Explore topic-wise InterviewSolutions in .

This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

12351.

1. What is heat engine?

Answer»

In thermodynamics and engineering, a heat engine is a system that converts heat or thermal energy—and chemical energy—to mechanical energy, which can then be used to do mechanical work. It does this by bringing a working substance from a higher state temperature to a lower state temperature

12352.

33. What is a heat engine?

Answer»

In thermodynamics and engineering, a heat engine is a system that converts heat or thermal energy—and chemical energy—to mechanical energy, which can then be used to do mechanical work. The mechanical work often involves powering a generator which converts the mechanical energy to electrical energy.

12353.

3)The motion of a particle varies with timeaccording to the relation y- A(sin wt+cos wt)ThenA) it is an oscillatory motion but not a SHMB) it is a SHM of amplitude AC) it is a SHM of amplitude 2AD) it is a SHM of amplitude A V2

Answer»

Given y = A(sinwt +coswt)

multiply and divide with √2 on the R.H.S => y = A√2(sinwt/√2 +coswt/√2) => y = A√2 ( sin(wt +π/4) ...... ( 1/√2 = sinπ/4=cosπ/4)

so, the equation becomes

y = A√2sin(wt+π/4)

so, here the amplitude is A√2.

option D.

why you divide and multiply the equation by under root 2

because you have to add sin and cos function , to represent S.H.M in only one function..

so, √2 is multiplied and divided to convert

sinwt + coswt into sin function only.

12354.

The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum isBo-510 nT. What is the amplitude of electric part of the wave?

Answer»
12355.

ustly your answer.ORName the type of mirror used () by dentist and (il) shaving mirrors.Give two reasons why such mirrors are used in each case.Define electri

Answer»

Mouth mirror used by a dentist is a concave mirror, to get a magnified reflection of the mouth, without inverting the reflection image. A convex lens if used would provide a real image, which means would need a screen to form the image - all within the small space of a human mouth.

Concave mirrors, when viewed from closer than their focal length, make the reflected object appear larger.

Shaving in a concave mirror allows a person to see fine details including any remaining hairs or stubble that remains to be shaved.

12356.

The magnetic field at the centre of coil of n turns, bentin the form of a square of side 2/, carrying current i, is(2) V2μ0mπίTl4d

Answer»
12357.

what is heat engine?Explain construction, working and uses.

Answer»

A heat engine typically uses energy provided in the form ofheatto doworkand then exhausts the heat which cannot be used to do work. Thefirst lawandsecond law of thermodynamicsconstrain the operation of a heat engine. The first law is the application of conservation of energy to the system, and the second sets limits on the possible efficiency of the machine and determines the direction of energy flow.

12358.

.Ans.What are the laws of reflection through curved mirrors?Laws of reflection;

Answer»

The law of reflection says that the angle of incidence is equal to the angle of reflection. Or in less technical language, the angle at which light hits a surface (angle of incidence) is equal to the angle at which light bounces away from the surface (angle of reflection)Please like the solution 👍 ✔️👍

12359.

16. We can derive Newton'sa) second and third laws from the first law.b) first and second laws from the third law.third and first laws from the second lawd) all the three laws are independent of each other.

Answer»
12360.

10) A circular coil has 1000 turns each of area 2 m². If a current of 3mA flowthe coil, find the magnetic moment of a coil

Answer»
12361.

Q.20. Derive expression for the magnetic induction at the centre of a coil carrying current.

Answer»

Magnetic FieldPatterndue toaCircular Loop Carrying Current. Themagnetic fieldlines are concentric circles at every point of acurrent carrying circular loop. ... The direction ofmagnetic field at the centreofcircular coilis perpendicular to the place of thecoil. i.e. along the axis of thecoil.

B= idlsin theeta/r^2 by combination of all these

12362.

Radius of current carrying coil is 'R'. Then ratioof magnetic fields at the centre of the coil to theaxial point, which is R V3 distance away from thecentre of the coil :-

Answer»
12363.

A refrigerator is(a) an electric motor (b) a heat engine(c) a heat engine working back (d) an air cooler.Q.7

Answer»

Arefrigeratoris a reversedheat engine. ... Aheatpump is similar to arefrigerator.

12364.

5 MOLES OF AN IDEAL GAS ARE TAKEN IN A CARNOT ENGINE WORKING BETWEEN 100 . C-30 . C. THE USEFUL WORKDONE IN 1 CYCLE IS 420J. CALCULATE THE RATIO OF THE VOLUME OF THE GAS AT THE END AND BEGINNING OF THE ISOTHERMAL EXPANSION. (TAKE R = 8.4 J/mol K)

Answer»

The work done during isothermal expansion is given asW = 2.303nRT.ln(Vf/ Vi)so,ln(Vf/ Vi) = W / 2.303nRTor ratio will be given as(Vf/ Vi) = exp[W / 2.303nRT]here,Vf= final volumeVi= initial volumen = 5R = 8.314 J/KmolT = 100C = 373Kand W = 420Jthus,(Vf/ Vi) = exp[420 / (2.303 x 5 x 8.314 x 373)]or(Vf/ Vi) = exp[(420 / 7141.883)]thus(Vf/ Vi) = 1.059

12365.

