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8351.

16. A car is moving in a straight line with speed18 km h-1. It is stopped in 5 s by applyingthe brakes. Find : (i) the speed of car in m s.(ii) the retardation and (iii) the speed of carafter 2 s of applying the brakes

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8352.

, А car travelling at a speed of 30 km/h is broughta distance of 8 m by applying brakes. If0.the same car is moving at a speed o60 km/h then it can be brought to rest with sambrakes in(1) 64 m(3) 16 m(2) 32 m(4) 4 m

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32m

8353.

25. An unloaded bus can be stopped by applyingbrakes on straight road after covering a distance x.Suppose, the passenger add 50% of its weight asthe load and the braking force remains unchanged,how far will the bus go after the application of thebrakes? (Velocity of bus in both case is same)(1) Zero(3) 2x(2) 1.5x(4) 2.5x

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8354.

The driver of a truck traveling with a velocity vsuddenly notices a brick wall in front of him at adistance d. Is it better for him to apply brakes or tomake a circular turn without applying brakes in orderto just avoid crashing into the wall? Why?

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8355.

(D) none of the aboveAcar of mass m attempts to go on the circular road of radius r, which is banked for a speed of36 km/hr. The friction coefficient between the tyre and the road is negligible.(A) The car cannot make a turn without skidding.10.,(B)H the car turns at a speed less than 36 km/hr, it will slip downmV(C) If the car turns at the constant speed of 36 km/hr, the force by the road on the car is equal toe constant speed of 36 km/hr, the force by the road on the car is equal to(DYffthe car turns at the correct speed of 36 km/hr, the force by the road on the car is greater than mgas well as greater than

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8356.

whatis ttht VolumG

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1 mole=22.4 l0.1 mole =2.24 l

8357.

Whatis Electic fiellIeC

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The region around the electric charge in which the stress or electric force act is called an electric field or electrostatic field. If the magnitude of charge is large, then it may create a huge stress around the region. The electric field is represented by the symbol E. The SI unit of the electric field is newton per coulomb which is equal to volts per meter.

8358.

n Kohlrausch's law and its applications

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Kohlrausch's lawstates that the equivalent conductivity of an electrolyte at infinite dilution is equal to the sum of the conductances of the anions and cations. If a salt is dissolved in water, the conductivity of the solution is the sum of the conductances of the anions and cations.

8359.

1.Give the applications of KCI.

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The practical application of KCL is to determine the amount of current flowing through individual electronic component in a circuit. Using that law we can manipulate current to the component by controlling resistance to it.

The KCL states that for a balanced network, the current coming at a node is equal to current outgoing. So, on a simple note, we can balance a given circuit by adjusting voltage and current so that at a selected node, the current if measured is zero because incoming current = outgoing current. So, by balancing we can calculate a no. of parameters from a circuit.

8360.

15. Derive an expression for velocity of a cat on a banked circular road having coefficient of thehence write the expression for optimur velocity

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8361.

11. In an experimental set-up as shown in the figure, a piece of silver was placed touchingpoints A and B. Next time it was replaced by a piece of wood. In which case did the bulbglow? Give reason to justify the observation.A BM

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8362.

What is. EMF seties a witethe..-applications of EMF

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Ans :- An electromotive force series (EMF series) is a metal's ranking in respect to inherent reactivity. Reactivity of metals. The metals located at the top of the series are considered the most noble, with the highest level of positive electrochemical potential.

1. The reactivity of the metaldepends on its tendency to lose electrons, i.e., tendency to form cation . This tendency depends on the magnitude of standard electrode potential. The metal which has lower value of standard electrode potential readily loses the electron or electrons and is form cations. Such a metal is said to be chemically reactive metal. The chemical reactivity of metals increases from top to bottom in the emf series. The metal higher in the emf series is more active than the metal lower in the series.For example :-Li+ + e has electrode potential of -3.05,Where as K+ + e has electrode potential of -2.93As Li has least value of electrode potential , therefore Li is more reactive.

2. Electropositive character of metals :The electropositive character also depends on the tendency to lose electron or electrons. The electropositive character of metals also increases from top to bottom in the emf series.On the basis of standard electrode potential values, metals are divided into three groups(a) Strongly electropositive metals :Metals having standard electrode potential near about – 2.0 volt or more negative .Like alkali metals, alkaline earth metals are strongly electropositive in nature.(b) Moderately electropositivemetals: Metals having values of electrode potentials between 0.0 and about – 2.0 volt are moderately electropositiveAl, Zn, Fe, Ni, Co, etc., belong to this group.(c) Weakly electropositive :The metals which are above hydrogen and possess positive values of electrode potentials are weakly electropositive metals.Cu, Hg, Ag, etc., belong to this group.

