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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 37101. |
In the question number 52, the speed with which the stone hits the ground is |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/15-274069" style="font-weight:bold;" target="_blank" title="Click to know more about 15">15</a> m `s^(-1)` <br/>90 m `s^(-1)` <br/>99 m `s^(-1)` <br/>49 m `s^(-1)` </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Motion along horizontal <a href="https://interviewquestions.tuteehub.com/tag/direction-1696" style="font-weight:bold;" target="_blank" title="Click to know more about DIRECTION">DIRECTION</a>, `downarrow +ve` <br/> `u_(x) = 15 ms^(-1), a_(x) = 0`<br/> `v_(x) = u_(x) + a_(x)t = 15 + 0 xx 10 = 15 ms^(-1)`<br/> Motion along vertical direction, <br/> `u_(y) = 0, a_(y) = <a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a>` <br/> `v_(y) = u_(y) + a_(y)t = 0 + 9.8 xx 10 = 98 ms^(-1)` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a>` Speed of the stone when it hits the ground is <br/> `v = sqrt(v_(x)^(2) + v_(y)^(2)) = sqrt((15)^(2) + (98)^(2)) ~~ 99 ms^(-1)`</body></html> | |
| 37102. |
A sound wave is passing through air column in the form of compression and rarefaction. In consecutive compressions and rarefactions. |
| Answer» <html><body><p>(a)denisty remains <a href="https://interviewquestions.tuteehub.com/tag/constant-930172" style="font-weight:bold;" target="_blank" title="Click to know more about CONSTANT">CONSTANT</a>. <br/>(b) Boyle's law is <a href="https://interviewquestions.tuteehub.com/tag/obeyed-7702081" style="font-weight:bold;" target="_blank" title="Click to know more about OBEYED">OBEYED</a>. <br/>(c) bulk modulus of air oscillates. <br/>(d) there is no transfer of heat. </p>Solution :During the propagation of sound in air, condensations take place at a given positon, rapidly and periodically. Hence, what ever <a href="https://interviewquestions.tuteehub.com/tag/amount-374803" style="font-weight:bold;" target="_blank" title="Click to know more about AMOUNT">AMOUNT</a> of heat is generated at agiven <a href="https://interviewquestions.tuteehub.com/tag/postion-2944657" style="font-weight:bold;" target="_blank" title="Click to know more about POSTION">POSTION</a> in air medium, same amount of heat is absorbed there only when rarefaction takes place at the same position after half <a href="https://interviewquestions.tuteehub.com/tag/period-1151023" style="font-weight:bold;" target="_blank" title="Click to know more about PERIOD">PERIOD</a> `T/2.` Thus, there is no transfer of heat and hence this process can be taken as adiabatic.</body></html> | |
| 37103. |
A 2 cm thick slab of commercial thermocole, 100" cm"^(2) in cross-section and having thermal conductivity 2xx10^(-4) cal sec^(-1)" cm"^(-1)(C^(0))^(-1) has insulating regions differing by 100^(0)C. The quantity of heat flowing through it in a day will be |
| Answer» <html><body><p>20.4 <a href="https://interviewquestions.tuteehub.com/tag/kcal-531581" style="font-weight:bold;" target="_blank" title="Click to know more about KCAL">KCAL</a> <br/>43.2 kcal <br/>86.4 kcal <br/>63.6 kcal </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 37104. |
A thin circular ring of mass 'm' and radius R is rotating about its with a constant angular velocity omega. The objects each of mass M are attached gently to the opposite ends of a diameter of the ring. The new angular velocity of ring is |
| Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/omegam-2205498" style="font-weight:bold;" target="_blank" title="Click to know more about OMEGAM">OMEGAM</a>)/(M+m)`<br/>`(omegam)/(M+m)`<br/>`(<a href="https://interviewquestions.tuteehub.com/tag/omega-585625" style="font-weight:bold;" target="_blank" title="Click to know more about OMEGA">OMEGA</a>(m+2M))/(m)`<br/>`(omega(m-2M))/(m+2M)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 37105. |
An ideal gas goes from the state I to to the state f as shown in figure. The work done by the gas during the process |
| Answer» <html><body><p>is <a href="https://interviewquestions.tuteehub.com/tag/positive-1159908" style="font-weight:bold;" target="_blank" title="Click to know more about POSITIVE">POSITIVE</a> <br/>is negative<br/>is zero<br/>cannot be <a href="https://interviewquestions.tuteehub.com/tag/obtained-7273275" style="font-weight:bold;" target="_blank" title="Click to know more about OBTAINED">OBTAINED</a> from this <a href="https://interviewquestions.tuteehub.com/tag/information-1043838" style="font-weight:bold;" target="_blank" title="Click to know more about INFORMATION">INFORMATION</a> .</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 37106. |
A disc rotates with angular velocity omega and kinetic energy E. Then its angular momentum |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/conserved-2539138" style="font-weight:bold;" target="_blank" title="Click to know more about CONSERVED">CONSERVED</a> about <a href="https://interviewquestions.tuteehub.com/tag/com-409611" style="font-weight:bold;" target="_blank" title="Click to know more about COM">COM</a> only<br/>conserved about the <a href="https://interviewquestions.tuteehub.com/tag/point-1157106" style="font-weight:bold;" target="_blank" title="Click to know more about POINT">POINT</a> of <a href="https://interviewquestions.tuteehub.com/tag/contact-25916" style="font-weight:bold;" target="_blank" title="Click to know more about CONTACT">CONTACT</a> only<br/>conserved about all the points.<br/>not conserved about any point.</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 37107. |
