InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 8301. |
51. In n-p-n transistor circuit, the collectorcurrent is 10mA. If 90% of the electronsemitted reach the collector |
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| 8302. |
The number of electrons present in the outermost of an atom represents |
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Answer» The number of electron present in outermost of an atom represent valency |
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| 8303. |
For the transistor circuit shown belowB 100, voltage drop between emitter and baseis 0.7 V then value of VCE will be :-1002T 18VCE5V(1) 10 V(2) 5 V(3) 13 V(4) 0 v |
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Answer» Option (3) is correct. |
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| 8304. |
>. A ball is dropped from a height. If it takes 0-200 s tocross the last 6-00 m before hitting the ground, find theheight from which it was dropped. Take g - 10 m/s2 |
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Answer» i am getting ans as 45 m is it correct No! your calculation of initial velocity is wrong, you cannot use speed - distance formula in the case of acceleration. can you give the reason for that |
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| 8305. |
03. AAMrelsarticle starts from rest with constant acceleration. Ita distance x in the first 10 s and a distance y in the next 20 s. Theion between x and y is (a) y x (b) y2x (c) y 8x (d) y-4x. 04. |
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Answer» distance covered in 1st 10sec => x= 1/2*(a)*(10)² = 50a speed after 10sec => v = 10a so, y = 10a*(20) +1/2*(a)*(20)² =200a+200a = 400a so, here y/x = 400a/50a = 8 y = 8x option c |
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| 8306. |
andd vPetle is ven byr13 |
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Answer» At the highest point, vertical velocity is zero. Hence dy/dt = 0, I.e, 16–30*t = 0. That means, the projectile reaches its maximum height at t = 8/15 seconds. At this time, y = 64/15 SI units. |
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| 8307. |
fricuoniess TheThere are some passengers insiaea suauonary railway comparment. The track iscentre of mass of the compurtment nself (without the passengers is C, wniie the centre of mass of thecompartment pius passengers system is CIf the passengers move about insÄąde the comparumentalong tne trackA, bo C and C, will move with respect to the ground(B) neither C nor C, will move with respect to the groundcC will move but C, will be stationary with respect uo the grounaD)C wili move bur C will be stationary with respect to tne grouna.cer acrs n a sysrem ot partuciss. The velocity and acceleration of the cenlre o! |
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| 8308. |
6. A piece of brass of volume 30 cm3 has a mass of252 g. Find the density of brass in (i) g cm-3, l(ii) kg m-3.16, A |
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Answer» thanks |
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| 8309. |
Calculate the work done for adiabatic expansionof a gas |
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Answer» According to first law of thermodynamics, ΔU = q + W In adiabatic process, q = 0 Hence , ΔU = W and ΔU = Cv ΔT Thus it can be written as W = Cv ΔT W = Cv [T2 - T1] |
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| 8310. |
The weight of a rock on the moon is 200.6 N. What isits mass on the earth?(Take g of earth 9.8 ms^-2 ; g of moon - 1.7ms^-2)(A) 20 kg (B) 118 kg (C) 200 kg (D) 1180 kg |
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| 8311. |
n object is projected from ground with speed0 m/s at angle 30° with horizontal. Its centripetalacceleration one second after the projection is[Take g 10 m/s2] |
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| 8312. |
what is adiabatic change |
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Answer» Adiabatic change: The change in pressure and volume of a gas resulting a change in temperature without exchange of heat in an isolated system is called adiabatic changes. |
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| 8313. |
what is adiabatic heating |
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Answer» Adiabatic heating Adiabatic processes are those in which there is no net heat transfer between a system and its surrounding environment (e.g., the product of pressure and volume remains constant). Because it is a gas, air undergoes adiabatic heating and cooling as it experiencesatmospheric pressurechanges associated with changing altitudes. Increasing pressure adiabatically heats air masses, falling pressures allow air to expand and cool.With adiabatic heating, as a mass of air descends in the atmosphere—as it does when it moves downslope from a mountain range—the air encounters increasing atmospheric pressure. Compression of the air mass is accompanied by an increase in temperature. |
