 
                 
                InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 12401. | 11. Consider the situation shown in figure (6-E2). Calculate(a) the acceleration of the 1.0 kg blocks, (b) the tensionin the string connecting the 1-0 kg blocks and (c) thetension in the string attached to 0.50 kg.1.0 kg1.0 kgμ 0.210,0.5 kg | 
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| 12402. | 3. If three particles of masses 2 kg, 1 kg and 3 kg are placed at cornean equilateral triangle of perimeter 6 m then the distance of centre ofmass which is at origin of particles from 1 kg mass is (approximately(Assume 2 kg on x-axis1) 6m2) 2m4) 2m | 
| Answer» 3)that was right answer | |
| 12403. | 108. If the rheostat slider were to move from theextreme right to the far left, How will the readingof voltmeter V1 change?rheostat(1) First increase and then decrease(2) First decrease and then increase(3) Increase continuously(4) Decrease continuously | 
| Answer» option C should be correct because when the rheostat is at right.. then resistance offered by it , will be more.. and gradually it will decrease.. so potential around other resistance will increase..hence V1 reading will also increase. | |
| 12404. | The work done by the weight of a 1 kg masswhile it moves up through 1 m is- | 
| Answer» 1 joule is the best answer. | |
| 12405. | 4. A particle of mass 2 kg moves on a circular path with constant speed 10 m/s. Find change in speedmagnitude of change in velocity. When particle corupletes half revolution. | 
| Answer» After completing half revolution, particle speed remains constant so change in speed will be 0 m/sec, but there is change in velocity vector... Both have same magnitude but opposite directions, so magnitude of change in velocity will be 20 m/sec | |
| 12406. | 41,of mass20 kg is moving on a thcioorizontal surface with a velocity of 1-0 m/s (figure9-E12) towards another block of equal mass kept at restThe spring constant of the spring fixed at one end is 100 49.N/m. Find the maximum compression of the spring.1.0 m/s2.0 kg00000 2.0 kg50Figure 9-E12 | 
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| 12407. | E 14. Solve the equation 4 sin xsin 2x sin 4x = sin 3x | 
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| 12408. | The brakes of a 1,000 kg car can exert asteady retarding force of 5000 N. Thecar is travelling at 20 m/s. When thebrakes are applied it travels a distance | 
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| 12409. | A car of mass 800 kg moves on a circular track of radius 40 m. If the coefficient offriction is 0.5, then maximum velocity with which the car can move is(a) 7 m/s(b) 14 m's(c) 8 m's(d) 12m's | 
| Answer» Given, m = 800 kgr = 40 mμ = 0.5 Maximum velocity with which car can move without falling is vmax = √(μrg)vmax = √(0.5 × 40 × 9.8)vmax = 14 m/s Therefore, maximum velocity with which car can move without falling is 14 m/s. (b) is correct option option b is correct answer | |
| 12410. | A constant retarding force of 50 N is applied to a body of mass 20 kg moving initially with a speeHow long does the body take to stop ?16.d 15ms[2 Marks] | 
| Answer» The force exerts a deceleration on the body and it can be found by,F=ma50=20×aa=2.5ms^-2 The deceleration is2.5ms^-2 To find the time taken to stop the mass, we can use, v = u+at0=15-2.5tt=15/2.5t=6s Therefore, it would take 6 seconds to stop the mass | |
| 12411. | 12. A car of mass 800 kg moving at 54km/h is brought to rest over a distance of 15m. Find the retarding forcedeveloped by the brakes of the car. | 
| Answer» velocity is 54km/h = 54*5/18 = 15m/sand distance covered is 15m also final velocity is 0. so, u² = 2*a*s => a = u²/2s = 15*15/2*15 = 15/2 m/s² now force will me M*a = 800*15/2 = 400*15 = 6000N | |
| 12412. | . The brakes of a 1,000 kg car can exert asteady retarding force of 5000 N. Thecar is travelling at 20 m/s. When thebrakes are applied it travels a distance | 
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| 12413. | The V-I graph for a good conductor makesangle 420 with V-axis. Here V denotes voltageand I denotes current. Then the resistance ofthe conductor will be(a) sin 420(c) tan 42(b) cos 42°(d) cot 42° | 
| Answer» Resistance is given by the cotangent of the angle made by curve with v axis R= cot42° option (d) is correct. | |