3. Displacement reactions(a) To predict whether a given metal will displace another, from its salt solution:A metal lower in the emf series will displace the metal from its solution which is higher in the emf series, i.e., The metal having high standard electrode potential will displace the metal from its salt’s solution which has lower value of standard electrode potential. A metal higher in the series has greater tendency to provide electrons to the cations of the metal to be precipitated.

(b) Displacement of one nonmetal from its salt solution by another non-metal:A non-metal having high value of reduction potential will displace another non-metal with lower reduction potential, electrons readily.

(c) Displacement of hydrogen from dilute acids by metals :The metal which can provide electrons to H+ ions present in dilute acids for reduction, evolve hydrogen from dilute acids.The metal having negative values of reduction potential possess the property of losing electron or electrons.Thus, the metals occupying bottom positions in the electrochemical series readily liberate hydrogen from dilute acids.The metals which are above hydrogen in electrochemical series like Cu, Hg, Au, Pt, etc., do not evolve hydrogen from dilute acids.

(d) Displacement of hydrogen from water :Iron and the metals below iron are capable of liberating hydrogen from water. The tendency increases from top to bottom in electrochemical series.Alkali and alkaline earth metals liberate hydrogen from cold water but Mg, Zn and Fe liberate hydrogen from hot water or steam.

4. Reducing power of metals:Reducing nature depends on the tendency of losing electrons. More the negative electrode potential, more is the tendency to lose electron or electrons. Thus reducing nature increases from top to bottom in the electrochemical series.Sodium is a stronger reducing agent than zincAlkali and alkaline earth metals are strong reducing agents.

(v) Oxidising nature of non-metals :Oxidising nature depends on the tendency to accept electron or electrons. higher the value of electrode potential, higher is the tendency to accept electrons. Thus, oxidising nature decreases from top to bottom in the electrochemical series.

8363.

What do you mean by the resolving powerof optical instrument ? Write expression forresolving power a telescope.)

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the ability of an optical instrument or type of film to separate or distinguish small or closely adjacent images.

8364.

what do you mean by the resolving power of instrument?write expression foe resolving power a telescope.

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1. Resolving power is the capacity of an instrument to resolve two points which are close together.2. In telescopes, very close objects such as binary stars or individual stars of galaxies subtend very small angles on the telescope. To resolve them we need very large apertures. We can use the Rayleigh’s to determine the resolving power. The angular separation between two objects must be

△θ = 1.22 λd

Resolving power = 1△θ = d1.22 λ

Thus higher the diameter d, better the resolution. The best astronomical optical telescopes have mirror diameters as large as 10m to achieve the best resolution. Also larger wavelengths reduce the resolving power and consequently radio and microwave telescopes need larger mirrors.

8365.

wover switch on or switch off electricity when there is aLPG. Why?

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if there is leakage of LPG gas then there are chances of catching fire by electric shortage done by switching the the appliance

it can spot g by DJ by ghhbjjjkkkj

8366.

3, What is the purpose of an electric switch?

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Aswitchis anelectricdevice that is used to complete or break anelectriccircuit

8367.

Question2You should always uselectrical tools withonducting handles?YesNo

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No. commuting handles will allow Current to flow through them, which may give us tremendous shock.

8368.

The handles of the tools like screwdrivers and pliers used by electriclans forrepair work usually have plastic or rubber covers on them. Can you explainwhy?

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8369.

Name any two electrical gadgets that have switches built into them

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Torch and oven

8370.

GM-m2 dr is equal to2Gm,m2Gm1m2o) Cmim Cppn,(2) 3Gmm2Gmm2(3) 3

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how 1÷r^2 converted into r^-1

its the formula for integrals.

thank you so much

8371.

Find the odd one out and write the reason :Fuse wire, bad conductor, rubber gloves, generator

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generator is odd one out.Reason : Rest of others are the substances which is used to slow down the flow of current but generator is used to generate electricity.

8372.

1. A circuit is connected as shown in the figureRc with the switch S open. When the switch isclosed, the total amount of charge that flowsfrom Y to X is [2007, 3M]3uF6uF302602mA. zeroB. 54uC C. 27 uC D. 81°C

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d) is the correct answer

plz mark it best if it helps u

8373.

8. A thyristor can be termed as(a) de switch.(c) either (a) or (b).(b) ac switch(d) square-wave switch.

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A thyristor can be termed as DC switch.

