Click to know more about III">III</a>)</body></html> | |
36235. |
The amount of heat must be supplied to 2.0 xx 10^(-2) kg of nitrogen (at room temperature) to rise its temperature by 45°C at constant pressure is (Molecular mass of N_2= 28 , R= 8.3 "J mol"^(-1) "K"^(-1) ) |
Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/94-342308" style="font-weight:bold;" target="_blank" title="Click to know more about 94">94</a> J<br/>1037 J<br/>1868 J<br/>467 J</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
36236. |
The colour of light is determined by its |
Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/frequency-465761" style="font-weight:bold;" target="_blank" title="Click to know more about FREQUENCY">FREQUENCY</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/amplitude-859568" style="font-weight:bold;" target="_blank" title="Click to know more about AMPLITUDE">AMPLITUDE</a> <br/>intensity</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
36237. |
Practical unit of heat is : |
Answer» <html><body><p>calorie<br/>horse power<br/>joule<br/>watt</p>Answer :a</body></html> | |
36238. |
The displacement of a body of mass 2 kg varies with time.t. as S =t^(2) + 2t, where S is in metres and .t.is in seconds. The work done by all the foces acting on the body during the time interval t = 2s to t = 4s is |
Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/36-309156" style="font-weight:bold;" target="_blank" title="Click to know more about 36">36</a> <a href="https://interviewquestions.tuteehub.com/tag/j-520843" style="font-weight:bold;" target="_blank" title="Click to know more about J">J</a><br/>64 J<br/>100 J<br/>120 J </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
36239. |
In the expression for force F=ma, which mass, inertial mass or gravitational mass, does m represent ? Statethe reason for your answer. |
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> : In the <a href="https://interviewquestions.tuteehub.com/tag/expression-980856" style="font-weight:bold;" target="_blank" title="Click to know more about EXPRESSION">EXPRESSION</a> F= ma, m stands for inertial mass.<br/>For F=ma, mass of the body `m = F/a` <br/> But mass of body <a href="https://interviewquestions.tuteehub.com/tag/measured-7257656" style="font-weight:bold;" target="_blank" title="Click to know more about MEASURED">MEASURED</a> as the ratio of force to <a href="https://interviewquestions.tuteehub.com/tag/acceleration-13745" style="font-weight:bold;" target="_blank" title="Click to know more about ACCELERATION">ACCELERATION</a> is <a href="https://interviewquestions.tuteehub.com/tag/called-907796" style="font-weight:bold;" target="_blank" title="Click to know more about CALLED">CALLED</a> inertial mass.</body></html> | |
36240. |
An air pump is pumping air in to a large vessel against a pressure of 1 atmosphere. In each stroke 1000C.C of air enters in to the vessel. If the number of strokes made by the pump per minute is 30, the power of the pump is [1 atm = 10^5 Pa) |
Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a> KW<br/>50 KW<br/>100 KW<br/>50 <a href="https://interviewquestions.tuteehub.com/tag/w-729065" style="font-weight:bold;" target="_blank" title="Click to know more about W">W</a> </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
36241. |
Two identical cylindrical vessels each of area of cross section A are on a level ground. Each contains a liquid of density rho. The heights of liquid columns are h_(1) and h_(2).If the two vessels are connected by means of a narrow pipe at the bottom, the work done by gravity in equalizing the liquid levels is |
Answer» <html><body><p>`(Arhog(h_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)-h_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))^(2))/2`<br/>`(Arhog)/2(h_(1)^(2)-h_(2)^(2))`<br/>`(A rhog)/<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>(h_(1)^(2)-h_(2)^(2))`<br/>`(Arhog)/4(h_(1)-h_(2))^(2)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
36242. |
A uniform disc of mass 'm' and radius r rotates along an axis passing trough its centre of mass and normal to its plane. An unstretchable rope wound on the disc. Tangential acceleration of a point P on the periphery of the when a uniform force F is applied on the rope is xF/m where 'x' is |
Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a></body></html> | |
36243. |
Time taken by light to cross nuclear diameter is of the order of |
Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(<a href="https://interviewquestions.tuteehub.com/tag/22-294057" style="font-weight:bold;" target="_blank" title="Click to know more about 22">22</a>)s`<br/>`10^(-<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>)s`<br/>`10^(-<a href="https://interviewquestions.tuteehub.com/tag/14-272882" style="font-weight:bold;" target="_blank" title="Click to know more about 14">14</a>)s`<br/>`10^(-22)s`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :(d)</body></html> | |
36244. |
A shell is fired from a cannon with a velocity V at an angle theta with the horizontal direction. At the highest point in its path, it explodes into two pieces of equal masses. One of the pieces retraces its path to the cannon. The speed of the other piece immediately after the explosion is |
Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/3v-310794" style="font-weight:bold;" target="_blank" title="Click to know more about 3V">3V</a> <a href="https://interviewquestions.tuteehub.com/tag/cos-935872" style="font-weight:bold;" target="_blank" title="Click to know more about COS">COS</a> theta` <br/>`2V cos theta` <br/>`(3)/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a> cos theta` <br/>`V cos theta` </p>Answer :A</body></html> | |
36245. |
The linear superpositions of two simple harmonic motions of amplitudes A and B is |
Answer» <html><body><p>not simple <a href="https://interviewquestions.tuteehub.com/tag/harmonic-1015999" style="font-weight:bold;" target="_blank" title="Click to know more about HARMONIC">HARMONIC</a><br/>simple harmonic with <a href="https://interviewquestions.tuteehub.com/tag/amplitude-859568" style="font-weight:bold;" target="_blank" title="Click to know more about AMPLITUDE">AMPLITUDE</a> always equal to A+B<br/>simple harmonic with amplitude always equal to `sqrt(A^(2)+B^(2))`<br/> simple harmonic with amplitude <a href="https://interviewquestions.tuteehub.com/tag/depends-948548" style="font-weight:bold;" target="_blank" title="Click to know more about DEPENDS">DEPENDS</a> on <a href="https://interviewquestions.tuteehub.com/tag/phase-22748" style="font-weight:bold;" target="_blank" title="Click to know more about PHASE">PHASE</a> A, B and phase difference be <a href="https://interviewquestions.tuteehub.com/tag/tween-3236078" style="font-weight:bold;" target="_blank" title="Click to know more about TWEEN">TWEEN</a> them</p>Answer :D</body></html> | |
36246. |
A man can swim at the rate of 5 km/h in still water. A river 1 km wide flows at the rate of 3 km/h. The man wishes to swim across the river directly opposite to the starting point. A. Along what direction must the man swim? B. What should be his resultant ? C. How much time he would take to cross? |
Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :a. 1270; <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>. 4km/hr; <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>. <a href="https://interviewquestions.tuteehub.com/tag/15-274069" style="font-weight:bold;" target="_blank" title="Click to know more about 15">15</a> <a href="https://interviewquestions.tuteehub.com/tag/min-548008" style="font-weight:bold;" target="_blank" title="Click to know more about MIN">MIN</a></body></html> | |
36247. |
A fly wheel is rotating about its own axis at an angular velocity 11 rads^(-1), its angular velocity in revolution per minute is |
Answer» <html><body><p>105<br/>210<br/>315<br/>420</p>Answer :A</body></html> | |
36248. |
You are riding inan automobile of mass 3000 kg. Assuming that you are examining the oscillation characteristics of its suspension system. tHe suspension sags 15 cm when the entire automobile is placed on it. Also, the amplitude of oscillation decreases by 50 % during one amplitude of oscillation decreases by 50 % during one complete oscillation. Estimate the values of (a) the spring and shock absorber system of one wheel, assuming that each wheel supports 750 kg. |
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :a. `F=mg=3000xx10=3xx10^(4)N.mx=-15xx10^(-<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)m` <br/> `K=-F/(<a href="https://interviewquestions.tuteehub.com/tag/4x-319255" style="font-weight:bold;" target="_blank" title="Click to know more about 4X">4X</a>)=(-3xx10^(4))/(4(-15xx10^(-2)))=5xx10^(4)N//m` <br/> <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>. mass supported by each spring `m=3000/4=750` kg <br/> damped oscillations Amplitude `A_(t)=Ae^(-bt//2m)`<br/> Time <a href="https://interviewquestions.tuteehub.com/tag/period-1151023" style="font-weight:bold;" target="_blank" title="Click to know more about PERIOD">PERIOD</a> `T=2pisqrt(m/K)=2xx3.14sqrt(750/(5xx10^(4)))` <br/> `=77xx10^(-2)` seconds <br/> Amplitude decreases by 50% then at `=A//2` and t=T <br/> `:.A/2=Ae^(-bt//2m)` or `b=(0.693xx2m)/T` <br/> `b=1350kg//s`</body></html> | |
36249. |
A thin brass sheet at 10^(@)C and a thin stell sheet at 20^(@)C have the same surface area. The common temperature at which both would have the same area is (coefficient of liner expansion for brass and steel are respectively 19xx10^(-6//@)C and 11xx10^(-6//@)C). |
Answer» <html><body><p>`-3.75^(@) <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>`<br/>`-2.75^(@) C`<br/>`2.75^(@) C`<br/>`3.75^(@) C`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
36250. |
The ……….. Value that can be measured by a ………….. Is called …………. Of the instrument. |
Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/minimum-561095" style="font-weight:bold;" target="_blank" title="Click to know more about MINIMUM">MINIMUM</a> ; measuring instrument ; <a href="https://interviewquestions.tuteehub.com/tag/least-7256596" style="font-weight:bold;" target="_blank" title="Click to know more about LEAST">LEAST</a> <a href="https://interviewquestions.tuteehub.com/tag/count-936718" style="font-weight:bold;" target="_blank" title="Click to know more about COUNT">COUNT</a> .</body></html> | |