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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 38101. |
Two bodies of masses 10 kg and 20 kg are located in X-y plane at (0, 1) and (1,0). The position of their centre of mass is |
| Answer» <html><body><p>(2/3, 1/3)<br/>(1/3, 2/3) <br/>(2,1)<br/>(1/3, 4/3) </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 38102. |
On an open ground , a motorist follows a track that turns to his left by an angle of 60^(@) after every 500 m. Starting from a giventurn , specify the displacement ofof themotorist at thethird , sixth and eighth turn . Compare the magnitude of the displacement with the total path length covered by the motorist in each case. |
| Answer» <html><body><p></p>Solution :Displacement of magnitude <a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a> km and direction `60^(@)` with theinitial direction , totalpath length = 1.5km (third turn), <a href="https://interviewquestions.tuteehub.com/tag/null-17167" style="font-weight:bold;" target="_blank" title="Click to know more about NULL">NULL</a> displacement <a href="https://interviewquestions.tuteehub.com/tag/vector-20923" style="font-weight:bold;" target="_blank" title="Click to know more about VECTOR">VECTOR</a> , path length = <a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a> km (sixth turn), 866 `m.30^(@)`, 4 km (eight turn)</body></html> | |
| 38103. |
A small glass marble of mass 'm' oscillates between the two edges, inside a hemispherical glass bowl of radius 'r'. If 'V' is the speed of marble at the lowest position, the normal reaction at that position is |
| Answer» <html><body><p>`(mv^2)/(<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a> )`<br/>`(2mv^2)/(r )`<br/>`(3mv^2)/(r )`<br/>`(3mv^2)/(<a href="https://interviewquestions.tuteehub.com/tag/2r-300472" style="font-weight:bold;" target="_blank" title="Click to know more about 2R">2R</a> )`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 38104. |
A 4g bullet is fired horizontally with a speed of 300 m/s into 0.8kg block of wood at rest on a table and gets embedded in the block. If the coefficient of friction between the block and the table is 0.3, how far will the block slide approximately ? |
| Answer» <html><body><p>0.19 m<br/>0.569 m<br/> 0.758 m<br/>0.379 m</p>Answer :D</body></html> | |
| 38105. |
Time (T), velocity (C) and angular momentum (h) are chosen as fundamental quantities instead of mass, length and time. In terms of these, the dimensions of mass would be: |
| Answer» <html><body><p>`[M]=[T^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>) C^2h]` <br/>`[M] = [T(-1)C^(-<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) <a href="https://interviewquestions.tuteehub.com/tag/h-1014193" style="font-weight:bold;" target="_blank" title="Click to know more about H">H</a>^(-1)]` <br/>`[M] = [T^(-1)C^(-2) h]` <br/>`[M] = [TC^(-2) h]` </p>Answer :C</body></html> | |
| 38106. |
Which of the following relations is not correct ? |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a> A.U = 1.496xx <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(<a href="https://interviewquestions.tuteehub.com/tag/11-267621" style="font-weight:bold;" target="_blank" title="Click to know more about 11">11</a>)m`<br/>`1ly = 9.46xx10^(15)m`<br/>`1parsec = 3.084xx10^(<a href="https://interviewquestions.tuteehub.com/tag/16-276476" style="font-weight:bold;" target="_blank" title="Click to know more about 16">16</a>)m`<br/>`1 ly = 6.3xx10^(-<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>) A.U.</p>Answer :(d)</body></html> | |
| 38107. |
A body freely falling from a height h describes (11h)/(36) in the last second of its fall. The height h is (g=10ms^(-2)) |
| Answer» <html><body><p>125m<br/>180m<br/>360m<br/>90m</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 38108. |
Find antilog of (i) - 2.6674 (ii) - 3.01 (iii) -0.3467 |
| Answer» <html><body><p><br/></p>Solution :(i) Given, log ` x = - 2.6674 = <a href="https://interviewquestions.tuteehub.com/tag/bar3-2460440" style="font-weight:bold;" target="_blank" title="Click to know more about BAR3">BAR3</a> +3 - 2.6674 = 3.3326` <br/> Taking antilog on both the sides, we <a href="https://interviewquestions.tuteehub.com/tag/getx-3645420" style="font-weight:bold;" target="_blank" title="Click to know more about GETX">GETX</a> = 0.002151 <br/> (<a href="https://interviewquestions.tuteehub.com/tag/ii-1036832" style="font-weight:bold;" target="_blank" title="Click to know more about II">II</a>) Given, log `x = - 3.01 = bar 4 + 4 - 3.01 = bar 4.99` <br/> Taking antilog on both the sides, we <a href="https://interviewquestions.tuteehub.com/tag/get-11812" style="font-weight:bold;" target="_blank" title="Click to know more about GET">GET</a> x = 0.0009772 <br/> (iii) Given log `x = - 03467 = bar 1 + 1 -0.3467 = bar1. 6533` <br/> Taking antilog on both the sides, we get x = 0.4501</body></html> | |
| 38109. |
Describe the moment of a force about a point as a vector quantity. |
