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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 38151. |
The motion of a torsional pendulum is |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/periodic-598580" style="font-weight:bold;" target="_blank" title="Click to know more about PERIODIC">PERIODIC</a> <br/>Oscillatory<br/>Angular <a href="https://interviewquestions.tuteehub.com/tag/simple-1208262" style="font-weight:bold;" target="_blank" title="Click to know more about SIMPLE">SIMPLE</a> <a href="https://interviewquestions.tuteehub.com/tag/harmonic-1015999" style="font-weight:bold;" target="_blank" title="Click to know more about HARMONIC">HARMONIC</a> <br/>All of the above </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 38152. |
The density of the material of a body is 0.76g*cm^(-3) and its weight in air is 40gxxg. If the density of the material of the counterpoising weight if 8.4g*cm^(-3) and the density of air is 1.293g*L^(-1), then what is the real weight of the body? |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`40.062gxxg`</body></html> | |
| 38153. |
A pendulum bob of mass 'm' is released from horizontal position. It collides easltically at the lowest point with another pendulum of same length but with a bob of mass '2m' initially at rest. The ratio of the heights to which the bobs of the two pendulums rise after collisions is |
| Answer» <html><body><p>`1:1`<br/>`1:2`<br/>`1:9`<br/>`1:4`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 38154. |
A liquid of density rho flows along a horizontal pipe of uniform cross - section A with a velocity v through a righ angled bend as shown in fig. What force has to be exerted at the bend to hold the pipe in equilibrium ? |
| Answer» <html><body><p></p>Solution :Change in momentum of mass `Delta m` of liquid as it passes through the bend<br/>`Delta p = P_(f)-P_(i)`<br/>`= Delta <a href="https://interviewquestions.tuteehub.com/tag/mv-1082193" style="font-weight:bold;" target="_blank" title="Click to know more about MV">MV</a> sqrt(2)`<br/>`F = (Delta P)/(Delta t)=(sqrt(2))v(Delta m)/(Delta t) , [as Delta m = <a href="https://interviewquestions.tuteehub.com/tag/rho-623364" style="font-weight:bold;" target="_blank" title="Click to know more about RHO">RHO</a> A Delta <a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a>]`<br/>`F = sqrt(2)v ((rho.A Delta L))/(Delta t), [as Delta L//Delta t=v]`<br/>`F = sqrt(2)rho A v^(2)`<br/>`therefore` So the force to be applied at the bend to hold it in position is `sqrt(2)rho Av^(2)` in the <a href="https://interviewquestions.tuteehub.com/tag/direction-1696" style="font-weight:bold;" target="_blank" title="Click to know more about DIRECTION">DIRECTION</a> as shown in fig. (Otherwise pipe will move in opposite direction.).<br/><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_NEO_CAO_PHY_XI_V01_MP1_C05_SLV_018_S01.png" width="80%"/></body></html> | |
| 38155. |
State Kepler's law of time periods. |
| Answer» <html><body><p></p>Solution :The square of time <a href="https://interviewquestions.tuteehub.com/tag/period-1151023" style="font-weight:bold;" target="_blank" title="Click to know more about PERIOD">PERIOD</a> of a planet is <a href="https://interviewquestions.tuteehub.com/tag/directly-955045" style="font-weight:bold;" target="_blank" title="Click to know more about DIRECTLY">DIRECTLY</a> proportional to the <a href="https://interviewquestions.tuteehub.com/tag/cube-940156" style="font-weight:bold;" target="_blank" title="Click to know more about CUBE">CUBE</a> of the semi-major axis of the <a href="https://interviewquestions.tuteehub.com/tag/ellipse-450431" style="font-weight:bold;" target="_blank" title="Click to know more about ELLIPSE">ELLIPSE</a>. <br/> `T^2 prop r^3`</body></html> | |
| 38156. |
Dimensional analysis of the relation (Energy) =" (Pressure difference)"^(3//2) "(Volume)"^(3//2) gives the value of n as |
| Answer» <html><body><p>3<br/>2<br/>`3//2`<br/>`1//2`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 38157. |
Kepler's third law states that the square of period of revolution (T) of a planet around the sun, is proportional to third power of average distance of r between sun and planet i.e. T^(2) prop k r^(3) where k is constant. If the mass of sun and planet are M, m respectively than as per Newtons law of gravitation force of ttracion, F = (GMm)/(r^(2)). The relation between G & K s describe as |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/gk-468580" style="font-weight:bold;" target="_blank" title="Click to know more about GK">GK</a> = 4 PI^(2)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/gmk-3648666" style="font-weight:bold;" target="_blank" title="Click to know more about GMK">GMK</a> = 4PI^(2)`<br/>K = G<br/>`K = (<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)/(G)`</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 38158. |
A side wall of a wide open tank is provided with a narrowing tube through which water flows out. The cross-sectional area of the tube decreases from S=3.0 cm^(2) to s=1.0 cm^(2). The water level in the tank is h=4.6 m heigher than in the tube. Neglecting the viscosity of water, find the horizontal component of the force tending to pull the tube out of the tank. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :[<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a> <a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a>]</body></html> | |
