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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 37201. |
A particle is released from rest from a tower of height 3h. The ratio of times to fall equal heights 'h' i.e. t_(1):t_(2):t_(3)" is "(sqrt(3)=1.7&sqrt(2)=1.4) |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>):sqrt(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>):<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>`<br/>`3:2:1`<br/>`1:14:1.7`<br/>`10:4:3`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 37202. |
1 kilowatt hour is equivalent to |
| Answer» <html><body><p>`10^(-<a href="https://interviewquestions.tuteehub.com/tag/7-332378" style="font-weight:bold;" target="_blank" title="Click to know more about 7">7</a>)<a href="https://interviewquestions.tuteehub.com/tag/j-520843" style="font-weight:bold;" target="_blank" title="Click to know more about J">J</a>`<br/>`1.6xx10^(-19)J`<br/>4.186J<br/>`3.6xx10^(-6)J`</p>Answer :D</body></html> | |
| 37203. |
Three identical spheres each of radius 3cm are placed on a horizontal surface touching one another. The distance of centre of mass of system from any centre of the sphere is |
| Answer» <html><body><p>1/<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a> m<br/>3 <a href="https://interviewquestions.tuteehub.com/tag/cm-919986" style="font-weight:bold;" target="_blank" title="Click to know more about CM">CM</a><br/>`2sqrt(3)cm`<br/>`1//sqrt(3)cm`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 37204. |
A load of 100 N acts on a bar of length 10 cm and area of cross section 1 cm. Find the energy stored in it. (Y= 10^(11) N//m^(2)) |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`<a href="https://interviewquestions.tuteehub.com/tag/5xx10-1901302" style="font-weight:bold;" target="_blank" title="Click to know more about 5XX10">5XX10</a>^(-<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>)<a href="https://interviewquestions.tuteehub.com/tag/j-520843" style="font-weight:bold;" target="_blank" title="Click to know more about J">J</a>`</body></html> | |
| 37205. |
For a gas elastic limit |
| Answer» <html><body><p>Exists<br/>Does not exist<br/>Exists only at <a href="https://interviewquestions.tuteehub.com/tag/absolute-11456" style="font-weight:bold;" target="_blank" title="Click to know more about ABSOLUTE">ABSOLUTE</a> zero<br/>Exists for a <a href="https://interviewquestions.tuteehub.com/tag/perfect-1150611" style="font-weight:bold;" target="_blank" title="Click to know more about PERFECT">PERFECT</a> gas</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a></body></html> | |
| 37206. |
A body is projected at angle 30^(0) to horizontal on a planet with a velocity of 80 ms^(-1) its time of flight is 4 seconds then acceleration due to gravity on that planet is |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> ms^(-2)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a> ms^(-2)`<br/>`10 ms^(-2)`<br/>`20 ms^(-2)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 37207. |
Two blocks are connected by a string as shown in figure. They are released from rest. Show that after they moved a distance L, their common speed in given by sqrt((2(m_(2)-mum_(1))gl)/((m_(1)+m_(2)))) where mu is the coefficient of friction |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :In moving a distance L by `m_(1) and m_(2)` the <a href="https://interviewquestions.tuteehub.com/tag/pe-590719" style="font-weight:bold;" target="_blank" title="Click to know more about PE">PE</a> will be lost by `m_(2)` only and will be `m_(2)gl`, while work done by friction will be only on `m_(1)` and will be `<a href="https://interviewquestions.tuteehub.com/tag/mu-566056" style="font-weight:bold;" target="_blank" title="Click to know more about MU">MU</a> m_(1)gL`. Now as the string is inextensible `v_(1) = v_(2) = v ` and so, the gain in <a href="https://interviewquestions.tuteehub.com/tag/ke-527890" style="font-weight:bold;" target="_blank" title="Click to know more about KE">KE</a> wil be = `(1//2) (m_(1) + m_(2)) v^(2)`. By conservation of energy. <br/> Loss in PE = Grain in KE + <a href="https://interviewquestions.tuteehub.com/tag/wd-729586" style="font-weight:bold;" target="_blank" title="Click to know more about WD">WD</a> against friction <br/> i.e., `m_(2)gL =(1)/(2)(m_(1)+m_(2))v^(2)+mu m_(1)gL` <br/> `v=sqrt((2(m_(2)-mum_(1))gL)/((m_(1)+m_(2))))`</body></html> | |
| 37208. |
A liquid in a thermos flask is vigorouslyshaken. Then the temperature of the liquid |
| Answer» <html><body><p>Is not <a href="https://interviewquestions.tuteehub.com/tag/altered-362954" style="font-weight:bold;" target="_blank" title="Click to know more about ALTERED">ALTERED</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/increases-1040626" style="font-weight:bold;" target="_blank" title="Click to know more about INCREASES">INCREASES</a> <br/>Decreases<br/>None</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 37209. |
A body of mass M is kept on a rough horizontal surface (friction coefficient = mu). A person is trying to pull the body by applying a horizontal force but the body is not moving. The force by the surface on A is F where |
| Answer» <html><body><p>F = Mg <br/>`F = mu Mg` <br/>`Mg <a href="https://interviewquestions.tuteehub.com/tag/le-540308" style="font-weight:bold;" target="_blank" title="Click to know more about LE">LE</a> F le Mg sqrt(1+mu^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))` <br/>`Mg ge F ge Mg sqrt(1-mu^(2))` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :C</body></html> | |
