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12301.

Explain the working principle of Human Vocal System.

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The basic principle of voice recognition involves the fact that speech or words spoken by any human being cause vibrations in air, known as sound waves.

12302.

The change in a vector may occur due to(1) Rotation of frame of reference(2) Translation of frame of reference(3) Rotation of vector(4) Both (1) & (3)

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12303.

(3) AccelerationThe change in a vector may o(1) Rotation of frame of referenceranslation of frame of reference(3) Rotation of vector(4) Both (1) & (3)

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When the frame of reference rotates ,the components of vector ie x&y changes.thus the vector changes.also when vector rotates the components change.

ans is 3

12304.

- What is Reference Systems?

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reference system - a system that uses coordinates to establish position

A system that used coordinates to establish position

Reference System is defined as a system that uses coordinates to establish position.

A system that uses coordinates to establish position

reference system is defined as a system that uses coordinates to establish position

A spatial reference system or coordinate reference system is a coordinate-based local, regional or global system used to locate geographical entities. A spatial reference system defines a specific map projection, as well as transformations between different spatial reference systems

Reference system is defined as a system that uses coordinates to establish position.

Aspatial reference system(SRS) orcoordinate reference system(CRS) is acoordinate-basedlocal, regional or global system used to locate geographical entities. A spatial reference system defines a specificmap projection, as well as transformations between different spatial reference systems. Spatial reference systems are defined by theOGC'sSimple Feature Accessusingwell-known text representation of coordinate reference systems, and support has been implemented by severalstandards-basedgeographic information systems. Spatial reference systems can be referred to using aSRIDinteger, including EPSG codes defined by theInternational Association of Oil and Gas Producers. It is specified in ISO 19111:2007 Geographic information—Spatial referencing by coordinates, prepared byISO/TC 211, also published asOGCAbstract Specification, Topic 2: Spatial referencing by coordinate.

a system that uses coordinate to establish position

12305.

State different types of systems of units.

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In mechanics, length, mass and time are the three fundamental quantities. They are independent of each other and all other quantities can be related with them. For the units of these three basic quantities, following systems have been used: (i) C.G.S. system (or French system): In this system, the unit of length is centimetre (cm), mass is gram (g) and time is second (s).

(ii) F.P.S. system (or British system): In this system, the unit of length is foot (ft), mass is pound (lb) and time is second (s).

(iii) M.K.S. system (or metric system): In this system, the unit of length is metre (m), mass is kilogram (kg) and time is second (s).

12306.

10.The graph between the displacement x and time t for a particle moving in a straight line is shown in figure. During the intervalOA, AB, BC and CD, the acceleration of the particle is00TimetA) OA, AB, BC, CDB) OA, AB, BC, CD-0+0C) OA, AB, BC, CDD) OA, AB, BC, CD0

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12307.

The rm.s. value of current for a variable currenti-i, cos ot + i2 sin ot :-(1) oli, tiz)1 +i2(2)(11 + i2 )2(4),231/22

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12308.

0A beam of length l. is placed along the y-axis between y0 and y - L. The linear density (mass/length) p otits of p and q. (b) Find thethe rod varies with the distance y from the origin as ρ-pr + q' (a) Find the Shinmass of the rod in terms of p, q and L

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12309.

LABEL THE DIAGRAM*2 pointsOUTEREARMODLFEARINNER EARBOA) Ear wax B) SnailOA) Oval window B) Semicircular canalsOA) Eardrum B) CochleaOA) Pinna B) Auditory Nerve

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label the diagram of auditory nerve

A). Eardrum B). Cochlea

A) Eardrum B) Cochlea

A) Eardrum B) Conchlea

12310.

The maximum distance to whichtransmission can be made by a TV tower atheight h is given by (Given R is radius ofearth):(A) Rh(B) R/h(C) V2Rh(D) (A) 10 。(B) 3 。(C) 300 to(D) 30 o

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option c √2Rhit is the maximum distance

12311.