| 38159. |
Which one of the foliowing is not an assumption of kinetic theoy of gases? |
| Answer» <html><body><p>The volume <a href="https://interviewquestions.tuteehub.com/tag/occupied-7262366" style="font-weight:bold;" target="_blank" title="Click to know more about OCCUPIED">OCCUPIED</a> by the molecules of the gas is negliglble<br/>The force of <a href="https://interviewquestions.tuteehub.com/tag/attraction-887653" style="font-weight:bold;" target="_blank" title="Click to know more about ATTRACTION">ATTRACTION</a> between the molecules is negligible<br/>the collislon between the molecules are elastic<br/>All molecules have same <a href="https://interviewquestions.tuteehub.com/tag/speed-1221896" style="font-weight:bold;" target="_blank" title="Click to know more about SPEED">SPEED</a>..</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 38160. |
A rectangular plank os mass 'm_1' and height 'a' is on a horizontal surface. On the top of it another rectangular plank of mass 'm_2' and height 'b' is placed. The potential energy of the system is, |
| Answer» <html><body><p>`(m_(1)+m_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)) ((a+b))/(2)<a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a>`<br/>`[(m_(1)+m_(2))/(2)a+m_(2) (b)/(2)]g`<br/>`[((m_1)/(2)+m_(2))a+m_(2)(b)/(2)]g`<br/>`[((m_1)/(2)+m_(2))a+m_(1)(b)/(2)]g`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :C</body></html> | |
| 38161. |
One end of a massless spring of spring constant 100 N/m and natural length 0.5m is fixed and the other end is connected to a particle of mass 0.5 kg lying on a frictionless horizontal table. The spring remains horizontal. If the mass is made to rotate at an angular velocity of 2 rad/s, find the elongation of the spring. |
| Answer» <html><body><p>4cm<br/>3cm<br/>1cm<br/>2cm</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 38162. |
Unit of magnetic induction field B is |
| Answer» <html><body><p>tesla<br/>Wb `m^(-<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a> ("Am")^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)`<br/>all the above</p>Answer :D</body></html> | |
| 38163. |
Consider a large bound book. a) If it is placed on the table, locate its centre of mass. b) If it is made to stand vertically on the table will the centre of mass remain same ? c) If it is placed on the table and opened such that half the number of pages are on one side and half on the other, where will the centre of mass be now approximately ? If 3/4 of the pages are on one side, to which side the centre of mass will shift ? |
| Answer» <html><body><p></p>Solution :(a) Cenre of mass of book is at its geometric centre. <br/> (b) Yes. When the book is made to <a href="https://interviewquestions.tuteehub.com/tag/stand-1223993" style="font-weight:bold;" target="_blank" title="Click to know more about STAND">STAND</a> <a href="https://interviewquestions.tuteehub.com/tag/vertically-3260386" style="font-weight:bold;" target="_blank" title="Click to know more about VERTICALLY">VERTICALLY</a> on the table, then there is no change in position of centre of mass because the centre of mass is independent of co-ordinate system. <br/> (<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>)When the book is <a href="https://interviewquestions.tuteehub.com/tag/opened-2895201" style="font-weight:bold;" target="_blank" title="Click to know more about OPENED">OPENED</a> with half the number of pages to one side and the other half on the other side, then the centre of mass is at a <a href="https://interviewquestions.tuteehub.com/tag/height-1017806" style="font-weight:bold;" target="_blank" title="Click to know more about HEIGHT">HEIGHT</a> of `h/4` from the ground level, when h = width (or height) of the book. <br/> (d) If `3/4` of pages are at one side and `1/4` of pages at the other side, then centre of mass will shift towards `3/4`pages part.</body></html> | |
| 38164. |
The density of water at the surface of the oceanis rho. If the bulk modulus of water is B then, what is the density of ocean water at a depth, where the pressure is nP_(0),(P_(0) is the atmospheric pressure) |
| Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Increase in pressure `(Delta P) = nP_0 - P_0 = (n-1) P_0` <br/>From `M = <a href="https://interviewquestions.tuteehub.com/tag/rho-623364" style="font-weight:bold;" target="_blank" title="Click to know more about RHO">RHO</a> <a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>` , the decrease in volume due to increase in pressure `Delta P` is <br/>`Delta V = (V Delta P)/(<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>)` <br/>`rArr V. = V - Delta V = V - (V Delta P)/(B) = V/B (B - Delta P)` <br/>`rho. = (M)/(V.) = (rho V)/(V.) = (rho B)/((B - Delta P)) = (rho B)/((B - (n-1)P_0 1))`</body></html> | |
| 38165. |
Two bodies of masses 50 kg and 200 kg are placed at a distance of 1m. The distance from the larger body at which the intensity of gravitational field will be zero is |
