InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 11101. |
MITIUUIII Assessment Practice Sheet)| 10. A physical quantity A is related to four otherphysical quantities a, b, c and d asfollows, Arao. The percentage errors ofavameasurement in a, b, c and d are 1%, 3%, 2%and 2% respectively. What is the percentage errorin the quantity A?(1) 12%(2) 7%(3) 5%(4) 14% |
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| 11102. |
Name the physical quantity whose unit is angstrom? |
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Answer» Angstrom is unit which is used to measure Length. |
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| 11103. |
Name the physical quantity whose unit is angstrom ? |
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Answer» It is the smallest unit of length. The unit of length is angstrom |
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| 11104. |
Is it possible to have dimensionless and unitphysical quantities?es |
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Answer» Unitless quantity-the quantity which is measured consist no unit . These quantity are relative to some other quantity or have some constant value. ex -specific gravity, relatives permittivity. Important thing is thatAll unitless quantity are dimensionless quantity. Dimensionless quantity- these are the quantity which are out of frame reference or coordinate geometry.ex mass(kg) , temperature(F/C),pressure(N/m2). Note-all Dimensionless are not unitless. They may have unit or may not. |
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| 11105. |
6) Ramu: All minerals are Ores.Somu: All Ores are mineralswhich statement of them that you support? Why? |
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Answer» Minerals are naturally occurring inorganic solids with a crystalline structure and a definite range of chemical formula. Ores are concentrations of minerals in rock that are high enough to be economically extracted for use. All ores are minerals, but all minerals are not necessarily ores. |
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| 11106. |
d 24. A ball is dropped from a balloon going up at a speed of7 m/s. If the balloon was at a height 60 m at the timeof dropping the ball, how long will the ball take inreaching the ground ? |
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| 11107. |
Derive the expression for the energy stored in parallel plate capacitor. Hence obtain theexpression for energy density of electric field |
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Answer» When a capacitor Is charged by a battery., it has to perform more and more,work done is stored as electric energy in capacitor,Therfore the work done is given as:dW = V dqAs we know that q =CVV = q/CW =∫dW =∫Vdq = ∫q/C dq= q^2/2C |
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| 11108. |
Example 9.6 Light from a point source in air falls on a sphericalglass surface (n 1.5 and radius of curvature - 20 cm). The distof the light source from the glass surface is 100 cm. At what positionthe image is formed? |
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| 11109. |
6. Static electricity is produced by(a) friction only(b) induction onlyc) friction and induction both (d) chemical reaction only |
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Answer» option c is the answer. |
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| 11110. |
b) During a freefall,willheavleröbjeetsacceieratemuelali29. Can we apply Newton's third law to the gravitational force ? Explain |
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Answer» Yes, newton's third law can be applied to the gravitational force. According to newton's law of gravitation, every body in the universe attracts every another body. Also, the force of attraction between two bodies are equalin magnitude and opposite in direction. For example: when a apple falls towards the earth, both the apple and earth attracts each other with a force which are equal in magnitude and opposite in direction. |
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| 11111. |
Calculate the deviation suffered by the way which is incident on the plane horizontal mirror at an angle of 60° |
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Answer» 30° because normal ray is 90 so when we find angle of deviation 90 - 60=30° |
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| 11112. |
Dean Stardingand morene leth__unilom.takcom a balluny daltonacceleration attalns a speed uermineA 40 minutesand its accelerationellelcentenas |
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Answer» sorry friend I don't know |
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| 11113. |
A bus decreases its speed from80 km/h to 60 km/h in 5 s. |
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Answer» thanks |
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| 11114. |
Acaristravellingat20km/handspeedsupto60km/hin6secondsWhatis ts aceleaton |
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Answer» acceleration=v-u/ta=60-20/6=40/6=6.6km/hr^2 wrong. |
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| 11115. |
4. International Principles:- |