20.During an isothermal expansion, a confined idealgas does +150 J of work against its surroundings.This implies that :-

Answer»
12366.

10 Name and state the two rules for finding the direction ofmagnetic field produced by electric current through a straightconductor

Answer»

set bro u r in 8 n we have not been taught Maxwell's law

12367.

How can one reverse the direction of magneticfield produced at the centre of a circular coilcarrying electric current? [1-mark, 2011]

Answer»

The direction of the magnetic field can be changed by changing the direction of the current. If a circular coil is carrying current in a clockwise direction then the direction of the magnetic field created at the centre of the coil will be inside the plane. And in a coil carrying current in an anti-clockwise direction will have the direction of the magnetic field outside the plan, at the centre of the coil.

12368.

70. Explain why it is impossible to design a heat engine with 100% efficiency?erteuperatuOrEven Carnot engine cannot have 100% efficiency. Explain, Why?

Answer»

Answer: Another form of the Second Law of Thermodynamics or Carnot's Principle is that : It is not possible to make aheat enginewhose only effect is to absorbheatfrom a high-temperature region and turn all that heatinto work. ... Or, it is not possible todesign a heat enginethat has an efficiencyof 1.00 or100%

The second law of thermodynamics puts a fundamental limit on the thermalefficiencyof all heatengines. Even an ideal, frictionlessenginecan't convert anywhere near100% of its input heat into work. ... No device converting heat into mechanical energy, regardless of its construction, can exceed thisefficiency.

12369.

72. In a Carnot engine, the temperature of the sink is increased. What will happen to its efficiecncy?

Answer»

We know ƞ = 1 – T2/T1

On increasing the temperature of the sink (T2), the efficiency of the Carnot engine will decrease

12370.

A long Straight wire carries a current 20A from west to eastdirection.What is the magnitude of the magnetic field strength atapoint 20 cm below the wire?

Answer»
12371.

43. An ideal Carnot engine, whose efficiency is 40%.receives heat at 500 K. If its efficiency is 50%, thenthe intake temperature for the same exhausttemperature is

Answer»
12372.

13012. What is solenoid? Draw the field ines of magnetic field produced on passing current through anfield lines of maaround a current carrying solenoid.(2)

Answer»
12373.

2. A long straight current carrying wire passes normally through the centre ofcircular loothe wire increases, will there be an induced emf in the loop ? Justify.

Answer»
12374.

Calculate the SELF inductance of a solenoid carrying current.

Answer»
12375.

A Carnot engine has the same efficiencybetween 800 K to 500K and x K to 600 K. Thevalue of 'x' is

Answer»
12376.

42. In an adiabatic change, the pressure andtemperature of a monatomic gas are related asP oc T, where c equals

Answer»
12377.

what is ground wave communication ? on what factor does the maximum range of propogation in this mode depend

Answer»

When the waves propagates near to the surface, the waves glide over the surface of the earth, they are called ground waves. The maximum range of coverage depends on the transmitted power and frequency.

12378.

The strength of magnetic field inside a long current carrying straight solenoid is(A) more at the ends than at the centre(B) minimum in the middle(C) small at all points(D) found to increase from one end to the other

Answer»

(d) The magnetic field inside a long straight current-carrying solenoid is uniform which is represented by parallel lines. Hence it is same at all points.

12379.

The magnetic field inside a long straight solenoid-carrying c

Answer»

The magnetic field inside a long straight current-carrying solenoid is uniform which is represented by parallel lines. Hence it is same at all points.

12380.

45. A cylindrical cavity of diameter a exists inside acylinder of diameter 2a as shown in the figure. Both thecylinder and the cavity are infinitely long. A uniformcurrent density j flowsalong the length. If themagnitude of themagnetic field at thepoint P is given by2μ0aj, then the value122aof N is

Answer»
12381.

19.The strength of magnetic field inside a long current carrying straight solenoid is(A) more at the ends than at the centre(B) minimum in the middle(C) small at all points(D) found to increase from one end to the other

Answer»

It is maximum at the mid of the solenoid and minimum (half of the maximum value) at the end .

what will be the answer

12382.

andA long solenoid of N turns has a self'inductancearea of cross section A. When a current i flows throughthe solenoid, the magnetic field inside it has magnitudeB. The current i is equal to:(A) BAN/L(C) BN/ALL(B) BANL(D)B/ANL

Answer»

L = N*(φ/I)and φ = B/A so L= NB/AI => I = BN/AL , option C.

12383.