| Answer» <html><body><p>`(1)/(3) m`<br/>`(2)/(3) m`<br/>`(4)/(3) m`<br/>`(5)/(3) m`</p>Solution :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/MOD_UNT_PHY_XI_P1_C08_E07_013_S01.png" width="80%"/> <br/> `(G xx 50)/(<a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a>^(2)) = (G xx <a href="https://interviewquestions.tuteehub.com/tag/200-288914" style="font-weight:bold;" target="_blank" title="Click to know more about 200">200</a>)/((1-x)^(2))` <br/> `((1-x)/(x))^(2) = (200)/(50)` <br/> `(1-x)/(x) = 2` <br/> `1 - x = <a href="https://interviewquestions.tuteehub.com/tag/2x-301182" style="font-weight:bold;" target="_blank" title="Click to know more about 2X">2X</a> "" rArr 3x = 1 rArr x = (1)/(3)` <br/> `1 - x = (2)/(3)m`. <br/> The distance from larger <a href="https://interviewquestions.tuteehub.com/tag/body-900196" style="font-weight:bold;" target="_blank" title="Click to know more about BODY">BODY</a> is `(2)/(3)m`</body></html> | |
| 38166. |
Two cylindrical rods of the same material have the same temperature difference between their ends. The ratio of the rates of flow of heat through them is 1 : 8. The radii of the rods are in the ratio 1 : 2. What is the ratio of their lengths ? |
| Answer» <html><body><p>`2:1`<br/>`4:1`<br/>`1:8`<br/>`1:32`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 38167. |
A rope is wound on a circular disc of moment of inertia 0.1 kg . m^(2). A tangential force of 20 N on the rope rotates the disc about its axis. If the radius of the wheel is 0.1 m, calculate its acceleration. Now a mass of 2 kg is suspended at thelower end of the rope. What will be the angular acceleration? g = 10 m.s^(-2) |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/20-287209" style="font-weight:bold;" target="_blank" title="Click to know more about 20">20</a> <a href="https://interviewquestions.tuteehub.com/tag/rad-1175618" style="font-weight:bold;" target="_blank" title="Click to know more about RAD">RAD</a>.`s^(-<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) , 16.7 rad .s^(-2)`</body></html> | |
| 38168. |
F = (Gm_(1)m_(2))/(r^(2)) is valid |
| Answer» <html><body><p>Between <a href="https://interviewquestions.tuteehub.com/tag/bodies-900171" style="font-weight:bold;" target="_blank" title="Click to know more about BODIES">BODIES</a> with any <a href="https://interviewquestions.tuteehub.com/tag/shape-1204673" style="font-weight:bold;" target="_blank" title="Click to know more about SHAPE">SHAPE</a> <br/>Between particles<br/>Between any bodies with <a href="https://interviewquestions.tuteehub.com/tag/uniform-1437485" style="font-weight:bold;" target="_blank" title="Click to know more about UNIFORM">UNIFORM</a> density<br/>Between any bodies with same shape </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 38169. |
An ideal gas is taken around the cycle ABCA as shown in the P-V diagram. The total work done by the gas during the cycle is |
| Answer» <html><body><p>PV<br/>2PV<br/>4PV<br/>3PV</p>Solution :The <a href="https://interviewquestions.tuteehub.com/tag/total-711110" style="font-weight:bold;" target="_blank" title="Click to know more about TOTAL">TOTAL</a> work <a href="https://interviewquestions.tuteehub.com/tag/done-2591742" style="font-weight:bold;" target="_blank" title="Click to know more about DONE">DONE</a> <br/> = Area of `Delta ABC = (1)/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) xx <a href="https://interviewquestions.tuteehub.com/tag/2v-300496" style="font-weight:bold;" target="_blank" title="Click to know more about 2V">2V</a> xx 3P = 3PV`</body></html> | |
| 38170. |
A spring mass system oscillates with a frequency v, if is taken in an elevator slowly accelerating upward, the frequency will |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/increase-1040383" style="font-weight:bold;" target="_blank" title="Click to know more about INCREASE">INCREASE</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/decrease-946104" style="font-weight:bold;" target="_blank" title="Click to know more about DECREASE">DECREASE</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/remain-1184279" style="font-weight:bold;" target="_blank" title="Click to know more about REMAIN">REMAIN</a> same <br/><a href="https://interviewquestions.tuteehub.com/tag/become-389953" style="font-weight:bold;" target="_blank" title="Click to know more about BECOME">BECOME</a> zero</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 38171. |
The relative velocity of two consecutive layers is 8cm/s. If the perpendicular distance between the layers is 0.1 cm, then the velocity gradient will be |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/8sec-1930880" style="font-weight:bold;" target="_blank" title="Click to know more about 8SEC">8SEC</a>^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)`<br/>`80sec^(-1)`<br/>`0.8sec^(-1)`<br/>`0.08sec^(-1)` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 38172. |