| 37210. |
An object 1cm tall is placed 4cm infront of a mirror. In order to produce an upright image of 3cm height one needs a |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/convex-933348" style="font-weight:bold;" target="_blank" title="Click to know more about CONVEX">CONVEX</a> <a href="https://interviewquestions.tuteehub.com/tag/mirror-1098189" style="font-weight:bold;" target="_blank" title="Click to know more about MIRROR">MIRROR</a> of radius of <a href="https://interviewquestions.tuteehub.com/tag/curvature-20184" style="font-weight:bold;" target="_blank" title="Click to know more about CURVATURE">CURVATURE</a> 12cm<br/>Concave mirror of radius of curvature 12cm<br/>Concave mirror of radius of curvature 4cm<br/>Plane mirror of height 12cm</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 37211. |
A uniform square plate has a small piece Q of an irregular shape removed and guled to the centre of the plate leaving a hole behind in figure. The moment of inertia about the z-axis is then, . |
| Answer» <html><body><p>increased<br/>decreased <br/>the same <br/>changed inunpedicted manner </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :in thegivendiagrams, <a href="https://interviewquestions.tuteehub.com/tag/whenthe-1453070" style="font-weight:bold;" target="_blank" title="Click to know more about WHENTHE">WHENTHE</a> smallpieceQ removed andgluedtothecentreof <a href="https://interviewquestions.tuteehub.com/tag/theplate-2304994" style="font-weight:bold;" target="_blank" title="Click to know more about THEPLATE">THEPLATE</a>, themasscomescloser to thez- axis, hence, <a href="https://interviewquestions.tuteehub.com/tag/momentof-2840703" style="font-weight:bold;" target="_blank" title="Click to know more about MOMENTOF">MOMENTOF</a> inertia decreases.</body></html> | |
| 37212. |
An ideal gas is initially at temperature T and volume V. Its volume is increased by Delta V due to an increase in temperature Delta T. Pressure remaining constant. The physical quantity delta = ( Delta V)/( V Delta T) varies with temperature as : |
| Answer» <html><body><p><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_TRG_AO_PHY_XI_V01_D_C01_E04_003_O01.png" width="30%"/><br/><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_TRG_AO_PHY_XI_V01_D_C01_E04_003_O02.png" width="30%"/><br/><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_TRG_AO_PHY_XI_V01_D_C01_E04_003_O03.png" width="30%"/><br/><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_TRG_AO_PHY_XI_V01_D_C01_E04_003_O04.png" width="30%"/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 37213. |
A car of mas 1250 kg experiences a resistance of 750 n when it moves at 30ms^(-1). If the engine can develop 30 KW at this speed, the maximum acceleration that the engine can produce is |
| Answer» <html><body><p>`0.8ms^(-<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>`0.2ms^(-2)`<br/>`0.4ms^(-2)`<br/>`0.5ms^(-2)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 37214. |
One mole of helium is kept in a cylinder of area 8.5 cm^2 . Cylinder is closed by a light frictionlesspiston. If a heat of 42 J given to gas causes a rise of temperature through 2^@C , then |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/delta-947703" style="font-weight:bold;" target="_blank" title="Click to know more about DELTA">DELTA</a> U =30J`<br/>`Delta W = 17.1J`<br/><a href="https://interviewquestions.tuteehub.com/tag/displacement-956081" style="font-weight:bold;" target="_blank" title="Click to know more about DISPLACEMENT">DISPLACEMENT</a> of <a href="https://interviewquestions.tuteehub.com/tag/piston-600809" style="font-weight:bold;" target="_blank" title="Click to know more about PISTON">PISTON</a> = <a href="https://interviewquestions.tuteehub.com/tag/20cm-293006" style="font-weight:bold;" target="_blank" title="Click to know more about 20CM">20CM</a> <br/> displacement of piston = 10 cm</p>Answer :B::C</body></html> | |
| 37215. |
If a street light of mass M is suspended from the end of a uniform rod of length L in different possible patterns as shown in figure, then: |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/pattern-590239" style="font-weight:bold;" target="_blank" title="Click to know more about PATTERN">PATTERN</a> A is more sturyd<br/>pattern <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a> is more sturdy<br/>pattern <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> is more sturdy<br/>all will have same sturdiness</p>Answer :A</body></html> | |
| 37216. |
A book with printing error contains four different formulae for displacement. Choose the correct formula/formulae (a) y = a sin (2pi)/(T)t (b) y = a sin vt (c) y = a/T sin (t/a) (d) y =a/T (sin (2pi)/(T) t + cos (2pi)/(T) t) |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :The argument of sine and cosine function must be dimensionaless so (a) is the <a href="https://interviewquestions.tuteehub.com/tag/probable-2213116" style="font-weight:bold;" target="_blank" title="Click to know more about PROBABLE">PROBABLE</a> correct <a href="https://interviewquestions.tuteehub.com/tag/formula-464310" style="font-weight:bold;" target="_blank" title="Click to know more about FORMULA">FORMULA</a>. Since <br/> (a) y = a sin `((2pi)/(T)t), :. [(2pit)/(T)] = [T^(0)]` is dimensionless. <br/> (b) y = a sin vt, `:. [vt] = [T]` is dimensional so this equation is <a href="https://interviewquestions.tuteehub.com/tag/incorrect-499101" style="font-weight:bold;" target="_blank" title="Click to know more about INCORRECT">INCORRECT</a>. <br/> (c) y = `a/t sin (t/a), :. [t/a]` is dimensional so this is incorrect. <br/> (b) y = `a/t (sin ""(2pi)/(T) t + cos""(2pit)/(T))` , Though `(2pit)/(T)` dimensionless `a/T` does not have dimension of displacement so this is also incorrect.</body></html> | |
