InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 11251. | 
                                    (D) Plise difference (3) between input and output voltage for the following circuits () and (Gi)10.0. The phase differenキVoR.will be(A) 0 and 0(C) π/2 and π/2(B)(D)π/2 and 0< δ π/2 respectively0 and 0 < δ π/2 respectively | 
                            
| 
                                   Answer»  As, we know that in capacitive circuit, the output voltage lags behind input by tan inverse of( R/Xc). So option B is correct  | 
                            |
| 11252. | 
                                    State and explain Kirchhoff's laws forelectric circuits. | 
                            
| 
                                   Answer»  Kirchhoff'scurrentlaw(1stLaw) states that current flowing into a node (or a junction) must be equal to current flowing out of it. This is a consequence of charge conservation.Kirchhoff'svoltagelaw(2ndLaw) states that the sum of all voltages around any closed loop in acircuitmust equal zero. please like the solution 👍 ✔️  | 
                            |
| 11253. | 
                                    other. Find the loss of kinetic energy during the collision.Consider a head-on collision between two particles of masses m, and m2. The initial speeds of theparticles are u, and u2 in the same direction. The collision starts at t 0 and the particles interact for atime interval Δ. During the collision, the speed of the first particle varies as v )-4-(y-ulQ.33tFind the speed of the second particle as a function of time during the collision. | 
                            
| 
                                   Answer»  correct answer is the correct ans is Mg/M+m+I/r² sorry for above ans  | 
                            |
| 11254. | 
                                    1. A jet airplane travelling at the speed of 450 kmh-1ejects the burnt gases at the speed of 1200 kmh-1relative to the jet airplane. Find the speed of theburnt gases w.r.t. a stationary observer on earth. | 
                            
| 
                                   Answer»  Velocity of jet w.r.t. groundVjg= 450 km/h …...(Upward) Velocity of products relative to jetVPJ= 1200 km/h …(downward) Hence, velocity of products relative to ground = -1200+450 = -750 km/h Here – ve sing means downward .  | 
                            |
| 11255. | 
                                    A car travelling at 60 kmh overtakes anothercar travelling at 42 kmh. Assuming cach car tobe 5.0 m long, find the time taken during theovertake and the total road distance used for theovertake24.[Ans. 2 s; 38.3 m] | 
                            
| 
                                   Answer»  thanks bro  | 
                            |
| 11256. | 
                                    A car A is moving with a speed of 60 kmh-1 aB is moving with a speed of 75 kmh 1, alorparallel straight paths, starting from the samepoint. What is the position of car A w.r.t. B after20 minutes?and car(Ans. 5 km behind) | 
                            
| 
                                   Answer»  Thank you very much..  | 
                            |
| 11257. | 
                                    3. An open car is moving on a road with a speed of100 kmh1. A man sitting in the car fires a bulletfrom the gun in the opposite direction. If the speedof the bullet is 250 kmh-1 relative to the car, thenfind its (bullet's) speed with respect to an observer(Ans. 150 kmh-1)on the ground. | 
                            
| 
                                   Answer»  Velocity of car, u=100 km/hVelocity of bullet in opposite direction, v=250 km/hSince observer is on ground, so ,for him the velocity of bullet will be (v-u) =250-100=150 km/h  | 
                            |
| 11258. | 
                                    vo electric circuits X and Y have been shown here. In which circuit will theater- give higher reading and why 2R2R1R1 | 
                            
| 
                                   Answer»  Second will have less reading as in second resistance are connected in series so resistance will be more so current will be less now ammeter reading will be more in first X Circuitas there resistance are in parallel so less resistance and high current  | 
                            |
| 11259. | 
                                    A rickshaw puller pulls the rickshaw by applying a force of 100N. If the rickshaw moveswith constant velocity of 9 kmh', then the power of the rickshaw puller isa) 250 Wb) 245 Wc) 255 Wd) 260 W | 
                            
| Answer» | |
| 11260. | 
                                    A rickshaw puller pulls the rickshaw by applying a force of 100kg N. if the rickshaw moves with constant (v) of 36km/h . find the power of the rickshaw puller.? | 
                            
| Answer» | |
| 11261. | 
                                    Voltmeter shown reads 18V. The resistance ofvoltmeter is44.2 302.430 V50Ω/824 52(A)(C)75Ω800/7Ω(B) 12092(D) 900/7Ω30 | 
                            
| 
                                   Answer»  Option (D) is correct.  | 
                            |
| 11262. | 
                                    Two particles are moving in circular paths of radiir, and r2 with same angular speeds. Then the ratioof their centripetal acceleration is | 
                            
| Answer» | |
| 11263. | 
                                    6. A body lying initially at point (3, 7) starts moving with a constant acceleration of 4i. Its position after 3 sisgiven by the co-ordinates(2) (7, 18)(3) (21, 7) | 
                            
| Answer» | |
| 11264. | 
                                    9. Explain the different motions at the same time. Give examples. | 
                            
| 
                                   Answer»  A body can have multiple motions at the same time, 1) Wheels of a moving car it has circular motion and rectilinear motion 2 ) A bob of a pendulum has linear and periodic motion  | 
                            |
| 11265. | 
                                    If H1 and H2 be the greatest heights of a projectilein two paths for a given value of range, then thehorizontal range of projectile is given by14 | 
                            
| Answer» | |
| 11266. | 
                                    IK. An aeroplane fles 400 m north and 300 m south and then fies 1200 m upwards then net displacement isA) 1200 mE4 1300 mC) 1400 mD) 1500 m | 
                            
| Answer» | |
| 11267. | 
                                    foxce of l ob im In a body Tn Tts ounfies fon Calewlate the oor done bt jrce.ON causes a ciaplacemen | 
                            
| 
                                   Answer»  Work done = Force× displacementW= 10× 2 =20 J.  | 
                            |
| 11268. | 
                                    हू 8 जय जि .: हा 00. Fon 2 ००८गौ, dBsterwce या का या 8. %“g”’v_m_'m)ue oy W[0 5me) | 
                            
| Answer» | |
| 11269. | 
                                    Question 9. A pipe 20 cm long is closed at one end. Which harmonicmode of the pipe is resonantly excited by source of 1237.5 Hz? (Soundvelocity in air 330 m/s).2 m | 
                            
| 
                                   Answer»  thank you..  | 
                            |
| 11270. | 
                                    9 A worker lives at a distance of 1.32 km from the factory. If the speed of sound in air be330 m/s, how much time will the sound of factory siren take to reach the worker ? | 
                            
| Answer» | |
| 11271. | 
                                    Two particles X and Y having equal charges, after being accelerated through the same potentialdiference, enter a region of uniform magnetic field and describe circular path of radius Ri and R2respectively. The ratio of mass of X to that of Y is1/2R,2(D) 1R2R2 | 
                            
| Answer» | |
| 11272. | 
                                    1An iron rod of 0.2 cm? cross-sectional area is subjected to a magnetising field of 1200 A/m.If the susceptibility of iron is 599, then magnetic flux produced in the rod is | 
                            
| Answer» | |
| 11273. | 
                                    5 kn avol dis fawus an int will | 
                            
| Answer» | |
| 11274. | 
                                    6 The co-ordinates of a moving particle at a time t, are5 cos 10t. The speed of thegive by, x 5 sin 10 t,yparticle is: | 
                            
| 
                                   Answer»  speed in x direction is dx/dt = 5*cos(10)t.10 = 50cos(10)t speed in y direction is dy/dt = 5*10*-sin(10)t so , speed is = √50²cos²(10t)+50²sin²(10t) = 50√2.  | 
                            |
| 11275. | 
                                    tween x-A and x = +A . The time taken for it to go from 0 to A/2 is T,and to go from A/2 to A is T2.Then(A) Ti <T2(B) T T2(C)T1 =T2(D)T1 =2T2 | 
                            
| Answer» | |
| 11276. | 
                                    o. A current i flows in the networkshown in the figure. Resultingmagnetic induction at point P isOP(A) Hoi41(B) (2uoi8a(C) Hoi(D) HolΣπα82a | 
                            
| 
                                   Answer»  Hi..Thank you for your question.I will be happy to help you Please give me some time to solve your problem option b is your correct answer Please let me know if you have any question regarding any steps provided in the solution option b is the right answer  | 
                            |
| 11277. | 
                                    The x and y coordinates of the particle at any time are x-5t-2t2 and y-10t respectivelywhere x and y are in metre and 't' in seconds. The acceleration of the particle at 't' 2s is | 
                            
| Answer» | |
| 11278. | 
                                    The spring extends by x on loading, then energy stored by the spring is:(if T is the tension in spring and k is spring constant)2T22kT2(A) 2kT2(B) 242(C) | 
                            
| Answer» | |
| 11279. | 
                                    11. A calorimeter contains 75 g of water at 15°C. When50 g water of 100°C is poured in the calorimeter, thetemperature of the mixture becomes 25°C. Calculatewater equivalent of the calorimeter. Ans. 300 g. | 
                            
| 
                                   Answer»  (m + 0.075)*1 *10 = (m+0.050)*1*7510m + 0.750 = 75m + 3.75065m = 3m = 3/65 kg  | 
                            |
| 11280. | 
                                    gi0N 8t the solutionace leision of the solutionD) it increases the viscosity of the liquid4)If a detergent is dissolved in water, the surface tension of waterA) remains constantB) increasesG decreasesD) becomes zero5) When a mercury drop of radius R hrar int | 
                            
| 
                                   Answer»  In a soap-and-water solution the hydrophobic (greasy) ends of the soap molecule do not want to be in the liquid at all. Those that find their way to the surface squeeze their way between the surface water molecules, pushing their hydrophobic ends out of the water. This separates the water molecules from each other. Since the surface tension forces become smaller as the distance between water molecules increases, the intervening soap molecules decrease the surface tension. (C) is correct option  | 
                            |
| 11281. | 
                                    whatA submarine is 1260 m below the sea level. If it rises up at the rate of 24 m a minute,depth will be the submarine after 35 minutes?! | 
                            
| 
                                   Answer»  24*35=840.....1260-840=420  | 
                            |
| 11282. | 
                                    A submarine is at 350 m below the sea level. It ascends for 10 seconds and then stops. Its final positionis at 100 m below the sea level. Find the speed of the submarine. | 
                            
| 
                                   Answer»  We know,Distance = Speed * Time Distance covered by submarine = 350 - 100 = 250 m Time taken = 10 sec Therefore,Speed of submarine= Distance/Time= 250/10= 25 m/sec  | 
                            |
| 11283. | 
                                    Electric fteld due to an electric dipole at a point on the equatorialline. | 
                            
| Answer» | |
| 11284. | 
                                    34.Theelectricpotential due to a hollow, charged metallicsphere of radius 12 cm at a point distant 6.0 cm fromits centre is 100 V. Calculate the potential at thesurface of the sphere and at a point 20 cm from theAns. 100 V, 60 Vcentre. | 
                            
| Answer» | |
| 11285. | 
                                    Calculate the potential at a point due to a charge of 4 x 10-9 C located9 x 10-2 m away from it. | 
                            
| Answer» | |
| 11286. | 
                                    1. In a submarine equipped with sonar, the time delay between the generation of apulse and its echo after reflection from an enemy submarine is observed to be 80s. If the speed of sound in water is 1460 m s1. What is the distance of enemysubmarine?. | 
                            
| Answer» | |
| 11287. | 
                                    2.4 PoTENTIAL DUE TO AN ELECTRIC DIPOLIE | 
                            
| 
                                   Answer»  We already know that electric dipole is an arrangement which consists of two equal and opposite charges +q and -q separated by a small distance 2a. ... Potential due to electric dipole does not only depends on r but also depends on angle between position vector r and dipole moment p.  | 
                            |
| 11288. | 
                                    derive the expression of electric potential due to at a point electric dipole . | 
                            
| 
                                   Answer»  1  | 
                            |
| 11289. | 
                                    Derive an expression for the electric potential due to electric dipole(a) on axial line (b) on bi-sector line | 
                            
| Answer» | |
| 11290. | 
                                    what the shape of equipotential surface for a point charge? | 
                            
| 
                                   Answer»  For an isolated charge, the equipotential surfaces are co-centricsphericalshells and the distance between the shells increases with the decrease in electric field  | 
                            |
| 11291. | 
                                    POTENTIAL DUE TO A POINT CHARGE | 
                            
| 
                                   Answer»  The potential difference between two points ΔV is often called the voltage and is given by ΔV=VB−VA=ΔPEq Δ V = V B − V A = Δ PE q . The potential at an infinite distance is often taken to be zero. The case of the electric potential generated by a point charge is important because it is a case that is often encountered.  | 
                            |
| 11292. | 
                                    What is binary fission? | 
                            
| 
                                   Answer»  Fission, in biology, is the division of a single entity into two or more parts and the regeneration of those parts into separate entities resembling the original.  | 
                            |
| 11293. | 
                                    Explain Maxwell free space equation | 
                            
| 
                                   Answer»  Maxwell's equationsare a set ofpartial differential equationsthat, together with theLorentz forcelaw, form the foundation ofclassical electromagnetism, classicaloptics, andelectric circuits. The equations provide a mathematical model for electric, optical, and radio technologies, such as power generation, electric motors,wirelesscommunication, lenses, radar etc. Maxwell's equations describe howelectricandmagnetic fieldsare generated bycharges,currents, and changes of the fields. One important consequence of the equations is that they demonstrate how fluctuating electric and magnetic fields propagate at the speed of light. Known aselectromagnetic radiation, these waves may occur at various wavelengths to produce aspectrumfromradio wavestoγ-rays. The equations are named after the physicist and mathematicianJames Clerk Maxwell, who between 1861 and 1862 published an early form of the equations that included the Lorentz force law. He also first used the equations to propose that light is an electromagnetic phenomenon. can you please send me more information  | 
                            |
| 11294. | 
                                    iThe unit for permittivity of free space (Eo) is | 
                            
| 
                                   Answer»  The SI unit for permittivity isfaradpermeter(F/m or F. m−1).  | 
                            |
| 11295. | 
                                    points.The shape of equipotential surface of a point chargein free space is | 
                            
| 
                                   Answer»  The shape will be concentric spheres with centre at the charge .  | 
                            |
| 11296. | 
                                    The unit for permittivity of free space (o) is(a) CN'm2 (b) Nm(d) CNm2 (d) CN tm | 
                            
| 
                                   Answer»  The SI unit for permittivity is farad per meter (F/m or F. m−1). The lowest possible permittivity is that of a vacuum. Vacuum permittivity, sometimes called the electric constant, is represented by ε0and has a value of approximately 8.85×10−12F/m. It's unit is C²N^−1M^−2 ( coulomb squared per Newton per square meter). Like my answer if you find it useful!  | 
                            |
| 11297. | 
                                    018) Which of the following has greater number of atoms 100 gm of N2 or 100 gm of NHs. (5) | 
                            
| Answer» | |
| 11298. | 
                                    1.29 A hollow charged conductor has a tiny hole cut into its surface.ń , where n is theShow that the electric field in the hole is (G/29)unit vector in the outward normal direction, and σ is the surfacecharge density near the hole. | 
                            
| Answer» | |
| 11299. | 
                                    The surface charge density of a thin chargeddisc of radius R is σ. The value of the electric32.field at the centre of the disc isIS E Withrespect to the field at the centre, the electricfield along the axis at a distance /3 R fromthe centre of the disc:(1) reduces by 70.7%(2) reduces by 29.3%(3) reduces by 86.6%(4) reduces by 13.4% | 
                            
| 
                                   Answer»  wrong answer  | 
                            |
| 11300. | 
                                    8.The reaction responsible for energy generation in the Sun is :(A) a chemical reaction(B) a controlled fission reaction(C) an uncontrolled fission reaction (D) fusion reaction | 
                            
| 
                                   Answer»  Fusionpowers stars and produces virtually all elements in a process called nucleosynthesis. The Sun is a main-sequence star, and, as such, generates its energy by nuclearfusionof hydrogen nuclei into helium.  | 
                            |