Why are sphere rockets usually launched from west to east in the equatorial plane of Earth? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :We know that Earth revolves from west to east about its polar axis. Therefore, all the particles on the Earth have velocity from the west to east. On the Earth have velocity from the west to east. This velocity is maximum in the <a href="https://interviewquestions.tuteehub.com/tag/equatorial-2617989" style="font-weight:bold;" target="_blank" title="Click to know more about EQUATORIAL">EQUATORIAL</a> <a href="https://interviewquestions.tuteehub.com/tag/line-1074199" style="font-weight:bold;" target="_blank" title="Click to know more about LINE">LINE</a>, as `upsilon = R omega`,where `R` is the radius of earth and `omega` is the angular velocity of revolution of earth about its polar axis. when a rocket is launched from west to east in equatorinal plane, the maximum linear velocity is added to the launching velocity of the rocket, due to it, launching <a href="https://interviewquestions.tuteehub.com/tag/becomes-1994370" style="font-weight:bold;" target="_blank" title="Click to know more about BECOMES">BECOMES</a> <a href="https://interviewquestions.tuteehub.com/tag/easier-447966" style="font-weight:bold;" target="_blank" title="Click to know more about EASIER">EASIER</a>.</body></html> | |
| 38173. |
The resultant of the forces vec(F)_(1) = 4hat(i) - 3hat(j) and vec(F)_(2) = 6hat(i) + 8hat(j) is |
| Answer» <html><body><p>`5sqrt(<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a> hat(i) - 5hat(<a href="https://interviewquestions.tuteehub.com/tag/j-520843" style="font-weight:bold;" target="_blank" title="Click to know more about J">J</a>)`<br/><a href="https://interviewquestions.tuteehub.com/tag/125-271180" style="font-weight:bold;" target="_blank" title="Click to know more about 125">125</a><br/>`-2hat(i) - 3hat(j)`</p>Answer :A</body></html> | |
| 38174. |
Obtain an expression for the variation ineffective gravitational acceleration g' with latitude due to earth's rotation: |
| Answer» <html><body><p></p>Solution :`implies` The angle made by the line joining a given place on the earth.s surface to the centre of the earth with the <a href="https://interviewquestions.tuteehub.com/tag/equatorial-2617989" style="font-weight:bold;" target="_blank" title="Click to know more about EQUATORIAL">EQUATORIAL</a> line is called the latitude `(<a href="https://interviewquestions.tuteehub.com/tag/lamda-536483" style="font-weight:bold;" target="_blank" title="Click to know more about LAMDA">LAMDA</a>)`of that place.<br/> `:.`For the equator latitude `lamda = 0^@` <br/> and for the poles latitude `lamda = 90^@` <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/KPK_AIO_PHY_XI_P1_C08_E01_018_S01.png" width="80%"/> <br/> `implies` As shown in figure the latitude of the place P on the earth.s surface is `lamda= anglePOE.`At this position consider a particle of mass m. Two forces acting on it. <br/>(1) Earth.s gravitational force mg is in `vec(PQ)`direction `"".... (1)` <br/>(2) Earth has an acceleration <a href="https://interviewquestions.tuteehub.com/tag/due-433472" style="font-weight:bold;" target="_blank" title="Click to know more about DUE">DUE</a> to rotational <a href="https://interviewquestions.tuteehub.com/tag/motion-1104108" style="font-weight:bold;" target="_blank" title="Click to know more about MOTION">MOTION</a>. So, this particle is in the accelerated frame of reference <br/> `implies` At this point the acceleration of the frame of reference is`((v^2)/r)`in `vec(PM) ` direction. Hence, friction acceleration of particle is `((v^2)/r)` . It is in `vec(PQ )` direction. Hence, frictional <a href="https://interviewquestions.tuteehub.com/tag/centripetal-415325" style="font-weight:bold;" target="_blank" title="Click to know more about CENTRIPETAL">CENTRIPETAL</a> force <br/> `(mv^2)/r` <br/> `=mromega^2 "" [:. v = r omega]` <br/> This force is in `vec(PQ)` direction . <br/> `implies`The component frictional centripetal force in the direction of `vec(PR) = mr omega^(2) cos lamda ""...(2) ` <br/> `:.`From equation (1) and (2) effective force on P, F `= mg - mromega^(2) cos lamda` <br/>If g is the effective gravitational acceleration of this particle then,<br/> `mg. = mg = mromega^(2) cos lamda ` <br/> `:. B. = g - r omega^(2) cos lamda ""...(3)` <br/> `implies`But from figure `MP=r=R_(E)cos lamda` ( `:. "From " DeltaOMP` )<br/> `:. g. = g - R_(E) omega^(2) cos^(2) lamda` <br/> OR <br/> `implies` From equation (4), we get information about the variation in g with latitude due to the earth.s rotation. <br/>Special Cases :<br/> (1) At equator `lamda =90^(@) , cos lamda = 0` <br/> `:. g. =g [1-(R_eomega^2cos ^(2) 90^@)/g]` <br/> `:. g. =g [1-0]` <br/> `:. g. = g`which is the maximum value of the effective gravitation acceleration.</body></html> | |
| 38175. |
At a metro station, a girl walks up a stationary escalator in time t_(1). If she remains stationary on the escalator, then the escalator take her up in time t_(2). The time takne by her to walk up on the moving escalator will be |
| Answer» <html><body><p>`(t_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)+t_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))//2`<br/>`t_(1)t_(2)//(t_(2)-t_(1))` <br/>`t_(1)t_(2)//(t_(2)+t_(1))`<br/>`t_(1)-t_(2)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 38176. |