| 37217. |
If L_1 = 2.02 m pm 0.01 m , L_2 = 1.02 m pm 0.01 m ,determine L_1 + 2L_2 |
| Answer» <html><body><p></p>Solution :`L_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>) + 2L_(2) = L_(1) + L_(2) + L_(2)` <br/> `= (2.02 <a href="https://interviewquestions.tuteehub.com/tag/mpm-549063" style="font-weight:bold;" target="_blank" title="Click to know more about MPM">MPM</a> 0.1) + (1.02 m pm 0.01m) + (1.02 m pm 0.01 m) ` <br m="" pm=""/></body></html> | |
| 37218. |
100g of water is supercooled to -10°C. At this point, due to some disturbance mechanized or otherwise some of it suddenly freezes to ice. What will be the temperature of the resultant mixture and how much mass would freeze? [S_(W) = 1 "cal"/g/""^(@) C and L_("Fusion")^("W") = 80 "cal/g"] |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>^(@) , 12.5g`<br/>`0^(@) <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>, 2.5g`<br/>`-<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(@) C, 2.5 <a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a>`<br/>`-10^(@) C, 12.5g`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 37219. |
The relation between pressure and temperature of a monoatomic gas in an adiabatic process is P prop T^(-C), where C = ____ |
| Answer» <html><body><p>`2/5`<br/>`5/2`<br/>`3/5`<br/>`5/3`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :The relation between pressure and temperature in an adiabatic process, <br/> `P.T^(gamma/(1-gamma))` =constant <br/> `therefore P prop T^((1-gamma)/gamma)`, comparing it with `P prop T^(-<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>)` <br/> `therefore -C=(1-gamma)/gamma` <br/> `therefore C=(gamma-1)/gamma` <br/> For <a href="https://interviewquestions.tuteehub.com/tag/monoatomic-2841458" style="font-weight:bold;" target="_blank" title="Click to know more about MONOATOMIC">MONOATOMIC</a> gas `gamma=5/3` <br/> `therefore C=(5/3-1)/(5/3)=(2/3)/(5/3)` <br/> `therefore C=2/5`</body></html> | |
| 37220. |
A satellite S is moving in an elliptical orbit around the earth. The mass of the satellite is very small compared to the mass of the earth |
| Answer» <html><body><p>the acceleration of S is always directed towards the centre of the earth <br/>the <a href="https://interviewquestions.tuteehub.com/tag/angular-11524" style="font-weight:bold;" target="_blank" title="Click to know more about ANGULAR">ANGULAR</a> <a href="https://interviewquestions.tuteehub.com/tag/momentum-1100588" style="font-weight:bold;" target="_blank" title="Click to know more about MOMENTUM">MOMENTUM</a> of S about the centre of the earth <a href="https://interviewquestions.tuteehub.com/tag/changes-913881" style="font-weight:bold;" target="_blank" title="Click to know more about CHANGES">CHANGES</a> in direction, but its magnitude remains constant <br/>The total <a href="https://interviewquestions.tuteehub.com/tag/mechanical-2780" style="font-weight:bold;" target="_blank" title="Click to know more about MECHANICAL">MECHANICAL</a> energy of S varies periodically with time <br/>the linear momentum of S remains constant in magnitude </p>Answer :A</body></html> | |
| 37221. |
How can you move the body up the smooth plane without acceleration? |
| Answer» <html><body><p> </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :By <a href="https://interviewquestions.tuteehub.com/tag/applying-1982651" style="font-weight:bold;" target="_blank" title="Click to know more about APPLYING">APPLYING</a> an <a href="https://interviewquestions.tuteehub.com/tag/external-981194" style="font-weight:bold;" target="_blank" title="Click to know more about EXTERNAL">EXTERNAL</a> force `F=mg <a href="https://interviewquestions.tuteehub.com/tag/sintheta-3034717" style="font-weight:bold;" target="_blank" title="Click to know more about SINTHETA">SINTHETA</a>`, up the plane after giving an initial <a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a> up the plane.</body></html> | |
| 37222. |
Why are gas thermometers more sensitive than mercury thermometers? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :The <a href="https://interviewquestions.tuteehub.com/tag/coefficient-920926" style="font-weight:bold;" target="_blank" title="Click to know more about COEFFICIENT">COEFFICIENT</a> of expansion of <a href="https://interviewquestions.tuteehub.com/tag/gas-1003521" style="font-weight:bold;" target="_blank" title="Click to know more about GAS">GAS</a> is very <a href="https://interviewquestions.tuteehub.com/tag/large-1066424" style="font-weight:bold;" target="_blank" title="Click to know more about LARGE">LARGE</a> compared to that of <a href="https://interviewquestions.tuteehub.com/tag/mercury-558950" style="font-weight:bold;" target="_blank" title="Click to know more about MERCURY">MERCURY</a>.</body></html> | |
| 37223. |
A small body of mass m can slide without friction along a through bent which is in the form of a semi-circular arc of radius R. At what height h will the body be at rest with respect to the trough,if the trough rotates with uniform angular velocity omega about a vertical axis: |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a><br/>`R-(2g)/(omega^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))`<br/>`R+(2g)/(omega^(2))`<br/>`R-(<a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a>)/(omega^(2))`</p>Answer :d</body></html> | |