| 12414. | A block of mass 10 kg, moving in x direction witha constant speed of 10 m/s, is subjected to aretarding force F-0. Ix.J)/m during itstravel fromx = 20 m to 30 m. Its final KE will be :(1) 450 J(3) 250 J(2) 275 J(4) 475 J | 
| Answer» i think the answer is 475j. please inform me whether i am right or not | |
| 12415. | A proton from cosmic rays enters the earth'smagnetic field in a direction perpendicular to thefield. If the velocity of proton is 2x10' m/s andB 1.6 x 106 wb/m2, find the force exerted on theproton by the magnetic field.(Charge on a proton (e) 1.6 x 10 1°c)(Ans : 5.12 x 10 18N) | 
| Answer» we know that Force = qVB(sin 90= 1))so after putting all the value= 1.6*2*2*10⁻¹⁸N5.12*10⁻¹⁸NAnswer Thanks | |
| 12416. | ularloopofarea1 cm', carrying a current of 10 A.,is placed in a magnetic field of 01 T perpendicular toe plane of the loop. The torque on the loop due to the)Acircmagnetic field isa)zero (b) 10 N m (c) 10 N m (d) 1 N m | 
| Answer» as its placed perpendicular hence theta is 90 torque is NIABcosthetaand if costheta is zerohence torque is zero | |
| 12417. | Question 15. Consider a untiform clectric field E3 10'iNC(a) What is the flux of this field through a square of 10 cm owhose planc is paralc) to the y-Z planc?(b) What is the Buxhroagh the same square if the normal to its plancmakes a 60P angls rith the X-axis? | 
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| 12418. | 19. A person moves 30 m north and then 20 m towards east and finally 30v2 m in south-west direction. Thedisplacement of the person from the origin will beA) 10 m along northB) 10 m long southC) 10 m along westD) Zero | 
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| 12419. | A person moves 30 m north and then 20 m towards east and finally30V2 m in south west direction. The displacement of the personfrom the origin will beD&K CET 2004)(a) 10 m along north(b) 10 m long south(e) 10 m along west (d) Zero | 
| Answer» option D. hai 
 | |
| 12420. | Write down two English alphabet which do not show lateral inversion on reflection from aplane mirror. | 
| Answer» alphabets like A,H,I,M,O,T,U,V,W,X,Y donot show lateral inversion | |
| 12421. | A long sighted person has a distance ofdistinct vision of 1 m. Find the nature and thefocal length of the lens used by him to read abook 25 cm from the eye, using spectacles.(a) convex; 22.3 cm (b) concave; 2.5 cm(c) concave; 33.3 cm (d) convex; 33.3 cm | 
| Answer» option B is the correct answer b is the right answer b is the right answer option b is the correct answer of the given question Here option d is correct | |
| 12422. | A near sighted man cannot see objects clearly up to a distance of 1-5m. Calculate the power of the lens ofthe spectacles necessary for the remedy of this defect.3. | 
| Answer» The distance of far point x = 1.5mTo view distant objects, concave lens of focal length -1.5 should be used.i.e. f = -x = -1.5mPower of lens = 1/f = 1/(-1.5m) = -0.666D To correct this defect of vision, he must use a concave lens. The concave lens will bring the image back to the retina | |
| 12423. | +Physics - Surprise Test - 7In the given circuit all resistances are ofvalue of R ohm each. The equivalentresistance between A and B is :WAAA | 
| Answer» 2R because due to wires neglected remaining resistance | |
| 12424. | a person suffering from short sighted Ness can see clearly only upon a distance of 2m. find the nature & power of the lens required to correct his vision | 
| Answer» Here, u = - infinity, v = - 2m (or -200cm) 1/f = 1/v - 1/u 1/f = -1/2 + 1/infinity therefore, f=-2m P = 1/f = -1/2 = - 0.5 D hence power of lens req is - 0.5 D | |
| 12425. | 41. The person having short sightedness cannot see anobject clearly more than the distance in meters is(1) 1 m(3) 2 m(2) 1.2 m(4) 11 m | 
| Answer» beyond 2 m is the right answer | |
| 12426. | A particle is thrown upwards with a spupward direction, and (b) the maximum height reached.eed of 39.2 m/s. Find (a) the time for which it moves in the | 
| Answer» Intial velocity(u) = 39.2 m/sfinal velocity(v) = 0 acceleration(a) = -9.8 a) using third equation of motion 2as = v^2 -u^22 (-9.8)(s)= (0)^2 - (39.2)^2 -19.6 s = - 1536.6419.6s = 1536.64s = 1536.64 / 19.6= 78.4 so,the maximum height covered = 78.4 m b) let time taken be t using acceleration formula a= (v-u)/t-9.8 = (0- 39.2)/t-9.8 t = -39.29.8t = 39.2t = 39.2 / 9.8= 4 Thanks | |
