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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 37051. |
The mean free path of molecules of a gas (radius 'r') is inversely proportional to |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>r<br/>`<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(r)`<br/>`r^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 37052. |
Which of the following Kepler's laws is also known as harmonic law? |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/first-461760" style="font-weight:bold;" target="_blank" title="Click to know more about FIRST">FIRST</a> law<br/>Second law<br/><a href="https://interviewquestions.tuteehub.com/tag/third-1414358" style="font-weight:bold;" target="_blank" title="Click to know more about THIRD">THIRD</a> law<br/>None of these</p>Solution :(<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> ) <a href="https://interviewquestions.tuteehub.com/tag/kepler-531882" style="font-weight:bold;" target="_blank" title="Click to know more about KEPLER">KEPLER</a>'s third law is <a href="https://interviewquestions.tuteehub.com/tag/also-373387" style="font-weight:bold;" target="_blank" title="Click to know more about ALSO">ALSO</a> known as harmonic law.</body></html> | |
| 37053. |
The kinetic theory of gases gives the formula PV=(1)/(3)Nmv^(bar2) for the pressure P exerted by a gas enclosed in a volume V. The term Nm represents |
| Answer» <html><body><p>the mass of a mole of the gas<br/>the mass of the gas present in the <a href="https://interviewquestions.tuteehub.com/tag/volume-728707" style="font-weight:bold;" target="_blank" title="Click to know more about VOLUME">VOLUME</a> V<br/>the <a href="https://interviewquestions.tuteehub.com/tag/average-13416" style="font-weight:bold;" target="_blank" title="Click to know more about AVERAGE">AVERAGE</a> mass of <a href="https://interviewquestions.tuteehub.com/tag/one-585732" style="font-weight:bold;" target="_blank" title="Click to know more about ONE">ONE</a> molecule of the gas<br/>the total number of molecules present in volume V</p>Answer :B</body></html> | |
| 37054. |
The length of a seconds pendulum at a place is 1.02m. Find the time period of another pendulum of length 0.51m at the same place. |
| Answer» <html><body><p></p>Solution :The <a href="https://interviewquestions.tuteehub.com/tag/time-19467" style="font-weight:bold;" target="_blank" title="Click to know more about TIME">TIME</a> period of a <a href="https://interviewquestions.tuteehub.com/tag/simple-1208262" style="font-weight:bold;" target="_blank" title="Click to know more about SIMPLE">SIMPLE</a> pendulum is `T=2pisqrt((l)/(g))`………….(1) <br/> i.e., `(l)/(T^(2))= (g)/(4pi^(2))= "constant"` <br/> at a given place ……………(2) <br/> If `T_(1)` and `T_(2)` are the time periods of the pendulum for length `l_(1)` and `l_(2)`. From Eq(2) we cab <a href="https://interviewquestions.tuteehub.com/tag/write-746491" style="font-weight:bold;" target="_blank" title="Click to know more about WRITE">WRITE</a> <br/> `(l_(1))/(T_(1)^(2))= (l_(2))/(T_(2)^(2))`..............(2) <br/> Here `T_(1)=2s` when `l_(1)= 1.02m` when `l_(2)= 0.5 m, T_(2)=? `<br/> Using Eq. (3)`(1.02)/(2^(2))= (0.51)/(T_(2)^(2))` or `T_(2)^(2)= (0.51)/(1.02) xx 4 =2 ` <br/> `:. T_(2)= sqrt(2) = 1.414 s` When the lenght increases the time period of the pendulum increases. So the clock loses time or <a href="https://interviewquestions.tuteehub.com/tag/runs-1192287" style="font-weight:bold;" target="_blank" title="Click to know more about RUNS">RUNS</a> slow.</body></html> | |
| 37055. |
A drop of water breaks into two droplets of equal size. In this process which of the following statements is correct? |
| Answer» <html><body><p>The sum of the <a href="https://interviewquestions.tuteehub.com/tag/temperature-11887" style="font-weight:bold;" target="_blank" title="Click to know more about TEMPERATURE">TEMPERATURE</a> of the <a href="https://interviewquestions.tuteehub.com/tag/two-714195" style="font-weight:bold;" target="_blank" title="Click to know more about TWO">TWO</a> droplets together is equal to the <a href="https://interviewquestions.tuteehub.com/tag/original-1139424" style="font-weight:bold;" target="_blank" title="Click to know more about ORIGINAL">ORIGINAL</a> temperature of the drop <br/>The sum of the masses of the droplets is equal to the originl mass of the drop<br/>The sum of the radii of the two droplets is equal to the radius of the original drop<br/>The sum of the surface areas of the two droplets is equal to the surface <a href="https://interviewquestions.tuteehub.com/tag/area-13372" style="font-weight:bold;" target="_blank" title="Click to know more about AREA">AREA</a> of the original drop </p>Answer :B</body></html> | |
| 37056. |