| 37224. |
A body constrained to move along the z-axis of a coordinate system is subject to a constant force F given by. What is the work done by this force in moving the body a distance of 4m along the z-axis ? |
| Answer» <html><body><p>`12 <a href="https://interviewquestions.tuteehub.com/tag/j-520843" style="font-weight:bold;" target="_blank" title="Click to know more about J">J</a>`<br/>`24 J`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/48-318016" style="font-weight:bold;" target="_blank" title="Click to know more about 48">48</a> J`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a> J`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 37225. |
The bob of vibrating simple pendulum is made of ice. How will the period of swing will change when the ice starts melting ? |
| Answer» <html><body><p></p>Solution :(i) The period of swing of simple pendulum will remains unchanged till the location on the centre of gravity of the bob left after melting the <a href="https://interviewquestions.tuteehub.com/tag/ice-1035302" style="font-weight:bold;" target="_blank" title="Click to know more about ICE">ICE</a> remains at a fixed distance from the point of suspension. <br/> (<a href="https://interviewquestions.tuteehub.com/tag/ii-1036832" style="font-weight:bold;" target="_blank" title="Click to know more about II">II</a>) If the centre of gravity pf ice bob after melting is raised upwards , then the effective length of pendulum decrease and hence the time period of <a href="https://interviewquestions.tuteehub.com/tag/sawing-3008223" style="font-weight:bold;" target="_blank" title="Click to know more about SAWING">SAWING</a> decrease. If the centre of gravity of ice shifts on lower side, the time period of swing <a href="https://interviewquestions.tuteehub.com/tag/increase-1040383" style="font-weight:bold;" target="_blank" title="Click to know more about INCREASE">INCREASE</a>.</body></html> | |
| 37226. |
What is meant by a closed pipe system ? |
| Answer» <html><body><p></p>Solution :A pipewhich is clsed at <a href="https://interviewquestions.tuteehub.com/tag/one-585732" style="font-weight:bold;" target="_blank" title="Click to know more about ONE">ONE</a> <a href="https://interviewquestions.tuteehub.com/tag/end-971042" style="font-weight:bold;" target="_blank" title="Click to know more about END">END</a> is <a href="https://interviewquestions.tuteehub.com/tag/known-534098" style="font-weight:bold;" target="_blank" title="Click to know more about KNOWN">KNOWN</a> as a <a href="https://interviewquestions.tuteehub.com/tag/closed-919469" style="font-weight:bold;" target="_blank" title="Click to know more about CLOSED">CLOSED</a> <a href="https://interviewquestions.tuteehub.com/tag/pipe-1154875" style="font-weight:bold;" target="_blank" title="Click to know more about PIPE">PIPE</a> system.</body></html> | |
| 37227. |
Regarding linear momentum of a body (a) It is a measure of quantity of motion contained by the body (b) Change in momentum is the measure of impulse (c) Impulse and acceleration act in opposite direction to the change in momentum (d) In the case of uniform circular motion the linear momentum is conserved. |
| Answer» <html><body><p>a & <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a> are <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a><br/>b & <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> are true <br/>c & d are true <br/>a, b & c are true</p>Answer :A</body></html> | |
| 37228. |
Answer the following questions based on the P - T phase diagram of CO_(2) : (a) CO_(2) at 1 atm pressure and temperature -60^(@)C is compressed isothermally. Does it go through a liquid phase ? (b) What happens when CO_(2) at 4 atm pressure is cooled from room temperature at constant pressure ? (c) Describe qualitatively the changes in a given mass of solid CO_(2) at 10 atm pressure and temperature -65^(@)C as it is heated up to room temperature at constant pressure. (d) CO_(2)is heated to a temperature 70^(@)C and compressed isothermally. What changes in its properties do you expect to observe ? |
| Answer» <html><body><p></p>Solution :(a) No, `CO_(2)` is in steam from at 1 atm pressure and `-60^(@)C` <a href="https://interviewquestions.tuteehub.com/tag/temperature-11887" style="font-weight:bold;" target="_blank" title="Click to know more about TEMPERATURE">TEMPERATURE</a>. <br/> It its isothermal compression is done i.e. increasing pressure with constant temperature then it <a href="https://interviewquestions.tuteehub.com/tag/directly-955045" style="font-weight:bold;" target="_blank" title="Click to know more about DIRECTLY">DIRECTLY</a> converts into solid form without coming through liquid. (<a href="https://interviewquestions.tuteehub.com/tag/sublimation-1231130" style="font-weight:bold;" target="_blank" title="Click to know more about SUBLIMATION">SUBLIMATION</a>) <br/> (b) `CO_(2)` is in gaseous state at 4 atm pressure and `27^(@)C` temperature. <br/> If it is clled at constant pressure then it directly converts into gaseous state without coming through liquid. It intersects at curve III. <br/> (c) `CO_(2)` is in solid form at <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a> atm pressure and `-60^(@)C` temp. <br/> If it is heated at constant pressure then first it comes in liquid form and then in gaseous form because it intersects the fusion and vaporization curve. <br/> (d) It is seen from phase diagram of `CO_(2)` that the above `70^(@)C` temperature it doesn.t have liquid area. Then <a href="https://interviewquestions.tuteehub.com/tag/also-373387" style="font-weight:bold;" target="_blank" title="Click to know more about ALSO">ALSO</a> it reacts as an ideal gas with increase in pressure.</body></html> | |
