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a) th is correct answer

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1 dioptre is SI unit of the power of a lens whose focal length is 1 metre. It is denoted by the letter D. Thus 1D = 1 m-1. Simply, when focal length ‘ f ‘ is expressed in metres, then, power is expressed in dioptres. The power of a convex lens is positive and that of a concave lens is negative

One coulomb is defined as the quantity of electricity transported in one second by a current of one ampere.

Rs=R1+R2+R3+......

1/Rp=1/R1+1/R2+1/R3+....

Rs=R1+R2+ R3 (in series)1/Rp= 1/R1+1/R2 + 1/R3 ( in parallel)

Basic property of magnetic lines of force is that, they can never intersect each other. Among the two points given below, which one is correct?

Magnetic lines of force of same magnet can't intersect each other, but magnetic lines of force of different magnets can intersect each other.Magnetic lines of force can't intersect each other irrespective of their origin (i.e whether the lines were of same magnet or different magnets, they can't intersect)Suppose I have two bar magnets. If I tend to make the repelling poles join together by exerting force (i.e, if I tend to make north pole of two magnets, or south pole of two magnets join together).

If two linesofforce intersectonone point, thiswillindicate theforcehavingtwodifferent directions at thepointof inter section at the same time whichisnot possible.

Ohm's Lawstates that the potential difference between two points is directly proportional to the electric current. Resistance is the property of conductor which resists the flow of electric current through it. SI Unit of resistance isohm.

Current = charge/ time= 24/0.8= 30 A

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μ0

Metric (SI) Dimensions

length×mass×time^-2×electric-current^-2

s = 5t i + 6t² j - 10k

ds/dt = v = 5 i + 12t j - 0 k

dv/dt = 12j

at t = 1

v = 5 i + 12 j - 0 k

a = 12 j

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now substitute the values of m, K, and temperature (T) = 127+273= 300Kthat us given in the ques.

20,10,20 will be in parallel so after solving it will be in series with 8 ohm

Ans :- The number of oscillations per second of avibrating objectis known as its frequency.Time periodis thetime required to complete one oscillation. When the amplitude ofvibrationof a sound is large, the sound is very loud. The sound is feeble for small amplitude.

Amplitude

The maximum displacementof avibrating bodyfromits mean position is calledAmplitude

Thevibrating object producesa series of compressions and rarefactions, one after the other in themedium. These pulses travel one behind the other as thesoundwaves move forward. When thissoundwave reaches our ear, it forces the tympanic membrane to vibrateand thus causes the sensation of hearing

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Length of the string is directly correlated with the frequency of a sound wave.

i.e. a short string vibrates faster and produces a higher pitch while a longer string produces a lower pitch.

Thus, cutting the string into half will increase the pitch of sound.

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a = ω²Ahence A=a/ω²and w=2π/T

The expression of velocity in S.H.M is

V² = ω²(a² -x²) here.. a = maximum amplitude and ω is the frequency..

so, compraing V = √144-16x² = √(12)²-(4x)² , we get ω (as coefficients of x)= 4 and a as √9 = 3m

so, maximum acceleration is aω² = 3*4*4 = 48m/s²

so option D

it's diffrentiation will be 1/x

dt is the smallest change in the time.broadly it can be termed as ∆t = t2 -t1

dy indicates The smallest change in the variables y of a Particle

Let us suppose the first force to be 3x and the other force to be 5x.

Now resultant can be given by sqrt [a*a + b*b + 2abcos(angle between a and b)]

So here that is, sqrt [9x*x + 25x*x + 15x*x] = 35 N

So, 7x = 35

Or,x = 5

Thus,the values of the forces are 15N and 25N.

Take the case if the the block is accelerating upward !

Then only you can have the the table surface exerts more force then the weight!If the block exerts a force of 9.8N on the table it means the ground is not accelerating.

option d

ohk but I didn't got the last line!!!!could u make it a bit simple

a body when kept anywhere experiences normal reaction from groundit is a case of Newton's third law of motion..this action has an equal and opposite reaction.

Work done= Force × Displacement =10 ×2 =20 J

good sir

v=u+atu=0a=4m/s^2t=4secv=4*4=16m/s

3) is correct answer

The correct answer is (3)

3) is the correct answer

third one is the correct answer

option 3 is the correct answer to this question.

option 3 is the correct answer to this question.