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Light year :A unit of length in astronomy equal to the distance that light travels in one year in a vacuum.

Parsec: One parsec is the distance at which one astronomical unit subtends an angle of one arcsecond. A parsec is equivalent to 3.26 light years

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Balance forcesare twoforcesacting in opposite directions on an object, and equal in size. Anytime there is abalanced forceon an object, the object stays still or continues moving continues to move at the same speed and in the same direction.

Balancedforcesdo not cause a change in motion. When balancedforcesact on an object at rest, the object will not move. If you push against a wall, the wall pushes back with an equal but oppositeforce. Neither you nor the wall will move.Forcesthat cause a change in the motion of an object areunbalanced forces.

Balance forcesare twoforcesacting in opposite directions on an object, and equal in size. Anytime there is abalanced forceon an object, the object stays still or continues moving continues to move at the same speed and in the same direction.

Balancedforcesdo not cause a change in motion. When balancedforcesact on an object at rest, the object will not move. If you push against a wall, the wall pushes back with an equal but oppositeforce. Neither you nor the wall will move.Forcesthat cause a change in the motion of an object areunbalanced forces.

Force that do not cause change in motion is called balanced force and force that cause a change in the motion of an object is called unbalanced force.

Station is to provide an international laboratory for experiments within the space environment. Which, despite all our technological advances, is nearly impossible to replicate here on Earth. Because for many of those experiments, the key parameter is—weightlessness.

Limitation of Ohm's Law. Thelimitations of Ohm's laware explained as follows: Thislawcannot be applied to unilateral networks. A unilateral network has unilateral elements like diode, transistors, etc., which do not have same voltage current relation for bothdirections of current.

Let the Distance between A and is x km.

First Case---Initial Speed = 40 km/hr.

Using the Formula,

Speed = Distance/Time time = Distance/Speed time(t1) = x/40 hr.

In second Case,Final Speed = 60 km/hr.

Thus, time(t2) = x/60 km/hr.

For Average Speed,

Total Distance covered by the Car = x + x = 2x km.Total time = t1 + t2 = x/40 + x/60 = (4x + 2x)/120 = 6x/120 = x/20 hrs.

Using the Formula,

Average Speed = Total Distance/Total Time = 2x/(x/20) = 2x× (20/x) = 2× 20 = 40 km/hr.

Thus, Average Speed of the Car is 40 km/hr.

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d=100kmt=2 1/2 = 2.5hrsv=d/t=100/2.5=40km/hr

i) now d=120kmt=d/vt=120/40t=3hrs

ii)nowt=4hrsd=vtd=40*4=160km

In this question car starting from rest so u =0 acceleration= f distance = S time =t so velocity= 0 because they were in constant speed. hope this will help you like my answer and make it best answer.

In this question car starting from rest so u =0 acceleration= f distance = S time =t so velocity= 0 because they were in constant speed.hope this will help you like my answer and make it best answer.

Because of more friction is acting on mat

because of more friction is acting on mat

Because the we known that frictional force is directly propositional.To the weight of the person

(4x - 5) (4x - 1) plese solve question

How u find AB

(a) When a body projected upward with some velocity then acc. to newton due to gravity it falls downward so the velocity of that body become "zero" at highest poin tand it falls.

Angle between horizontal and gravitational force is 900.

w=FScos90°

= FS*0

= 0

horizontal velocity because horizontal velocity remain same throughout the projectile motion

In straight track, displacement will be equal to distance.

Distance= 100m (Given)

Displacement =100m

But I asked two more questions

Work done by the force = force * displacement horizontally W = F * Radius = 5 N * 5 m = 25 J

K E = Work done by Force 5 N + change in PE, due to conservation of energy

1/2 m v² = 25 N + 1/2 kg * 10 m /s² * 5 m = 50 N

v² = 200 => v = 10 √2 m/sec. = 14.14 m/s

Ans :- The composition of the ionosphere atnight is different than during the day because of the presence or absence of the sun.You can pick up someradiostationsbetterat nightbecause the reflection characteristics of the ionosphereare betteratnight.

Here the tension in the inclined string , will balance the horizontal and vertical movement of both the blocks

so, vertical component of tension = Tcos(45°) = W

and, horizontal component of tension =Tsin(45°)= friction force = 450 N

upon dividing both the equation Tcos(45°)/Tsin(45°) = W/450

=> W/450 = 1=> w = 450N

option C

The time period of the current = (2x0.01) = 0.02 second

Time period is the time required to complete one cycle.

After half rotation the current reverses its direction. In one rotation, the current flows in the original direction completing one cycle.

Frequency = 1/ time period = 50 Hz.

When thehorse is applying force to startthecartithasto overcome static friction and to keep thecartin motion,thehorse hasto overcome sliding friction. But static frictionis morethan sliding friction ,so thehorse, pulling acart has to applyagreater force to startthecartthan to keep the cartin motion.

Option B. Particle C is thrown with speed in horizontal direction so in Italy vertical speed is 0. But for particle B their is some initial speed in vertical direction and for A when it comes back to the same height it will have same speed as that of B

option c at bottom of plane

option c is the correct answer of the given

Given, Hight of Hall( H) = 25 m Let ball is thrown with speed 40m/s at an angle ∅ with horizontal .

We know, H = u²sin²∅/2g 25= (40)² × sin²∅/2× 10 25 = 80 × sin²∅Sin²∅ = 25/80 Sin∅ = 5/4√5 Cos∅ = √55/4√5

Now, horizontal range = u²sin2∅/g= (40)²× 2sin∅×cos∅/g= 160 × 2 × 5/4√5 × √55/4√5 = 20√55 m

Given vertical height = 10m. if we took it as max vertical height

then, u^2/2g = 10m => u^2/g = 20

As horizontal projectile range = u^2sin2∂/g

So, range is maximum when∂=45 degrees

Hence, maximum horizontal range is u^2/2g = 20,m

Energy = power*time

Energy = 60*5= 300 W/h