Three moles of an ideal gas at 300 K are isothermally expanded to five times its volume and heated at this constant volume so that the pressure is raised to its initial value before expansion. In the whole process 83.14 KJ heat is required. Calculate the ratio C_p//C_v of the gas. log. 5 = 1.61 and R = 8.3 Joules/mole K. |
| Answer» <html><body><p></p>Solution :For the isothermal expansion, by Boyle.s law, we have<br/> `P_1 V_1=P_2 V_2or(P_1)/(P_2) = (V_2)/(v_1) = (5V_1)/( V_1) = 5`<br/>Now, applying gas law at constant volume, we <a href="https://interviewquestions.tuteehub.com/tag/get-11812" style="font-weight:bold;" target="_blank" title="Click to know more about GET">GET</a> <br/> `(P_2)/(T_2)=(P_3)/(T_3)( thereforeP_3 = P_1)(or)(P_2)/(T_2) =(T_2)/(T_3) = (T_1)/(T_3)` <br/> (As <a href="https://interviewquestions.tuteehub.com/tag/first-461760" style="font-weight:bold;" target="_blank" title="Click to know more about FIRST">FIRST</a> expansion was isothermal, <a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a> `T_1 =T_2`.) <br/> `threfore(T_3)/(T_1) =(P_1)/(P_2) = 5or T_3 = 5T_1 = 5 xx300= 1500K` <br/>Now ` dQ= dU+ <a href="https://interviewquestions.tuteehub.com/tag/dw-943287" style="font-weight:bold;" target="_blank" title="Click to know more about DW">DW</a>= nC_vd Tint_( V_i)^(v_2) PdV ` <br/>But `P= nRT_1 //V`, where `mu`is the number of moles of the gas.<br/> ` thereforedQ= nC _v dT + nRT_1log _e(V_2 //V_1)` <br/>Now `C_p-C_v=Rand(C_p -C_v) = gamma. so C_v = R // ( gamma -1)` <br/> `therefored Q=( nR)/( gamma -1) dT+ nRT_1log_e(V_2)/(v_1)`<br/><a href="https://interviewquestions.tuteehub.com/tag/substituting-1231652" style="font-weight:bold;" target="_blank" title="Click to know more about SUBSTITUTING">SUBSTITUTING</a> the values : `83.14 xx 10^3` Joule `=( 3 xx 8.3 )/( gamma -1)` <br/>`(1500- 300 ) +8.3300log_e5 (or)83140 =( 29880)/( gamma -1) + 12027( log_e 5=1.61 ]thereforegamma= 1.42`</body></html> | |
| 37108. |
An ice box made of styrofoam (thermal conductivity =0.01" Jm"^(-1)s^(-1)K^(-1)) is used to keep liquids cool. It has a total wall area including lid of 0.8" m"^(2) and wall thickness of 2.0 cm. A bottle of water is placed in the box and filled with ice. If the outside temperature is 30^(0)C the rate of flow of heat into the box is : (in J-s^(-1)) |
| Answer» <html><body><p>16<br/>14<br/>12<br/>10</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 37109. |
A sphere rolls off the top of a stairway with a horizontal velocity of magnitude 200 cm/sec.The steps are 10 cm high and 10 cm wide. Which step will the ball hit first ? (g = 10m//s^(2)) |
| Answer» <html><body><p>8<br/>2<br/>4<br/>6</p>Answer :A</body></html> | |
| 37110. |
The work done by the string of a simple pendulum in one complete oscillation is equal to |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/zero-751093" style="font-weight:bold;" target="_blank" title="Click to know more about ZERO">ZERO</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/total-711110" style="font-weight:bold;" target="_blank" title="Click to know more about TOTAL">TOTAL</a> <a href="https://interviewquestions.tuteehub.com/tag/energy-15288" style="font-weight:bold;" target="_blank" title="Click to know more about ENERGY">ENERGY</a> of the <a href="https://interviewquestions.tuteehub.com/tag/pendulum-1149901" style="font-weight:bold;" target="_blank" title="Click to know more about PENDULUM">PENDULUM</a> <br/>P.E. of the pendulum <br/>K.E. of the pendulum</p>Answer :A</body></html> | |
| 37111. |
A horizontal force F pushes a 4 kg block (A) which pushes against a 2 kg block (B) as shown. The blocks have an acceleration of 3m//s^(2) to the right. There is no friction between the blocks and the surfaces on which they slide. What is the net force B exerts on A ? |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/6n-332098" style="font-weight:bold;" target="_blank" title="Click to know more about 6N">6N</a> to the right<br/>12 <a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a> to the right<br/>6 N to the left<br/>12 N to the left</p>Solution :`F=ma, F_("<a href="https://interviewquestions.tuteehub.com/tag/net-5194" style="font-weight:bold;" target="_blank" title="Click to know more about NET">NET</a>")=F-f, f=ma` <br/> `a=(T_(3))/(m_(1)+m_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)+m_(3)), T_(2)=(m_(1)+m_(2))a`</body></html> | |
| 37112. |
If a cyclist moving with a speed of 4.9 m/s on a level can take a sharp circular turn of radius 4 m, then coefficient between the cycle tyres and road is |
| Answer» <html><body><p><br/></p>Solution :`<a href="https://interviewquestions.tuteehub.com/tag/tan-1238781" style="font-weight:bold;" target="_blank" title="Click to know more about TAN">TAN</a> <a href="https://interviewquestions.tuteehub.com/tag/theta-1412757" style="font-weight:bold;" target="_blank" title="Click to know more about THETA">THETA</a> = mu=v^(2)//rg, mu = 4.9^(2)//<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a> xx 9.8 = 0.245`</body></html> | |
| 37113. |
Two identical loudspeakers placed 3.00 m apart are driven by the same oscillator as shown in Fig. 7.12. A listener is originally at point O , located 8.00 m from the centre of the line connecting the two speakers. The listener then moves to point P, which is a perpendicular distance 0.350 m from O , and she experiences the first minimum sound intensity . What is the frequency of the oscillator ? |