| 12427. | The time period of a simple pendulum is T remaining at rest inside a lift. Find the time period of pendulum whenlift starts to move up with an acceleration of g/4[AIIMS 2001](A) T(B) T/2(C) 2T/5(D)2T/5 | 
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| 12428. | a) Define Para, Dia & Ferro Magnetism in detail and also explain Domain theory forferromagnetism, | 
| Answer» To explain the phenomenon of ferromagnetism, Weiss proposed a hypothetical concept of ferromagnetic domains. He postulated that the neighboring atoms of the ferromagnetic materials, due to certain mutual exchange interactions, from several number of very small regions, called domains.Weiss theory of ferromagnetism is also called domain theory of ferromagnetism. It has following points: The domains which are aligned approximately along the direction of the applied magnetic field grow in size at the cost of unfavorably oriented domains, that is, those align opposite to the field direction get reduced. In other words, the domain boundaries move so as to expand the favorable domains. Also domains rotate and orient themselves in the direction of the external magnetic field. In the presence of the weak external field, the magnetisation in the material occur mostly by the process of domain growing, but in the strong magnetic field the material is magnetised mostly by the process of domain alignment. When the field is removed, the domain boundaries do not recover their original positions and thus the material is not completely demagnetised, but some residual magnetism remains in it. | |
| 12429. | Define the following terms. Also, write their SI units(a) amplitude(b) time period(c) frequency | 
| Answer» b)time period(denoted by 'T' ) is thetimeneeded for one complete cycle of vibration to pass in a given point. As the frequency of a wave increases, thetime periodof the wave decreasesSI unit is second c)Frequency is the number of occurrences of a repeating event per unit of time. It is also referred to as temporal frequency, which emphasizes the contrast to spatial frequency and angular frequency.SI unit - HZ a) Amplitude is the maximum displacement of points on a wave, which you can think of as the degree or intensity of change. This maximum displacement is measured from the equilibriumSI unit is meter | |
| 12430. | state different ways to induce current in a coil | 
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| 12431. | 174. The boiling point of methanol is greater than methyl thiolbecause(a)there is intramolecular hydrogen bonding in methanoland intermolecular hydrogen bonding in methylthiolitalsding(b) there is intermolecular hydrogen bonding in methanol(c) there is no hydrogen bonding in methanol and(d) there is no hydrogen bonding in methanol andand no hydrogen bonding in methyl thiolintermolecular hydrogen bonding in methyl thiolintramolecular hydrogen boding in methyl thiol. | 
| Answer» option bthere is intermolecular hydrogen bonding in methanol and no hydrogen bonding in methyl thiol | |
| 12432. | Write any three points about Ursa Minor constellation.1. | 
| Answer» Ans :- Ursa Minor constellation lies in the northern sky. The constellation’s name means “the smaller bear,” or “the lesser bear,” in Latin. The Great Bear constellation is represented by its larger neighborUrsa Major. Ursa Minor was first catalogued by the Greek astronomer Ptolemy in the 2nd century. It is easy to recognize because it contains the famousLittle Dipperasterism. Ursa Minor is also notable for marking the location of the north celestial pole, as it is home toPolaris, the North Star, which is located at the end of the dipper’s handle. | |
| 12433. | Whal precautions should be taken in domestic circuits? Explain it. 6SECTION B (Chemistry) | 
| Answer» Following precautions should be taken to avoid the overloading of domestic circuits: (a) Do not use too many appliances at the same time. (b) Use the appliances within the safe limit of electric circuit. (c) Do not connect too many appliances in a single socket. | |
| 12434. | mention the provision of two different current rating in domestic circuit . Explain with reason the advantage of such provision. | 