A large cylindrical chamber has a massless piston fitted at the top. An acoustic source is situated at the centre of the bottom of the cylinder, while an observer is situated at the bottom circumference (inside the chamber). The observer is moving directly towards the source with constant velocity and hears a frequency f. If the chamber were to be isochorimally heated then, the observed frequency will be : |
| Answer» <html><body><p>same as `f`<br/>higher than `f`<br/>lower than `f`<br/>Data insufficient<br/></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/use-1441041" style="font-weight:bold;" target="_blank" title="Click to know more about USE">USE</a> <a href="https://interviewquestions.tuteehub.com/tag/doppler-441774" style="font-weight:bold;" target="_blank" title="Click to know more about DOPPLER">DOPPLER</a>'s effect, the speed of sound <a href="https://interviewquestions.tuteehub.com/tag/increases-1040626" style="font-weight:bold;" target="_blank" title="Click to know more about INCREASES">INCREASES</a> with increase in temperature.</body></html> | |
| 37057. |
A metal block of area 0.10 m^2 is connected to a 0.010 kg mass via a string that passes over an ideal pulley(considered massless and frictionless) as in Fig 10.15 A liquid with a film thickness of 0.30 mm is placed between the block and the table . When released the block moves to the right with a constant speed of 0.085 ms^-1. FInd the coefficienyt of viscosity of the liquid. |
| Answer» <html><body><p></p>Solution :The metal <a href="https://interviewquestions.tuteehub.com/tag/block-18865" style="font-weight:bold;" target="_blank" title="Click to know more about BLOCK">BLOCK</a> moves to the <a href="https://interviewquestions.tuteehub.com/tag/right-1188951" style="font-weight:bold;" target="_blank" title="Click to know more about RIGHT">RIGHT</a> because of the <a href="https://interviewquestions.tuteehub.com/tag/tension-1241727" style="font-weight:bold;" target="_blank" title="Click to know more about TENSION">TENSION</a> in the string. The tension T is equal in magnitude to the weight of the suspended mass m. Thus the shear force F is `F=T=mg=0.010 <a href="https://interviewquestions.tuteehub.com/tag/kg-1063886" style="font-weight:bold;" target="_blank" title="Click to know more about KG">KG</a> times 9.8 ms^-2=9.8 times 10^-2 N` <br/> Shear stress on the fluid =`F//A=(9.8 times 10^-2)/0.10 N//m^2` <br/> Strain rate `=v/l=0.08/(0.30 times 10^-3)` <br/> `n=("stress")/("strainrate") s^-1` <br/> `=((9.8 times 10^-2 N)(0.30 times 10^-3 m))/((0.085 ms^-1)(0.10 m^2))` <br/> `=3.46 times 10^-3 Pas`</body></html> | |
| 37058. |
If C_(P) and C_(P) denote the specific heat (per unit mass of an ideal gas of moleculat weight M, then (where R is the molar gas constant) |
| Answer» <html><body><p>`c_(P)-c_(<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>)=<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>//M^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>`c_(P)-c_(V)=R `<br/>`c_(P)-c_(V)=R//M `<br/>`c_(P)-c_(V)=MR `</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :C</body></html> | |
| 37059. |
(A): The gravitational force between the gas molecules is ineffective due to extermely small size and very high speed. (R): No force of interaction acts between molecules of an ideal gas. |
| Answer» <html><body><p>Both (A) and ( <a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>) are <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a> and (R ) is the <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> explanation of (A)<br/>Both (A) and (R ) are true and (R) is not the correct explanation of (A) <br/>(A) is true but (R ) is false <br/>Both (A) and (R ) are false </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :B</body></html> | |
| 37060. |
Can we convent water at 0^(0)C into ice by dropping ice into it. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :No, there will be no <a href="https://interviewquestions.tuteehub.com/tag/exchange-454713" style="font-weight:bold;" target="_blank" title="Click to know more about EXCHANGE">EXCHANGE</a> of <a href="https://interviewquestions.tuteehub.com/tag/heat-21102" style="font-weight:bold;" target="_blank" title="Click to know more about HEAT">HEAT</a>.</body></html> | |
| 37061. |
A ball is thrown vertically upwards. Which of the following graph/graphs represent velocity y=time graph of the ball during its flight (air resistance is neglected) |
| Answer» <html><body><p><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_DOC_OBJ_PHY_XI_V01_A_C03_E01_049_O01.png" width="30%"/><br/><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_DOC_OBJ_PHY_XI_V01_A_C03_E01_049_O02.png" width="30%"/><br/><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_DOC_OBJ_PHY_XI_V01_A_C03_E01_049_O03.png" width="30%"/><br/><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_DOC_OBJ_PHY_XI_V01_A_C03_E01_049_O04.png" width="30%"/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 37062. |