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| 8314. |
2. Name the experiment which confirms the wave nature of electron |
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Answer» The experiment that shows the wave nature of electron is Davisson and Germer experiment. |
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| 8315. |
58.53. What will be the maximum speed of a car on aroad turn of radius 30 m if the coefficient of frictionbetween the tyres and the road is 0.4(Take g=9.8 m/s2)Va) 10.84 m/s (b) 9.84 m/s(c) 8.84 m/s (d) 6.84 m/s |
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| 8316. |
Obtain the relation (a) P, V (b) V, T (C) P, T during adiabatic change |
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| 8317. |
23. Solar radiation emitted by sun resembles that emitted by atherblack body at a temperature of 6000 K. Maximum intensity isemitted at wavelength of about 4800 Å. If the sun were tocool down from 6000 K to 3000 K, then the peak intensitywould occur at a wavelengthtem(a) 4800A (b) 9600 A () 2400 A (d) 19200 A |
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Answer» 9600A |
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| 8318. |
16. In Young's experiment, the wavelength of lightused is 6000 A, the distance between two slits is0.05 cm and the distance of screen from the slits is1 m. Find out the distance between first dark fringeAns. 0.06 cm.and first bright fringe. |
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| 8319. |
(C)The central fringe will be white. |
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Answer» You can understand that the central fringe itself is white. Fringe width of individual colours is directly proportional to (approximately) the wavelength of the colour. To understand why, it's easy enough. Central fringe is the place on the screen where there is zero optical path difference(or phase difference) between any to waves simultaneously emanating from the two slits. Moving away from the central fringe means there is a difference in distance travelled by such waves to reach the given point. When you move more closer to one of them means you increase the path difference. When you want more change in phase difference for lesser path difference, then wavelength must be smaller. 2 pi times the ratio of path difference to wavelength gives phase difference. |
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| 8320. |
in a Young's double sit experiment wave length of light used is 5000 Aand distance between the slits is 2 mm, distance of screen from the slitss 1 m. Find fringe width and also calculate the distance of 7h dark fringefrom central bright fringe |
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| 8321. |
earth s mageduc neld t tha lcain3 015, A galvanometer coil has a resistance of 12 Ί and the metre shows full scale deflection for a currentof 3 mA. How will you convert the meter into a voltmeter of range 0 to 18 V?16, A beam of light consisting of two wavelengths 650 nm and 520 nm is used to obtain interferencefringes in a Young's double slit experiment. What is the least distance from the central maximumwhere the bright fringes due to both the wavelengths coincide? The distance between the slits ismm and the screen is at a distance of 1 m from the slits.1 |
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Answer» Like my answer if you find it useful! |
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| 8322. |
what is potential difference and what is its Si units |
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Answer» SI UNIT IS :VOLTand it is denoted by letter v hi |
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| 8323. |
gas molecule of mass 10-27 kg is movingwith a velocity of 18 kmh-1.Calculate the.S.C.E.2011)K.E. in SI units.(H.P.S |
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| 8324. |
,.Showthatmaximumintensityininterferencepatterm is four times theintensity due to each slit if amplitude of light emerging from slits issame |
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Answer» Intensity is directly proportional to the square of amplitude 'a'.As both slits have same intensity both have the same amplitude. Constructive interference is due to mixing of waves in phase and hence maxima.As in phase then amplitudes have to be added. So a+a = 2aSquare of this gives the intensity of maximum. So 4 a2Hence 4 times the intensity of light being used |
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| 8325. |
b. In Young's experiment, the wavelength of lightused is 6000 A, the distance between two slits is0.05 cm and the distance of screen from the slits is1 m. Find out the distance between first dark fringeAns. 0.06 cm.and first bright fringe. |