A bottle contains 82 gm of liquid of 10^(@)C. When it is heated to 35^(@)C, 2 gm of liquid is expelled. Calculate the apparent coefficient of expansion of liquid. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Mass of the <a href="https://interviewquestions.tuteehub.com/tag/liquid-1075124" style="font-weight:bold;" target="_blank" title="Click to know more about LIQUID">LIQUID</a> in the bottle `(m _(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>))= 82gm,` Mass of the luquid expelled `(m _(1) - m (2))= 2 <a href="https://interviewquestions.tuteehub.com/tag/gm-1008640" style="font-weight:bold;" target="_blank" title="Click to know more about GM">GM</a> ` <br/> Mass of the remaining `= 82-2 =80 gm,` Initial temperature `(t _(1)) = 10^(@)C` <br/> Final temperature `(t _(2)) = <a href="https://interviewquestions.tuteehub.com/tag/35-308504" style="font-weight:bold;" target="_blank" title="Click to know more about 35">35</a> ^(@)C,` Coefficient of apparent expansion <br/> `gamma _(a) = (m _(1) -m _(2))/( m _(2) (t _(2) - t _(1))) = (2)/( 80 ( 35 - 10)) = (2)/( 80 xx 25) = (2)/(2000) = 0.001 //^(@)C` <br/> `therefore gamma _(a) = 0.001 //^(@)C`</body></html> | |
| 38177. |
(A): If a particle is thrown upward then distance travelled in last second of upward journey is independent of the Velocity of projection. (R ) : A vertically projected body covers a distance of 4.9 m in the last second of its upward journey. |
| Answer» <html><body><p>Both (A) and (<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>) are true and (R) is the correct <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> of (A)<br/>Both (A) and (R) are true and (R) is not the correct explanation of (A)<br/>(A) is true but (R) is false<br/>Both (A) and (R) are false</p>Answer :A</body></html> | |
| 38178. |
Statement A : Whrn no external force acts on a body its centre of mass will be at rest or under uniform motion.Statement B : When a force acts on a body at its centre of mass then will have only translation motion |
| Answer» <html><body><p>only A is correct<br/>only <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a> is correct<br/>both A and B are correct<br/>Both A and B are wrong</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 38179. |
(A) A concave mirror and convex lens both have the same focal length in air. When they are submerged in water. They will still have the same focal length. ( R) The refractive index of air is greater than the refractive index of water. |
| Answer» <html><body><p>Both A and <a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a> are <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a> and R is the <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> explanation of A<br/>Both A and R are true and R is not the correct explanation of A<br/>A is true and R is false<br/>Both A and R is false</p>Answer :D</body></html> | |
| 38180. |
A liquid of density 'd' and surface Tension 'T' ascends into a capillary tube. Then the potential energy of the liquid is |
| Answer» <html><body><p>`( <a href="https://interviewquestions.tuteehub.com/tag/2pi-1838601" style="font-weight:bold;" target="_blank" title="Click to know more about 2PI">2PI</a> T)/( <a href="https://interviewquestions.tuteehub.com/tag/dg-431744" style="font-weight:bold;" target="_blank" title="Click to know more about DG">DG</a>)`<br/>`( <a href="https://interviewquestions.tuteehub.com/tag/pi-600185" style="font-weight:bold;" target="_blank" title="Click to know more about PI">PI</a> T)/( dg)`<br/>`( 2pi T^2)/( dg)`<br/>`( pi T^2)/( 2dg)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 38181. |
Torques of equal magnitude are applied to a hollow cylinder and a solid sphere, both having the same mass and radius. The cylinder is free to rotate about its standard axis of symmetry, and the sphere is free to rotate about an axis passing through its centre. Which of the two will acquire a greater angular speed after a given time. |
| Answer» <html><body><p></p>Solution :Suppose `I_(1)andI_(2)` be the respective moment of inertia of hollow <a href="https://interviewquestions.tuteehub.com/tag/cylinder-942617" style="font-weight:bold;" target="_blank" title="Click to know more about CYLINDER">CYLINDER</a> and the solid sphere and `omega_(1)andomega_(2)` be the respective <a href="https://interviewquestions.tuteehub.com/tag/angular-11524" style="font-weight:bold;" target="_blank" title="Click to know more about ANGULAR">ANGULAR</a> <a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a> and `alpha_(1)andalpha_(2)` respective angular accelerations. <br/> As can equal torque is applied to both the bodies <br/> `I_(1)alpha_(1)=I_(2)alpha_(2)` <br/> `:. (I_(1))/(I_(2))=(alpha_(2))/(alpha_(1))` <br/> but `(MR^(2))/((2)/(5)MR^(2))=(alpha_(2))/(alpha_(1))` <br/> `:.(5)/(2)=(alpha_(2))/(alpha_(1)).....(1)` <br/> Now in `omega=omega_(0)+alphat,omega_(0)=0` <br/> `omega_(1)=alpha_(1)tandomega_(2)=alpha_(2)t` <br/> `:. (omega_(1))/(omega_(2))=(alpha_(1))/(alpha_(2)).....(2)` <br/> `:. (omega_(1))/(omega_(2))=(2)/(5)` [From <a href="https://interviewquestions.tuteehub.com/tag/eqn-973463" style="font-weight:bold;" target="_blank" title="Click to know more about EQN">EQN</a>. (1)] <br/> `:. omega_(2)gtomega_(1)` <br/> `:.` The angular speed of the solid sphere will be greater than that of hollow cylinder.</body></html> | |
| 38182. |