An isolated rail car of mass M is moving alongastraight, frictionless track at an initial speed v_(0). The car is passing under a bridge when a crate filled with N bowling balls, each of mass m, is dropped from the bridge into the bed of the rail car. the crate splits open and the bowling balls bounce around inside the rail car, but none of them fall out. (A). Is the momentum of the ratil car+bowling balls system conserved in this collision? |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A::<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 37063. |
A simple pendulum of length 0.2m has bob of mass 5gm, it is pulled aside through an angle 60^(@) from the vertical. A spherical body of mass 2.5 gm is placed at the lowest position of the bob. When the bob is released it strikes the spherical body and comes to rest. What is the velocity of the spherical body? (g= 9.8 ms^(-2)) (in m/s) |
| Answer» <html><body><p>`1.4`<br/>`2.8`<br/>`3.5`<br/>`4.9`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 37064. |
A block of mass 'M' moving on the firctionless horizontal surface collides with the spring of spring constant 'k'. The other end of the spring is rigidly fixed to a vertical wall. If the spring is comressed by L, the maximum momentum of the block after collision is : |
| Answer» <html><body><p>`sqrt(<a href="https://interviewquestions.tuteehub.com/tag/mk-548207" style="font-weight:bold;" target="_blank" title="Click to know more about MK">MK</a>)<a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a>`<br/>`(kL^2)/(<a href="https://interviewquestions.tuteehub.com/tag/2m-300757" style="font-weight:bold;" target="_blank" title="Click to know more about 2M">2M</a>)`<br/>zero<br/>`(ML^2)/(<a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>)`</p>Answer :B</body></html> | |
| 37065. |
The component of a vector r along X-axis will have maximum value if |
| Answer» <html><body><p>r is <a href="https://interviewquestions.tuteehub.com/tag/along-1974109" style="font-weight:bold;" target="_blank" title="Click to know more about ALONG">ALONG</a> positive Y-axis<br/>r is along positive X-axis<br/>r makes an angle of `<a href="https://interviewquestions.tuteehub.com/tag/45-316951" style="font-weight:bold;" target="_blank" title="Click to know more about 45">45</a>^(@)` with the X-axis <br/>r is along <a href="https://interviewquestions.tuteehub.com/tag/negative-570381" style="font-weight:bold;" target="_blank" title="Click to know more about NEGATIVE">NEGATIVE</a> Y-axis</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 37066. |
An isolated rail car of mass M is moving alongastraight, frictionless track at an initial speed v_(0). The car is passing under a bridge when a crate filled with N bowling balls, each of mass m, is dropped from the bridge into the bed of the rail car. the crate splits open and the bowling balls bounce around inside the rail car, but none of them fall out. (B).What is the average speed of the rail car + bowling balls system some time after the collision? |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 37067. |
Explain the statement, "The accuracy of the measurement, can be made not by absolute error but by percentage error only. |
| Answer» <html><body><p></p>Solution :Suppose the <a href="https://interviewquestions.tuteehub.com/tag/length-1071524" style="font-weight:bold;" target="_blank" title="Click to know more about LENGTH">LENGTH</a> of two <a href="https://interviewquestions.tuteehub.com/tag/different-951434" style="font-weight:bold;" target="_blank" title="Click to know more about DIFFERENT">DIFFERENT</a> objects measured by the same Vernier <a href="https://interviewquestions.tuteehub.com/tag/calipers-412402" style="font-weight:bold;" target="_blank" title="Click to know more about CALIPERS">CALIPERS</a> are `+-0.1 cm and 8.05 +-0.01`respectively. <br/> Here the absolute error (0.01 cm.) is same in both the measurements. <br/> Percentage error in first measurement `=(0.01)/(2.20)xx100%xx100%=0.12%` <br/> Hence absolute error being same for both measurements, still the percentage error in larger measurement is small and <a href="https://interviewquestions.tuteehub.com/tag/smaller-1213327" style="font-weight:bold;" target="_blank" title="Click to know more about SMALLER">SMALLER</a> measurement is <a href="https://interviewquestions.tuteehub.com/tag/large-1066424" style="font-weight:bold;" target="_blank" title="Click to know more about LARGE">LARGE</a>. Hence it can be said that if percentage error is smaller then that measurement is more accurate.</body></html> | |
| 37068. |