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Answer» fringe width=wavelength xdistance from screen/slit differencehencefringe width=6000*10^-10*1/0.05*10^-2=0.12cmdistance between first dark and bright fringe is=0.12/2=0.06cmas fringe width is the distance in bright to bright hence half of distance |
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| 8326. |
1. How can we decide whether an object is movingfaster than the other. |
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Answer» by finding its net force by finding is net force by finding the velocity of both objects If the speed of an object is faster than the other object then we can say that an object is moving faster than another 4.5 If the speed of an object is faster than the other object then we can say that an object is moving faster than another |
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| 8327. |
Ifthe distance travelled by a body in the nth second is given by (4+ 6 n) m then find theinitial velocity and acceleration of the body. |
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Answer» Snth= u + a(n-1/2) = u -a/2 + an Snt= 4 + 6n (given) comparing both equations u-a/2 = 4 , a = 6m/s^2 u = 4+a/2 = 7m/s |
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| 8328. |
TION OF LIGHTht will take to travelplate of thicknessglass is 1510-12the interference patter?7. The intensity ratio in the interference pattern is19. What is the amplitude ratio and the ratioof widths of two slits?(Hr. Board 2011) (Ans. 2:1:4:11intensity ratio |
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| 8329. |
8)State the SI units of gyromagnetic ratio and magnetic intensity. |
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Answer» 1.Its SI unit is theradianpersecondper tesla (rad⋅s−1⋅T−1) or, equivalently, the coulomb per kilogram (C⋅kg−1). The term "gyromagnetic ratio" is often used as a synonym for a different but closely related quantity, theg-factor. Theg-factor, unlike the gyromagnetic ratio, is dimensionless. 2.In SI units, B is measured inteslas(symbol: T) and correspondingly ΦB(magnetic flux) is measured inwebers(symbol: Wb) so that a flux density of 1 Wb/m2is 1tesla. |
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| 8330. |
r one of two identical slits producing interference in Young'sexperiment is covered with glass, so that the light intensitypassing through it is reduced to 50%, find the ratio of themaximum and minimum intensity of the fringe in the interferencepattern.What kind of fringes do you expect to observe if white light is usedinstead of monochromatic light?(a) I(b) |
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Answer» (b) White light consists of waves of inumerable wavelengths starting from violet to red colour. Therefore if monochromatic light in Young’s interference experiment is replaced by white light, then the waves of each wavelength form their separate interference patterns. The resultant effect of all these patterns is obtained on the screen. The path difference between waves starting from S1 and S2 at the location (M) of central fringe is zero,i.e., for pointMof screenS1m− S2m=0 i.e., the waves of all colours reach at mid pointMin same phase. Therefore the central fringe (atM) iswhite. As fringe width ,i.e., wavelength increases in order of colours denoted by VIBGYOR therefore on either side of it some coloured fringes are obtained in order of colour VIBGYOR. That is the violet (V) fringe appears first and the red (R) the last. After this the fringes of many colours overlap at each point of the screen and so the screen appears uniformly illuminated. Thus if we use white light in place of monochromatic light the central fringe is white, containing on either side a few coloured fringes (in order VIBGYOR) and the remaining screen appears uniformly illuminated. |
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| 8331. |
A block A constrained to slide along the incline plane of thewedge B. Block A is attached with a string which passes through pthree ideal pulleys and connected to the wedge B. If the wedge ispulled towards right with an acceleration 'a'. The acceleration ofthe block with respect to wedge is(C) a(A) 2a(B) 1.5a(D) zero |
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Answer» The tension will be related to the weight of the block A. All parts of the string will have the same speed and magnitude of acceleration. As we look at the acceleration of the block Awrt wedge B, we can add a pseudo force on the block in the leftside direction. OR, equivalently, add an acceleration of "-a" towards left.With respect to the wedgeIf it happens that if Wedge moves by distance x, the block also moves x horizontally, then their relative acceleration is 0. option(d) is correct can u please provide me with the solution |