8374.

the velocity v of a particle at time is given by v=at+b/t+c,where a,b,c are constant .The dimension of a,b,c are respectively

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if you know the law of homogeneity then dimension of at= bt=c right then

if you know the law of homogeneity then dimension of at= bt=c right then

8375.

1. In the given figure a block of mass m is tied on a wedge by an ideal string as shown in figure. String isparallel to the inclined surface of wedge. All the surfaces involved are smooth. Wedge is being movedtowards right with a time varying velocity V (m/s) where t is in sec. At what time block will justbreak the contact with wedge. (use g 10 m/s?)ta2VE(m/s)20 45

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8376.

10 thereI pls hell whether it issintheta or Cos that aAngloof incidence-Angle ofLa Lireoreflection50Table 50, 50째 + 0 = 90째ClockNormalEarA = 90째-50째of 0 - 400Lo Lua 400 (from oFig. 12.4he ceiling and wall behind the stage of good conference halls orWhy is the ceiling and wallConcert halls made curved?Long Answer Questionsresent graphically by two separate diagrams in each caseTwo sound waves having the same amplitude but different frequencies?Two sound waves having the same frequency but different amplitudes.nues having different amplitudes and also different

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The ceiling and walls behind the stages are made curved so that the sound after reflection reaches all corners of the hall uniformly.

8377.

Two sound waves of relative intensities400:1 show interference. The ratio ofintensity at the maxima to minima is closeto:(A) 21/19(B) 11/9(C) 401/399441361

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The ratio is given by. (√i1+√i2)²/((√i1-√i2)²= (√400+1)²/(√400-1)²= (20+1/20-1)² = (21/19)² = 441/361

option D should be correct. and root should not be there in the option

8378.

21. Which of the following is dimensionless?a)Boltzmann's constantc) Poisson's ratiob)Planck's constantd) Relative density

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c) Poisson's Ratio Because it ratio of same quantity i.e. lateral strain/longitudinal strain

8379.

5)Find the work done by force F 2i -3i + k whenits point of application moves from the point4 (1, 2,-3) to the point B(2, 0,-5). (Ans. 6 units)F(a)s forces

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8380.

194. The intensity ratio of waves is 25:9. What is the ratio oftheir amplitudes?(a) 5:3(c) 25:9(b) 50: 18(d) 3:5

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I1/I2=(a1/a2)2

a1/a2 = √(l1/l2)

= √(25/9)

= 5/3

= 5:3

Like my answer if you find it useful!

8381.

4. Derive expression for displacement covered by body in nth second.

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8382.

If the distance covered by an object is zerowhat can we say about its displacement?

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The displacement is 0.

the displacement is also 0

8383.

what is maximum shear stress?

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Themaximum shear stressis themaximum concentratedshearforce in a small area. It is very critical for a structural engineer to locate and evaluate themaximum shear stressin a member in order to design the member in such a way to resist it

8384.

If velocity of a particle is given as v (2t+1)ms1. Find displacement covered by particle fromt 1 to t#2sec.

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8385.

Explain why a cyelist bends while negotiatinga curve road? Arrive at the expression forangle of bending for a given velocity.

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Acyclist bendsinwardswhileturning around acurvein order tonegotiatethe effects of slipping which would occur otherwise. Now, the leaning action of thecyclistprovides the necessary centripetal force required for following acurvedpath.

wrong answer

8386.

A particle travels 21m in first 3secs and 45m in next 5 secs.find the initial velocity and acceleration of the particle.Also calculate the distance traveled in next 2 secs.

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hum alag alag kyu nahi lga skte ye equations dono distances pr

8387.

।९||1||)।गप।2.फलन -5 sine + 12 cose का अधिकतम मान है :(1) 12 (2) 13 (3) 7 (4) 17

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2) 13 is the correct answer

4) is the correct answer

2) 13 is the correct answer

8388.

2) r8 m(3) 15.6 m(4) 39.2 mTwo bodies are thrown vertically úpward, with the same initial velocity of 98 m/s but 4 sec apartHow long after the first one is thrown when they meet ?(2) 11 sec(1) 10 sec(3) 12 sec(4) 13 sec

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When they meet, their displacements will be same. Therefore ,

s= ut-(1/2)gt^2=u(t-4) -(1/2)g(t-4)^2

Simplifying and making t subject, we get

t=(u+2g)/g. OR

Substituting the values,

t=(98+19.6)/9.8 OR

t=12s after the first body was thrown.

Go and ask this question to your teacher 👌

8389.

1 2 seCif a freely falling body travels in the last second, a distance equal to the distance travelled by it in the first threeseconds, the time of its travel is1]3 secQ.41.[Manipal-2000][2] 4 sec[3] 5 sec[4] 6 sechich is aning upward with a velocity 12 m/sec. The velocity of the packet after

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8390.