| Answer» <html><body><p></p>Solution :In Fig. O is the <a href="https://interviewquestions.tuteehub.com/tag/point-1157106" style="font-weight:bold;" target="_blank" title="Click to know more about POINT">POINT</a> of rotation, P is the point of application of a force `vecF`, `vecr`=`vecOP`, <a href="https://interviewquestions.tuteehub.com/tag/position-1159826" style="font-weight:bold;" target="_blank" title="Click to know more about POSITION">POSITION</a> vector of the point `vecP`, with respect to the point O. Then the moment of the force `vecF` about the point O, is `vecF=vecrxxvecF` <br/> According to the <a href="https://interviewquestions.tuteehub.com/tag/properties-11511" style="font-weight:bold;" target="_blank" title="Click to know more about PROPERTIES">PROPERTIES</a> of cross <a href="https://interviewquestions.tuteehub.com/tag/product-25523" style="font-weight:bold;" target="_blank" title="Click to know more about PRODUCT">PRODUCT</a> the direction of the vector `vecG` is along the direction of advance of a righthanded screw, when it is rotated from `vecr` towards `vecF`. The direction of `vecG`, as shown in the figure, is perpendicular to the plane of rotation, i.e., <a href="https://interviewquestions.tuteehub.com/tag/always-373607" style="font-weight:bold;" target="_blank" title="Click to know more about ALWAYS">ALWAYS</a> along the axis of rotation.<br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/CHY_DMB_PHY_XI_P1_U05_C01_E02_001_S01.png" width="80%"/></body></html> | |
| 38110. |
An accelration produces a narrow beam of protons, each having an initial speed of v_(0). The beam is directed towards an initially uncharges distant metal sphere of radius R and centered at point O. The initial path of the beam is parallel to the axis of the sphere at a distance of (R//2) from the axis, as indicated in the diagram. The protons in the beam that collide with the sphere will cause it to becomes charged. The subsequentpotential field at the accelerator due to the sphere can be neglected. The angular momentum of a particle is defined in a similar way to the moment of a force. It is defined as the moment of its linear momentum, linear replacing the force. We may assume the angular momentum of a proton about point O to be conserved. Assume the mass of the proton as m_(P) and the charge on it as e. Given that the potential of the sphere increases with time and eventually reaches a constant velue. One the potential of the sphere has reached its final, constant value, the minimum speed v of a proton along its trajectory path is given by |
| Answer» <html><body><p>`v_(0)`<br/>`v_(0)//<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>`<br/>`2v_(0)`<br/><a href="https://interviewquestions.tuteehub.com/tag/none-580659" style="font-weight:bold;" target="_blank" title="Click to know more about NONE">NONE</a> of these</p>Solution :From the angular <a href="https://interviewquestions.tuteehub.com/tag/momentum-1100588" style="font-weight:bold;" target="_blank" title="Click to know more about MOMENTUM">MOMENTUM</a> conservation <br/> `mv_(0)xxR/2=mvxxRrArr v=V_(0)/2`</body></html> | |
| 38111. |
What is 'retrograde motion' of planets? |
| Answer» <html><body><p></p>Solution :When the motion of the planets are observed in the night <a href="https://interviewquestions.tuteehub.com/tag/sky-1211556" style="font-weight:bold;" target="_blank" title="Click to know more about SKY">SKY</a> by <a href="https://interviewquestions.tuteehub.com/tag/naked-569307" style="font-weight:bold;" target="_blank" title="Click to know more about NAKED">NAKED</a> <a href="https://interviewquestions.tuteehub.com/tag/eyes-455676" style="font-weight:bold;" target="_blank" title="Click to know more about EYES">EYES</a> over a period of a few months, it can be seen that the planets move eastwards and <a href="https://interviewquestions.tuteehub.com/tag/reverse-1188140" style="font-weight:bold;" target="_blank" title="Click to know more about REVERSE">REVERSE</a> their motion for a while and return to eastward motion again. This is <a href="https://interviewquestions.tuteehub.com/tag/called-907796" style="font-weight:bold;" target="_blank" title="Click to know more about CALLED">CALLED</a> 'retrograde motion' of planets.</body></html> | |
| 38112. |
An accelration produces a narrow beam of protons, each having an initial speed of v_(0). The beam is directed towards an initially uncharges distant metal sphere of radius R and centered at point O. The initial path of the beam is parallel to the axis of the sphere at a distance of (R//2) from the axis, as indicated in the diagram. The protons in the beam that collide with the sphere will cause it to becomes charged. The subsequentpotential field at the accelerator due to the sphere can be neglected. The angular momentum of a particle is defined in a similar way to the moment of a force. It is defined as the moment of its linear momentum, linear replacing the force. We may assume the angular momentum of a proton about point O to be conserved. Assume the mass of the proton as m_(P) and the charge on it as e. Given that the potential of the sphere increases with time and eventually reaches a constant velue. After a long time, when the potential of the sphere reaches a constant value, the trajectory of proton is correctly sketched as |