Calculate the surface tension of water ass uming that the density of water is 1000Kgm^(-3), angle of contact 0^(@), acceleration due to gravity is 9.8mS^(-2), radius of capillary tube is 0.2 mm, and the rise of water in the capillary tube is 6.3 cm. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`6.174xx10^(-<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)<a href="https://interviewquestions.tuteehub.com/tag/nm-579234" style="font-weight:bold;" target="_blank" title="Click to know more about NM">NM</a>^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)`</body></html> | |
| 37069. |
Calculate the ratio of electromagnetic and gravitational forces between two electrons. (charge of the electrons= e = 1.6 xx 10^(-19) C,mass of the electron = m = 9.1 xx 10^(-31) kg , permittivity of free space (1)/(4pi epsi_0) = 9 xx 10^9 (N-m^2)/(C^2) universal gravitational constant G =6.67 xx 10^(-11) (N-m^2)/(kg^2) |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`4.17 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 10^42`</body></html> | |
| 37070. |
The lower end of a capillary tube of diameter 2.00mm is dipped 8.00cm below the surface of water in a beaker. What is the pressure required in the tube in order to blow a hemispherical bubble at its end in water? The surface tension of water at temperature of the experiments is 7.30 times 10^2 Nm^-1.1 atmospheric pressure =1.01 times 10^5 Pa density of water =1000 kg//m^3,g=9.80 ms^-2. Also calculate the excess pressure. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a></body></html> | |
| 37071. |
The energy (E), angular momentum (L) and universal gravitational constant (G) are chosen as fundamental quantities. The dimensions of universal gravitational constant in the dimensional formula of Planck's constant h is |
| Answer» <html><body><p>zero<br/>`-1`<br/>`5//3`<br/>`1`<br/></p>Solution :(a) `hprop G^(<a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a>)<a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a>^(y)E^(z)`<br/> <a href="https://interviewquestions.tuteehub.com/tag/write-746491" style="font-weight:bold;" target="_blank" title="Click to know more about WRITE">WRITE</a> the dimensions on both sides <br/> `[<a href="https://interviewquestions.tuteehub.com/tag/ml-548251" style="font-weight:bold;" target="_blank" title="Click to know more about ML">ML</a>^(2)T^(-1)]prop[M^(-1)L^(3)T^(-2)]^(x)[ML^(2)T^(-1)]^(y)[ML^(2)T^(-2)]^(z)` <br/> `[ML^(2)T^(-1)]=k[M^(-1)L^(3)T^(-2)]^(x)[ML^(2)T^(-1)]^(y)[ML^(2)T^(-2)]^(z)` <br/> Comparing the powers, we get <br/> `1=-x+y+z`...........(i) <br/> `2=3x+2y+2z` .........(ii) <br/> `-1=-2x=y-2z`...........(iii) <br/> On solving eqs (i), (ii) and (iii) we <a href="https://interviewquestions.tuteehub.com/tag/ger-468132" style="font-weight:bold;" target="_blank" title="Click to know more about GER">GER</a> <br/> `x=0`</body></html> | |
| 37072. |
In a projectile motion the velocity (a) is always perpendicular to the acceleration (b) is not always perpendicular to the acceleration (c) is perpendicular to the acceleration for one instant only (d) is perpendicular to the acceleration for two instants. |
| Answer» <html><body><p>a & <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a> are correct<br/>b & c are correct<br/>c & d are correct<br/>a & d are correct</p>Answer :B</body></html> | |
| 37073. |
A U-tube has two vertical limbs of diameters 4mm and 5mm. When water is poured into it, the water level difference between the limbs is (T = 70dyne cm^(-1) ) (g=10ms^(-2)) |
| Answer» <html><body><p>0.14 cm<br/>0.014 m<br/>14 mm<br/>0.14 mm</p>Answer :A</body></html> | |
| 37074. |
After perfectly inelastic collision between two identical particles moving with same speed in different directions, the speed of the combined particle becomes half the initial speed of either particle. The angle between the velocities of the two before collision is |
| Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>></p>Solution :In <a href="https://interviewquestions.tuteehub.com/tag/perfectly-7309466" style="font-weight:bold;" target="_blank" title="Click to know more about PERFECTLY">PERFECTLY</a> inelastic collision between two particles, linerar momentum is conserved. `Let theta ` be the <a href="https://interviewquestions.tuteehub.com/tag/angle-875388" style="font-weight:bold;" target="_blank" title="Click to know more about ANGLE">ANGLE</a> between the velocities of the two particles before collision . Then <br/> `p _(2) = p _(1) ^(2) + 2 p _(i) p_(2) cos theta or (2m (v )/(2)) ^(2) = (mv) ^(2)+ (mv) ^(2) + 2 (mv ) (mv) cos theta` <br/> or `1=1 + 1+ 2 cos theta or cos theta = - 1/2 , (or) theta = 120^(@)`</body></html> | |
| 37075. |
A capillary tube is immersed in water and the mass of water that rises in the capillary tube is 5xx10^(-3)Kg. If another tube of half the radius is immersed then the masss of water tha twill rise in the capillary tube is |
| Answer» <html><body><p>`7.<a href="https://interviewquestions.tuteehub.com/tag/5xx10-1901302" style="font-weight:bold;" target="_blank" title="Click to know more about 5XX10">5XX10</a>^(-3)kg`<br/>`2.5xx10^(-3)kg`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/1xx10-1804645" style="font-weight:bold;" target="_blank" title="Click to know more about 1XX10">1XX10</a>^(-3)kg`<br/>`5xx10^(-3)kg`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 37076. |