| 37229. |
In Column-I, 4 situations are depicted and in columa-II, 4 possible kinds of collision are listed. Match the situation with type of collision. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Evaluate `<a href="https://interviewquestions.tuteehub.com/tag/e-444102" style="font-weight:bold;" target="_blank" title="Click to know more about E">E</a>=(v_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)-v_(1))/(u_(1)-u_(2))` for each case alongwith using conservation of <a href="https://interviewquestions.tuteehub.com/tag/linear-1074458" style="font-weight:bold;" target="_blank" title="Click to know more about LINEAR">LINEAR</a> momentum.</body></html> | |
| 37230. |
A flask is filled with 13 g of an ideal gas at 27^(@)C and its temperature is raised to 52^(@)C. Find the mass of the gas that has to be released to maintain the temperature of the gas in the flask at 52^(@)C and the pressure is same as the initial pressure. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Let n be the initial number of moles and n. be the final number of moles. Since <a href="https://interviewquestions.tuteehub.com/tag/pressure-1164240" style="font-weight:bold;" target="_blank" title="Click to know more about PRESSURE">PRESSURE</a> and volume <a href="https://interviewquestions.tuteehub.com/tag/remain-1184279" style="font-weight:bold;" target="_blank" title="Click to know more about REMAIN">REMAIN</a> the same, we have <br/> `PV=nRT=nRxx300=n.Rxx325` <br/> `(n.)/(n)=(300)/(325)=(12)/(13)` <br/> `("Final mass")/("Initial mass")=(12)/(13)<a href="https://interviewquestions.tuteehub.com/tag/rarr-1175461" style="font-weight:bold;" target="_blank" title="Click to know more about RARR">RARR</a>" Final mass"=(12)/(13)xx13=12g` <br/> `"Mass to be released "=13-12=1g`</body></html> | |
| 37231. |
What do you mean by mass element dm? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Mass element (dm) is a small <a href="https://interviewquestions.tuteehub.com/tag/portion-1159785" style="font-weight:bold;" target="_blank" title="Click to know more about PORTION">PORTION</a> of <a href="https://interviewquestions.tuteehub.com/tag/body-900196" style="font-weight:bold;" target="_blank" title="Click to know more about BODY">BODY</a> which when integrated over the whole body <a href="https://interviewquestions.tuteehub.com/tag/gives-1007647" style="font-weight:bold;" target="_blank" title="Click to know more about GIVES">GIVES</a> <a href="https://interviewquestions.tuteehub.com/tag/total-711110" style="font-weight:bold;" target="_blank" title="Click to know more about TOTAL">TOTAL</a> mass of the body.</body></html> | |
| 37232. |
Consider a mixture of oxygen and hydrogen kept at room temperature. As compared to a hydrogen molecule an oxygen molecule hits the wall. |
| Answer» <html><body><p>with <a href="https://interviewquestions.tuteehub.com/tag/greater-476627" style="font-weight:bold;" target="_blank" title="Click to know more about GREATER">GREATER</a> <a href="https://interviewquestions.tuteehub.com/tag/average-13416" style="font-weight:bold;" target="_blank" title="Click to know more about AVERAGE">AVERAGE</a> speed<br/>with smaller average speed<br/>with greater average kinetic energy<br/>with smaller average kinetic energy</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 37233. |
An uniform block of mass M, height h and base width a is kept on a rough inclined plane as shown in figure. Friction is enough to prevent any slipping between inclined plane and block. The angle of inclined plane is then increased. The limiting value of theta so that the block not tip over tan^(-1)("xa/h") where 'x' is |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a></body></html> | |
| 37234. |
Using free body diagram show that it is easy to pull an object than to push it |
| Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>></p>Solution :Whena bodyis pushedat anarbitraryangle `theta` thatvariesfrom `(p " to"(pi )/(2))` . TheappliedforceF canberesolvedintotwocomponentsas Fsin `theta` parallelto the surfaceand F cos `theta` prependicularto the <a href="https://interviewquestions.tuteehub.com/tag/surface-1235573" style="font-weight:bold;" target="_blank" title="Click to know more about SURFACE">SURFACE</a>. Thetotaldownwardforceactingon thebodymg +F cos `theta` . Itis impliedthat thenormalforceactingon thebodyincrease. sincethereis noaccelerationalongthe verticaldirectionthe normalforce N is given by <br/> As a resultthe maximalstaticfrictionalsoincreasesand thatis <a href="https://interviewquestions.tuteehub.com/tag/equal-446400" style="font-weight:bold;" target="_blank" title="Click to know more about EQUAL">EQUAL</a> to <br/> `f_(s) ^(<a href="https://interviewquestions.tuteehub.com/tag/max-546895" style="font-weight:bold;" target="_blank" title="Click to know more about MAX">MAX</a>)= mu_(s)N_(push)` <br/> `-mu_(s ) (mg + F cos theta)` <br/> Equationshows thata greaterforceneedstobe appliedto pushthe objectintomotion<br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PRE_GRG_PHY_XI_V02_C03_E01_020_S01.png" width="80%"/><br/> Whenan <a href="https://interviewquestions.tuteehub.com/tag/objectis-1127367" style="font-weight:bold;" target="_blank" title="Click to know more about OBJECTIS">OBJECTIS</a> pulledat anangle `theta` the aplliedforceisresolvedinto twocomponents. The totaldownwardforceacting on theobject is<br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PRE_GRG_PHY_XI_V02_C03_E01_020_S02.png" width="80%"/> <br/> Equation (3)showsthat thenormal forceis less that `N_(push)`Fromequation `(1) ` and (3)weknowthat itis easier to pullan objectthattopushto makeit move.</body></html> | |