| Answer» <html><body><p>1<br/>2<br/>3<br/><a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a></p>Solution :After <a href="https://interviewquestions.tuteehub.com/tag/long-537592" style="font-weight:bold;" target="_blank" title="Click to know more about LONG">LONG</a> <a href="https://interviewquestions.tuteehub.com/tag/time-19467" style="font-weight:bold;" target="_blank" title="Click to know more about TIME">TIME</a> sphere gets positive charge so the trajectory of the proton is (4) due to repulsion.</body></html> | |
| 38113. |
Find the height to which the water rise when a capillary tube of radius 0.24 mm is dipped vertically in a beaker containing water. Surface tension of water is 7.0xx10^(-2)Nm^(-1), angle of contact is 0^(@) and density of water is 1000Kgm^(-3). |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :5.952 <a href="https://interviewquestions.tuteehub.com/tag/cm-919986" style="font-weight:bold;" target="_blank" title="Click to know more about CM">CM</a></body></html> | |
| 38114. |
An accelration produces a narrow beam of protons, each having an initial speed of v_(0). The beam is directed towards an initially uncharges distant metal sphere of radius R and centered at point O. The initial path of the beam is parallel to the axis of the sphere at a distance of (R//2) from the axis, as indicated in the diagram. The protons in the beam that collide with the sphere will cause it to becomes charged. The subsequentpotential field at the accelerator due to the sphere can be neglected. The angular momentum of a particle is defined in a similar way to the moment of a force. It is defined as the moment of its linear momentum, linear replacing the force. We may assume the angular momentum of a proton about point O to be conserved. Assume the mass of the proton as m_(P) and the charge on it as e. Given that the potential of the sphere increases with time and eventually reaches a constant velue. The total energy (E) of a proton in the beam travelling with seed v at a distance of r (r ge R) from point O. Assuming that the sphere has acquired an electrostatic charge Q is |
| Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/eq-446394" style="font-weight:bold;" target="_blank" title="Click to know more about EQ">EQ</a>)/(4piepsilon_(0)r)`<br/>less than `(eQ)/(4pi epsilon_(0)r)`<br/><a href="https://interviewquestions.tuteehub.com/tag/greater-476627" style="font-weight:bold;" target="_blank" title="Click to know more about GREATER">GREATER</a> than `(eQ)/(4pi epsilon_(0)r)`<br/>zero</p>Solution :`P.E=(1)/(4pi in_(0))Q_(e)/r` and `KE=1/2 mv^(2)` <br/> <a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a> total <a href="https://interviewquestions.tuteehub.com/tag/energy-15288" style="font-weight:bold;" target="_blank" title="Click to know more about ENERGY">ENERGY</a> is greater than `(eQ)/(4pi in_(0)r)`</body></html> | |
| 38115. |
Show that for a simple pendulum, the work done by the tension of the string becomes zero during its oscillation. |
| Answer» <html><body><p></p>Solution :Work done by a force is the productof the force with the component of the displacement of <a href="https://interviewquestions.tuteehub.com/tag/thedisplacement-3193593" style="font-weight:bold;" target="_blank" title="Click to know more about THEDISPLACEMENT">THEDISPLACEMENT</a> along the force. In the <a href="https://interviewquestions.tuteehub.com/tag/case-910082" style="font-weight:bold;" target="_blank" title="Click to know more about CASE">CASE</a> of an <a href="https://interviewquestions.tuteehub.com/tag/oscillating-2900383" style="font-weight:bold;" target="_blank" title="Click to know more about OSCILLATING">OSCILLATING</a> siple pendulum, tension in the bob. <a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a>, the component of displacement of the bob is zero in the direction of tension, therefore, the tension does notdo anywork.</body></html> | |
| 38116. |
What is meant by the term potential energy ? Give its two examples. |
| Answer» <html><body><p></p>Solution :The energy <a href="https://interviewquestions.tuteehub.com/tag/possessed-603189" style="font-weight:bold;" target="_blank" title="Click to know more about POSSESSED">POSSESSED</a> by the body by <a href="https://interviewquestions.tuteehub.com/tag/virtue-1446933" style="font-weight:bold;" target="_blank" title="Click to know more about VIRTUE">VIRTUE</a> of its position is called <a href="https://interviewquestions.tuteehub.com/tag/potential-1161228" style="font-weight:bold;" target="_blank" title="Click to know more about POTENTIAL">POTENTIAL</a> energy.</body></html> | |
| 38117. |
If a bullet is suddenly stopped the rise in temperature is independent of |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a> of the <a href="https://interviewquestions.tuteehub.com/tag/bullet-403823" style="font-weight:bold;" target="_blank" title="Click to know more about BULLET">BULLET</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/material-1089170" style="font-weight:bold;" target="_blank" title="Click to know more about MATERIAL">MATERIAL</a> of bullet <br/><a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a> of bullet <br/>All the above </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 38118. |
(A) : Law of conservation of momentum is the consequence of Newtons third law. (R ) : Action, Reaction pairs are internal forces in collisions. |