One mole of an ideal monatomic gasundergoes a process described by theequation pVconstant. The heat capacityof the gas during this process is [NEET 2016]O A () 3(0) 2R () R

Answer»

answer will be option d

12384.

One mole of an ideal gas undergoes anisothermal change at temperature 'T" so thatits volume v is doubled. R is the molar gasconstant. Work done by the gas during thischange is

Answer»

work done = nRTln(Vf/vi) = 1*R*T*ln(2v/v) = RTln2 L-atm

12385.

why don't the two magnetic field lines of force intersect each other

Answer»
12386.

Why don't two magnetic lines intersect each other?

Answer»

Thetwo magnetic field linesdo notintersecteach other because if they do it means at the point ofintersectthe compass needle is showingtwodifferent directions which is not possible.

12387.

-5. Calculate the total charge on one mole electrons

Answer»

Charge on one electron = 1.6022 × 10–19 coulombCharge on one mole of electron = (1.6022 × 10–19 C) (6.022 × 1023)= 9.65 × 104 C

12388.

list the properties of magnetic lines of forces

Answer»
12389.

Q.12. List the properties of magnetic lines offorces.

Answer»

Magnetic lines of forcehave a number of importantproperties, which include:

They seek the path of least resistance between oppositemagneticpoles.

In a single barmagnetas shown to the right, they attempt to form closed loops from pole to pole. They never cross one another.

Like my answer if you find it useful!

12390.

A light bulb is rated 200 W for 220 V ac supply of 50 Hz. Calculate(0 the resistance of the bulb(i) the rms current through the bulb

Answer»

tank you

12391.

A bulb is rated as 250 V; 0.4 A. Find its : (i) power, and (ii) resistance.

Answer»

V=250v

i=0.4A

r=v/i

r=250/0.4

r=2500/4

resistance=625 ohm

p=vi

v=250v ,i=0.4a

p=(250*0.4)w=100w

Hit like if you find it useful

12392.

A torch bulb is rated 25 V and 750 mA. Cali ulate () its power (i) its resistance (ii) theenergy consumed, if the bulb is lighted for jour hoursList three properties of magnetic field lin

Answer»

V=2.5 VI=750mA= 750x10⁻³Apower =p=?Power =V*I =2.5x750x10⁻³=1.875Wreistance :V=IRR=V/I=2.5/750x10⁻³=3.3 ohmsEnergy consumed if bulb is lighted for 4 hours :E=p*t=1.875x4=7.500Wh=27x 10³joules

12393.

36. An electric bulb rated 240 V - 80 W is operated on 120 V. The power consumed by it will be(a) 80 W(b) 60 W(c) 40 W(d) 20 W

Answer»
12394.

power dissipation Ultese Luis.[CBSE 2016: 2770 marki43.A 10 V cell of negligible internal resistance is connected in parallel across a battery of emf 200 V andinternal resistance 38 Q as shown in the figure. Find the value of current in the circuit[CBSE 2018 : 2/70 markttion200V3892WW

Answer»
12395.

Three blocks of masses 2 kg 4 kg and 6 kg arranged as shown in figureconnected by string on a frictionless incline of 37º A force of 120 N isapplied upward along the incline to the uppermost block. The cords arelight. The tension T1 and T2 in the strings are (g = 10 m/s?](A) T1 = 8N(B) T2 = 36N(C) T1 = 20N(D) T2 = 60N37°

Answer»

I am not sure about the answer of this question...

option c is correct but not sure

12396.

Consider the scale of a voltmeter shown in the diagram and answerfollowing questions:s 1.7003.0(a)(b)(c)What is the least count of the voltmeter?What is the reading shown by the voltmeter ?If this voltmeter is connected across a resistor of 20 立, howcurrent is flowing through the resistor ?

Answer»

Least count of voltmwter always is 0.5 volt

The reading shown by voltmeter is 1.8 volt as each division measures 0.15volt

The current flowing through the resistor of 20 ohm is approx 0.09amp

12397.

2)State and explain Joule's law.A voltmeter is connected across a battery of emf 12V and internal resistance of 10Ω. If the voltmeterresistance 230Ω calculate the current flowing through the resistance and reading shown by thevoltmeter.(I A, V 11.5v)20 *

Answer»

Since V is directly proportional to R in series thereforereading will be 230/240×12=23/2V=11.5V

12398.

A voltmeter is connected across a battery of emf 12v and internal resistance ofIf the voltmeter resistance is 23002, what reading will be shown by voltmeter?16)

Answer»

Since V is directly proportional to R in series thereforereading will be 230/240×12=23/2V=11.5V

thanx

12399.

(5) Fill in the blank and rewrite the completed statement:is expressed in Oersted

Answer»

Magnetic field strength

Explanation:Oersted (symbol Oe) is the unit of magnetic field strength |H|.

12400.

Find the magnitude of the electric field at the point Pin the configuration shown in figure (29-E7) for d>s aTake 2qa=p.-q +q

Answer»