| Answer» <html><body><p></p>Solution :In this example , signal representing the sound is electrically <a href="https://interviewquestions.tuteehub.com/tag/split-11788" style="font-weight:bold;" target="_blank" title="Click to know more about SPLIT">SPLIT</a> and sent to two different loudspeakers . After leaving the speakers , the sound waves recombine at the positionof the listener. Despite the difference in how thesplitting occurs , the path differnce discussion related to Fig . 7.12 can be applied here. <br/> Because the sound waves from two separate sources combine , we apply the waves in interference analysis model. Figure 7.12 shows the physical arrangement of the speakers , along with two shaded right triangles that can be drawn on the basis of the lengths described in the problem . The first minimum occurs when the two waves reaching the listener at point `P are 180^(@)` out of phasw , in other words , when their path difference `Delta <a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a> equals lambda//2`. <br/> From the shaded triangles , find the path lengths from the speakers to the listener : <br/> `r_(1) = sqrt (( 8.00 m)^(2) + ( 1.15 m)^(2)) = 8.08 m` <br/> `r_(2)= sqrt(( 8.00 m)^(2) + ( 1.85 m)^(2)) = 8.21 m` <br/> Hence, the path difference is ` r_(2) - r_(1) = 0.132 m`. Because this path differnce must equal `lambda//2` for the first minimum , `lambda = 0.26 m`. To <a href="https://interviewquestions.tuteehub.com/tag/obtain-582970" style="font-weight:bold;" target="_blank" title="Click to know more about OBTAIN">OBTAIN</a> the oscillator <a href="https://interviewquestions.tuteehub.com/tag/frequency-465761" style="font-weight:bold;" target="_blank" title="Click to know more about FREQUENCY">FREQUENCY</a> , use equation `v = lambda f`, where ` v` is the speed of sound in <a href="https://interviewquestions.tuteehub.com/tag/air-852233" style="font-weight:bold;" target="_blank" title="Click to know more about AIR">AIR</a> , `343 m//s`.</body></html> | |
| 37114. |
If a vertical mass spring system is taken to the moon, will its time period after? |
| Answer» <html><body><p></p>Solution :The <a href="https://interviewquestions.tuteehub.com/tag/time-19467" style="font-weight:bold;" target="_blank" title="Click to know more about TIME">TIME</a> <a href="https://interviewquestions.tuteehub.com/tag/period-1151023" style="font-weight:bold;" target="_blank" title="Click to know more about PERIOD">PERIOD</a> will not be <a href="https://interviewquestions.tuteehub.com/tag/changed-913862" style="font-weight:bold;" target="_blank" title="Click to know more about CHANGED">CHANGED</a>. Because the time period of a body <a href="https://interviewquestions.tuteehub.com/tag/suspended-656920" style="font-weight:bold;" target="_blank" title="Click to know more about SUSPENDED">SUSPENDED</a> to the end of spring is `T= 2pi sqrt((m)/(k))`.</body></html> | |
| 37115. |
Give the quantities for which the following are the dimensions: M^(1)L^(-1)T^(-2) |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/stress-1229213" style="font-weight:bold;" target="_blank" title="Click to know more about STRESS">STRESS</a> or <a href="https://interviewquestions.tuteehub.com/tag/pressure-1164240" style="font-weight:bold;" target="_blank" title="Click to know more about PRESSURE">PRESSURE</a></body></html> | |
| 37116. |
A river of width 'w' is flowing variable velocity given by v_(r)=v_(0)(1+ (sqrt(3)-1)/(w)y). Where 'y' is perpendicular distance from one bank. A boat is driven such that it moves perpendicular to bank. Velocity of boat in still water is 2V(0) Drift of boat is |
| Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/w-729065" style="font-weight:bold;" target="_blank" title="Click to know more about W">W</a> pi)/(3(<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(3)-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>))`<br/>`(pi w)/(2)`<br/><a href="https://interviewquestions.tuteehub.com/tag/zero-751093" style="font-weight:bold;" target="_blank" title="Click to know more about ZERO">ZERO</a><br/>`(pi w)/(6(sqrt(3)-1))`</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 37117. |
A river of width 'w' is flowing variable velocity given by v_(r)=v_(0)(1+ (sqrt(3)-1)/(w)y). Where 'y' is perpendicular distance from one bank. A boat is driven such that it moves perpendicular to bank. Velocity of boat in still water is 2V(0) The velocity of boat wrt to water when it reaches opposite bank |
| Answer» <html><body><p>`2V_(<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>)`<br/>`V_(0)`<br/>`3V_(0)`<br/>`sqrt(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>) V_(0)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 37118. |
The density of hydrogen at S.T.P is 0.08696 gm/litre. Find the gas constant of hydrogen. |
