InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 11001. |
14) Show the heterolysis of covalent bond by usingcurved arrow notation and complete the followingbnequations. Identify the nucleophile in each case.i) CH,-CI KCN - |
| Answer» | |
| 11002. |
(1) There IS NU OverUI CRUNCE. TUWEYE, ETCcarrying 5 marks each. You have to attempt only one of theSECTION - A1. The resistivity of a metallic wire depends on its :(A) material(B) area of(C) thickness(D) length2. The r.m.s. value of an a.c. is 5 A. Its maximum value will b(A) 10 A(B) 52.(C) 5/2A(D) 5733. Main parts of a communication system are :(A) receiver and communication channel (B) trans(C) transmitter and communication channel (D) trans |
|
Answer» 1. Material is the correct answer a) material is the correct answer The correct answer is Material 1. material is the correct answer 1) material 2) 5√2A 3).c is correct answer answer 1 is correct i hope it help you material is the best answer for the question material is the correct ans material is the right answer |
|
| 11003. |
in a communication system noise is likely to affect the signal |
|
Answer» Noise is mostly generated in channel. |
|
| 11004. |
.48. Name at least two gases responsible for the greenhouse effect |
|
Answer» Gases responsible for green house gas carbon dioxide, methane, nitrous oxide, chlrofluorocarbons |
|
| 11005. |
Name two processes based on the principle of electrolysis. |
|
Answer» Processes based on principle of electrolysisElectroplatingElectrorefining thanksgiving |
|
| 11006. |
Staining is a the process of adding colour to the specimen based onstains.58. Cell membrane = safranine Red: Nucleus = ?1) Janus Green-B 2) Methyline blue 3) Crystal viol |
|
Answer» Methyline blue is correct answer nucleaus:janus green-Bis the right answer. nucleus:janus green-Bis the right answer |
|
| 11007. |
3) A monochromatic beam of light passes from a denser medium to a rarer medium. As a resulta) It's a Velocity incrcases b) lts velocity Decreases c) Its Frequer cy Decrease d) lts Wavelength decre |
| Answer» | |
| 11008. |
6. Find the equivalent capacitance of the system shown infigure (31-W4a) between the points a and bC1C2C1C2C3C12C2 |
| Answer» | |
| 11009. |
eparticle19elastic.DIoIlofthe previous problem has a massd a speed v before the collision and it sticks to thesion. The rod has a mass M. (a) Findvelocity of the centre of mass C of the system66m androd after the colliconstituting "the rod plus the particle". Ob) Find thevelocity of theparticle with respect to C before thecollision. (c) Find the velocity of the rod with respect toC before the collision. (d) Find the angular momentunmof the particle and of the rod about the centre of massC before the collision. (e) Find the moment of inertia ofthe system about the vertical axis through the centre ofmass C after the collision. (f) Find the velocity of thecentre of mass C and the angular velocity of the systemabout the centre of mass after the collision.inined |
| Answer» | |
| 11010. |
ind the radius of gyration of a thin uniform rod of length 1 m about an axis perpendicular to its length and through(i) an end (ii) the centre.. F(Ans. 0.5774 m, 0.2887 m) |
|
Answer» not his answer |
|
| 11011. |
13. An electric dipole consists of charges +2x108coulomb separated by a distance of 2mm. It isplace near a long line charge of density 4x 10-4C/m as shown in fig., such that the negativecharge is at a distance of 2cm from line charge. Calculate the force acting on the dipole.-q+q+2cm2mm |
| Answer» | |
| 11012. |
a A thin uniform sheet of metal of uniform thickness is cut into the shape bounded by the line xy tkx, as shown. Find the coordinates of the centre of mass.a andyak |
| Answer» | |
| 11013. |
5. Explain the density and relative density of an object |
|
Answer» density = mass /volume relative density is the specific gravity specific gravity = density of a substance / density of the reference substance reference substances are water and air, so the density of air =1.225 Kg/m^3 and density of water =1000 Kg/m^3. |
