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6301.

पी1 ८ ७७) 20 1. व(0 दे (व. ८ 6 51८ 60 Mo | ¥Cad Mefunn with ot bW»:C‘Ad004: ८00 Wen ) न ८ (909८ (0 छा 0 A <o\/er\o:\% 4 &pcasl Yot bt(७1120 12. FJounmneYy.

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6302.

2If VA 2 V calculate current flowingthrough the circuit and calculate10V⅓andVeC.6(Ans:current-1 Amp. VB2N Vc=6V)

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6303.

78. The figure below shows current in a partof electric circuit. The current i is2ampTamp1.3.mp1.1.2 amp2.3.7 ampZamp3.1.3 amp4.1 amp-tobboucho

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tq

6304.

Q.1) Three resistances of 10,2030 are connected in (a)series (b) parallel. Find in each case the following : (1)Total resistance (2) Total current ( 3) Voltage acrosseach resistance (4) Current through each resistance.Supply voltage V-230v (5 Marks)

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6305.

IV. Answer the following questions:19. Mention the factors on which the resistance of a conductor depends. ORnnected to a 6VAn electric lamp whose resistance is 20 ohm and a conductor of 4 ohm resistance are cobattery. Calculate the total resistance of the circuit

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factors on which resistance depend are:-1. resistivity of the conductor2. length of the conductor3. cross sectional area of the conductor

if the lamp and conductor connected in series then total resistance=20+4= 24 ohm

if the lamp and conductor comnected jn parallel then total resistance =(1/20)+(1/4) = 0.05+0.25 = 0.3ohm

6306.

value after one year.Find the population of a city after 2 years, which is at present 12lakh, if the rate of increase is 4%.o 2 years, which i at present 322.or at

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6307.

What is (a) the highest, (b) the lowest total resistance that can be securedby combinations of four coils of resistance 4 Ω, 8 Ω, 12 Ω, 24 Ω?5.

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Thank you

6308.

final Total resistance?

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total resistance is equal to 8 ohm

6309.

State Fleming's right Hand Rule. Give the principle, construction and working of the ACgenerator with a simple diagram. What modification will you suggest so that the output is DC14.

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Fleming's Right-hand Rule (for generators) shows the direction of induced current when a conductor attached to a circuit moves in a magnetic field. It can be used to determine the direction of current in a generator's windings.

When a conductor such as a wire attached to a circuit moves through a magnetic field, an electric current is induced in the wire due to Faraday's law of induction. The current in the wire can have two possible directions. Fleming's right-hand rule gives which direction the current flows.

The right hand is held with the thumb, index finger and middle finger mutually perpendicular to each other (at right angles), as shown in the diagram.[1]

The thumb is pointed in the direction of the motion of the conductor relative to the magnetic field.The first finger is pointed in the direction of the magnetic field. (north to south)Then the second finger represents the direction of the induced or generated current within the conductor (from the terminal with lower electric potential to the terminal with higher electric potential, as in a voltage source)The bolded letters in the directions above give a mnemonic way to remember the order. Another mnemonic for remembering the rule is the initialism "FBI", standing for Force (or otherwise motion), B the symbol for the magnetic field, and I the symbol for current. The subsequent letters correspond to subsequent fingers, counting from the top. Thumb -> F; First finger -> B; Second finger -> I

There is also a Fleming's left hand rule (for electric motors). The appropriately handed rule can be recalled from the letter "g", which is in "right" and "generator".

These mnemonics are named after British engineer John Ambrose Fleming, who invented them.

6310.

5) State right hand rule.

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6311.

5. State the use of galvanonm

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Agalvanometeris an electromechanical instrument for detecting and measuring electric current. The most commonuse of galvanometerswas as analog measuring instruments, called ammeters,usedto measure the direct current (flow of electric charge) through an electric circuit.

6312.

