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8251.

1094. In a repulsion motor, commutator provides a means of connecting

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In repulsive sort of motor we use Normally wires as a commutator

8252.

Why is it difficult to walk on a muddy road?

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on the slippery ground friction is much less

On the slippery ground, the friction is much less and we cannot exert a backward action force on it which would produce a forward reaction force on us. Hence, it becomes difficult to walk on a slippery road.

8253.

to cpul.6. Why is it difficult to walk on a muddy road?

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8254.

Chinaware s are wappedil stiaw paphy we hurt less when we jumps on a muddy floor in comparison to a hard floor?110od in cors scooters and motorevcles

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When we jump on a muddy floor, the floor is carried in the direction of the jump and the time interval \[\Delta t\]for which force acts is increased. This decreases rate of change of momentum and hence the force of reaction. Therefore we are hurt less.

8255.

plainhow you can take care of your eyes

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8256.

Ask an electrician to explain to youthe electrical wining in your houseand other related important points.Take care to understand them well,and explain them to others also

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switches,three type of wire,and other wiring material

8257.

Q.14 Two blocks of masses m, = 10 kg andm2 15 kg are connected using an ideal string.Find the acceleration of the mass m2",-10kg200N(1) 6 m/s2(3) 8 m/s2(2) 2 m/s2(4) 4 m/s2

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net force acting on the system = 200Ntotal mass = (15+10) = 15kg

so acceleration = net force/total mass = 200/25 = 8m/s²

both the blocks will move with same acceleration.

option 3

thanx bro

8258.

melhod of centrifugation.- vample of muddy water?3. Explain the crystallizationDiffan

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crystallization is the process by which crystals of salt etc are produced while doing experiment in Science.

8259.

nal force between two masses at ad' apart is 6N. If these masses are takenn and kept at same separation, then the forebetween them will become(1)1 N(3) 36 N(2) N(4) 6 N

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6N because mass is constant in universe its un changed

and hence g is also universal constant

8260.

20, Two masses mSkg and mskg tied to a strindgare hanging over a light frictionless pulley What is theacceleration of the masses when they are free to movenl s(a) 02 ms(b) 98 msrrm(d) 48 m/

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8261.

Gravitational force between two masses at adistance 'd' apart is 6N. If these masses are takento moon and kept at same separation, then the forcebetween them will become :(1) 1 N(2) N6(3) 36 N(4) 6 N

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8262.

8. A car is moving at a constant speed of 40 km/h along astraight road which heads towards a large vertical walland makes a sharp 90 turn by the side of the wall. Afly flying at a constant speed of 100 km/h, starts fromthe wall towards the car at an instant when the car is20 km away, flies until it reaches the glasspane of thecar and returns to the wall at the same speed. It continuesto fly between the car and the wall till the car makes the90° turn. (a) What is the total distance the fly hastravelled during this period? (b) How many trips has itmade between the car and the wall?

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8263.

Diagonals AC and BD of a trapezium ABCDwith AB || DC intersect each other at thepoint O. Using a similarity criterion for two3.OA OEBOC OD,triangles, show that a

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8264.

2-1 Describe an atom and how atomic structure affectsinteractions between atoms

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An atom is the smallest component of an element having the chemical properties of the element, consisting of a nucleus containing combinations of neutrons and protons and one or more electrons bound to the nucleus by electrical attraction; the number of protons determines the identity of the element.

Elements are made of atoms, and the structure of the atom determines how it will behave when interacting with other chemicals. The key in determining how an atom will behave in different environments lies in the arrangement of electrons within the atom.

8265.

36. A particle is moving with velocity v-Ktyi+x)whe k is constant. The general equation of its pa(c# constant) is(4) yx2 + c

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As v= k(yi + xi)vₓ= Ky so dₓ/dt = Kyvy= Kₓ so dy/dt = Kₓ

dividing both equationsdy/dₓ= dy/dt divide dx/dt = Kx/Ky =x/yyou will getydy= xdx

integrating the equationy²/2 = x²/2 + c

Hence, option (1) is correct.

8266.

21. A force F-U'xA is exerted on a particle in addition tothe force of gravity, where v is the velocity of the particleand A is a constant vector in the horizontal directionWith what minimum speed a particle of mass m beprojected so that it continues to move undeflected witha constant velocity?

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8267.

ctive indicies of some media are listed below. Name the modia inwtiich the velocity of light is minimum & maximum.Medium Refractive Index1.621.81.942.43

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As index of refraction value increases, the optical density increases, and the speed of light in that material decreases.

Therefore, velocity of light is minimum for medium N and maximum for medium K

8268.

With what minimum velocity should blockbe projected from left end A towards end Bsuch that it reaches the other end B ofconveyer belt moving with constant velocityv. Friction coefficient between block and4.belt is u.(B) /2ugL(D) 2/HgL(A) VugL

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8269.

Velocity of light is minimum in - a) diamond, b) water, c) air, d) glass

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option D glass is the answer.

8270.

(al 10 s161 12passenger is at a distance of x from a bus when the bus begins to move with constanthat is the minimum velocity with which the passenger should run towards the busso as to reach it?[b] 2axIc] vaxIdl ax

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8271.