| Answer» कर्नो इंजन की प्रमेय लिखो। the two different current ratings provided in a domestic circuit are 5A and 15A. this is because different electrical appliances have different power ratings. hence, they draw different current when connected to the mains supply. some appliances need smaller currents, while some other need heavy currents. | |
| 12435. | An electric oven of 2 kWpower rating is operated in a domestic electriccircuit (220 V) that has a current rating of 5 A. What result do youexpect? Explain. | 
| Answer» thanku | |
| 12436. | SINGLE CORRECT ANSWER TYPE1. The bob of a simple pendulum (mass m and length D)dropped from a horizontal position strikes a block of thesame mass elastically placed on a horizontal frictionlesstable. The KE of the block will be(a) 2 mgl(e) mgl(b) mgl/2(d) 02, From a stationarv tonk of mass 125000 pound a small shell | 
| Answer» when the bob is a height l then it potential energy = m g lIt hits another block of same mass.So as per conservation of energym g l will be equally distributed among the two.Hence kinetic energy of block will be1/2 * m g l | |
| 12437. | 2n"2. A bucket full of water of total mass M is pulled up using a uniform rope of mass m and lengtwork done is W=Mg+mgl/2 = (M+m/2) gl (Bucket is treated as point mass) | 
| Answer» If total Mass = M is pulled up using a uniform rope of mass m and length L and work done is W=Mgl+mgl/2= (M+m/2) gl. The ans will be 2(M+m-2) | |
| 12438. | 3) has unneMatch list I with list II and select the correct answerby using the codes given below the listsList I (Item)A. Distance between 1. MicronList II (Units of length)earth and starsB. Inter atomic distance2. Angstromin a solidC. Size of nucleus3. Light yearD. Wavelength of4. Fermi5. Kilometreinfrared laser | 
| Answer» A. Distance between earth and stars- light yearB. Inter atomic distance- micronC)size of nucleus- AngstromD) Wavelength- fermi | |
| 12439. | 4. A uniform rod of mass m, length L, area ofcross-section A and Young's modulus Yhangs from the ceiling. Its elongation under its* own weight will beVmgLmgL2mg(1) Zero2AYAYs. The diagram shows a force-extensionAy(4) | 
| Answer» 3) is correct answer Hook’s Law: Stress = Young’s Modulus × strain ⇒F/A=Yδ/L⇒δ=FLAY dδ=dFxAY dF= centrifugal force due to mass of the element of length dx =dMxω2=MLxdxω2 dδ=MLdxω2x.xAY δ=∫L0Mω2LAYx2dx=Mω2L23AY 3) is the right answer of the following 2) is the correct answer 4) is the correct answer | |
| 12440. | write five points on air pollution | 
| Answer» Ans :- Combustion from Industry Almost all of the common air pollutants can be produced by industrial processes. Some of these are produced by combustion of fossil fuels that drive the industrial process, resulting in particulates, ozone and nitrogen oxides. Transportation Emissions Common forms of transportation like cars, planes and ships generally use combustion to harness energy from fossil fuels. The combustion process releases pollutants into the air, such as particles and carbon monoxide, and also releases substances that quickly form into nitrogen oxides and ozone, which are important air pollutants. Home Heating Keeping homes warm is commonly the job of fossil fuels such as oil, gas and coal. Their combustion means that heating is an important source of air pollutants like sulfur dioxide. If electricity is used to heat the house, the energy plants that produced it may also have been driven by fossil fuels. Home Cooking The energy used in cooking may have come from energy plants, in which case the potential for air pollution has arisen earlier. Alternatively, such as in developing countries, home cooking requires direct burning of wood or coals, which produces the particulate pollution at the point of use. Agriculture Side-Effects Farmers use machinery driven by fossil fuels to plow fields and harvest produce, and the animals that are raised in bulk for food also produce their own type of air pollution. Methane is a gas that contributes to the greenhouse effect that allows global warming; it arises from intestinal gas released by livestock. | |
| 12441. | What's is mean by air pollution | 