0 ~<gpa sy A VY P L <+ %g}\;\st 8 ) € 1979 18

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चुम्बकीय सुई या चुम्बकीय कम्पास (Magnetic Needle) में एक छोटे सुई के आकार के चुम्बक को एक काँच के ढक्कन वालेअचुम्बकीय पदार्थ से बने खोल में एक चूल (pivot) पर आलम्बित किया जाता है | सुई के उत्तरी-धूर्व अंश को काले रंग दिया जाताहै | जिससे की दोनों धुरवों में से उत्तरी-धूर्व को स्पष्ट रूप से पहचाना जा सके | चुम्बको के उपरोक्त वर्णित गुणों केअनुसार,चुम्बकीय सुई सदैव उत्तर-दक्षिण दिशा में ठहरती है| इस लघु यंत्र का उपयोग, प्रयोगशालाओ में किया जाता है | नाविक,इस यंत्र की सहायता से अपने जलयान के शीर्ष की दिशा को वास्तविक उत्तर दिशा (True north) की अपेक्षा वांच्छिक दिशा में सैटकरने के लिए प्रयोग करते है |

किसी चुम्बक के चारो ओर का वह क्षेत्र जिसमे किसी बिन्दु पर रखी गई चुम्बकीय सुई (Magnetic Needle) एक निश्चित दिशा मेंठहर जाती है चुम्बकीय क्षेत्र कहलाता है |चुम्बकीय क्षेत्र को काल्पनिक बल रेखाओ (Magnetic Lines of force ) का बना माना जाता है | चुम्बकीय बल रेखा एकनिषकोण वक्र है जिसके किसी बिन्दु पर खीची गई स्पर्श रेखा उस बिन्दु पर कार्यरत चुम्बकीय क्षेत्र की दिशा को प्रदर्शित करती है |

6313.

22. Let C be the capacitance of a capacitor dischargingthrough a resistor R. Supposet, is the time taken forthe energy stored in the capacitor to reduce to halfits initial value and t, is the time taken for the chargeto reduce to one-fourth its initial value. Then, theratio t/t, will be(b) 1 (c)(a) 2(d)N-

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c) is correct answer

6314.

5. Define permittivity. what is the SI unit and Dimension of ÂŁ, ?DG

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Definition of permittivity. : the ability of a material to store electrical potential energy under the influence of an electric field measured by the ratio of the capacitance of a capacitor with the material as dielectric to its capacitance with vacuum as dielectric. — called also dielectric constant.

In SI units, permittivity is measured in farads per meter (F/m or A.

6315.

what is dimension of velocity

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Dimesnion of velocity is metres per second (m/s).

6316.

5) State dimension and unit of momentum

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6317.

Define Dimension

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A dimension is a measurement such as length, width, or height

6318.

dy A starts from rest with an acceleration a1. After 2 seconds, another body B starts from rest with an acceleration a.If theytravel equal distances in the 5th second, after the start of A, then the ratio ai a2 is equal toA) 5: 9в) 5 : 7C)9:5D)9:7

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For the body ‘A’, the distance travelled in 5thsecond is,

S5= 0 + ½ a1(2n - 1)

=> S5= 9/2 a1 [n = 5]

For the body ‘B’, the distance travelled in the 5thsecond after the start of A is actually the distance travelled by the body B in the 3rdsecond, since, B starts 2 s later.

Therefore,

S3= 0 + ½ a2(2n - 1)

=> S3= 5/2 a2 [n = 3]

Since, the distance travelled are same,

9/2 a1= 5/2 a2

=> a1: a2= 5 : 9

6319.

A block of mass M is pulled along a horizontal frictionless surtat one end of the rope as shown in figure, then the force which the block exerts on the rope i521.ace by a rope of mass m. If a force F is appliedmFMF(d) Mm iMm tM

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6320.

et of weight W' dropped from aStrikes the ground and comes to restardation equal to twice the accelerationot gravity. The force exerted on thegrounds is4) 4W

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Force exerted is equal to the change in momentum in one second. Now, retardation is rate of decrease of velocity. The value of retardation is given as 2g. Then,

Force, F=dp/dt=m(dv/dt). But,

m=W/g and dv/dt=2g, therefore ,

F=(W/g)(2g)=2W

6321.

A ladder 1.5 m is place against the wall in such a way that the foot of the ladder is 0.6 m away fronwall. Find the height of the wall to which the ladder reaches.

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ladder is 1 .5 m

6322.

A-6. A child is standing in front of a straiaht plane miror. His father is standingbehind him, as shown in the figure. The height of the father isheight of the child. What is the minimum length of the mirror requirthe child cancompletely see his own image and his father's image in the mirror?ed so that(Height of child is H)5H6B)2зн2(D)

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6323.