In the above problem tension in the string attached to the bob in position B isx g cos theta. Then x is |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a></body></html> | |
| 37077. |
An electron moving with velocity 2.2 xx 10^(6) m/s, revolving in circular orbit of radius 0.53 Å. Calculate its angular velocity. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`v= 2.2 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(6)` m/s <br/> `r= 0.53 A= 0.53 xx 10^(-10)`m <br/> Angular velocity `<a href="https://interviewquestions.tuteehub.com/tag/omega-585625" style="font-weight:bold;" target="_blank" title="Click to know more about OMEGA">OMEGA</a>= (v)/(r)= (2.2 xx 10^(6))/(0.53 xx 10^(-10))` <br/> `omega= 4.15 xx 10^(16) rad s^(-1)`</body></html> | |
| 37078. |
According to Dalton's law of partial pressure |
| Answer» <html><body><p>p=(`p_(1)+P_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`+….) <br/>p(`n_(1)+n_(2)`+…..)`k_(B)T`<br/>Both 1 and 2 are correct<br/>both 1 and 2 are correct</p>Answer :C</body></html> | |
| 37079. |
Value of friction depend on …... and …... . |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/type-715478" style="font-weight:bold;" target="_blank" title="Click to know more about TYPE">TYPE</a> and <a href="https://interviewquestions.tuteehub.com/tag/material-1089170" style="font-weight:bold;" target="_blank" title="Click to know more about MATERIAL">MATERIAL</a> of <a href="https://interviewquestions.tuteehub.com/tag/surface-1235573" style="font-weight:bold;" target="_blank" title="Click to know more about SURFACE">SURFACE</a> in <a href="https://interviewquestions.tuteehub.com/tag/contact-25916" style="font-weight:bold;" target="_blank" title="Click to know more about CONTACT">CONTACT</a>.</body></html> | |
| 37080. |
Water drops fall from the roof of a building 20 m high at regular time intervals. If the first drop strikes the floor when the sixth drop begins to fall, the heights of the second and fourth drops from the ground at that instant are |
| Answer» <html><body><p>12.8 m and 3.2m<br/>12.8 m and 7.2 m<br/>19.2 m and 0.8 m<br/>7.2 m and 16.8 m</p>Answer :D</body></html> | |
| 37081. |
A uniform circular disc has a radius of 20cm. A circular disc of radius 10cm is cut concentrically from the original disc. The shift in centre of mass is |
| Answer» <html><body><p>`(1)/(200)<a href="https://interviewquestions.tuteehub.com/tag/cm-919986" style="font-weight:bold;" target="_blank" title="Click to know more about CM">CM</a>`<br/>`(<a href="https://interviewquestions.tuteehub.com/tag/7-332378" style="font-weight:bold;" target="_blank" title="Click to know more about 7">7</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/300-305868" style="font-weight:bold;" target="_blank" title="Click to know more about 300">300</a>)cm`<br/>`(1)/(<a href="https://interviewquestions.tuteehub.com/tag/400-315233" style="font-weight:bold;" target="_blank" title="Click to know more about 400">400</a>)cm`<br/>zero</p>Answer :D</body></html> | |
| 37082. |
A cylinder containing an ideal gas is in vertical position and has a piston of mass M that is able to move up or down without friction. Fig. if the temperature is increased. |
| Answer» <html><body><p>both `p` and `<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>` of the gas will change. <br/>only `p` will increase according to Charle's law<br/>`V` will change but not `p`.<br/>`p` will change but not `V`. </p>Solution :As piston is of fixed mass M, and it is able to <a href="https://interviewquestions.tuteehub.com/tag/move-548879" style="font-weight:bold;" target="_blank" title="Click to know more about MOVE">MOVE</a> up or down with out <a href="https://interviewquestions.tuteehub.com/tag/friction-21545" style="font-weight:bold;" target="_blank" title="Click to know more about FRICTION">FRICTION</a>, therefore, when temperature is increased, piston movesout, <a href="https://interviewquestions.tuteehub.com/tag/increasing-1040633" style="font-weight:bold;" target="_blank" title="Click to know more about INCREASING">INCREASING</a> the <a href="https://interviewquestions.tuteehub.com/tag/volume-728707" style="font-weight:bold;" target="_blank" title="Click to know more about VOLUME">VOLUME</a> V. The pressure p on the gas remains the same, because of fixed mass.</body></html> | |
| 37083. |