| 37235. |
For a particle executing S.H.M along x-axis force is given by |
| Answer» <html><body><p>`-<a href="https://interviewquestions.tuteehub.com/tag/kx-1064991" style="font-weight:bold;" target="_blank" title="Click to know more about KX">KX</a>`<br/>A <a href="https://interviewquestions.tuteehub.com/tag/cos-935872" style="font-weight:bold;" target="_blank" title="Click to know more about COS">COS</a> kx<br/> A `<a href="https://interviewquestions.tuteehub.com/tag/e-444102" style="font-weight:bold;" target="_blank" title="Click to know more about E">E</a>^(-kx)`<br/>Akx</p>Answer :A</body></html> | |
| 37236. |
What will be the speed of infrasonics and ultrasonics in air at 0^(@)C ? |
| Answer» <html><body><p></p>Solution :The <a href="https://interviewquestions.tuteehub.com/tag/speed-1221896" style="font-weight:bold;" target="_blank" title="Click to know more about SPEED">SPEED</a> of audible sound (20 <a href="https://interviewquestions.tuteehub.com/tag/hz-493442" style="font-weight:bold;" target="_blank" title="Click to know more about HZ">HZ</a> to 2000Hz) in air at `0^(@)<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>` is roughly `332ms^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)` . Irrespective of the frequencies, whether infrasonics, ultrasnics or audible , sound propagates with the same speed in a given medium.</body></html> | |
| 37237. |
A particle is acted by a force F= kx, where 'K' is a positive constant. Its P.E at x=0 is zero. Which curve corretly represents the variation of potential energy of the block with respect to 'x' |
| Answer» <html><body><p><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_NEO_CAO_PHY_XI_V01_B_APP_E03_021_O01.png" width="30%"/><br/><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_NEO_CAO_PHY_XI_V01_B_APP_E03_021_O02.png" width="30%"/><br/><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_NEO_CAO_PHY_XI_V01_B_APP_E03_021_O03.png" width="30%"/><br/><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_NEO_CAO_PHY_XI_V01_B_APP_E03_021_O04.png" width="30%"/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 37238. |
Draw the P-T and V-T diagrams for an isobaric process of expansion, corresponding to n moles of an ideal gas at a pressure P_(0),from V_(0) to 2V_(0). |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :For the graph of P versus T the variation is a straight line normal to the <a href="https://interviewquestions.tuteehub.com/tag/pressure-1164240" style="font-weight:bold;" target="_blank" title="Click to know more about PRESSURE">PRESSURE</a> axis, the temperature varying from `T_(1)`to `T_(2)`as shown figure.<br/> From the gas equation PV = nRT<br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_NEO_CAO_PHY_XI_V01_PMH_C13_SLV_033_S01.png" width="80%"/> <br/> we have, `V = ((<a href="https://interviewquestions.tuteehub.com/tag/nr-581903" style="font-weight:bold;" target="_blank" title="Click to know more about NR">NR</a>)/(P_(<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>)))T or V prop T` <br/> At `V=V_(0) , T_(1) =(P_(0)V_(0))/(nR) and " at " V=2V_(0), T_(2) =(2P_(0) V_(0))/(nR)` <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_NEO_CAO_PHY_XI_V01_PMH_C13_SLV_033_S02.png" width="80%"/> <br/> From the graph of V versus T, the equation `V=((nR)/(P_(0)))T or V = kT` shows that the volume variesdirectly, as the temperature (Charles. law). So, the graph is a straight line inclined to the (V-T) axis, and passing through the <a href="https://interviewquestions.tuteehub.com/tag/origin-1139399" style="font-weight:bold;" target="_blank" title="Click to know more about ORIGIN">ORIGIN</a> (when produced) as shown in figure.</body></html> | |
| 37239. |
The gravitational force between a hollow spherical shell (of radius R and uniform density) and a point mass is E. Show the nature of F versus r graph where r is the distance of the point from the centre of the hollow spherical shell of uniform density. |
| Answer» <html><body><p></p>Solution :`<a href="https://interviewquestions.tuteehub.com/tag/implies-1037962" style="font-weight:bold;" target="_blank" title="Click to know more about IMPLIES">IMPLIES</a>` Take density of the shell `(<a href="https://interviewquestions.tuteehub.com/tag/rho-623364" style="font-weight:bold;" target="_blank" title="Click to know more about RHO">RHO</a>)`is constant. <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/KPK_AIO_PHY_XI_P1_C08_E04_025_S01.png" width="80%"/><br/>Mass of the shell = (density) `xx`(volume)<br/> `(rho) xx 4/3 piR^(3) = M` <br/>As the density of the shell is uniform, it can be treated as a point mass placed at its centre.<br/> Now, gravitational force between `M and M_D` <br/>`F = (GMm)/<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>^(r ge R)` <br/> `F = 0 (r lt R)` <br/>The <a href="https://interviewquestions.tuteehub.com/tag/relation-1183220" style="font-weight:bold;" target="_blank" title="Click to know more about RELATION">RELATION</a> of F versus r is <a href="https://interviewquestions.tuteehub.com/tag/shown-1206565" style="font-weight:bold;" target="_blank" title="Click to know more about SHOWN">SHOWN</a> in the diagram. <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/KPK_AIO_PHY_XI_P1_C08_E04_025_S02.png" width="80%"/></body></html> | |
| 37240. |
The distance travelled by a body is 107.25m in time 1.5s. The velocity with correct significant figures is |
| Answer» <html><body><p>71.5<br/>71<br/>71.5<br/>`72.0`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 37241. |
A container of negligible heat capacity contains 1kg of water. It is connected by a steel rod of length 10m and area of cross-section 10cm^(2) to a large steam chamber which is maintained at 100^(@)C. If initial temperature of water is 0^(@)C, find the time after which it beomes 50^(@)C. (Neglect heat capacity of steel rod and assume no loss of heat to surroundings) (use table 3.1, take specific heat of water =4180 J//kg.^(@)C) |
| Answer» <html><body><p></p>Solution :Let temperature of water at <a href="https://interviewquestions.tuteehub.com/tag/time-19467" style="font-weight:bold;" target="_blank" title="Click to know more about TIME">TIME</a> t be `T`, then thermal current at time t, <br/> `I = ((100 -T)/(R ))` <br/> This increases the temperature of water form `T to T +dT` <br/> `rArr i = (<a href="https://interviewquestions.tuteehub.com/tag/dh-943253" style="font-weight:bold;" target="_blank" title="Click to know more about DH">DH</a>)/(dt) = ms (dT)/(dt)` <br/> `rArr (100-T)/(R ) = ms(dT)/(dt) rArr overset(50)underset(0)<a href="https://interviewquestions.tuteehub.com/tag/int-11513" style="font-weight:bold;" target="_blank" title="Click to know more about INT">INT</a> (dT)/(100-T) = overset(t)underset(0)int (dT)/(Rms)` <br/> `rArr -ln ((<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)/(2)) = (t)/(Rms)` <br/> or `t = Rms <a href="https://interviewquestions.tuteehub.com/tag/ln2-1076476" style="font-weight:bold;" target="_blank" title="Click to know more about LN2">LN2</a> sec` <br/> `= (L)/(KA) ms ln2 sec` <br/> `= ((10m)(1kg)(4180J//kg-^(@)C))/(46(w//m^(@)C)xx(10xx10^(-4)m^(2)))ln2` <br/> `= (418)/(46) (0.69) xx 10^(5) = 6.27 xx 10^(5) sec = 174.16 hours`</body></html> | |
| 37242. |
Explain work energy theorem . |
| Answer» <html><body><p></p>Solution :For straightline motion : If body is <a href="https://interviewquestions.tuteehub.com/tag/moving-548882" style="font-weight:bold;" target="_blank" title="Click to know more about MOVING">MOVING</a> with initial velocity u and constantacceleration a , it acquired velocity v with displacement s <a href="https://interviewquestions.tuteehub.com/tag/thenfrom-2304784" style="font-weight:bold;" target="_blank" title="Click to know more about THENFROM">THENFROM</a> the third equationof motion , <br/> `v^(2) -u^(2) = 2as`<br/> multiplying `m/2 `on both sides of equation ,<br/> `1/2 mv^(2) -1/2 "mu"^(2) =mas ` <br/> `K_(f) -K_(i)=Fs [ :. ma =F] `<br/>For motion in three dimension :<br/> `v^(2) -u^(2) = 2vec(a) .vec(d)`<br/> where v = final velocity , u = <a href="https://interviewquestions.tuteehub.com/tag/intial-2746226" style="font-weight:bold;" target="_blank" title="Click to know more about INTIAL">INTIAL</a> velocity , `vec(a)` = constant acceleration and `vec(d)` = displacementMultiplying by `m/2 ` on both side of equation , <br/> ` 1/2 mv^(2) -1/2 "mu"^(2) = m vec(a) .vec(d)` <br/> `vec(F) .vec(d) ""[ :. mvec(a) = vec(F)] `<br/> The left hand side is the change in kinetic energy of body , whileright <a href="https://interviewquestions.tuteehub.com/tag/handis-481975" style="font-weight:bold;" target="_blank" title="Click to know more about HANDIS">HANDIS</a> the multiplication of force and the displacement .It is known as work and it is denoted by W. <br/> ` :. K_(f) - K_(i) = W and DeltaK = W ` <br/> This <a href="https://interviewquestions.tuteehub.com/tag/relation-1183220" style="font-weight:bold;" target="_blank" title="Click to know more about RELATION">RELATION</a> is known as work energy theorem . <br/> Note : If a body undergoes a displacement in the direction of net force , then work done on the body which is positive andthe speed and kineticenergy of body increases but if force and displacement are in opposite direction , then work done by the body which is negative and the speed and kinetic energy decreases .</body></html> | |
| 37243. |
A moving particle of mass .m. makes head on elastic collision with another particle of mass 3m. The least Fraction of the initial kinetic energy lost by the first particle (mass m) is |
| Answer» <html><body><p>`2//3`<br/>`5//3`<br/>`3//4`<br/>`1//3`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 37244. |
If the Earth shirnks such that its density becomes 8 times to the present value, then the new during of the day in hours will be |
| Answer» <html><body><p>24<br/>12<br/>6<br/>4</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 37245. |
The pair of physical quantities having the same dimensions is |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/power-2475" style="font-weight:bold;" target="_blank" title="Click to know more about POWER">POWER</a> and Torque<br/>Thermal capacity and specific heat<br/>Latent heat and <a href="https://interviewquestions.tuteehub.com/tag/gravitational-476409" style="font-weight:bold;" target="_blank" title="Click to know more about GRAVITATIONAL">GRAVITATIONAL</a> potential<br/>Angular <a href="https://interviewquestions.tuteehub.com/tag/momentum-1100588" style="font-weight:bold;" target="_blank" title="Click to know more about MOMENTUM">MOMENTUM</a> and Impulse</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 37246. |
Assertion - Finite angular disacement is not a vector quantiy. Reason It does not obey vector laws. |
| Answer» <html><body><p>If both Assetion and Reason are correct but Reason is the correct explanation of Assertion.<br/>If both Assetion and Reason are correct but Reason is not the correct explanation of Assertion.<br/>If Asserion is true but Reason is false<br/>If Asserion is false but Reason is true</p>Solution :(a) If a particle is roting about on <a href="https://interviewquestions.tuteehub.com/tag/axis-889931" style="font-weight:bold;" target="_blank" title="Click to know more about AXIS">AXIS</a> on its elf theorientain of the particle is not same under a different <a href="https://interviewquestions.tuteehub.com/tag/order-1138220" style="font-weight:bold;" target="_blank" title="Click to know more about ORDER">ORDER</a> of addition of angular displacement ,so it cannot be <a href="https://interviewquestions.tuteehub.com/tag/regarded-7268030" style="font-weight:bold;" target="_blank" title="Click to know more about REGARDED">REGARDED</a> as vector quantity . <br/> `d theta+d theta_(2)=d theta_(2)+d theta_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)` <br/>`buttheta_(1)+theta_(2) netheta_(2)+theta_(1)`</body></html> | |
| 37247. |
The efficiency of a carnot heat engine depend on |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/working-1459914" style="font-weight:bold;" target="_blank" title="Click to know more about WORKING">WORKING</a> substance<br/><a href="https://interviewquestions.tuteehub.com/tag/temperature-11887" style="font-weight:bold;" target="_blank" title="Click to know more about TEMPERATURE">TEMPERATURE</a> of <a href="https://interviewquestions.tuteehub.com/tag/sink-1210432" style="font-weight:bold;" target="_blank" title="Click to know more about SINK">SINK</a> alone<br/>temperature of <a href="https://interviewquestions.tuteehub.com/tag/source-1219297" style="font-weight:bold;" target="_blank" title="Click to know more about SOURCE">SOURCE</a> only <br/>temperature of both source and sink</p>Answer :D</body></html> | |
| 37248. |
In order to stop a car in shortest distance on a horizontal road one should |
| Answer» <html><body><p>apply the <a href="https://interviewquestions.tuteehub.com/tag/brakes-14257" style="font-weight:bold;" target="_blank" title="Click to know more about BRAKES">BRAKES</a> very hard so that the wheels stop rotating <br/>apply the brakes hard <a href="https://interviewquestions.tuteehub.com/tag/enough-446095" style="font-weight:bold;" target="_blank" title="Click to know more about ENOUGH">ENOUGH</a> to just prevent slipping <br/>pump the brakes (<a href="https://interviewquestions.tuteehub.com/tag/press-605361" style="font-weight:bold;" target="_blank" title="Click to know more about PRESS">PRESS</a> and release)<br/>shut the engine off and not apply brakes </p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 37249. |
The potential as a function of x is plotted in figure. Which of the following is // are correct? |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/na-572417" style="font-weight:bold;" target="_blank" title="Click to know more about NA">NA</a></body></html> | |
| 37250. |
Consider the Earth as a homogenous sphere of radius R and a straight hole is bored in it through its centre. Show that a particle dropped into the holewill execute a simple harmonic motion such that its time period is T= 2pi sqrt((R)/(g)) |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`T=2pisqrt((R)/(g))` <br/> Oscillations of a particle dropped in a tunnel along the diameter of the earth. <br/> Consider earth to be a sphere of <a href="https://interviewquestions.tuteehub.com/tag/radius-1176229" style="font-weight:bold;" target="_blank" title="Click to know more about RADIUS">RADIUS</a> R and centre O. A straight tunnel is dug along the diameter of the earth. Let .g. be the value of acceleration due to gravity at the surface of the earth. <br/> Suppose a body of mass .m. is dropped into the tunnel and it is at point P. i.e., at a depth d below the surface of the earth at any instant. <br/> If g. is acceleration due to gravity at P. <br/> then `g.=g(1-(d)/(R))=g((R-d)/(R))` <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/FM_PHY_XI_V02_C10_E01_041_S01.png" width="80%"/> <br/> If y is distance of the body from the centre of the earth, then <br/> `R-d=y` <br/> `therefore g.=g((y)/(R))` <br/> Force acting on the body a point P is <br/> `F=-mg.=-(mg)/(R)y" i.e., "Fpropy` <br/> Negative sign indicates that the force <a href="https://interviewquestions.tuteehub.com/tag/acts-848461" style="font-weight:bold;" target="_blank" title="Click to know more about ACTS">ACTS</a> in the opposite direction of displacement. <br/> Thus the body will execute SHM with force <a href="https://interviewquestions.tuteehub.com/tag/constant-930172" style="font-weight:bold;" target="_blank" title="Click to know more about CONSTANT">CONSTANT</a>, `k=(mg)/(R)` <br/> The period of oscillation of the body will be `T=2pisqrt((m)/(k))=2pisqrt((m)/(mg//R))` <br/> `T=2pisqrt((R)/(g))`</body></html> | |