The motion of a car is.described by the velocity-time graph as shown infigure given below.A.010 20 30 40 50 60

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Question you have submitted is incomplete. Please post a complete question.

we have to find distance from the graph.Here graph is velocity to time.By finding area we can get distance.so distance=1/2*20*5+20*5+1/2*10*5 =50+100+25=175m

8272.

Example 2.3 The moon is observed troho diametrically.。wo diametrically opposite points A and Bory Darth. The angle e subtended at theoon by the two directions of observationis 1°54', Given the diameter of the Earth tobe about 1.276 x 107 m, compute thedistance of the moon from the Earth

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Here parallactic angle, ø=1°54'=114'=(114×60)"=114×60×4.85×10^-6 rad = 3.32×10^-2 radBasis, b=AB=1.276×10^7 mSo, the distance of the moon from the earth, S= b/ø =(1.276×10^7)÷(3.32×10-2)= 3.84×10^8 (ans)

Here parallactic angle, ø=1°54'=114'=(114×60)"=114×60×4.85×10^-6 rad = 3.32×10^-2 radBasis, b=AB=1.276×10^7 mSo, the distance of the moon from the earth, S= b/ø =(1.276×10^7)÷(3.32×10-2)= 3.84×10^8 (ans)

thaks

8273.

an object is moving in circular track of radius 7m. find its distance and displacement after half revolution

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8274.

A particle is moving in a circular path of radius r. What will be the displacement after a half circle?

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8275.

Potential energy of two equal and opposite point charges 2ÎźC each held i mapartin air is

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8276.

In the above problem, if the cyclist reaches exactlythe other side of the point x (i.e. diametricallyopposite point to x), then find the distance travelledand magnitude of displacement of cyclist.7.

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8277.

-0 .•DIn the given figure, if Q, and Q, are positive, where could a negative charge be placed so as to have verticallyupward net force on it?(1) A(2) B(3) O(4) D(5) Et o in the como or the horizontal distance from F

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The figure shows thefield lines.If a negative charge is placed at extreme right or extreme left, the charge will experience a net force in opposite direction. Also, on the line perpendicular to the line joining the charges, the negative charge will experience a net force towards the centre of system.

As I said, “Up” is a relative direction. Therefore, in any of the above configuration, for some reference frame, the force will act “vertically Up”.

8278.

1. Obtain the formula of kinetic energy of an object

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Like if you find it useful

8279.

entripetal acceleration of a cyclist completing 7 rounds in a minute along a circular track of radius 5 m witha constant speed, is(1) 2.7 m/s2(3) 3.78 m/s2(2) 4 m/s2(4) 6 m/s2nleration becomes

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Hence, option (1) is correct.

8280.

Q.11 (a) What happens to the focal length of a lens which is immersed in water?(b) An object is placed at the focus of a concave lens. Where will be its image formed?

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8281.

Find the sum of odd integers from 1 to 2001.

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1+3+5+7+9+....+1999+20012001=1+(n-1)22000=2(n-1)n-1=1000n=1001S1001=(1001/2)(1+2001)=1001/2(2002) =1001*1001=1002001

8282.

Define heat ? Write its units?

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Heat is a form of energy that can be transferred from one object to another or even created at the expense of the loss of other forms of energy.Joule is unit of energy

8283.

Define the term heat.

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Heat is the form of energy that is transferred between two substances at different temperatures. The direction of energy flow is from the substance of higher temperature to the substance of lower temperature.

8284.

s3. An objec!less inwater or more in watel. GIvown an equation that defines density54 1a5 kg of material A occupydensityy 20 cm3 whereas 20 kg of material B occupy 90 cm3. Which has the greaterA or B ? Support your answer with calculations

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8285.

A wire of length 2 m and cross sectional area10-4 m2 is stretched by a load 102 kg. The wireis stretched by 0.1 cm. Calculate longitudinalstress, longitudinal strain, Young's modulus ofmaterial of wire.

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Given, length of wire, l = 2m

cross sectional area , A = 10^-4 m²

Load , F = 102kgwt = 102 × 9.8 N

extension of wire, ∆l = 0.1cm = 0.001m

Longitudinal stress = F/A

= 102 × 9.8/(10^-4)

= 999.6 × 10^4 ≈ 1 × 10^7 N/m²

Longitudinal strain. = extension of wire/original length of wire = ∆l/l

= 10^-3/2 = 5 × 10^-4

we know, Young's modulus = longitudinal stress/longitudinal strain

= 1 × 10^7/5 × 10^-4

= 20 × 10^9 N/m²

Like my answer if you find it useful!

8286.

3 x ^ { 2 } + 16 x + 5 = 0

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8287.

32. Water is flowing at a speed of 1.Sms through horizontal tube of cross - sectional area10 ms and you are trying to stop the flow by your palm Assuming that the waterstops immediately after hitting the palm the mininmum force that you must exert shoadbe (density of water-10kg)1) 15N2) 22.5N3) 33.7N4) 45N

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Since the water attains zero velocity immediately after impact with palm , the force acting on it will be (Density)(Area) [(velocity)^2] because this is actually the momentum of the water flowing per second, which is actually force.