The human ciculatory system can be thought of as a closed system of interconnecting pipes through which fluid is continuously circulated by two pumps the two pumps the right and left verticles of the heart, work as simple two-stroke force pumps. The muscles of the heart regulate the force by contracting and relaxing. the contraction (systole) lasts about 0.2s and a complete systole/diastole (contraction/relaxation) cycle lasts about 0.8s. For flood pressures and speeds in the normal range. the volume flow rate of blood through a blood vessel is directly proportional tot he pressure difference over a length of the vessel and to the fourth power of the radius of the vessel. The total mechanical energy per unit volume of blood just as it leaves the heart is E//V=rhogh+P+rhov^(2) Q. During intense exercise the volume of blood pumped per second by an athlete,s heart increases by a factor of 7, and his blood pressure increases by 20%/by what factor does the power output of the heart increase during exercise? |
| Answer» <html><body><p>1.2<br/>3.5<br/>7<br/>8.4</p>Answer :D</body></html> | |
| 37084. |
The human ciculatory system can be thought of as a closed system of interconnecting pipes through which fluid is continuously circulated by two pumps the two pumps the right and left verticles of the heart, work as simple two-stroke force pumps. The muscles of the heart regulate the force by contracting and relaxing. the contraction (systole) lasts about 0.2s and a complete systole/diastole (contraction/relaxation) cycle lasts about 0.8s. For flood pressures and speeds in the normal range. the volume flow rate of blood through a blood vessel is directly proportional tot he pressure difference over a length of the vessel and to the fourth power of the radius of the vessel. The total mechanical energy per unit volume of blood just as it leaves the heart is E//V=rhogh+P+rhov^(2) Q. The blood pressure in a capillary bed is essentially zero, allowing blood to flow extremely slowly through the tissues in order to maximize exhange of gases nutrients and waste products what is the work on 200cm^(3) of blood against gravity to bring it to the capillaries to the brain 50 cm above the heart? |
| Answer» <html><body><p>5145 J<br/>105 J<br/>10 J<br/>1 J</p>Answer :D</body></html> | |
| 37085. |
The human ciculatory system can be thought of as a closed system of interconnecting pipes through which fluid is continuously circulated by two pumps the two pumps the right and left verticles of the heart, work as simple two-stroke force pumps. The muscles of the heart regulate the force by contracting and relaxing. the contraction (systole) lasts about 0.2s and a complete systole/diastole (contraction/relaxation) cycle lasts about 0.8s. For flood pressures and speeds in the normal range. the volume flow rate of blood through a blood vessel is directly proportional tot he pressure difference over a length of the vessel and to the fourth power of the radius of the vessel. The total mechanical energy per unit volume of blood just as it leaves the heart is E//V=rhogh+P+rhov^(2) Q. What is the gravitational potential energy of 8cm^(3) of blood in a 1.8 m tall man, in a blood vessel 0.3 m above his heart? (Note: The man's blood pressure is 1.3xx10^(4)N//m^(2)) |
| Answer» <html><body><p>`1xx10^(-4)<a href="https://interviewquestions.tuteehub.com/tag/j-520843" style="font-weight:bold;" target="_blank" title="Click to know more about J">J</a>`<br/>`2.5xx10^(-2)J`<br/>`301xx10^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)J`<br/>`3xx10^(6)J`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 37086. |
A ring is suspended from a point S on its rim as shown in the figure. When displaced from equilibrium, it oscillates with time period of 2 seconds. The radius of the ring is (take g = pi^(2)) |
| Answer» <html><body><p>0.5m<br/>0.5m<br/>0.15m<br/>1.0m</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 37087. |
Uranium has two isotopes of masses 235 and 238 units. If both of them are present in uranium hexafluoride gas, find the percentage ratio of difference in rms velocities of two isotopes to the rms velocity of heavier isotope. |
| Answer» <html><body><p>1.64<br/>0.064<br/>0.64<br/>6.4</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 37088. |
In column - I names of measuring instruments are mentioned and column - II possible type of errors are specified - Match the columns appropriately.{:(,"Column - I",,"Column - II"),((A),"Vernier callipers",(P),"Back lash error"),((B),"Screw gauge",(Q),"Positive zer error"),((C ),"Travelling microscope",(R ),"Negative zero error"),((D),"Meter scale",(S),"No error"):} |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A-QRS; B-PQRS; C-PQRS; D-S</body></html> | |
| 37089. |
If two bodies are in thermal equilibrium, then their temperature must be equal'. State whether the statementis true or false. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`"<a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a>"`</body></html> | |
| 37090. |
coefficient of real expansion of mercury is0.18 xx 10^(-3) //""^(@) C. If the density of mercury at 0^(@) C is 13.6 gm/c.c, its density at 573K will be |