| Answer» <html><body><p></p>Solution :Density of hydrogen at S.T.P = 0.08696 gm/litre <br/> <a href="https://interviewquestions.tuteehub.com/tag/volume-728707" style="font-weight:bold;" target="_blank" title="Click to know more about VOLUME">VOLUME</a> of 1 gm of hydrogen `=1/0.08696"litre"=1000/0.08696c.c` <br/> At S.T.P, pressure `=76 <a href="https://interviewquestions.tuteehub.com/tag/times-1420471" style="font-weight:bold;" target="_blank" title="Click to know more about TIMES">TIMES</a> 13.6 times 980"<a href="https://interviewquestions.tuteehub.com/tag/dyne-961313" style="font-weight:bold;" target="_blank" title="Click to know more about DYNE">DYNE</a>"//cm^(2)` , Temperature = 273 K , Get constant, `r=(PV)/T` <br/> `""=((76 times 13.6 times980)(1000/0.08696))/(273)=(76 times 13.6 times 98)/(273 times 8696) times 10^(9)=0.04267 times 10^(9)` <br/> `""=4.267 times 10^(<a href="https://interviewquestions.tuteehub.com/tag/7-332378" style="font-weight:bold;" target="_blank" title="Click to know more about 7">7</a>)" <a href="https://interviewquestions.tuteehub.com/tag/erg-446447" style="font-weight:bold;" target="_blank" title="Click to know more about ERG">ERG</a> "gm^(-1)K^(-1)=4.267" J "gm^(-1)K^(-1)=4267" J "Kg^(-1)K^(-1)`</body></html> | |
| 37119. |
A river of width 'w' is flowing variable velocity given by v_(r)=v_(0)(1+ (sqrt(3)-1)/(w)y). Where 'y' is perpendicular distance from one bank. A boat is driven such that it moves perpendicular to bank. Velocity of boat in still water is 2V(0) Time taken to reach other bank |
| Answer» <html><body><p>`(pi w)/(6(sqrt(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)-1)V_(<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>))`<br/>`(w)/(6sqrt(3) - 1 )V_(0))`<br/>`(w)/(6(sqrt(3)+1)V_(0))`<br/>`(pi w)/(3(sqrt(3)-1)V_(0))`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 37120. |
A ball is thrawn downward from a height of 30m with a velocity of 10 ms^(-1).Determine the velocity with which the ball strikes the ground by using law of conservation of energy. |
| Answer» <html><body><p></p>Solution :Height from which the ball is <a href="https://interviewquestions.tuteehub.com/tag/dropped-2594665" style="font-weight:bold;" target="_blank" title="Click to know more about DROPPED">DROPPED</a> = 30 m <br/>Velocity with which the ball is dropped=`10 <a href="https://interviewquestions.tuteehub.com/tag/ms-549331" style="font-weight:bold;" target="_blank" title="Click to know more about MS">MS</a>^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)` <br/>According to law of conservation of energy, <br/>Gain in kinetic energy=Loss in <a href="https://interviewquestions.tuteehub.com/tag/potential-1161228" style="font-weight:bold;" target="_blank" title="Click to know more about POTENTIAL">POTENTIAL</a> energy<br/>For bodies falling down `v62 = u^2 + 2gh ` <br/>` v^2 = (10)^2 + 2 xx 9.8 xx 30 = 688` <br/> ` v = 26.23 ms^(-1)`</body></html> | |
| 37121. |
What is calorimeter ? What is Calorimeter ? Explain its principle and construction. |
| Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/calorimetry-908029" style="font-weight:bold;" target="_blank" title="Click to know more about CALORIMETRY">CALORIMETRY</a> means measurement of heat. <br/> A device in which heat measurement can be <a href="https://interviewquestions.tuteehub.com/tag/made-3718337" style="font-weight:bold;" target="_blank" title="Click to know more about MADE">MADE</a> is called calorimeter. <br/> When there is no heat <a href="https://interviewquestions.tuteehub.com/tag/exchange-454713" style="font-weight:bold;" target="_blank" title="Click to know more about EXCHANGE">EXCHANGE</a> between system and surroundings, then it is called isolated system. <br/> When different <a href="https://interviewquestions.tuteehub.com/tag/parts-1148278" style="font-weight:bold;" target="_blank" title="Click to know more about PARTS">PARTS</a> of an isolated system are at different temperature, a quantity of heat transfers from the part at higher temperature to the part at lower temperature. The heat lost by the part at higher temperature is equal to the heat gained by the part at lower temperature.<br/> When a body at higher temperature is brought in contact with another body at lower temperature, the heat lost by the hot body is equal to the heat gained by the colder body, provided no heat is allowed to escape to the surroundings. <br/> Construction : <br/> It consists a metallic vessel and stirrer of the same material <a href="https://interviewquestions.tuteehub.com/tag/like-1073845" style="font-weight:bold;" target="_blank" title="Click to know more about LIKE">LIKE</a> copper or aluminium. <br/> The vessel is kept inside a wooden jacket which contains heat insulating materials like glass, wool etc. <br/> The outer jacket acts as a heat shield and reduces the heat loss from the inner vessel. <br/> There is an opening in the out jacket through which a mercury thermometer can be inserted into the calorimeter.</body></html> | |
| 37122. |
(A) : Power developed in circular motion is always zero.(R ) : Workdone in case of circular motion is not zero. |
| Answer» <html><body><p>Both (A) and (<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a> ) are true and (R ) is the <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> of (A) <br/>Both (A) and (R ) are true and (R ) is not the correct explanation of (A) <br/>(A) is true but (R ) is false <br/>(A) is false and (R ) is false </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 37123. |
Stainless steel cooking pans are perferred with extra ……….. bottoms. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/copper-933790" style="font-weight:bold;" target="_blank" title="Click to know more about COPPER">COPPER</a></body></html> | |
| 37124. |
Thermodynamic process are indicated in the following diagram. Match the following |
| Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>>`P rarr C, Q rarr A, R rarr D, S rarr <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>`<br/>`P rarr C, Q rarr D, R rarr B, S rarr A`<br/>`P rarr D, Q rarr B, R rarr A, S rarr C`<br/>`P rarr A, Q rarr C, R rarr D, S rarr B`</p>Solution :In process I, volume is <a href="https://interviewquestions.tuteehub.com/tag/constant-930172" style="font-weight:bold;" target="_blank" title="Click to know more about CONSTANT">CONSTANT</a> <br/> `:.` Process `I rarr` Isochoric, `P rarr C` <br/> As slope of curve <a href="https://interviewquestions.tuteehub.com/tag/ii-1036832" style="font-weight:bold;" target="_blank" title="Click to know more about II">II</a> is more than the slope of curve III. Process `II rarr` <a href="https://interviewquestions.tuteehub.com/tag/adiabatic-849856" style="font-weight:bold;" target="_blank" title="Click to know more about ADIABATIC">ADIABATIC</a> and Process `II rarr` Isothermal <br/> `:. Q rarr A, R rarr D` <br/> In process IV, pressure is constant <br/> Process `IV rarr` Isobaric, `S rarr B`</body></html> | |
| 37125. |
The upper end of a wire of radius 4mm and length 100cm is clamped and its other end is twisted through an angle of 30° then the angle of shear is |
| Answer» <html><body><p>`0.012^(@)`<br/>`0.<a href="https://interviewquestions.tuteehub.com/tag/12-269062" style="font-weight:bold;" target="_blank" title="Click to know more about 12">12</a>^(@)`<br/>`1.2^(@)`<br/>`12^(@)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 37126. |
A particle of mass m moving with velocity 2v collides with another particle of mass 3m moving with velocity v in the same direction. If it is perfect inelastic collision, the loss of K.E. of the system is |
| Answer» <html><body><p>`(3)/(<a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a>)<a href="https://interviewquestions.tuteehub.com/tag/mv-1082193" style="font-weight:bold;" target="_blank" title="Click to know more about MV">MV</a>^(2)`<br/>`(<a href="https://interviewquestions.tuteehub.com/tag/27-298706" style="font-weight:bold;" target="_blank" title="Click to know more about 27">27</a>)/(8) mv^(2)`<br/>`(3)/(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>) mv^(2)`<br/>zero</p>Answer :A</body></html> | |
| 37127. |
Answer the following question : What is the frequency of oscillation of a simple pendulum mounted in a cabin that is freely falling under gravity ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Gravity <a href="https://interviewquestions.tuteehub.com/tag/disappears-955235" style="font-weight:bold;" target="_blank" title="Click to know more about DISAPPEARS">DISAPPEARS</a> for a <a href="https://interviewquestions.tuteehub.com/tag/man-1085541" style="font-weight:bold;" target="_blank" title="Click to know more about MAN">MAN</a> under free <a href="https://interviewquestions.tuteehub.com/tag/fall-983217" style="font-weight:bold;" target="_blank" title="Click to know more about FALL">FALL</a>, so frequency is <a href="https://interviewquestions.tuteehub.com/tag/zero-751093" style="font-weight:bold;" target="_blank" title="Click to know more about ZERO">ZERO</a>.</body></html> | |
| 37128. |
Necessary condition of equilibrium is that acceleration of body should be zero. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a>.</body></html> | |
| 37129. |
A ball with initial speed of10m/s collides elastically with two other identical balls at rest as shown in figure, whose centres are on a line perpendicular to the initial velocity and which are initially in contact with each other.All the three balls are lying on a smooth horizontal table. The first ball is aimed directly at the contact point of the other two balls.All the balls are smooth. Find the velocities of the three balls after the collision. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`[2m//s,6.93 m//s" ""at"" "<a href="https://interviewquestions.tuteehub.com/tag/30-304807" style="font-weight:bold;" target="_blank" title="Click to know more about 30">30</a>^(@)"with <a href="https://interviewquestions.tuteehub.com/tag/incident-1039786" style="font-weight:bold;" target="_blank" title="Click to know more about INCIDENT">INCIDENT</a> <a href="https://interviewquestions.tuteehub.com/tag/direction-1696" style="font-weight:bold;" target="_blank" title="Click to know more about DIRECTION">DIRECTION</a>"]`</body></html> | |
| 37130. |
A block is projected with an initial velocity v_("Block") on a long conveyor belt moving with velocity v_("Block") (at that instant)having constant acceleration a_("Belt"). Mark the correct option regarding friction after long time (friction coefficient between block and belt = mu). If : {:(,"Column-1",,"Column-2"),("(A)",v_("Block")=2v_("Belt")and a_("Belt")=0,"(P)","zero"),("(B)",v_("block")=2v_("Belt")and a_("Belt")gt mug,"(Q)",f_(s)"static friction" (0 lt f_(s) lt f_(L))),("(C)",v_("Block")=2v_("Belt")and a_("Belt")=mug,"(R)",f_(L)"limiting friction"),("(D)",v_("Block")=2v_("Belt")and a_("Belt")lt mug,"(S)",f_(K) "kinetic friction"):} |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A-P; B-S; C-R; D-Q</body></html> | |
| 37131. |
A force vec(F) = (4hat(i) - 3hat(j) - 5hat(k)) N moves a body for (3hat(i) + 6hat(j) + 3hat(k)) m to (ahat(i) - 8hat(j) + 5hat(k)) m. If the work done by the force is 8j, the value of .a. is |
| Answer» <html><body><p>6<br/>4<br/>8<br/>-8</p>Answer :D</body></html> | |