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Answer» The International Principles on the Application of Human Rights to Communications Surveillance is a document which attempts to "clarify how international human rights law applies in the current digital environment". |
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| 11116. |
Example 11.4 What is the work to be doneto increase the velocity of a car from30 km h^-1 to 60 km h^-1 if the mass ofthe car is 1500 kg? |
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Answer» This is wrong answer This is also wrong i think the answer should be 156375 J. Mass of the car,m= 1500kg Initial velocity of the car = 30km/hr = 30×1000m/60 ×60s =8.33m/s Similarly,the final velocity of the car, v= 60km/hr =16.67 m/s Therefore,the initial kinetic energy of the car, E(initial) = 1/2 mu^2 =1/2×1500×8.33 52041.68 J. The final kinetic energy of the car, E(final) = 1/2 1500×16.67 =208416.68 J. Thus, the work done = change in kinetic energy = E(final) - E(initial) = 208416.68 - 52041.68 = 156375 J. sorry for inconvenience, the conversion is done wrong in previous solution. Last solution is correct |
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| 11117. |
Example 11.4 What is the work to be doneto increase the velocity of a car from30 km h-1 to 60 km h-' if the mass ofthe car is 1500 kg? |
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Answer» Work = Change in kinetic energy= 0.5 m (v² - u²)= 0.5 × 1500 kg × [(60 × 5/18 m/s)² - (30 × 5/18 m/s)²]= 156250 joules= 156.25 kJ Work done is 156.25 kJ |
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| 11118. |
Explain why, it might be dangerous to raise an umbrella over our head in a thunderstorm. |
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Answer» Lightning is an electric discharge from cloud which can travel through metallic rod of theumbrella. Because of this, the person carryingumbrellamay experience electric shock. Hence it is notsafe to raiseanumbrelladuring thunderstorm. |
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| 11119. |
(2 реж2рео Sin*30 o5E - x0T BN |
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Answer» thanks |
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| 11120. |
. Potential difference = 45 voltElectric Evrent = 2010 angResistance = ? |
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Answer» Materials and components that obey Ohm's law are described as "ohmic" which means they produce the same value for resistance (R = V/I) R =V/'I = 4.5/3*10^3 R = 1.5*10^-3 R = 1.5*10^-3 Ohms |
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| 11121. |
05.The phase difference between two SHM y, 10 sin10xt+and y 12sin 8Ttatt 0.5 s is:S IS:11π1213π(b) 12(a)17π12 |
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Answer» phi1=π/3and phi2=π/4hence difference is π/3+π/4=11π/12 |
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| 11122. |
(C) It is the same as his actual weignt.(D) It is zeroA kite of mass m is skillfully held stationary in the sky. The net11.force on the kite is(C)(D) none of these(A) zero(B) mg.-mg.folt hy us? |
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Answer» say answer |
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| 11123. |
A particle executes SHM represented by theequation : 10 y=0.1 \sin 50 \pi t, where the displacementy is in metre and time t in second. Find theamplitude and frequency of the particle. |
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Answer» y = 0.01 sin 50 pi t=> Amplitude = 0.01 m2pi /T = 50 pi=> 1/T = 25=> Frequency = 25 Hz PLEASE HIT THE LIKE BUTTON thanks |
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| 11124. |
easy way to find phase difference if a particle is showing SHM |
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Answer» Displacement in SHM is given by x = A sin( wt) where A is amplitude, w is angular velocity, t is instantaneous time. Velocity is rate of change of displacement with time. Differentiating displacement with respect to time, we have, V = Aw cos(wt) Phase difference between sin and cos function is 90 degrees or pi/2 radians . Hence phase difference between displacement and velocity is 90 degrees or pi/2 radians. Similarly, acceleration can be obtained by differentiating equation of velocity. Acceleration a = - Aw^2 sin (wt) Hence phase difference between velocity and acceleration is also pi/2. Phase difference between displacement and acceleration is pi radians or 180 degrees. Hope this will clear concept |
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| 11125. |
A particle executes SHM with a time period of 2 s and amplitude 5 cm Find (i) displacement (ii) velocity and (ii) acceleration, after 1/3 second ; starting from the mean position. |
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Answer» (i) displacement is x = 5 sin (2π/T t ) = 5 sin (π t ) [cm] x(t=1/3) = 5 sin (π/3) = 5*√3/2. (ii) then the velosity would be v = 5π cos (π t) [cm/s] v(t=1/3) =2.5π (iii) acceleration a = -5 π2sin (π t) a(t=1/3)= -2.5π2√3 |
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| 11126. |
Give the magnitude and direction of net force acting on a kite skillfully held stationary in theSky. |
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Answer» (c)Zero net force The kite is stationary inthe sky, i.e., it is not moving at all. Hence, as perNewton’s first law of motion, no net force is acting on the kite. |