| Answer» <html><body><p>Both (A) and (R ) are <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a> and (R ) is the <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> explanation of (A) <br/>Both (A) and (R ) are true and (R ) is not the correct explanation of (A) <br/>(A) is true but (R ) is <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a> <br/>(A) is false and (R ) is false </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 38119. |
Moment of inertia of a circular ring about a given axis is…………..moment of inertia of…………of………….and………………about the same axis. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/greater-476627" style="font-weight:bold;" target="_blank" title="Click to know more about GREATER">GREATER</a> than , <a href="https://interviewquestions.tuteehub.com/tag/circular-916697" style="font-weight:bold;" target="_blank" title="Click to know more about CIRCULAR">CIRCULAR</a> <a href="https://interviewquestions.tuteehub.com/tag/disc-955290" style="font-weight:bold;" target="_blank" title="Click to know more about DISC">DISC</a> , same mass , same <a href="https://interviewquestions.tuteehub.com/tag/size-1211196" style="font-weight:bold;" target="_blank" title="Click to know more about SIZE">SIZE</a>.</body></html> | |
| 38120. |
Particle A is moving with a constant velocity of V_(A) = 50 ms^(–1) in positive x direction. It crossed the origin at time t = 10 s. Another particle B started at t = 0 from the origin and moved with a uniform acceleration of a_(B) = 2 ms^( –2) in positive x direction. (a) For how long was A ahead of B during the subsequent journey? (b) Draw the position (x) time (t) graph for the two particles and mark the interval for which A was ahead of B. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :(a) `<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a> <a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>) s` <br/> `(##IJA_PHY_V01_C02_E01_057_A01##)`</body></html> | |
| 38121. |
A thin rectangular strip ABCD of thickness d is such that the coefficient of linear expansion ' alpha' of any section of the strip (of the form XY) distant 'x' from the face AB varies as alpha= alpha_(0) + alpha_(1) x. Determine the radius of curvature of the strip when heated through a temperature range Delta T |
| Answer» <html><body><p>`( <a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)/( 2 alpha_(1) ( Delta T) ) [2 + ( alpha_(<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>) + alpha_(1) d) Delta T)`<br/>`( 1)/( 2alpha_(1) (Delta T) ) [ 2+ ( 2alpha_(0) + alpha_(1) d) Delta T]`<br/>`( 1)/( alpha_(1) ( Delta T) )[ 1+ ( 2alpha_(0) + alpha_(1) d ) Delta T]`<br/>`(1)/( alpha_(1) ( Delta T) ) [2 + (alpha_(0) + alpha_(1) d) Delta T]`</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 38122. |
The Ratio of the escape velocity to the orbital velocity of a surface satellite of the earth is |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/sqrt2-3056932" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT2">SQRT2</a>`<br/>`1/sqrt2`<br/>`1/2`<br/>2</p>Answer :A</body></html> | |
| 38123. |
A 2kg block is dropped from a height of 0.4 m on a spring of force constant 1960Nm^(-1). The maximum compression of the spring is |
| Answer» <html><body><p>`10cm`<br/>`20 <a href="https://interviewquestions.tuteehub.com/tag/cm-919986" style="font-weight:bold;" target="_blank" title="Click to know more about CM">CM</a>`<br/>`30cm `<br/>`<a href="https://interviewquestions.tuteehub.com/tag/40cm-315881" style="font-weight:bold;" target="_blank" title="Click to know more about 40CM">40CM</a>`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :C</body></html> | |
| 38124. |
Non -viscous flow can be a streamline. |
| Answer» <html><body><p><br/></p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a> .For non -viscous fluid `eta=0`<br/> `<a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a>` From `R_(e)=(rhovD)/(eta),R_(e)` = infinite <br/><a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a> , such type of flow can never be a <a href="https://interviewquestions.tuteehub.com/tag/streamline-1229093" style="font-weight:bold;" target="_blank" title="Click to know more about STREAMLINE">STREAMLINE</a>.</body></html> | |
| 38125. |
A splash is heard 3.12s after a stone is dropped into a well 45 m deep. The speed of sound in air is [g=10ms^(-2)] |
| Answer» <html><body><p>`330ms^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)`<br/>`375ms^(-1)` <br/>`<a href="https://interviewquestions.tuteehub.com/tag/340ms-1856857" style="font-weight:bold;" target="_blank" title="Click to know more about 340MS">340MS</a>^(-1)`<br/>`346ms^(-1)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 38126. |
Derive the expression for the terminal velocity of a sphere moving in a high viscous fluid using stokes force. |