|
| 11014. |
Q) what is the difference between relative density and density? (3m) |
|
Answer» the term relative density can be defined as the ratio between the density of substance to that of water at a particular temperature. where as, density is just the ratio of total mass of the substance to total volume of the substance. |
|
| 11015. |
13. The relative density of silver is 10.8 and the density of water is 10 kg/m^2. Thedensity of silver is |
|
Answer» If answers are in other units send options |
|
| 11016. |
Relative density of silver is 10.8. The density of water is103 kg m4. What is the Density of silver in S.I Unit? |
| Answer» | |
| 11017. |
) Relative density of silver is 10.8. The density of water s103 kg m What is the Density of silver in S.I Unit? |
| Answer» | |
| 11018. |
4. Relative density of mercury is 13.6. The density of water is 10% kg/m. What is the density ofmercury in SI unit? |
|
Answer» thanks for raising the doubt with us |
|
| 11019. |
22. A wooden block of mass 8kg is tied to a string attached to the bottomof the tank. In the equilibrium the block is completely immersed inwater. If relative density of wood is 0.8 and g = 10ms, the tension T.in the string is |
| Answer» | |
| 11020. |
The mass of an empty density bottle is 21.8 g,when filled completely with water it is 41.8 gand when filled completely with liquid it is40.6 g. Find:.(a) the volume of density bottle(b) the relative density of liquid. |
|
Answer» Density = Mass / Volume= (40.6 - 21.8) / 20= 0.94 g/cm^3 Density of liquid A is 0.94g/cm^3 Volume of the bottle, V=20 mlMass of bottle,m= 21.8g. When filled with liquid the bottle weighs 40.6g Therefore, Mass of liquid in the bottle, m= 40.6 – 21.8 = 18.8g Density of liquid = m/ V = 18.8/20 =>0.94 g/ml The mass of empty bottle =21.8gwhen filled complete with water =41.8g =21.8 -41.8g =20 gthe mass of water =20 gthe volume of the water in cubic cm =20 mlwhen filled complete with water =40.6gthe empty bottle =21.8g when filled with water =40.6-21.8g =18.8gDensity of liquid =m÷v=18.8 ÷20 g =0.94 The mass of empty bottle =21.8gwhen filled complete with water =41.8g =21.8 -41.8g =20 gthe mass of water =20 gthe volume of the water in cubic cm =20 mlwhen filled complete with water =40.6gthe empty bottle =21.8g when filled with water =40.6-21.8g =18.8gDensity of liquid =m÷v=18.8 ÷20 g =0.94 |
|
| 11021. |
A A body when aoted upon by a force of 10 kgf gets displacedby 05 m. Calculate the work done by the force in sachcase when the displacement is () in direction. (l) at anangle 60°. (i) normal to the force. (g 10 m s2)(Ans. (i) 50 J (ii) 25 J (in zero) |
| Answer» | |
| 11022. |
wo persons hold a rope of negligible weight tightat its ends so that it is horizontal. A 15 kg weight isattached to the rope at the mid point which is nowno longer remains horizontal. The minimum tensionrequired to completely straighten the top is(1) 15 kg(3) 5 kg(2) 15/2 kg(4) Infinitely large |
|
Answer» T be the tension in string. for equilibrium 2Tcoso = mg string will be straight if 0 = 90 degrees. and cos0 = 0 T= mg/2 coso . t=infinity |
|
| 11023. |
(iv) Horizontal Range (R):l an the horizontal dis |
|
Answer» The initial velocity and angle of projection decides the range as well as the height it reaches. Let V be the velocity and A be the angle, then the velocity is split into horizontal and vertical components as VcosA and VsinA. This problem is solved easily if we understand this. That the vertical component decreases due to gravity and reaches zero at the top, then reverses and reaches its initial value when the projectile hits ground. And that the horizontal component remains constant neglecting wind. So the range will be time taken for the projectile to go to the top and reach ground again Now we have to use velocity acceleration formula v=u+at If t is the time taken from start to reach the top and g is the gravity constant then 0=VsinA-gt t=VsinA/g Total time = 2 VsinA/g So range= 2 VsinA/g. VcosA you have nice thinking capability |