Why are porcelain objects wrapped in paper or straw before packing for transportation ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Porcelainwaresarewrapped in strawor <a href="https://interviewquestions.tuteehub.com/tag/paper-1146067" style="font-weight:bold;" target="_blank" title="Click to know more about PAPER">PAPER</a> so thatwhentheyreceive jerksduringtransportationthe <a href="https://interviewquestions.tuteehub.com/tag/timeof-1420447" style="font-weight:bold;" target="_blank" title="Click to know more about TIMEOF">TIMEOF</a> impactmaybe more .Assuchonly asmallforcecan <a href="https://interviewquestions.tuteehub.com/tag/act-1106" style="font-weight:bold;" target="_blank" title="Click to know more about ACT">ACT</a> on Chinawaresduringsjerksand <a href="https://interviewquestions.tuteehub.com/tag/thereis-706906" style="font-weight:bold;" target="_blank" title="Click to know more about THEREIS">THEREIS</a> not fearsdamage to them.</body></html> | |
| 38183. |
A glass window is to be fit in an aluminium frame. The temperature on the working day is 40°c and the glass window measures exactly 20 cm xx 30cm. [ alpha_("glass") = 9 xx 10^(-6)//^(@) C, alpha_("aluminium") = 24 xx 10^(-6)//^(@) C]. The size of the aluminium frame is _. so that there is no stress on the glass in winter even if the temperature drops to 0^(@) C? |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/20-287209" style="font-weight:bold;" target="_blank" title="Click to know more about 20">20</a>.012 cm <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> <a href="https://interviewquestions.tuteehub.com/tag/30-304807" style="font-weight:bold;" target="_blank" title="Click to know more about 30">30</a>.01 cm`<br/>`10 cm xx 20 cm`<br/>`30 cm xx 20 cm`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/15-274069" style="font-weight:bold;" target="_blank" title="Click to know more about 15">15</a> cm xx 30 cm`</p>Answer :A</body></html> | |
| 38184. |
What is a centripetal force? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Work-done by <a href="https://interviewquestions.tuteehub.com/tag/centripetal-415325" style="font-weight:bold;" target="_blank" title="Click to know more about CENTRIPETAL">CENTRIPETAL</a> <a href="https://interviewquestions.tuteehub.com/tag/force-22342" style="font-weight:bold;" target="_blank" title="Click to know more about FORCE">FORCE</a> is <a href="https://interviewquestions.tuteehub.com/tag/zero-751093" style="font-weight:bold;" target="_blank" title="Click to know more about ZERO">ZERO</a>.</body></html> | |
| 38185. |
Show that the motion of a particle represented by y= sin omega t- cos omega t is simple harmonic with a period of (2pi)/(omega). |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Displacement `y= sin omega t - cos omega t` <br/> `therefore y= sqrt(2) [(1)/(2) sin omega t- (1)/(sqrt(2)) cos omega t]` <br/> `therefore y= sqrt(2) [cos (pi)/(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)sin omega t - sin (pi)/(4) cos omega t]` <br/> `therefore y= sqrt(2) sin (omega t-(pi)/(4))` <br/> comparing this euqation with general <a href="https://interviewquestions.tuteehub.com/tag/equation-974081" style="font-weight:bold;" target="_blank" title="Click to know more about EQUATION">EQUATION</a> of <a href="https://interviewquestions.tuteehub.com/tag/shm-630759" style="font-weight:bold;" target="_blank" title="Click to know more about SHM">SHM</a> `y= A sin (omega t + phi)`, <br/> Amplitude A= 2 unit <br/> <a href="https://interviewquestions.tuteehub.com/tag/angular-11524" style="font-weight:bold;" target="_blank" title="Click to know more about ANGULAR">ANGULAR</a> frequency, `omega = (2pi)/(T)` <br/> `therefore T= (2pi)/(omega)` <br/> `therefore omega = (2pi)/(T)` <br/> `therefore T= (2pi)/(omega)` <br/> Given function represent SHM with a periodic time `T= (2pi)/(omega)`.</body></html> | |
| 38186. |
The pressure inside two soap bubbles is 1.01 and 1.02 atmosphere respectively. The ratio of their volumes is (atmospheric pressure =10^5 Pa) |
| Answer» <html><body><p>`1:1`<br/>`2:3`<br/>`8:1 `<br/>` 3:5`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 38187. |
Deduce expressions for the excess pressure inside a : (i) liquid drop, (ii) soap bubble. |
| Answer» <html><body><p></p>Solution :(i) Liquid drop:Let us consider a liquid drop of radius <a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a> and the <a href="https://interviewquestions.tuteehub.com/tag/surface-1235573" style="font-weight:bold;" target="_blank" title="Click to know more about SURFACE">SURFACE</a> tension of the liquid is T.<br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PRE_GRG_PHY_XI_V02_C07_E03_009_S01.png" width="80%"/> <br/>The various <a href="https://interviewquestions.tuteehub.com/tag/forces-16875" style="font-weight:bold;" target="_blank" title="Click to know more about FORCES">FORCES</a> acting on the liquid drop are,<br/>(a) Force due to surface tension `F_(T)=2piRT` towards right<br/>(b) Force due to outside pressure,`F_(P_1)=P_(1)piR^(2)` towards right<br/>(c) Force due to inside pressure, `F_(P_2)=P_(2)piR^(2)` towards left<br/>As the drop is in equilibrium,<br/>`F_(P_2)=F_(T)+F_(P_1)` <br/>`P_(2)piR^(2)=2piRT+P_(1)piR^(2)` <br/>`rArr(P_(2)-P_(1))piR^(2)=2piRT` <br/>Excess pressure is `DeltaP=P_(2)-P_(1)=(2T)/(R)` <br/>(ii) Liquid bubble:A soap bubble of radius R and the surface tension of the soap bubble be T is as shown in Figure. A soap bubble has two liquid surfaces in contact with air, one inside the bubble and other outside the bubble. Hence, the force on the soap bubble due to surface tension is `2xx2piRT`. The various forces acting on the soap bubble are,<br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PRE_GRG_PHY_XI_V02_C07_E01_053_S02.png" width="80%"/> <br/>(a) Force due to surface tension `F_(T)=4piRT` towards right<br/>(b) Force due to outside pressure, `F_(P_1)=P_(1)piR^(2)` towards right<br/>(c) Force due to inside pressure, `F_(P_2)=P_(2)piR^(2)` towards left<br/>As the bubble is in equilibrium,<br/>`F_(P_2)=F_(T)+F_(P_1)` <br/>`P_(2)piR^(2)=4piRT+P_(1)piR^(2)` <br/>`rArr(P_(2)-P_(1))piR^(2)=4piRT` <br/>Excess pressure is `DeltaP=P_(2)-P_(1)=(4T)/(R)` <br/>(iii) Air bubble:Let us consider an air bubble of radius R inside a liquid having surface tension T as shown in Figure. Let `P_(1)andP_(2)` be the pressures outside and inside the air bubble, respectively. Now, the excess pressure inside the air bubble is `DeltaP=P_(1)-P_(2)`.