| Answer» <html><body><p>12.90 gm/c.c<br/>13.10 gm/c.c<br/>12.95 gm/c.c<br/>12.75 gm/c.c</p>Answer :A</body></html> | |
| 37091. |
Assertion: Each vibrational mode gives two degrees of freedom. Reason: By law of equipartition of energy, the energy for each degree of freedom in thermal equlibrium is 2k_(B)T. |
| Answer» <html><body><p>If both assertion and reason are true and reason is the correct <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> os assertion. <br/>If both assertion and reason are true but reason is not be correct explanation of assertion. <br/>If assertion is true but reason is false. <br/>If both assertion and reason are false. </p>Solution :By <a href="https://interviewquestions.tuteehub.com/tag/law-184" style="font-weight:bold;" target="_blank" title="Click to know more about LAW">LAW</a> of equipartition of energy, the energy for each degree of <a href="https://interviewquestions.tuteehub.com/tag/freedom-999700" style="font-weight:bold;" target="_blank" title="Click to know more about FREEDOM">FREEDOM</a> in thermal <a href="https://interviewquestions.tuteehub.com/tag/equilibrium-974342" style="font-weight:bold;" target="_blank" title="Click to know more about EQUILIBRIUM">EQUILIBRIUM</a> is `1/2k_(B)T.`<br/> Each <a href="https://interviewquestions.tuteehub.com/tag/quadratic-610697" style="font-weight:bold;" target="_blank" title="Click to know more about QUADRATIC">QUADRATIC</a> term from in the total energy rxpression of a molecules is to be conunted as a degree of freedom. Thus each vibriational mode gives 2 degrees of freedom i.e., kinetic and potential energy modes, corresponding to the energy `2((1)/(2)k_(BT))=k_(B)T.`</body></html> | |
| 37092. |
The temperature of a furnace is 2324^(@)C and the intensity is maximum in its radiation spectrum nearly at 12000A . If the intensity in the spectrum of a star is maximum nearly at 4800A, calculate the surface temperature of the star. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`T_(2)=lamda_(<a href="https://interviewquestions.tuteehub.com/tag/m1-546405" style="font-weight:bold;" target="_blank" title="Click to know more about M1">M1</a>)T_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)//lamda_(m2)=12000xx10^(-8)xx2597//4800xx10^(-8)=6492.5` K</body></html> | |
| 37093. |
A spring of force constant 800N/m has an extension of 5cm. The work done in extending it from 5cm to 15cm is |
| Answer» <html><body><p>16J<br/>8J<br/>32J<br/>24J</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a></body></html> | |
| 37094. |
The efficiency of Carnot engine is 50% and temperature of sink is 500 K. If temperature of source is kept constant and its efficiency raised to 60%, then the required temperature of sink will be |
| Answer» <html><body><p>100 K<br/>600 K<br/>400 K<br/>500 K</p>Solution :The efficiency of a Carnot <a href="https://interviewquestions.tuteehub.com/tag/engine-25861" style="font-weight:bold;" target="_blank" title="Click to know more about ENGINE">ENGINE</a> is `eta = <a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a> - (T_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))/(T_(1))` where `T_(1)` is the temperature of the source and `T_(2)` is the temperature of the <a href="https://interviewquestions.tuteehub.com/tag/sink-1210432" style="font-weight:bold;" target="_blank" title="Click to know more about SINK">SINK</a>. <br/> Here, `T_(2) = 500 K, eta = 50%, T_(1) = ?` <br/> `:. 0.5 = 1 - (500)/(T_(1))` or `T_(1) = 1000 K` <br/> Let `T._(2)` be the new sink temperature. Then <br/> `eta. = 1- (T._(2))/(T_(1)) :. 0.6 = 1 - (T._(2))/(1000)` <br/> or `T._(2) = 400 K`</body></html> | |
| 37095. |
A source producing sound of frequency 170 Hz is approaching a stationary observer with a velocity 17 ms^(-1). The apparnet change in the wavelength of sound heard by the observer is (speed of sound in air =340 ms^(-1)) |
| Answer» <html><body><p>`0.2 m`<br/>`0.1 m`<br/>`0.5 m`<br/>`0.4 m`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`lambda=(v)/(<a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a>)=(340)/(<a href="https://interviewquestions.tuteehub.com/tag/170-278357" style="font-weight:bold;" target="_blank" title="Click to know more about 170">170</a>)=<a href="https://interviewquestions.tuteehub.com/tag/2m-300757" style="font-weight:bold;" target="_blank" title="Click to know more about 2M">2M</a>` <br/> `n'=(340)/(340-17)xx170` <br/> `n=178.9 Hz` <br/> Now, `lambda'= (v)/(n)=(340)/(178.9)=1.9` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/rarr-1175461" style="font-weight:bold;" target="_blank" title="Click to know more about RARR">RARR</a> lambda- lambda'=2-1.9=0.1 m`</body></html> | |
| 37096. |
A tension of 20 N is applied to a copper wire of cross sectional area 0.01 cm^(2), Young's modulus of copper is 1.1 xx 10^11N//m^(2) and Poisson's ratio is 0.32. The decrease in cross sectional area of the wire is |