RectilinearMotionIn a car race, car A takes time t less than ear B and passes the finishing point with a velocity v more than thevelocity with which car B passes the point. Assuming that the cars start from rest and travel with constant24.accelerations a and a2, the value ofs

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6324.

oving on a circular road of radius r 150 m and its speed is increasing at a r92 Ainstant its speed is 30 m/s, net acceleration of the car at this instant is(1) 8 m/s2(3) 10 m/s2rate 8 mis?.(2) 6 m/s2(4) 14 m/s?

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= Radius of circular path = 150 m= Perimeter or length of path = 2 Pi r = 2 * 22 / 7 * 150 = 942.85 m.

= v = u + a t

= 30 = 0 + 8 * t

= t = 3.75 s.

S = u t + 1 /2 a t^2

942.85 = 0 + 1 / 2 * a * 3.75^2

= 942.85 = 7.03 a

= a = 13.4 m/s.

Why did you take initial velocity 0? It is not stated and we can't assume that...

6325.

Give the value of X in the following nuclearreaction:U238Th 234He92(A) 92(C) 90(B) 2(D) 4

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Correct option is C) 90

6326.

What ls2.er what area should a force of 100 N act to produce a pressure of 500 pascal?

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6327.

2 dyne1 Newton= 105 dyneEXAMPLE 22 Calculate the number of w a, footin one horse power. (1 horsepower = 550 ×32 footpoundal/sand uatt are the

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Mechanic / Hydraulic horsepower

1 hp(I) = 745.699872 W=0.745699872 kW

Electrical horsepower

1 hp(E) = 746 W = 0.746 kW

Proof:

One mechanical horsepower of 550 foot-pounds per second is equivalent to 745.7 watts.

1 hp = 550 Foot Pound per second

1 Pound = 4.44822 Newtons

1 Foot is 0.3048 Meters.

1 hp = 550 * 4.44822 * 0.3048 meters

1 hp = 745.69 Newton meter per second = 746watts

6328.

63. For the network shown in the figure thethe current i is :-2Ω4Ω4Ω3Ω6Ω18V5V

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This arrangement is a wheat stone bridge

as 4/6 = 2/3 ..

so. here , the middle resistance has no. current.

so, the 4Ω and 2Ω , will combine in series add up to 6Ω

and the lower 6 and 3 will add up to 9Ω

now this 6 and 9 are in parallel to each other so, Req = 6*9/(9+6) = 54/15 Ω

so I = V/R = 15V/54 = 5V/18 .

6329.

Find the equivalent resistance of the network shownin figure between the points a and b.

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6330.

For the network shown in the figure, the value of the current9V3518V305V5V18เฉ

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As 4/6= 2/3so middle resistance will be removedBecause of balance bridgeso now4+2//6+3= 6//9= 6*9/15= 54/15 total resistancenow I= V/R= V/54/15= 15V/54= 5V/18

6331.

10. A network is shown in the figure. Each resistance'ls 2 12isThe offective resistance between P and(

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6332.

●The wavelength of a radio wave is 1.0 m. Find its frequency.

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f=c/lf=3*10^8/1f=3*10^8sec^-1

6333.

\vec{A}=-2 i+3 j-4 \hat{k} \text { and } \vec{B}=3 \hat{i}-4 \hat{j}+5 \hat{k} . \text { Find } \vec{A B}

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Α.B = (-2î+3ĵ-4k̂).(3̂î-4ĵ+5k̂)= (-2*3) + (3*-4) + (-4*5)=-6-12-20=-38

6334.

Which of the following is the unit of heat?Joule/ fm卉才河俞Ampere/trta261 Volt /-Who among the following is the future Buddha that is yet to come? fha

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the unit of the heat is joule

joule is the unit of heat

6335.

1. A bird hit the windscreen of a fast moving car and fell on the bonnet. Which of the two, caror the bird, suffers greater change in momentum?

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Answer:The bird will suffer more change in momentum.

Explanation:Becoz. as compared to car the mass of a bird is negligible and also the velocity of car is more than that of bird...after the collision the car continues to be in motion whereas the bird comes to hault(rest)..therefore there is more change in momentum of the bird..

6336.

RasonaneeL8

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Definition of Resonance - "The increase in amplitude of oscillation of an electric or mechanical system exposed to a periodic force whose frequency is equal or very close to the natural undamped frequency of the system."

6337.