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| 8332. |
A block A constrained to slide along the incline plane of thewedge B. Block A is attached with a string which passes throughthree ideal pulleys and connected to the wedge B. If the wedge ispulled towards right with an acceleration 'a'.(a) Find the acceleration of the block with respect to wedge.(b) Find the acceleration of the block with respect to ground.mmmim |
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Answer» Can u you find it wrt ground also |
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| 8333. |
27. Find theacceleration of rod A and wedge B in the arrangement shown infigure if the mass of rod equal tbetween all contact surfaces is negligible. Take angle of wedge a34hat of the wedge and the frilction A5 |
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| 8334. |
Figure 7.134 shows a block A constrained to slide alongthe incline plane of the wedge B. Block A is attachedwith a string which passes through three ideal pullcys andconnected to the wedge B. If the wedge is pulled towardsright with an acceleration 'a'.DA |
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| 8335. |
.8 N2.0.7 x9.8V3N3.9.8.. νοTwo bozes of same material start moving on surface, one with avelocity of 10ms1 and another with a velocity V. If the ratio ofstopping times for the two bozes is 1:3, then the value of V is1) 3.3ms3) 10ms-4) 50ms-12) 30ms-1 |
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| 8336. |
Describe the expression for resolving power ofmicroscope. |
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Answer» Resolving Power of Microscope: For microscopes, the resolving power is the inverse of the distance between two objects that can be just resolved. This is given by the famous Abbe’s criterion given by Ernst Abbe in 1873 as △d=λ/2nsinθ Resolving power =1/△d=2nsinθ/λ Wherenis the refractive index of the medium separating object and aperture. Note that to achieve high resolutionn sin θmust be large. This is known as the Numerical aperture. Thus, for good resolution: sin θmust be large.To achieve this, the objective lens is kept as close to the specimen as possible. A higher refractive index (n) medium must be used.Oil immersion microscopes use oil to increase the refractive index. Typically for use in biology studies this is limited to 1.6 to match the refractive index of glass slides used. (This limits reflection from slides). Thus the numerical aperture is limited to just 1.4-1.6. Thus, optical microscopes (if you do the math) can only image to about 0.1 micron. This means that usually organelles, viruses and proteins cannot be imaged. Decreasing the wavelength by using X-rays and gamma rays.While these techniques are used to study inorganic crystals, biological samples are usually damaged byx-raysand hence are not used. The limit set by Abbe’s criterion for optical microscopy cannot be avoided. However, using different fluorescence microscopy techniques the Abbe’s limit can be circumvented. Stefan Hell used a technique called Simulated Emission Depletion (STED) and the duo Eric Betzig and W.E. Moerner used super imposed images using green fluorescent proteins to bypass the resolution limit and obtain optical images in never before seen resolution. All three were awarded the 2014 Nobel Prize in Chemistry for their pioneering work. |
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| 8337. |
6. A man weighing 80 kg is standing at the centre of a lat boat and he is 20 m from the shorc. He walksm on the baat owards the shore and then halts. The boat weight 200 kg. flow far is he from theshore al thc end of this time(A)2Dm(B 13.8 m(C) 14.3 m(D) 15.4 mmmnmeni The track is frictionless. The |
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| 8338. |
0. A block and tackle system has the velocity ratio 3.Draw a labelled diagram of the system indicating thepoints of application and the directions of load L andeffort E. A man can exert a pull of 200 kgf. (a) Whatis the maximum load he can raise with this pulleysystem if its efficiency is 60% ? (b) If the effort endmoves a distance 60 cm, what distance does the loadmove ?Ans. (a) 360 kgf (b) 20 cm. |
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| 8339. |
The resolving power of human eye (in minute) is |
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Answer» The actual resolving power of the human eye with 20/20 vision is typically considered to be about one arc minute or 60 arc seconds thnx |
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| 8340. |
How can the resolving power of a telescope be increased? |
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Answer» The resolving power of a telescope, can be increased by(i)increasing the diameter of its objective(ii)using light of short wavelength. |