|
| 11024. |
uperties of SolidsBoard & Competitive Examsa load of 10 kg is hung from the wire, then extension of 2 m is produced. Then work done by restoringforce is(1) 200(3) 50 JSubstances which can be elastically stretrh(2) 100 J(4) 25 J5. |
|
Answer» the answer to this question is 200 J the work done is given by F.S and force is = mg = 10*10 = 100N so, work done = 10*10*2 = 200J |
|
| 11025. |
NCERT4.32. (a) Show that for a projectile the angle between thevelocity and the x-axis as a function of time is givenby-1 (voy gt0 (t) tanox(b) Shows that the projection angle 0, for a projectilelaunched from the origin is given by(4hθ = tan-1 nmwhere the symbols have their usual meaning.Sol. |
| Answer» | |
| 11026. |
30 If the time of flight of a bullet over a horizontal rangeRis T, then the angle of projection with horizontal is(1) tan(2) tan 2R(3) a2R(4) tan 2RgT |
| Answer» | |
| 11027. |
30 If the time of flight of a bullet over a horizontal rangeRis T, then the angle of projection with horizontal is(1) tan- 972R(2) tan 2R2gT(1(3) tan- 2R(4) tan-1(R)2T |
| Answer» | |
| 11028. |
Earthquakes cannot be ......... |
|
Answer» Earthquakes can not be predicted. that Questions Anwar is earthquake cannot be predicted The earthquakes can't be predicted Anwar is earthquake cannot be Predicted /stopped or prevented by They can't be predicted Earthquake cannot be predicted earthquakes cannot be predicted actually earthquake are not predicted and often cause huge damage |
|
| 11029. |
Choose the correct option:Evening star rises when:(a) |
|
Answer» the question you have posted is incomplete please post the complete question |
|
| 11030. |
in the cirmuit given beiiow, lind the camem through 100bog302+15 |
|
Answer» let the voltage at the centre be V and current in 10Ω = i1 , 20Ω = i2 and 30Ω = i3 let i1 = i2+i3 so, according to Kirchoff rules => (10-v)/10 = (v-15)/30 + (v-6)/20=> 10-v = v/3 -5 +v/2 -3=> 11v/6 = 18=> v = 108/11 so, Ii = (10-108/11)/10 = 2/110 = 1/55 A |
|
| 11031. |
Two nuclei have mass number in the ratio 1:8.What is the ratio of nuclear density? |
| Answer» | |
| 11032. |
6230Radios of age of girls and his mother 2:50.90 cmsad G4 Ple A8S ah) 685:n gand Oud these Current age. andalso find that what there age 's 10 year990. Pad that |
|
Answer» According to the question present age of girl = 2xthat of her mother = 5xafter 5 years age of girl = 5yand that if mother = 11ynow According to the given condition, 2x + 5 = 5y -2x + 5y = 5 ... (i) and 5x + 5 = 11y -5x + 11y = 5 ... (ii) Multiplying eq (i) by 5 and (ii) by 2 and subtracting (i) from (ii) we get, -3y = -15y= 5 x = 10Hence present age of girl = 2x10 = 20and that of mother = 5x10 = 50Age of girl 10 years ago = 20 -10 =10Age of mother 10 years ago = 50 -10 =40 y=5 x =10 correct answer following |
|
| 11033. |
balls of mass ratio 1:2 are dropped from the same height.Two(G)State the ratio between their velocities when they strike the ground, andi) the ratio of the forces acting on them during motion. |
| Answer» | |
| 11034. |
A rocket has been fired upwards to launch a satellite in its orbit. Namethe two forces acting on the rocket immediately after leaving the launchingpad.9.Iront in ater air in |
|
Answer» thanks u very much |
|
| 11035. |
9. A rocket has been fired upwards to launch a satellite in its orbit. Namethe two forces acting on the rocket immediately after leaving the launchingpad. |
| Answer» | |
| 11036. |
Q. 11 Check by dimension analysis whether the following equations are correct(i) v =, where P is Pressure and pis density |
|
Answer» V = velocity has dimension of LT-¹ and pressure = F/A has dimension of ML-¹T-² and density = M/V has dimension of ML-³ so, pressure/density = L²T-²and √(pressure/density) = LT-¹ which is same as Velocity , hence ✓ |
|
| 11037. |
usesofthemirror |
|