<br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PRE_GRG_PHY_XI_V02_C07_E01_053_S03.png" width="80%"/> <br/>In order to find the excess pressure inside the air bubble, let us consider the forces acting on the air bubble. For the hemispherical portion of the bubble, considering the forces acting on it, we get,<br/>(a) The force due to surface tension acting towards right around the rim of length `2piR` is `F_(T)=2piRT` <br/>(b) The force due to outside pressure `P_(1)` is to the right acting across a cross <a href="https://interviewquestions.tuteehub.com/tag/sectional-2255905" style="font-weight:bold;" target="_blank" title="Click to know more about SECTIONAL">SECTIONAL</a> area of `piR^(2)` is `F_(P_1)=P_(1)piR^(2)` <br/>(c) The force due to pressure `P_(2)` inside the bubble, acting to the left is `F_(P_2)=F_(T)+F_(P_1)` <br/>`P_(2)piR^(2)=2piRT+P_(1)piR^(2)` <br/>`rArr(P_(2)-P_(1))piR^(2)=2piRT` <br/>Excess pressure is `DeltaP=P_(2)-P_(1)=(2T)/(R)`</body></html> | |
| 38188. |
What do you mean by saying that the work done by a system is a path function?" |
| Answer» <html><body><p></p>Solution :Work <a href="https://interviewquestions.tuteehub.com/tag/done-2591742" style="font-weight:bold;" target="_blank" title="Click to know more about DONE">DONE</a> depends not only on the initial and final <a href="https://interviewquestions.tuteehub.com/tag/states-1225920" style="font-weight:bold;" target="_blank" title="Click to know more about STATES">STATES</a> put also on the path <a href="https://interviewquestions.tuteehub.com/tag/followed-2079285" style="font-weight:bold;" target="_blank" title="Click to know more about FOLLOWED">FOLLOWED</a> by the <a href="https://interviewquestions.tuteehub.com/tag/system-1237255" style="font-weight:bold;" target="_blank" title="Click to know more about SYSTEM">SYSTEM</a>.</body></html> | |
| 38189. |
Calculate the heat required to convert 3 kg of ice at -12 ^(@) Ckept in a calorimeter to steam at 100^(@) C at atmospheric pressure. Given specific heat capacity of ice = 2100 J kg^(-1) K^(-1) , specific heat capacity of water= 4186 J kg^(-1) K^(-1) , latent heat of fusion of ice= 3.35 xx 10^(5) J kg^(-1) and latent heat of steam= 2.256 xx 10^(8) J kg^(-1). |
| Answer» <html><body><p></p>Solution :We have <br/> Mass of the ice, `m = 3` <a href="https://interviewquestions.tuteehub.com/tag/kg-1063886" style="font-weight:bold;" target="_blank" title="Click to know more about KG">KG</a> <br/> specific heat <a href="https://interviewquestions.tuteehub.com/tag/capacity-908575" style="font-weight:bold;" target="_blank" title="Click to know more about CAPACITY">CAPACITY</a> of ice, `s_("ice")` <br/> ` = 2100 J kg^(-1) K^(-1)` <br/> specific heat capacity of water , `s_("water")` <br/> ` = 4186 J kg^(-1) K^(-1)` <br/> latent heat of fusion of ice , `L_("f ice ") ` <br/> ` = 3.35 xx 10^(5) J kg^(-1)` <br/> latent heat of steam , `L_("ateam") ` <br/> ` = 2.256 xx 10^(<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>) J kg^(-1)` <br/> Now, Q = heat required to convert 3 kg of ice at ` - 12^(@) C` to steam at `100 ^(@) C`, <br/> `Q_(1) ` = heat required to convert ice at ` - 12^(@) C` to ice at `0^(@) C` . <br/> `= m s_("ice") Delta T_(1) = (3 kg) (2100 J kg^(-1). K^(-1)) [0 - (-12)]^(@) C = 75600 J` <br/> `Q_(2)` = heat required to <a href="https://interviewquestions.tuteehub.com/tag/melt-1093077" style="font-weight:bold;" target="_blank" title="Click to know more about MELT">MELT</a> ice at `0^(@) C` to water at `0^(@) C` <br/> ` = m L_("f ice ") = (3 kg) (3.35 xx 10^(5) J kg^(-1))` <br/> ` = 1005000 J` <br/> ` Q_(3)` = heat required to convert water at `0^(@) C` to water at `100 ^(@) C`. <br/> ` ms_(w) Delta T_(2) = (3kg) (4186 J kg^(-1) K^(-1)) (100^(@) C)` <br/> ` = 1255800 J` <br/> ` Q_(4)` = heat required to convert water at `100^(@) C` to steam at `100^(@) C`. <br/> ` = m_("steem") = (3 kg) (2.256 xx 10^(6) J kg^(-1))` <br/> ` = 6768000 J ` <br/> So, Q = `Q_(1) + Q_(2) + Q_(3) + Q_(4)` <br/> ` = 75600 J + 100500 J + 1255800 J + 6768000 J` <br/> ` = 9.1 xx 10^(6) J`</body></html> | |
| 38190. |
Which property of sound undergoes an apparent change due to Doppler effect ? |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :N/A</body></html> | |
| 38191. |
Two forces P and Q are acting on the same body. If P=(25+-0.2)N and Q=(16+-0.7)N find their resultant when the two forces are (i) in the same direction and (ii) in opposite direction. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :(i) `41+-0.9` (<a href="https://interviewquestions.tuteehub.com/tag/ii-1036832" style="font-weight:bold;" target="_blank" title="Click to know more about II">II</a>) `9.+-0.9`</body></html> | |