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| 8341. |
what is polarization of light |
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Answer» Alight wave that is vibrating in more than one plane is referred to as unpolarized light.Polarized light waves are light waves in which the vibrations occur in a single plane. The process of transforming unpolarized light into polarized light is known as polarization of light. |
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| 8342. |
Write the Brewster's law for polarization of light. |
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Answer» Brewster Law states that the tangent of the polarizing angle of incidence (i.e, the Brewster angle) of a transparent medium is equal to the refractive index of the medium. i.e.,μ = tan ip where ip = polarizing angle of incidence (p is in subscript) = Brewster angleand, μ = refractive index of the transparent medium |
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| 8343. |
6. Write the Brewster's law for polarization of light |
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Answer» Brewster's Law: According to this law when unpolarised light is incident at polarising angle (i) on an interface separating a rarer medium from a denser medium, of refractive index μ such that μ = tan i, then light reflected in the rarer medium is completely polarised. Reflected and refractive rays are perpendicular to each otherPlease like the solution 👍 ✔️ |
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| 8344. |
oxygen, it SUt What are metals? Name three metals. |
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Answer» Ans :- A metal is a material that, when freshly prepared, polished, or fractured, shows a lustrous appearance, and conducts electricity and heat relatively well. Metals are typically malleable or ductile. A metal may be a chemical element such as iron, or an alloy such as stainless steel. Examples of metals arealuminium,copper,iron,tin,gold,lead,silver,titanium, uranium, andzinc. |
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| 8345. |
give reason . Charging by friction gives rise to equal and opposite charges in two formerly neutral bodies |
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Answer» Thefrictional chargingprocess results in a transfer of electrons between thetwoobjects that are rubbed together. Rubber has a much greater attraction for electrons than animal fur.Having an excess of electrons, the rubber balloon ischargednegatively. |
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| 8346. |
An automobile moves on a road54 km/h. The radius of its wheelsis.a speed ofthe moment of inertia of the wheel about iagof rotation is 3 kg-m2. If the vehrest in 15s, the magnitude of average torout itsaxiss broughtuetransmitted by its brakes to wheel is:(1) 2.86 kg-m2/s2 (2) 6.66 kg-m2/s(3) 8.58 kg-mas(4) 10.86 kg-m/s |
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Answer» Given Conditions⇒ Initial linear velocity(u) = 54 km/hr.= 54× 5/18 [Changing into m/s.]= 15 m/s.Radius of the wheel(r) = 0.35 m. Now, Using the Formula, Initial Angular Velocity (ω₁) = u/rω₁ = 15/0.35ω₁ = 42.86 radian/sec. Also, Final Angular Velocity (ω₂) = 0 Now, Using the Formula,Angular Acceleration (α) = (ω₂ -ω₁)/t= (0 - 42.86)/15= - 2.86 radian/sec² Moment of Inertia about the axis of the rotation(I) = 3 kg-m² ∴ Torque = I×α⇒ Torque = 3× -2.86⇒ Torque = -8.58 Nm. Hence, the average negative torque is -8.58 N-m. thankyou radius is o.45 not 0.35 but no problem I understand concept |
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| 8347. |
18) A car travels a certain distance with a speed of 50 km/h and returns with a speedof 40 km/h Calculate the average speed for the whole journey11.diration with a velocity of 5 me-lifth |
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| 8348. |
tsunami |
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Answer» A large wave on the ocean, usually caused by an undersea earthquake, a volcanic eruption, or coastal landslide. A tsunami can travel hundreds of miles over the open sea and cause extensive damage when it encounters land. Also called tidal waves thanks |
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| 8349. |
wheel of radius 2 m rolls on the ground withuniform velocity 4 m/s.The relative accelerationof the topmost point of the wheel with respect tothe bottommost point of the wheel is |
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| 8350. |
A svelist is riding with a speed of 27km h. As he approaches a circular turn on the road of radiusSplies brakes and reduces his speed at the constant rate of 0-5 ms What is the magnitudetnmand direction of the net acceleration of the cyclist on the circular turn |
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