InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 9951. |
An electric motor is rated 2.5 horse power. What is its power in watts ? |
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Answer» 1 hp = 745.699872 wTherefore 2.5 hp = 1864.249 w |
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| 9952. |
den of 2 amperes passed through a resistance of 100 ohms17. An electric kettle rated at 220 v, 2.2 kW, works for 3 hours. Find the energy consumed and the currentdrawn |
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| 9953. |
An electric bulb of 100 watt works for 4 hrs a day calculate the unit of energyconsumed in 15 days |
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Answer» Power rating of the bulb: 100 WDuration used each day: 4 hrNumber of days: 15 Total energy consumed by the electric bulb: = power * duration = 100 W * 4 hrs/day * 15 days = 6000 W-hrs = 6 kWh So energy consumed is 6 units. |
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| 9954. |
of 9 V is connected in series with resistors of 0.2 Ω, 0.3 Ω, 04 Ω, 0.5 Ω and 12 Ω.How micurrent would flow through the 12 Ω resistor ?15. An electric bulb of resistance 20 9 and a resistance wire of 4 0 are gnnnected in scries with a fi Y |
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| 9955. |
For a heater rated at 4 kW and 220 V, calculate:(a) the current(b) the resistance of the heater(c) the energy consumed in 2 hours, and(d) the cost if 1 kWh is priced at 4.60. |
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| 9956. |
7When a 9V battery is connected in series with resistors of 0.292,0.392, 0.492, 0.512, and 1202 respectively, how much current wouldflow through the 120 resistor? |
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Answer» I= .67 amp is the correct answer of the given question |
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| 9957. |
When a 9V battery is connected in series with resistors of 0.292,0.392, 0.412, 0.512, and 1292 respectively, how much current wouldflow through the 1292 resistor? |
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Answer» There is no current division in a series circuit.Current flow through the component is the same. Resistances are connected in series.Hence,R=0.2+0.3+0.4+0.5+12=13.4ohms potential difference,V=9V I=V/R=9/13.4=0.671 A Therefore,the amount of current that would flow through 12ohm resistor would be 0.671A |
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| 9958. |
How can the voltage rating of a cell beincreased? |
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Answer» Since , V is directly proportional to I , so when current increase voltage will also increase , they are proportional to each other |
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| 9959. |
an electric heater rated at 1200W is connected to a 220V source. A fuse wire of 5A is chosen.Will the fuse blow up or work? when the heater is switched on. |
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| 9960. |
) How can the voltage rating of a cell be increased? |
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Answer» Voltage and current are proportional to each other i.e if current increases then the voltage will decrease and vise versa. |
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| 9961. |
Cxplain the mechanism of solar cooker with diagram? |
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| 9962. |
An electric heater uses 600J of electrical energy in 5 minutes calculate the power |
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Answer» Work= 600J = 600J Time= 5 minutes = 5 x 60= 300 seconds Power = Work/Time = 600/300 = 2 W |
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| 9963. |
What is the role of fuse used in series with any electrical appliance? Whyshould a fuse with defined rating not be replaced by one with a largerrating? |
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Answer» Fuse is used for protecting appliances due to short-circuiting or overloading. The fuse is rated for a certain maximum current and blows off when a current more than the rated value flows through it. If a fuse is replaced by one with larger ratings, the appliances may get damaged while the protecting fuse does not burn off. This practice of using fuse of improper rating should always be avoided.Like if you find it useful Fuseisusedfor protectingappliancesdue to short-circuiting or overloading. Thefuseisratedfor a certain maximum current and blows off when a current more than theratedvalue flows through it. ... This practice of usingfuseof improperrating shouldalways be avoided. |
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| 9964. |
1. An electrical appliance is rated as 60 W-150 V(a) What do you understand by this statement(b) How much current will flow through theappliance when in use ? Ans: 04A |
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Answer» a) This is the rating of that appliancesthat shows the permissible valuesb)Power = Voltage x current60W= 150* currentcurrent = 60/150= 2/5 AMPERE = 0.4 A Please like the solution 👍 ✔️ |
