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let us assumevrepresents velocity and t represents time in given expression then we may find dimensions ofa & bas following

L.H.S=v

=[L][T^(-1)]

R.H.S=at+bt^2

[at]=[bt^2](since only quantity of same dimensions are additive.)

[bt^2]=[bT^2]

since LHS should be equal to RHS

so

[bT^2]=[LT^(-1)]

b=LT^(-3)

sodimension of b will be [LT^(-3)]

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Thanks

let us assumevrepresents velocity and t represents time in given expression then we may find dimensions ofa & bas following

L.H.S=v

=[L][T^(-1)]

R.H.S=at+bt^2

[at]=[bt^2](since only quantity of same dimensions are additive.)

[bt^2]=[bT^2]

since LHS should be equal to RHS

so

[bT^2]=[LT^(-1)]

b=LT^(-3)

sodimension of b will be [LT^(-3)]

Given that the drift speed of the electrons is Vd = 2.5×10^−4 m/s, charge of the electron is e= 1.6×10^−19 C, electron density is n = 8.0×10^28 per m3.

So, the current in the wire is,I = neAVdI = (8.0×10^28)×(1.6×10^−19)×A×(2.5×10^−4)I = A{32×105} amp

Resistance of the wire is,

R=VI=5/(32×10^5×A) Ω

So the resistivity is,ρ = (A/l)*R= A/0.1×(5/32×10^5×A) = 5×10^−4/32⇒ρ=1.56×10^−5 Ω m

answer is 1.6*10^-5

I = q/t

q = It = 1 × 16 = 16 C

4.5 ohm is the correct answer.

Anwer: d) holes and electronsExplanation:Semiconductor Current. The current which will flow in an intrinsic semiconductor consists of both electron and hole current. That is, the electrons which have been freed from their lattice positions into the conduction band can move through the material.

Natural gashas no color or odor. ...Natural gasis often praised as a clean energy alternative. It burns more cleanly than other fossilfuels, emitting lower levels of harmful emissions such as carbon monoxide, carbon dioxide and nitrous oxides. It produces less greenhousegasesthan other fossilfuelsdo.

prime factories is 408 is correct answer

2×2×2×2×2×3 is the prime fact of 96

2×2×2×2××2×3 is the prime factor of 96

bhai second wala 2×2×2×3×17 is the prime fact of 408

prime factories is 408 is the correct answer

96/1=48/2=24/2=12/2=6/2=3, 408/2=204/2=102/2=51/3=17

Density = mass/volume

Volume = mass/density

Volume = 1/1.3

Volume = 0.77 m^3

Velocity is the vector quantity it is the direction aware

19. If an object is immersed in a liquid then the buoyant force due to liquid acts on the object in verticallyupwarddirection.

19. If an object is immersed in a liquid then the buoyant force due to liquid acts on the object in verticallyupwarddirection.

A body of mass 500g or 0.5 kg , initially at rest is acted upon by force which causes it to move a distance 4m in 2sec.

here, initial velocity , u = 0time taken , t = 2 sec distance covered , s = 4m

use formula , S = ut + 1/2 at² 4 = 0 + 1/2 × a × 2² 4 = 2a => a = 2 m/s²

we know, from Newton's 2nd law of motion, F = ma here, m = 0.5kg and a = 2m/s² so, F = 0.5 × 2 = 1N

hence, force applied 1N

a= 2F= 1N is the correct answer of the given question

body will be at rest, when the Velocity of the body is 0.

like my answer if correct

the angle is 45 degree s

the angle is 45 degrees

a*b=a*babhineta =abcostetatanteta=1teta=45please like my answer

It is not possible to see in a dark room because of absence of light. We know that we are able to see something when light falls on it. If there is light outside the room, then the objects outside the room can be seen.

R2 R3 in serioes = 4+4= 8ohmnow R4 and 8 ohm in parallel= 8*4/8+4= 32/12= 8/3now 4+4+8/3= 12+12+8/3= 32/3 is resusltant resistance

P = P₀ + ρgh Where P₀ is the atmospheric pressure , g is acceleration due to gravity, h is the height from the Earth surface and ρ is density of water Here, P₀ = 10⁵ N/m² , g = 10m/s² , h = 3000m and ρ = 10³ Kg/m³ Now, P = 10⁵ + 10³ × 10 × 3000 = 3.01 × 10⁷ N/m²

Again, we have to use formula, B = P/{-∆V/V} Here, B is bulk modulus and { -∆V/V} is the fractional compression So, -∆V/V = P/B Put , P = 3.01 × 10⁷ N/m² and B= 2.2 × 10⁹ N/m²∴ fractional compression = 3.01 × 10⁷/2.2 × 10⁹ = 1.368 × 10⁻²

your answer is right but to long

bt thanks............

thanks

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Order of G = 10^-11

Mass of the person = 80 kgit is same on the Earth as well as on the Moon.

weight (force ) of the person on Earth = 80 kg wt = 80 kg * ge = 784 Newtons

weight of the person on the Moon = 80 kg * gm = 130.4 Newtons

2000

2000

2000

the moment of the inertia of the disc about an axis passing throw it's center of gravity and perpendicular to it's plane will be given by 1/2MK²= 1/2*M*(0.2)²k²= 0.02distance of center of oscillation from the point of suspension is = L= PO= k^2/L+L = 0.3mperiod of oscillation = T = 2π√L/g= 2*3.14*√0.3/9.8=1.098 second

plz explain