| Answer» <html><body><p></p>Solution :Expression for terminal velocity : Consider a sphere of radius <a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a> which falls freely through a highly viscous liquid of <a href="https://interviewquestions.tuteehub.com/tag/coefficient-920926" style="font-weight:bold;" target="_blank" title="Click to know more about COEFFICIENT">COEFFICIENT</a> of viscosity `eta`. Let the density of the material of the sphere be `<a href="https://interviewquestions.tuteehub.com/tag/rho-623364" style="font-weight:bold;" target="_blank" title="Click to know more about RHO">RHO</a>` and the density of the fluid be `sigma`. <br/> Gravitational force acting on the sphere. <br/> `F_(G) = mg = (4)/(3)pi r^(3)rho g` (downward force) <br/> Up thrust, `U = (4)/(3)pi r^(3) sigma g` (upward force) <br/> viscous force `<a href="https://interviewquestions.tuteehub.com/tag/f-455800" style="font-weight:bold;" target="_blank" title="Click to know more about F">F</a>= 6pi eta r v_(t)` <br/> At terminal velocity `v_(t)` <br/> downward force = upward force <br/> `F_(G) - U = F rArr (4)/(3) pi r^(3) rho g - (4)/(3) pi r^(3) sigma g = 6pi eta r v_(t)` <br/> `v_(t) = (2)/(9) xx (r^(2)(rho - sigma))/(eta) g rArr v_(t) <a href="https://interviewquestions.tuteehub.com/tag/prop-607409" style="font-weight:bold;" target="_blank" title="Click to know more about PROP">PROP</a> r^(2)` <br/> Here, it should be noted that the terminal speed of the sphere is directly proportional to the square of its radius. If `sigma` is greater than `rho`, then the term `(rho - sigma)` becomes negative leading to a negative terminal velocity. <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/SUR_PHY_XI_V02_C07_E03_007_S01.png" width="80%"/></body></html> | |
| 38127. |
What is the efficiency of time realisation in cesium atomic clocks ? |
| Answer» <html><body><p></p>Solution :The <a href="https://interviewquestions.tuteehub.com/tag/uncertainty-1436217" style="font-weight:bold;" target="_blank" title="Click to know more about UNCERTAINTY">UNCERTAINTY</a> in time <a href="https://interviewquestions.tuteehub.com/tag/realisation-1178917" style="font-weight:bold;" target="_blank" title="Click to know more about REALISATION">REALISATION</a> of a <a href="https://interviewquestions.tuteehub.com/tag/cesium-407908" style="font-weight:bold;" target="_blank" title="Click to know more about CESIUM">CESIUM</a> <br/> <a href="https://interviewquestions.tuteehub.com/tag/atomic-2477" style="font-weight:bold;" target="_blank" title="Click to know more about ATOMIC">ATOMIC</a> clock is `+- 10^(-13).` it implies that such <br/> <a href="https://interviewquestions.tuteehub.com/tag/clocks-919290" style="font-weight:bold;" target="_blank" title="Click to know more about CLOCKS">CLOCKS</a> gain or loss no more then ` 3mu s` in one year.</body></html> | |
| 38128. |
A particle moves with position vector given by r=3t^(2)hat(i)+4hat(j) where r is measured in metres and t in seconds. For t gt0. Match the entries in Column I with those in Column - II. {:("Column-I","Column-II"),("(A) Angular acceleration","(P) increase with time"),("(about the axis passing through the origin)",),("(B) Liner momentum of the particle ","(Q) decrease with time"),("(C) Angular speed of the particle about the axis passing through the origin","(R) constant in time"),("(D) Magnitude of angular momentum of the particle with respect the origin is ","(S) directly proportional to the time."),(,"(T) is along negative axis "):} |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A-RS;B-PS;C-PS;D-PS</body></html> | |
| 38129. |
The simple harmonic motion of a particle is governed by x = A sin (omega t + phi) where phi = (5pi)/6 Find the position and direction of movement of particle at t=0 a) |
| Answer» <html><body><p>A/2, <a href="https://interviewquestions.tuteehub.com/tag/negative-570381" style="font-weight:bold;" target="_blank" title="Click to know more about NEGATIVE">NEGATIVE</a> <a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a>-<a href="https://interviewquestions.tuteehub.com/tag/axis-889931" style="font-weight:bold;" target="_blank" title="Click to know more about AXIS">AXIS</a> <br/>A/2, <a href="https://interviewquestions.tuteehub.com/tag/positive-1159908" style="font-weight:bold;" target="_blank" title="Click to know more about POSITIVE">POSITIVE</a> x - axis <br/>A/4 negative x-axis <br/>A/4 positive x-axis </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 38130. |
Which of the following velocity-time graphs shows a realistic situation for a body in motion |
| Answer» <html><body><p><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_DOC_OBJ_PHY_XI_V01_A_C03_E01_045_O01.png" width="30%"/><br/><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_DOC_OBJ_PHY_XI_V01_A_C03_E01_045_O02.png" width="30%"/><br/><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_DOC_OBJ_PHY_XI_V01_A_C03_E01_045_O03.png" width="30%"/><br/><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_DOC_OBJ_PHY_XI_V01_A_C03_E01_045_O04.png" width="30%"/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 38131. |
Two discs have the same mass and thickness. Their materials are of densities d_(1) and d_(2). The ratio of their M.I about their central axis is |
| Answer» <html><body><p>`d_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>):d_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)`<br/>`d_(1):d_(2)`<br/>`d_(1)^(2):d_(2)^(2)`<br/>`d_(2)^(2):d_(1)^(2)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 38132. |
A block of wood is floating on water at 0^(@)C with a certain volume 'V' above the water level. The temperature of water is slowly raised to 20^(@)C . How does the volume 'V' change with the rise in temperature ? |