I was able to write this because AreaxVelocity is Quantity of Water flowing per second. Multiply this by Density , you get Mass of water flowing per second. Multiply this by velocity and you get momentum flowing per second. You can check that the dimensions of this formula have the same dimensional formula as that of force.

Now putting the values, we obtain the answer b.) 22.5 N

8288.

EXAMPLE 1.8A cube of wood floating in water supportsa 300 g mass at the centre of its top face.When the mass is removed, the cube risesby 3 cm. Determine the volume of thecube.

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Let the side of the cube be ‘a’ cm and its mass be ‘m’.

So, density of the cube is, ρ = m/a^3

Let ‘h’ be the immersed height of the cube.

So, volume immersed = ha^2

And, mass of water displaced = (ρw)ha^2

For floatation, weight of water displaced = weight of cube

=> (ρw)ha^2g = mg

=> m = (ρw)ha^2

Again, when 300 g is added to the cube the cube is immersed further by 3 cm.

So, the new volume of water displaced = (h+2)a^2

The new mass of water displaced = (ρw)(h+2)a^2

Thus,

(ρw)(h+3)a^2g = (m+300)g

=> (ρw)(h+3)a^2= (ρw)ha^2+300

For water. ρw= 1 g/cm3

So,

(h+3)a^2= ha^2+ 300

=> ha^2+ 3a2= ha^2+ 300

=> a = 10 cm

This is the length of a side of the cube.

8289.

eyes

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Eyesare organs of the visual system.

They provide organisms with vision, the ability to receive and process visual detail, as well as enabling several photo response functions that are independent of vision.

Eyesdetect light and convert it into electro-chemical impulses in neurons.

8290.

के प्रतिरोध क॑ सिरों क॑ बीच विभवान्तर! 10V-3Q

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8291.

Calculate the work done in moving acharge 6C from a point of 10V to apoint of 100V

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8292.

1.2 In the circuit:10v034+21The value of i, is(A)2A(C)2.6A(B) -0.06(D) 1.4A

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10/2-3A= 5-3= 2A

Option-A

option A is the right answer.

8293.

what is ribosome

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Theribosomeis a complex molecule made ofribosomalRNA molecules and proteins that form a factory for protein synthesis in cells. In 1955, George E. Palade discoveredribosomesand described them as small particles in the cytoplasm that preferentially associated with the endoplasmic reticulum membrane

ribosome is a cell organelle. It functions as a micro-machine for making proteins. Ribosomes are composed of special proteins and nucleic acids. The TRANSLATION of information and the Linking of AMINO ACIDS are at the heart of the protein production process.A ribosome, formed from two subunits locking together, functions to: (1) Translate encoded information from the cell nucleus provided by messenger ribonucleic acid (mRNA), (2) Link together amino acids selected and collected from the cytoplasm by transfer ribonucleic acid (tRNA). (The order in which the amino acids are linked together is determined by the mRNA) and, (3) Export the polypeptide produced to the cytoplasm where it will form a functional protein.

8294.

D.IVIOA. 2C. 3How many electrons are present in the outermost orbit of oxygenatom?A. 2C. 3B. 6464

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B. 6

Explaination : Electronic configuration of Oxygen = 2, 6.

8295.

Electrons in the outermost orbit are called.

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Electrons in the outermost orbit are called valence electronsPlease hit the like button if this helped you.

8296.

calculate number of electrons present in 1 Microcoulamb

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One electron possesses a charge of 1.6 ×10-19C, i.e., 1.6 ×10-19C of charge is contained in 1 electron.

∴ 1 C of charge is contained in 1/1.6 x 10-19= 6.25 x 1018= 6 x 1018

Therefore,6 x 1018electrons constitute one coulomb of charge.

8297.

3.The number of electrons present in 1 C of chargeis

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The charge on an electron is negative and it is -1.6⨯10-19coulomb therefore, 1 C charge is carried by 1/ (-1.6⨯10-19) = 6.25 ⨯ 1018electrons.

Hence if 1 A current flows through a conductor, it implies that6.25 ⨯ 1018electrons pass per a second across the cross section of the conductor.

8298.

Propagation of Sound

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ThePropagation of sound.Soundis a sequence of waves of pressure whichpropagatesthrough compressible media such as air or water. (Soundcanpropagatethrough solids as well, but there are additional modes ofpropagation). During theirpropagation, waves can be reflected, refracted, or attentuated by the medium

8299.

10. The magnetic force on a moving charge q' withvelocity v in magnetic field B is given by,F q (v x B). If the angle between v and B is60°, then the value of F v(1) can't be calculated because of insufficient data.(2) are qv'B sin 0.(3) are zero(4) are qvB cos θ.

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Yes option 2). is correct because we just need to multiply both sides by dot product of v.

8300.

For the transistor circuit shown below, if\beta=100, voltage drop between emitter and baseis 0.7 V then value of VCE will be :-(1) 10 v(2) 5 v(3) 13 v(4) 0 v

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Option (3) is correct.