Answer» Concave Mirror Concave mirrors are commonly used in torches, search-lights and vehicles headlights to get powerful parallel beams of light. They are often used as shaving mirrors to see a larger image of the face. The dentists use concave mirrors to see large images of the teeth of patients. Large concave mirrors are used to concentrate sunlight to produce heat in solar furnaces. Convex Mirror Convex mirrors are commonly used as rear-view (wing) mirrors in vehicles. Convex mirrors are preferred because they always give an erect, though diminished, image. Also, they have a wider field of view as they are curved. Thus, convex mirrors enable the driver to view much larger area than would be possible with a plane mirror. Mirrorsare mostly used for personal grooming purposes, architectural design, cameras, lasers, telescopes and various industrial machineries. There are also some non-optical objects where theuseof electromagnetic radiation is used and designed for other wavelengths mirror can help you to see the objects behind you while driving or riding.. Mirrorsare mostly used for personal grooming purposes, architectural design, cameras, lasers, telescopes and various industrial machineries. There are also some non-optical objects where theuseof electromagnetic radiation is used and designed for other wavelengths |
|
| 11038. |
A particle is thrown vertically up with a velocity of 50 m/s. what will be its velocity at highestpoint of journey? How high would the particle rise? What time it takes to reach the highest point?(Take the value of g-10 m/s') |
|
Answer» U= 50m/sg= -10m/s^2 The velocity at the highest point will be 0 m/sThus v=0 Height can be calculated by 2gs=v^2-u^2-20s= -2500s= 125m Time :v= u+gt0=50-10t-50=-10tt= 5sec |
|
| 11039. |
A particle is thrown vertically up with a velocity of 50 m/s. what will be its velocity at highestpoint of journey? How high would the particle rise? What time it takes to reach the highest point?Take the value of g=10 m/ s*)ud |
| Answer» | |
| 11040. |
100 J of heat is produced each second in a 4 Ω resistance. Find thepotential difference across the resistor. |
| Answer» | |
| 11041. |
A particle is thrown vertically upiwith a velocity of 50 m/s. what will be its velocity at highestpoint of journey? How high would the particle rise? What time it takes to reach the highest point?(Take the value of g-10 m/ s?)Page 3 of 4 |
|
Answer» tq |
|
| 11042. |
(c) 6.25x10*(d) 625x108 100J of heat are produced each second ina40resistance. Find the potential difference across the |
|
Answer» Power = Potential²/Resistance=> 100= V²/4=> V² = 400=> V = 20 VPlease hit the like button if this helped you |
|
| 11043. |
13. The speed of a projectile at the highest point becomes下times its initial speed. The horizontal range ofthe projectile will be27u2g3g |
| Answer» | |
| 11044. |
The speed of a projectile at the highest pointbecomes /2 times its initial speed. The horizontal rangeof the projectile will be2(b) 702g2(c) 7o4g3g |
| Answer» | |
| 11045. |
A projectile is fired from the top of a 40 m high cliswith an initial speed of 50 m/s at an unknown angleFind its speed when it hits the ground. |
| Answer» | |
| 11046. |
Heat produced per second in aresistor of 42 is 400 J. Calculatethe value of potential differenceacross the resistor and current in it. |
| Answer» | |
| 11047. |
7.In the circuit shown, the cument in the 1Ω resistor is6V[JEE (Main) 20152Ω3Ω |
| Answer» | |
| 11048. |
A 0.5 kg ball is thrown up with an initial speed 14 m/s andreaches a maximum height of 8.0m. How much energy isdissipated by air drag acting on the ball during the ascent |
| Answer» | |
| 11049. |
Duplex process of steel making is a combination of(a) Basic bessemer and acid open hearth processes(b) Acid bessemer and basic open hearth processes(c) Acid bessemer and acid open hearth processes(d) Basic bessemer and basic open hearth processes25. |
|
Answer» A two-stepprocedure in whichsteelis refined by one process(usually the Bessemer process) and finished by another process(usually open-hearth or electric-furnace). Also known as duplexing;duplexpractice. |
|
| 11050. |
t2.2ind the vac6V |
| Answer» | |