| Answer» <html><body><p>remain unchanged<br/>decrease continuously<br/>decrease till `4^(@)<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>` and then <a href="https://interviewquestions.tuteehub.com/tag/increase-1040383" style="font-weight:bold;" target="_blank" title="Click to know more about INCREASE">INCREASE</a>.<br/>increase till `4^(@)C` and then decrease.</p>Solution :The density of water <a href="https://interviewquestions.tuteehub.com/tag/increases-1040626" style="font-weight:bold;" target="_blank" title="Click to know more about INCREASES">INCREASES</a> from `<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>^(@)` to `4^(@)C` and then decreases. <a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a>, the volume V of the block above water level will increase till `4^(@)C` and then decrease.</body></html> | |
| 38133. |
Let us assume that our galaxy consists of 2.5 x× 10^(11) stars each of one solar mass. How long will a star at a distance of 50,000 ly from the galactic centre take to complete one revolution? Take the diameter of the Milky Way to be 10^(5) ly. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`3.54 ×x <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(<a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a>)` <a href="https://interviewquestions.tuteehub.com/tag/years-1464846" style="font-weight:bold;" target="_blank" title="Click to know more about YEARS">YEARS</a>.</body></html> | |
| 38134. |
A Carnot engine will sink temperature at 17^(@)C has 50% efficiency. By now much should its source temperature by changed to increase its efficiency to 60% ? |
| Answer» <html><body><p>225 K<br/>`128^(@)C`<br/>580 K<br/>145 K</p>Solution :`eta = 1 - (T_(2))/(T_(1))` <br/> <a href="https://interviewquestions.tuteehub.com/tag/initially-516121" style="font-weight:bold;" target="_blank" title="Click to know more about INITIALLY">INITIALLY</a>, `(<a href="https://interviewquestions.tuteehub.com/tag/50-322056" style="font-weight:bold;" target="_blank" title="Click to know more about 50">50</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/100-263808" style="font-weight:bold;" target="_blank" title="Click to know more about 100">100</a>) = 1 - (273 + 17)/(T_(1))` or `(290)/(T_(1)) = (1)/(2)` or `T_(1) = 580 K` <br/> Finally, `(<a href="https://interviewquestions.tuteehub.com/tag/60-328817" style="font-weight:bold;" target="_blank" title="Click to know more about 60">60</a>)/(100) = 1 - (273 + 17)/(T._(1))` or `(290)/(T._(1)) = (2)/(5)` or `T._(1) = 725 K` <br/> `:.` Change in source <a href="https://interviewquestions.tuteehub.com/tag/temperature-11887" style="font-weight:bold;" target="_blank" title="Click to know more about TEMPERATURE">TEMPERATURE</a> `= (725 - 580) K = 145 K`</body></html> | |
| 38135. |
A liquid of specific heat 0.5 cal/g^(0)c at 60^(0)C, is mixed with another liquid of specific heat 0.3 cal/gm^(0)c at 20^(0)C. After mixing, the temperature of the mixture becomes 30^(0)C. In what proportion by weight are the liquids mixed ? |
| Answer» <html><body><p>`1:2`<br/>`3:4`<br/>`4:5`<br/>`1:5`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 38136. |
Two parallel glass plates separated by a very short distance l, contains and oil drop of volume V, introduced between them. If theta be the angle of contact and T the surface tension of the oil, find the force with one presses against the other. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`2TVcostheta//1^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`</body></html> | |
| 38137. |
Two needles are floating on the surface of water. A hot needle when touches water surface between the needles, then they move |
| Answer» <html><body><p>closer <br/><a href="https://interviewquestions.tuteehub.com/tag/away-386546" style="font-weight:bold;" target="_blank" title="Click to know more about AWAY">AWAY</a> <br/>surface <a href="https://interviewquestions.tuteehub.com/tag/tension-1241727" style="font-weight:bold;" target="_blank" title="Click to know more about TENSION">TENSION</a> <br/>all of the above</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 38138. |
A body of mass 0.40 kg moving initially with a constant speed of 10 m s^(-1) to the north is subject to a constant force of 8.0 N directed towards the south for 30 s.Take the instant the force is applied to bet = 0, the position of the body at that time to be x = 0, and predict its position att = –5 s, 25 s, 100 s. |
| Answer» <html><body><p></p>Solution :u = `<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a> ms^(-1)` <br/> m= 0.40kg (Northdirection) <br/>t=30 s <br/> Herenorthdirectionis consideredas <a href="https://interviewquestions.tuteehub.com/tag/positiveand-2943357" style="font-weight:bold;" target="_blank" title="Click to know more about POSITIVEAND">POSITIVEAND</a> southdirectionisconsideredas negative<br/>Forceis appliedfor t=30 s <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/KPK_AIO_PHY_XI_P1_C05_E02_022_S01.png" width="80%"/> <br/> (i) At t=5 sposition <br/> `X_(1) = ut` <br/>`=10xx (-5)` <br/> (ii)at t=25 s <br/> `x_(2)ut + (1)/(2)4r^(2)` <br/> where`a = (F )/( m ) =(-8)/(0.4)= - 20ms^(-2)` <br/> `=<a href="https://interviewquestions.tuteehub.com/tag/250-297421" style="font-weight:bold;" target="_blank" title="Click to know more about 250">250</a>- 6250` <br/> `-=6 km` <br/>when forceis appliedfor 30s distancecovered<br/> velocityof objectafter30 s <br/> = u+ 9t <br/>=10 -600 <br/> (<a href="https://interviewquestions.tuteehub.com/tag/iii-497983" style="font-weight:bold;" target="_blank" title="Click to know more about III">III</a>)Positionof objectat t=100s <br/> `:.x_(100)= x_(30) a + x_(70)` <br/>=-870041300 <br/> `=-5000 m` <br/> `=-50 km` <br/> Thuspositionat -5 s 25 s and 10 willbe-50 m-6 kmand-50 km</body></html> | |