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| 11127. |
Q4. If a body is not in rest net force acting upon it cannot be zero. (True/False) |
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Answer» When a bodyis moving with a constant velocity, thenet external force actingon thebodyiszero. Yes, evenwhenthenet external forceiszero, an object may travel withnon-zerovelocity. The answer is False. |
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| 11128. |
10. A feather of mass 20 g is dropped from a height. It isfound to fall down with a constant velocity. What isthe net force acting on it? |
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Answer» Net force will be zero as F = mai. this case change i. velocity is zero so acceleration will be zero hence...F=20 × 0 = 0 newton since the velocity is constant there isn't any force acting. |
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| 11129. |
Give the magnitude and direction of net force acting on a kite skillfully held stationary in theSky.3. |
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Answer» Zero net force The kite is stationary inthe sky, i.e., it is not moving at all. Hence, as perNewton’s first law of motion, no net force is acting on the kite. |
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| 11130. |
The maximum force, in addition to the weightrequired to pull a wire 5 cm long from the surface ofwater at 20°C is 728 dynes. Calculate the surfaceten sion of waterAns. 72.8 dynes/cm |
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Answer» T=F/2l=728/2*5=72.8dyne/cm |
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| 11131. |
A particle executes SHM of amplitude a. (i) At whatdistance from the mean position is its kinetic energyequal to potential energy?(ii) At what points is its speedhalf the maximum speed?Ans. (i(ii)a-a |
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Answer» Potential energy = (1/2) kx^2=(1/2) mω^2x^2Kinetic energy = (1/2) mv^2= (1/2) m[ω√(A^2-x^2)]^2=(1/2) mω^2(A^2-x^2)Where,xis the required position about the mean position,A is amplitude of SHM,m is mass of particle executing SHM,ω is the angular frequency of the particle. Given, P.E. = K.E.so, (1/2) mω^2x^2 = (1/2) mω^2(A^2-x^2)so, x^2= A^2/2so,x =A/√2 I knew it I want 2nd part |
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| 11132. |
A particle starts SHM from the mean position. Itsamplitude is a and total energy E. At one instant, itskinetic energy is 3E/4 Its displacement at that instant is(a) 1/V2(c) Q(b) a/2(d) a//3/3/2 |
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Answer» The equation of the simple harmonic motion is y = A sinωt with usual notations. The total energy is (½) m ω2a2and the kinetic energy is (½)m ω2(a2–y2). Therefore we have (½) m ω2a2= E and(½)m ω2( a2–y2) = 3E/4. Dividing the second equation by the first, 1 – y2/a2= ¾, from which y = a/2. |
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| 11133. |
a spherical ball contracts in volume by 0.01% when subjected to a normal uniform pressure of 100 atmospheres . the bulk modulus of its material in dynes/cm^2 is |
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| 11134. |
The height of a tower is 7848 cm. A particle isthrown from the top of the tower with thehorizontal velocity of 1784 cm/s. The time takerby the particle to reach the ground is (g 981cm/s?)(a) 8s (b)2s (c)4s (d)8s |
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| 11135. |
The average kinetic energy of a gas molecule at 27°C is 6.21x 10-21J. Its average kinetic eat 227°C will be(1) 52.2 x1021J (2) 5.22 x1021nergy(3) 10.35 x 10 2(4) 11.35x1021 |
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Answer» thanks |
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| 11136. |
30.When temperature is increased from 0°C to 273°C, inwhat ratio the average kinetic energy of moleculeschange ?(2)3(3)4(4)2 |
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| 11137. |
Explalfl.g has a speed of 400 m/s. What is its kinetic energy ? If the builet strikes a thick targetin 2 cm, calculate the average net force acting on the bullet What happens to thekinetic energy originally in the bullet ? |
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| 11138. |
7.Mean kinetic energy (or average energy) per gm.molecule of a monoatomic gas is given by:(2) KT/2(4) 3KT/2(1)3RT/2(3) RT/3 |
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| 11139. |
Define moment of inertia of a rigid body find the moment of inertia of a straight rod about an axis passing through its centre and perpendicular to its plane. |
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Answer» The moment of inertia, otherwise known as the angular mass or rotational inertia, of a rigid body is a tensor that determines the torque needed for a desired angular acceleration about a rotational axis; similar to how mass determines the force needed for a desired acceleration. |
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| 11140. |
Define moment of inertia of a rigid body. Find the moment of inertia of a circular ring about an axis passing through its center and perpendicular to its plane. |
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Answer» Themoment of inertia, otherwise known as the angular mass or rotationalinertia, of a rigid bodyis a tensor that determines the torque needed for a desired angular acceleration about a rotational axis; similar to how mass determines the force needed for a desired acceleration. |
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| 11141. |
I. A forceof S0 dynes acts on a rigid body, such that the perpendicular distance between the fulcrumand the point of application of force is 75 cm. Calculate the moment of force. |
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Answer» Force F = 50 dynes ⊥ distance = 75cm ∴ Moment of force = F × ⊥ distance = 50 × 75 = 3750 dynecm |
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| 11142. |
Q.3 A person is said to be shont-sightod if(1) the person cannot soe things clearly when they are placed near the eye.(2) the ray from a distant object are focussed before they reach the retina.(3) the cye ball is too short(4) the retina does not work efficiently |
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Answer» Short-sightedness, ormyopia, is a very common eye condition that causes distant objects to appear blurred, while close objects can be seen clearly.hence the ray from a distant object are focussed before they reach the retinaoption 2 |
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| 11143. |
9. At what temperature is the root mean square speed of an atom in an argon gascylinder equal to the rms speed of helium gas atom at-20°C? Atomic mass ofargon 39.9 u and that of helium 4.0 u. |
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| 11144. |
A cylinder of fixed capacity 67.2 litres containshelium gas at STP. Calculate the amount ofheat required to raise the temperature of thegas by 15°C ? (R = 8.314 Jmol-Ĺ k-1 |
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Answer» Volume V = 67.2 litres of Helium at STP ΔT = 15⁰K1 mole of an ideal gas occupies 22.4 litres at STP. So number of moles of Helium gas n = 67.2/22.4 = 3 we know that γ = ratio of specific heats for an ideal mono atomic gas = 5/3 C_p = heat capacity at constant pressure for a mono atomic gas = 5/2 R C_v = heat capacity at constant volume for a mono atomic gas = 3/2 R Change in internal energy = n C_v ΔT = 3 * 3/2 * 8.31 J/mol/°K * 15°K = 560.925 Joules There is no change in the volume and hence no work done in heating the gas by 15 deg. Heat supplied = change in internal energy = 560.925 Joules |
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| 11145. |
sample of helium gas is at a temperature of 300 K and a pressure of 0.5 atm. What isaverage kinetic energy of a molecule of a gas? |
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Answer» 502 kinatic energy is releases |
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| 11146. |
26. A nearly ideal rigid body is -(a) rubber (b)iron. (c) aluminium. (d) glass |
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Answer» it may be iron.. option b |
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| 11147. |
m ulus Ul Steel = 200 X IU Nm.) Two steel rods and an aluminium rod of equal lengthlo and equal cross section are joined rigidly at their endsas shown in the figure below. All the rods are in a stateof zero tension at 0°С. Find the length of the systemwhen the temperature is raised to 0. Coefficient of linearexpansion of aluminium and steel are On and onrespectively. Young's modulus of aluminium is Y, and!of steel is Y,SteelAluminiumSteelFigure 23-E1 |
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Answer» Copper rod joined to a steel rod.the rods have equal length and equal cross-sectional area.the free end of the copper rod is kept at 0 degree and that of steel rod is kept at 100 degrees.find temperature at the junction of rods.conductivity of copper=390W/m-c and that of steel=46W/m-c |
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| 11148. |
9.a Consider the circuit shown in the figure. An ideal voltmeter reads 10V across X. If an ideal ammeter isconnected across X it reads 5A. Find the value of X in Ω. |
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Answer» Since voltmeter and , ammeter are connected across x Ω , so, V across X = 10 and, i = 5A so,The vakue of resistance X is 10/5 = 2Ω . I did the same bro but unfortunately the answer is 3 |
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| 11149. |
A steel needle sinks in water but a steel ship floats. How? |
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Answer» Ans :- An object willfloatinwaterif its density is less than that ofwater.A steel needle sinkssince its density is more thanwater. The interior of aship is hollow. Therefore, its average density is less than that ofwater, therefore, itfloats. |
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| 11150. |
3. Which is more elastic-rubber or steel? Explain. |
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Answer» Elasticity is defined as the property by virtue of which a material is able to stretch when a force is applied and is able to get back to its original state when the force is removed. Steel is more elastic than rubber as rubber come back to its original position after stretching,but after this there is some looseness or u can say it becomes loose but in case of steel even after very frequent stretching it don'tbecome loose. |
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