| 37132. |
Aman of mass 60kg lifts a 15 kg mass to the top of a building of height 10 m in 5 minutes. H is efficiency is |
| Answer» <html><body><p>0.1<br/>0.2<br/>0.3<br/>0.4</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 37133. |
A wire is hanged from the ceiling without any weight below it, would there any stress in the wire ? |
| Answer» <html><body><p></p>Solution :Yes, it is because the <a href="https://interviewquestions.tuteehub.com/tag/weight-1451304" style="font-weight:bold;" target="_blank" title="Click to know more about WEIGHT">WEIGHT</a> of wire is acting as a deforming <a href="https://interviewquestions.tuteehub.com/tag/force-22342" style="font-weight:bold;" target="_blank" title="Click to know more about FORCE">FORCE</a>.</body></html> | |
| 37134. |
Displacement of a body is (5vec i+3 vecj-4vec k)m when a force (6 veci+6vecj+4veck)N acts for 5 sec. The power in watt is |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/16-276476" style="font-weight:bold;" target="_blank" title="Click to know more about 16">16</a>`<br/>`9.6`<br/>`6.4`<br/>`3.2`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 37135. |
The equation given below is the Vandar Wall's equation for a gas (P+(a)/(V^2))(V-b)=RT where P is the pressure, V is the volume, R is the universal gas constant and T is the temperature. Find the dimensions of a"/"b. |
| Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>></p>Solution :`[P]=((a)/(V^2))` (only quantities of similar dimension can be <a href="https://interviewquestions.tuteehub.com/tag/added-367625" style="font-weight:bold;" target="_blank" title="Click to know more about ADDED">ADDED</a> or <a href="https://interviewquestions.tuteehub.com/tag/subtracted-2258353" style="font-weight:bold;" target="_blank" title="Click to know more about SUBTRACTED">SUBTRACTED</a>) <br/> `[a]=[PV^(2)]` <br/> `[ML^(-1)T^(-2)][L^3]^(2)= [ML^(5)T^(-2)]` <br/> Similar, `[<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>]=[V]=[L^3]` <br/> `[(a)/(b)]=[(ML^(5)T^(-2))/(L^(3))]=[ML^(2)T^(-2)]`.</body></html> | |
| 37136. |
(A) When a body slides on rough surface, its momentum is not conserved. (B) When a ball falls from a height, momentum of earth ball system is conserved (C )In case of explosion of flying bomb, momentum is conserved |
| Answer» <html><body><p>A, <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a> are true<br/>A,B <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> are true<br/>A, C are false<br/>A is false</p>Answer :A</body></html> | |
| 37137. |
A stone is dropped from the top of a tower of height 60 m. At the same time, another stone is thrown up from the foot of the tower with a velocity 20 m/s. Calculate the displacement of the centre of mass of the two stones at time of collision. (g=10 m/s^(2)) |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Initially the centre of mass of the <a href="https://interviewquestions.tuteehub.com/tag/two-714195" style="font-weight:bold;" target="_blank" title="Click to know more about TWO">TWO</a> stones is at a height of <a href="https://interviewquestions.tuteehub.com/tag/30-304807" style="font-weight:bold;" target="_blank" title="Click to know more about 30">30</a> m from the ground. Acceleration of the centre of mass <br/> `= (mxxg+mxxg)/(m+m)`=g (downward)<br/> Let the stones colide after time t. <br/> At that time <a href="https://interviewquestions.tuteehub.com/tag/distance-116" style="font-weight:bold;" target="_blank" title="Click to know more about DISTANCE">DISTANCE</a> travelled by the first <a href="https://interviewquestions.tuteehub.com/tag/stone-1228007" style="font-weight:bold;" target="_blank" title="Click to know more about STONE">STONE</a> `= (1)/(2) "gt"^(2)` <br/> and distance travelled by the second stone = `ut -(1)/(2)"gt"^(2)` <br/> Now, `(1)/(2)"gt"^(2)+ut-(1)/(2)"gt"^(2)=60` <br/> `:.""t=(60)/(u)=(60)/(20)=3 s` <br/> Initital speed of the centre of mass, <br/> `u_("cm") = (mxx0+mxx20)/(m+m)` = 10 m/s (upward) <br/> `:.` Displacement of the centre of mass <br/> `= u_("cm")xxt-(1)/(2)"gt"^(2)=10xx3-(1)/(2)xx10xx9=-15`m <br/> Therefore, the centre of mass will move downward by 15 m.</body></html> | |
| 37138. |
A body projected up reaches a point A in its path at the end of 4^(th) second and reaches the ground after 5 seconds from the start. The height of A above the ground is (g=10ms^(2)) |
| Answer» <html><body><p>`19.6m`<br/>`30.6m`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/11m-268878" style="font-weight:bold;" target="_blank" title="Click to know more about 11M">11M</a>`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/20m-293046" style="font-weight:bold;" target="_blank" title="Click to know more about 20M">20M</a>`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 37139. |
The velocity of a particle under going SHM at the mean position is 4ms^(-1). Find the velocity of the particle at the point where is equal to half the amplitude. |
| Answer» <html><body><p>`2sqrt(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)<a href="https://interviewquestions.tuteehub.com/tag/ms-549331" style="font-weight:bold;" target="_blank" title="Click to know more about MS">MS</a>^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)`<br/>`5sqrt(3)ms^(-1)`<br/>`4sqrt(3)ms^(-1)`<br/>`3sqrt(3)ms^(-1)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 37140. |