| 38139. |
A block of mass 20 kg is placed on a rough horizontal plane and a horizontal force of 12 N is applied. If coefficient of friction is 0.1 the frictional force acting on it is, |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/20-287209" style="font-weight:bold;" target="_blank" title="Click to know more about 20">20</a> N <br/>12 N <br/><a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a> N <br/>28 N</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 38140. |
The dimensional formula of the physical quantity whose S.I. unit is farad is |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/ml-548251" style="font-weight:bold;" target="_blank" title="Click to know more about ML">ML</a>^(2)T^(-3)I^(-2)`<br/>`M^(-1)<a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a>^(-3)T^(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)I^(2)`<br/>`M^(-1)L^(-2)T^(4)I^(2)`<br/>`M^(-1)L^(-2)T^(3)I^(2)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :C</body></html> | |
| 38141. |
A closed hollow insulated cylinder is filled with gas 0°C and also contains an insulated piston of negligible weight and negligible thickness at the middle point. The gas on one side of the piston is heated to 100°C. If the piston moves 5cm, the length of the hollow cylinder is |
| Answer» <html><body><p>13.65 cm<br/>27.3 cm<br/>38.6 cm<br/>64.6 cm</p>Answer :D</body></html> | |
| 38142. |
A bullet of mass 25g moving with a velocity of 500 ms^(-1) enters into a wooden block and comes out of it with a velocity of 100 ms^(-10. Find the work done by the bullet while passing through the wooden block. |
| Answer» <html><body><p></p>Solution :`m= 25 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(-3) kg, u= 500m//s, v= 100m//s` <br/> Work energy theorem `W= (1)/(2) mv^(2)- (1)/(2) m u^(2)` <br/> `=(1)/(2) xx 25 xx 10^(-3) [(100)^(2)- (<a href="https://interviewquestions.tuteehub.com/tag/500-323288" style="font-weight:bold;" target="_blank" title="Click to know more about 500">500</a>)^(2)]= <a href="https://interviewquestions.tuteehub.com/tag/300j-306456" style="font-weight:bold;" target="_blank" title="Click to know more about 300J">300J</a>`</body></html> | |
| 38143. |
A ball is thrown straight up . What is its velocity and acceleration at the top ? |
| Answer» <html><body><p></p>Solution :Atthe highest <a href="https://interviewquestions.tuteehub.com/tag/point-1157106" style="font-weight:bold;" target="_blank" title="Click to know more about POINT">POINT</a>, the <a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a> of the ball is zero and its accelertion is equal to <a href="https://interviewquestions.tuteehub.com/tag/acceleration-13745" style="font-weight:bold;" target="_blank" title="Click to know more about ACCELERATION">ACCELERATION</a> due to gravity <a href="https://interviewquestions.tuteehub.com/tag/acting-269" style="font-weight:bold;" target="_blank" title="Click to know more about ACTING">ACTING</a> is <a href="https://interviewquestions.tuteehub.com/tag/downward-2061463" style="font-weight:bold;" target="_blank" title="Click to know more about DOWNWARD">DOWNWARD</a> direction.</body></html> | |
| 38144. |
In the following which is not the unit of time |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/leap-1070473" style="font-weight:bold;" target="_blank" title="Click to know more about LEAP">LEAP</a> year<br/>Lunar month<br/>Light year<br/>sidereal year</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 38145. |
Can the coefficent of frictionbe more than one |
| Answer» <html><body><p></p>Solution :Yes. The <a href="https://interviewquestions.tuteehub.com/tag/coefficient-920926" style="font-weight:bold;" target="_blank" title="Click to know more about COEFFICIENT">COEFFICIENT</a> of friction can be more than one in some cases such as silicone rubber. Coefficient of friction is the ratio of <a href="https://interviewquestions.tuteehub.com/tag/frictional-465947" style="font-weight:bold;" target="_blank" title="Click to know more about FRICTIONAL">FRICTIONAL</a> force to <a href="https://interviewquestions.tuteehub.com/tag/normal-1123860" style="font-weight:bold;" target="_blank" title="Click to know more about NORMAL">NORMAL</a> force. i.e., `<a href="https://interviewquestions.tuteehub.com/tag/f-455800" style="font-weight:bold;" target="_blank" title="Click to know more about F">F</a> = mu R` . If `mu`is greater than one means frictional force is greater than normal force. But in general case the <a href="https://interviewquestions.tuteehub.com/tag/value-1442530" style="font-weight:bold;" target="_blank" title="Click to know more about VALUE">VALUE</a> is usually between 0 and 1.</body></html> | |
| 38146. |
Give difference between charge and mass. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`<a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a> = Y/3`</body></html> | |