| Answer» <html><body><p>`1.16 xx 10^(-<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>) "<a href="https://interviewquestions.tuteehub.com/tag/cm-919986" style="font-weight:bold;" target="_blank" title="Click to know more about CM">CM</a>"^(2)`<br/>`1.16 xx 10^(-5) cm^(2)`<br/>`1.16 xx 10^(-4) cm^(2)`<br/>`1.16 xx 10^(-<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>) cm^(2)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 37097. |
A child sits stationary at one end of a long trolley moving uniformly with a speed V on a smooth horizontal floor. If the child gets up and runs about on the trolley in any manner, what is the speed of the CM of the (trolley + child) system ? |
| Answer» <html><body><p></p>Solution :The running of the child will produce no effect on the velocity of centre of <a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a> of the trolley. Because trolley and child has same system and <a href="https://interviewquestions.tuteehub.com/tag/force-22342" style="font-weight:bold;" target="_blank" title="Click to know more about FORCE">FORCE</a> and due to it child motion is <a href="https://interviewquestions.tuteehub.com/tag/purely-2962981" style="font-weight:bold;" target="_blank" title="Click to know more about PURELY">PURELY</a> internal. Since no <a href="https://interviewquestions.tuteehub.com/tag/external-981194" style="font-weight:bold;" target="_blank" title="Click to know more about EXTERNAL">EXTERNAL</a> force is involved in the child-trolley system, the child.s motion will produce no change in the velocity of the centre of mass of the trolley. As a result system of child and trolley have centre of mass with <a href="https://interviewquestions.tuteehub.com/tag/constant-930172" style="font-weight:bold;" target="_blank" title="Click to know more about CONSTANT">CONSTANT</a> speed.</body></html> | |
| 37098. |
A liquid drop of diameter 2 mm and surface tension 70 dy cm^(-1) is sprayed into 1000 identical small droplets. Calculate the work done in the process. |
| Answer» <html><body><p></p>Solution :Number of drops n = 1000, diameter of drop d = 2mm, radius of drop r = 1mm = `10^(-1)<a href="https://interviewquestions.tuteehub.com/tag/cm-919986" style="font-weight:bold;" target="_blank" title="Click to know more about CM">CM</a>` <br/> <a href="https://interviewquestions.tuteehub.com/tag/surface-1235573" style="font-weight:bold;" target="_blank" title="Click to know more about SURFACE">SURFACE</a> tension T = <a href="https://interviewquestions.tuteehub.com/tag/70-333629" style="font-weight:bold;" target="_blank" title="Click to know more about 70">70</a> dyne `cm^(-1)`, <a href="https://interviewquestions.tuteehub.com/tag/work-20377" style="font-weight:bold;" target="_blank" title="Click to know more about WORK">WORK</a> done to spray the large drop into <a href="https://interviewquestions.tuteehub.com/tag/small-1212368" style="font-weight:bold;" target="_blank" title="Click to know more about SMALL">SMALL</a> drops W = `4pir^(2)T(n^(1//3)-1)` <br/> `rArrW=4xx22/7xx(10^(-1))^(2)xx70[(1000)^(1//3)-1]` <br/> `rArrW=4xx22xx10^(-2)xx10xx9rArrW=79.2"ergs".=7.9xx10^(-6)J`.</body></html> | |
| 37099. |
The angular velocities of three bodies in SHM are w_(1), w_(2), w_(3)with their respective amplitudes as A_(1), A_(2), A_(3). If all three bodies have same mass and velocity then |
| Answer» <html><body><p>`A_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)w_(1)= A_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)w_(2)= A_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)w_(3)`<br/>`A_(1)w_(1)^(2) = A_(2)w_(2)^(2) = A_(3)w_(3)^(2)`<br/>`A_(1)^(2)w_(1)= A_(2)^(2)w_(2)= A_(3)^(2)w_(3)`<br/>`A_(1)^(2)w_(1)^(1)= A_(2)^(2)w_(2)^(2)= A_(3)^(2)w_(3)^(3)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 37100. |
What is meant by Cartesian coordinate system? |
| Answer» <html><body><p></p>Solution :At any given <a href="https://interviewquestions.tuteehub.com/tag/instant-1046099" style="font-weight:bold;" target="_blank" title="Click to know more about INSTANT">INSTANT</a> of time, the <a href="https://interviewquestions.tuteehub.com/tag/frame-998974" style="font-weight:bold;" target="_blank" title="Click to know more about FRAME">FRAME</a> of reference with respect to which the position of the object is described in <a href="https://interviewquestions.tuteehub.com/tag/terms-1242559" style="font-weight:bold;" target="_blank" title="Click to know more about TERMS">TERMS</a> of position coordinates (x, y, 2) is called cartesian <a href="https://interviewquestions.tuteehub.com/tag/coordinate-933698" style="font-weight:bold;" target="_blank" title="Click to know more about COORDINATE">COORDINATE</a> <a href="https://interviewquestions.tuteehub.com/tag/system-1237255" style="font-weight:bold;" target="_blank" title="Click to know more about SYSTEM">SYSTEM</a></body></html> | |