Derive an expression for the time period (T)of a simple pendulum which may depend upon the mass (m) of the bob , length (l) of the pendulum and acceleration due to gravity(g). |
| Answer» <html><body><p></p>Solution :Let `T=km^(x) l^(y)g^(<a href="https://interviewquestions.tuteehub.com/tag/z-750254" style="font-weight:bold;" target="_blank" title="Click to know more about Z">Z</a>) ` where k is a <a href="https://interviewquestions.tuteehub.com/tag/dimensionless-954191" style="font-weight:bold;" target="_blank" title="Click to know more about DIMENSIONLESS">DIMENSIONLESS</a> constant.<br/> <a href="https://interviewquestions.tuteehub.com/tag/writing-25453" style="font-weight:bold;" target="_blank" title="Click to know more about WRITING">WRITING</a> the equation in dimensional form, we have `[M^(0)L^(0)t^(1)]=[M]^(x)[L]^(y)[LT^(-2)]^(z)=[M^(x)L^(Y+Z)T^(-<a href="https://interviewquestions.tuteehub.com/tag/2z-301338" style="font-weight:bold;" target="_blank" title="Click to know more about 2Z">2Z</a>)]`<br/> Equating exponent of M,L and T on both sides, <br/>we get `x=0,y+z=0,-2z=1`. <br/>Solving the eq., we get `x=0,y=1/2,z=-1/2` <br/> Hence , `T=ksqrt(l/g)`, where k is constant.</body></html> | |
| 37141. |
Spherical waves of frequency 1500 Hz are emitted from a 1.0 W source in an isotropic non-absorbing medium.What will the intensity and amplitude of the wave 1.0 m from the source if density of the medium be 1.3 kg m^(-3) and wave velocity is 300 ms^(-1). |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`7.96xx10^(-<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) <a href="https://interviewquestions.tuteehub.com/tag/w-729065" style="font-weight:bold;" target="_blank" title="Click to know more about W">W</a> m^(-2), 2.14xx10^(-<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>) m`</body></html> | |
| 37142. |
A block A of mass m_(1) rests on a horizontal table. A light string connected to it passes over a frictionless pulley at the edge of table and from its other end another block B of mass m_(2) is suspended. The coefficient of kinetic friction between the block and the table ismu_(k). When the block A is sliding on the table the tension in the string is |
| Answer» <html><body><p>`((m_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)+mu_(k)m_(1))g)/((m_(1)+m_(2)))`<br/>`((m_(2)-mu_(k)m_(1))g)/((m_(1)+m_(2)))`<br/>`(m_(1)m_(2)(1+mu_(k))g)/((m_(1)+m_(2)))`<br/>`(m_(1)m_(2)(1-mu_(k))g)/((m_(1)+m_(2)))`</p>Solution :Frictional force acting on block A = `mu_(k)m_(1)g` <br/> Hence resultant force on the blocks = `m_(2)g-mu_(k)m_(1)`g<br/> Their <a href="https://interviewquestions.tuteehub.com/tag/acceleration-13745" style="font-weight:bold;" target="_blank" title="Click to know more about ACCELERATION">ACCELERATION</a>, a = `(m_(2)g-mu_(k)m_(1)g)/(m_(1)+m_(2))` <br/> If the <a href="https://interviewquestions.tuteehub.com/tag/tension-1241727" style="font-weight:bold;" target="_blank" title="Click to know more about TENSION">TENSION</a> in the string is T, then for block B, <br/> `m_(2)g-T=m_(2)a` <br/> `:. T=m_(2)(g-a) = m_(2)g(1-(m_(2)-mu_(k)m_(1))/(m_(1)+m_(2)))` <br/> =`m_(2)g (m_(1)+mu_(k)m_(1))/(m_(1)+m_(2))` <br/> `=(m_(1)m_(2)(1+mu_(k))g)/(m_(1)+m_(2))` <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/CHY_DMB_PHY_XI_P1_U03_C02_E07_016_S01.png" width="80%"/></body></html> | |
| 37143. |
A girl swings in a cardle with period pi//4 second and amplitude 2m. A boy standing infront of it blows a whistle of natural frequency 1000Hz. The minimum frequency as heard by the girl is (Velocity of sound in air is 320ms^(-1)) |
| Answer» <html><body><p>`850Hz`<br/>`1000Hz`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/750hz-335447" style="font-weight:bold;" target="_blank" title="Click to know more about 750HZ">750HZ</a>`<br/>`950Hz`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`V_(0)=V_(g)=omegaA=(2piA)/(T)=(2pixx2)/(pi//4)=16m//s` <br/> `V_(s)=V_(b)=0n_(<a href="https://interviewquestions.tuteehub.com/tag/min-548008" style="font-weight:bold;" target="_blank" title="Click to know more about MIN">MIN</a>)=((<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>-V_(0))/(V))n`</body></html> | |
| 37144. |
A copper wire of length 2.2 m and a steel wire of length 1.6 m, both of diameter 3.0 mm, are connected end to end. When stretched by a load, the net elongation is found to be 0.70 mm. Obtain the load applied. Young's modulus of copper Y _(C) =1.1 xx 10 ^(11) Nm ^(-2) Young's modulus of steel Y _(S) =2.0 xx 10 ^(11) Nm^(-2). |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Let C copper and S for steel <a href="https://interviewquestions.tuteehub.com/tag/equal-446400" style="font-weight:bold;" target="_blank" title="Click to know more about EQUAL">EQUAL</a> radius of wire, <br/> `r = (3.0 xx 10 ^(-3))/( 2) = 1.5 xx 10 ^(-3) m` <br/> Length of copper wire `L _(C)=2.2 m` <br/> Length of steel wire `L _(S) = 1.6 m` <br/> Total increase in length for both wire, <br/> `Delta L _(C) + Delta L _(S) = 0.7 xx 10 ^(-3) m` <br/> Young.s modulus `=("Strees")/("Strain") = ("Stress")/((Delta L)/(L))` <br/> `therefore Y xx (Delta L )/(L)=` Stress [`because ` Strain `= (Delta)/(L)]` <br/> Stress on both <a href="https://interviewquestions.tuteehub.com/tag/thw-3217424" style="font-weight:bold;" target="_blank" title="Click to know more about THW">THW</a> wire is same, <br/> `therefore Y _(C) xx ( Delta L _(C))/( L _(C)) = Y _(S) xx ( Delta L _(S))/(L _(S))` <br/> `therefore (Delta L _(C))/( Delta L _(S)) = (Y_(S))/( Y _(C)) xx (L _(C))/( L _(S)) = (2.0 xx 10 ^(11))/(1.1 xx 10 ^(11)) xx (2.2)/(1.6)` <br/> `therefore (Delta L _(C))/(Delta L _(S))=2.5` <br/> Expanding `(Delta L _(C) + Delta L _(S))/( Delta L _(S)) = (2.5 + 1.0)/(1.0)` <br/> `therefore (0.7 xx 10 ^(-3))/( Delta L _(S))= 3.5` <br/> `therefore Delta L _(S) = (0.7 xx 10 ^(-3))/( 3.5) = 1/5 xx 10 ^(-3)` <br/> `= 2 xx 10 ^(-4) m` <br/> Now, `Delta L _(C) + Delta L _(S) =0.7 xx 10 ^(-3)` <br/> `therefore Delta L _(C) = 7 xx 10 ^(-4) -2 xx 10 ^(-4)` <br/> `= 5 xx 10 ^(-4) m` <br/> `therefore Y = ("Stress")/("Strain")` <br/> `therefore ` Stress `= Y xx` Strain <br/> `therefore F/A =Y xx` Strain <br/> `therefore F = Y xx` Strain ` xx A` <br/> `therefore F = Y _(S) xx (Delta L _(S))/(L _(S)) xx pi r ^(2)` <br/> `=2.0 xx 10 ^(11) xx(2.0 xx 10 ^(-4))/( 1.6) xx 3.14 xx (1.5 xx 10 ^(-3)) ^(2)=17.6625 xx 10 ^(1)` <br/> `therefore ~~1.8 xx 10 ^(2) <a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a>` where, F is appied load `F = Y_(C)xx (Delta L _(C))/(L _(C)) xx pi r ^(2)` From this formula load canbe calculate.<br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/KPK_AIO_PHY_XI_P2_C09_E02_004_S01.png" width="80%"/></body></html> | |
| 37145. |
When a block of iron floats in mercury at 0°C, a fraction K_1 of its volume is submerged, while at the temperature 60^(@)C, a fraction K_2 is seen to be submerged. If the coefficient of volume expansion of iron is gamma_(Fe) and that of mercury is gamma_(Hg) then the ration ( K_1)/(K_2) can be expressed as |
| Answer» <html><body><p>`( <a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>+ <a href="https://interviewquestions.tuteehub.com/tag/60-328817" style="font-weight:bold;" target="_blank" title="Click to know more about 60">60</a> gamma_(<a href="https://interviewquestions.tuteehub.com/tag/fe-460008" style="font-weight:bold;" target="_blank" title="Click to know more about FE">FE</a>))/( 1+ 60 gamma_(Hg))`<br/>`( 1- 60 gamma_(Fe))/( 1+ 60 gamma_(Hg))`<br/>`( 1+ 60 gamma_(Fe))/( 1-60 gamma_(Hg))`<br/>`( 1+ 60 gamma_(Hg))/( 1+ 60 gamma_(Fe))`</p>Answer :A</body></html> | |
| 37146. |
A gas has pressures 100 cm and 136.99 cm of Hg temperatures 0^(@)C" and "100^(@)C under constant volume. Calculate the pressure coefficient ? |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>.699 <a href="https://interviewquestions.tuteehub.com/tag/times-1420471" style="font-weight:bold;" target="_blank" title="Click to know more about TIMES">TIMES</a> <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(-3)//^(@)<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>`</body></html> | |
| 37147. |
If amplitude of particle executing SHM is doubled, which of the following quantites are doubled a.Time period b. Maxomum velocity c. Maximum acceleration d. total energy |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a> and <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a><br/>a, b and c<br/>a and c <br/>a, b, c and d</p>Answer :A</body></html> | |
| 37148. |
If the change in the value of g at a height h above the surface of the earth is same as at depth .x. below the surface of the earth,then (h lt lt R) |
| Answer» <html><body><p>d=h<br/>d=2h<br/>`d=(<a href="https://interviewquestions.tuteehub.com/tag/3h-310742" style="font-weight:bold;" target="_blank" title="Click to know more about 3H">3H</a>)/<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>`<br/>`d=h/2`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 37149. |
The length and breadth of a table are (125+-0.4)cm and (75+-0.5)cm respectively. What is the area of the table? |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Length of the small <a href="https://interviewquestions.tuteehub.com/tag/piece-1154494" style="font-weight:bold;" target="_blank" title="Click to know more about PIECE">PIECE</a> `=(15.1+-0.1)-(11.9+-0.2)`. The <a href="https://interviewquestions.tuteehub.com/tag/error-25548" style="font-weight:bold;" target="_blank" title="Click to know more about ERROR">ERROR</a> in the length of this remaining pencil `=0.2=0.1+` error in the length of small piece, which should be 0.1. So the length of the small piece `=(15.1-11.9)+-0.1=(3.2+-1)<a href="https://interviewquestions.tuteehub.com/tag/cm-919986" style="font-weight:bold;" target="_blank" title="Click to know more about CM">CM</a>`</body></html> | |
| 37150. |
A square plate of moment of inertia 'I' is pivoted at its centre. It has a small projection of neglegible mass to one of its sides. A particle of mass 'm' moving with a velocity v parallel to the side having projection strikes to projection and stricks to it. If 'l' is the side length, the angular velocity of plate is |
| Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/mvl-2164932" style="font-weight:bold;" target="_blank" title="Click to know more about MVL">MVL</a>)/(2[I+(<a href="https://interviewquestions.tuteehub.com/tag/ml-548251" style="font-weight:bold;" target="_blank" title="Click to know more about ML">ML</a>^(2))/(4)])`<br/>`(mvl)/(2[I+ml^(2)])`<br/>`(mvl)/(<a href="https://interviewquestions.tuteehub.com/tag/2i-300397" style="font-weight:bold;" target="_blank" title="Click to know more about 2I">2I</a>)`<br/>`(mvl)/(<a href="https://interviewquestions.tuteehub.com/tag/4i-318769" style="font-weight:bold;" target="_blank" title="Click to know more about 4I">4I</a>)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |