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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 11051. |
6E, rRIf E= 6V, r = 20 then maximum power dissipatedthrough R is :- |
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Answer» Maximum power=i x i /Rcurrent=12=12/1/2=24=24 X 24/R |
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| 11052. |
SciD.230. Four charge +4,-4, +q and -9 are puttogether on tour comers of a square asshown in figure. The work done byexternal agent in assembling thisconfiguration isA. zeroC. +2.59kq' /aB. -2.59 kq' /aD. |
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Answer» option B is the correct answe -2. 59 is the correct answerplease like my answer |
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| 11053. |
In the circuit shown, the reading of thevoltmeter and the ammeter are6VAO100221002210012 |
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Answer» Reading of volt meter= 6*100/300= 2 volt Reading of ammeter= 6/150= 2/50= 1/25 ampthanks |
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| 11054. |
Find the current in the 1012 resistance:-2100+20(1) 0.27 A P, to P,(3) 0.45 A P, to P(2) 0.03 A P, to P,(4) 0.27 A P, to P2 |
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Answer» the answer could be option 3 3) is the correct answer |
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| 11055. |
Draw a speed-time graph using the given data.Time (s)Speed (m/s)248 1010 15 20 20 20 15 |
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Answer» You can share the box to make it attractive |
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| 11056. |
what is first order liver? |
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Answer» Ans :- The most simplest of machines is the commonlever. ...First order levershave the turning point(fulcrum) between the load and the effort. A well knownfirst order leveris the see-saw. A pair of wire cutters is an example of twofirst order levers working together please answer all types of livers. |
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| 11057. |
e upper circular stone of a hand flourgrinder is provided with a handle near its rim(i.e., at the maximum distance from thecentre) so that it can easily be rotated aboutthe iron pivot at its centre by applying asmall force at the handle.(2) Th |
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Answer» Torque = force × perpendicular distance. By providing handle near rim the perpendicular distance between point of pivotion and point where force is applied, less force has to be applied to do work. Please hit a like if you find it useful |
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| 11058. |
Paragraph for Question Nos. 13 to 15Figure shows a siphon in action. A siphon is very convenient for50 cmemoving liquid from containers. But necessary condition for its workingis th175at the liquid removing tube must be filled completely with the liquidso that there could be pressure difference along the tube. If there is noliquid, pressure at all points has the same value and so liquid will notflow. The liquid shown in the figure is water having density of 1000kg/m. Both the liquid containers are open toatmosphere. All the heights are shown in the figure. (Take g 10 m/s')313Find the pressure difference between points B and C.(Zero(C) 1.25 x 104 N/m2(8) 1.5 x 101 N/m2(D) 101 N/m2 |
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| 11059. |
54. A hydraulic jack consists of a handle cum lever of 30cm.2 length and an assembly of given dimensions. In order that aload of 20 kN be supported by the jack, what should be theforce exerted on the handle? The distance between thefulcrum of the lever and the point where the plunger isconnected is 25mm.Brainstorming300mmLever Handle15mmFluid(a) 2000N (b) 2500N (c) 700N (d) 1500N |
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| 11060. |
\vec { a } - \vec { b } = \vec { a } + \vec { b } \text { . Comment on } \vec { b } |
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Answer» b= 0 it is a zero vector |
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| 11061. |
selve this equatfon see bysthe |
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| 11062. |
UUUU3003.2§ ferŹ3AMM3002findequivalenceResistance |
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| 11063. |
The following quantum numbers are possible for how many orbital(s) n=3,l=2,m=+2? |
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Answer» The following Quantum numbers are possible for only one orbital. |
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| 11064. |
8. At what separation should two equal charges, 1-0 C each,be placed so that the force between them equals theweight of a 50 kg person?17 |
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| 11065. |
At what separation should two equal charges, 10 eachn g is this force?be placed so that the force between them equals theweight of a 50 kg person? |
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| 11066. |
4. Two equal charges are placed at a separation of 1-0 m.What should be the magnitude of the charges so thatthe force between them equals the weight of a 50 kgperson? |
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| 11067. |
3. It costs less4. It causes less pollution than fossil energy.Q 5. What are the limitations of extracting energy from (a) the wind? (b) waves?se(e) tides ? |
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Answer» Limitations of extracting energy from above sources are (a)A windmill requires wind of speed more than 15 km/h to generate electricity from wind energy. Also large numbers of windmills are required to get feasible output which covers a large area. (b)Very strong ocean waves are required in order to extract energy from waves. But these are not available all the time? (c)Very high tides are required in order to extract energy from tides. But tides depends on the relative positions of the Sun, moon, and the Earth. |
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| 11068. |
4. Two equal charges are placed at a separation of 10 m.What should be the magnitude of the charges so thatthe force between them equals the weight of a 50 kgperson? |
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| 11069. |
A.35, in a rectangle ABCD (BC 2AB. The moment of inertia alongwhich axis will be minimumA) BCB) BDC) HrBy EG1h Three identical thin rods each of length /and mass M are joined together to form a letter H. What is the |
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| 11070. |
11.10) 12opposite and equal charges 4 x 10-coulomb when placed 2x10cm apart form a dipole. IfANIC the value of maximum torque andThis dipole is placed in an extemal electric field 4x10N/C, the value of IThe work done in rotating it through 100 from its initial orientation which is along electric fieldwill be :(A) 64x10-N-m and 44 x 10(B) 32x10-'N-m and 32 x 10-44.(C) 64x10 N-m and 32x100(D) 32 10 'N-m and 64 x 10 J. |
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Answer» The answer is option-D |
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| 11071. |
. Two solid balls of rubber A and B whose masses are200 gm and 400 gm respectively, are moving inmutually opposite directions. If the velocity of ball Ais 0.3 m/s and both the balls come to rest aftercollision, then the velocity of ball B is - |
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| 11072. |
Two solid rubber balls A and B havingmasses 200 and 400 gm respectively aremoving in opposite directions withvelocity of A equal to 0.3 m/s. Aftercollision the two balls come to rest, thenthe velocity of Bis [CPMT 1978, 86, 88(a) 0.15 m/sec (b) 1.5 m/sec(c) - 0.15 m/sec (d) of theabove |
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| 11073. |
Two solid balls of rubber A and B whose masses are200 gm and 400 gm respectively, are moving inmutually opposite directions. If the velocity of ballAis 0.3 m/s and both the balls come to rest aftercollision, then the velocity of ball B is(1) 0.15 m/s(2)-0.15 m/s(3) 1.5 m/s(4) of the above |
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Answer» Let after collision the velocity of ball B is "V" as they both have come to rest after collision Their momentum will be equal so M1V1= M2V2 0.2×0.3 = 0.4×V2....(converted mass into kg) Then by solving we will get V2 which is velocity of ball b is 0.15sec |
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| 11074. |
.36.Two charges 4 x 10-C and -16 x 10-Care separated by a distance 20 cm in air.The position of the neutral point from thesmall charge is |
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Answer» see thisthanks |
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| 11075. |
Sample Problem. A driver decreases the speed of a car from 25 m/s to 10 m/s in 5 seconds. Find theacceleration of the car. |
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| 11076. |
. Nat has completely illed R anu.If bromine atom is available in the form of, say, two isotopes32 Br (49.7%) and SO Br (50.3%), calculate the average atomicmass of bromine atom.li fon element X is 16.2 u. |
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| 11077. |
Ans: 2b. If the absolute refractive indices ofglass and water are 3/2 and 4/3respectively, what is the refractiveindex of glass with respect to water? |
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| 11078. |
b. If the absolute refractive indices ofglass and water are 3/2 and 4/3respectively, what is the refractiveindex of glass with respect to water?Ans: 9/8 |
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| 11079. |
If refractive indices of glass and water with respect to air are 3/2 andSample Problem4/3respectively, what is the refractive index of glass with respect to water4 |
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| 11080. |
Find the critical angle for a ray of light at glass -water interface if refractive indices for glass andwater are 1.62 and 1.32 respectively. |
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Answer» it wrong |
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| 11081. |
Six charges are placed at the corner of a regularhexagon as shown. If an electron is placed at itscentre O, force on it will beeax Zero(B) Along OF(C) Along OC(D) of these22 |
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Answer» Answer :- net Force act on electron will be zero . Explanation :- A regular hexagon has all sides are equal length . Now when we placed six equal charges at the corner of regular hexagon and one electron is placed at centre , then all six charges attract the electron with equal magnitude of force towards itself e.g., force act by each charge on electron , F = Kqe/r² Arrangement of forces are shown in figure . Here it is clear how net force act on it is zero. Hence answer is 0 please note that all charges are not same.Now please answer. |
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| 11082. |
One half of a ccnvex lens of focal length 10 cm is covered with a black paper. Can such a lensproduce an image of a complete object placed at a distancediagram co ustify your answerof 30 cm from the lens. Drav: a ray |
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| 11083. |
20. The refracting angle of a prism is 60 It is found that for two different angles ofcidence, the deviation produced by the prism is 40° If the difference between thetwo angle of incidence is 10s What are their values?(1) 55 45(2) 60, 50(3) 65, 55(4) 58°, 4821. The dispersion produced by an equilateral prism ot flint-glass is 2.16 and thatproduced by an equilateral prism of crown glass is 1.08°. What should be the angleof a crown glass prism, which will produce an achromatic combination with a flintglass prism of refracting angle 30?(2) 30°(3) 60°(4) 75 |
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| 11084. |
A thin bar of length f is placed horizontally along theprincipal axis of a concave mirror of focal length f insuch a way that centre of the bar coincides withcentre of curvature of the mirror. The length of imageof bar will be |
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| 11085. |
4A thin bar of length f is placed horizontally along theprincipal axis of a concave mirror of focal length f insuch a way that centre of the bar coincides withcentre of curvature of the mirror. The length of imageof bar will be |
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Answer» sir I am not talking about where it will form but about the actual length of the image .options are |
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| 11086. |
4IUf/3 is placed along theample 12. A thin rod of length fl3 is nl.que mirror of focal length f sucreal and elongated, just touches 1oth f such that itstouches the rod.Optic arts of a concise mirrorimage which is real and elong(HIT 93What will be the magnification ?of the red plazo |
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Answer» Since the image touches the rod, one end of the rod must be at C of the mirror.Since the image is real and elongated, the other end of the rod must be between C and F of the mirror.The distance of this latter ( A) end from the optic center of the mirror is (R-f/3) = 2f-f/3= 5f/ 3(u –f)= 5f/ 3-f = 2f/3m = f/ (u-f) = 3/2 = 1.5 Magnification of the A end of the rod is 1.5 where as the magnification of the joint of image and rod is 1. |
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| 11087. |
eneuaa α and4_ake constants-find dimensional |
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Answer» Dimension of E = ML²T-³ I-¹ , and dimensions of ∅ = K so, dimension of a∅ should also be ML²T-³I-¹ => dimension of a = ML²T-³I-¹/K = ML²T-³I-¹K-¹ and similarly dimension of ß∅ should be ML²T-³I-¹ => dimension of ß = ML²T-³I-¹K-² |
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| 11088. |
6. Using force (F), Length (L) and time (T)as fundamental dimension, find thedimension of'surface tension, young'smoduļus. |
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Answer» Force/length= MLT-²/L =MLT-² YOUNG'S MODULES =ML-¹T-² |
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| 11089. |
5. If force (F), length (L) and time (T) are chosen as thefundamental quantities, then what would be thedimensional formula for density? (Ans. FL4T2) |
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| 11090. |
1. The equation of force applied on a body is given by F- a+x wherex is the displacement and 'a', and 'b are constants. then the dimensionof will be-(a) MT-Ia(b) T-l(c) L(d) LT |
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| 11091. |
10.) The time dependence of a physical quantity P isgiven by PPo exp (-a t), where ais a constantand t is time. The constant α(1) dimensionless42) has dimensions T-2(3) has dimensions of P |
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| 11092. |
1.3 Check that the ratio kelG me m isdimensionless. Look up a Table of PhysicalConstants and determine the value of thisratio. What does the ratio signify? |
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| 11093. |
3) Which of Following is not Sl unitA) kg B)m C)ampere D)cm |
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Answer» which of following is not si unit is cm cm is the right answer centimeter is not a SI units option D is the right answer cm is the right answer which of following is not si unit is cm which of following is si unit is cm cm is cgs system unit of distance the correct answer is cm Cm is not SI unit ... cm is not a SI unit optionD can is not si unit. m kilogram, meter, ampere all are SI unit cm is not SI unit |
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| 11094. |
3) If length 'L', force F and time T' are taken asfundamental quantities. What would the dimensionalequation of mass and density? |
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Answer» Mass=force/acceleration=F/[LT^-2]=[FL^-1T^2] density=mass/volume=[FL^-1T^2]/L^3=[FL^-4T^2] |
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| 11095. |
. a) State Newton's second law of motion.b) Express it mathematically and find Sl unit of force from it. |
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Answer» 1.Newton's second lawof motion pertains to the behavior of objects for which all existing forces are not balanced. Thesecond lawstates that the acceleration of an object is dependent upon two variables - the net force acting upon the object and the mass of the object. |
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| 11096. |
30. Name the physical quantity whose unitis volt/ampere.Powen |
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Answer» resistance is the correct answer resistance............ |
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| 11097. |
BWhy strain is unit less and dimensionless physical quantity? |
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Answer» Answer :- Strain is the ratio of two quantities having the same dimension. The ratio of quantities with same dimensions gives merely a numerical value (As you know, a non-zero number divided by the same number results in 1). Because of this, strain has no dimensions strain is the ratio of change in a quantity by the same quantity...so the quantity is same hence its unit is same..so their dimensions are same...which makes strain a dimensionless quantity |
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| 11098. |
2) What is meant by unit of a physical quantity |
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| 11099. |
Name the physical quantities whose units are (i) Pascal (i) decapoise. |
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Answer» I)Thepascal(symbol: Pa) is theSI derived unitofpressureused to quantifyinternal pressure,stress,Young's modulusandultimate tensile strength. It is defined as onenewtonpersquare metre. ii)The poise is the unit of dynamic viscosity in the centimetre gramsecondsystem of units. Decapoise, symbol daP, is a prefixed form used to indicate multiples of poise. |
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| 11100. |
20. If pressure P, velocity V and time T are taken afundamental physical quantities, the dimensionaformula of the force is-(1) PV T2(2) Ply2-2(3) PVT |
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