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| 9965. |
b. What energy is being used in the solar cooker? |
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Answer» Ans :- Heat energy Converting light energy toheatenergy: Solar cookersconcentratesunlight onto a receiver such as a cooking pan. |
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| 9966. |
4. What are the advantages and disadvantages of using a solar cooker ? Aret |
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| 9967. |
čą (An objects placed at a distance of 10cm from a convex mirror of focal length of 15cm Find theposition and the nature of the image) |
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| 9968. |
6. 4818. Explain solar cooker with neat diagram. |
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| 9969. |
Whyisanormaleye not able to see cliearly the objects placed closer than25 cm? |
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| 9970. |
Why is a normal eye not able to see clearly the obiects placed closer than 25 cm? |
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| 9971. |
Distinguish clearly between distance anddisplacement of a projectile. |
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| 9972. |
Comprehension Check1. Who did Connie Macpherson think her visitor was?2. Which sentence in the text shows that the visitor did noto hide his identity? |
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Answer» what did dhira find in the shoes |
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| 9973. |
26. A person sitting on the top of a tall builáing is droppingballs at regular intervals of one second. Pind thepositions of the 3rd, 4th and 5th ball when the 6th ballis being dropped. |
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| 9974. |
1.You are travelling in a bus. Is the person sitting next to you in motion? |
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Answer» If I am travelling in a Bus then the Person sitting near us in bus will be in rest with respect us. Since, rest and motion are relative terms we need some frame of reference to decide whether the body is in motion or rest. We all know that Earth is in motion but still it is considered as Inertial Frame. All the bodies which are in motion or rest are decided with respect to it. |
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| 9975. |
26. A person sitting on the top of a tall building is droppingballs at regular intervals of one second. Find thepositions of the 3rd, 4th and 5th ball when the 6th balis being dropped. |
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| 9976. |
14. If a body is moving with constant speed, then itsacceleration(1) Must be zero(3) May be uniform(2 May be variable(4) Both (2) & (3) |
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Answer» option 4 may be an answer.it can either be variable or uniform acceleration |
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| 9977. |
26. A person sitting on the top of a tall building is droppingballs at regular intervals of one second. Find thepositions of the 3rd, 4th and 5th ball when the 6th ballis being dropped. |
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| 9978. |
The greatest acceleration or deceleration that a train may have is a. The minimum time in which the train may reach fromone station to the other separated by a distance d is5.2d(4) 22 a |
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Answer» option 2 is correct explain it using the second equation o motion u and v for train will be zero. for minimum time maximum acceleration will be needed and hence the distance is d. thus d = 1/2*a*t^2 now time t = root(2d/a) but answer is 4th option |
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| 9979. |
what is optimal solution |
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Answer» Anoptimal solutionis a feasiblesolutionwhere the objective function reaches its maximum (or minimum) value – for example, the most profit or the least cost. A globallyoptimal solutionis one where there are no other feasible solutions with better objective function values. |
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| 9980. |
CLASS RESPONSEORAL QUESTIONIFind the odd-one out. Give reasons for your choice.a. Speed, Energy, Force, Mass, Temperatureb. Weight, Acceleration, Velocity, Distance,Momentumc. Rolling stone, Moving ball, Big table, A dancinggirl, Vibrating stringA book is lying on a table. Examine and define its |
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Answer» All the terms there,except Force only,are scalar quantities. Force is a vector quantity. momentum, dancing girl |
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| 9981. |
14 परावर्तन के एक प्रयोग में आपतित किरण और परावर्तक सतः।के बीच का कोण 45° है। परावर्तन के कारण किरण के पथ मेंउत्पन्न विचलन का मान क्या होगा?(b) 135(a) 45°(c) 90°(d) 60° |