| Answer» Air pollution occurs when harmful or excessive quantities of substances ...... A very effective means to reduce air pollution is the transition to renewable energy. may cause diseases, allergies and even death to humans; it may also cause harm to other living organisms such as animals and food crops, and may damage thenaturalorbuilt environment. Both human activity and natural processes can generate air pollution. | |
| 12442. | An expression of snell's law from denser medium to rarer medium29) sihr> sin3) sini sinră) si | 
| Answer» When light travels from adenser mediumto ararer medium, it bends away from the normal, as illustrated to the left. This behavior follows fromSnell's Law. As you saw before, the larger angle must be in themediumhaving the lower index ofrefraction If light travels from one medium with refractive index ni and incident angle i, to another medium with refractive index nr and refraction angle r, then the relationship is described by Snell's Law as such:nisin(i)=nrsin(r) which can be rewritten like this:sin(i)/sin(r)=nr/ni The case where light travels from a denser to rarer medium, then the only change would be that now ni>nr in which case the above equation would yield the index of refraction of the rarer medium in relation to the denser medium. (a) sini > sinr is correct option | |
| 12443. | Hox does angle of refraction vary when angle of incidence increases in the case lighting a denser medium? | 
| Answer» As theangle of incidenceincreases, theangle of refractiongets closer to ninety degrees. At anyangle of incidencegreater than the criticalangle, the light cannot pass through the surface - itisall reflected | |
| 12444. | 5. When a liquid is cooled, the molecules become denser unnili | 
| Answer» When a liquid is cooled, the molecules become denser until it become solid. | |
| 12445. | Glass wares are wrapped in papers or straws pieces. Why? | 
| Answer» | |
| 12446. | STANSFORD INTERNATIONAL HR. SEC. SCHOOLHOLISTIC EDUCATIONNameWORKSHEET-SCIENCESOUNIClassMAX.MARKS:GRADE: IXTICK THE CORRECT ANSWER10 x 1 =1. The density of a medium through which sound propagates is maximum in a region which is called(a) Rarefaction(b) Crestic) Compressiond) Trough.2 Mechanical waves can travel: | 
| Answer» Sound waves are characterised by the motion of particles in the medium and are called mechanical waves. Air is the most common medium through which sound travels. When a vibrating object moves forward, it pushes and compresses the air in front of it creating a region of high pressure. This region is called a compression (C). Hence, option c is correct. thanks | |
| 12447. | Q. 22. What is deforestation? Write its causes and and origin. Theaffecto | 
| Answer» Deforestation is the permanent destruction of forests in order to make the land available for other usesCauses:Agricultural Expansion,Livestock Ranching, Logging, Infrastructure Expansion. ,Overpopulation.Effect :The most dramatic impact is a loss of habitat for millions of species. Eighty percent of Earth's land animals and plants live in forests, and many cannot survive the deforestation that destroys their homes. Deforestation also drives climate change | |
| 12448. | explain depletion in the water table. | 
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| 12449. | 1. State and define sound. Sound waves cannot travel in vacuum. Why?uthich causes a sensation of sound in our erm | 
| Answer» Sound, a mechanical disturbance from a state of equilibrium that propagates through an elastic material medium. The study of sound should begin with the properties of sound waves. There are two basic types of wave, transverse and longitudinal, differentiated by the way in which the wave is propagated. Sound waves are mechanical waves. Unlike EM waves, mechanical waves can't travel in vacuum, because for their propagation they require oscillation of matter. So they can transfer only through a medium. | |
| 12450. | 13). What is presbyopia? Write two causes of this defect. | 
| Answer» Presbyopia is a common defect of vision, which generally occurs at old age. A person suffering from this type of defect of vision cannot see nearby objects clearly and distinctively. A presbyopic eye has its near point greater than 25 cm and it gradually increases as the eye becomes older. Presbyopia is caused by the 1. Weakening of the ciliary muscles 2. Reduction in the flexibility of the eye lens. | |