| 38147. |
A ball is dropped from a height h on a floor if the coefficient of restitution ise. Find the (a). Speed of ball after the first second … n^(th) collision. (b). Maximum height attained by the ball, after the first, second … n^(th) collision. (c). Time taken by the ball to reach the highest point after the first, second, ...n^(th) collision. (d). total distance covered by the ball. (e). totol time of journey. |
| Answer» <html><body><p></p>Solution :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/CPS_V01_C10_S01_151_S01.png" width="80%"/> <br/> O to A: <br/> Speed of the ball when it hits the ground `u=sqrt(2gh)` <br/> Time take by the ball to hit the floor, <br/> `h=(1)/(2)g t_(<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>^(2))impliest_(0)=sqrt((2h)/(g))` <br/> `v_(1)-v_(2)=-e(u_(1)-u_(2))` <br/> 1 ball, 2 floor <br/> `u_(2)=v_(2)=0` <br/> `v_(1)=-eu_(1)=-<a href="https://interviewquestions.tuteehub.com/tag/eu-446864" style="font-weight:bold;" target="_blank" title="Click to know more about EU">EU</a>` <br/> Speed of the ball after the <a href="https://interviewquestions.tuteehub.com/tag/first-461760" style="font-weight:bold;" target="_blank" title="Click to know more about FIRST">FIRST</a> collision `=eu` <br/> A to B <br/> `0=v_(1)^(2)-2gh_(1)impliesh_(1)=(v_(1)^(2))/(2g)=(e^(2)u^(2))/(2g)=(e^(2)xx2gh)/(2g)=e^(2)h` <br/> <a href="https://interviewquestions.tuteehub.com/tag/height-1017806" style="font-weight:bold;" target="_blank" title="Click to know more about HEIGHT">HEIGHT</a> attained by the ball after the first collision `=e^(2)h` <br/> `0=v_(1)-g t_(1)impliest_(1)=(v_(1))/(g)=(eu)/(g)=(e)/(g)sqrt(2gh)=esqrt((2h)/(g))=et_(0)` <br/> After every collision the speed becomes e times. Maximum height becomes `e^(2)` times. time to reach at the heighest point becomes e times. <br/> `{:(,1^(st)"collision","After 2nd collision",n^(th)" collsion"),("speed of ball",eu,e^(2)u,e^(n)u),("Maximum height",e^(2)h,e^(4)h,e^(2n)h),("Time to reach at highest point",et_(0),et_(0),e^(n)t_(0)):}` <br/> when `u=sqrt(2gh),t_(0)=sqrt(2h//g)` <br/> <a href="https://interviewquestions.tuteehub.com/tag/total-711110" style="font-weight:bold;" target="_blank" title="Click to know more about TOTAL">TOTAL</a> distance covered by the ball <br/> `S=h+2h_(1)+2h_(2)+. . . infty` <br/> `=h+2e^(2)h+2e^(4)h+. . . infty` <br/> `=h+2e^(2)h{1+e^(2)+. . .infty}` <br/> `=h+2e^(2)h{(1)/(1-e^(2))}=((1+e^(2))/(1-e^(2)))h` <br/> Total time of journey <br/> `T=t_(0)+2t_(1)+2t_(2)+... infty` <br/> `=t_(0)+2et_(0)+2e^(2)t_(0)+. . . infty` <br/> `=t_(0)+2et_(0)(1+e+ . . .infty)` <br/> `=t_(0)+2et_(0)((1)/(1--e))=((1+e)/(1-e))t_(0)=((1+e)/(1-e))sqrt((2h)/(g))`</body></html> | |
| 38148. |
A satellite is revolving in a circular orbit round the earth at a height of h. If the acceleration due to gravity at theta height is g. The orbital speed of the satellite. |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(gh)`<br/>`sqrt(2gh)`<br/>`sqrt(<a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a>(R+h))`<br/>`sqrt(gR)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 38149. |
Let bar(upsilon), upsilon_("rms") and upsilon_(p) respectively denote the mean speed, root mean square speed and most probable speed of the molecules in an ideal monatomic gas at absolute temperature T. The mass of a molecule is m. Then: |
| Answer» <html><body><p>No <a href="https://interviewquestions.tuteehub.com/tag/molecule-563028" style="font-weight:bold;" target="_blank" title="Click to know more about MOLECULE">MOLECULE</a> can have a <a href="https://interviewquestions.tuteehub.com/tag/speed-1221896" style="font-weight:bold;" target="_blank" title="Click to know more about SPEED">SPEED</a> <a href="https://interviewquestions.tuteehub.com/tag/greater-476627" style="font-weight:bold;" target="_blank" title="Click to know more about GREATER">GREATER</a> than `sqrt(2) upsilon_("rms")`<br/>No molecule can have a speed less than `upsilon_(p) // sqrt(2)`<br/>`upsilon_(p) lt bar( upsilon) lt upsilon_("rms")`<br/>The <a href="https://interviewquestions.tuteehub.com/tag/average-13416" style="font-weight:bold;" target="_blank" title="Click to know more about AVERAGE">AVERAGE</a> kinetic energy of a molecule is `(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)/(4) m upsilon_(P)^(2)`</p>Answer :C::D</body></html> | |
| 38150. |
Eiffel tower is made up of iron and its height is roughly 300 m. During winter season (January) in France the temperature is 2^(@)C and in hot summer its average temperature 25^(@)C. Calculate the change in height of Eiffel tower between summer and winter. The linear thermal expansion coefficient for iron alpha = 10xx10^(-6)" per "^(@)C |
| Answer» <html><body><p></p>Solution :`(DeltaL)/(L) = alpha_L DeltaT = DeltaL = alpha_L L DeltaT`<br/>`DeltaT = 10 xx 10^(-<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>) xx 300xx23 =0.<a href="https://interviewquestions.tuteehub.com/tag/69-331759" style="font-weight:bold;" target="_blank" title="Click to know more about 69">69</a> m = 69 <a href="https://interviewquestions.tuteehub.com/tag/cm-919986" style="font-weight:bold;" target="_blank" title="Click to know more about CM">CM</a>`</body></html> | |