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Answer» 90 is a right answer because because out side 45° and in side 45° is called 90° 90 is right because it is 45 45 and 90 angle answer is C 90° because the mid point is of 45° it is happened possible in right angle triangle with 90° angle 9is correct answer in this questions |
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| 9982. |
10. 45 g of water at 50°C in a beaker is cooled when50 g of copper at 18°C is added to it. The contentsare stirred till a final constant temperature is reached.Calculate the final temperature. The specific heatcapacity of copper is 0.39 J g K-1 and that of waterİS 4-2 J g-1 K-1. State the assumption used.Ans. 47°CAssumption : There is no loss of heat.lus |
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Answer» Heat gained by copper = m × C × θ = 50 × 0. 39 × (T − 18) Heat lost by water = 45 × 4. 2 × (50 − T) Heat lost = Heat gained 45 × 4. 2 × (50 − T) = 50 × 0. 39 × (T − 18) 9450 − 189 T = 19. 5 T − 351208. 5 T = 9801 Or T = 47°C (Approx) |
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| 9983. |
1. A beaker contains 200 gm of water. The heatcapacity of the beaker is equal to that of 20 gm ofwater. The initial temperature of water in thebeaker is 20°C. If 440 gm of hot water at 92°C ispoured in it, the final temperature (neglectingradiation loss) will be nearest to |
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| 9984. |
Classify the resistors. |
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Answer» They are basically of 2 types –1)Fixed Resistor and2)Variable ResistorsClassification of Resistors:From operating conditions point of view, resistors can be classified into two.1) Fixed resistors2) Adjustable/ variable resistors 1) Fixed resistors are further classified into:a) Carbon composition type resistors b) Metalized type resistors c) Wire wound type resistorsa) Carbon composition type resistors:This is the most common type of low wattage resistor. The resistive material is of carbon-clay composition and the leads are made of tinned copper. These resistors are cheap and reliable and stability is high.b)Wire wound resistors:These resistors are a length of wire wound an insulating cylindrical core. Usually wires of material such as constantan (60% copper and 40% nickel) and manganin which have high resistivities and low temperature coefficients are employed. The completed wire wound resistor is coated with an insulating material such as baked enamel.c) Metalized resistorsIt is constructed using film deposition techniques of depositing a thick film of resistive material onto an insulating substrate.Only approximate values of resistance can be had by this method.2) Variable resistorsFor circuits requiring a resistance that can be adjusted while it remains connected in the circuit(for eg: volume control on radio), variable resistors are required. They usually have 3 lead two fixed and one movable. thanks |
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| 9985. |
Find the odd one out and give the reason:speed, distance, mass, velocity |
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Answer» velocity as rest is scalar quantity and velocity is vector quantity |
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| 9986. |
A1.2 kg collar C may slide without friction along a fixed smooth horizontal rod. It isattached to three springs each of constant K 400 N/m and 150 mm undeformedlength. Knowing that the collar is released from rest in the position shown. Deteminethe maximum velocity it will reach in its motion. [Here A, O, B are fixed points.]ĺĽ |
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Answer» First find the deformed length of the springs. Spring 3: l = √((.15m)2 + (.3m)2) l = 0.3354 m Δx3 = 0.3354m - 0.15m Δx3 = 0.1854m Spring 2: l = √((.15m)2 + (.15m)2) l = 0.21213 m Δx2 = 0.21213m - 0.15m Δx2 = 0.06213m Spring 1: Undeformed Δx = 0m Now, Ei = PE (from the deformed springs, no KE or U) Ei = 1/2k1(Δx1)1 + 1/2k2(Δx2)2 + 1/2k3(Δx3)3 Ei = 1/2(400N/m)(0m)2 + 1/2(400N/m)(0.06213m)2 + 1/2(400N/m)(0.1854m)2 Ei = 7.6459J From the Law of Conservation of Energy Ei = Ef and velocity will be max when there is no spring potential energy restricting the collar and only KE. Ef = 1/2mv2 7.6459J = 1/2(1.2kg)v2 3.57 m/s = v |
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| 9987. |
100 grams of water is heated from 30 degrees Celsius to 50 degrees Celsius ignoring the slught expansion of water the change in its internal energy is |
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Answer» ΔQ = MSΔT = 100 x 10^-3x 4.184 x20= 8.4 X 10^3 ΔQ = 84 kJ, ΔW = 0 ΔQ = ΔV + ΔW V = 8.4 kJ |
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| 9988. |
1) Ammeter2) Switch3) Battery4) A wire jointb)c)d)e)( )-2 |
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Answer» 1 . E 2 . F3 . A4 . B |
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| 9989. |
15. An electric lamp and a candle produce equal illuminanceat a photometer screen when they are placed at 80 cmand 20 cm from the screen respectively. The lamp is nowcovered with a thin paper which transmits 49% of theluminous flux. By what distance should the lamp bemoved to balance the intensities at the screen again ? |