A particle travels 10 m in first 5 sec and 10 m in next3 sec. Assuming constant acceleration, what is thedistance travelled in next 2 sec?(a) 8.3 m(c) 10.3 mm(b) 9.3 m(d) of above

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Let assume initial velocity is u and constant acceleration a.

using s=ut+.5 a t^2

For first 5 second

10=5 u +.5x a x 25..........(1)

for next 3 seconds t=8 and s=20

20=8 u+.5xax64...........(2)

Solving 1 and 2

a=1/3 and u=7/6

Now for next 2 seconds t=10 and s'

S'=10x7/6 +.5x(1/3) 100

S'=170/6

Now distance travelled in 2 sec=(170/6)-20=50/6 meter

thnk u sir, it helped me a lot

8391.

6.Moving with a uniform acceleration from thestate of rest a body covers 22 m during the6th sec of its motion. What is the distancecovered by if during the first 6 sec?1) 36 m2) 48 m3) 72 m4) 150 m

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48 is right answer of this question. please like my answer

8392.

a body accelerate at 4m/s2 and then decelerate at 5m/s2 to come to rest . find the total time and distance covered .Plot v-t graph

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8393.

An electron starting from rest has a velocity thatincreases linearly with time as v = kt whereK= (2m/s)/s. The distance covered in first 3 sec. is1) 9 m 2) 16m 3 ) 27 m 4) 36 m

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what is your answer bhaiya

ds=ktdtS=1/2kt^2=1/2 2*3*3=9m

8394.

20. The driver of a train, travelling at 115 km/hr, sees aslow train travelling on the same track, which is100 m infront of him and in the same direction at aspeed of 25 km/hr. The least retardation that must beapplied to faster train to avoid a collision is(1) 5 m/s2(3) 3.125 m/s (4) 7 m/s(2) 2.5 m/s

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Velocity of train 'B' with respect to train 'A' = (115−25)km/h

VBA=−90km/h =−25m/s

Distance between the trains is 100m. Using the equations of motion

v^2=u^2−2as ,v=0

u^2=2as

625=2xax100

Then the least retardation that must be appiled to faster train to avoid a collision, a=3.125m/s^2

8395.

14. Which one of the following is wrong?a)..i-1b)c) ixi-od) k.K-Oj.js1

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d) k.k = 0The dot product of any unit vector with itself is one. i.i = 1. j.j = 1. k.k = 1

8396.

wBA-vBYAd) VBAve t VA14. Which one of the following is wrong?a)i.i=1b) j.js1d) k.K-0

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d) k.k = 0

The dot product of any unit vector with itself is one. So, k.k = 1

8397.

(d) at a punthe wire39. The diagram below shows the propagation of a wave.Which points are in same phase?АКDGthiand E

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b and f

B and F are in same phase as they are l distance apart thanks

8398.

47. Explain the traditional way of purifying water to make it fit for drinking.

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Traditional Methods Used for Water Filtration

Filtration done in clay vessel:The technique consists of pouring water into clay vessel having a suitable pore size. The water settles down in the clay vessel and passes through the pores of the clay. The purified water collects in a jar placed at the bottom of the clay vessel.

Filtration done through cloth:This is another common filtration method used in the early years. The filtration process removes impurities such as debris, insects, dust particles and other suspended elements. Water passes through a thin white cloth, which removes impurities present in water.

Filtration done through Winnowing Sieve:The filtration process removes coarse particles and other physical impurities present in water. Raw water passes through a winnowing sieve, which filters all the impurities, thereby collecting fresh water, which is safe for drinking.

8399.

The near point of hypermetropic eye is 80cm. what is the nature and powerrequired to enable him to read a book placed at 25 cm from the eyes?

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3.2is the correct answer of this question

3.2 is correct answer

3.2 is the Right answer

8400.

A gramophone disc rotates at 60 rpm. A coin ofmass 18 g is placed at a distance of 8 cm from thecentre. Calculate the centrifugal force on the coin.

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Angular velocity = w= 60rev/min1 revolution= 2pi radian one minute = 60 sec w= 60*2pi/60w= 2pi radian/secmass= 18g = 0.018 kgdistance =r= 8 cm = 0.08 m f= mv^2/r v=rw v^2=r^2w^2f= mr^2w^2/r r in division will be removed by removing square

F= mrw^2 f= 0.018*0.08*(2pi)^2square of 2 is 4and pi^2= 9.87 as per your questionTherefore,0.018*0.08*4*9.87= 0.05685= 0.057