A card is drawn from a pack of 52 playing cards.Find the probability that it is (a) a redking (b) a face card.12

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6338.

theirAsprings, string and pulley shown in figure are light. Initially when both the springs were innatural state, the system was released from rest. The maximum displacementCalculate xSmgof block m is xxl-1.Spring, KSpring, mITIITTTTT

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wrong answers

6339.

Z |ही PooClone J (१0९.हAh BQ©ot203hpeedo % हक ADKa crelorn.

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We knowthatV= u+ata= v-u/tV= 10*1000/3600= 100/36= 50/18u= 40*1000/3600= 400/36= 100/9= 50/18-100/9/(5)2.7-11.1/51.682 retarded motionas a= -ve

6340.

What will be the force constant of the spring systemshown in the figure19.k1k2(b) 2k, k(d) 2k, k

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6341.

it-2 + iß, ß e R-{0} is a root of x3 + 63x + λ = 0, λ e R then find roots of equation

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is it one question answer or full book answer

6342.

A submarine emits a sonar pulsewhich returns from anunderwater cliff in 1.02 s. If thespeed of sound in salt water is1531 m/s, how far away is theclif?

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6343.

28. Determine the current i in the circuit shown inAns. 25 A]Fig. 2.38.3Ω2Ω2Ω100 VC12Ω406ΩFig. 2.38

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6344.

of mass.MSE (Chandigarh), 200oThe diameter of a sphere is 5.32 cm. Calculate itssurface area with regard to significant figures.14.IKVS, 2006]

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6345.

QuestionsObjectiveSingle Correct OptionThe dimensional formula for Planck's constant and angular momentum are(a) [MIT)] and [MLT-11(c) [ML'T Jand [MI'T-21(d) (MLT Jand [MLT

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The dimensions of Planck's constant are the same as those of angular momentum.

hence, ML^2T-1 is correct for both.

6346.

) 14. Define unit vectorFind out a unit vector parallel to a vector A=21+3-4

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A unit vector is any vector that has a magnitude of one and could be pointing in any direction.

6347.

1. Find a unit vector parallel to the vector 3i+7j+4k.[MSE (Chandigarh), 2002]

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unit vector=given vector/magnitude of that vectorgiven vector=3i+7j+4kmagnitude=(3^2 +7^2 +4^2)^0.5magnitude=(9+49+16)^0.5=74^0.5unut vector=(3i+7j+4k)/(74^0.5)

6348.

A bus starts moving with uniform acceleration fromits position of rest. It moves 48 m in 4 s. On apply-ing the brakes, it stops after covering 24 m. Find thedeceleration of the bus.

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During first 4 sS = ut + 0.5at²48 m = (0 m/s × 4 s) + (0.5 × a × (4 s)²)48 m = (a × 8s²)a = 6 m/s²

Velocity at the end of 4s isv = u + at= 0 m/s + (6 m/s² × 4 s)= 24 m/s

Now, for rest of the journeya’ = (v² - u²) / (2S)= (0² - 24²) / (2 × 24)= -12 m/s²

∴ Deceleration of bus is 12 m/s²

thank you very much

6349.

If a block moving up an inclined plane at 30a velocity of 5 m/s, stops after 0.5 s,coefficient of friction will be nearly

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Initial velocity u=5m/s, final velocity v=0retardation=am/s2,. time=0.5secv=u+at0=5+a×0.5a=-10m/s2mg can be resolved as mgcos30° (acting opposite to normal reaction)and mgsin30°.(acting downwards)(R ) normal reaction=mgcos30°friction f=uR, where u is cofficient of frictionnet force= -(f+ mgsin30°)ma=-(uR+mgsin30)m(-10)=-(u.mgcos30+mgsin30)10m=m(u×√3/2+1/2).g10/g=√3u/2+1/2take g=10, and solving the equationu=1/√3

6350.

A bus starts moving with uniform acceleration fromits position of rest. It moves 48 m in 4 s. On apply-ing the brakes, it stops after covering 24 m. Find thedeceleration of the bus

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During first 4 sS = ut + 0.5at²48 m = (0 m/s × 4 s) + (0.5 × a × (4 s)²)48 m = (a × 8s²)a = 6 m/s²

Velocity at the end of 4s isv = u + at= 0 m/s + (6 m/s² × 4 s)= 24 m/s

Now, for rest of the journeya’ = (v² - u²) / (2S)= (0² - 24²) / (2 × 24)= -12 m/s²

∴ Deceleration of bus is 12 m/s²