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| 9990. |
An image formed on a screen is three times the size of the object. The object and screen are 80 cm apartwhen the image is sharply focussed.(a) State which type of lens is used. |
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Answer» thanks.... |
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| 9991. |
caveA small candle, 2.5 cm in size is placed at 27 cm in front of a conmirror of radius of curvature 36 cm. At what distance from the mirrorshould a screen be placed in order to obtain a sharp image? Describethe nature and size of the image. If the candle is moved closer to themirror, how would the screen have to be moved?A 45 cm |
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| 9992. |
(i) a body with constant acceler&(ii) an object moving in a certain direction with an acceleration in trep13. An electrical geyser of 15 kW works for 2 hours. Find the electrical energy units consumed in ail Ihr importance of the Universal Law of Gravitation7 Explain it throughany tho21. |
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Answer» Like if you find it useful |
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| 9993. |
EXERCISES1 A small candle, 2.5 cm in size is placed at 27 cm in front of a concavemirror of radius of curvature 36 cm. At what distance from the mirrorshould a screen be placed in order to obtain a sharp image? Describethe nature and size of the image. If the candle is moved closer to themirror, how would the screen have to be moved? |
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Answer» thanks |
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| 9994. |
34. Two poles are 10 m and 20 m high. The linejoining their tops makes an angle of 15° with thehorizontal. The distance between the poles isapproximately equal to(a) 36.3 m (b) 37.3 m (c) 38.3 m (d) 39.3 m2015 11 |
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| 9995. |
d) 40a) 10b) 20c) 303. The attractive property of magnet is maximum at..a) Centreb) Two poles c ) North poled) South poleA Natural magnet is known as |
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Answer» the answer is b) two poles c) north pole in comparison with the south pole |
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| 9996. |
0noi0ng questions1. What are the condition for total internal reflection sne of light in2. Refractive Index of /diamond is 2.42. Calculate thDiamond. (C 3x10* m/s) |
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Answer» 1)Two important conditions for total internal reflection are: Angle of incidence (i) should be greater than critical angle (ic). Ray should travel from denser medium to rarer medium. |
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| 9997. |
small candle, 2.5 cm in size is placed at 27 cm in frirror of radius of curvature 36 cm. At what distance firshould a screen be placed in order to obtain a sharp image?the nature and size of the image. If the candle is movedmirror, how would the screen have to be moved?9miDescribecloser to theadle is nlaced 12 em away from a convex mirror of focal |
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| 9998. |
A small candle, 2.5 cm in size is placed at 27 cm in front of a concavemirror of radius of curvature 36 cm. At what distance from the mirrorshould a screen be placed in order to obtain a sharp image? Describethe nature and size of the image. If the candle is moved closer to themirror, how would the screen have to be moved? |
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| 9999. |
Calculate the moment of inertia of an annular disc about an axis which lies in the plane of the disc and tangentialto the () inner circle and (i) outer circle. Mass of the disc is M and its inner radius is R, and outer radius is2" |
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| 10000. |
1. GIFA) Graphics Interchange Format2. JPEG B) Graphics Idea File3. PNG C) Joint Private Expert GroupD) Joint Photographic ExpertGroupE) Portable Network GroupF) Portable Network Graphics(b) 1-B, 2-D, 3-F(d) 1-A, 2-C 3-E(a) 1-A, 2-D, 3-E |
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Answer» 1)Graphics Interchange Format (GIF) is a bitmap image format that was introduced by CompuServe in 1987. It also supports animations and allows a separate palette of 256 colors for each frame 2)"JPEG" stands for Joint Photographic Experts Group, thenameof the committee that created theJPEGstandard and also other still picture coding standards. ... The Exif and JFIF standards define the commonly used file formats for interchange ofJPEG-compressed images. 3)PNGstands for Portable Network Graphics. It was created as an open format to replace GIF, because the patent for GIF was owned by one company and nobody else wanted to pay licensing fees. It also allows for afullrange of color and better compression option a |
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