For all real numbers b and c such that the product ofc and 3 is b, which of the following expressions represents the sum of c and 3 in terms of b?A. b+3B. 3b + 3C. 3(b +3)b +3E. 2 +3

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First let us set up the equation we are told—that the product of c and 3 is b.

3c=b

Now we must isolate c so that we can add its value to 3.

3c=b

c=b3

Finally, let us add this value to 3.

b3+3

Our final answer is E, b3+3

[Note: Because this problem uses variables in both the problem and in the answer choices—a key feature of a PIN question—you can always use the strategy of plugging in numbers to solve the question.]

12312.

If the force on a rocket, moving with a velocity of300 m s' is 210 N, then the rate of combustion ofthe fuel is(a) Ow7kgst (b) 1.4 kgs(c) 0.7 kg s-(d) 10.7 kg s-

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(C) is the correct answer

rate of combustion = f/v = 210/300 = 0.7kg/s (c) is correct answer. and it comes from Newton second law f=mdv/dt

Force on rocket = udm/dt∴ rate ofd combustion of fuel [dm/dt] = F/u = 210/300 = 0.7 kg/s

F = vdm/dt

dm/dt = F/v= 210 / 300= 0.7 kg/s

Rate of consumption of fuel is 0.7 kg/s

as from Newton second law of motion dp/dt=f and dm /dt = f/v so dm /dt = 210/300 = 0.7kg/s. so option c is right

12313.

3.i) A 50 g ball hits a wall at an angle 45° with speed 20 m/s and rebounds with the same speedperpendicular to the direction of incidence. Find the impulse.ii) A car is moving with a speed x m/s can be stopped by a force in distanceincreased by 50% what would be new stopping distance in terms of force remaining sameOrii) Find a vector whose magnitude is 10 and which is perpendicular to the vectors A-21+3)-4k andB-6i-9k+2j both.

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Impulse I = change in momentum

I= mv’-mv

we will take vertival and horizontal component

angle theta = 45’

I= (mvcos45°-mvsin45°)-(mvcos45°-mvsin45°)

vertical resolution cancelout & horizontal adds up

I=2mvsin45

I=2*0.05*20*1\root2

= 1\root2

= √2/2

12314.

b) In a dam, generating hydro-electric power, water falls at a rate2000 kgs-1 from a height of 160 m. Assuming that 80% of theenergy of falling water is converted to electric energy, calculate thepower generated. ( Take g-10 ms2)

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I think si

12315.

A man slides down a light rope whose breakingstrength is η times the weight of man (n < 1). Themaximum acceleration of the man so that the ropejust breaks is

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When he moves down

mg-nmg=ma

a=g(1-n)

12316.

Two plane mirrors are inclined at 70°. A ray incident on one mirror at angle 0 after reflection falls on thesecond mirror and is reflected from there parallel to the first mirror, is :(A) 50°(B) 45°(C) 30°(D) 55°

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B) is the correct answer

12317.

for a swim, even on a hot day, you feel cold as you get out of the pool.If yougoExplain why this happens, even though the air around you is warm.

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The reason is that when you get out the water on your skin will start evaporating quickly, especially if there's a bit of wind blowing on your skin. Evaporation is an endothermic process, this means that the water, turning into vapour, will take heat away from your body

12318.

2If yY - sine + Va coso: then the minimum value of y issin0 +v/3 coso' tnen the minimum value of y is(2) 23 +1

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For the minimum Value of y , the value at the denominator should be maximum

so, maximum value of asin∅+bcos∅ = √(1)²+(√3)² = √1+3 = √4 = 2

so, min value of y = 2/2 = 1

ok 1

12319.

The fear of being out of mobile phone contact is known as?

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Nomophobia

12320.

Two Isolated metallic Solid Sphere oRadii R and 2R are Charged suchthat both the Caavede have density. ThSurfaces are for away from Each oand Connected by their conductieDonWire Find The New Charge densitySpheres.

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12321.

A concave mirror forms a virtual image of sizetwice that of the object placed at a distance 5 cmfrom it. Find: (a) the focal length of the mirrror(b) position of image

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12322.

1. A motor car is going due north at a speed of 50 km/h.It makes a 90° left turn without changing the speed.The change in the velocity of the car is about(a) 50 km/h towards west, 'day, 70 km/h towards south-west(c) 70 km/h towards north-west(d) zero.

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thank u😊

50√2 km\h towards south west direction

12323.

1. An object is kept at a distance of 15 cm froma concave mirror whose radius of curvatureis 30 cm. What is the position of the image?

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12324.

02The Moon I, orbits Jupiter once in 1.769 days.The orbital radius of the Moon lo is 421700 km.Calculate the mass of Jupiter?

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12325.

PHYSIODo 20 numerical related to the following topicsMirror Formula-10Lens Formula and Power of lens-10

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if focal length is in metres then formula for calculating power is p=1/f and if focal length is in centimetres then p=100/f

When focal length is calculated in metre then formula for calculating power is[.°. P = 1 / f ]

When focal length is calculated in centimetre then formula for calculating power is:[.°. P = 100 / f ]

12326.

The width and the cross-section of a conductorremaining unchanged, what is the relationbetween the thermal resistance and thermalconductivity of that conductor ?

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Thermal resistanceis the reciprocal ofthermalconductance. In terms of insulation, thethermal resistanceis measured by the R-value.Resistanceis an electrical quantity that measures how the device or material reduces the electriccurrent flow through it. Theresistanceis measured in units of ohms

12327.

iv. An object kept 60 cm from a lensgives a virtual image 20 cm in frontof the lens. What is the focal lengthof the lens? Is it a converging lens ordiverging lens?

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12328.

n object kept 60 cm from a lensgives a virtual image 20 cm in frontof the lens. What is the focal lengthof the lens? Is it a converging lens ordiverging lens?(Ans: -30 cm, lens is diverging or concave

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12329.

what is thermal neutron?

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Thermal neutrons are those which have energy about (1/40) eV or 0.025 eV. They have this name because they would be in thermal equilibrium with atoms at room temperature, 300 K.

12330.

A batsman deflects a ball by an angle of 90 without changing its initial speed, which is equal to 54 km/hr.What is the impulse imparted to the ball ? (Mass of the ball is 0.15 k 800

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12331.

Q.3. Derive lens formula forconvex lens.

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Ans :- OF1=Focal length=fOA=object distance=uOA'=image distance=vTriangle OAB similar to Triangle OA'B'angleBAO=angle B'A'O=90°so, angle AOB=angleA'B'OA'B'/AB=OA'/OA ---------------(1)

Triangle OCF1 similar to Triangle F1A'B' A'B'/OC=A'F1/OF1OC=ABA'B'/AB=A'F1/OF1=OF1-OA'/OF1A'B'/AB=OF1-OA'/OF1---------------(2)

from eqn 1 and 2 we get OA'/OA=OF1 - OA'/OF1-v/-u= -f-(-v)/-fv/u= f+v/f-vf=-uf+uv

on dividing both sides by uvf we get 1/u=1/v+1/f1/v-1/u=1/f

magnification m=height of image /height of object or m=v/u

12332.

Derive the lens maker's formula for a concave lens.

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12333.

A body of mass 'm' slides down a smoothinclined plane having an inclination of 45with the horizontal. It takes 2s to reach thebottom. If the body is placed on a similarplane having coefficient friction 0.5, The timetaken for it to reach the bottom is

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12334.

he thermal capacity of 10g of a substance is8 calories/C. The specific heat is in Jkg-

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3.344 * 10^3 J/kg-K

ans pls

8 cal = 8*4.18 = 33.44J which is the heat required for 10 gms of substance and hence 3.344 J is needed for 1 gm and hence 3.344* 10^3 J is needed for 1 kg. hence 3.344*10^3 J/kg-K

12335.

The specific heat capacity of a substance A is 3,800 Jkg K-1 and that of a 121substance B is 400 Jkgi K-1. Which of the two substances is a good conductorof heat? Give a reason for your answer.c)21

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Here the reason for substance B is that, Substance B is good conductor of heat. Less is the specific heat capacity of a substance the better it acts as a conductor.

• But substance A is good conductor but less than B because less is the specific heat capacity of a substance is not better it acts as a conductor.

• That's why Substance B is good conductor of heat.

12336.

A stream of non viscous liquid emerges from avery short outlet tube at the base of a large opentank, in which the depth of liquid is h. The tubeis at a fixed angle θ to the ground as shownmaximum height of the stream y is. The

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12337.

When a ball is released from rest in a very long column of viscous liquid, its downward acceleration isa'(just after release). Then its acceleration when it has acquired two third of the maximum velocity

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12338.

9. A body of mass 0.01 kg starts to move in a viscousliquid with initial velocity 5 m/s. If drag force is 10-3 N then find time after which velocity will becomem/s10(1) 49 sec(3) 149 sec(2) 100 sec(4) 200 seo

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the retardation due to drag force is = F/m = 10-³/0.01 = 0.1m/s²

now from Newton's equation V = u +at but due to retardation V= 0=> 0 = 5-(1/10)*t => t = 5*10 = 50 sec..

option A is correct..

12339.

what is critical velocity ? Derive stokes' formula for viscous force acting on a body moving with terminal velocity in a viscous medium.

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critical velocity: the greatest velocity with which a fluid can flow through a given conduit without becoming turbulent.

12340.

of mass 2kg moves on a smooth horizontal plane under the action of a single force3i4+ 4 j) newton. Under this force it is displaced from (0,0) to (-1m, 1m). Find the work done by4.icleF (in Joule)

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Given force = 3i+4jand ,the displacement vector is given by p2 - p1

ds = -1i +1j

now , work done will be = F.ds = (3i+4j)•(-i+j) = -3+4 = 1J

12341.

1.5 kg of copper at 1083 C and 1 kg of ice at 0 "C are meltingand changing into their liquid state at their respectivetemperatures Which of them needs more heat?-(L, of ice -33S x 10 Jkg. L, of copper- 180 x 10 Jk)

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12342.

Show that the slope of an adiabatic curve at any point is Îł times the slope of an isothermal curve at thecorresponding point?

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12343.

The terminal velocity V of a spherical ball olead of radius R falling through a viscous liquidvaries with R such that

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12344.

Power supplied to a particle of mass 2kg varies with time as P=31/2 W. Here t is insecond. If velocity of particle at /=0 is v=0. the velocity of particle at time t=2s will be

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12345.

ection f5) Caiculation of normal reaction4 block of mass m' is placed on ground and an additional force F mg is applied on the biick ashown in figure. Calculate contact force between ground and block

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Total force acting on the mass = F+mg and that should be equal to the contact force provided by the ground

=> contact force = F+mg = 2mg

12346.

27. The acceleration (a) of a particle starting fromrest varies with time according to relation a =αt + β. What will be the velocity of the particleafter time t?2at2ct(2) G +pt22(3)α4ßt(4) t + P22

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option 2

12347.

According to the given velocity time graph thedistance travelled by the body before it stops is-25+(a) 80 m(b) 40 m(c) 120 m(d) 0v (m/s) →5712 3 à Ś ĆTime in (sec.) →

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area of curve = (1/2)x20x4 = 40m option b is answer

12348.

)The velocity varies with time according to the relation, v = 3t + 4. The distance travelledby the body in t = 2 s will beb) 12 ma) 10 md) 16 m

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the answer is = B answer

answer is ten meter (a) one is the write answer

the answer is B...

12349.

(E):mpui3ection-1. Velocity of a particle of mass 2 kg varies with time t according to the equation v (2ti + 4)m/s. Hereis in seconds. Find the impulse imparted to the particle in the time interval from t0 tot2 s

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12350.

Show that magnetic field due to a part ofcurrent carrying circular conductor isuo4π awhere θ is angle, which the circular partsubtends at its centre.Fig. 1.06 (a)Fig. 1.06 (b)

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