| 38192. |
The area under acceleration-time graph gives |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/distance-116" style="font-weight:bold;" target="_blank" title="Click to know more about DISTANCE">DISTANCE</a> travelled<br/>Change in <a href="https://interviewquestions.tuteehub.com/tag/acceleration-13745" style="font-weight:bold;" target="_blank" title="Click to know more about ACCELERATION">ACCELERATION</a> <br/>For acting<br/>Change in <a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a> </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 38193. |
The escapevelocities on the surface of two planets of masses m_1 and m_2 and having same radius v_1 and v_2 respectively . Then |
| Answer» <html><body><p>`v_1/v_2sqrt(m_1/m_2)` <br/>`v_2/v_1=m_1/m_2` <br/>`v_1/v_2=sqrt((m_2)/m_1)` <br/>`v_1/v_2=((m_2)/m_1)^<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 38194. |
Consider two objects of masses 5 kg and 20 kg which are initially at rest. A force 100 N is applied on the two objects for 5 second. (a) What is the momentum gained by each object after 5 s? (b) What is the speed gained by each object after 5 s? |
| Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/final-461168" style="font-weight:bold;" target="_blank" title="Click to know more about FINAL">FINAL</a> <a href="https://interviewquestions.tuteehub.com/tag/momentum-1100588" style="font-weight:bold;" target="_blank" title="Click to know more about MOMENTUM">MOMENTUM</a> on each object`Delta P = D Delta t=<a href="https://interviewquestions.tuteehub.com/tag/100-263808" style="font-weight:bold;" target="_blank" title="Click to know more about 100">100</a> xx 5 =500 kg ms^(-1)` <br/>Final <a href="https://interviewquestions.tuteehub.com/tag/speed-1221896" style="font-weight:bold;" target="_blank" title="Click to know more about SPEED">SPEED</a> on the object of mass `5 kg = 500//5 =100 ms^(-1)`<br/>Final speed on the object of mass `20 kg = 500//20 =25 m s^(-1)` <br.note acquires="" after="" but="" each="" heavier="" is="" lesser="" lower="" mass="" momentum="" not="" object="" one="" same="" seconds="" seconds.="" speed="" than="" that="" the="" with=""></br.note></body></html> | |
| 38195. |
An iron sphere of mass 20 xx 10^(-3) kg falls through a viscous liquid with terminal velocity 0.5 m/sec. Find the terminal velocity of another iron sphere of mass 54 xx 10^(-2) kg. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :3.5 m/sec</body></html> | |
| 38196. |
A bullet emerges out from a wooden plant with 75% of its initial kinetic energy. The number of additional planks required to stop the bullet is |
| Answer» <html><body><p>2<br/>3<br/>4<br/>5</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 38197. |
A cylindrical piece of cork of density ofbase area A and height h floats in a liquid of density p_(1). The cork is depressed slightly and then released. The cork oscillates up and down simple harmonically with period is (p is the density of cork) |
| Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>>`<a href="https://interviewquestions.tuteehub.com/tag/2pi-1838601" style="font-weight:bold;" target="_blank" title="Click to know more about 2PI">2PI</a>((<a href="https://interviewquestions.tuteehub.com/tag/hp-480511" style="font-weight:bold;" target="_blank" title="Click to know more about HP">HP</a>)/(p_(1)g))`<br/>`2pi((hp_(1))/(<a href="https://interviewquestions.tuteehub.com/tag/pg-591026" style="font-weight:bold;" target="_blank" title="Click to know more about PG">PG</a>))`<br/>`2pi((gp_(1))/(ph))`<br/>`2pi((hp_(1))/(g))`</p>Answer :A</body></html> | |
| 38198. |
Pressure versus temperature graph of an ideal gas is as shown in figure. Density of the gas at point A is rho_0. Density at B will be: |
| Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)/( <a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>) rho_0`<br/>`(3)/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) rho_0`<br/>`( 4)/(3) rho_0`<br/>`2 rho_0`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 38199. |
Some insects are able to walk on water .Give reason. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Some insects are able to walk because <a href="https://interviewquestions.tuteehub.com/tag/surfaceof-3091331" style="font-weight:bold;" target="_blank" title="Click to know more about SURFACEOF">SURFACEOF</a> a liquid has a tendency to contract like stretched elastic <a href="https://interviewquestions.tuteehub.com/tag/membrane-1093240" style="font-weight:bold;" target="_blank" title="Click to know more about MEMBRANE">MEMBRANE</a>.</body></html> | |
| 38200. |
Two satellite A and B revolve round the earth in circular orbits at heights R_(A) and R_(B) respectively from the surface of the earth. If the radius of the earth is R_(E), the ratio of magnitude of the velocities fo the satellites is |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>((R_(<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>) + R_(<a href="https://interviewquestions.tuteehub.com/tag/e-444102" style="font-weight:bold;" target="_blank" title="Click to know more about E">E</a>))/(R_(A) + R_(E)))`<br/>`(R_(B) + R_(E))/(R_(A) + R_(E))`<br/>`sqrt((R_(B))/(R_(A)))`<br/>`(R_(B))/(R_(A))` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |